Vector performed an experiment at a local farm to determine if the addition of bananas to his biomass cow menure recipe helps produce more or less energy. Me collected random samples of menure and benenes from the farm, prepared 15 bottles each of both matures, and placed oballeen on top of each bottle. Alter two weeks, he measured the circumference of each balloon in centimeters: the bigger the balloon grew, the more energy that was produced. The results of the experiment are displayed in the box plots below. Which description most accurately summarizes the sample results? 10. 11. 13. 13. 14. 15. 15. 15. 18. 18. 19 20. 22. 25. 26 22.22.26 29 30 31 36. 36 38. 39. 43 46. 46. 49. 50 MORE CONSISTENT LESS S OUT THE Autor behind ONE CON nece MORE

Vector Performed An Experiment At A Local Farm To Determine If The Addition Of Bananas To His Biomass

Answers

Answer 1

Notice the smaller range and values of the experiment with cow manure (smaller box diagram and also located at smaller values of total energy.

The banana mixture clearly generates a wider box diagram (so less consistent) and also located at higher values (to the right).

Therefore, the answer we choose is the last one (bottom right) that says that the cow manure data is more consistent than the other one, and also, since the mashed banana data is so much higher, combined with the previous will clearly give larger amounts of biogas.

Please select the bottom right option.


Related Questions

log2 z + 2 log2 x + 4 log, y + 12 logg x - 2 log2 y

Answers

[tex]\log _2(z)+2\log _2(x)+4\log (y)+12\log (x)-2\log _2(y)[/tex]

apply the property of the potency for those that have coefficients

[tex]b\cdot\log x=\log (x^b)[/tex]

apply the product property and the quotient product to leave it as a single log

[tex]\begin{gathered} \log (a)+\log (b)=\log (a\cdot b) \\ \log (a)-\log (b)=\log (\frac{a}{b}) \end{gathered}[/tex]

simplify the expression using this properties

[tex]\begin{gathered} \log _2(z)+2\log _2(x)+4\log (y)+12\log (x)-2\log _2(y) \\ \log _2(z)+\log _2(x^2)+\log (y^4)+\log (x^{12})-\log _2(y^2) \\ \log _2(x^2z)+\log (x^{12}y^4)-\log _2(y^2)^{} \\ \log _2(\frac{x^2z}{y^2})+\log (x^{12}y^4) \end{gathered}[/tex]

Use it in a lot and it can take forever

Answers

Part 1

Remember that

The rate of change is the same that the first derivative

so

The rate of change appears to be zero at times

t=1 weeks

t=4 weeks

t=6 weeks

Part 2

which of the following is true?

Verify each option

W'(3) > W'(7) -----> is not true

W'(3) < W'(7) -----> is true

W'(3)=W'(7) is not true

which of the following is true?

Verify each option

W'(0) < W'(5) -----> is true

therefore

the graph is

What is -1.47 rounded to four decimal places as needed?

Answers

Given the negative number

[tex]-1.47[/tex]

Four decimal places implies there should be four digits after the decimal point. in the absence of no digit, add zero to complete the number of required decimal place. To round the number above to four decimal places, we will have

[tex]-1.4700[/tex]

Hence, -1.47 rounded to four decimal places is -1.4700

Sample proportion of .14 and standard deviation of.02, use empirical rule to construct a 95% confidence interval

Answers

The empirical rule states that 65% of the data under the normal curve is within 1 standard deviation of the mean, 95% of the data is within 2 standard deviations of the mean, and 99% is within 3 standard deviations of the mean.

The approximation to the distribution of the sample proportion has the following shape:

[tex]\hat{p}\approx(p;\frac{p(1-p)}{n})[/tex]

The mean of the distribution is the sample proportion: μ= p

The standard deviation of the distribution is the square root of the variance

σ=√[p(1-p)/n]

For the given distribution:

μ= 0.14

σ= 0.02

95% of the distribution is μ ± 2σ

Upper bound:

[tex]\mu+2\sigma=0.14+2\cdot0.02=0.18[/tex]

Lower bound:

[tex]\mu-2\sigma=0.14-2\cdot0.02=0.10[/tex]

The 95% confidence interval is [0.10;0.18]

The following data for a random sample of banks in two cities represent the ATM fees for using another bank's ATM. Compute the range and sample standard deviation for ATM feesfor each city. Which city has the most dispersion based on range? Which city has more dispersion based on the standard deviation?City A 2.50 1.50 1.25 0.00 2.00City B 1.25 1.00 1.50 1.00 1.00

Answers

Given:

City A: 2.50 1.50 1.25 0.00 2.00

City B: 1.25 1.00 1.50 1.00 1.00

To find dispersion based on range:

The difference between the maximum and minimum values in a set of data is the range.

2.5 is the maximum value of data of city A and 0.00 is the minimum value of data of city A.

Hence, the range of data of city A is,

[tex]R_A=2.50-0.00=2.50[/tex]

1.5 is the maximum value of data of city B and 1.00 is the minimum value of data of city B.

Hence, the range of data of city B is,

[tex]R_B=1.50-1.00=0.50[/tex]

Since the range of city A is greater than that of city B, city A has most dispersion based on range.

To find dispersion based on the standard deviation:

The data for city A is,

2.50 1.50 1.25 0.00 2.00

The mean of city A is,

[tex]\begin{gathered} \mu_A=\frac{2.5+1.5+1.25+0+2}{5} \\ =1.45 \end{gathered}[/tex]

Let each individual value is represented by xi. Then, the squared difference of each individual value of city A is,

[tex](x_i-\mu_A)^2[/tex]

Now, find the square of difference of each individual value of city A is,

[tex]\begin{gathered} _{}(2.5-1.45)^2=(1.05)^2=1.1025 \\ (1.5-1.45)^2=(0.05)^2=0.0025 \\ (1.25-1.45)=(-0.2)^2=0.04 \\ (0.00-1.45)^2=(-1.45)^2=2.1025 \\ (2.00-1.45)^2=(0.55)^2=0.3025 \end{gathered}[/tex]

The number of values in the data set is n=5.

Let each individual value is represented by xi, then the sample standard deviation is,

[tex]S_A=\frac{1}{n-1}\sum ^n_{i\mathop=1}(x_i-\mu_A)^2[/tex]

Hence, the sample standard deviation of city A can be calculated as,

[tex]\begin{gathered} S_A=\sqrt{\frac{1}{5-1}(1.1025+0.0025_{}+0.04+2.1025+0.3025)}_{} \\ =\sqrt[]{\frac{3.55}{4}} \\ =0.9420 \end{gathered}[/tex]

Therefore, the sample standard deviation of city A is 0.9420.

The data for city B is:

1.25, 1.00, 1.50, 1.00, 1.00

The mean of city B is,

[tex]\begin{gathered} \mu_B=\frac{1.25+1.00+1.50+1.00+1.00}{5} \\ =1.15 \end{gathered}[/tex]

Let each individual value is represented by xi. Then, the squared difference of each individual value of city B is,

[tex]\begin{gathered} (x_i-\mu)^2 \\ (1.25-1.15)^2=0.1^2=0.01 \\ (1.00-1.15)^2=(-0.15)^2=0.0225 \\ (1.5-1.15)^2=(0.35)^2=0.1225 \\ (1.00-1.15)^2=(-0.15)^2=0.0225 \\ (1.00-1.15)^2=(-0.15)^2=0.0225 \end{gathered}[/tex]

The number of values in the data set is n=5.

Let each individual value is represented by xi, then the sample standard deviation of city B is,

[tex]S_B=\frac{1}{n-1}\sum ^n_{i\mathop=1}(x_i-\mu_B_{})^2[/tex]

Hence, the sample standard deviation of city B can be calculated as,

[tex]\begin{gathered} S_B=\sqrt[]{\frac{1}{5-1}(0.01+0.0225_{}+0.1225+0.0225+0.0225)}_{} \\ =\sqrt[]{\frac{0.2}{4}} \\ =0.2236 \end{gathered}[/tex]

Therefore, the sample standard deviation of city B is 0.2236.

Since the standard deviation of city A is greater than that of city B, city A has more dispersion based on the standard deviation.

Plot -5½ and 8½ on the number line below.

Answers

1) Let's plot those values on a number line. Since -5 1/2 and 8 1/2 can be written as -5.5 and 8.5

2) There we have:

The points H(-8,-1),I (-6,-9), J (-2,-8) and K (-4,0) form a quadrilateral. Find the desired slopes and lengths, then fill in the words that best identifies the type of quadrilateral

Answers

Answer:

[tex]\text{Quadrilateral HJLK is a }Rec\tan gle[/tex]

Explanation:

Here, we want to find the slopes and lengths of the sides of a quadrilateral

To find the slopes, we use the equation:

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]

To find the length, we use the equation:

[tex]L\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We take the sides one after the other

a) HI

We have the slope as:

[tex]m\text{ = }\frac{-9+1}{-6+8}\text{ = }\frac{-8}{2}\text{ = -4}[/tex]

We have the length as:

[tex]\begin{gathered} \sqrt[]{(-6+8)^2(-9+1)^2} \\ =\text{ }\sqrt[]{4+64} \\ =\text{ }\sqrt[]{68} \end{gathered}[/tex]

b) IJ

We have the slope as:

[tex]m\text{ = }\frac{-8+9}{-2+6}\text{ = }\frac{1}{4}[/tex]

We have the length as:

[tex]\begin{gathered} IJ\text{ = }\sqrt[]{(-6+2)^2+(-8+9)^2} \\ IJ\text{ = }\sqrt[]{17} \end{gathered}[/tex]

c) JK

Slope:

[tex]m\text{ = }\frac{-8+0}{-2+4}\text{ = -4}[/tex]

Length:

[tex]\begin{gathered} JK\text{ = }\sqrt[]{2^2+(-8)^2} \\ JK\text{ = }\sqrt[]{68} \end{gathered}[/tex]

D) KH

Slope:

[tex]m\text{ = }\frac{0+1}{-4+8}\text{ = }\frac{1}{4}[/tex]

Length:

[tex]\begin{gathered} KH\text{ = }\sqrt[]{(-4+8)^2+(0+1)^2} \\ KH\text{ = }\sqrt[]{17} \end{gathered}[/tex]

From the answers obtained, the side lengths KH and IJ are the same, while the side lengths JK and KI are the same

Also, looking at the slopes, when the product of the slopes of two lines equal -1, the two lines are perpendicular

Since:

[tex]\frac{1}{4}\times\text{ (-4) = -1}[/tex]

We can conclude that a set of two sides(KH, JK and HI, IJ) are perpendicular

Thus, we have it that the quadrilateral is a rectangle

1. Which of the following is not a radical expression that is equivalent to √1087A.B.C.D.√2-√54√3-√36√5-√21√6-√18

Answers

The radical expression √108 is not equivalent to the expression √5√21 .

Given the radical expression as √108 .

Now the number 108 can be broken down into factors as

108 = 54 × 2 , 36 × 3 , 18×6

therefore we can see that the radical expression is equivalent to

√108 = √54 × √2

√108 = √36 × √3

√108 = √18 × √6

But 21 × 5 = 105 ≠ 108.

Therefore the radical expression √108 is not equivalent to √5√21 .

Expressions in mathematics are statements with variables, numbers, or both, and at least two terms joined by an operator. Mathematical operations include addition, subtraction, multiplication, and division.

In mathematics, there are two types of expressions: numerical expressions, which only contain numbers, and algebraic expressions, which also contain variables.

A symbol with an unknown value is called a variable. A term can be made up of a single constant, a single variable, or a group of variables and constants multiplied or divided. A number that has been further multiplied by a variable serves as the coefficient in an equation.

Disclaimer: The complete question is :

Which of the following is not a radical expression that is equivalent to √108?

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Explicit rule that describes the rent in ‘n’ years. (Question 5)

Answers

Answer::

[tex]f(n)=62000(1.03)^n[/tex]

Explanation:

• The first year rent = $62,000

,

• The rate of increase, r = 3% = 0.03

Since the rent increases by a common factor each year, we can find the explicit rule by using the formula for the nth term of a geometric sequence.

The nth term of a geometric sequence is calculated using the formula:

[tex]T_n=a_1(r)^{n-1}[/tex]

In this case:

• a1 = 62,000

,

• r=1+0.03=1.03

Thus, an explicit rule that describes the rent after n years is:

[tex]f(n)=62000(1.03)^n[/tex]

Solve the system using graphing, substitution or elimination. If needed round soulutions to the nearest tenth

Answers

Given

The system of equations,

[tex]\begin{gathered} 9x+y=45\text{ \_\_\_\_\_\lparen1\rparen} \\ x^3-3x^2-25x+93=y\text{ \_\_\_\_\_\_\lparen2\rparen} \end{gathered}[/tex]

To find the solution.

Explanation:

It is given that,

[tex]\begin{gathered} 9x+y=45\text{ \_\_\_\_\_\lparen1\rparen} \\ x^3-3x^2-25x+93=y\text{ \_\_\_\_\_\_\lparen2\rparen} \end{gathered}[/tex]

From (1),

[tex]y=45-9x[/tex]

Substitute y in (2).

Then,

[tex]\begin{gathered} x^3-3x^2-25x+93=45-9x \\ x^3-3x^2-25x+9x+93-45=0 \\ x^3-3x^2-16x+48=0 \\ x^2(x-3)-16(x-3)=0 \\ (x-3)(x^2-16)=0 \\ (x-3)(x^2-4^2)=0 \\ (x-3)(x-4)(x+4)=0 \end{gathered}[/tex]

That implies,

[tex]\begin{gathered} x-3=0,x-4=0,x+4=0 \\ \text{ }x=3,\text{ }x=4,\text{ }x=-4 \end{gathered}[/tex]

Therefore, for x=3,

[tex]\begin{gathered} y=45-9\times3 \\ =45-27 \\ =18 \end{gathered}[/tex]

For x=4,

[tex]\begin{gathered} y=45-9\times4 \\ =45-36 \\ =9 \end{gathered}[/tex]

For x=-4,

[tex]\begin{gathered} y=45-(9\times-4) \\ =45+36 \\ =81 \end{gathered}[/tex]

Hence, the solution set is (3,18), (4,9), (-4,81).

Solve: 5(x + 3) = 2x -3

Answers

[tex]5(x+3)=2x-3[/tex]

we need to isolate x

first solve the parenthesis

[tex]5x+15=2x-3[/tex]

now solve x

[tex]\begin{gathered} 5x-2x=-3-15 \\ 3x=-18 \\ x=-\frac{18}{3} \\ x=-6 \end{gathered}[/tex]

the value of x is -6

hi! how do i find surface area of a cylinder? for some reason i can’t get the right answer

Answers

[tex]SA=2\pi r^2+2\pi rh[/tex]

Use the formula above to find the surface area of a cylinder.

For the given cylinder the given data is the height (6mi) and diameter (16mi), use the diameter to find the radius:

[tex]\begin{gathered} r=\frac{d}{2} \\ \\ r=\frac{16mi}{2}=8mi \end{gathered}[/tex]

Surface area:

[tex]\begin{gathered} SA=2\pi(8mi)\placeholder{⬚}^2+2\pi(8mi)(6mi) \\ SA=128\pi mi^2+96\pi mi^2 \\ SA=224\pi mi^2 \end{gathered}[/tex]Then, the surface area of the given cylinder is: 224π square miles

Find the equation of the circle that has a diameter with endpoints located at (7,3) and (7,-5). A. (x-7)²+(x+ 1)² = 16 B. (x-7)² + (-1)² =4 C. (x+1)²+(y-7)= 16 D. (x-7)²+(y+ 1)²= 64

Answers

Answer:

The equation of the circle is;

[tex]\mleft(x-7\mright)^2+\mleft(y+1\mright)^2=16[/tex]

Explanation:

Given that the circle has a diameter with endpoints located at (7,3) and (7,-5).

The diameter of the circle is the distance between the two points;

[tex]\begin{gathered} d=\sqrt[]{(7-7)^2+(3--5)^2_{}} \\ d=\sqrt[]{(0)^2+(3+5)^2_{}} \\ d=\sqrt[]{64} \\ d=8 \end{gathered}[/tex]

The radius of the circle is;

[tex]\begin{gathered} r=\frac{d}{2}=\frac{8}{2} \\ r=4 \end{gathered}[/tex]

The center of the circle is at the midpoint of the line of the diameter.

[tex]\begin{gathered} (h,k)=(\frac{7+7}{2},\frac{3-5}{2}) \\ (h,k)=(\frac{14}{2},\frac{-2}{2}) \\ (h,k)=(7,-1) \end{gathered}[/tex]

Applying the equation of a circle;

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Substituting the given values;

[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-7)^2+(y+1)^2=4^2 \\ (x-7)^2+(y+1)^2=16^{} \end{gathered}[/tex]

Therefore, the equation of the circle is;

[tex]\mleft(x-7\mright)^2+\mleft(y+1\mright)^2=16[/tex]

How to convert 9.4 degrees into feet and inches

Answers

The value of 9.4 degrees in feet is 0.1884 feet and in inches is 2.26 inches.

To calculate feet from degrees, divide the angle by 360, multiply by 2 times pi, then finally, multiply by the radius.

And feet to inches we know 1 foot equals 12 inches.

Converting degrees to feet is commonly discussed while looking at a circle and converting an angle to the length of the arc of that angle. When discussing latitude and longitude, that circle is frequently the earth.

The following formula is used to convert an angle in degrees to length in feet.

L = (a/360) * 2 * pi * r

Where,

L is the length in the feet.

a is the angle in degrees.

r is the radius of the circle in feet.

We are given 9.4 degrees.

Let r = 1 feet

Put the given values in the above formula, we will get;

L = (9.4/360) * 2 * pi * 1

L = 0.03 * 2 * 3.14 * 1

L = 0.1884 feet

L = 0.1884 * 12 = 2.26 inches.

Thus, the value of 9.4 degrees in feet is 0.1884 feet and in inches is 2.26 inches.

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Graph the solution of inequalities and shade in the solution set. If there are no solutions, graph the corresponding line and do not shade in any region. Y = grater and equal to 1/2x - 3 Y < - 2/3 x + 2

Answers

[tex]\begin{gathered} y\ge\frac{1}{2}x-3 \\ y<-\frac{2}{3}x+2 \end{gathered}[/tex]

start sketching the first inequality taking into account that it is all the region above the line of slope 1/2 and crosses over -3

then, do the same for the second equation over the same plane and look at the intersection

the shaded region should be the triangle at the left since the region is a solution to both inequalities.

Sphere 6.2 in diameter

Answers

ANSWER:

128.84 cubic inches.

STEP-BY-STEP EXPLANATION:

We have that the volume of a sphere is given by the following equation:

[tex]V=\frac{4}{3}\cdot\pi\cdot r^3[/tex]

The radius equals half the diameter, therefore we can calculate the radius as follows:

[tex]\begin{gathered} r=\frac{d}{2}=\frac{6.2}{2} \\ r=3.1 \\ \text{replacing and we calculate the volume:} \\ V=\frac{4}{3}\cdot\frac{22}{7}\cdot3.1^3 \\ V=128.84 \end{gathered}[/tex]

The volume of the sphere with the diameter of 6.2 is 128.84 cubic inches.

A Nintendo Switch handheld game has a screen that is 4 inches tall and 9.4 inches long, what is the diagonal distance across the screen? A. 13.4 inchesB. 10.22 inchesC. 9.4 inchesD. None of the above

Answers

EXPLANATION:

To calculate the diagonal distance we must follow the following steps:

-The length corresponds to the horizontal dimension of the screen.

-The height corresponds to the vertical dimension of the screen.

Now we must apply Pythagoras' theorem

[tex]\begin{gathered} a^2+b^2=c^2 \\ a=4 \\ b=9.4 \\ c=diagonal\text{ distance} \\ a^2+b^2=c^2 \\ (4)^2+(9.4)^2=c^2 \\ 16+88.36=c^2 \\ 104.36=c^2 \\ \sqrt[]{104.36=c} \\ c=10.21 \\ \text{ANSWER: 10.21 Inches} \end{gathered}[/tex]

Danielle plans to open a savings account with $2000. The bank offers 8% interest,compounded yearly. Which of the following functions can be used to find the projectedvalue of the account after t years?A.V (t) = 2,000 (1.08t)B. V (t) = 2,000 (1.8)^tC.V (t) = 2,000 (1.08)^tD. V (t) = 2,000 (1.008)^t

Answers

the formula for the compound interest is given as follows,

[tex]A=P(1+\frac{R}{100})^t[/tex]

here P = 2000 , R = 8 % , t = t.

so the value(V) is

[tex]\begin{gathered} V=2000(1+\frac{8}{100})^t \\ V=2000(1+0.08)^t \end{gathered}[/tex][tex]V=2000(1.08)^t[/tex]

so the answer is option C

A bag of popcorn contains 36 ounces. Your friend ate 14 of the bag. You eat 1/3 of what's left. How many ounces of popcorn did you eat?

Answers

Answer:

you ate 7.33333 (repeating) ounces of popcorn

Step-by-step explanation:

36 - 14 = 22

22/3 = 7.3333 (repeating)

The properties of integer addition and subtraction also apply topolynomial
addition and subtraction.
•_____under additionand subtraction
•Commutative property of addition
•____property of addition

Answers

Polynomial is commutative under addition and non-commutative under subtraction.

Given, the properties of integer addition and subtraction.

Now, we have to check the properties apply to polynomial or not

Let, a polynomial be p(x) = 2x²+3x+5

and other polynomial be q(x) = x²+2x+3

Now, on adding, we get

p(x) + q(x)

(2x²+3x+5) + (x²+2x+3) = 3x²+5x+8

also, q(x) + p(x)

(x²+2x+3) + (2x²+3x+5) = 3x²+5x+8

So, as p(x) + q(x) = q(x) + p(x)

Therefore, polynomial is commutative under addition

Now, on subtracting, we get

p(x) - q(x)

(2x²+3x+5) - (x²+2x+3) = x²+x+2

also, q(x) - p(x)

(x²+2x+3) - (2x²+3x+5) = -x²-x-2

So, as p(x) + q(x) ≠ q(x) + p(x)

Therefore, polynomial is non-commutative under subtraction.

Hence, polynomial is commutative under addition and non-commutative under subtraction.

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What is the x-value of the solution to this system of equations? 6x + 8y = -18x = -2y - 5

Answers

Since the second equation is x in function of y, we can use the substitution method to find y and then find x

First, we substitute x from the second equation into the first equation:

[tex]\begin{gathered} 6(-2y-5)+8y=-18 \\ -12y-30+8y=-18 \end{gathered}[/tex]

And solve for y:

[tex]\begin{gathered} (-12+8)y-30=-18 \\ -4y=-18+30 \\ -4y=12 \\ y=\frac{12}{-4}=-3 \end{gathered}[/tex]

And now we replace y = -3 into the second equation:

[tex]\begin{gathered} x=-2y-5 \\ x=-2\cdot(-3)-5 \\ x=6-5 \\ x=1 \end{gathered}[/tex]

The x-value of the solution is 1

What answer shows two pairs of adjacent angles in the figure?angles 2 and 5; angles 2 and 4angles 1 and 4; angles 2 and 5angles 4 and 5; angles 2 and 4angles 1 and 4; angles 1 and 2

Answers

Step 1

Given;

[tex]A\text{ pair of angles in a figure}[/tex]

Required; To find which answer shows two pairs of adjacent angles in the figure.

Step 2

Adjacent angles are two angles that have a common side and a common vertex (corner point) but do not overlap in any way.

Therefore, the pair of adjacent angles is;

[tex]\text{Angles 4 and 5; Angles 2 and 4}[/tex]

Hence, the answer is: angles 4 and 5; angles 2 and 4

Pls help I attached the question

Answers

Answer:

C

Step-by-step explanation:

Find an equation that fits the graph below; choose one of the following forms

Answers

Step 1:

Write the two equations

[tex]y\text{ = }A\sin \lbrack B(x\text{ - C)\rbrack + D and y = Asin\lbrack{}B(x-C)\rbrack + D}[/tex]

Step 2:

The amplitude of graph A = 2

The midline of the graph is D = 0

The graph is a sin graph.

y = 2sin[B(x - C)] + 0

y = 2sin[B(x - C)]

Final answer

y = 2sin[B(x - C)] + D

Find the diameter of the circle.The image shows a circle with radius 9 centimeters.The diameter of the circle is _______ centimeters.The solution is _______

Answers

The diameter of the circle is given as

[tex]\begin{gathered} \text{diameter}=2\times radius\text{ of the circle} \\ d=2r \end{gathered}[/tex]

The given radius is

[tex]=9\operatorname{cm}[/tex]

Therefore, the diameter will be

[tex]\begin{gathered} \text{diameter =2}\times9\operatorname{cm} \\ \text{diameter =18cm} \end{gathered}[/tex]

Hence,

The diameter of the circle =18 centimeters

suppose that your boss must choose for employees in your office to attend a conference in Jamaica. Because all 14 of you want to go . he decides that the only fair way is to draw names out of a hat. What is the probability that you, Samuel, Emma and Paul are chosen? Into a fraction or round your answer to four decimal places if necessary

Answers

suppose that your boss must choose four employees in your office to attend a conference in Jamaica. Because all 14 of you want to go . he decides that the only fair way is to draw names out of a hat. What is the probability that you, Samuel, Emma and Paul are chosen? Into a fraction or round your answer to four decimal places if necessary

total employees=14

probability that you are chosen is P=1/14

probability that Samuel are chosen is P=1/13

the probability that Emma are chosen is P=1/12

the probability that Paul are chosen is P=1/11

therefore

the probability that you, Samuel, Emma and Paul are chosen is

P=(1/14)(1/13)(1/12)(1/11)=4.16x10^-5=0.00004

problem N 2

P=(1/27)(1/26)(1/25)=0.00005698=0.0001

Probably 1/14 to pick you total amount employees is 14

Suppose you go to work for a company that pays one penny on the first day, 2 cents on the second day, 4 cents on the third day and so on.

Hint: use an= a1 (r)^n-1 and Sn= a1 (1-r^n) / 1 - r

A. If the daily wage keeps doubling, what would your income be on day 31? Give your answer in dollars NOT pennies.

Income on day 31 = $ __________

B. If the daily wage keeps doubling, what will your total income be for working 31 days? Give your answer in dollars NOT pennies.

Total Income for working 31 days = $ _________

Answers

The amount earned, calculated using the formula for geometric progressions are as follows;

(A) The income on day 31 =$1,073,741,824

(B) Total income for 31 working days = $2,147,483,647

What is a geometric progression?

A geometric progression is one in which each subsequent term is a constant multiple of the previous  term

(A) The function that indicates the amount earned on the nth day is the formula for a geometric progression , which can be presented as follows;

[tex]a_n = a_1\cdot r^{n-1}[/tex]

The sum is presented as follows;

[tex]S_n =a_1\cdot \dfrac{1 - r^n}{1 - r}[/tex]

Therefore;

The common ratio, r = 2

The first term, a₁ = 1

The amount received on day 31 is therefore;

[tex]a_{31} = 1\times 2^{31-1} = 1,073,741,824[/tex]

Income on day 31 = $1,073,741,824

(B) The total income in 31 days is therefore;

[tex]S_{31} =a_1\cdot \dfrac{2^{31} - 1}{2- 1}== 2,147,483,647[/tex]

The total income in 31 working days = $2,147,183,647

Learn more about geometric progression in mathematics here::

https://brainly.com/question/15562660

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Factor the polynomial: s^2+ 12s + 32

Answers

SOLUTION

We want to factor the polynomial

[tex]s^2+12s+32[/tex]

To do this we look for two values with s such that when we multiply them, we get 32 and when we add then we get the middle item 12s.

These are 8s and 4s because

[tex]\begin{gathered} 8s+4s=12s \\ 8s\times4s=32s^2 \end{gathered}[/tex]

Now we replace 8s and 4s with the middle item and factorize, we have

[tex]\begin{gathered} s^2+12s+32 \\ s^2+8s+4s+32 \\ s(s+8)+4(s+8) \\ (s+4)(s+8) \end{gathered}[/tex]

Hence the answer is

(s + 4) (s + 8)

Which equation represents a line which is parallel to the line 3y - 2x = -24?Submit AnswerOy= -x - 7Oy= - žx – 2Oy= {x +3Oy= x +4

Answers

ANSWER

[tex]y=\frac{2}{3}x+3[/tex]

EXPLANATION

Parallel lines have the same slope. First we should rewrite the given line in the slope-intercept form by clearing y, so that we can see what is the slope:

[tex]\begin{gathered} 3y-2x=-24 \\ 3y=2x-24 \\ y=\frac{2}{3}x-8 \end{gathered}[/tex]

The slope of the line is 2/3, so the slope of the parallel line must be 2/3 too. From this options, the equation with a slope of 2/3 is:

[tex]y=\frac{2}{3}x+3[/tex]

Consider the fraction 1/2, if this fraction is divided by 3, will the quotient be more or less than the quotient in the first part?

Answers

[tex]\begin{gathered} \text{you must compare 1/2 with 1/2 divided by 3. This las operation is equal to 1/6:} \\ \frac{\frac{1}{2}}{3}=\frac{\frac{1}{2}}{\frac{3}{1}}=\frac{1\cdot1}{2\cdot3}=\frac{1}{6} \\ \text{I did this computation by using the sandwich law. I uploaded the image below} \\ \text{Now we must compare the quotient of 1/2 and the quotient of 1/6} \end{gathered}[/tex][tex]\begin{gathered} as\text{ you can se}e,\text{ the quotient in the division 1/2 is 0.5 } \\ \text{and the quotient in 1/6 is 0.16,} \\ \sin ce\text{ 0.5 }>0.16,\text{ then the quotient in the first part } \\ \text{is larger than the quotient in the second part} \end{gathered}[/tex][tex]\text{this last image exemplify the "Sandwich law"}[/tex]

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