Graph the system of linear inequalities and shade in the solution set. If there are no solutions, graph the corresponding lines and do not shade in any region X - y > 2 Y < - 1/3x + 1

Answers

Answer 1

We need to graph the following inequality system:

[tex]\begin{cases}x-y>2 \\ y<-\frac{1}{3}x+1\end{cases}[/tex]

Now we need to isolate the y-variable on the left side for the first equation:

[tex]\begin{cases}yNow we have to graph the boundary lines, which are:[tex]\begin{gathered} y=x-2 \\ y=-\frac{1}{3}x+1 \end{gathered}[/tex]

We need to points to graph these equations. We will use the points that have x equal to 0 and y = 0.

For the first equation:

[tex]\begin{gathered} y=0-2 \\ y=-2 \end{gathered}[/tex]

The first point is (0,-2).

[tex]\begin{gathered} 0=x-2 \\ x=2 \end{gathered}[/tex]

The second point is (2, 0).

For the second equation:

[tex]\begin{gathered} y=-\frac{1}{3}\cdot0+1 \\ y=1 \end{gathered}[/tex]

The first point (0,1).

[tex]\begin{gathered} 0=-\frac{1}{3}x+1 \\ \frac{1}{3}x+1 \\ x=3 \end{gathered}[/tex]

The second point is (3, 0).

Now we can trace both boundary lines:

Finally we can shade the solution set, which is the region that is below both lines, since both have an "<" signal.

Graph The System Of Linear Inequalities And Shade In The Solution Set. If There Are No Solutions, Graph
Graph The System Of Linear Inequalities And Shade In The Solution Set. If There Are No Solutions, Graph

Related Questions

simplify the expression tan (3 x+ 2pi) as the tangent of a single angle

Answers

tan(3x)

Explanation

[tex]\tan (3x+2\pi)[/tex]

Step 1

remember some property

[tex]\tan (a+b)=\frac{\tan a+\tan b}{1-\tan a\tan b}[/tex]

then

[tex]\begin{gathered} \tan (3x+2\pi)=\frac{\tan 3x+\tan 2\pi}{1-\tan 3x\tan 2\pi}\text{ Equation(1)} \\ \tan \text{ 2}\pi=0 \\ so \\ \tan (3x+2\pi)=\frac{\tan 3x+0}{1-\tan 3x\cdot0}\text{ } \\ \tan (3x+2\pi)=\frac{\tan \text{ 3x}}{1-0}=\frac{\tan \text{ 3x}}{1} \\ \tan (3x+2\pi)=\tan (3x) \end{gathered}[/tex]

I hope this helps you

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 7z​

Answers

Answer:

(-3, 4)(5, 0)

=====================

Given system

x + 2y = 5 x² + y² = 25

Rearrange the first equation

x = 5 - 2y

Substitute the value of x into second equation

(5 - 2y)² + y² = 254y² - 20y + 25 + y² = 255y² - 20y = 0y² - 4y = 0y(y - 4) = 0y = 0 and y = 4

Find the value of x

y = 0x = 5 - 2*0 = 5y = 4x = 5 - 2*4 = -3

Answer:

[tex](x,y)=\left(\; \boxed{-3,4} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y)=\left(\; \boxed{5,0} \; \right)\quad \textsf{(larger $x$-value)}[/tex]

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}\;x+2y=5\\x^2+y^2=25\end{cases}[/tex]

To solve by the method of substitution, rearrange the first equation to make x the subject:

[tex]\implies x=5-2y[/tex]

Substitute the found expression for x into the second equation and rearrange so that the equation equals zero:

[tex]\begin{aligned}x=5-2y \implies (5-2y)^2+y^2&=25\\25-20y+4y^2+y^2&=25\\5y^2-20y+25&=25\\5y^2-20y&=0\end{aligned}[/tex]

Factor the equation:

[tex]\begin{aligned}5y^2-20y&=0\\5y(y-4)&=0\end{aligned}[/tex]

Apply the zero-product property and solve for y:

[tex]5y=0 \implies y=0[/tex]

[tex]y-4=0 \implies y=4[/tex]

Substitute the found values of y into the first equation and solve for x:

[tex]\begin{aligned}y=0 \implies x+2(0)&=5\\x&=5\end{aligned}[/tex]

[tex]\begin{aligned}y=4 \implies x+2(4)&=5\\x+8&=5\\x&=-3\end{aligned}[/tex]

Therefore, the solutions are:

[tex](x,y)=\left(\; \boxed{-3,4} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y)=\left(\; \boxed{5,0} \; \right)\quad \textsf{(larger $x$-value)}[/tex]

The United States Pentagon building is modeled on the coordinate plane as regular pentagon ABThe vertices of the pentagon are A(-7.42,2.42), B(0,7.88),C(7.42,2.42),D(4.605,-6.35), and E(-4.605-6.35) what is the approximate perimeter in feet of the us pentagon building

Answers

Given,

The coordinates of the vertices of the pentagon is,

A(-7.42,2.42), B(0,7.88), C(7.42,2.42),D(4.605,-6.35), and E(-4.605-6.35)

Required

The approximate perimeter of the pentagon.

The perimeter of the pentagon is calculated as,

The length of side AB is,

[tex]AB=\sqrt{(-7.42-0)^2+(2.42-7.88)^2}=\sqrt{84.868}=9.2124[/tex]

The length of side BC is,

[tex]AB=\sqrt{(7.42-0)^2+(2.42-7.88)^2}=\sqrt{84.868}=9.2124[/tex]

The length of side CD is,

[tex]CD=\sqrt{(4.605-7.42)^2+(-6.35-2.42)^2}=\sqrt{84.8371}=9.211[/tex]

The length of DE is,

[tex]DE=9.21[/tex]

The length of AE is,

[tex]CD=\sqrt{(4.605-7.42)^2+(-6.35-2.42)^2}=\sqrt{84.8371}=9.211[/tex]

The perimeter of the pentagon is,

[tex]Perimeter=9.2124+9.2124+9.211+9.211+9.21=46.0568[/tex]

Hence, the perimeter of the pantagon is 46.0568.

[tex]y = \frac{1}{3} x + 15[/tex]what is the answer

Answers

The slope of the given equation is ,

[tex]m=\frac{1}{3}[/tex]

Slope of perellel line will also be same = 1/3 ,

The equation of perellel line is ,

[tex]\begin{gathered} y-0=\frac{1}{3}(x-6) \\ y=\frac{1}{3}x-2 \end{gathered}[/tex]

Do anyone know the answer to these questions? Please explain as well

Answers

given data:

[tex]\begin{gathered} \frac{7}{21}\text{ and }\frac{21}{24} \\ \end{gathered}[/tex]

to find whether they form an proposition.

using cross product,

[tex]\begin{gathered} \frac{7}{21}\cdot\frac{21}{24} \\ 24\cdot7=21\cdot21 \\ 168\ne441 \end{gathered}[/tex]

the cross product are not equal.

Thus, they donot form a proposition.

5x + 4y = 12Step 1 of 2: Determine the missing coordinate in the ordered pair (0) so that it will satisfy the given equation,

Answers

Answer:

Explanations:

Given the equation;

[tex]5x+4y=12[/tex]

In order to get the missing coordinate in the ordered pair (0, ?), we will substitute x = 0 into the equation and get the corresponding y-value as shown:

[tex]\begin{gathered} 5(0)+4y=12 \\ 0+4y=12 \\ 4y=12 \end{gathered}[/tex]

Divide both sides of the equation by 4;

[tex]\begin{gathered} \frac{4y}{4}=\frac{12}{4} \\ y=3 \end{gathered}[/tex]

Therefore, the missing coordinate will be 3 to have (0, 3)

which of the following equations is a direct variation equation that has the ordered pairs 12.5, 5 as a solutiona. y=7.5xb. y=x-7.5c. x=y+7.5d. y=2.5x e. y= -2.5x f. (2/5)x

Answers

The ordered pair given is 12.5, 5

This means that

When x = 12.5, y = 5

Looking at the given equations, if we substitute the values of x and y, the correct option would be C

The equation is expressed as

x = y + 7.5

By substituting, it becomes

12.5 = 5 + 7.5

12.5 = 12.5

The correct option is C

1. If triangle ABC is congruent to triangle DEF, DE=17, EF =13, DF =9, and BC = 2x-5, then which of the following is the correctvalue of x?(1) 5(3) 9(2) 7(4) 11

Answers

If both trianlges are congruent, we get that:

[tex]BC=DE[/tex]

This way,

[tex]2x-5=17[/tex]

Solving for x :

[tex]\begin{gathered} 2x-5=17 \\ \rightarrow2x=17+5 \\ \rightarrow2x=22 \\ \Rightarrow x=11 \end{gathered}[/tex]

This way, we get that x = 11

Answer: Option 4

IQ is normally distributed with a mean of 100 and a standard deviation of 15.a) Suppose one individual is randomly chosen. Find the probability that this person has an IQ greater than 95.Write your answer in percent form. Round to the nearest tenth of a percent.P(10 greater than 95) =%b) Suppose one individual is randomly chosen. Find the probability that this person has an IQ less than 125.Write your answer in percent form. Round to the nearest tenth of a percent.P(IQ less than 125) =%c) In a sample of 800 people, how many people would have an IQ less than 110?peopled) In a sample of 800 people, how many people would have an IQ greater than 140?peopleCheck Answer

Answers

To answer this questions we need to remember the standard score formula given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

where x is the value we are looking for, mu si the mean and sigma is the standard deviation.

a.

We need the probability:

[tex]P(IQ>95)[/tex]

using the standard score this is equivalent to:

[tex]\begin{gathered} P(IQ>95)=P(z>\frac{95-100}{15}) \\ =P(z>-0.3333) \end{gathered}[/tex]

Using a normal distribution table we have:

[tex]P(z>-0.3333)=0.6306[/tex]

Therefore the probability to select a person with more than 95 IQ points is 63.1%.

b.

Following the same reasoning as before we have:

[tex]\begin{gathered} P(IQ<125)=P(z<\frac{125-100}{15}) \\ =P(z<1.6667) \\ =0.9522 \end{gathered}[/tex]

Therefore the probability to select a person with less than 125 IQ points is 95.2%

c.

To find how many people of this sample have more less than 110 points we need to find that probability:

[tex]\begin{gathered} P(IQ<110)=P(z<\frac{100-110}{15}) \\ =P(z<-0.666) \\ =0.7475 \end{gathered}[/tex]

Multiplying this value with the sample size we have

[tex](800)(0.7475)=598[/tex]

Therefore 598 people will have an IQ less than 110.

d.

By the same reasoning as before we have:

[tex]\begin{gathered} P(IQ>140)=P(z>\frac{140-100}{15}) \\ =P(z>2.6667) \\ =0.0038 \end{gathered}[/tex]

Multiplying this value with the sample size we have

[tex](800)(0.0038)=3[/tex]

Therefore 3 people will have an IQ greater than 140.

012Explanation34BCheck5Use the figure and the table to answer the parts below.67(a) Find the probability that a real number between 4 and 6 is picked.08(b) Find the probability that a real number between 4 and 7 is picked.0RegionABCXArea0.320.560.12 I need help with this math problem

Answers

Given:

The graph is:

Find-:

(a)

Find the probability that a real number between 4 and 6 is picked.

(b)

Find the probability that a real number between 4 and 7 is picked.

Explanation-:

The area of the region

[tex]\begin{gathered} \text{ Region }\rightarrow\text{ Area} \\ \\ A\rightarrow0.32 \\ \\ B\rightarrow0.56 \\ \\ C\rightarrow0.12 \end{gathered}[/tex]

The probability is:

[tex]P(A)=\frac{\text{ Favorable outcome}}{\text{ Total outcome}}[/tex]

The total outcomes is:

[tex]\begin{gathered} =0.32+0.56+0.12 \\ \\ =1 \end{gathered}[/tex]

(a)

Probability to the 4 and 6

The 4 to 6v region is B

[tex]\begin{gathered} P(B)=\frac{\text{ favorable outcomes for B}}{\text{ Total outcomes}} \\ \\ P(B)=\frac{0.56}{1} \\ \\ P(B)=0.56 \end{gathered}[/tex]

(B)

Probability for 4 to 7

The region B and C

[tex]\begin{gathered} 1. \\ \\ P(B\text{ and }C)=\frac{0.56+0.12}{1} \\ \\ =0.68 \end{gathered}[/tex]

Solve each equation by using the square root property. X^2–6x+9=4

Answers

We have the following:

[tex]\begin{gathered} x^2-6x+9=4 \\ \end{gathered}[/tex]

solving by the square root property

[tex]\begin{gathered} x^2-6x+9=4 \\ x^2-6x+9-9=4-9 \\ x^2-6x=-5 \\ x^2+2ax+a^2=\mleft(x+a\mright)^2 \\ 2ax=-6x \\ 2a=-6\rightarrow a=-3 \\ x^2-6x+(-3)^2=-5+(-3)^2 \\ (x-3)^2=-5+(-3)^2 \\ (x-3)^2=-5+9 \\ x-3=\pm\sqrt[]{4} \\ x=\sqrt[]{4}+3=2+3=5 \\ x=-\sqrt[]{4}+3=-2+3=1 \end{gathered}[/tex]

Find the absolute value of | 2x+ z | + 2y x = 2.1, y = 3, z = -4.2

Answers

Answer:

6

Explanations:

The given absolute value expression is:

| 2x+ z | + 2y

Substitute x = 2.1, y = 3, z = -4.2 into the given expression:

[tex]|2(2.1)+(-4.2)|+2(3)[/tex]

This can be simplifed as:

[tex]|2(2.1)-4.2|+6[/tex][tex]|4.2-4.2|+6[/tex]

Since |4.2-4.2| = 0, the expression above becomes:

0 + 6

= 6

Therefore, the absolute value of the expression, after simplification, is 6

1 - The Le Mans car race is a 24-hgur race. The longest distance erertraveled by a car in the race is 3,315 miles. What is the distancerounded to the nearest ten?2- The longest river in the world is the Nile. It is 4,184 miles long.What is the length of the Nile River rounded to the nearesthundred miles?3- Frank rounds 846,025 to the nearest hundred thousand and to the nearest ten thousand.Part A What is 846,025 rounded to the nearest hundred thousand?Part B What is 846,025 rounded to the nearest ten thousand?Part C Which rounded number is greater? Explain.

Answers

1. To find the nearest ten of 3315.

Since 15 is midway between 10 and 20.

So, the nearest ten of 3315 is 3320.

2. To find the nearest hundred miles of 4,184 miles:

184 is closest to 200.

Hence, the nearest hundred miles of 4,200 miles.

3.

A) To find the nearest hundred thousand of 846,025:

846,025 is closest to 800,000.

Hence, nearest hundred thousand of 846,025 is 800,000.

B) To find the nearest ten thousand of 846,025:

46,025 is closest to 50,000.

Hence, nearest ten thousand of 846,025 is 850,000.

C) Comparing the results of Part A and Part B,

The rounded number of Part B is greater.

Math Lab A - Section 203B Notebook Home Insert Draw View Class Notebook U abe А. = = A Styles ☆ ? The table shows the average mass, in kilograms, of different sizes of cars and trucks. Size Small Car Average Mass (kilograms) 1,354 1,985 Large Car Large Truck 2,460 Part A To the nearest hundred, how much greater is the mass of a large truck than the mass of a small car? Fill in the blanks to answer the question. To the nearest hundred, a large truck has a mass of kilograms, and a small car has a mass of kilograms. So, a large truck has a mass about kilograms greater than a small car.

Answers

Given:

Round the mass of the large car to the nearest thousand.

Because 1985 is between 1,000 and 2,000 and closer to 2,000 ,the number should round up to 2,000.

Option D is the correct answer.

10 Natalie uses a 15% off coupon when she buys a camera. The original price of the camera is $45.00. How much money does Natalie save by using the coupon.?

Answers

Given data:

The given discount through coupon is d=15%.

The original price of camera is c=$45.00.

The discount on the given amount is,

[tex]\begin{gathered} d=(\frac{15}{100})(45) \\ =6.75 \end{gathered}[/tex]

Thus, the amount saved is $6.75.

Marie requires 2 gallons of paint to cover an area of 400 square feet. Identify the graph that shows the relationship between the quantity of paint and the area covered and the parent function that best describes it. Then use the graph to estimate how many gallons of paint Marie requires to paint an area of 2,400 square feet.

Answers

Given:

x = 2 gallons of paint

y = 400 square feet of area

The graph representing the given point (x,y) = (2, 400) is number 4: linear 12 gallons.

Then, to estimate how many gallons of paint Marie requires to paint an area of 2,400 square feet.

We locate the point y = 2400 and find the corresponding x value. This is:

x = 12

Answer:

* the graph is the fourth one

* 12 gallons

Which integer represents this scenario? a fish grows 4 inches a) -4" b) 4” 6.NS.5

Answers

as it is about growth, the integer is positive, therefore

answer is b) 4"

Well think about growth it would be b 4

Use the box method to distribute and simplify (-3x – 3)(5 + 4x²). Drag and drop the terms to the correct locations of the table.

Answers

Looking at the diagram, the box method has already been applied. The simplified answer would be gotten by adding up each term in the boxes while taking into consideration, the signs of each term. It becomes

- 15x - 15 - 12x^2 - 12x^3

Rearranging the terms in descending order of the exponents, it becomes

- 12x^3 - 12x^2 - 15x - 15 15x - 15 - 12x

Can you help Turn this equation to the other equation

3x-y=-27
x+2y=16

y=_x+_
y=_x+_

Answers

Answer:

y=3x+27

2y= x+16or,

or,y= x+16/2

A college had 5,000 students in 2018. The number of students decreased by 10% in 2019 andanother 5% in 2020. How many students did the college have in 2020? (1 point)

Answers

Okay, here we have this:

Inicially we have 5000 students, let's calculate how many were left in 2019:

Students in 2019=5000*0.9

Students in 2019=4500

Now, let's finally calculate how many were left in 2020:

Students in 2020=4500*0.95

Students in 2020=4275

Finally in 2020 they were 4275 students

please help me I really need help in my math work

Answers

we need to know the formula of the area of a rectangle

[tex]A=l\cdot w\text{ }[/tex]

we already know A and l we need to clear w

[tex]w=\frac{A}{l}=\frac{2x^2+5x-12}{2x-3}[/tex]

we need to do the division

[tex]undefined[/tex]

7/8 = 7/16 =Reduce your answer to the lowest terms.

Answers

[tex]\frac{\frac{7}{8}}{\frac{7}{16}}[/tex][tex]\frac{7}{8}\times\frac{16}{7}=\frac{16}{8}=2[/tex]

how do I have to search x in a triangle??

Answers

1) the value of x is 7

Explanation:

1) From the diagram, the angles with the red ink are equal.

SInce the two angles at the base are equal, we call the triangle an isosceles triangle.

This triangle have two sides and two angle equal.

As a result, the sides opposite the angles given in the triangle are equal to each other.

The sides opposite the angles are x and 7. So, x is equal to 7.

Hence, the value of x is 7

The same principle or procedure can be applied to question number 2.

The value of x is 7 so that is your answe

10x + 50 + 6x = 58 if x is the solution to the given equation, what is the value of 32x

Answers

The solution to the given equation is;

[tex]\begin{gathered} 10x+50+6x=58 \\ \text{Collect all like terms,} \\ 10x+6x=58-50 \\ 16x=8 \\ \text{Divide both sides by 16} \\ \frac{16x}{16}=\frac{8}{16} \\ x=\frac{1}{2} \end{gathered}[/tex]

Therefore, the value of 32x shall be;

[tex]\begin{gathered} 32x \\ =32(\frac{1}{2}) \\ =\frac{32}{2} \\ =16 \end{gathered}[/tex]

The answer is 16

Can you show me how to solve this and graph?

Answers

The points (x,y) whose values satisfy the equation -5y=13 belong to the graph of that equation.

First, isolate y by dividing both sides of the equation by -5 and simplifying:

[tex]\begin{gathered} -5y=13 \\ \Rightarrow\frac{-5y}{-5}=\frac{13}{-5} \\ \Rightarrow y=-\frac{13}{5} \end{gathered}[/tex]

Then, the points (x,y) belon to the graph of the equation -5y=13 whenever the value of y is -13/5, regardless of the value of x. Then, choose two different values of x to find two points that belong to the graph. For example, x=0 and x=2. Then, this two points belong to the graph:

[tex]\begin{gathered} (0,-\frac{13}{5}) \\ (2,-\frac{13}{5}) \end{gathered}[/tex]

Notice that -13/5=-2.6,

Plot the points (0,-2.6) and (2,-2.6) in a coordinate plane:

Since the given equation is linear, the graph of the equation is a straight line. We can draw a straight line between any two points given. Draw a line between (0,-2.6) and (2,-2.6) to find the graph of the equation -5y=13:

2/7 in reduced terms

Answers

2/7 is in reduced terms already

no simplification can be made over this fraction.

hope it is clear

Let the random variable x be the number of rooms in a randomly chosen owner- occupied housing unit in a certain city. The distribution for the units is given below.

Answers

(a)

Since X can only assume whole values, it is a discrete random variable.

(b)

The sum of all probabilities in the table must be equal to 1, so we have:

[tex]\begin{gathered} 0.07+0.22+0.41+0.2+0.05+0.03+0.01+P(10)=1\\ \\ 0.99+P(10)=1\\ \\ P(10)=1-0.99\\ \\ P(10)=0.01 \end{gathered}[/tex]

(c)

The values of x smaller than 5 in the table are 3 and 4, so we have:

[tex]P(X<5)=P(3)+P(4)=0.07+0.22=0.29[/tex]

(d)

For x between 4 and 6, we have:

[tex]P(4\leq x\leq6)=P(4)+P(5)+P(6)=0.22+0.41+0.2=0.83[/tex]

(e)

Looking at the table, for x = 3 we have:

[tex]P(3)=0.07[/tex]

Max exercise 4 hrs during each 7 day week. At this rate, how many hours do he exercise in 35 days?

Answers

We know that Max exercises 4 hours during each 7-day-week.

After 35 days (5 weeks), the number of hours would be

[tex]4\cdot5=20[/tex]Max would exercise 20 hours after 35 days.

If f(5)=3, write an ordered pair that must be on the graph of y = f(x + 1) + 2

Answers

Answer:

(4, 5)

Explanations:

The given function is:

y = f(x + 1) + 2

There are many ordered pairs that can be on the graph of y = f(x + 1) + 2, but with the information given will can look for one of them.

Let x = 4

y = f(x + 1) + 2

y = f(4 + 1) + 2

y = f(5) + 2

Since it is given that f(5) = 3, the equation above can be simplified to get the value of y.

y = f(5) + 2

y = 3 + 2

y = 5

Therefore, an ordered pair that must be on the graph of y = f(x+1) + 2 is (4, 5)

Generalize Two data sets have the same number of values. The first data set has a mean of 7.2 and a standard deviation of 1.25. The second data set has a mean of 7.2 and a standard deviation of 2.5. Which data set is more spread out?

Answers

ANSWER

The second data set is more spread out

EXPLANATION

The standard deviation measures the spread of a data distribution. The more spread out a data distribution is, the greater its standard deviation.

In this problem, the second data set has twice the standard deviation of the first data set, so it's more spread out.

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