For the interval expressed in the number line, write it using set-builder notation and interval notation.
Answers
Answer:
Writing the number line in set builder notation we have;
[tex]\mleft\lbrace x\mright|x>0\}[/tex]Writing in interval notation.
[tex]x=(0,\infty)[/tex]Explanation:
Given the number line in the attached image.
x starts on 0, with a non shaded circle and pointed to the right/positive direction.
So;
[tex]x>0[/tex]Writing the number line in set builder notation we have;
[tex]\mleft\lbrace x\mright|x>0\}[/tex]Writing in interval notation.
[tex]x=(0,\infty)[/tex]Since the upper boundary of x is not stated then we will represent it with infinity in the interval notation.
[tex]\begin{gathered} (\text{ }\rightarrow\text{ greater than} \\ \lbrack\text{ }\rightarrow\text{ greater than or equal to } \\ so,\text{ } \\ 0Related Questions
r-9<-25. on a graph bar
Answers
r-9<-25 is equal to solution: [tex]$\quad R < -16$[/tex], Interval Notation: [tex]$\quad(-\infty,-16)$[/tex]. The graph is shown in attachement.
R-9<-25
Add 9 to both sides
R-9+9<-25+9
Simplify
R<-16
A graph is simply an orderly representation of data. It aids us in comprehending the info. The numerical information gathered through observation is referred to as data.
Data is derived from the Latin term Datum, which meaning "anything supplied."
Data is collected continuously through observation when a research question is formulated. It is then organized, summarized, categorised, and graphically shown.
To learn more about graph visit:https://brainly.com/question/17267403
#SPJ9
») A box has a length of 6 centimeters, a width of 4 centimeters, and a height of 5 centimeters. Jen filled the bottom layer of the box with 24 cubes. What is the volume of the box? 120 cubic centimeters 24 cubic centimeters 5 cm 4 cm 96 cubic centimeters 6 cm = 1 cubic centimeter 144 cubic centimeters
Answers
We can find the volume of the box by multiplying the length, width and heigth.
We can write this as:
[tex]V=l\cdot w\cdot h=(6\operatorname{cm})\cdot(4\operatorname{cm})\cdot(5\operatorname{cm})=(24\operatorname{cm})(5\operatorname{cm})=120\operatorname{cm}^3[/tex]The base layer is 24 cm^3 (24 cubes of 1 cm^3) because its the volume of width 4 cm and length 6 cm, with a height of 1 cm (the height of the cube).
If we multiply the number of cubes, 24 of 1 cm^3, by the real height, that is 5 times 1 cm, we get: 24 cm^3 * 5 = 120 cm^3.
Answer: the box has a volume of 120 cm^3
determine the degree of the polynomial -56a^2y^3+23a^2y-29a+17
Answers
The degree a polynomial is determine by the highest highest power of variable in the equation.
However, for a multivariable polynomial, the degree is the highest sum of powers of different variables in any of the terms in the expression.
For this polynomial,
[tex]-56a^2y^3+23a^2y\text{ - 29a + 17}[/tex]The degree of polynomial is 5 at the term -56^2y^3 which has 2 and 3 exponent at variable a and y respectively.
Yael used to have a square garage with 222 ft2 of floor space. She recently built an addition to it. The garage is still a square, but now it has 50% more floor space. What was the length of one side of the garage originally? What is the length of one side of the garage now
Answers
• The length of one side of the garage originally is approximately 14.9 ft
,• The length of one side of the garage now is approximately 18.3 ft
Explanation:Old garage = 222 sq. ft
New garage has 50% more floor space.
50% of 222 = 111
Therefore, the new garage is (222 + 111) sq. ft = 333 sq. ft
Since the garage is square,
one side of the old garage is:
[tex]\sqrt[]{222}=14.9\text{ ft}[/tex]One side of the new garage is:
[tex]\sqrt[]{333}=18.3\text{ ft}[/tex]For the following set of data, find the percentage of data within population standarddeviations of the mean, to the nearest percent.88, 92, 57, 62, 57, 56, 58, 57Copy Values for CalculatorOpen Statistics Calculator
Answers
Answer: 100 %
Explanation:
The first step is to rearrange the numbes in ascending order. It becomes
56, 57, 57, 57, 58, 62, 88, 92
The next step is to calculate the population μ, mean.
μ = sum of terms/number of terms
From the information given
n = number of terms = 8
μ = (56 + 57 + 57 + 57 + 58 + 62 + 88 + 92)/8 = 65.875
μ = 65.875
The formula for calculating the population standard deviation, σ is
σ = √[Σ(x - μ)^2]/n
Σ(x - μ)^2/n = [(56 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (57 - 65.875)^2 + (58 - 65.875)^2 + (62 - 65.875)^2 + (88 - 65.875)^2 + (92 - 65.875)^2)]/8 = 197.859375
σ = √197.859375
σ = 14.1
2 population standard deviations to the left of the mean = 65.875 - 2(14.1) = 37.675
2 population standard deviations to the rig tof the mean = 685875 -+2(14.1) == 94.075
Number of terms between 37.675 and 94.075 = 8
Thus,
the percentage of data within 2 population standard deviations of the mean
= 8/8 x 100 = 100%
A parabola has a vertex at (2, -1) and a y- intercept at (0,3). Is this enough information to sketch a graph? Explain your answer. Henny Yoffe . 11:20 AM
Answers
It is given that the parabola has the vertex at (2,-1)and y intercept of 3,
Consider the general equation of the parabola with vertex (p,q),
[tex]y=a(x-p)^2+q[/tex]Sbstitute 2 for 'p' and -1 for 'q',
[tex]y=a(x-2)^2-1[/tex]Given that the y-intercept is 3, it means that the curve passess through (0,3),
So it must satisfy the equation,
[tex]3=a(0-2)^2-1\Rightarrow4a=4\Rightarrow a=1[/tex]Substitute the value of 'a', 'p', and 'q' in the standard equation,
[tex]y=1(x-2)^2-1\Rightarrow y=(x-2)^2-1[/tex]Thus, the equation of the parabola can be obtained using the given conditions.
Determine whether each sequence is arithmetic. If so, identify the common difference. -34, -28, -22, -16
Answers
Answer:
Question:
Determine whether each sequence is arithmetic. If so, identify the common difference. -34, -28, -22, -16
The numbers are given below as
[tex]-34,-28,-22,-16[/tex]Concept:
Define an arithmetic sequence
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
The general form of an arithmetic sequence is given below as
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ a_1=first\text{ }term \\ n=number\text{ of terms} \\ d=common\text{ difference} \end{gathered}[/tex]To check if they have a common difference, we will use the formulas below
[tex]\begin{gathered} d=a_2-a_1=-28-(-34)=-28+34=6 \\ d=a_3-a_2=-22-(-28)=-22+28=6 \\ d=a_4-a_3=-16-(-22)=-16+22=6 \end{gathered}[/tex]Hence,
Since the sequence has a common difference,
It is therefore an ARITHMETIC SEQUENCE
Their common difference is
[tex]\Rightarrow6[/tex]1. An input-output table has constant differences. When the input is 3, the output is 10. When the input is 7, the output is 24. a. Find the constant difference. b. Find the output when the input is 0. C. Find the linear function that fits the table.
Answers
a)7,17
b)-25
c)
[tex]y=3.5x-25[/tex]Explanation
table
a) differences
10-3=7
24-7=17
Step 1
find the slope
[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]Let
P1(3,10)
p2(7,24)
replace,
[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{24-10}{7-3}=\frac{14}{4}=\frac{7}{2} \\ \text{slope}=\frac{7}{2} \end{gathered}[/tex]Step 2
find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-10=\frac{7}{2}(x-10) \\ y-10=\frac{7}{2}x-\frac{70}{2} \\ y=\frac{7}{2}x-\frac{70}{2}+10 \\ y=3.5x-25 \end{gathered}[/tex]Step 3
when x=0
[tex]\begin{gathered} y=3.5x-25 \\ y=3.5\cdot0-25 \\ y=-25 \end{gathered}[/tex]I hope this helps you
Sailor SheftalSimilar Figures / Proportion (Level 1)Aug 02, 10:17:02 AM?Triangle EFG is similar to triangle HIJ. Find the measure of side HI. Round youranswer to the nearest tenth if necessary.G94425Submit AnswerAnswer:attempt 1 out of 2
Answers
If we have two similar triangles, that ratio of the corresponding sides are all the same. This means that:
[tex]\frac{GF}{JI}=\frac{EF}{HI}[/tex]Substituting the lengths, we get:
[tex]\begin{gathered} \frac{44}{9}=\frac{25}{HI} \\ HI=25\cdot\frac{9}{44}=5.1136\ldots\approx5.1 \end{gathered}[/tex]Solve the following problems.a. After 6 points have been added to every score ina sample, the mean is found to be M=70 and thestandard deviation is s= 13. What were the valuesfor the mean and standard deviation for the originalsample?b. After every score in a sample is multiplied by 3, themean is found to be M=48 and the standard devia-tion is s=18. What were the values for the meanand standard deviation for the original sample?
Answers
Original mean = 64
standand deviation = 13
Explanations:Let the value of of the originalmean be X. If after 6 points have been added to every score in a sample, the mean is found to be M = 70, then;
X + 6 = 70
Subtract 6 from both sides
X + 6 - 6 = 70 - 6
X = 70 - 6
X = 64
Hence the mean of the original sample will be 64.
The standard deviation of the data will remain unchanged since the distance from the mean will remain the same no matter the change in mean. Therefore the standard deviation of the sample will be 13.
Find each probability of the events and place them in order
Answers
Considering Box A,
Total number of pens = 3 + 5 = 8 pens
Probability of picking a purple (P) and black (B) pen is given below as,
[tex]\begin{gathered} P(P)=\frac{3}{8} \\ P(B)=\frac{5}{8} \end{gathered}[/tex]Considering Box B,
Total number of pens = 15 + 5 = 20 pens
Probability of picking a purple and black pen is given below as,
[tex]\begin{gathered} P(P)=\frac{15}{20} \\ P(B)=\frac{5}{20} \end{gathered}[/tex]For event 1, probability of choosing a red (R) pen from Box B is zero because there is no red pen in the Box.
Event 1 P(R) = 0
For event 2, probability of choosing a purple or black pen from Box A is,
[tex]P(P\text{ or B)=}\frac{3}{8}+\frac{5}{8}=\frac{3+5}{8}=\frac{8}{8}=1[/tex]Event 2 P(P or B) = 1
For event 3, probability of choosing a purple pen from Box A is,
[tex]P(P)=\frac{3}{8}[/tex]Event 3 (P) = 3/8
For event 4, probability of choosing a black pen from Box B is given below as,
[tex]P(B)=\frac{5}{20}=\frac{1}{4}[/tex]Event 4 P(B) = 1/4
Arranging each events from the least likely to the most likely is in the order below
[tex]\text{Event 1, Event 4, Event 3, Event 2}[/tex]Answer deduced above.
In a music class of 20 students, there are 12 who play the Guitar (G), 7 who play the piano (P) and 4 who do not play any of his instruments.A) Represent the situation using a Venn diagram.B) What is the probability that a randomly selected student will play guitar and piano?C) What is the probability that a randomly selected student will play one of these two instruments?D) What is the probability that a randomly selected student will not play the piano?
Answers
n(U) = 20
n(G) = 12
n(P) = 7
[tex]\text{ n(G u P)}^1=4[/tex]Let x represent students that play both instruments
n(PuG) = x
A. Venn diagram
B. What is the probability that a randomly selected student will play guitar and piano?
Firstly solve for x
12-x + x + 7-x + 4 = 20
23-x = 20
-x = 20 - 23
-x = -3
x = 3
Number of students that play guitar and piano = x = 3
Total students = 20
Probability that a randomly selected student will play guitar and piano = 3/20
C. What is the probability that a randomly selected student will play one of these two instruments?
[tex]\begin{gathered} \text{ = }\frac{12-x}{20}\text{ +}\frac{7-x}{20} \\ =\frac{12-3}{20}+\frac{7-3}{20} \\ =\frac{9}{20}+\frac{4}{20} \\ =\frac{13}{20} \end{gathered}[/tex]D. What is the probability that a randomly selected student will not play the piano?
Students who do not play piano are students that play guitar only and students who do not play any instrument
students that play guitar only = 12 -x = 12 -3 = 9 students
students who do not play any instrument = 4
Probability that a randomly selected student will not play the piano =
[tex]\frac{9}{20}+\frac{4}{20}\text{ = }\frac{13}{20}[/tex]
what is 7^3? Describe the strategy you used and explain why you used that approach
Answers
Given expression is
[tex]7^3[/tex]We can expand the given expression as follows.
[tex]7^3=7\times7\times7[/tex]Multiplying 7 and 7, we get
[tex]=49\times7[/tex]Multiplying 49 and 7, we get
[tex]=343[/tex]Hence 7^3 is 343.
We multiply the number twice by itself to find the cube of 7.
This strategy is easy and basic to find the cube of the number.
If.A = (e, x, a, m) and U = {a, b, c, d, e, f, g, h, I, J. K, 1. m. n. o. p. q. r, S, t. u, v. w.x.y.z} find A.
Answers
Given that the set A contains the letters e, x, a and m, the complement A' will be the set that does not include these letters, thus, A' can be written as:
[tex]A^{\prime}=\mleft\lbrace b,c,d,f,g,h,i,j,k,l,n,o,p,q,r,s,t,u,v,w,y,z\mright\rbrace[/tex]Please help me I don’t know how to do this
Answers
Translations
One point located at (x,y), translated to the point (h,k) has been applied the rule:
T(x,y) -> (h,k)
And the translation changed the coordinates by ( h-x, k-y).
The point (4,-9) is mapped to (9,-14). The change is:
(9 - 4, -14 - (-9 ) = (5 , -5)
The rule of translation is:
T(x,y) -> (x + 5 , y -5)
If we translated the point (-9,-8) under the same rule:
T(-9,-8) -> (-9 + 5 , -8 -5)
T(-9,-8) -> ( -4 , -13)
The image of the point (-9,-8) is ( -4 , -13)
15. WORK REQUIRED: Given : ZA = 2D and BA – ED. What congruent sides would allow us to use SAS to prove Triangle ABC is congruent to Triangle DEF? (write your answer in this form: WX=YZ with no spaces) NN TA Your answer This is a regulired question
Answers
Let's begin by listing out the information given to us:
Both triangles have Line BD equal
[tex]BD=BD[/tex]Line AB equals Line CD
[tex]AB=CD[/tex]Angle A equals Angle C
[tex]m\angle A=m\angle C[/tex]Hence, Triangle ABD is congruent to Triangle CDB
Find the vbalie If K, and then write an equation to describee the direct variation.
Answers
Given:
x = 9 and y = 6
Use the equation:
y = kx
Where y varies directly as x
K is the constant of proportionality.
Let's find the value of k:
[tex]\begin{gathered} y\text{ = kx} \\ \\ 6\text{ = 9k} \\ \\ \text{Divide both sides by 9:} \\ \frac{6}{9}=\frac{9k}{9} \\ \\ \frac{2}{3}=k \end{gathered}[/tex]k = ⅔
An equation to describe the direct variation is:
[tex]y\text{ = }\frac{2}{3}x[/tex]ANSWER:
[tex]undefined[/tex]Which of the following expressions is equivalent to the one shown below?71377OA. 791OB. 720O C. 76O D. 75
Answers
Given
[tex]\frac{7^{13}}{7^7}[/tex]Find
Equivalent expression
Explanation
Here , we use laws of exponents
[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]so ,
[tex]\begin{gathered} =\frac{7^{13}}{7^7} \\ \\ =7^{13-7} \\ \\ =7^6 \end{gathered}[/tex]Final Answer
Therefore , the correct option is C
1.) twenty-five and five hundred seventy-eight thousandths
2.) Six thousand one and one hundreadths
Answers
Answer:
Here are the numbers:
1) 25.578
2) 6,001.01
please finish this super fastWhat is the median travel time, in minutes? 21 24 29 36
Answers
Given:
Required:
We need to find the median.
Explanation:
Recall that the vertical line that split the box in two is the median.
The vertical line that split the box in two is the median at 24 minutes.
The median is 24.
Final answer:
The median is 24.
The length of two sides of a triangle are 5 inches and 8 inches. Which of the following lengths could be the length of the third side of the triangle?
Answers
there are 2 possible triangles that can arranged one being the 8 the longest side, and another one being the 5 and 8 the sides of the triangle
use the pythagorean theorem to solve.
for the black triangle.
[tex]\begin{gathered} a^2+b^2=c^2 \\ (8^2+5^2)=c^2 \\ (89)=c^2 \\ \sqrt[]{89}=c \\ c=9.43 \end{gathered}[/tex]for the green triangle.
[tex]\begin{gathered} a^2+b^2=c^2 \\ 5^2+b^2=8^2 \\ b^2=(8^2-5^2) \\ b^2=39 \\ b=\sqrt[]{39} \\ b=6.25 \end{gathered}[/tex]SIMPLIFIED Uplift Summer Algebra 1 Final Assessment - Copy12 of 2012 of 20 ItemsQuestionColton solves -30=6(x-1) by dividing both sides by 6 first. Kaylee solves the same equation by using the Distributive Property first on the right side of the equation. Who is correct?
Answers
The method use by both students are correct. Hence the right answer to the question is OPTION D
please answer quickly I'm just trying to confirm my answer
Answers
Given the following vector:
[tex]v=<-\sqrt{3},2\sqrt{3}>[/tex]The magnitude of the vector will be as follows:
[tex]||v||=\sqrt{(-\sqrt{3})^2+(2\sqrt{3})^2}=\sqrt{3+12}=\sqrt{15}[/tex]So, the answer will be option 2) ||v|| = √15
Assume that (a,b) is a point on the graph of f. What is the corresponding point on the graph of the following function?f(x-25)What is the point on the graph of f(x-25) that corresponds to the point (a,b) on the graph of f?
Answers
Given
There exist a point (a, b) on the original function f(x).
Two points are corresponding if they appear in the same place in two similar situations.
The new function f(x-25) is a function shifted right by 25 units.
Hence, the point on the graph of f(x-25) that corresponds to the point (a, b) on the graph of f is:
[tex](a+25,\text{ b)}[/tex]
The length of a rectangle is 5 times its width if the perimeter is at most 96 cm what is the greatest possible value for the width
Answers
The value of the width in the rectangle is 8cm.
How to calculate the width?Based on the information, let the width be represented as w.
Let the width be represented as 5 × w = 5w
Perimeter = 96cm
Perimeter of a rectangle = 2(length + width)
Perimeter = 2(5w + w)
96 = 12w
Divide
w = 96/12
w = 8
The value of the width is 8cm.
Learn more about rectangles on:
brainly.com/question/25292087
#SPJ1
Area of a cylinder: S = 2лr² + 2лrh; solve for h.
Answers
The given equation for the area of a cylinder is:
S = 2πr² + 2лrh
Subtract 2πr² from both sides
S - 2πr² = 2πr² - 2πr² + 2лrh
S - 2πr² = 2лrh
Divide both sides 2лr
[tex]\begin{gathered} \frac{S-2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r} \\ \\ h=\frac{S-2\pi r^{2}}{2\pi r} \end{gathered}[/tex]If $4,780 is deposited in an account that pays 1.25% interest compounded annually, how much interest is in the account at the end of 8 years? A $5,279.44 B $500.44 C$ 478.00 D $499.44
Answers
We can calculate the interest as the difference between the future and the present value of the investment:
[tex]I=FV-PV[/tex]The present value is $4780.
The annual interest rate is r=1.25/100=0.0125.
The number of years is 8, so n=8.
We can calculate the future value as:
[tex]\begin{gathered} FV=PV(1+r)^n \\ FV=4780\cdot(1+0.0125)^8 \\ FV=4780\cdot1.0125^8 \\ FV\approx4780\cdot1.1045 \\ FV\approx5279.44 \end{gathered}[/tex]Then, we can calculate the interest as:
[tex]I=FV-PV=5279.44-4780=499.44[/tex]Answer: D. $499.44
slope = 2/5; y-intercept = -7
Answers
We want to find the equation of the line with given slope and y-intercept.
The slope-intercept form of a line is:
[tex]y=mx+b[/tex]Where
m is the slope
b is the y-intercept (y-axis cutting point)
We are given the slope and y-intercept, so we simply substitute it. Steps are shown below:
[tex]\begin{gathered} y=mx+b \\ y=\frac{2}{5}x+(-7) \\ y=\frac{2}{5}x-7 \end{gathered}[/tex]The equation of the line is:
[tex]y=\frac{2}{5}x-7[/tex]An empty shipping box weighs 250 grams. The box is then filled with t-shirts. Each tshirts weighs 132.5 grams. The equation W = 250 + 132.5T represents the relationship between the quantities in this solution where W is the weight in grams of the filled box and T the number of shirts in the box. Consider this equation 2900 = 250 + 132.5T. What does the solution to this equation tell us?
Answers
Given the next equation
2900 = 250 + 132.5T
its solution is:
2900 - 250 = 132.5T
2650 = 132.5T
2650/132.5 = T
T = 20
Given that W is weigth and T is t-shirts, the solution tell us that a box with 20 t-shirts weights 2900 grams
A bowl has 4 green marbles 3 red marbles and 2yellow marbles what is the probability that you are going to select a red marble and a yellow marble. You replace the marble before another marble is selected
Answers
ANSWER
2/27
EXPLANATION
There are a total of 9 marbles in the bowl. The probability of drawing a red marble is,
[tex]P(red)=\frac{\#red.marbles}{\#total.marbles}=\frac{3}{9}=\frac{1}{3}[/tex]Then you draw another marble, but you put the first back in the bowl, so the total number of marbles is the same. The probability of drawing a yellow marble is,
[tex]P(yellow)=\frac{\#yellow.marbles}{\#total.marbles}=\frac{2}{9}[/tex]The probability of drawing a red marble and a yellow marble is,
[tex]P(red.and.yellow)=P(red)\cdot P(yellow)=\frac{1}{3}\cdot\frac{2}{9}=\frac{2}{27}[/tex]