Forces are applied along various points on a lever arm as shown below.Calculate the net torqu and describe the direction of rotation from the axis of rotation that would result in a net moment(torque) of zero

Forces Are Applied Along Various Points On A Lever Arm As Shown Below.Calculate The Net Torqu And Describe

Answers

Answer 1

The net torque applied on the lever be 180 N-m.

The direction of torque is perpendicular to both force and axis of lever and it acts outwards.

So any force at any point on  axis of rotation for which torque is 180 N-m and directed in opposite direction would result in a net moment(torque) of zero.

What is torque?

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.

A vector quantity is a torque. The force acting on the axis determines the direction of the torque vector.

Mathematically, torque = force × perpendicular distance.

So, net torque applied on the lever :

= + (15N)×(20m) + (5N)×(15m) - (5N)×(5m) -(10N)×(17m)

= 180 N-m.

And the direction of torque is perpendicular to both force and axis and it acts outwards.

So any force at any point on  axis of rotation for which torque is 180 N-m and directed in opposite direction would result in a net moment(torque) of zero.

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Related Questions

A simple harmonic oscillator has a mass m=2.0 kg and a spring constant k=800 N/m.a) What is the frequency of oscillations?b) If the oscillator has a maximum speed of v=10.0 m/s, what is the maximum oscillation amplitude?c) What length would a simple pendulum need to be in order to oscillate at the same frequency?

Answers

a)

In order to calculate the frequency of oscillations of a simple harmonic oscillator, first let's calculate the period, using the formula:

[tex]\begin{gathered} T=2\pi\sqrt[]{\frac{m}{k}} \\ T=2\pi\sqrt[]{\frac{2}{800}} \\ T=2\pi\sqrt[]{\frac{1}{400}} \\ T=2\pi\cdot\frac{1}{20} \\ T=\frac{\pi}{10}=0.31416\text{ s} \end{gathered}[/tex]

Since the frequency is the inverse of the period, we have:

[tex]\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{\frac{\pi}{10}} \\ f=\frac{10}{\pi}=3.183\text{ Hz} \end{gathered}[/tex]

b)

In order to calculate the maximum oscillation amplitude given the maximum speed, let's use the formula below:

[tex]\begin{gathered} v_{\max }=X\sqrt[]{\frac{k}{m}} \\ 10=X\cdot\sqrt[]{\frac{800}{2}} \\ 10=X\cdot20 \\ X=\frac{10}{20}=0.5\text{ meters} \end{gathered}[/tex]

c)

The formula for the pendulum frequency is:

[tex]\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{2\pi\sqrt[]{\frac{L}{g}}} \\ f=\frac{\sqrt[]{\frac{g}{L}}}{2\pi} \end{gathered}[/tex]

Then, for f = 3.183 and g = 9.81, we have:

[tex]\begin{gathered} 3.183=\frac{\frac{\sqrt[]{9.81}}{\sqrt[]{L}}}{2\pi} \\ \frac{\sqrt[]{9.81}}{\sqrt[]{L}}=3.183\cdot2\pi \\ \frac{3.132}{\sqrt[]{L}}=20 \\ \sqrt[]{L}=\frac{3.132}{20} \\ \sqrt[]{L}=0.1566 \\ L=0.3957 \end{gathered}[/tex]

So the length is 0.3957 m or 39.57 cm.

What is the mass of an object that has 795J of moving kinetic energy and is moving at 3.5 m/s ?

Answers

Given data

*The given energy is k = 795 J

*The speed of the object is v = 3.5 m/s

The formula for the kinetic energy of the object is given as

[tex]k=\frac{1}{2}mv^2[/tex]

*Here m is the mass of the object

Substitute the known values in the above expression as

[tex]\begin{gathered} 795=\frac{1}{2}m(3.5)^2 \\ m=129.79\text{ kg} \end{gathered}[/tex]

Hence, the mass of the object is m = 129.79 kg

Particle Mass (amu)
proton 1.007593
neutron 1.008982
deuterium 2.014186
tritium 3.016448
helium 3 3.015779
helium 4 4.003873
1.0 ev = 1.6 · 10-19 j
1.0 amu = 931 Mev
1 angstrom () = 1 X 10-10m
h = 6.63 · 10-34 J-s.

Always use significant figure rules. Remember that these rules apply to all numbers that are measurements.
The mass of a deuterium nucleus 21H is less than its components masses. Calculate the binding energy.


Mev

Answers

The binding energy of  deuterium is  2.224 MeV.

Given parameters:

Mass of proton = 1.007593 amu.

Mass of neutron = 1.008982 amu.

Mass of deuterium =  2.014186 amu

We know that: deuterium atom is made up with one proton and one neutron.

So, mass of the components of the deuterium =  1.007593 amu + 1.008982 amu. = 2.016575 amu.

Hence, mass loss =   mass of the components of the deuterium - Mass of deuterium

= 2.016575 amu -  2.014186 amu.

= 0.002389 amu.

We know that, 1.0 amu = 931 Mev

So, binding energy = mass loss x  931 Mev

= 0.002389 x 931 Mev

= 2.224 MeV.

Hence, the binding energy of  deuterium is  2.224 MeV.

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20. There is a bell at the top of a tower that is 45 m high. The bell weighs 19 kg. The bell has
energy. Calculate it.

Answers

Explanation:

Find an energy is E =mgh, so E = 45*10*19=8550j

general questions: a small car and a large suv are at a stoplight. the car has a mass equal to half that of the suv, and the suv can produce a maximum accelerating force equal to twice that of the car. when the light turns green, both drivers push their accelerators to the floor at the same time. which vehicle pulls ahead of the other vehicle after a few seconds?

Answers

After a few seconds, no vehicle will pull ahead, it is a tie because the acceleration for the small car and the SUV are the same.

According to Newton's second law F = ma where m is the mass of the object, F is the force that works on the object, and a is the acceleration.

Mass of the SUV = m₂ = mMass of the small car = m₁ = half of the SUV = 0.5mAccelerating of the small car = F₁ = FAccelerating of the SUV = F₂ = 2F

The bigger acceleration of a car, it will make the car move further and faster. So we have to calculate the ratio of acceleration for both cars.

F₁ : F₂ = m₁ a₁ : m₂ a₂

F : 2F = 0,5m a₁ : m a₂

1 : 2 = 0,5 a₁ : a₂

2 × 0,5 a₁ = 1 × a₂
a₁ = a₂

The acceleration for the small car is the same as the acceleration for the SUV. It is a tie.

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ill give brainliest if you help me

Answers

G is the right answer.
Stay blessed

Fully explain step-by-step Questions number one a,b,c,d solve for all required

Answers

(1) The equation is

[tex]v_2=v_1+a\Delta t[/tex]

For v_1,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ Subtract\text{ a}\Delta t\text{ on both sides.} \\ v_2-a\Delta t=v_1+a\Delta t-a\Delta t \\ v_2-a\Delta t=v_1 \end{gathered}[/tex]

For a,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }\Delta t\text{ on both sides.} \\ \frac{v_2-v_1}{\Delta t}=a\frac{\Delta t}{\Delta t} \\ \frac{v_2-v_1}{\Delta t}=a \end{gathered}[/tex]

For time,

[tex]\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }a\text{ on both sides.} \\ \frac{v_2-v_1}{a}=\frac{a}{a}\Delta t \\ \frac{v_2-v_1}{a}=\Delta t \end{gathered}[/tex]

Energy is produced in the Sun’s...
A. corona
B. photosphere
C. chromosphere
D. core

Answers

The real correct answer is A

What is the length of our milky way? (astronomy)

Answers

Answer:

about 100,000 light years away

Explanation:

What is the milky way galaxy.

It's where our solar system is. Scientists gave it that name because it looks like someone spilled a glass of milk.

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The current theory of the structure of the
Earth, called plate tectonics, tells us that the
continents are in constant motion.
Assume that the North American continent
can be represented by a slab of rock 5500 km
on a side and 29 km deep and that the rock
has an average mass density of 2960 kg/m3
.
The continent is moving at the rate of about
5 cm/year.What is the mass of the continent?
Answer in units of kg.What is the kinetic energy of the continent?
Answer in units of J.A jogger (of mass 73 kg) has the same kinetic
energy as that of the continent.
What would his speed be?
Answer in units of m/s.

Answers

Based on the data provided:

The mass of the continent is 2.596 * 10²¹ kgThe kinetic energy of the continent is 6525 J

What is the mass of the rock?

The mass of the rock is determined using the formula below:

Mass = density * volume

The density of the rock = 2960 kg/m³

The volume of the rock = area of side * depth of rock

Volume of the rock = 5.5 * 10⁶ m x 5.5 * 10⁶ m x 2.9 * 10⁴ m

Volume of the rock = 8.77 * 10¹⁷ m³

Mass of the rock = 8.77 * 10¹⁷ m³ * 2960 kg/m³

Mass of the rock = 2.596 * 10²¹ kg

B) The kinetic energy is found using the formula below:

Kinetic Energy = ½mv²

Kinetic Energy  = ½ x 2.596 * 10²¹ kg x (5.0 cm/year x 1m/100cm x 1yr/365 day x 1day/24hr x 1hr/3600s)²

Kinetic Energy = 6525 J

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a meter stick has a mass of 0.172 kg and balances at its center. when a small chain is suspended from one end, the balance point moves 21.8 cm toward the end with the chain. determine the mass of the chain.

Answers

If the stick stays in the above-shown horizontal position at rest, m is 5 kg.

What is meant by mass?The amount of matter in a substance or an object is measured by its mass. The kilogram (kg) is the fundamental SI unit of mass, while lower masses can also be measured in grams (g). A balance is what you would use to measure mass. In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or position in response to the application of a force.

In the event that the torques around the suspension point are balanced, the stick will stay at rest in the horizontal position.

[tex]\tau_{\mathrm{CCW}} &=\tau_{\mathrm{CW}} \\[/tex]

[tex]r_1 F_1 &=r_2 F_2 \\[/tex]

[tex]r_1 m_1 g &=r_2 m_2 g \\[/tex]

[tex]m_2 &=\frac{r_1 m_1}{r_2}=\frac{(50 \mathrm{~cm})(3 \mathrm{~kg})}{30 \mathrm{~cm}}=5 \mathrm{~kg}[/tex]

It should be noted that finding m2 could also be done using the center of mass formula, but doing so would require algebra. The balance point can typically be located using the center of mass formula. It is typically simpler to apply torque if the balance point is known.

The complete question is:

A uniform meter stick of mass 1 kg is hanging from a thread attached at the stick’s midpoint. One block of mass m = 3 kg hangs from the left end of the stick, and another block, of unknown mass m, hangs below the 80 cm mark on the meter stick. If the stick remains at rest in the horizontal position shown above, what is m ?

A. 4 kg

B. 5 kg

C. 6 kg

D. 8 kg

E. 9 kg

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Rate of change of distance​

Answers

Answer:

Speed

Explanation:

Speed is called as rate of change of distance, speed is a scalar quantity.

A 55 kg ice skater is gliding along at 3. 5 m/s. Five seconds later her speed has dropped to 2. 8m/s.

Answers

If a 55 kg ice skater is gliding along at 3. 5 m / s has her speed has dropped to 2.8 m / s in 5 s, the force required is - 7.7 N

a = v - u / t

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time

u = 3.5 m / s

v = 2.8 m / s

t = 5 s

a = ( 2.8 - 3.5 ) / 5

a = - 0.7 / 5

a = - 0.14 m / s²

According to Newton's second law of motion,

F = m a

F = Force

m = Mass

a = Acceleration

m = 55 kg

F = 55 * - 0.14

F = - 7.7 N

The negative sign indicates that the force is applied on the opposite direction of motion

Therefore, the force required to drop the speed is - 7.7 N

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How does earthing provides safety to electrical appliances?​

Answers

Answer:

The act of immediately discharging electrical energy into the Earth directly with the aid of a low-resistance wire is known as earthing. Electrical earthing is accomplished by attaching the equipment's non-current-carrying component or the supply system's neutral section to the ground.

Four reasons why it's crucial to ground electrical equipment:

1. Increased longevity of appliances: Grounding electrical appliances results in less stress on the equipment and a reduction in the exposure of the appliances to hazardous currents.

2. Eradication of fire risk: If there is a problem with the insulation, there may be a spark, which could cause a fire and damage to property. The risk of fire is decreased by grounding electrical equipment by sending leakage current from insulation faults to the ground.

3. Protection from electrical surges: Electrical surges, whether brought on by lightning or for other reasons, produce dangerously high voltage. All the hazardous electricity will flow to the ground rather than causing harm to the electrical system if your appliances or electrical system as a whole is grounded.

4. Voltage Stabilization: Ideally, the ground's potential is zero. Therefore, all electrical devices use the earth as a point of reference. Calculating the required potential for each electrical appliance would be challenging without a reference point.

Electrocution is the term for when electricity enters the body. Burns, respiratory failure, neurological effects, and heart failure are all results of high-current electric shock. It might even result in death. Therefore, in the event of an insulation fault, a safe path for the current to flow must be provided via earthing.

Explanation:

The Earth serves as an efficient pathway for the flow of electrons that escape the insulation because it is a good conductor of electricity. Additionally, the Earth's enormous size creates a pathway for the safe discharge of electric charge. No current escapes from a device that is properly grounded. In the event that the device develops an internal problem, this stops people from being shocked or electrocuted. Electronic equipment is stabilized by earthing. It shields appliances from over-current or excessive voltage. Earthing is another fire safety measure. Overvoltage can cause a device to spontaneously combust due to overheating.

An electric space heater draws 25.0 A from a 200 V source. It is operated, on the average, for 10.0 h each day.At AED 0.30 per kWh, how much does it cost to operate the heater for 15 days?

Answers

The cost of energy consumption to operate the heater for 15 days is $2.25

Voltage (V) = 200 V

Current (I) = 25 A

Power (P) = VI = 200 * 25 = 5,000 W

Now, the calculation of the energy consumption for 15 days in KW/h

We will convert W to kW,

1000 W = 1kW

Therefore,

5,000 W = 5000 W × 1 KW / 1000 W = 5kW

The daily energy consumption will be calculated. This is attainable as follows,

P = 5kW

Time(t) = 10 h

Energy (E) = P/t = 5/10 = 0.5 kW/h per day.

Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:

1 day = 0.5 kW

Cost of one day = 0.5 * 0.30 = $ 0.15

Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25

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what is the name of the side of angle x

Answers

It doesn’t say x anywere

Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixtures has entries has no set composition, must have more than one state of matter, must have more than one substance. What mistake did Dominic make? The title should read “Properties of Solutions” because some mixtures do not have all of the properties listed. There is a definite recipe to make each mixture, so the composition of a mixture is set. Although it is possible to have more than one state, it is also possible to have only one state. A single substance can be used to make a mixture if the substance is composed of more than one element. Mark this and return

Answers

The mistake that Dominic made is that C. Although it is possible to have more than one state, it is also possible to have only one state

What exactly is a mixture?

A mixture in chemistry is a material composed of two or more simpler components that are not chemically linked.

Individual substances retain their properties in a mixture, but their properties may change if they form a compound; when mixed, individual substances retain their properties in a mixture, but their properties may change if they form a compound.

When matter is mixed, such as with clouds, it can take on characteristics from various states. As a result, while it is possible to have more than one state, it is also possible to have only one state.

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a certain planet has equatorial radius about 0.463 times that of the earth, and mass only 0.110 times that of the earth. calculate the free-fall acceleration due to gravity on this planet in units of gg (earth's gravitational acceleration).

Answers

Using the theories of gravitation, we got that  3.42×[tex]10^{11}[/tex]m/sec²  is the free-fall acceleration due to gravity on a a certain planet has equatorial radius about 0.463 times that of the earth, and mass only 0.110 times that of the earth.

We know that acceleration due to gravity on the planet is given by

=Gm/r²

where G is the earth's gravitational constant, m is the mass of the planet and r is the radius of the planet

We are given that mass of the planet is 0.110 times that of the earth.

and radius of the planet is 0.463 times that of the earth.

We know that value of G is 6.67×[tex]10^{11}[/tex].

So putting the values, we get

Acceleration of planet=[6.67×[tex]10^{11}[/tex]×0.110 Mass of the earth]/(0.463)² radius of the earth

=>Acceleration of planet=[(6.67×0.110)×    [tex]10^{11}[/tex]]/(0.463×0.463)

=>Acceleration of planet = (0.7337/0.2143)×[tex]10^{11}[/tex]

=>Acceleration of planet =3.42×[tex]10^{11}[/tex]m/sec²

Hence, for a certain planet has equatorial radius about 0.463 times that of the earth, and mass only 0.110 times that of the earth, the free-fall acceleration due to gravity on this planet is 3.42×[tex]10^{11}[/tex]m/sec².

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what is the ratio of the gravitational force that earth exerts on the sun in the winter and the force that it exerts in the summer?

Answers

1:1  is the ratio of the gravitational force that earth exerts on the sun in the winter and the force that it exerts in the summer because it is independent of temperature.

F=GMm/R²

Any action that aims to maintain, alter, or deform a body's motion is considered a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).

According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight path in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changes velocity) in the direction of the force.

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How much energy is stored in a spring with a spring constant of 150 N/m when it is compressed 2 cm?

Answers

The energy stored in a spring is elastic potential energy. The formula for calculating the elastic potential energy is expressed as

elastic potential energy = 1/2kx^2

where

k represents spring constant

x represents the distance through which the spring was compressed

From the information given,

k = 150 N/m

x = 2cm

we would convert 2cm to m

recall, 100cm = 1 m

2 cm = 2/100 = 0.02 m

By substituting these values into the formula,

elastic potential energy = 1/2 x 150 x 0.02^2

elastic potential energy = 0.03 J

A car tyre has a constant volume. Why does the pressure of the air in the tyre increase when its
temperature increases?

A) The air molecules hit each other less often.
B) The air molecules hit the inside of the tyre less often.

C) The average speed of the air molecules in the tyre is greater.

D) There are more air molecules in the tyre

Answers

Answer:

C) The average speed of the air molecules in the tyre is greater.

Explanation:

As temperature increases the speed of the molecule increases too.

A rocket moving upward at 2.50 km/s
discards its first stage and continues to
accelerate upward at 40.0 m/s² for
another 120 s. How much altitude does it
gain during this time (km)?
[?] km

Answers

The altitude gained by the rocket is 588km

If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.

We know that the second equation of motion is

h = ut + 1/2 at²

Initial speed, u = 2.50km/s

acceleration, a = 40m/s² = 0.04km/s²   [1m = 0.001km]

time, t = 120s

Altitude gain during this time, h

h = ut + 1/2 at²

h = 2.50 * 120 + 1/2 * 0.04 * 120²

h = 588km

Hence, the altitude gained by the rocket is 588km

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A platinum resistance thermometer has a resistance of 10.40 ohms at00 C and 14.35 ohms at 100 C. Assuming that the resistance changesuniformly with temperature, what is(a) The temperature when the resistance is 11.19 ohms?(b) The resistance of the thermometer when the temperature is 45 C?

Answers

(a) 0.05 ° C

(b) 12.17 ohms

Explanation

Assuming that the resistance changes uniformly with temperature we can set the equation of the line

so

Step 1

find the equation of the line:

the equation of a line has the form:

[tex]\begin{gathered} y=mx+b \\ where\text{ m is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]

to do that, we need 2 points from the line, so let

x represents the temperature

y represents resistance

[tex]\begin{gathered} P1(0,10.40) \\ P2(100,14.35) \end{gathered}[/tex]

now, to find the slope of a line we need to use the expression

[tex]\begin{gathered} slope=\frac{y_2-y_1}{x_2-x_1} \\ where \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]

then, replace the values in the formula

[tex]slope=\frac{14.35-10.4}{100-0}=\frac{3.95}{100}=0.0395[/tex]

so, the slope is 0.0395

b) now, use the slope point formula to find the equation of the line

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ where\text{ m is the slope and P1\lparen x}_1,y_1) \\ replace \\ y-10.4=0.0395(x-0) \\ y=0.0395x+10.4 \end{gathered}[/tex]

so, the equation of the lines is

y=0.0395x+10.4

Step 2

Now, we can use the equation to find the asked values

(a) The temperature when the resistance is 11.19 ohms?

let

[tex]\begin{gathered} resistance\text{ = 11.19,so y=11.19} \\ replace\text{ in the equation and solve for x} \\ y=0.0395x+10.4 \\ 11.19=0.0395x+10.4 \\ 11.19-10.4=0.0395x \\ 0.79=0.0395x \\ x=\frac{0.0395}{0.79}=0.05 \end{gathered}[/tex]

therefore

(a) 0.05 ° C

Step 3

(b) The resistance of the thermometer when the temperature is 45 C?

let

[tex]tempereature\text{ = x= 45 C}[/tex]

now, replace in the expression to find the resistance

[tex]\begin{gathered} y=0.0395x+10.4 \\ y=0.0395(45)+10.4 \\ y=12.17 \end{gathered}[/tex]

therefore,

(b) 12.17 ohms

I hope this helps you

A current of 11.37 A passes through a wire. How many electrons pass through the wire in 18.19 seconds ?

Answers

[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]

Explanation

An Ampere is in the SI base unit of electric current equal to one coulomb per second.

[tex]\text{ 1 Ampere=}\frac{1\text{ C}}{s}[/tex]

and remember that the charge of an electron is

[tex]Q_e=-1.6*10^{-19\text{ }}C[/tex]

Step 1

a) let

[tex]\begin{gathered} I=11.37\text{ Amperes} \\ I=11.37\text{ A}*(\frac{\frac{1C}{s}}{A})=11.37\frac{C}{s} \\ also \\ time\text{ =}18.9\text{ s} \end{gathered}[/tex]

so

[tex]\begin{gathered} I=\frac{Q}{time} \\ replace \\ 11.37A=\frac{Q}{18.19} \\ multiply\text{ both sides by 18.19} \\ 11.37A*18.19=\frac{Q}{18.19}*18.19 \\ 206.8206\text{ C}=Q \end{gathered}[/tex]

b) now , to find the number o f electrons , divide the total a}charge by the charge of an electron

[tex]Number\text{ of electrons=}\frac{206.8206C}{\lvert{-1.6*10^{-19\text{ }}C}\rvert}=1.29*10^{21}\text{ electrons}[/tex]

therefore, the answer is

[tex]\begin{equation*} =1.29*10^{21}\text{ electrons} \end{equation*}[/tex]

I hope this helps you

A 0.400kg ball is dropped from a height of 3.00m onto a spring with a spring constant of 600.N/m. How much does the spring compress if the ball comes to a stop.0.313m0.098m0.0392m0.198m

Answers

Given data

*The given mass of the ball is m = 0.400 kg

*The given height is h = 3.00 m

*The given spring constant is k = 600.0 N/m

*The value for the acceleration due to the gravity is

[tex]g=9.8\text{ m/s\textasciicircum{}2}[/tex]

The expression for the spring compresses at a distance is given by the conservation of energy as

[tex]\begin{gathered} U_s=U_p \\ \text{mgh}=\frac{1}{2}kx^2 \\ x=\sqrt[]{\frac{2mgh}{k}} \end{gathered}[/tex]

Substitute the values in the above expression as

[tex]\begin{gathered} x=\sqrt[]{\frac{2\times0.400\times9.8\times3.00}{600.0}} \\ =0.198\text{ m} \end{gathered}[/tex]

a constant force is applied to a body that is already moving. the force is directed at an angle of 60 degrees to the direction of the body's velocity. what is most likely to happen is that group of answer choices

Answers

the body will gradually change direction more and more toward that of the force while speeding up.

In physics, pressure is a power that may trade the movement of an object. A pressure can purpose an object with mass to exchange its speed (e.g. transferring from a country of relaxation), i.e., to boost up. pressure also can be defined intuitively as a push or a pull. A force has each importance and direction, making it a vector quantity. Its miles are measured within the SI unit of newton (N). force is represented via the symbol F (formerly P).

The authentic shape of Newton's second law states that the internet pressure acting upon an object is the same as the fee at which its momentum changes with time. If the mass of the item is steady, this regulation implies that the acceleration of an item is immediately proportional to the internet pressure acting at the item, is in the route of the net force, and is inversely proportional to the mass of the object.

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Show that average speed of a rabbit that runs 30m in 2s is 15m/s

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The rabbit's average speed is 15m/s because the formula for calculating average speed is Distance divided by time.

What is the average speed?

The average speed of an object can be defined as the total distance traveled by it in a particular interval of time. this can be determined by dividing the total distance moved by the object by the time taken to move.

It is the ratio of the distance the rabbit travels in m and the time taken by the object to travel in seconds.

Hence: Distance D=30m

                Time,  T=2s

Average Speed S=ΔD/ΔT                            

                      S=30m/2s                            

                      S=15m/s

Therefore rabbit's Average speed is 15m/s

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an elevator that weighs 3.0 * 10^3 n is accelerated upward at 1.0 m/s^2. what force does the cable exert to give it this acceleration?

Answers

The answer is 3306 12M.

Solution:

By Newton Law of muts a:

T- mg = ma

T = ma + mg

T = m (a + g)

= T = 306·12 (1 + 9.8)

=) T = 3306.12 N.

Hence The force act 3306 12M.

This is the application of Newton's second law to the forces you feel in an elevator. It feels heavy when you accelerate and feels light when you accelerate. When the elevator rope breaks, you and the elevator accelerate at the same speed, so you're in weightlessness.

The elevator speeds up or slows down. In any case, the direction of acceleration is upward. The weight acts downward on a person. An upward vertical force acts on a person, and the magnitude of the vertical force is equal to the weight. The net force is due to the small vertical force the elevator exerts on the person. This force, according to Newton's third law is the same as the downward force on the elevator.

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A ball is thrown vertically upward. As it rises, what happens to its kinetic energy?.

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The kinetic energy and potential energy of an object continue to decrease when thrown vertically upward.The ball retains the same total energy.The ball will only have potential energy when it reaches its highest point, when its velocity is zero and it has no kinetic energy.

What happens to a ball's kinetic energy when it is thrown vertically up?

Zero kinetic energy is produced. The transformation of kinetic energy into potential energy occurs in accordance with the law of conservation of energy. At this height, potential energy is at its highest.

Is there an increase in kinetic energy when a ball is thrown up?

We transfer potential energy to the ball when we throw it in the upward direction, allowing it to gain kinetic energy and allow it to rise to a certain height. However, the ball's kinetic energy decreases as it continues to rise in height, eventually reaching zero.

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How do wings help a plane to fly?

Answers

ANSWER

EXPLANATION

We want to find out how wings help a plane to fly.

The wings of an airplane are there to help lift the plane. They are shaped to make air move faster over the wings.

They are used for lifting, landing, turning and controlling the airplane. The curve on the wings make the air move faster than the air at the bottom of the wings which appropriates Bernoulli's principle to push the plane into the air.

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