Which shows the graph of x - 4y=-4?5O1 2 3 4 5 x433-2+4-5-4-3-2-12-لنا -343-51543212-A
Answers
Explanation
Using a graphing calculator, the graph of x-4y =-4 can be seen below.
Related Questions
when solving the system below algebraically using the substitution method, which of the following could be an equation you could. create to solve for x?A) x = 3y - 3B) -2x + 6(2x + 11) = 6C) -2x - 6 = - 2x - 11D) -2 (3y - 3) + y = 11
Answers
We have that the solutions of the system are
[tex]x\text{ = -6 and y = -1}[/tex]So we are going to check which of the answers give that answer, we are going to try with A fisrt
[tex]x\text{ = }3(-1)\text{ }-3\text{ = -6}[/tex]So with A, the solutions are the same, so we have that the answer is A.
12) Triangle ABC and A'B'C' are shown on the coordinate plane. Which algebraic representation showshow to find the coordinates of triangle A'B'C'?
Answers
x,y) ---------> (2/3x, 2/3y)
1) For that dilation, we always start from the pre-image. In this case, the ABC is the bigger one
So taking one point of that triangle as an example.
C(9,3)
And one of that image
C'( 6,2)
Dilating from C to C' all other points follow that same rule.
2) This leads us to conclude
Pre image Image
(x,y) ---------> (2/3x, 2/3y)
this is confusing isnt there supposed to be 2 numbers
Answers
Let's begin by listing out the information given to us:
Angle U = 27°
TU is tangent to S implies this is a right triangle
Angle T = 90°
The sum of interior angles in a triangle is 180 degrees
U + T + S = 180°
⇒27 + 90 + S = 180
⇒S = 180 - (90 + 27) = 53
S = 53°
hi how are you I need help with this question.
Answers
Hello
Question one requires us to find the value of the angle
Using trigonometric ratios
SOHCAHTOA
[tex]\begin{gathered} \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \\ \text{opposite}=8 \\ \text{adjacent}=10 \\ \tan \theta=\frac{8}{10} \\ \tan \theta=0.8 \\ \theta=\tan ^{-1}0.8 \\ \theta=38.66\approx38.7^0 \end{gathered}[/tex]For question b, we can use trigonometric ratio to find the value of the missing side or use pythagoran's theorem
I would use pythagoran's theorem here because we would arriave at our answer faster
[tex]\begin{gathered} x^2=y^2+z^2 \\ x^2=8^2+10^2 \\ x^2=64+100 \\ x^2=164 \\ \text{take the square root of both sides} \\ x=\sqrt[]{164} \\ x=12.81\approx12.8 \end{gathered}[/tex]From the calculations above, the value of the angle is 38.7 degree and the missing side is 12.8 units
what is the measure of m<1 will ensure that the rail is parallel to the bottom of the staircase?
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You can observe that angle 1 and angle with 47° are inside a parallelogram.
Consider that the sum of the internal angles of a parallelogram is 360°.
Moreover, consider that the angle at the top right of the parallogram is congruent with the angle of 47°, then, such an angle is if 47°.
Consider that angle down right side is congruent with angle 1, then, they have the same measure.
You can write the previous situation in the following equation:
47 + 47 + ∠1 + ∠1 = 360 simplify like terms
94 + 2∠1 = 360 subtract both sides by 94
2∠1 = 360 - 94
2∠1 = 266 divide by 2 both sides
∠1 = 266/2
∠1 = 133
Hence, the measure of angle 1 is m∠1 = 133°
help pls for geometry
Answers
Answer:
ohhh that one is hard but i think is ur mom
Step-by-step explanation:
i wanted to wast y0our time but hopefully you get the answet
Jenny knit a total of 12 centimeters of scarf over 2 nights. How many nights will Jenny have
to spend knitting in order to knit a total of 18 centimeters of scarf? Assume the relationship is
directly proportional.
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As we can assume the relationship is directly proportional, we have to build the proportion and do the cross product. So:
[tex]\begin{gathered} \frac{12cm}{\text{2 nights}}=\frac{18cm}{x\text{ nights}} \\ 12x=2\cdot18 \\ 12x=36 \\ x=\frac{36}{12} \\ x=3 \end{gathered}[/tex]She needs 3 nights
f the area of the rhombus below is 232 m 2, and diagonal AC = 16 m, find the length of diagonal BD.
Answers
The formula for calculating the area of a rhombus is expressed as
Area = 1/2d1d2
where
d1 and d2 are the lengths of the diagonals
From the information given,
Area = 232
d1 = AC = 16
d2 = BD
Thus,
232 = 1/2 x 16 x BD
232 = 8BD
BD = 232/8
BD = 29
What strategies can be used to find solutions for equations such as 2,000 = 20x + 10y?
Answers
The strategies you can use to solve the equation 2000 = 20x + 10y are
1. if you have information on the values of y and x.
2. By establishing another relationship of y and x values. This relationship can now be solved simultaneously using substitution method or elimination method. Graphing can also be used to solve the equation.
PLEASE HELPFind the value of x.B68ХDx = [?]
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Since the triangles are similar, that means the the prop
Find the area:*1 point8 in- .Your answerI
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Write the quadratic function with the indicated characteristics. The graph passes through the origin and the points (-3, 0) and (-1, 3).
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substituteGiven:-
[tex](0,0),(-3,0)(-1,3)[/tex]To find the quadratic equation.
So now we use the formula,
[tex]y=ax^2+bx+c[/tex]So now we subtitute the points and find the value of a,b,c. So we get,
[tex]\begin{gathered} 0=a(0)+b(0)+c \\ c=0 \end{gathered}[/tex]Also,
[tex]\begin{gathered} 0=a(-3)^2+b(-3)+c \\ 0=9a-3b \end{gathered}[/tex]Also,
[tex]\begin{gathered} 3=a(-1)^2+b(-1)+0 \\ 3=a-b \end{gathered}[/tex]So now we simplify both equation. so we get,
[tex]\begin{gathered} 9a-3b=0 \\ 3a-3b=9 \end{gathered}[/tex]Now we add both the equations. we get,
[tex]\begin{gathered} 6a=-9 \\ a=-\frac{3}{2} \end{gathered}[/tex]Now we find the value of b, so we get,
[tex]\begin{gathered} a-b=3 \\ -\frac{3}{2}-b=3 \\ -b=3+\frac{3}{2} \\ -b=\frac{9}{2} \\ b=-\frac{9}{2} \end{gathered}[/tex]So the required values are,
[tex]y=-\frac{3}{2}x^2-\frac{9}{2}x+0[/tex]11 divided by 2014
(Lond division answer)
Answers
Answer:
0.005461767627
Step-by-step explanation:
0.005461767627
filling in to send
Relate decimals and fractionsOf the 100 students in the fourth grade, 70 students are girls.Write a fraction in tenths and a fraction in hundredths to tell what fraction of the fourth-grade students are girls Question 5 Write a fraction in tenths and a fraction in the hundredths to tell what fraction of the fourth-grade students are boys
Answers
Step 1. Gather all of the information.
Out of 100 students, 70 students are girls. This also means that the other 30 students are boys:
--> 70 girls, and 30 boys for every 100 students.
Step 2. Write a fraction in tenths and a fraction in hundredths to tell what fraction of the fourth-grade students are girls.
The fraction in hundredths:
[tex]\frac{70}{100}[/tex]To find the fraction in tenths, we simplify the previous fraction by dividing both numbers by 10, and the resulting numbers are 7 and 10.
The fraction in tenths:
[tex]\frac{7}{10}[/tex]Step 3. Write a fraction in tenths and a fraction in the hundredths to tell what fraction of the fourth-grade students are boys.
In this case, we use 30 instead of 70 because now we are talking about the number of boys.
The fraction in hundredths:
[tex]\frac{30}{100}[/tex]We do the same as we did in step 2 to find the fraction tenths, divide both numbers by 10, the result is 3 and 10.
The fraction in tenths:
[tex]\frac{3}{10}[/tex]Answer:
Write a fraction in tenths and a fraction in hundredths to tell what fraction of the fourth-grade students are girls
[tex]\frac{7}{10}\text{ and }\frac{70}{100}[/tex]Write a fraction in tenths and a fraction in the hundredths to tell what fraction of the fourth-grade students are boys
[tex]\frac{3}{10}\text{ and }\frac{30}{100}[/tex]
the denominator of a fraction is 3 more than the numerator. if both the numerator and denominator are increased by 4, the new fraction is equal to 3/4. what is the original fraction
Answers
Explanations:
Let the numerator of the fraction be x and let the denominator be y.
Hence, the original fraction is:
[tex]\frac{x}{y}[/tex]It is given that the denominator is 3 more than the numerator. It follows that:
[tex]y=x+3[/tex]It is also given that when both the numerator and denominator are increased by 4, the new fraction is equal to 3/4. This implies mathematically to the equation:
[tex]\frac{x+4}{y+4}=\frac{3}{4}[/tex]Simplify this equation:
[tex]\begin{gathered} 4(x+4)=3(y+4) \\ \Rightarrow4x+16=3y+12 \end{gathered}[/tex]Substitute y=x+3 into this equation:
[tex]4x+16=3(x+3)+12[/tex]Solve the equation for x:
[tex]\begin{gathered} \Rightarrow4x+16=3x+9+12 \\ Collect\text{ like terms:} \\ \Rightarrow4x-3x=9+12-16 \\ \Rightarrow x=5 \end{gathered}[/tex]Substitute x=5 into the equation y=x+3:
[tex]y=5+3=8[/tex]Hence, x=5, and y=8.
It follows that the original fraction is 5/8.
Answer:
The original fraction is 5/8.
The ordered pair (8,5) represents a point on the graph of a proportional relationship. Which ordered pair also represents a point on the same graph? A. (5/8, 1) B. (1, 5/8) C. (5,8) D. (1, 8/5)
Answers
Given the ordered pair:
(8, 5)
Let's find the ordered pair that represents a point on the same graph assuming this is a graph of a proportional relationship.
Here, we have:
(x, y) ==> (8, 5)
Since this is a graph of a proportional relationship, let's find the constant of proportionality.
We have:
[tex]K=\frac{y}{x}=\frac{5}{8}[/tex]This means when x is 1, y is 5/8.
Thus, the ordered pair that also represents a point on the same graph is:
[tex](1,\frac{5}{8})[/tex]ANSWER:
[tex]\text{ B. (1, }\frac{5}{8})[/tex]Leila purchased 21.5 centimeters of wire for $17.20.Find the unit price in dollars per centimeter.If necessary, round your answer to the nearest cent.
Answers
Explanation
Given: Leila purchased 21,5cm of wire for $17.20.
Required: To determine the unit price in dollars per centimeter.
This is achieved thus:
To determine the unit price per centimeter, we divide the cost by the length of wire as follows:
[tex]\begin{gathered} 21.5cm=\text{ \$}17.20 \\ \therefore1cm=\frac{\text{ \$}17.20}{21.5}=\text{ \$}0.80 \end{gathered}[/tex]Hence, the answer is:
[tex]\text{ \$}0.80\text{ }per\text{ }centimeter[/tex]1) Two integers have a sum of 47 and a difference of 23. Find the product of the numbers.
Answers
Given:
Two intergers have a sum of 47 and a difference of 23.
Let's find the product of the two numbers.
Let x and y represent the numbers.
We have:
Two integers have a sum of 47: x + y = 47
Two integers have a difference of 23: x - y = 23
We gave the system of equations:
x + y = 47.......................equation 1
x - y = 23.......................equation 2
Let's solve the system simultaneously using substitution method.
Rewrite equation 1 for x:
x = 47 - y
Substitute (47 - y) for x in equation 2:
(47 - y) - y = 23
47 - y - y = 23
47 - 2y = 23
Subtract 47 from both sides:
47 - 47 - 2y = 23 - 47
-2y = -24
Divide both sides of the equation by -2:
[tex]\begin{gathered} \frac{-2y}{-2}=\frac{-24}{-2} \\ \\ y=12 \end{gathered}[/tex]Now, substitute 12 for y in either of the equations.
Let's take equation 1.
x + y = 47
x + 12 = 47
Subtract 12 from both sides:
x + 12 - 12 = 47 - 12
x = 35
Therefore, we have:
x = 35, y = 12
The numbers are 35 and 12.
To find the product of the numbers, let's multiply the numbers:
35 x 12 = 420
Therefore, the product of the numbers is 420.
ANSWER:
420
I just need the answer to check my work no explanation needed
Answers
To solve for z, we proceed as follows:
[tex](\frac{1}{4})^{3z-1}=16^{z+2}\times64^{z-2}[/tex]Now, we simplify the expression on the right-hand side of the equation as follows:
[tex](\frac{1}{4})^{3z-1}=(4^2)^{z+2}\times(4^3)^{z-2}[/tex][tex](\frac{1}{4})^{3z-1}=4^2^{(z+2)}\times4^3^{(z-2)}[/tex][tex](\frac{1}{4})^{3z-1}=4^{2z+4}\times4^{3z-6}[/tex][tex](\frac{1}{4})^{3z-1}=4^{2z+4+3z-6}[/tex][tex](\frac{1}{4})^{3z-1}=4^{5z-2}[/tex]Now, we simplify the expression on the left-hand side of the equation as follows:
[tex](4^{-1})^{3z-1}=4^{5z-2}[/tex][tex]4^{-1(3z-1)}=4^{5z-2}[/tex][tex]4^{-3z+1}=4^{5z-2}[/tex]Now, since we have both expressions on the left and right hand sides to have a base of 4, we can simply equate their indices, as follow:
[tex]\begin{gathered} 4^{-3z+1}=4^{5z-2} \\ \Rightarrow-3z+1=5z-2 \\ \end{gathered}[/tex]Now, we collect like terms:
[tex]-3z-5z=-2-1[/tex][tex]\begin{gathered} -8z=-3 \\ \Rightarrow z=\frac{-3}{-8} \\ \Rightarrow z=\frac{3}{8} \end{gathered}[/tex]9. the product of c and 10
Answers
SOLUTION
9. We want to find the product of c and 10.
Product means multiplication. So the product of c and 10 means
[tex]c\times10[/tex]So we bring 10 and c together, to get 10c.
Hence the answer is 10c
QUESTION 4 of 10: A "direct response" social media advertisement offers a 50% discount at your restaurant for one of two people diningtogether as a couple on Valentine's Day. The discount will apply to the lower priced meal. One meal will cost $24.77 and the other costs$22.56. What will the total cost of the check be with the discount?a) $24.77b) $34.95c) $36.05d) $47.33Submit
Answers
QUESTION 4 of 10: A "direct response" social media advertisement offers a 50% discount at your restaurant for one of two people dining
together as a couple on Valentine's Day. The discount will apply to the lower priced meal. One meal will cost $24.77 and the other costs
$22.56. What will the total cost of the check be with the discount?
a) $24.77
b) $34.95
c) $36.05
d) $47.33
step 1
apply discount to the lowe price
so
the lower price is $22.56
50%=50/100=0.50
0.50(22.56)=$11.28step 2
step 2
adds the costs
11.28+24.77=$36.05
therefore
answer C
Interpret parts of the algebraic expression to describe the real-world scenario.
Answers
Answer:
Given equation is, (Dollar value of a sandwich shop of a tip jar)
[tex]0.65h+1.25[/tex]h is the number of hours since the shop opened.
a) To find the value where the tip jar increasing per hour.
we know that,
A slope of a line is the change in y coordinate with respect to the change in x coordinate.
The slope or gradient of a line is a number that describes both the direction and the steepness of the line. That gives the value of the rate of y with respect to x.
The equation of a line with slope and intercept is,
y=mx+c
where m is the slope.
The increasing value of a tip jar per hour is the slope of the given equation.
The slope of the ginen equation is,
[tex]0.65[/tex]we get,
$0.65 is value of the tip jar increasing per hour
Answer is: $0.65 is value of the tip jar increasing per hour.
b) To find the initial value of the tip jar when the shop opens.
Given equation is, (Dollar value of a sandwich shop of a tip jar)
[tex]0.65h+1.25[/tex]h is the number of hours since the shop opened.
When the shop opens, we get that h=0
Substitute h=0 in the given equation we get,
[tex]1.25[/tex]Therefore, the initial value of the tip jar when the shop opens is $1.25.
Answer is: Therefore, the initial value of the tip jar when the shop opens is $1.25.
Nina and Nathan are creating a budget so they can afford paying all their billsand save to move to a nicer apartment. They decide that the ratio of spendingto saving needs to be 7:3. Last month their bills totaled $3975.20. Theymanaged to save $1,248.00. What was their actual spending ratio? At thisrate, will they meet their goal?
Answers
The ratio of spending to savings needs to be 7:3.
The actual spending ratio is 3,975.20 : 1,248.00.
In order to reach the goal, the actual spending ratio must the lower than the decided spending ratio.
3,975.20 : 1,248.00 < 7:3.
Dividing the ratios:
3.18 < 2.33
Since 2.33 is not greater than 3.18, they will not reach their goal at this rate.
A mechanic has a length of hose 3 ft long. What is the length after 9in is cut off?The length is _ ft _ in?
Answers
ANSWER
[tex]2ft\text{ 3 in}[/tex]EXPLANATION
We want to find the length of the hose after 9 inches have been cut off.
First, convert the original length of the hose from feet to inches by multiplying by 12:
[tex]\begin{gathered} 1ft=12in \\ \Rightarrow3ft=3\cdot12in=36in \end{gathered}[/tex]Next, subtract 9 inches from that value:
[tex]\begin{gathered} 36-9 \\ \Rightarrow27in \end{gathered}[/tex]Finally, convert the length to feet by dividing by 12:
[tex]\begin{gathered} \frac{27}{12}ft \\ \Rightarrow2\frac{3}{12}ft \\ \Rightarrow2ft3in \end{gathered}[/tex]That is the answer.
Solve the equation. Round the result to two decimal places when appropriate. [tex] {x}^{6} + 36 = 100[/tex]
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A chemistry teacher needs to mix a 20% salt solution with a 80% salt solution to make 15 qt of a 40% salt solution. How many quarts of each solution should the teacher mix to get the desired result?20% salt solution qt80% salt solution qt
Answers
Given that the chemistry teacher needs to mix a 20% salt solution with an 80% salt solution to make 15 quarts of a 40% salt solution.
Let be "x" the number of quarts of 20% salt solution the teacher should mix to get the desired result, and "y" the number of quarts of 80% salt solution the teacher should mix to get the desired result.
You can write the following System of Equations using the information provided in the exercise:
[tex]\begin{cases}0.2x+0.8y={(0.4)(15)} \\ x+y=15\end{cases}[/tex][tex]\begin{cases}0.2x+0.8y={6} \\ x+y=15\end{cases}[/tex]In order to solve the exercise, you can use the Substitution Method:
1. Solve the second equation for "y":
[tex]y=15-x[/tex]2. Substitute the new equation into the first equation and solve for "x":
[tex]0.2x+0.8(15-x)=6[/tex][tex]0.2x+12-0.8x=6[/tex][tex]\begin{gathered} x=\frac{-6}{-0.6} \\ \\ x=10 \end{gathered}[/tex]3. Substitute the value into the second original equation and solve for "y":
[tex]\begin{gathered} 10+y=15 \\ y=15-10 \\ y=5 \end{gathered}[/tex]Hence, the answer is:
• 20% salt solution:
[tex]10\text{ }qt[/tex]• 80% salt solution:
[tex]5\text{ }qt[/tex]
Exterminator the average rate of change of f(x)3x+2/x+1 as x changes from x=0 to x=2
Answers
We can see from the question that we have the following function:
[tex]f(x)=\frac{3x+2}{x+1}[/tex]And we need to find the rate of change from x = 0 to x = 2.
1. To find the average rate of change, we need to remember the formula to find it:
[tex]\text{ Average rate of change}=\frac{\text{ change in y}}{\text{ change in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]And we also have the average rate of change for a function, f(x) between x = a and x = b is given by:
[tex]\text{ Average rate of change}=\frac{\text{ change in y}}{\text{ change in x}}=\frac{f(b)-f(a)}{b-a}[/tex]2. Then we have that the average rate of change between x = 0 and x = 2 is as follows:
[tex]\begin{gathered} x=0,x=2 \\ \\ \text{ Average rate of change}=\frac{f(2)-f(0)}{2-0} \\ \end{gathered}[/tex]3. However, we need to find the values for the function when f(2) and f(0). Then we have:
[tex]\begin{gathered} f(x)=\frac{3x+2}{x+1} \\ \\ x=2\Rightarrow f(2)=\frac{3(2)+2}{2+1}=\frac{6+2}{3}=\frac{8}{3} \\ \\ \therefore f(2)=\frac{8}{3} \end{gathered}[/tex]And we also have:
[tex]\begin{gathered} x=0 \\ \\ f(0)=\frac{3x+2}{x+1}=\frac{3(0)+2}{0+1}=\frac{0+2}{1}=\frac{2}{1}=2 \\ \\ \therefore f(0)=2 \end{gathered}[/tex]4. Finally, the average rate of change is given by:
[tex]\begin{gathered} A_{rateofchange}=\frac{f(2)-f(0)}{2-0}=\frac{\frac{8}{3}-2}{2}=\frac{\frac{8}{3}-2}{2}=\frac{\frac{8}{3}-\frac{6}{3}}{2}=\frac{\frac{2}{3}}{2}=\frac{2}{3}*\frac{1}{2}=\frac{1}{3} \\ \\ \therefore A_{rateofchange}=\frac{1}{3} \end{gathered}[/tex]Therefore, in summary, we have that the average rate of change of the function:
[tex]f(x)=\frac{3x+2}{x+1},\text{ between x = 0 to x =2 is: }\frac{1}{3}[/tex]Sample proportions of size ten were taken from a group of students. Students were asked if they wore glasses while watching TV. The proportion that wore glasses while watching TV was recorded. The standard deviation of the data is 0.19 The margin of error can be given by the formula Margin ferror = 2 * s/(sqrt(n)) where s is the standard deviation and n is the sample size . What is the margin of error for the data collected ?
Answers
Margin of error:
[tex]ME=2\times\frac{s}{\sqrt{n}}[/tex]For the given data collected
[tex]\begin{gathered} s=0.19 \\ n=10 \\ \\ ME=2\times\frac{0.19}{\sqrt{10}}=\frac{0.38}{\sqrt{10}}=0.12 \end{gathered}[/tex]Then, the margin of error is 0.12Use the Square Root Property to solve the quadratic equation 36c2−144c+144=−35. If there are multiple answers, list them separated by a comma, e.g. 1,2. If there is no solution, enter ∅.
Answers
The square root property to solve the quadratic equation;
[tex]\begin{gathered} 36c^2-144c+144=-35 \\ 36c^2-144c+144+35=0 \\ 36c^2-144c+179=0 \end{gathered}[/tex]is given as;
[tex]\begin{gathered} c=\frac{-b\pm\sqrt[]{b^2-4ad}}{2a} \\ \\ \text{Where} \\ a=36 \\ b=-144 \\ d=179 \end{gathered}[/tex][tex]\begin{gathered} c=\frac{-(-144)\pm\sqrt[]{(144)^2-4(36)(179)}}{2(36)} \\ c=\frac{144\pm\sqrt[]{-5040}}{72} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{Since,} \\ \sqrt[]{b^2-4ad}<0 \\ \text{Then, th}ere\text{ is no real solution for c} \\ c=\phi \end{gathered}[/tex]Select from the drop-down menus to correctly complete the statement. The expressions 3.22 1 and 10 – 0.33 . 2 should be joined by
Answers
we have the expressions
3.2^2-1=10.24-1=9.24
10-0.33*2=10-0.66=9.34
therefore
should be joined by a not equal sign to form an inequality
so
9.24 < 9.34
9.24 is less than 9.34
I’ve completed the question.
Would you like me to elaborate on any point?