Given that
The vertices of the polygon ABCD are A(1,1), B(2,3), C(3,2), and D(2,1). ANd it is reflected about the x-axis.
So we have to find the vertices of the polygon A'B'C'D'.
Explanation -
Since the reflection is about the x-axis, the x-axis will be unchanged and the y-axis will be changed.(sign will be changed)
And it will be changed by the factor +2 in upwards directions.
So if A, B, C, D are reflected across x-axis.
The new points will be A' = (1,-1)
B' = (2,-3)
C' = (3,-2)
D' = (2,-1)
Now we have to add 2 in the y axis as they move upwards.
Then, the required points will be
A' = (1, -1+2) = (1,1)B' = (2, -3+2) = (2,-1)C' = (3,-2+2) = (3,0)D' = (2, -1+2) = (2,1)So these are the required answers.
HELP PLEASE and please give out a good answer. Which ones are right? Or wrong?
You have the following equation for model the amount of money raised by selling concessions related to the number of fans:
y = 5.2x - 20
The previous equation has the form of a line y =mx + b, where m is the unit rate of change and b a constant value.
The first sentence is true because in the given situation m = 5.2 and it is the unit rate of change.
The second sentence is false because the constant -20 is independent of the number of fans.
The third sentence is true because if no fans are attended, then x=0 and
y = 5.2*0 - 20
y = -20
that is, there is a loss of money.
graph at least one full cycle of the following trig function, lable the amplitude midline and maximum and the intervals f(x)=2sin(x-pi/2)-1
(4+3i)-(2-i)Simplify, leave in a+bi form
The given expression is
(4 + 3i) - (2 - i)
We would simplify the terms inside the parentheses. The negative sign(- 1) outside the second parentheses would be used to multiply each term inside. We have
4 + 3i + - 1 * 2 + - 1 * - i
4 + 3i - 2 + i
By collecting like terms, we have
4 - 2 + 3i + i
2 + 4i
Thus, the answer in a + bi form is
2 + 4i
Point M is located at (-4,-6)What is located 4units from point M?
We have a point M located at (-4,-6).
We have to identify what is located 4 units from point M.
We can draw a circle with center at M with a radius of 4 units.
The circumference will include all the points that are 4 units away from M.
We can draw them as:
We can see that none of the points listed is 4 units from M.
The y-axis is located 4 units away from M.
Other point that is 4 units from M is for example (-4,-2).
a card is from a standard deck of cards is chosen at random, then a coin is tossed. what is the probability of getting ace and tails!?
A standard deck of cards consists of 52 cards with 4 aces.
The probability of getting an ace in a pack of the standard deck is;
[tex]P_1=\frac{4}{52}=\frac{1}{13}[/tex]Hi can you help me with this question real quick please
The volume of a sphere is given by
[tex]V=\frac{4}{3}\pi r^3[/tex]where V denotes the volume and r the radius. In our case,
[tex]r=\frac{3}{2}in[/tex]Then, by substituting this value into the formula, we have
[tex]V=\frac{4}{3}\pi(\frac{3}{2})^3[/tex]which gives
[tex]\begin{gathered} V=\frac{4}{3}\pi\frac{3^3}{2^3} \\ V=4\pi\frac{3^2}{8} \\ V=\pi\frac{9}{2} \end{gathered}[/tex]By taking Pi as 3.14, we get
[tex]V=14.13in^3[/tex]So , by rounding to the nearest tenth, the answer is 14.1 cubic inches.
Mauricio is buying his wife flowers for their anniversary. The florist has 5 red roses, 4 yellow roses, and 3 pink roses. What is the probability he will select 1 yellow rose the 2 red rose. Independent or Dependent
We will have the following:
The probability will be given by:
[tex]p=(\frac{1}{12})(\frac{5}{11})(\frac{4}{10})\Rightarrow p=\frac{1}{66}[/tex][tex]\Rightarrow p=0.01515151515\ldots\Rightarrow p\approx0.015[/tex]So, the probability of that happening is approximately 15%.
It is dependent.
13 inches by 6 inches by 4 inches. what is the maximum lenght
Aubrey spends a winter day recording the temperature once every three hours for science class. At 9 am, the temperature was -4.6°F. Between 9am and noon, the temperature increased by 4.2°F. Between noon and 3pm, the temperature went down 8.3°F. Between 3pm and 6pm, the temperature decreased by 6.9°F. What was the temperature at 6pm?
The temperature at 6pm is 15. degrees F if Aubrey spends a winter day recording the temperature once every three hours for science class.
What is a sequence?It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
It is given that:
Aubrey spends a winter day recording the temperature once every three hours for science class.
The temperature between 9 am and noon:
= -4.6 + 4.2
= -0.4 degree F
Between noon and 3pm, the temperature went down 8.3°F.
= -0.4 - 8.3
= -8.7 degrees F
Between 3pm and 6pm, the temperature decreased by 6.9°F.
= -8.7 - 6.9
= 15. degrees F
Thus, the temperature at 6pm is 15. degrees F if Aubrey spends a winter day recording the temperature once every three hours for science class.
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in a class, 2/3 of the pupils are boys. If there are 15 more boys than girls, how many pupils are there in the class (use equation method)
Solution
Step 1:
Let the number of pupils = n
[tex]\begin{gathered} Number\text{ of boys = }\frac{2}{3}n \\ Number\text{ of girls = }\frac{2}{3}n\text{ - 15} \end{gathered}[/tex]Step 2:
Write an equation to find the value of n
[tex]\begin{gathered} \frac{2}{3}n\text{ + }\frac{2}{3}n\text{ - 15 = n} \\ \frac{4n}{3}\text{ - n = 15} \\ \frac{4n\text{ - 3n}}{3}\text{ = 15} \\ \frac{n}{3}\text{ = 15} \\ \text{n = 15 }\times\text{ 3} \\ \text{n = 45} \end{gathered}[/tex]Final answer
There are 45 pupils in the class.
The wholesale price for a pillow is $4.50 . A certain department store marks up the wholesale price by 90% . Find the price of the pillow in the department store. Round your answer to the nearest cent, as necessary.
The wholesale price for a pillow is $4.50 .
The store marks up the wholesale price by 90%.
That is, 90% of $4.50 has been aadded with the wholesale price as the store price (SP).
Therefore we have, '
[tex]Sp=4.50+\frac{90}{100}\times4.50=8.55[/tex]Thus, the store price is $8.55
Find the area of the shaded region in the figure. Use the pi key for pi.The area of the shaded region in the figure is approximately: (Type an integer or decimal rounded to the nearest tenth as needed.)
Hello there. To solve this question, we'll need to remember some properties on geometry and areas of figures.
First, the area of a square is equal to the square of its side length.
The area of a circle is given by pi * the square of its radii, being this radii half of the diameter:
In this case, the side of the square is 1.5' and the diameter of the circle is 5.8'.
Finding the radii of the circle:
r = d/2 = 5.8'/2 = 2.9'
Calculating the area of the square and the circle
Asquare = 1.5² = 2.25 and Acircle = pi * 2.9² = pi * 8.41
The area of the shaded region is calculated by the difference between the area of the circle and the square
Ashaded = Acircle - Asquare
Ashaded = 8.41pi - 2.25
This is the area of the region we've been looking for.
Use the information from the previous question to answer this question now that you know the length of the missing side of the triangle, find the actual distance. Since each unit on the grid is zero. 5 mile, the ferry will travel about blank miles
Solution
find the actual distance. Since each unit on the grid is 0.5 mile, the ferry will travel about
Length of the missing side of the triagle = 10.2
Unit on the grid = 0.5mile
[tex]\begin{gathered} 1\text{unit -}\longrightarrow\text{ 0.5 mile} \\ 10.2\text{unit}--\longrightarrow x \\ x=\frac{10.2\times0.5}{1} \\ x=5.1 \end{gathered}[/tex]Hence the correct answer is Option C
I was out for quarantine and teacher won’t help, I need help!
A linear equation can be written as:
[tex]y=mx+b[/tex]Let:
y = c = Cost
x = h = Hours
Using the data, we can create a 2x2 system of equations. So:
[tex]\begin{gathered} x=2,y=20 \\ 20=2m+b_{\text{ }}(1) \\ ---------- \\ x=8,y=50 \\ 50=8m+b_{\text{ }}(2) \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} (2)-(1) \\ 50-20=8m-2m+b-b \\ 30=6m \\ m=\frac{30}{6} \\ m=5 \\ so\colon \\ 20=2(5)+b \\ b=10 \end{gathered}[/tex]Therefore,the linear equation is given by:
[tex]y=5x+10[/tex]For a equation of the form y = mx + b
m = Slope (rate)
b = y-intercept (Initial value)
Therefore the hourly rate for renting a bicycle is $5 and the deposit is $10
Which of the following polynomial has roots at 3, -4, and a double root at-2?
The second polynomial [tex]f(x) = (x - 3)(x+4)(x+2)^2[/tex] has roots 3, -4 and a double root at -2.
What is root of polynomial?
The values of a variable for which the provided polynomial equals zero are referred to as a polynomial's roots. P(a) = 0 if an is the polynomial's root for x.
Since, if x is a root of the polynomial then x is a zero of the polynomial.
That means f(x) = 0
Consider, the first polynomial, [tex]f(x) = (x+3)(x-4)(x-2)^2[/tex]
plug x = 3, [tex]f(3) = (9)(-1)(1)^2 = -9[/tex] ≠ 0
Plug x = -4, [tex]f(-4) = (-1)(-8)(36) = 368[/tex] ≠ 0
Plug x = -2, [tex]f(-2) = (1)(-6)(16) = -96[/tex] ≠ 0
Therefore, 3, -4 and -2 are not the roots of the first polynomial.
Now consider the second polynomial, [tex]f(x) = (x-3)(x+4)(x+2)^2[/tex]
Plug x = 3, [tex]f(3) = 0[/tex]
Plug x = -4, [tex]f(-4) = 0[/tex]
Plug x = -2, [tex]f(-2) = 0[/tex]
Therefore, x = 3, -4, -2 are the roots of the second polynomial.
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Determine if the two triangles are congruent.• If they are, complete the congruence statement; and identify how they are congruent.• Otherwise, select "Not Congruent" for BOTH drop downs.Be sure to identify any corresponding angles or sides that you know are congruent!AniBby[ Select ]AACB ZA [Select ]
Triangle ACB is congruent with triangle DCB by SAS
Because they have two sides of equal lenght (AC - DC and common side CB) and an agle of equal measure (A - D)
what is the minimum amount of shrink wrap she will need?
we know that
To find out the minimum amount of shrink, you need to calculate the surface area
The surface area of the figure is equal to the area of its two triangular faces and its three rectangular faces
so
SA=2[(1/2)(4)(2.2)]+(3)(4)+(2.2)(3)+(3)(4.6)
SA=8.8+12+6.6+13.8
SA=41.2 in^2
answer is option CUse the graph of the function to estimate the interval on which the function is decreasing.Enter your answer in interval notation.Enter any values to one decimal place.
The Solution:
Given:
Required:
To determine the interval in which the function is decreasing.
From the given graph, the interval in which the function is decreasing is:
[tex](-2.5,1)[/tex]
Therefore, the correct answer is (-2.5, 1)
Find two solutions for the equation 4x+3y=24 , draw it's graph .
The equation of consideration is:
[tex]4x\text{ + 3y = 24}[/tex]Since two unknowns ( x and y) are given in just one equation, to get each set of the solutions, we are going to choose a value of x and get a corresponding value of y
Let x = 0, to get the value of y at point x = 0, substitute this value of x into the given equation:
[tex]4(0)\text{ + 3y = 24}[/tex][tex]3y\text{ = 24}[/tex][tex]y\text{ = }\frac{24}{3}\text{ = 8}[/tex]The first set of solutions is therefore:
[tex]x\text{ = 0, y = 8}[/tex]To get the second set of solution, let us choose x = 3 and substitute this value into the given equation:
[tex]4(3)\text{ + 3y = 24}[/tex][tex]12\text{ + 3y = 24; 3y = 24 - 12; 3y = }12;\text{ y = 12/3; y = 4}[/tex]The second set of equation is:
[tex]x\text{ = 3, y = 4}[/tex]The above is the graph showing the two sets of solutions
Which of the following functions best models the data shown in the scatterplot below? y=3x+5y=x2+10y=x+8y=2x+
Given:
a graph is given
Required:
To simplify which option is correct
Explanation:
From the graph we know the model should be line. And it passes through (15,60)
if the model is y=x+8 , y =15+8=23
there is too much difference between 23 and 60, so y=x+8 is wrong
and y=3x+5 is right
Required answer:
y=3x+5
The Harris school district gives awards to its schools based on overall student attendance. The data for attendance are shown in the table below, where Min represents the fewest days attended and Max represents the most days attended for a single student:SchoolMinMaxRangeMeanMedianIQRσHigh School A1071808216915048.533.6High School B921807214113944.527.0High School C1041807516115154.532.4Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically. (5 points)Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically. (5 points) (10 points)
Answer to part A :
The school that gets the award for the highly consistent attendance among its students is school B . Because its range is the smallest that is there exists a smaller variation in the highest and the lowest value and also because the interquartile range is the smallest means that the data is spread out the least.
Answer to part B :
The school that gets the award for the highest average attendance among its students is High school A . This is because its mean and median are the highest which means that there are more kids attended school on average.
Leila drove to the mountains last weekend. There was heavy traffic on the way there and the trip took 7 hours. When Leila drove home, there was no traffic and the trip only took 4 hours. If her average rate was 27 miles per hour faster on the trip home, how far does Leila live from the mountains
We have the next formula
[tex]d=r\cdot t[/tex]where d is the distance, r is the rate and t is the time.
For the trip going
d=r*7
For the trip returning
d=(r+27)*4
Then we solve
7r=4r+108
We solve for r
7r-4r=108
3r=108
r=36
Then for d
d=36*7
d=252 miles
ANSWER
she lives 252 miles far from the mountains
Need help. Not understanding how to start with each of these
Given
mean = 84 pounds
standar deviation = 13 pounds
Procedure
a. New hippo weighs between 90 and 109 pounds
Areas under portions of a normal distribution can be computed by using calculus. Since this is a non-mathematical treatment of statistics, we will rely on computer programs and tables to determine these areas.
[tex]\begin{gathered} \mu=84 \\ \sigma=13 \\ \end{gathered}[/tex]Between 90 and 109
Results:
Area (probability) = 0.295
b. What weight corresponds with the 6th percentile?
The score you have entered means that the hippo is at the sixth percentile – their percentile rank is 6%
Given P(xZ = -1.555
The value of the z-score tells you how many standard deviations you are away from the mean.
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ x=z\sigma+\mu \\ x=-1.555\cdot13+84 \\ x=63.785 \end{gathered}[/tex]63.785 is the weight for the 6th percentile
c. What percentages of hippos are born weighing 27 pounds or less?
Z = (27 - 84)/13
Z-score = -4.38462
0% of hippos are born at 27 pounds or less
Hi so sorry i need help in geometry i think its asking if the two given angles are coterminal or not
Given these two angles:
[tex]\frac{5\pi}{4}[/tex][tex]-\frac{3\pi}{4}[/tex]You need to remember that, by definition, two angles are coterminal if the Difference (the result obtained by subtracting them) is:
[tex]360\text{\degree or }2\pi[/tex]Then, you need to set up:
[tex]\frac{5\pi}{4}-(-\frac{3\pi}{4})[/tex]Solving the Subtraction, you get:
[tex]=\frac{5\pi}{4}+\frac{3\pi}{4}[/tex][tex]=\frac{8\pi}{4}[/tex][tex]=2\pi[/tex]Hence, the answer is: They are Coterminal Angles.
Heather invested $19,400 in a growth fund at 3.16% compounded quarterly for 9 years and 6 monthsA) calculate the maturity value of this amount at the end of the termB) Calculate the amount of compounded interest earned
GIVEN:
We are given the details of an investment as follows;
Initial investment = $19,400
Interest rate = 3.16%
Period of investment = 9 years and 6 months
Required;
To use the information given to calculate
(a) The maturity value at the end of the term
(b) The amount of compound interest earned.
Step-by-step solution;
The formula applied in calculating the maturity value is as follows;
[tex]A=P(1+r)^t[/tex]Where the variables are;
[tex]\begin{gathered} A=Maturity\text{ }value \\ \\ P=Initial\text{ }investment\text{ }(19400) \\ \\ r=rate\text{ }of\text{ }interest\text{ }(0.0316) \\ \\ t=time\text{ }in\text{ }years\text{ }(9.5) \end{gathered}[/tex]However, for an investment whose interest is compounded at different intervals within 1 year, the formula becomes modified as shown below;
[tex]A=P(1+\frac{r}{n})^{tn}[/tex]Where the variable n is the number of times interest is compounded annually. For an investment whose interest is compounded quarterly, that is, four times a year, the formula becomes;
[tex]A=P(1+\frac{r}{4})^{4t}[/tex]We can now calculate as follows;
[tex]\begin{gathered} A=19400(1+\frac{0.0316}{4})^{4\times9.5} \\ \\ A=19400(1+0.0079)^{38} \\ \\ A=26161.6208681 \\ \\ A\approx26161.62 \end{gathered}[/tex]We can now determine the amount of compound interest earned by deducting the initial amount invested from the maturity value. Thus we have;
[tex]\begin{gathered} Interest=A-P \\ \\ Interest=26161.62-19400 \\ \\ Interest=6761.62 \end{gathered}[/tex]Therefore,
ANSWER:
[tex]\begin{gathered} Maturity\text{ }value=26,161.62 \\ \\ Interest=6,761.62 \end{gathered}[/tex]12. Write the equation of the line that is perpendicular to the line x - 4y = 20 and passes through the point (2,-5).
Two perpendicular lines have reciprocal and opposite slopes.
First we have to write the given line in the slope-intercept form:
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
We have this equation:
[tex]x-4y=20[/tex]To write it in the slope-intercept form we have to clear y:
[tex]\begin{gathered} x-20=4y \\ \downarrow \\ y=\frac{1}{4}x-5 \end{gathered}[/tex]The slope is 1/4 and the y-intercept is -5.
The slope of the perpendicular line will be the opposite and reciprocal of 1/4, that's -4.
For now we have the perpendicular line's equation:
[tex]y_p=-4x+b[/tex]There are a lot of lines that are perpendicular to the given line, but only one that passes through (2, -5). We use this point to find the y-intercept by replacing x = 2 and y = -5 into the expression above and solving for b:
[tex]\begin{gathered} -5=-4\cdot2+b \\ -5=-8+b \\ -5+8=b \\ b=3 \end{gathered}[/tex]The y-intercept of the perpendicular line is 3.
The equation of a line perpendicular to the given line that passes through the point (2,-5) is
[tex]y_p=-4x+3[/tex]In one city, the probability that a person will pass his or her driving test on the first attempt is 0.63. 11 people are selected at random from among those taking their driving test for the first time. What is the probability that among these 11 people, the number passing the test is between 2 and 4 inclusive?
The probability that among these 11 people, the number passing the test is between 2 and 4 inclusive is 0.0665
What is Probability?
Probability gives us the information about how likely an event is going to occur
Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.
Probability of any event is greater than or equal to zero and less than or equal to 1.
Probability of sure event is 1 and probability of unsure event is 0.
Now
Binomial distribution of probability will be used
Here, n = 11, p = 0.63,
P(X = x) = [tex]{n\choose x} p^x(1-p)^{n-x}[/tex]
P(X= 2) = [tex]{11\choose 2} 0.63^2(1-0.63)^{11-2}[/tex]
= 0.0028
P(X = 3) = [tex]{11\choose 3} 0.63^3(1-0.63)^{11 - 3}\\[/tex]
= 0.0144
P(X = 4) = [tex]{11\choose 4} 0.63^4(1-0.63)^{11 - 4}\\\\[/tex]
= 0.0493
The probability that among these 11 people, the number passing the test is between 2 and 4 inclusive = 0.0028 + 0.0144 + 0.0493
= 0.0665
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2.Evaluate the following mixed numbers, then simplify.7 1/2 divide 1 1/8
Given the numbers : 7 1/2 and 1 1/8
We will divide them
so,
[tex]\begin{gathered} 7\frac{1}{2}\div1\frac{1}{8} \\ \\ =\frac{15}{2}\div\frac{9}{8} \\ \\ =\frac{15}{2}\times\frac{8}{9} \\ \\ =\frac{8}{2}\times\frac{15}{9}=4\times\frac{5}{3}=\frac{20}{3}=6\frac{2}{3} \end{gathered}[/tex]main and Range HAMAD SALIM 12 Range 12 The graph below represents the function y = f(x). State the domain and range of this function. 1 I US
Remember that the domain is the data set of all possibles values of x and the range is the data set of all possibles values of y
so
Looking at the graph
Domain is the interval for x
[-5,8}
All real numbers greater than or equal to -5 and less than or equal to 8
Range is the interval for y
[-3,2]
All real numbers greater than or equal to -3 and less than or equal to 2
Due 05/05/200:00Tickets to a school play cost $3 for students and $8 for adults. On opening night, $1,000 was collected and 150 tickets sold Use substitution to solvea system of equations to find how many of each kind of ticket were sold? Enter your answers in the boxesstudent ticketsadult tickets
We will use the next variables
x is the number of tickets sold for students
y is the number of tickets sold for adults
First equation
x+y=150
Second equation
3x+8y=1000
we isolate the x of the first equation
x=150-y
we substitute the equation above in the second equation
3(150-y)+8y=1000
450-3y+8y=1000
we sum like terms
5y=1000-450
5y=550
y=550/5
y=110
Then we substitute the value of y in the equation with x isolate
x=150-y=150-110=40
x=40 and y=110
The students sold
40 tickets for students
110 tickets for adults