Give the slope and the Y intercept of the line represented by y-7=-7x

Answers

Answer 1

Answer:

• m=-7

,

• b=7

Explanation:

Given the line:

[tex]y-7=-7x[/tex]

To determine the slope and y-intercept, first, express the line in the slope-intercept form (y=mx+b).

[tex]\implies y=-7x+7[/tex]

You can then compare:

• Slope, m = -7

,

• y-intercept, b =7

The slope of the line is -7 and the y-intercept is 7.


Related Questions

The value of an antique car is modeled by the function

Answers

[tex]V(t)=150\cdot(1.004)^t[/tex]

when we are modeling increments using functions the standard form should be

[tex]V(t)=A\cdot(1+r)^t[/tex]

In which A represents the initial value and r represents the rate it is increasing per year.

In this case to find what is the increment per year we equal what is inside the parentheses

[tex]\begin{gathered} 1+r=1.004 \\ r=1-1.004 \\ r=0.004 \end{gathered}[/tex]

now this decimal can be represented as a percentage if we multiply by 100

[tex]\begin{gathered} \text{\%r}=0.004\cdot100 \\ \text{\%r=0.4\%} \end{gathered}[/tex]

It is increasing by 0.4% per year.

It takes 3 1/3 spoons of chocolate syrup to make 3 1/2 į gallons of chocolate milk.How many spoons of syrup would it take to make 5 gallons of chocolate milk?

Answers

Given:

[tex]3\frac{1}{3}spoons\text{ of chocolate syrup to make 3}\frac{1}{2}\text{ gallons of chocolate milk.}[/tex][tex]\begin{gathered} \text{Number of spoons required of syrup to make 5gallons of chocolate milk=}\frac{3\frac{1}{3}}{3\frac{1}{2}}\times5 \\ No\text{ of spoons required of syrup to make 5gallons of chocolate milk=}\frac{\frac{10}{3}}{\frac{7}{2}}\times5 \\ No\text{ of spoons required of syrup to make 5gallons of chocolate milk=}\frac{10}{3}\times\frac{2}{7}\times5 \\ No\text{ of spoons required of syrup to make 5gallons of chocolate milk=}\frac{100}{21} \\ No\text{ of spoons required of syrup to make 5gallons of chocolate milk=}4\frac{16}{21}\text{ } \end{gathered}[/tex]

What are the coordinates of the first and last two points of his route?

Answers

Answer:

Step-by-step explanation:

Suppose that a is an angle with seca alpha = - 11/10 and a is not in the third quadrant. Compute the exact value of sina. You do not have to rationalize the denominatorSin a =

Answers

Answer:[tex]\sin\alpha=0.41628[/tex]

Explanation:

Given that

[tex]sec\text{ }\alpha=-\frac{11}{10}[/tex]

[tex]\alpha=sec^{-1}(-\frac{11}{10})=155.4^o[/tex]

Now

[tex]\sin\alpha=\sin155.4=0.41628[/tex]

Which expression has the same value as sin(20∘)?A)cos(10∘)B)cos(20∘)C)cos(40∘)D)cos(70∘)

Answers

sin 20 = y / r

cos 70 = y/ r

sin 20 = cos 70 = 0.342

Answer:

cos 70

Consider the line . y=3/2x+3Find the equation of the line that is parallel to this line and passes through the point .(-8,3)Find the equation of the line that is perpendicular to this line and passes through the point . (-8,3)

Answers

Answer:

Equation of parallel line: y = 3x/2 + 15

Equation of perpendicular line: y = - 2x/3 - 7/3

Explanation:

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

The equation of the given line is

y = 3x/2 + 3

By comparing with the slope intercept equation,

slope, m = 3/2

Recall, if two lines are parallel, it means that they have the same slope. Thus, the slope of the parallel line passing through the point, (- 8, 3) is 3/2. We would find the y intercept, c by substituting m = 3/2, x = - 8 and y = 3 into the slope intercept equation. We have

3 = 3/2 * - 8 + c

3 = - 12 + c

c = 3 + 12 = 15

By substituting m = 3/2 and c = 15 into the slope intercept equation, the equation of the parallel line passing through the point, (- 8, 3) is

y = 3x/2 + 15

Recall, if two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line. Thus, the slope of the perpendicular line passing through the point, (- 8, 3) is - 2/3. We would find the y intercept, c by substituting m = - 2/3, x = - 8 and y = 3 into the slope intercept equation. We have

3 = - 2/3 * - 8 + c

3 = 16/3 + c

c = 3 - 16/3 = - 7/3

By substituting m = - 2/3 and c = - 7/3 into the slope intercept equation, the equation of the perpendicular line passing through the point, (- 8, 3) is

y = - 2x/3 - 7/3

What is anequation of the line that passes through the points (-7, -7) and(-7,4)?

Answers

The line passes through (-7,-7) and (-7,4); thus the x-component remains fixed but the y-component is free

the y- component can take any value! thus the equation is

x=-7

A company sold garden hoses at a reduced price of $5.64 and took an end of season markdown of $13.35 what was the original selling price of each house? Use the formula M=S-N, where M is the markdown, S is the original selling price, and N is the reduced price. The original selling price of each hose is?

Answers

From the details provided in the question, the formula;

[tex]M=S-N[/tex]

Can be used to derive either of;

Markdown, Original selling price or Reduced price.

Having been given;

[tex]\begin{gathered} \text{Markdown}=13.35 \\ \text{ Reduced Price=5.64} \\ \text{Original selling price=?} \end{gathered}[/tex]

We can now substitute the known values as follows;

[tex]\begin{gathered} M=S-N \\ 13.35=S-5.64 \\ \text{Add 5.64 to both sides;} \\ 13.35+5.64=S-5.64+5.64 \\ 18.99=S \end{gathered}[/tex]

The original selling price, that is N, is now;

$18.99

if like bc is parallel to line AD what is the measure of BAD

Answers

[tex]\begin{gathered} \angle ABC\text{ and }\angle CAD\text{ are supplementary angles } \\ \text{Therefore,} \\ \angle ABC+\angle CAD=180\text{ degree} \\ \angle ABC=3x-7 \\ \angle CAD=2x+32 \\ 3x-7+2x+32=180 \\ 5x+25=180 \\ 5x=180-25 \\ 5x=155 \\ x=\frac{155}{5} \\ x=31 \end{gathered}[/tex][tex]\begin{gathered} \text{Therefore,} \\ \angle BAD=2x+32 \\ \angle BAD=2(31)+32 \\ \angle BAD=62+32 \\ \angle BAD=94\text{ degrees} \end{gathered}[/tex]

D.

When Ryan runs the 400 meter dash, his finishing times are normally distributedwith a mean of 65 seconds and a standard deviation of 2 seconds. If Ryan were to run.36 practice trials of the 400 meter dash, how many of those trials would be between63 and 65 seconds, to the nearest whole number?

Answers

Solution

Step 1

Dalvin's finishing time is normally distributed with a mean of 65 seconds and a standard deviation of 1 second.

[tex]\begin{gathered} \text{Mean }\mu\text{ = 65} \\ Standard\text{ deviation }\sigma\text{ = 1} \end{gathered}[/tex]

Step 2

Under the empirical rule, 68% of the results will be within 1 standard deviation.

Step 3

Since the standard deviation is 1 second, 68% of Dalvin's finishing time will be between 63 and 65 seconds.

Final answer

68%

∣/8∣=3Group of answer choicesx = 2 and x = 4x = 16 and x = 4x = -24 and x = 24x = -6 and x = -8

Answers

Given:

[tex]|\frac{x}{8}|=3[/tex]

Applying absolute value property

[tex]\frac{x}{8}=-3\text{ and }\frac{x}{8}=3[/tex]

Multiply both-side by 8.

That is;

[tex]\begin{gathered} \frac{x}{8}\times8=-3\times8 \\ \\ \text{and } \\ \\ \frac{x}{8}\times8=3\times8 \end{gathered}[/tex]

[tex]x=-24\text{ and x=24}[/tex]

Hence, x=-24 and x=24

Given the area of triangle AEC=63cm^2, find the area of triangle ABC.

Answers

We are given that the area of triangle AEC = 63 centimeters squared.

Since segment CD equals segment DB that means that triangle CDA and triangle BDA have the same area, and also triangle CDE and triangle BDE have the same area. This means mathematically the following:

[tex]A_{\text{ADC}}-A_{\text{AEC}}=A_{\text{ADB}}-A_{\text{AEB}},\text{ (1)}[/tex]

Also

[tex]A_{\text{ADC}}=A_{\text{ADB}},\text{ (2)}[/tex]

Replacing equation (1) in equation (2)

[tex]A_{\text{ADC}}-A_{\text{AEC}}=A_{\text{ADC}}-A_{\text{AEB}}[/tex]

Simplifying

[tex]A_{\text{AEC}}=A_{\text{AEB}}[/tex]

Therefore:

[tex]A_{\text{AEB}}=63\operatorname{cm}^2[/tex]

Since segments DE and EA is the same, then:

[tex]A_{\text{CDE}}=A_{\text{AEC}}[/tex]

Therefore:

[tex]A_{\text{CDE}}=63\operatorname{cm}^2[/tex]

Since

[tex]A_{\text{CDE}}=A_{\text{BDE}}[/tex]

We have:

[tex]A_{\text{BDE}}=63\operatorname{cm}^2[/tex]

therefore, the area of the triangle is:

[tex]A_{\text{ABC}}=A_{\text{AEC}}+A_{\text{AEB}}+A_{\text{CDE}}+A_{\text{BDE}}[/tex]

Replacing the known values:

[tex]\begin{gathered} A_{\text{ABC}}=68+68+68+68=4(68) \\ A_{\text{ABC}}=272\operatorname{cm}^2 \end{gathered}[/tex]

Line A is perpendicular to Line B.If the slope of Line A is -5,what is the slope of Line B?391410

Answers

Given:

Line A is perpendicular to Line B.

Required:

what is the slope of Line B?

Explanation:

Based on the given conditions, formulate.

[tex]m=\frac{-5}{3}[/tex]

Find the slope of line that is perpendicular to

[tex]\frac{-5}{3}[/tex][tex]m=\frac{3}{5}[/tex]

Required answer:

[tex]m=\frac{3}{5}[/tex]

Change to Ax+By=C form. y=-5x+9

Answers

The function is:

[tex]y=5x+9[/tex]

Now to put in the form Ax+By=c we hace to let the number that don't have x ot y in the left side of the equation anthe the rest of the term in the right side of the equation:

[tex]-5x+y=9[/tex]

where:

[tex]\begin{gathered} A=-5 \\ B=1 \\ C=9 \end{gathered}[/tex]

1.X: -2, -1, 0, 1, 2Y: -7, -2, 1, -2, -7Domain:Range:Function: Yes Or no?

Answers

We have

X: -2, -1, 0, 1, 2

Y: -7, -2, 1, -2, -7

the domain is the set of all the possible values for x, in this case, we have

{-2, -1, 0, 1, 2}

the range is the set of all possible values of y in this case we have

{-7, -2, 1}

With this information, we can say it is a function,

Using the following images, name the intersection of line QS and line LC.

Answers

The intersection between two non-parallel lines is a point, as we can see in the following diagram:

As we can see from the image, the intersection point between QS and LC is W.

Answer: Point W

2. You pay $18.00 for 30 text messages. At the same rate, how much would 12text messages cost?17

Answers

$18 for 30 messages

Ratio = price / messages = 18/30

For 12 messages:

Price / messages = x /12

Equal both ratios:

18/30 = x /12

Solve for x:

0.6 (12) = x

$7.2 = x

$7.2 for 12 messages

I need help with my math

Answers

The Slope of a Line

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

[tex]\displaystyle m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The graph provided suggests the use of the points (3,-3) and (5,-3). The slope is:

[tex]\displaystyle m=\frac{-3+3}{5-3}=\frac{0}{2}=0[/tex]

The slope of the line is 0. It corresponds to a horizontal line

The total volume of a tree increases
8% each year. What will its volume be
after 7 years if its volume is 5 cubic
meters now?
A) 5(1.08)^7
B) 5(7)(0.08)
C) 5(0.08)^7
D) 5(7)(1.08)

Answers

Answer:

A

Step-by-step explanation:

it all starts with 5 m³.

after one year this will be

5 × 1.08

as the original 5 m³ have increased by 8% (= multiplication by 1.08, as 8% = 0.08, and adding 8% means 100% + 8% = 1 + 0.08 = 1.08).

after the second year we will see another increase by 8% compared to the previous year.

so,

(5 × 1.08) × 1.08 = 5(1.08)²

...

and so, after the nth year, the volume is

5(1.08)^n

therefore, after 7 years means n = 7, and we get

5(1.08)⁷

Can anyone help me with this (there is a part two)

Answers

Number of bottles: 6

Coupon discount on each bottle: $0.50

Final price: $5.10

If p is the regular price of each bottle, then 6p is the regular price of 6 bottles. This means that we have used 6 coupons of $0.50, so the total discount should be 6*0.50 dollars. We subtract this amount from the regular price (6p), leading to $5.10. The equation that represents this situation is:

[tex]\begin{gathered} 6p-6\cdot0.50=5.10 \\ \Rightarrow6(p-0.50)=5.10 \end{gathered}[/tex]

There were 750 books sold last week at side bookstore. The table below summarizes these books by genre. This information is also presented as a circle graph. Find the central angle measure x, for self help slice in the circle graph. Do not round.

Answers

we have that

total books sold=750

self help=117

the percentage of self-help books is equal to

117/750=0.156=15.6%

Remember that

in the complete circle, the angle of 360 degrees represents the 100%

so

Applying proportion

Find out the measure of angle x for a percentage equal to 15.6%

360/100=x/15.6

solve for x

x=(360/100)*15.6

x=56.16 degrees

if anyone could help me on #17 i would appreciate it!

Answers

Answer:

[tex]f(x)=-\lvert x-7\rvert+2[/tex]

Step-by-step explanation:

The function that was transformed is:

[tex]f(x)=\lvert x\rvert[/tex]

If it reflects in the x-axis, shift 7 units to the right, and shift upward 2 units, we need to know the transformation rules for these displacements:

[tex]\begin{gathered} \text{ -f(x) reflects the function in the x-axis (upside-down)} \\ f(x-b)\text{ shifts the function b units to the right.} \\ \text{ f(x)+b shifts the function b units upward.} \end{gathered}[/tex]

Now, with this in mind, the equation of the function transformed would be:

[tex]f(x)=-\lvert x-7\rvert+2[/tex]

A bag is made with 1,350 green, blue, and white beads. Twice as many green beads as blue beads are used the number of white beads is half of the total number of green and blue beads. how many green beads are used?

Answers

Write equations for each succeeding sentences. Use G for green, B for blue, and W for white beads.

[tex]\begin{gathered} G+B+W=1350 \\ G=2B \\ W=\frac{1}{2}(G+B) \\ G=\text{?} \end{gathered}[/tex]

Solve for the value of G as follows.

Rewrite the equations in terms of B. Since the value of G is already written in terms of B, write the value of W in terms of B.

[tex]\begin{gathered} W=\frac{1}{2}(G+B)_{}_{} \\ =\frac{1}{2}(2B+B) \\ =\frac{1}{2}(3B) \end{gathered}[/tex]

Substitute the values of G and W, in terms of B, into the first equation and then solve for B.

[tex]\begin{gathered} G+B+W=1350 \\ 2B+B+\frac{1}{2}(3B)=1350 \\ 4B+2B+3B=2700 \\ 9B=2700 \\ B=300 \end{gathered}[/tex]

Note that we obtained the third equation by multiplying both sides of the equation by 2. This eliminates the denominator, 2, from the left side of the equation.

Substitute the obtained value of B in the second given equation to solve for G.

[tex]\begin{gathered} G=2B \\ =2(300) \\ =600 \end{gathered}[/tex]

Substitute the obtained value of B into the obtained value of W and then simplify.

[tex]\begin{gathered} W=\frac{1}{2}(3B) \\ =\frac{1}{2}\lbrack3(300)\rbrack \\ =\frac{1}{2}(900) \\ =450 \end{gathered}[/tex]

To check if the answer is correct, add all the number of beads per color and determine if the sum is the same as the given value.

[tex]\begin{gathered} G+B+W=1350 \\ 600+300+450=1350 \\ 1350=1350 \end{gathered}[/tex]

Since the equation is true, the answers are correct.

Therefore, there must be 600 green beads that were used.

When a figure is translated its orientation (blank) and the measurements of its angles (blank).The options for both blanks are the same and the options are, remain the same or change

Answers

First of all, remember that translation is a transformation which doesn't imply a change of size or shape, that is, the image will be congruent to its image.

Having said that, the complete paragraph would be

When a figure is translated its orientation remains the same and the measurements of its angles remain the same.

The orientation doesn't change because it's defined as the position of points of the figure, these points change its position where we rotate the figure, which is not the case here.

the following ordered pairs give the entrance exam scores x and the grade-point averages y after 1 year of college for 10 students.interpret the slope of the line in a relationship of the problem.

Answers

Find the slope

we take the points

(75,2.3) and (82,3)

so

m=(3-2.3)/(82-75)

m=0.7/7

m=0.1

the units of the slope are grade-point averages by entrance exam scores

Chris rented a truck for one dah There was a base fee of 18.95$ and there was an additional charge of 83 cents for each mile driven. Chris had to pay 209.02 when he returned the truck. For how many miles did he drive the truck?

Answers

Given:

Base fee $18.95

83 cents for each mile driven.

[tex]\text{Amount excluding the base fee=209.02-18.95}[/tex][tex]\text{Amount excluding the base fee= \$}190.07[/tex][tex]\text{Number of miles driven =}\frac{\text{19007}}{83}[/tex][tex]undefined[/tex]

Wich function is used to find y,the remaining balance after x number of payments have been made?

Answers

The slope of a line that passes through points (x1, y1) and (x2, y2) is computed as follows:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The line of the picture passes through (0, 20000) and (40, 0) then its slope is:

[tex]m=\frac{0-20000}{40-0}=-500[/tex]

The y-intercept of the line is (0, 20000)

Slope-intercept form of a line:

y = mx + b

where m is the slope and b is the y-coordinate of the y-intercept. Replacing with m = -500 and b = 20000, we get:

y = -500x + 20000

60 is the LCM of witch of the following pair of numbers? 12 and 18 .....10 and 30.......15 and 20......20 and 25 witch on

Answers

The correct pair is 15 and 20

Here, we want to select the pair of numbers which 60 is their LCM

What this mean is we want to select two numbers that 60 is the smallest multiple they have

For 12 and 18, the lcm is 36; so this is incorrect

For 10 and 30, the lcm is 30; so this is also incorrect

for 20 and 25, the lcm is 100; this is also incorrect

for 15 and 20, the lcm is 60 and this is our correct choice

What value of x will make the following equation true? Log4(4^5x+1)=16•7/5•0•1/5•3(Picture for clarification)

Answers

Given:

There are given that expression:

[tex]log_4\left(4^{5x+1}\right?=16[/tex]

Explanation:

From the given log function:

[tex]log_4(4^{5x+1})=16[/tex]

According to the log rule:

[tex]5x+1=16[/tex]

Then,

[tex]\begin{gathered} 5x+1=16 \\ 5x=16-1 \\ x=\frac{15}{5} \\ x=3 \end{gathered}[/tex]

Final answer:

Hence, the correct option is D.

Find the quotient. Express the final result using positive integer exponents only (72x^-1 y^4)^-1 / (8x^8y^3)

Answers

ANSWER:

[tex]\frac{1}{576x^7y^7}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]\frac{\left(72x^{-1}y^4\right)^{-1}}{8x^8y^3}[/tex]

We operate to simplify and we are left with the following:

[tex]\frac{72^{-1}x^{-1\cdot-1}y^{4\cdot-1}}{8x^8y^3}=\frac{\frac{1}{72}xy^{-4}}{8x^8y^3}=\frac{1}{72\cdot8\cdot x^8\cdot x^{-1}\cdot y^3\cdot y^4}=\frac{1}{576x^7y^7}[/tex]

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