Answers
Answer:
[-16,16]U[20,+oo)
Step-by-step explanation:
1) x-16 ≥ 0
x ≥ 16
2) x-20 ≥ 0
x ≥ 20
3) x+16 ≥ 0
x ≥ -16
- 16. 16. 20
1) - - +. +
2) - - - +
3) - +. +. +
- +. - +
Solution : -16≤x≤ 16 ∨ x≥20
Related Questions
Graph the solution to the following system of inequalities.ys-2x-3y> 4x + 710-8-4-Х?10
Answers
Explanation
[tex]\begin{gathered} y\leq-2x-3 \\ y>4x+7 \end{gathered}[/tex]Step 1
First, graph the inequality 1
[tex]y\leq-2x-3[/tex]the related equation is
[tex]y=-2x-3[/tex]now, get 2 coordinates of the line
a) when x=1
[tex]\begin{gathered} y=-2x-3 \\ y=-2(1)-3 \\ y=-2-3 \\ y=-5 \\ so,\text{ the coordinate is (1,-5)} \end{gathered}[/tex]b)when x=0
[tex]\begin{gathered} y=-2x-3 \\ y=-2\cdot0-3 \\ y=0-3 \\ y=-3 \\ \text{coordinate P2}\Rightarrow(0,-3) \end{gathered}[/tex]now, draw a line that pases trought the coordinates we found.
Since the inequality is ≤ , not a strict one, the border line is solid
Step 2
Now, do the same for inequality 2
so
[tex]y>4x+7[/tex]the related equation is
[tex]y=4x+7[/tex]find 2 coordinates of the line
a)when x=0
[tex]\begin{gathered} y=4x+7 \\ y=4\cdot0+7 \\ y=0+7 \\ y=7 \\ so,\text{ the coordinate 3 is (0,7)} \end{gathered}[/tex]b) when x=-2
[tex]\begin{gathered} y=4x+7 \\ y=4\cdot-2+7 \\ y=-8+7 \\ y=-1 \\ so,\text{ the coordinate 4 is (-2},-1) \end{gathered}[/tex]now, draw the line 2, this lines passes trougth the coordiantes 3 and 4
Since the inequality is >, a strict one, the border line is dotted
Step 3
Graph:
in inequality (1) we need the values smaller r than -2x-3, it measn all values under the line,
and in Inequality 2 we need the values greater than 4x+7, it means all values over the line
so, the solution is the dark purple zone
I hope this helps you
what is 7/8 - 3 1/5? i cant firgure it out
Answers
Answer:
-93/40 or -2 13/40
Step-by-step explanation:
7/8 - 16/5
Adjust based on the LCM
35/40 - 128/40
35-128/40
What is an obtuse angle?A) Angle COAB) Angle BOAC) Angle DOBD) Angle DOA
Answers
An obtuse angle is an angle that measures more than 90° but not eauql or greater than 180°.
COA is the sum of COB and BOA, which is 90°, so COA is not obtuse.
BOA is 60°, so it is not obtuse.
DOA is a straight line, so it is 180°, so not obtuse.
DOB is COD plus COB. Since COA is 90°, DOC is also 90°, so DOC ples COB is 120°, which is between 90° and 180°, so DOB is obtuse and the correct alternative is C.
7/8 of a watermelon weight is water. if the watermelon weighs 24 kilograms, how many of the kilograms come from water?
Answers
ANSWER
21 kg of the watermelon are water.
EXPLANATION
We have to divide the weight of the watermelon by 8 and then multiply by 7 - or in other words, multiply by 7/8:
[tex]24\times\frac{7}{8}=\frac{24}{8}\times7=3\times7=21[/tex]21 of the 24 kilograms of the watermelon are from water.
is 0.5 a integer but not a whole number
Answers
...
Natural Numbers are the numbers 1 through infinity.
Whole numbers.
So, they start from 1 and go on...
1, 2, 3, 4, .....
Now, Whole numbers are very same just that they start from 0, so it would be:
0, 1, 2, 3, ....
Integers would include the negatives fo the naturals and 0, so they would be:
...-2, -1, 0 , 1, 2, ....
We want a number NOT natural but integer, that would be 0.
So,
Natural Numbers = 1, 2, 3, 4, 5, ....
Whole Numbers = 0, 1, 2, 3, 4, 5, .....
Integers = ...-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...
if H & J equals 7 and 10s equals 10 find LK
Answers
The trapezoid HJKL has T and S as midpoints of the legs
The length of TS can be calculated as the mean or average of the lengths of HJ and LK, i.e.:
[tex]TS=\frac{HJ+LK}{2}[/tex]We are given the lengths HJ=14, LK=42, thus:
[tex]TS=\frac{14+42}{2}=\frac{56}{2}=28[/tex]Now if we have HJ=7 and TS=10, we can find LK by solving the equation for LK
[tex]LK=2TS-HJ[/tex][tex]LK=2*10-7=20-7=13[/tex]The length of LK is 13
Given the standard restricted domains, which of the following relationships does not hold for x=-1? (Assume angles are in radians.)
Answers
Answer:
[tex]D:\text{ arccos\lparen cos\lparen-1\rparen\rparen= 1}[/tex]Explanation:
From the restricted domain, we want to check for the relationship that does not hold
All we have to do here is to substitute the value -1 for x, after which we evaluate each of the given equations
We proceed as follows:
[tex]\begin{gathered} a)\text{ sin\lparen}\sin^{-1}(-1))\text{ = -1} \\ b)\text{ arcsin\lparen sin\lparen-1\rparen\rparen = -1} \\ c)\text{ cos\lparen arc cos \lparen-1\rparen\rparen = -1} \\ d)\text{ arc cos\lparen cos\lparen-1\rparen\rparen = 1} \\ e)\text{ tan\lparen arc tan\lparen-1\rparen\rparen = -1} \\ f)\text{ arctan\lparen tan\lparen-1\rparen\rparen = -1} \end{gathered}[/tex]The correct option is thus D
y = x2 + 5x - 10y=-x² + 2x + 10
Answers
Since in both given equations, the variable y is already clear, then you can equal the two equations and then solve for x. So, you have
[tex]\begin{cases}y=x^2+5x-10\text{ (1)} \\ y=-x^{2}+2x+10\text{ (2)}\end{cases}[/tex][tex]\begin{gathered} x^2+5x-10=-x^2+2x+10 \\ \text{ Add }x^2\text{ to both sides of the equation} \\ \text{ Subtract 2x to both sides of the equation} \\ \text{ Subtract 10 to both sides of the equation} \\ x^2+5x-10+x^2-2x-10=-x^2+2x+10+x^2-2x-10 \\ 2x^2+3x-20=0 \end{gathered}[/tex]To solve for x you can use the quadratic formula, that is,
[tex]\begin{gathered} \text{ For }ax^2+bx+c=0\text{ where a}\ne0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]In this case
a=2
b=3
c=-20
So,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{(3)^2-4(2)(-20)}}{2\cdot2} \\ x=\frac{-3\pm\sqrt[]{9+160}}{4} \\ x=\frac{-3\pm\sqrt[]{169}}{4} \\ x=\frac{-3\pm13}{4} \\ x_1=\frac{-3+13}{4}=\frac{10}{4}=\frac{5}{2}=2.5 \\ x_2=\frac{-3-13}{4}=\frac{-16}{4}=-4 \end{gathered}[/tex]Now you can plug in the solutions found in any of the given equations to find their respective y-coordinates.
For the first solution, you have
[tex]\begin{gathered} x_1=\frac{5}{2} \\ y_{}=-x^2+2x+10\text{ (2)} \\ y_1=-(\frac{5}{2})^2+2(\frac{5}{2})+10 \\ y_1=-\frac{25}{4}+5+10 \\ y_1=\frac{35}{4} \\ y_1=8.75 \\ \text{ Then} \\ (2.5,8.75) \end{gathered}[/tex]For the second solution, you have
[tex]\begin{gathered} x_2=-4 \\ y=-x^2+2x+10\text{ (2)} \\ y_2=-(-4)^2+2(-4)+10 \\ y_2=-16-8+10 \\ y_2=-14 \\ \text{Then} \\ (-4,-14) \end{gathered}[/tex]Therefore, the solution set of the given system of equations is
[tex]\mleft\lbrace(-4,-14),(2.5,8.75)\mright\rbrace[/tex]Parallelogram ABCD is below. m
Answers
The consecutive angles of a parallelogram are supplementary. therefore:
[tex]\begin{gathered} m\angle A+m\angle B=180 \\ 41+x+8.5=180 \\ x+49.5=180 \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=180-49.5 \\ x=130.5 \\ x\approx131 \end{gathered}[/tex]As the number manu fucture increase from soo+200. manufactute (ost increase from 350 to 650 birr. Assume that the given data establishes relationship between Cost. cand number of units made. Q and asume that the the relation This is linear. Assuum the thice unit is birr 13.
Answers
y = 3x + 50 is the linear equation relating the total cost to the number of units produced.
We know that a linear equation is of the form
y = mx + b
Where m is the slope (rate of change of y with respect to x) and b is the value when x is 0.
With the given information, the cost increased by
$650 - $350 = $300
When the number of units produced increased by 200 - 100 = 100.
So the rate of change of cost (y) with respect to x (number of units) is 300/100=3.
So the equation is of the form
y = 3x + b
Use one of the two given data points to determine b.
When the production was 100, the total cost was $350:
So,
350 = 3(100) + b
350 = 300 + b
b = 50
Hence the answer is y = 3x + 50 is the linear equation relating the total cost to the number of units is produced.
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A car travels at a steady speed of 40 mph. How far will it go in 15 minutes?
Answers
The distance travelled by the car in 15 minutes can be determined as,
[tex]\begin{gathered} D=s\times t \\ D=40\text{ mph}\times15\text{ min}\times\frac{1\text{ h}}{60\text{ min}} \\ D=10\text{ miles} \end{gathered}[/tex]Thus, the required distance is 10 miles.
what is the reference angle for four radians rounded to two decimal places?
Answers
The reference angle can be calculated 4 radians is in the third quadrant, of the coordinate
reference angle=angle - 3.14
reference angle=4-3.14
the reference angle of 4 radians is 0.8584 rounded to two decimal places is 0.86 radians
Which situation can be represented by the equation y = 9x?Question 3 options:Michael drove x amount of hours in his car. This is 9 times the amount of miles as y.Michael drove x amount of miles in his car. He drove y amount of hours in 9 miles.Michael has y amount of miles to drive. This amount is 9 times x, the amount of miles to drive in hours.Michael has x amount of hours. This amount is 9 times y, the amount of miles to drive in hours.
Answers
Solution:
Given:
[tex]y=9x[/tex]This is a linear equation that relates distance, speed, and time.
where;
[tex]undefined[/tex]7. Solve this riddle. I am an even number. I am between 10 and 20. And when I am divided by 7, I have no remainder. What number am I?
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
solve the riddle = ?
Step 02:
We must analyze the exercise to find the solution
a. even number
b. 10 ----- 20
c. x / 7 ===> no remainder
11 , 13 , 15 , 17 , 19 ===> even numbers
Find the diameter of a circle with a circumference of 28.26 centimeters. Use 3.14 for π.
Answers
Answer:
The diameter of the circle is 9.0 cm.
[tex]d=9.0\text{ cm}[/tex]Explanation:
Given that the circumference of the circle is 28.26 centimeters.
[tex]C=28.26\text{ cm}[/tex]Recall that the formula for the circumference of a circle is;
[tex]\begin{gathered} C=2\pi r=\pi d \\ d=\frac{C}{\pi} \end{gathered}[/tex]Substituting the given values;
[tex]\begin{gathered} d=\frac{28.26\text{ cm}}{3.14} \\ d=9.0\text{ cm} \end{gathered}[/tex]Therefore, the diameter of the circle is 9.0 cm.
[tex]d=9.0\text{ cm}[/tex]The average amount of water used per person each day in a country is 45 gallons. How much water does the average person use in one year?
Answers
Proportions
It's assumed the amount of water consumed by one person is proportional to the time.
The contant of proportionality is given as 45 gal/day.
Since one normal year has 365 days, then we use the same proportion to calculate the water used in one year as follows:
Water used = 45 * 365 = 16,425 gallons.
The average person uses 16,425 gallons.of water in one year
Find and graph the intercepts of the following linear equation: x-4y=16
Answers
The given function is:
[tex]x-4y=16[/tex]The x-intercept is the value of x when y = 0.
[tex]\begin{gathered} x-4(0)=16 \\ x=16 \end{gathered}[/tex]The y-intercept is the value of y when x = 0.
[tex]\begin{gathered} (0)-4y=16 \\ -4y=16 \\ \text{ Dividing both sides of the equation by }-4 \\ y=-4 \end{gathered}[/tex].
Help meeee please!!!!
Answers
The coordinates of B' are (1, 0) after transforming the parallelogram down 4 units and right 3 units.
What are coordinates?Coordinates are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions or in space of three dimensions. These are the set of values that shows the exact position. Coordinates are the set of points, or numbers, that locates a point on a line, on a plane, or in space. The points at the coordinates are called coordinate points. The coordinate plane has two axes. Those are horizontal and vertical axes. The two axes intersect each other at a point called the origin. Coordinate axes are one of the fixed reference lines of a coordinate system. It is a two-dimensional number line. It is used to locate the position of any point.
From the graph, the coordinates of B are (-2, 4).
Translating 4 units down means the value of the y-axis is changing. Therefore, new coordinates will be
(-2-0, 4-4)
=(-2, 0)
Then the parallelogram is translated to 3 units to the right. So, the x-axis is changing to a positive end.
The coordinates of B' will be
(-2+3, 0+0)
= (1,0)
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ВС: Round your answer to the nearest hundredth. B 2 7
Answers
opposite to angle 65 = BC
adjacent to angle 65 = 7
[tex]\tan \text{ }\theta\text{ = }\frac{\text{opposite }}{\text{adjacent}}[/tex][tex]\tan \text{ 65 =}\frac{BC}{7}[/tex][tex]\begin{gathered} BC\text{ = 7 x tan 65} \\ =\text{ 7 x 2.1445} \\ BC\text{ = 15.0115} \\ BC\text{ }\approx\text{ 15.01 (nearest hundreth)} \end{gathered}[/tex]which is the better buy and provide the unit price for your answer! $5.28 for 6 candy bars or $12.75 for 15 candy bars?
Answers
Answer:
Explanation:
Given:
$5.28 for 6 candy bars
$12.75 for 15 candy bars
To determine the better buy, we simplify each option first:
For $5.28 for 6 candy bars:
5.28/6 = $0.88 per candy bar
For $12.75 for 15 candy bars:
12.75/15 = $0.85 per candy bar
Therefore,
2. The following is a graph of the function f(x) = 2^x. Graph thetransformation f(x+3) on the blank coordinate axis.yy
Answers
Explanation:
The transformation f(x+3) indicates that we have to translate the graph of f(x) 3 units to the left.
In the graph of f(x) the y-intercept is at y = 1. For f(x+3) this point is moved 3 units to the left, so it is (-3, 1).
Answer:
The graph of f(x+3) is
3. Which situation could be represented by the graph shown?3027242118A. Garrett buys limes for $0.80 each.B. Sophia buys 12-packs of soda for $1.75 each.C. Jacob buys packs of gum for $1.50 each.D. Allison purchases lemons for $0.75 each.15129631 2 3 4 5 6 7 8 9 10
Answers
Find the slope of the graph, use 2 points on the line (0,0) and (4,3)
[tex]m=\frac{3-0}{4-0}=\frac{3}{4}=0.75[/tex]The equation of the graph is y=0.75x, it represents the situation in option D. Allison purchases lemons for $0.75 each
Find the 55th term of the arithmetic sequence -7, -5, -3,
Answers
The given numbers are -7,-5,-3.
The common differen
Find the distance between vertices A and C of a regular hexagon whose sides are 20 cm each angle of the hexagon is 120 degrees
Answers
Use cosine law to find b:
[tex]b^2=a^2+b^2-2ac*cosB[/tex][tex]\begin{gathered} b^2=(20cm)^2+(20cm)^2-2(20cm)(20cm)*cos120º \\ b^2=400cm^2+400cm^2-800cm^2*(-0.5) \\ b^2=400cm^2+400cm^2+400cm^2 \\ b^2=1200cm^2 \\ b=\sqrt{1200cm^2} \\ b=20\sqrt{3}cm \\ b\approx34.64cm \end{gathered}[/tex]Then, the distance between A and C is 20√3 cm or approximately 34.64 cmGlven: Circle P with center at (-2, 3) and a radius of 23. Identify the equation that could represent circle P. (3 – 2) + (y - 3)2 = 23 (2+2) + (y + 3)' = 23 (2 – 2)2 + (y + 3) = 23 (2+2)² + (y – 3)2 =23
Answers
The correct option is:
[tex](x+2)^2+(y-3)^2=23[/tex]Because we need to remember that the equation for a circumference centered in (h,k) and with radius r is:
An arithmetic sequence has a 10th term of 15 and 14th term of 35. show that the equation (y=mx+b) of this graph equals an =-30+(n-1)5.
Answers
The arithmetic sequence follows
[tex]a_n=-30+(n-1)5[/tex]Lets see if the 10th term is 15 by replacing the n for 10
n=10
[tex]a_{10}=-30+(10-1)5[/tex][tex]a_{10}=-30+(9)5=-30+45=15[/tex]Now, Lets see if the 14th term is 35 by replacing the n for 14
n=14
[tex]a_{14}=-30+(14-1)5[/tex][tex]a_{14}=-30+(13)5=-30+65=35[/tex]Then so, the sequence follows the equation an =-30+(n-1)5.Use the intercepts to graph the equation. y = -6 x-intercept: Enter as a coordinate: such as (a, b). If there is no x-intercept, enter DNE. Enter as a coordinate: such as (a, b). If y-intercept: there is no y-intercept, enter DNE. 8 6 5 4 ربا
Answers
Answer:
x -intercept: DNE
y-intercept: (-6, 0)
Explanation:
The x-intercept is the point where the line intersects the x-axis.
The y-intercept is the point where the line intersects the y-axis.
Now when we draw the line y = -6, we get
We see that the red line does not intersects the x-axis at any point; thereffore, the x-intercept does not exist.
x -intercept: DNE
The red line intersects the y-axis at y = -6; therefore, the y-intercept is the point (0, -6)
TWO-Variable SystemsThe two lines graphed below are parallel. How many solutions are there to thesystem of equations?O A. TwoO B. ZeroO C. OneO D. Infinitely manyPREVIOUS
Answers
Answer:
B. Zero
Explanation:
The solutions of a system of equations are the points where the graphs intersect. If the lines are parallel, the lines will not intersect, so there will be no solutions to the system.
Therefore, the solutions to the system of two parallel lines are
B. Zero
If $163,300 is invested in an account earning 3.75% annual interest compounded semi-annually, how much interest is accrued in the first 4 years? Round to the nearest cent?
Answers
Solution:
An amount compounded is given as;
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{Where;} \\ P=\text{ amount invested;} \\ r=\text{ interest rate;} \\ n=\text{ number of times interest applied per time period;} \\ t=\text{ number of time period elapsed.} \end{gathered}[/tex]Given that;
[tex]\begin{gathered} P=163,300 \\ r=0.0375 \\ n=2 \\ t=4 \end{gathered}[/tex]Thus, we have;
[tex]\begin{gathered} A=163300(1+\frac{0.0375}{2})^{2\times4} \\ A=163300(1.01875)^8 \\ A=189464.20 \end{gathered}[/tex]Thus, the interest accrued in the first 4 years is;
[tex]\begin{gathered} I=A-P \\ I=189464.20-163300 \\ I=26164.20 \end{gathered}[/tex]FINAL ANSWER: $26,164.20
Use the formula P(B\A)=n(A and B)÷n(A) to find the probability P(kinglface card) when a single. card is drawn from a standard 52 card deck. P(king face card)=
Answers
In a deck of 52 cards, there 4 faces of Kings. These are the King of Hearts, King of Diamonds, King of Spades, and King of Clubs. Therefore, the chance of drawing a king face card in a deck of cards would be 4 out of 52 or 1 out of 13.
Answer: P(king face card) = 1/13