Given:• ABCD is a parallelogram.• DE=3z-3• EB=2+11• EC = 5x + 7What is the value of x?44.507
Answers
To answer this question, we need to recall that: "the diagonals of a parallelogram bisect each other"
Thus, we can say that:
[tex]DE=EB[/tex]And since: DE = 3x - 3 , and EB = x + 11, we have tha:
[tex]\begin{gathered} DE=EB \\ \Rightarrow3x-3=x+11 \end{gathered}[/tex]we now solve the above equation to find x, as follows:
[tex]\begin{gathered} \Rightarrow3x-3=x+11 \\ \Rightarrow3x-x=11+3 \\ \Rightarrow2x=14 \\ \Rightarrow x=\frac{14}{2}=7 \\ \Rightarrow x=7 \end{gathered}[/tex]Therefore, the correct answer is: option D
Related Questions
What is 5x100? Pls tell me
Answers
We want to calculate;
[tex]5\times100=500[/tex]Thus the answer is 500.
function "p" is in the form y = ax² + c if the values of "a" and "c" are both less than 0, which graph could represent "p" ?A) graph AB) graph BC) graph CD) graph D
Answers
INFORMATION:
We know that:
- function "p" is in the form y = ax² + c
- the values of "a" and "c" are both less than 0
And we must select the graph that can represent p.
STEP BY STEP EXPLANATION:
To select the correct option we must know that:
- the form y = ax² + c is the form of a parabola
- the sign of "a" determines whether the parabola opens up or down
- "c" will move the function c units up or down about the origin.
Now, since "a" and "c" are both less than 0 we can conclude that:
- the parabola opens down because "a" is negative (less than 0)
- the parabola will be c units down about the origin because "c" is negative
Finally, we can see that the option which met the conditions is graph B.
ANSWER:
B) graph B
Line segments, AB, BC, CD, DA create the quadrilateral graphed on the coordinate grid above. The equations for two of the four line segments are given below. Use the equations of the line segments to answer the questions that follow. AB: y = -x + 1 1
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Given the equations of the side length as shown;
AB y = 1/3 x + 1
CD = y = -3x+11
Before we determine whether they are parallel or perpendicular, we must first know that;
Two parallel lines have the same slope i.e Mab = Mcd
For two lines to be perpendicular then the product of the slopes must give -1 i.e MabMcd = -1
Comapring both equations with the general equation of a line y = mx+c;
For line AB: y = 1/3 x + 1
Mab = 1/3
For line CD: y = -3x+11
Mcd = -3
Taking the product of the slope;
MabMcd = 1/3 * -3
MabMcd = -1
Is AB perpendicular or parallel to CD? Since the product of their slope gives -1, hence the lines AB and CD are PERPENDICULAR to each other.
What is the radius of a circle with circumferenceC= 40 CM
Answers
Solution:
The circumference C, of a circle is;
[tex]C=\pi r^2[/tex]Given;
[tex]C=40cm,\pi=3.14[/tex]The radius r, is;
[tex]\begin{gathered} 40=3.14(r^2) \\ \text{Divide both sides by 3.14} \\ \frac{40}{3.14}=\frac{3.14(r^2)}{3.14} \\ r^2=12.74 \\ \text{Take the square root of both sides;} \\ \sqrt[]{r^2}=\sqrt[]{12.74} \\ r=3.57 \end{gathered}[/tex]The radius of the circle is 3.57cm
45 pointsSolve the logarithmic equation below. All work must be shown to earn full credit and
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We know that the substraction of two logarithm of the same base is related to a division:
[tex]\log _460-\log _44=\log _4(\frac{60}{4})[/tex]Since 60/4 = 15, then
[tex]\log _4(k^2+2k)=\log _415[/tex]Then, the expressions in the parenthesis are equal:
k² + 2k = 15
Factoring the expression
Now, we can solve for k:
k² + 2k = 15
↓ substracting 15 both sides
k² + 2k - 15 = 0
Since
5 · (-3) = -15 [third term]
and
5 - 3 = 2 [second term]
we are going to use 5 and -3 to factor the expression:
k² + 2k - 15 = (k -3) (k +5) = 0
We want to find what values should have k so
(k -3) (k +5) = 0
if k -3 = 0 or if k +5 = 0, the expression will be 0
So
k - 3 = 0 → k = 3
k +5 = 0 → k = -5
Answer: k = 3 or k = -5B(q-L)--------- =3. its all divided by h but I don't. hunderstand how to solve for q
Answers
Given the equation below,
[tex]\frac{B(q-L)}{h}=r[/tex]Solving for q, by making q the subject of formula from the above equation
Multiply both sides by h
[tex]\begin{gathered} h\times\frac{B(q-L)}{h}=r\times h \\ B(q-L)=rh \end{gathered}[/tex]Divide both sides by B
[tex]\begin{gathered} \frac{B(q-L)}{B}=\frac{rh}{B} \\ (q-L)=\frac{rh}{B} \end{gathered}[/tex]Add L to both sides
[tex]\begin{gathered} q-L+L=\frac{rh}{B}+L \\ q=\frac{rh}{B}+L \end{gathered}[/tex]Hence, the answer is
[tex]q=\frac{rh}{B}+L[/tex]4.
The value of a truck decreases exponentially since its purchase. The two points on the
graph shows the truck's initial
value and its value a decade afterward.
[6040,000)
a) Express the car's value, in dollars, as a function of time
d, in decades, since purchase.
(1 24,000)
b) Write an expression to represent the car's value 4 years
after purchase.
c) By what factor is the value of the car changing each year? Show your reasoning.
Answers
Answer:
a. v = 40 000 (3/ 5)^d
b. v = 40 000 (3/5)^(4/10)
c. 0.95
Explanation:
The exponential growth is modelled by
[tex]v=A(b)^d[/tex]We know that points (0, 40 000) and (1, 24 000) lie on the curve. This means, the above equation must be satsifed for v = 40 000 and d = 0. Putting v = 40 000 and d = 0 into the above equation gives
[tex]40\; 000=Ab^0[/tex][tex]40\; 000=A[/tex]Therefore, we have
[tex]v=40\; 000b^d[/tex]Similarly, from the second point (1, 24 000) we put v = 24 000 and d = 1 to get
[tex]24\; 000=40\; 000b^1[/tex][tex]24\; 000=40\; 000b^{}[/tex]dividing both sides by 40 000 gives
[tex]b=\frac{24\; 000}{40\; 000}[/tex][tex]b=\frac{3}{5}[/tex]Hence, our equation that models the situation is
[tex]\boxed{v=40\; 000(\frac{3}{5})^d\text{.}}[/tex]Part B.
Remember that the d in the equation we found in part A is decades. Since there are 10 years in a decade, we can write
t = 10d
or
d = t/10
Where t = number of years
Making the above substitution into our equation gives
[tex]v=40\; 000(\frac{3}{5})^{\frac{t}{10}}[/tex]Therefore, the car's value at t = 4 is
[tex]\boxed{v=40\; 000(\frac{3}{5})^{\frac{4}{10}}}[/tex]Part C:
The equation that gives the car's value after t years is
[tex]v=40\; 000(\frac{3}{5})^{\frac{t}{10}}[/tex]which using the exponent property that x^ab = (x^a)^b we can rewrite as
[tex]v=40\; 000\lbrack(\frac{3}{5})^{\frac{1}{10}}\rbrack^t[/tex]Since
[tex](\frac{3}{5})^{\frac{1}{10}}=0.95[/tex]Therefore, our equation becomes
[tex]v=40\; 000\lbrack0.95\rbrack^t[/tex]This tells us that the car's value is changing by a factor of 0.95 each year.
Find the equation of the circle having the given properties:
Answers
The equation of a circle is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]3.
Using the points (4, 0), (0, 2) and (0, 0), we have:
[tex]\begin{gathered} (0,0)\colon \\ h^2+k^2=r^2 \\ (0,2)\colon \\ h^2+(2-k)^2=r^2 \\ h^2+4-2k+k^2=r^2 \\ \text{Comparing both equations:} \\ h^2+k^2=h^2+4-2k+k^2 \\ 4-2k=0 \\ k=2 \\ (4,0)\colon \\ (4-h)^2+k^2=r^2 \\ 16-8h+h^2+4=r^2 \\ \text{Comparing this last equation with the first one:} \\ 16-8h+h^2+4=h^2+4 \\ 16-8h=0 \\ h=2 \\ \\ h^2+k^2=r^2 \\ r^2=4+4=8 \end{gathered}[/tex]So the equation of this circle is:
[tex](x-2)^2+(y-2)^2=8[/tex]Angel X is 2n +12°, and angle why is 3n+18° find the measure of angle X
Answers
When two angles together form a straight line, they form a 180º angle.
They are called supplementary angles.
x and y are supplementary (they together form a straight line).
This is
x + y = 180
Equation for nSince x = (2n +12)º. Instead of x we are going to write 2n + 12.
And y = (3n + 18)º. Then we are going to write 3n + 18 instead of y.
This is
x + y = 180
↓
(2n + 12) + (3n + 18) = 180
2n + 12 + 3n + 18 = 180
Now we have an equation taht we can use to find n.
2n + 12 + 3n + 18 = 180
Solving the equationWe have the equation and we are going to simplify it:
2n + 12 + 3n + 18 = 180
↓ since 2n + 3n = 5n
5n + 12 +18 = 180
↓ since 12 + 18 = 30
5n + 30 = 180
Now, we can solve it:
5n + 30 = 180
↓ taking 30 to the right side (substracting 30 both sides)
5n + 30 - 30 = 180 - 30
↓ since 30 - 30 = 0
5n + 0 = 180 - 30
5n = 180 - 30 = 150
5n = 150
↓ taking 5 to the right side (dividing by 5 both sides)
5n = 150
5n/5 = 150/5
↓ since 5n/5 = n
n = 150/5 = 30
n = 30
Then, we have n = 30
Finding xSince
x = 2ºn + 12º
then, replacing n = 30
x = 2º · 30 + 12º
x = 60º + 12º
x = 72º
Answer: C. 72ºDistance-Time Grapfoss Object ng Constant Speed - 9) Achillwit and string a speed The graph above shows the Giant the ball towed from starting pucat in 5 seconds.
Answers
In the given graph, the following are the records of the distance of the tennis ball at a certain time (seconds) after being hit:
Time (seconds) Distance (meters)
1 0.5
2 1
3 1.5
4 2
5 2.5
To be able to get the speed of the tennis ball, let's use any of the data (Time and Distance Covered) in the graph, and use the formula in calculating the speed.
[tex]\text{ Speed = }\frac{Dis\tan ce}{Time}[/tex]Let's use 1 second = 0.5 meter. We get,
[tex]\text{ Speed = }\frac{0.5\text{ meter}}{1\text{ second}}[/tex][tex]\text{Speed = 0.5 meter/second}[/tex]Therefore, the speed of the tennis ball is 0.5 m/s.
The answer is letter A.
Anna is 10 years older than Brad. The sum of their ages is 26. The system of equations representing their ages is _ Solve the system using inverses. Then select the correct calculation and the ages of Anna and Brad.
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Answer:
The correct answer is option B.
[tex]undefined[/tex]Answer this question based on the knowledge of angle in a Circle.
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From the given diagram, PQ is a diameter and since the triangle inside a semicircle is right angled, hence triangle PQR is a right triangle.
Also since the side QR is parallel to OS, hence the line PR is perpendicular to the lines QR and OS
Hence;
PR ⊥ QR and OS ⊥ PR
Proof that From △PRQ,
Since OS ⊥ PR, hence △PSR is divided into two similar triangles by the line OS showing that the base angles (
Recall that for an isosceles triangle, the base angles and two opposite sides are equal. Based on the proof above, we can conclude that;△PSR is isosceles triangle showing that SP = SRSimplify the expression `2\sqrt{a^{2}b^{8}}\left(ab^{3}\right)^{-1}`You may type many lines to show your work. Enter equations inside the text using the square-root button below.
Answers
ANSWER
2b
EXPLANATION
To simplify this expression, we have to apply some of the exponents' properties. First, the square root is a fractional exponent,
[tex]\sqrt{x}=x^{1/2}[/tex]So we can rewrite the expression as,
[tex]2\sqrt{a^2b^8}(ab^3)^{-1}=2(a^2b^8)^{1/2}(ab^3)^{-1}[/tex]Then, we can distribute the exponents into the multiplication,
[tex](xy)^z=x^zy^z[/tex]In this problem,
[tex]2(a^2b^8)^{1/2}(ab^3)^{-1}=2(a^2)^{1/2}(b^8)^{1/2}(a)^{-1}(b^3)^{-1}[/tex]Exponents of exponents are multiplied,
[tex](x^y)^z=x^{yz}[/tex]In this problem,
[tex]2(a^2)^{1/2}(b^8)^{1/2}(a)^{-1}(b^3)^{-1}=2\cdot a^{2\cdot1/2}\operatorname{\cdot}b^{8\operatorname{\cdot}1/2}\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{3\operatorname{\cdot}(-1)}[/tex]Simplify if possible,
[tex]2\cdot a^{2\cdot1/2}\operatorname{\cdot}b^{8\operatorname{\cdot}1/2}\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{3\operatorname{\cdot}(-1)}=2\cdot a^1\operatorname{\cdot}b^4\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{-3}[/tex]Now, the product of two powers with the same base is equal to the base raised to the sum of the exponents,
[tex]x^y\cdot x^z=x^{y+z}[/tex]In this problem,
[tex]2\cdot a^1\operatorname{\cdot}b^4\operatorname{\cdot}a^{-1}\operatorname{\cdot}b^{-3}=2\cdot a^{1-1}\operatorname{\cdot}b^{4-3}[/tex]Solve the subtractions,
[tex]2\cdot a^{1-1}\operatorname{\cdot}b^{4-3}=2\cdot a^0\cdot b^1=2b[/tex]Hence, the simplified expression is 2b.
2. Mason was able to sell 35% of his vegetables before noon. If Mason had 200 kg of vegetables in the morning, how many kilograms of vegetables did he NOT sell?
Answers
130kg
1) Since Mason was able to do 35% He wasn't able to make 65%
2) Then we can write it :
65% x 200 Rewriting it in decimal form
0.65 x 200
130
3) So Mason could not sell 130kg of his crop.
Identify how many solutions there are to the system of equations represented on the following graph. Treat the red and black graphs as one circle. H H
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The solution of two or more equations is the point where the equation intersects. The more that the graph of the equation intersects, the more its solutions.
From the given graph of circle and parabola, they intersect three times. Therefore, there are 3 solutions in this given system of equations.
Robbie ran 21 miles less than O'neill lastweek. Robbie ran 17 miles. How manymiles did O'neill run?
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We need to find the distance, in miles, that O'Neill ran.
We know that Robbie ran 21 miles less than O'Neill. This is the same as saying that O'Neill ran 21 miles more than Robbie.
Also, we know that Robbie ran 17 miles.
Then, to find the distance O'Neill ran, we need to add 21 miles to the 17 miles Robbie ran.
We obtain:
[tex]17\text{miles}+21\text{miles}=38\text{miles}[/tex]Find the value of tan X rounded to the nearest hundredth, if necessary.
5
W
1
√26
X
Answers
The value of tan x is 5
We need to find the value of tan x
Tan is one of the trignometric functions and the range of a tan function varies from 0 ≤ tan x ≤ 2π
In the triangle vwx, the perpendicular of x is VW and the base is WX
tan x = perpendicular / base
Here, the perependicular is 5 and base is 1
tan x = 5/1
tan x = 5
Therefore, the value of tan x is 5
To learn more about trignometric functions refer here
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Two cards are drawn from a standard deck without replacement. What is the probability that the first card is a diamond and the second card is red
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The probability that the first card drawn without replacement is a diamond and the second card drawn is red is approximately 0.12
Probability of an event without replacementThe probability for an event without replacement implies that once an item is drawn, then we do not replace it back to the sample space before drawing another item.
In a standard deck of cards, there is a total of 52 cards with 13 diamonds and 26 reds (including diamonds)
probability that the first card drawn is diamond = 13/52
probability that the first card drawn is red = 25/51 {because diamond is also a red and was drawn first without replacement}
So;
probability that the first card is a diamond and the second card is red = (13/52) × (25/51)
probability that the first card is a diamond and the second card is red = 325/2652
probability that the first card is a diamond and the second card is red = 0.1225
Therefore, the proprobability that the first card drawn without replacement a diamond and the second card is red is approximately 0.12
Learn more about probability here: https://brainly.com/question/20140376
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(6-5g)(-3g+9)Multiply polynominals
Answers
The two polynomials are multiplied as follows:
[tex](6-5g)(-3g+9)[/tex]Open the first bracket as follows:
[tex](6-5g)(-3g+9)=6(-3g+9)-5g(-3g+9)[/tex]Open the two brackets as follows:
[tex]\begin{gathered} 6(-3g+9)-5g(-3g+9)=-18g+54+15g^2-45g \\ =15g^2-63g+54 \end{gathered}[/tex]Hence the multiplication of the polynomials results in:
[tex](6-5g)(-3g+9)=15g^2-63g+54[/tex]How many yards are there in 72 miles? Round answer to nearest 100th (2-decimal places).
Answers
Given,
The number of total miles are 72.
As know that,
There are 1760 yards in one mile.
The number of yards in 72 mile is,
[tex]\text{Number of yards=72}\times1760=126720\text{ miles}[/tex]Hence, the nnumber of yards in one mile is 126720.
I dont understand how the answer is 1/3. how do you calculate that answer????
Answers
1/3
Explanation:To convert repeating decimals to fraction, we need to represent it with a variable
let n = 0.3333...
Multiply the above by 100:
100n = 33.3333...
The 3 dots after the 3333 means the numbers continues; hence indicating a repeating decimal
n = 0.3333 ...equation 1
100n = 33.3333 ...equation 2
subtract equation 1 from 2:
100n - n = 33.3333 - 0.3333
100n - n = 99n
99n = 33
divide both sides by 99:
99n/99 = 33/99
n = 1/3
Therefore, 0.3 repeating decimal in fraction is 1/3
What is the solution of the system?{4x−y=−38x+y=3Enter your answer in the boxes.
Answers
Solution:
Given:
[tex]\begin{gathered} 4x-y=-38 \\ x+y=3 \end{gathered}[/tex]Solving the system simultaneously by substitution method;
[tex]\begin{gathered} 4x-y=-38\ldots\ldots\ldots\ldots\ldots(1) \\ x+y=3\ldots\ldots\ldots\ldots\ldots\ldots.(2) \\ \\ \text{making y the subject of the formula from equation (2);} \\ x+y=3 \\ y=3-x\ldots\ldots\ldots\text{.}\mathrm{}(3) \\ \\ \text{Substituting equation (3) into equation (1);} \\ 4x-y=-38 \\ 4x-(3-x)=-38 \\ 4x-3+x=-38 \\ 4x+x=-38+3 \\ 5x=-35 \\ \text{Dividing both sides by 5;} \\ x=-\frac{35}{5} \\ x=-7 \\ \\ \text{Substituting the value of x into equation (3) to get y;} \\ y=3-x \\ y=3-(-7) \\ y=3+7 \\ y=10 \end{gathered}[/tex]Therefore, the solution of the system is;
[tex](x,y)=(-7,10)[/tex]Each participant must pay $14 to enter the race. Each runner will be given a T-shirt that cost race organizers $3.50. If the T-shirt was the only expense for the race organizers, which of the following expressions represents the proportion of the entry fee paid by each runner that would be donated to charity?
Answers
The total amount paid by each participant is $14, from which $3.5 will be used for the T-shirt. As that is the only expense, all the remaining money will be available to donate to charity.
[tex]14-3.5=10.5[/tex]Then, for each participant, $10.5 of the $14 paid will be donated to charity.
To find the proportion of the fee paid that would be donated we just need to divide those values:
[tex]\frac{\text{Amount of money donated}}{\text{Total fee paid}}[/tex][tex]\frac{10.5}{14}=\frac{3}{4}[/tex]Then, 3/4 is the proportion of the entry fee paid that will be donated to charity.
Find the point on the curve y=5x+1 closest to the point (0,4).
Answers
Given the coordinates of two points P and Q, we can calculate the distance between them using the formula:
[tex]\begin{gathered} \begin{cases}P={(x_P},y_P) \\ Q={(x_Q},y_Q)\end{cases} \\ . \\ d=\sqrt{(x_P-x_Q)^2+(y_P-y_Q)^2} \end{gathered}[/tex]In this case, we want the smallest distance between a point in the curve and the point (0, 4)
Then, we know that there is a point that we can call Q = (x, y) that is the closest to the point (0, 4). We can write, using the distance formula:
[tex]d=\sqrt{(x-0)^2+(y-4)^2}=\sqrt{x^2+(y-4)^2}[/tex]The equation given is:
[tex]y=5x+1[/tex]We want to rewrite the distance formula to include the equation of the curve. Since there is a term 'x²', we can solve the equation for x and square on both sides:
[tex]\begin{gathered} y=5x+1 \\ . \\ y-1=5x \\ , \\ x=\frac{y}{5}-\frac{1}{5} \\ . \\ x^2=(\frac{y}{5}-\frac{1}{5})^2 \end{gathered}[/tex]Now we can substitute in the distance equation:
[tex]d=\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}[/tex]We can see that this is a distance function for any point of the curve to the point (0, 4). This is actually a function of y.
[tex]d(y)=\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}[/tex]Now, we can apply calculus to find the minimum of this function. Let's take the first derivative:
[tex]d^{\prime}(y)=\frac{\frac{2}{5}(\frac{y}{5}-\frac{1}{5})+2(y-4)}{2\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}}[/tex]Simplify:
[tex]d^{\prime}^(y)=\frac{26y-101}{25\sqrt{(\frac{y}{5}-\frac{1}{5})^2+(y-4)^2}}[/tex]And since we want to find a minimum, we need to also calculate the second derivative:
[tex]d^{\prime}^{\prime}(y)=\frac{26\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}-\frac{(2(y-4)+\frac{2}{5}(\frac{y}{5}-\frac{1}{5})(26y-101)}{2\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}}}{25((y-4)^2+(\frac{y}{5}-\frac{1}{5})^2)}[/tex]Simplify:
[tex]d^{\prime}^{\prime}(y)=\frac{9}{25((y-4)^2+(\frac{y}{5}-\frac{1}{5})^2)^{\frac{3}{2}}}[/tex]Now, we need to find the critical points of the function. The critical points are the x values where the first derivative is 0.
Then:
[tex]d^{\prime}(y)=\frac{26y-101}{25\sqrt{(y-4)^2+(\frac{y}{5}-\frac{1}{5})^2}}[/tex]Is a quotient, For a quotient to be 0, the only way this is possible is for the numerator to be 0. Then:
[tex]\begin{gathered} 26y-101=0 \\ . \\ y=\frac{101}{26} \end{gathered}[/tex]And now, to see if this critical point is a minimum, we evaluate it in the second derivative, if the second derivative is positive in this critical point, the function has a minimum at that point:
[tex]d^{\prime}^{\prime}(\frac{10}{26})=\frac{9}{25((\frac{101}{26}-4)^2+(\frac{101}{26}-\frac{1}{5})^2)^{\frac{3}{2}}}\approx1.76746[/tex]Then, the function d(y) has a minimum at y = 101/26
Now, we need to find the x coordinate of this point. We use the equation of the curve:
[tex]\begin{gathered} \frac{101}{26}=5x+1 \\ . \\ x=(\frac{101}{26}+1)\cdot\frac{1}{5}=\frac{15}{26} \end{gathered}[/tex]Thus, the answer to the point in the curve that is the closest to (0, 4) is:
[tex](\frac{15}{26},\frac{101}{26})[/tex]Find the solution for the given the system of equations:Y= (1/2)x - 1/2 and y=2^(x+3)
Answers
Answer:
This system has no solution.
Step-by-step explanation:
The solution of this system is the ordered pair that is the solution to both equations, we can solve this using the graphical method, which consists of graphing both equations in the same coordinate system.
The solution to the system will be at the point where the two functions intersect.
Since the functions do not intersect, this system has no solution.
Given the line segment with points P (1,6) andQ (9,-4). What is the length of PQ?(2 Points)
Answers
When 2 coordinate points are given, we can find its length by using the distance formula. Which is
[tex]\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]We
• take differences in y coordinates and x coordinates
,• square them
,• take their sum
,• take square root of the answer
Tha's all.
So, let's do the steps:
y diff: -4 -6 = -10
x diff: 9-1 = 8
Now, it becomes:
[tex]\begin{gathered} \sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ =\sqrt[]{(-10)^2+(8)^2} \\ =\sqrt[]{164} \\ =2\sqrt[]{41} \end{gathered}[/tex]The length of PQ (exact) is:
[tex]2\sqrt[]{41}[/tex]In decimal: 12.81
Find and graph the intercepts of the following linear equation:5x-2y=-10
Answers
x-intercept = -2
y-intercept = 5
Explanation:[tex]\begin{gathered} Given: \\ 5x\text{ - 2y = -10} \end{gathered}[/tex]x-intercept is the value of x when y = 0
To get the x-intercept, we will substitute y with zero:
[tex]\begin{gathered} 5x\text{ - 2\lparen0\rparen = -10} \\ 5x\text{ = -10} \\ divide\text{ both sides by 5:} \\ x\text{ = -10/5} \\ \text{x = -2} \\ So,\text{ the x-intercept = -2} \end{gathered}[/tex]y-intercept is the value of y when x = 0
To get the y-intercept, we will substitute x with zero:
[tex]\begin{gathered} 5(0)\text{ - 2y = -10} \\ -2y\text{ = -10} \\ divide\text{ both sides by -2:} \\ \frac{-2y}{-2}\text{ = }\frac{-10}{-2} \\ division\text{ of same signs give positive sign} \\ y\text{ = 5} \\ So,\text{ the y-intercept = 5} \end{gathered}[/tex]Plotting the graph:
Select the correct answer.Which expression is equivalent to this quotient?+++55 + 15OA.1 + 35(1 + 5)2I + 31 + 5ОВ.O C.1 + 3ODI + 5ResetNext2022 Edmentum. All rights reserved.
Answers
Given
[tex]\frac{\frac{1}{x+5}}{\frac{x+3}{5x+15}}[/tex]Answer
[tex]\begin{gathered} \frac{\frac{1}{x+5}}{\frac{x+3}{5x+15}} \\ =\frac{1}{x+5}\times\frac{5(x+5)}{x+3} \\ \frac{5}{x+3} \end{gathered}[/tex]A dilation with a scale factor of 2 maps ....
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The measure of the angles is the same. After a dilation what changes is the length of the sides, but the angles are the same of
[tex]\measuredangle B\text{ = }\measuredangle E[/tex]The second choice is correct.
Solve the inequalities. State whether the inequalities have no solutions or real solutions.4( 3 - 2x) > 2( 6 - 4x)
Answers
Given an inequalities show if it have no solutions or real solutions:
[tex]4(3-2x)>2(6-4x)[/tex]Step 1: Expand the inequalities
[tex]\begin{gathered} 4(3-2x)>2(6-4x) \\ 12-8x>12-8x \end{gathered}[/tex]Step 2: Subtract 12 from both side of the inequalities
[tex]\begin{gathered} 12-8x>12-8x \\ \text{subtract 12 from both side} \\ 12-8x-12>12-8x-12 \\ -8x>-8x \end{gathered}[/tex]Step 3: Add 8x to both side of the inequalities
[tex]\begin{gathered} -8x>-8x \\ \text{add 8x to both side} \\ -8x+8x>-8x+8x \\ 0>0 \end{gathered}[/tex]Therefore the solution for the above inequalities is No solution