Given data:
* The distance to the Grandma house is d = 120 miles.
* The value of the speed limit is v = 60 mph.
* The time for the dinner is t = 5 p.m.
Solution:
The time taken to reach the Grandma house while moving in the speed limit is,
[tex]\begin{gathered} v=\frac{d}{T} \\ T=\frac{d}{v} \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} T=\frac{120}{60} \\ T=2\text{ hours} \end{gathered}[/tex]The time of leaving is,
[tex]\begin{gathered} t_1=t-T \\ t_1=5-2 \\ t_1=3\text{ p.m.} \end{gathered}[/tex]Thus, the time at which the person should leave for grandma's house is 3 p.m.
a student rolls a marble off of a 1.0 m tall table and it lands 1.5 m away Calculate the initial horizontal velocity. (closest to) Answer A 0.30 m/s B 0.54 m/s C 1.82 m/s D 3.33 m/s
The horizontal velocity of the marble is 3.33 m/s.
option D is the correct answer.
What is the initial horizontal velocity of the marble?The initial horizontal velocity of the marble is calculated by applying the following equation as shown below;
X = Vₓt
where;
Vₓ is the horizontal velocity of the marblet is the time of motion of the marbleThe time of motion of the marble from the table is calculated as follows;
t = √(2h/g)
where;
h is the height of the tableg is the acceleration due to gravityt = √(2 x 1 / 9.8)
t = 0.45 seconds
The horizontal velocity of the marble is calculated as;
Vₓ = X / t
Vₓ = 1.5 m / 0.45 s
Vₓ = 3.33 m/s
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Why are electrical safety devices important in an electric circuit?
Answer:A fuse is an electrical safety device that has the capability to protect an electric circuit from excessive electric current. It is designed to allow current through the circuit, but in the event that the current exceeds some maximum value it will open, severing the circuit.
Explanation:
Answer:
See below
Explanation:
Ground wires and fuse are used to help avoid an electrical shock and current overload (and possible fire)
a car has a mass of 2,000 kg. there are two passengers in the car, each with a mass of 55 kg. if the coefficient of kinetic friction is .02, what is the force of friction experienced by the car? what is the acceleration of the car if the car is applying a force of 1060 n?
f = μ N
N = m g
f = Frictional force
μ = Co-efficient of friction
N = Normal force
m = Mass
g = Acceleration due to gravity
m = 2000 + 55 + 55
m = 2110 kg
g = 9.8 m / s²
μ = 0.02
f = 0.02 * 2110
f = 42.2 N
According to Newton's second law of motion,
F = m a
F = Force
a = Acceleration
F = 1060 N
a = F / m
a = 1060 / 2110
a = 0.5 m / s²
Therefore,
The force of friction experienced by the car is 42.2 NThe acceleration of the car if the car is applying a force of 1060 N is 0.5 m / s²To know more about Newton's second law of motion
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hat would her speed be at 440 mm ? (in reality, the air resistance will restrict her speed to perhaps 150 km/hkm/h .) express your answer to two significant figures and include the appropriate units.
228 m/s velocity would be at 440 mm.
initial height , hi = 3100 m
hf = 430 m
time taken is t
3100 - 430 = 0.5 × 9.8 × t^2
t = 23.34 s
time taken=23.34 s
let the speed is u
u =[tex]\sqrt(2 * g * (hi - hf))[/tex]
u = [tex]\sqrt(2 * 9.8 * (3100 - 440))[/tex]
u = 228 m/s
her speed is 228 m/s
A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.
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Help me please!!!!!!:)
When substances combine chemically,
C) the total mass of both substances will be equal to the mass of each of the mass added together.
State the Law of Conservation of Mass?
"The mass cannot be created through a chemical reaction, neither can it be destroyed."
following this law the mass of the products and the mass of the reactants are always equal in a physical or chemical transition.
The product's mass equals the sum of the reactant's mass.Lavoisier made the mass conversation law public knowledge.Another way to put it is that "matter is neither formed nor can it be destroyed in a chemical reaction." Also known as the "Law of the indestructibility of matter," the law of mass conservation.To learn more about Law of Conservation of Mass from the given link
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Help me please????????
Answer:it should be A
Explanation:
Three vectors are shown in this figure. Their respective moduli are F = 40N T = 75 N and N = 25.6NCalculate the vector a so that F + N + T = 2.00A
First, separate each vector into its vertical and horizontal components. Then, add all the vertical components together, as well as the horizontal components, to find the components of the vectpr F+T+N. Set each component of the vector F+T+N to be equal to the corresponding component of 2.00A to find the components of A. Use the components of A to find the magnitude and direction of the vector A.
The vertical and horizontal components of T are given by:
[tex]\begin{gathered} T_y=T\sin (10.0º) \\ =75N\cdot0.1736\ldots \\ =13.02N \end{gathered}[/tex][tex]\begin{gathered} T_x=T\cos (10.0) \\ =75N\cdot0.9848\ldots \\ =73.86N \end{gathered}[/tex]The vertical and horizontal components of N are:
[tex]\begin{gathered} N_y=N \\ =25.6N \end{gathered}[/tex][tex]N_x=0[/tex]The vertical and horizontal components of F are:
[tex]\begin{gathered} F_y=-F\cdot\cos (15) \\ =-40N\cdot0.9659\ldots \\ =-38.637N \end{gathered}[/tex][tex]\begin{gathered} F_x=-F\cdot\sin (15) \\ =-40N\cdot0.2588\ldots \\ =-10.353N \end{gathered}[/tex]The vertical component of F+N+T is given by:
[tex]\begin{gathered} (F+N+T)_y=F_y+N_y+T_y \\ =-38.637N+25.6N+13.02N \\ =-0.017N \\ \approx0.0N \end{gathered}[/tex]The horizontal component of F+N+T is given by:
[tex]\begin{gathered} (F+N+T)_x=F_x+N_x+T_x \\ =-10.353N+73.86N \\ =63.51N \end{gathered}[/tex]Since F+N+T=2.00A, then this is true for each component:
[tex]\begin{gathered} (F+N+T)_y=(2.00A)_y=2.00\cdot A_y \\ (F+N+T)_x=(2.00A)_x=2.00\cdot A_x \end{gathered}[/tex]Substitute the values for the components of F+N+T to find the values of the components of A:
[tex]\begin{gathered} 2.00A_y=0.00N \\ \Rightarrow A_y=\frac{0.0N}{2.00}=0.0N \end{gathered}[/tex][tex]\begin{gathered} 2.00A_x=63.51N \\ \Rightarrow A_x=\frac{63.51N}{2.00}=31.75N \end{gathered}[/tex]Since the vertical component of A is 0, then the vector A has a magnitude of 31.75N directed toward the positive X axis.
Therefeore, the answer is:
[tex]A=31.75N\text{ toward the positive direction of X.}[/tex]a load of 41 n attached to a spring hanging vertically stretches the spring 3.1 cm. the spring is now placed horizontally on a table and stretched 11 cm. what force is required to stretch it by this amount? answer in units of n.
A load of 41 n attached to a spring hanging vertically stretches the spring 3.1 cm. the spring is now placed horizontally on a table and stretched 11 cm. 145.42 N force is required to stretch it by this amount
k = spring constant
x = displacement
force1 = - k x1
41 = - k (3.1)
k = 13.22 N/cm
force2 = -k x2
= - 13.22 * 11 = 145.42 N
145.42 N force is required to stretch it by this amount
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As part of an experiment on momentum, a billiard ball with a mass of
0.180 kg travels 1.5 m in 0.5 s. What is the momentum of the ball?
(1 point)
Answer: 0.54 kg meter per second
Explanation:
this is a cost of 0.180. Multiplying by 1.5 divided by 5 equals 0.54 Kg meter per second. This is the momentum.
I hope this helps!
Please, explain step by step.A car that’s initially traveling at 10 m/s accelerates uniformly for 4 seconds at a rate of 2 m/s2, in a straight line. How far does the car travel during this time?
To understand this first, analyze the conditions of the car
[tex]\begin{gathered} v_0=\frac{10m}{s} \\ t=4s \\ a=\frac{2m}{s} \\ \\ d=\text{?} \end{gathered}[/tex]Whit this data we have to find the distance traveled by the car in these 4 seconds
[tex]\begin{gathered} d=v_0\cdot t+\frac{a\cdot t^2}{2} \\ d=10\cdot4+\frac{2\cdot4^2}{2} \\ d=40+16=56m \end{gathered}[/tex]Where do rock formations go when they are subducted?
Group of answer choices below
A. Above the surface
B. Into the ocean
C. Into the mantle
D. To the core
Option C: Rock formations are subducted into the mantle after subduction.
Describe subduction.Where two or more lithospheric plates meet, a geological process called as subduction recycles rocks from the oceanic lithosphere into the Earth's mantle. Where the tectonic plate converged between the oceanic lithosphere and a less dense lithosphere, the heavier plate sinks beneath the other plate into the mantle.
Deeply subducted sedimentary and metaphorical rocks eventually melt to generate magma, which subsequently cools to form igneous rock.
Therefore the rock cycle encompasses the entire process and lasts millions of years.
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A child is pulling a wagon across the grass but friction between the grass and wheel creates a force in the opposite direction . If the wagon is speeding up , what does that mean about the two forces ?
ANSWER
The applied force is larger than the frictional force
EXPLANATION
If we draw a free-body diagram,
By Newton's second law, for the horizontal forces is,
[tex]F_a-F_f=m\cdot a[/tex]If the wagon is speeding up, it means that there is a positive acceleration. Therefore, the difference Fa - Ff is positive,
[tex]\begin{gathered} F_a-F_f>0 \\ \text{therefore} \\ F_a>F_f \end{gathered}[/tex]Hence, the applied force is greater than the frictional force.
the peak wavelength of the emission spectrum of a star is 320 nm. which one of the following is the only possible correct statement?
The peak wavelength of the emission spectrum of a star is 320 nm Object 1 is three times as hot as object 2.
In physics, the wavelength is the length over which a periodic wave repeats, or its spatial period. It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda () is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.
Question :
Object 1 is observed to be emitting most of its light at a wavelength of 320 nm (ultraviolet). Object 2 is observed to be emitting most of its light at a wavelength of 960 nm (infrared). How much hotter is object 1 than object 2?
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Two unequal masses m and 2m are attached to a thin bar of negligible mass that rotates about an axis perpendicular to the bar. When m is a distance 2d from the axis and 2m is a distance d from the axis, the moment of inertia of this combination is i.
The moment of inertia for this combination is I when m is 2d from the axis and 2m is 2d from the axis, therefore I = mr2.
Explain the moment of inertia.Moment of inertia is a word used to describe a physical property that measures how resistant a body is to having the speed of its rotation along an axis modified by the application of a torque (turning force). Axis options include internal, external, stationary, and moving.
What does it mean to be in an inertial moment?The moment of inertia is recognized as such and not as a moment of force because it opposes circular motion.
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Plot a graph of the pendulum period, T, vs. amplitude, A, in degrees using LabQuest App or graph paper. Scale each axis from the origin (0,0). According to your data, does the period depend on amplitude?
Given the graph of period vs amplitude.
It can be seen from the graph that the plot of the period versus amplitude is almost a horizontal line. That is, as the amplitude increase, the period of the pendulum remains almost unchanged.
This is also consistent with the fact that the period of the simple pendulum indeed does not depend upon its amplitude.
Thus, according to the graph, the period does not depend on the amplitude.
A jet of water squirts out horizontally froma hole on the side of the tank as shown below. If the hole has a diameter of 3.62 mm, whatis the height of the water above the hole inthe tank?Answer in units of cm.
The jet of water emerges with a speed v horizontally. Then, it falls a vertical distance of 1.58, and during the time of its fall until it hits the ground, it travels a distance of 0.586 meters.
Since the water moves according to the Projectile Motion formulas, the horizontal motion is uniform and the vertical motion is uniformly accelerated from rest.
Then, we can use the vertical distance to find the time that it takes for the water to reach the ground. Then, divide the horizontal distance traveled by the water by the time it took for the water to fall to find the horizontal speed of the water.
Finally, use Torricelli's Theorem to relate the height of the water above the hole in the pipe to the horizontal speed. Find the height of the hole by isolating it and replacing the value of the known variables.
Step 1: Time
Since the water falls from rest a distance of 1.58m, and the time it takes for an object to fall a distance d in free fall from rest is given by:
[tex]t=\sqrt[]{\frac{2d}{g}}[/tex]Then, replace d=1.58m and the value of the acceleration of gravity g=9.81m/s^2 to find the time it takes for the water to fall:
[tex]t=\sqrt[]{\frac{2(1.58m)}{9.81\frac{m}{s^2}}}=0.5675564161\ldots s[/tex]Step 2: Speed
Since the water travels a horizontal distance of 0.586m during that time, then, the speed of the water jet as it emerges from the hole, is:
[tex]v=\frac{x}{t}=\frac{0.586m}{0.5675564161\ldots s}=1.032496477\ldots\frac{m}{s}[/tex]Step 3: Height (Torricelli's Theorem)
According to Torricelli's Theorem, the speed of a liquid jet emerging from a hole located a distance h below the level of water of a large container, is:
[tex]v=\sqrt[]{2gh}[/tex]Isolate h from the equation:
[tex]h=\frac{v^2}{2g}[/tex]Replace v=1.032496477...m/s and g=9.81m/s^2 to find the height of the water above the hole in the tank:
[tex]h=\frac{(1.032406477\ldots\frac{m}{s})^2}{2(9.81\frac{m}{s^2})}=0.05433481013\ldots m\approx5.43\times10^{-2\text{ }}m[/tex]Write the answer in cm:
[tex]h=5.43cm[/tex]Therefore, the height of the water above the hole in the tank is 5.43 centimeters.
A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s. The linear speed of a point on the wheel’s rim = 178 radWhat is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?
Given data
*The given radius of the wheel is r = 30.0 cm = 0.30 m
*The given angle of the wheel rotates in 1.00 s is
[tex]\theta=178.0\text{ rad}[/tex]*The angular velocity of the wheel is
[tex]\omega=178.0\text{ rad/s}[/tex]The formula for the linear speed of a point on the wheel's rim is given as
[tex]v=r\omega[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v=(0.30)(178.0) \\ =53.4\text{ m/s} \end{gathered}[/tex]Hence, the linear speed of a point on the wheel's rim is v = 53.4 m/s
The formula for the wheel's frequency of rotation is given as
[tex]\begin{gathered} \omega=2\pi f \\ f=\frac{\omega}{2\pi} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} f=\frac{178.0}{2\times3.14} \\ =28.34\text{ Hz} \end{gathered}[/tex]Hence, the wheel's frequency of rotation is f = 28.34 Hz
what seems to happen to the one electron in the outer layer of sodium when it combines with chlorine to form sodium chloride?
the syringe used in the boyle's law experiment leaks, giving you a low pressure. will the calculated constant be too high, too low or unchanged?
The syringe used in the Boyle's law experiment leaks, giving a low pressure,hence, the calculated constant will be too low.
What is the statement of Boyle's law of gases?Boyle's law of gases states that the pressure of a given volume of gas is inversely proportional to the volume of the gas provided that the temperature is kept constant.
This implies that as pressure increases, the volume will decrease at a constant temperature.
On the other hand, if the volume increases, the pressure decreases at a constant temperature.
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By what factor does the gravitational force between two objects increase if one object doubles in mass and the distance between them decreases by half?
The factor is that since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.
What is gravitational force?Gravitational force is described as the universal force of attraction, which is acting between objects. This force causes mutual attraction between all things with mass or energy.
The newton's law of universal gravitation states that every particle in the universe attracts every other particle with a force along a line joining them. The force is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
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Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field what is the force applied to the ball ?
From Newton's second law of motion, the magnitude of the force applied is 1022.4 N
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and acceleration and it is a vector quantity.
Given that Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field.
The force F applied to the ball = mass × acceleration. That is,
F = ma
Where
m = 0.527 kgv = 19.4 m/st = 0.01 sF = ?a = ?Acceleration a = v/t
a = 19.4/0.01
a = 1940 m/s²
Force F = ma
F = 0.527 × 1940
F = 1022.4 N
Therefore, the force applied to the ball is 1022.4 N
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1. While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is theautomobile's acceleration? (Remember that a negative value indicates a slowing down.)
Given data
*The initial speed of the driver is u = 24 m/s
*The final speed of the driver is v = 15 m/s
*The given time is t = 12 s
The formula for the automobile's acceleration is given as
[tex]a=\frac{v-u}{t}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} a=\frac{15-24}{12} \\ =-0.75m/s^2 \end{gathered}[/tex]need help asappppppp
Visible light, x-rays, and radio waves are forms of electromagnetic waves that can travel through vacuum and mater.
Determine the power required for a 1150 kg car to climb a 100 m-long uphill road with a slope of 30 degree (from horizontal) in 12 s at a constant velocity.
The Power required for a 1150 kg car to climb is 104.46kW.
L = 100 m, 0°, 1150 kg, and 12 s are the values.
while it is moving at a fixed rateEnergy E = mxgh = mxglxsin = 1150x9.8x100xsin30=563500J
Power, P, is calculated as follows: 563500 / 12 = 46958.
3 watts equal 46.95 kW
(b) From a standstill to a final speed of 30 m/sE = mgxlsin+1/2mv2 and gxlsin+mv2
E = 1081000 J P = E / T = 1081000 / 12 = 90083.33 W = 90.1 kW E = 1150 x 9.8 x 100 x Sin 30 + 0.5 x 1150 x 30 x 30
(c) between 35 m/s and 5 m/sE = m x g x L Sin + mv - mu - half
0.5 x 1150 x 35 x 35 - 0.5 x 1150 x 5 x 5 E = 1150 x 9.8 x 100 x Sin 30 Plus = 104.46 kW = 104458.33 W = 563500 + 704375 - 14375 = 1253500 J P = E / T
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Calculate the kinetic energy of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s.
Given,
The mass of the car, m=1000 kg
The velocity of the car, v=20 m/s
The kinetic energy of an object is the energy of the body possessed due to its motion. The kinetic energy of a body is directly proportional to the square of the velocity of the object.
The kinetic energy of the car is given by,
[tex]E=\frac{1}{2}mv^2[/tex]On substituting the known values,
[tex]\begin{gathered} E=\frac{1}{2}\times1000\times20^2 \\ =200000\text{ J} \\ =200\text{ kJ} \end{gathered}[/tex]Thus the kinetic energy of the given car is 200 kJ.
A hover board is moving at 6 m/s . If it slows down at a rate of -3 m/s per second, how long is the board in the air before coming to rest? Round to 4 decimal places if necessary
Explanation
a uniformly accelerated motion is the one in which the acceleration of the particle throughout the motion is uniform,to fidn the time take we can use the formula:
[tex]\begin{gathered} t=\frac{v_f-v_1}{a} \\ where \\ v_f\text{ is the final velocity} \\ v_{i\text{ }}\text{ is the initail velocity} \\ a\text{ is the acceleration, so} \end{gathered}[/tex]Step 1
a)Let
[tex]\begin{gathered} v_i=6\text{ }\frac{m}{s} \\ v_f=0(\text{ rest\rparen} \\ a=-3\frac{m}{s^2} \end{gathered}[/tex]b) now, replace
[tex]\begin{gathered} t=\frac{v_{f}-v_{1}}{a} \\ t=\frac{0-(-6\frac{m}{s})}{3\frac{m}{s}} \\ t=2\text{ seconds} \end{gathered}[/tex]therefore, the answer is 2 seconds
I
Friction Virtual Lab
Coefficients of Friction.
Run the same simulation above. Use 50 kg mass and set the friction again to halfway. Apply the push, observe and record the maximum value of static friction.
1. Find the coefficient of static friction μs by using the equation (2)
2. Now apply the push so that the object moves with constant speed.
3. Find the coefficient of kinetic friction μk by using the equation (1)
4. According to your notes μs >μk, is this consistent with your results from questions 1 & 3? (If not, repeat the experiment)
4. Now add another 50 kg mass and repeat the experiment to find μk.
5. What is μk now?
6. Are your results in questions 3 and 5 different?
7. According to your notes, the coefficient of friction is constant. Is that consistent with your answer to question 7?
1 ) The coefficient of static friction μs by using the equation (2) = 0.26
3 ) The coefficient of kinetic friction μk by using the equation (1) = 0.19
1 ) The coefficient of static friction
μ[tex]_{s}[/tex] = [tex]f_{s} _{max}[/tex] / F[tex]_{n}[/tex]
μ[tex]_{s}[/tex] = 125 / 50 * 9.8
μ[tex]_{s}[/tex] = 0.26
3 ) The coefficient of kinetic friction
μ[tex]_{k}[/tex] = [tex]f_{k}[/tex] / F[tex]_{n}[/tex]
μ[tex]_{k}[/tex] = 94 / 50 * 9.8
μ[tex]_{k}[/tex] = 0.19
4 ) Yes, from ( 1 ) and ( 3 ),
μ[tex]_{s}[/tex] > μ[tex]_{k}[/tex]
5 ) μ[tex]_{k}[/tex] = [tex]f_{k}[/tex] / F[tex]_{n}[/tex]
μ[tex]_{k}[/tex] = 188 / 100 * 9.8
μ[tex]_{k}[/tex] = 0.19
6 ) No the μ[tex]_{k}[/tex] from ( 3 ) and ( 5 ) are exactly the same.
7 ) Since μ[tex]_{k}[/tex] from ( 3 ) and ( 5 ) are exactly the same, coefficient of friction is constant.
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HELP ME
PLS I will give brainliest
Answer:
Option 2
Explanation:
Since they want to know kinetic energy being increased, it cannot be Options 1 or 3. So now we're left with 2 and 4. 4 seems to be decreasing, so we can eliminate that. So, our answer is Option 2.
what do we mean by inflation? what do we mean by inflation? the expansion of universe starting with the instant after the big bang the rapid expansion of the universe, driven by white dwarf supernova, that we still observe today the sudden release of photons when particles and antiparticles annihilate each other a sudden expansion of the universe driven by the energy released when the strong and electroweak forces froze out from the gut force the photons released when electrons and protons first combined, forming the cosmic microwave background radiation
A pitching machine throws a 0.148kg baseball to the left at 26m/s. A batter then hits the baseball directly back at 39m/s. What is the change in momentum of this baseball
Let us assume that the initial direction of the ball, i.e., from the pitching machine to the batter as the negative direction, and the final direction of the ball is the positive direction.
Given,
The mass of the baseball, m=0.148 kg
The initial velocity of the baseball, u=-26 m/s
The final velocity of the baseball, v=39 m/s
The momentum of the ball before the batter hits it is given by,
[tex]p_1=mu[/tex]On substituting the known values,
[tex]\begin{gathered} p_1=0.148\times-26 \\ =-3.848\text{ kg}\cdot\text{m/s} \end{gathered}[/tex]The momentum of the ball after the batter hits it is given by,
[tex]p_2=mv[/tex]On substituting the known values,
[tex]\begin{gathered} p_2=0.148\times39 \\ =5.772\text{ kg}\cdot\text{m/s} \end{gathered}[/tex]The change in the momentum is given by,
[tex]\Delta p=p_2-p_1[/tex]On substituting the known values,
[tex]\begin{gathered} \Delta p=5.772-(-3.848) \\ =9.62\text{ kg}\cdot\text{m/s} \end{gathered}[/tex]Thus the change in the momentum of baseball is 9.62 kg·m/s