graph at least one full cycle of the following trig function, lable the amplitude midline and maximum and the intervals f(x)=2sin(x-pi/2)-1

Answers

Answer 1
[tex]\begin{gathered} f(x)=2\sin (x-\frac{\pi}{2})-1 \\ Maximum=1 \\ \text{midline}=\frac{1+(-3)}{2}=\frac{1-3}{2}=\frac{-2}{2}=-1 \\ \text{midline}=-1 \\ The\text{ midline is y=-1} \\ \text{Interval = (0,2}\pi\text{)} \end{gathered}[/tex]

Graph At Least One Full Cycle Of The Following Trig Function, Lable The Amplitude Midline And Maximum

Related Questions

identify the reflection of the figure with vertices P (2, -12), Q (-3, 13), and R (-5, - 15) across the x-axis.

Answers

EXPLANATION:

We are given the following coordinates for a figure on the coordinate plane;

[tex]\begin{gathered} P(2,-12) \\ Q(-3,13) \\ R(-5,-15) \end{gathered}[/tex]

To reflect any figure or any set of coordinates across the x-axis, we shall apply the rule;

[tex](x,y)\rightarrow(x,-y)[/tex]

Note that the x-coordinate remains the same whereas, the y-coordinate changes its sign.

Imagine folding a graph page in two equal halves along the horizontal axis. You'll observe the y-coordinates will switch sides from top to bottom (positive to negative) or bottom to top (negative to positive). The x-coordinate remains the same since moving the folded page does not affect values along the horizontal line.

Therefore, for the vertices given, the reflection across the x-axis would be;

[tex]P(2,-12)\rightarrow P^{\prime}(2,12)[/tex][tex]Q(-3,13)\rightarrow Q^{\prime}(-3,-13)[/tex][tex]R(-5,-15)\rightarrow R^{\prime}(-5,15)[/tex]

ANSWER:

The coordinates of the reflection across the x-axis therefore will be;

[tex]\begin{gathered} P^{\prime}(2,12) \\ Q^{\prime}(-3,-13) \\ R^{\prime}(-5,15) \end{gathered}[/tex]

Use elimination to solve each system of equations.4x + y = 233x - y = 12Use elimination to solve each system of equations.4x + y = 233x - y = 12

Answers

ANSWER

The solution is (5, 3)

EXPLANATION

To use elimination method, we have to subtract (or add) one equation from the other, in order to eliminate one of the variables. Then we'll have one equation with one variable. We solve it for that variable and then replace into one of the equations of the system to solve for the eliminated variable.

In these equations, we have +y in the first one and -y in the second one. We can add both equations to eliminate y:

[tex]\begin{gathered} (4x+y)+(3x-y)=23+12 \\ 4x+3x+y-y=35 \\ 7x=35 \end{gathered}[/tex]

Solving for x:

[tex]\begin{gathered} 7x=35 \\ x=\frac{35}{7} \\ x=5 \end{gathered}[/tex]

Now, we have to replace x = 5 into one of the equations and solve for y. Replacing in the first equation:

[tex]\begin{gathered} 4x+y=23 \\ 4\cdot5+y=23 \\ 20+y=23 \\ y=23-20 \\ y=3 \end{gathered}[/tex]

The solution to this system is (5, 3)

Select the following sentence that represents the equation below:

3(n2+1)=3n+12
Responses

The sum of the product of two and a number plus one times three is equal to twelve more than the product of three and the same number.
The sum of the product of two and a number plus one times three is equal to twelve more than the product of three and the same number., EndFragment,

Three times the sum of twice a number and one is equal to twelve less than the product of three and the same number.
Three times the sum of twice a number and one is equal to twelve less than the product of three and the same number., EndFragment,

The quotient of a number and two increased by one is equal to twelve more than the quotient of three and the same number.
The quotient of a number and two increased by one is equal to twelve more than the quotient of three and the same number., EndFragment,

Three times the sum of a number divided by two and one is equal to three times the same number increased by twelv

Answers

The answer is, Three times the sum of twice a number and one is equal to twelve less than the product of three and the same number.

Three times the sum of twice a number and one is equal to twelve less than the product of three and the same number.

What is a quotient?

It has a wide spread throughout the Mathematics. It is referred to as the integer part of a division, or as the fraction, or as a ratio. It is used when indicating the presence or the degree of a characteristic in something or by someone. Quotient is the result of a division. It is obtained when we divide one number by another. Quotient means how many times. And it is derived from the Latin.

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write a quadratic function whose graph has the given characteristicsvertex: (1,2)Point: (3,6)

Answers

Solution

For this case the general expression for a parabola is given by:

y- k= a(x-h)^2

From the info given we know that h = 1 and k= 2

And replacing we got:

y -2 = a(x-1)^2

And replacing the point given we got:

6-2 = a(3-1)^2

4= 4a

a=1

And the equation would be given by:

y-2 = (x-1)^2

16. The table below shows the population of California from 2010 to 2019.

Answers

The Solution:

The Regression Model that best fits the data given in the question is

[tex]P(t)=\frac{a}{1+e^{-bt}}[/tex]

From the Desmos plotter analysis attached above, we have that

[tex]\begin{gathered} a=74.907\approx74.91 \\ b=0.01397\approx0.01 \end{gathered}[/tex]

So, by substituting the values of the parameters, we get the required logistic Regression Model is given below:

[tex]P(t)=\frac{74.91}{1+e^{-0.01t}}[/tex]

b. The model predicts that the population of California in 2025 will be:

[tex]\begin{gathered} \text{From 2010 to 2025 is 25 years.} \\ So,\text{ t=25 years.} \\ S\text{ubstituting 25 for t in the regression model, we get} \end{gathered}[/tex]

[tex]P(t)=\frac{74.91}{1+e^{-0.01(25)}}=\frac{74.91}{1+0.77088}=\frac{74.91}{1.77088}=42.1127\approx42.1\text{ million people.}[/tex]

So, the population of California in 2025 will be 42.1 million people.

c. To find when the model predicts that the population of California will be 40 million,

we shall substitute 40 (in millions) for P in the model, and find t as below:

[tex]40=\frac{74.91}{1+e^{-0.01t}}[/tex]

Cross multiplying, we get

[tex]\begin{gathered} 40(1+e^{-0.01t})=74.91 \\ \text{Dividing both sides by 40},\text{ we have} \\ 1+e^{-0.01t}=\frac{74.91}{40} \\ \\ 1+e^{-0.01t}=1.87275 \\ e^{-0.01t}=1.87275-1 \\ e^{-0.01t}=0.87275 \end{gathered}[/tex]

Taking the ln of both sides, we get

[tex]\begin{gathered} \ln e^{-0.01t}=\ln 0.87275 \\ -0.01t=\ln 0.87275 \\ -0.01t=-0.136106 \\ \text{ Dividing both sides by -0.01, we get} \\ t=\frac{-0.136106}{-0.01}=13.61\approx14\text{ years} \end{gathered}[/tex]

So, 14 years from 2010 will be in the year 2024

d. According to the model, the carrying capacity for California's capacity is 74.9 million people.

Santa is saving money for a new bike that costs $175.62. He already has $39.59. How much more does he need to save before he can buy a bike?

Answers

Given

Santa is saving money for a new bike that costs $175.62. He already has $39.59.

Answer

Total money needed = 175.62 - 39.59 = $136.03

solve system of equations by substution { y=3x+19{ y=5x+33

Answers

Given:

[tex]\begin{gathered} y=3x+19\ldots\ldots\ldots(1) \\ y=5x+33​\ldots\ldots\ldots(2) \end{gathered}[/tex]

To solve: The system of equations by substitution

Explanation:

Substituting equation (1) in equation (2), we get

[tex]\begin{gathered} 3x+19=5x+33 \\ 3x-5x=33-19 \\ -2x=14 \\ x=-7 \end{gathered}[/tex]

Substitute the x value in equation (1), we get

[tex]\begin{gathered} y=3(-7)+19 \\ y=-21+19 \\ y=-2 \end{gathered}[/tex]

Final answers: The solutions are,

[tex]\begin{gathered} x=-7 \\ y=-2 \end{gathered}[/tex]

I don't know if -32 is greater or less than 15

Answers

Answer: -32 is less than 15.

Step-by-step explanation: 15 is greater than zero therefore it is not a negative number. -32 is less than 0 therefore it is a negative number. Negatives will always be less than positives.

The arcade charges $125.00 to reserve the location, and then $15.00 per person. Which expressionrepresents the total cost for any number of people n?

Answers

Let 'n' represent the number of people. Sin the arcade charces 15 per person, then we have the following first term:

[tex]15n[/tex]

since the charge to reserve is $125, we have:

[tex]15n+125[/tex]

thus, if 'c' represents the total cost, then the expression to represent this situation is:

[tex]c=15n+125[/tex]

Hi this is one of my exit ticket problem can you solve it please.

Answers

The triangles that are similar is A and B

Alex has a box of chocolates which are all
flavoured with either caramel or raspberry.
The possible outcomes of Alex picking two
chocolates at random are shown in the tree
diagram below.
If both chocolates are the same flavour, what
is the probability that they are both
raspberry?
Give your answer as a fraction in its simplest
form.

Answers

Probability that they are both raspberry = 5/33

From the question, we have

probability that they are both raspberry = 5/12*4/11

=5/33

Probability:

Possibility is referred to as probability. This branch of mathematics deals with the occurrence of a random event. The value's range is 0 to 1. Probability has been applied into mathematics to predict the likelihood of different events. Probability generally refers to the degree to which something is likely to occur. This fundamental theory of probability, which also applies to the probability distribution, can help you comprehend the possible outcomes for a random experiment. Gonna determine how likely something is to occur, use probability. Many things are hard to predict with 100% certainty. We can only anticipate the possibility of an event occurring using it, or how likely it is.

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second blank has the option of , the same verticle asymptote as function h, vertical asymptote at x=-7, vertical asymptote at x=-5, and vertical asymptote at x=3

Answers

Given:

The graph is g(x) is given and the function h(x) is,

[tex]h(x)=g(x+5)[/tex]

To classify the asymptotes:

Since the translated transformation of 5 units left,

There are no changes in the horizontal asymptote.

But, the vertical asymptote is,

[tex]\begin{gathered} x=-2-5 \\ =-7 \end{gathered}[/tex]

Thus, the graph h(x)=g(x+5) has the same horizontal asymptote as the function g

Inderstanding ocabulary Are 23 and 24 adjacent angles? Explain. 1. 2. 3. 4 3 4 3 4 3 . Reasoning Does every angle have a complement? Explain. ises For more exercises, see Extra Skills and Word Problem me a pair of vertical and adjacent angles in each figure. Find m21.

Answers

By definition, two angles are adjacent if they share one side and the vertex.

To determine if ∠3 and ∠4 are adjacent, you have to look at each image and determine if they share the vertex and one side:

1.

In this image ∠3 and ∠4 share, the vertex but they do not share one side, this indicates that these angles are not adjacent.

2.

In this image ∠3 and ∠4 share the vertex and one side (blue line), which indicates that they are adjacent angles.

3.

In this image ∠3 and ∠4 share one side (blue line) but each angle has its own vertex (green dots). You cannot conclude these angles are adjacent.

4.

Two angles are complementary of they add up to 90º, they don't necesarly have to be adjacent.

Any acute angle, meaning, any angle that measures less than 90º, has a complement.

For example, you have the following angles:

- If both ∠1 and ∠2 are acute angles and complementary, then we know that they add up to 90º:

[tex]\angle1+\angle2=90º[/tex]

-For example, ∠1= 46º, then you can determine the measure of ∠2 as follows:

[tex]\begin{gathered} \angle2=90º-\angle1 \\ \angle2=90-46 \\ \angle2=44º \end{gathered}[/tex]

Both ∠1=46º and ∠2=44º are acute and add up to 90º

-If one of the angles is a right angle, for example, ∠2=90º, then no matter what measure does ∠1 take, they will never add up to 90º.

We can say that right angles do not have a complement.

-If one of the measures of the angles is more than 90º (it is an obtuse angle), let's say, for example, ∠1= 124º, no matter what measure ∠2 has, if you add both angles, they will never add up to 90º.

So we can say that obtuse angles have no complements.

In conclusion, not all angles can have a complement, only acute angles have complements.

if andrew can run 60 meters in 6 seconds, how many meters can he run in 1 second?

Answers

Explanation

Step 1

the sp

Please I need help on this ASAP

Answers

The value of the function h(x) in part (a) is equal to h(x) = 2x.

The value of the function h(x) in part (b) is equal to h(x) = 5x/2 - 2.

How to determine the function h(x)?

In this exercise, you are required to calculate the value of the function h(x), which is a product of the addition of function f(x) and function g(x). This ultimately implies that, the value of function h(x) can be calculated by adding function f(x) and function g(x) together.

For the first part (a), the value of function h(x) would be calculated as follows:

Function h(x) = Function f(x) + Function g(x)

Substituting the given parameters into the formula, we have;

Function h(x) = (x + 4) + (x - 4)

Function h(x) = x + 4 + x - 4

Function h(x) = 2x

For the second part (b), the value of function h(x) would be calculated as follows:

Function h(x) = Function f(x) + Function g(x)

Substituting the given parameters into the formula, we have;

Function h(x) = (2x - 4) + (x/2 + 2)

Function h(x) = 2x - 4 + x/2 + 2

Function h(x) = 5x/2 - 2.

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10. f(x) = 2x+5 if x < 4 1x² + 3x if x 24 LX D = R =

Answers

Answer:[tex]\begin{gathered} D=(-\infty,\infty) \\ \\ R=(-\infty,-3)\cup\lbrack-\frac{9}{4},\infty) \end{gathered}[/tex]

Explanation:

The domain of the given piecewise function are all the values that x can take.

These are:

x < -4 and

[tex]x\ge-4[/tex]

It can be written as:

[tex](-\infty,\infty)[/tex]

The range is:

[tex](-\infty,-3)\cup\lbrack-\frac{9}{4},\infty)[/tex]

Find the prime factorization of 54 from least to greatest; then write it using exponents.

Answers

The prime factorization of 54 is

54 = 2 × 3 × 3 ×3

Using the exponential form of the prime factorization that is

54 = 2 × 3³

Martha opened a savings account and deposited 400.00 the account earns 1%interest compounded annually what is the balance after 3 years

Answers

p = 400.00

r = 1% = 1/100 = 0.01

t = 3 years

Therefore,

[tex]\begin{gathered} Amount=p(1+\frac{r}{n})^{nt} \\ \text{Amount}=400(1+\frac{0.01}{1})^{1\times3} \\ \text{Amount}=400\times1.030301 \\ \text{Amount}=\text{ \$}412.1204 \\ \text{Amount}=\text{ \$412.12} \end{gathered}[/tex]

After three years the amount will be = $412.12

How many distinct rearrangements of the letters in 'PUYGPGPYYUG' are there?

Answers

The answer is 92400

To solve this, we can count how many letters we have. There are 11 letters.

If those 11 letters were different from each other, the answer would be 11!

But we have letters that repeats:

3 P's

3 Y'2

3 G'2

2 U's

Since we want to know the quantity of distinct arrangements, we can divide by the repetition. This means:

[tex]\begin{gathered} 11!\text{ = total combinations} \\ \frac{11!}{3!\cdot3!\cdot3!\cdot2!}=\text{total distinct combinations} \end{gathered}[/tex]

We divide by 3! times 3! times 3! times 2!, because we have 3P's, 3Y's, 3G's and 2U's

Then on the calculator write the division and give us the answer 92400

Woad holder mange en windows-17Grado2rean, thetwo w Wawie kan 137( wow month am wa mama w War[mmer

Answers

a) The temperature at Milwaukee by 6am is given to be -5 degree fahrenheit.

By noon, this temperature has risen to 13 degree fahrenheit, thus this implies;

[tex]-5+13=8^0F[/tex]

Hence, the temperature at Milwaukee by noon will be 8 degree fahrenheit

b) Temperature in Winnipeg = -17 degree fahrenheit

Temperature in Orlando = 61 degree fahrenheit

Temperature in Winnipeg is lower than in Orlando implies;

[tex]61-(-17)=61+17=78^0F[/tex]

Hence, the temperature in Winnipeg is 78 degree fahrenheit lower than in Orlando

Complete the synthetic division work below to divide 5x^3 - 3x^2 + 2x - 1 by x+1 Fill in the blank with the four numbers that would go below the line. Separate numbers by commas. 5 -3 2 - 1

Answers

Abraham, this is the solution of the polynomials division:

5x^3 - 3x^2 + 2x - 1/ x+1

Step 1:

5x² + (-8x² + 2x - 1)/(x + 1)

Step 2:

5x² - 8x + (10x - 1)/(x + 1)

Step 3:

5x² -8x + 10 + (-11/x + 1)

The four numbers below the line are: 5 -8 10 - 11

Find from first principles the derivative of f(x)= root of X with respect to x

Answers

To find:

The derivative of function f(x) using the first principle.

[tex]f(x)=\sqrt{x}[/tex]

Solution:

By the first principle, the derivative of the function f(x) is given by:

[tex]f^{\prime}(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}[/tex]

So, the derivative of the given function can be obtained as follows:

[tex]\begin{gathered} f^{\prime}(x)=\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt{x}}{h} \\ =\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt{x}}{h}\times\frac{\sqrt{x+h}+\sqrt{x}}{\sqrt{x+h}+\sqrt{x}} \\ =\lim_{h\to0}\frac{x+h-x}{h(\sqrt{x+h}+\sqrt{x})} \\ =\lim_{h\to0}\frac{h}{h(\sqrt{x+h}+\sqrt{x})} \\ =\lim_{h\to0}\frac{1}{(\sqrt{x+h}+\sqrt{x})} \\ =\frac{1}{\sqrt{x+0}+\sqrt{x}} \\ =\frac{1}{2\sqrt{x}} \end{gathered}[/tex]

Thus, the derivative of the given function is:

[tex]f^{\prime}(x)=\frac{1}{2\sqrt{x}}[/tex]

Look at the four company logos below.VolkswagenLincolnLexusRed Cross0♡+The logo for Volkswagen haslines of symmetry.The logo for Lincoln haslines of symmetry.The logo for Lexus haslines of symmetry.The logo for Red Cross has4lines of symmetry.:: 0.: 1:: 2

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Figures logos

Lines of symmetry = ?

Step 02:

We must analyze the logos to find the solution.

Volkswagen ===> 1 line of symmetry

Lincoln ===> 2 lines of symmetry

Lexus ===> 0 lines of symmetry

Red Cross ===> 4 lines of symmetry

That is the solution.

Answer:

VW: 1

Lincoln: 2

Lexus: 0

Red Cross: 2

Step-by-step explanation:

VW can be split in half once, and have the same thing son both sides.

Lincoln be split in half horizontally and vertically and be identical on both sides

Lexus cannot be split in half at all and be identical.

The red cross can be split horizontally and vertically and still have identical pieces.

-Hope this helped

the answer and how to figure questions out like this!

Answers

Exponential regression

In order to find the exponential regression we are going to select some values of the given data.

STEP 1

An special value is when x=0.

On the table we can see that when x=0 then y=9

Replacing x by 0 in the given choices, we have that:

[tex]\begin{gathered} A\text{.} \\ y=8.04\cdot0.98^x \\ \downarrow \\ y=8.04\cdot0.98^0=8.04\cdot1 \\ =8.04 \end{gathered}[/tex]

[tex]\begin{gathered} B\text{.} \\ y=3.02\cdot3.67^x \\ \downarrow \\ y=3.02\cdot3.67^0=3.02\cdot1 \\ =3.02 \end{gathered}[/tex]

[tex]\begin{gathered} C\text{.} \\ y=6.61\cdot1.55^x \\ \downarrow \\ y=6.61\cdot1.55^0=6.61\cdot1 \\ =6.61 \end{gathered}[/tex]

[tex]\begin{gathered} D\text{.} \\ y=2.27\cdot2.09^x \\ \downarrow \\ y=2.27\cdot2.09^0=2.27\cdot1 \\ =2.27 \end{gathered}[/tex]

Observing the results we have that the two choices with closer results to 9 are A (with 8.04) and C (with 6.61)

STEP 2

Now, we are going to select two additional values from the table in order to find which is the best answer: A or C.

Let's take x=1.

When x = 1, then y=10.

Replacing on the equation A we have:

[tex]\begin{gathered} A\text{.} \\ y=8.04\cdot0.98^x \\ \downarrow \\ y=8.04\cdot0.98^1=8.04\cdot0.98 \\ =7.879 \end{gathered}[/tex]

and for the equation C:

[tex]\begin{gathered} C\text{.} \\ y=6.61\cdot1.55^x \\ \downarrow \\ y=6.61\cdot1.55^1=6.61\cdot1.55 \\ =10.2455 \end{gathered}[/tex]

For x=1, the nearest result is from the equation C.

Let's verify what happens when x=2.

When x=2 then y=16. Replacing on the equation A we have:

[tex]\begin{gathered} A\text{.} \\ y=8.04\cdot0.98^x \\ \downarrow \\ y=8.04\cdot0.98^2 \\ =7.7216 \end{gathered}[/tex]

and for the equation C:

[tex]\begin{gathered} C\text{.} \\ y=6.61\cdot1.55^x \\ \downarrow \\ y=6.61\cdot1.55^2 \\ =15.88 \end{gathered}[/tex]

Again, for x=2, the nearest result is from the equation C.

Then, we can conclude that the best candidate is equation C.

We could try other values of x to double check:

[tex]\begin{gathered} C\text{.} \\ y=6.61\cdot1.55^x \\ \downarrow \\ y=6.61\cdot1.55^2 \\ =15.88 \end{gathered}[/tex]

The shorter leg of a 30°-60°-90° triangle measures 9sqrt3 inches. What is the length of the longer leg? OA. 27 inches OB. 27sqrt3 inches OC. 18 inches OD. 18sqrt3 inches

Answers

We know that the proportion of the sides of a 30°-60°-90° triangle is:

The shorter leg is K, then:

[tex]K=9\sqrt[]{3}\text{ in}[/tex]

Using this result, we can calculate the length of the longer leg:

[tex]\begin{gathered} \sqrt[]{3}K=\sqrt[]{3}\cdot9\cdot\sqrt[]{3}=9\cdot3 \\ \Rightarrow=27\text{ in} \end{gathered}[/tex]

If F(x) =8+11 X-3X², finda. What is F (5)? b. What is F (x + b)?c. What is F (-3)?

Answers

[tex]\begin{gathered} \text{Given} \\ F(x)=8+11x-3x^2 \end{gathered}[/tex]

a. Solve for F(5).

To solve for F(5), substitute x = 5 to the given function, and evaluate accordingly to the operation

[tex]\begin{gathered} F(x)=8+11x-3x^2 \\ F(5)=8+11(5)-3(5)^2 \\ F(5)=8+55-3(25) \\ F(5)=63-75 \\ F(5)=-12 \end{gathered}[/tex]

b. Solve for F(x+b)

Again we substitute the paremeters by x+b to the given function, and we get

[tex]\begin{gathered} F(x)=8+11x-3x^2 \\ F(x+b)=8+11(x+b)-3(x+b)^2 \\ F(x+b)=8+11x+11b-3(x^2+2xb+b^2) \\ F(x+b)=8+11x+11b-3x^2-6xb-3b^2 \\ \\ \text{Since we cannot simplify further, we just rearrange} \\ \text{the final answer according to the degree of the terms} \\ F(x+b)=-3x^2-3b^2-6xb+11x+11b+8 \end{gathered}[/tex]

c. Solve for F(-3)

Substitute x = -3

[tex]\begin{gathered} F(x)=8+11x-3x^2 \\ F(-3)=8+11(-3)-3(-3)^2 \\ F(-3)=8-33-3(9) \\ F(-3)=-25-27 \\ F(-3)=-52 \end{gathered}[/tex]

Internet rates for two companies are shown in the table. After how many months of service is the total cost thesame no matter which company is used? What is this total cost?Intemet Service ProviderChargesTyson's Ethernet $100 activation fee plus $20 per monthDarriana's DSL$30 per month

Answers

We need to find in which month we have that the total cost is the same, so we are going to do the equations of cost of the two companies

For the Tyson's Ethernet we have that the equation is

[tex]f(m)=20\cdot m+100[/tex]

with m the month. And for the Darriana's DSL the equation is

[tex]g(m)=30\cdot m[/tex]

We need to equalize the equations, so we have

[tex]\begin{gathered} 30m=20m+100 \\ 30m-20m=20m+100-20m \\ 10m=100 \\ m=\frac{100}{10}=10 \end{gathered}[/tex]

Now to see the cost we replace in the two equations( wiith this we also verify), we have that

[tex]\begin{gathered} f(10)=20\cdot10+100=200+100=300 \\ g(10)=30\cdot10=300 \end{gathered}[/tex]

The answer is: after 10 months the total cost is the same, and this cost is $300.

Lily drank 2 1/2 cartons of juice in the month of January. In the month of February, she drank twice as many cartons of juice as in January. How many cartons of juice did she drink in February?

Answers

Answer:

Lily drank 5 cartons of juice in February.

Explanation:

From the question, we're told that in January, Lily drank 2 1/2 cartons of juice and drank twice of that amount in February, so all we need to do is multiply the amount she drank in January by 2 to get the amount she drank in February.

Solving this, we'll have;

[tex]2\ast(2\frac{1}{2})=2\ast(\frac{5}{2})=5[/tex]

Therefore, Lily drank 5 cartons of juice in February.

Use the 'Permutations' formula to evaluate the expression P(27,3)

Answers

The permutation formula is given as:

[tex]P(n,k)=\frac{n!}{(n-k)!}[/tex]

In this case n=27 and k=3; plugging the values in the formula we have:

[tex]P(27,3)=\frac{27!}{(27-3)!}=\frac{27!}{24!}=\frac{27\cdot26\cdot25\cdot24!}{24!}=27\cdot26\cdot25=17550[/tex]

Therefore, we have that P(27,3)=17550

Answer the statistical measures and create a box and whiskers plot for the followingset of data.4,4,5,5,5,6,6, 8, 9, 10, 12, 14, 14, 15, 17

Answers

Notice that the set of data is already ordered from lowest to highest, therefore the minimum value is 4 and the maximum value is 17.

The median is 8, the first quartile Q₁=5, and Q₃=14.

Then, the corresponding box and whiskers plot is:

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