The distance covered by an ostrich in 3.5 seconds by running at the speed of 2.6 meters per second is 9.1 m.
What is distance?
Distance is the measurement of how far the objects under consideration are. It can be measured in terms of meters, centimeters, kilometers etc. Distance is a scalar quantity unlike displacement which is a vector quantity.
The distance covered by an ostrich can be calculated as, d = s * t
where d is distance, s is speed and t is the time taken.
d = 2.6 ms^-1 * 3.5 s = 9.1 m.
Therefore, the ostrich ran for 3.5 seconds to cover 9.1 m distance at the speed of 2.6 meters per second.
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Group the labels according to the type of magnet they describe.
Electromagnets Both Bar Magnets
Answers;Created by a current
Have fixed strengths
Attract iron
Have polarity
Occur in nature
Invented in 19th century
Only when a current passes through a wire encircling the core of an electromagnetic magnet do they become magnetic.
When a current is delivered through the wrapped around the iron piece, an electromagnet is created, which is a soft iron piece transformed into a magnet. Electromagnets are transitory magnets that only become magnetic in the presence of current; they demagnetize when the current is cut off.A bar magnet is a rectangular section of an object that exhibits persistent magnetic qualities. It can be constructed of steel, iron, or any other ferromagnetic material.Metal separation, food processing, and recycling all use bar magnets. Neodymium magnets housed in a stainless steel cylinder make up our bar magnets.To know more about electromagnet
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How much heat is necessary to change 295 g of ice at -5°C to water at 20°C? Answer must be in kcal
Given:
• Mass of ice = 295 g ==> 0.295 kg
,• Initial temperature, T1 = -5°C
,• Final temperature, T2 = 20°C
Let's find the amount of heat necessary to change the ice to water.
To find the amount of heat, let's apply the Specific Heat Capacity formula:
[tex]\begin{gathered} Q=mc\Delta T \\ \\ Q=mc(T_2-T_1) \end{gathered}[/tex]Where:
m is the mass in kg = 0.295 kg
T1 is the initial temperature
T2 is the final temperature.
c is the specific heat capacity
Let's first find the amount of heat required to change ice from -5°C to 0°C.
[tex]\begin{gathered} Q_1=0.295*0.50*(0-(-5)) \\ \\ Q_1=0.295*0.50*5 \\ \\ Q_1=0.74\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change from 0°C(ice) to 0°C(water).
We have:
[tex]\begin{gathered} Q_2=m*L \\ \end{gathered}[/tex]
Where L is the latent fusion of water:
[tex]\begin{gathered} Q_2=0.295*79.7 \\ \\ Q_2=23.51\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change 0°C (water) to 20°C(water).
We have:
[tex]\begin{gathered} Q_3=mc_{water}(T_2-T_1) \\ \\ Q_3=0.295*1.0*(20-0) \\ \\ Q_3=0.295*1.0*20 \\ \\ Q_3=5.9\text{ kcal} \end{gathered}[/tex]Therefore, the total heat required is:
Q = Q1 + Q2 + Q3
Thus, we have:
[tex]\begin{gathered} Q=0.74+23.51+5.9 \\ \\ Q=30.15\text{ kcal} \end{gathered}[/tex]Therefore, the amount of heat neccesary is
The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest. what might be responsible for this difference in service
The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
In the case of retail industry, it was easy to show courteousness, helping mentality and to offer discounts in 2008. The service executives had good knowledge on the products sold in the retail industry which helped them to handle the issues efficiently. Hence they received very high scores compared to other industries.
But cable and satellite TVs were in its initial stages in 2008 and hence the representatives had a little knowledge on the same to address customer doubts. Hence it was difficult for them to address the issues and giving discounts was also not possible due to the high cost required for installation and service.
Therefore, the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
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Plot a graph of the pendulum period, T, vs. amplitude, A, in degrees using LabQuest App or graph paper. Scale each axis from the origin (0,0). According to your data, does the period depend on amplitude?
Given the graph of period vs amplitude.
It can be seen from the graph that the plot of the period versus amplitude is almost a horizontal line. That is, as the amplitude increase, the period of the pendulum remains almost unchanged.
This is also consistent with the fact that the period of the simple pendulum indeed does not depend upon its amplitude.
Thus, according to the graph, the period does not depend on the amplitude.
A dvd is rotating with an ever-increasing speed. how do the centripetal acceleration arad and tangential acceleration atan compare at points p and q?.
The centripetal acceleration arad and tangential acceleration atan compare at points P and Q by Q having a greater arad and atan than point P.
arad = v² / r
v = 2 π r / T
arad = 4 π² r / T²
Since time period will be constant at any point in the radius line,
arad ∝ r
So larger the radius, larger will be the centripetal acceleration. The radius at point P is smaller than the radius at point Q.
arad at Q > arad at P
atan = r α
α = 2 π / T²
atan = 2 r π / T²
Since time period will be constant at any point in the radius line,
atan ∝ r
So larger the radius, larger will be the tangential acceleration. The radius at point P is smaller than the radius at point Q.
atan at Q > atan at P
Therefore, Q has a greater arad and atan than point P.
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HELP ME
PLS I will give brainliest
Answer:
Option 2
Explanation:
Since they want to know kinetic energy being increased, it cannot be Options 1 or 3. So now we're left with 2 and 4. 4 seems to be decreasing, so we can eliminate that. So, our answer is Option 2.
Where do rock formations go when they are subducted?
Group of answer choices below
A. Above the surface
B. Into the ocean
C. Into the mantle
D. To the core
Option C: Rock formations are subducted into the mantle after subduction.
Describe subduction.Where two or more lithospheric plates meet, a geological process called as subduction recycles rocks from the oceanic lithosphere into the Earth's mantle. Where the tectonic plate converged between the oceanic lithosphere and a less dense lithosphere, the heavier plate sinks beneath the other plate into the mantle.
Deeply subducted sedimentary and metaphorical rocks eventually melt to generate magma, which subsequently cools to form igneous rock.
Therefore the rock cycle encompasses the entire process and lasts millions of years.
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Calculate the kinetic energy of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s.
Given,
The mass of the car, m=1000 kg
The velocity of the car, v=20 m/s
The kinetic energy of an object is the energy of the body possessed due to its motion. The kinetic energy of a body is directly proportional to the square of the velocity of the object.
The kinetic energy of the car is given by,
[tex]E=\frac{1}{2}mv^2[/tex]On substituting the known values,
[tex]\begin{gathered} E=\frac{1}{2}\times1000\times20^2 \\ =200000\text{ J} \\ =200\text{ kJ} \end{gathered}[/tex]Thus the kinetic energy of the given car is 200 kJ.
You throw a ball vertically upward from the roof of a tall building.
The ball leaves your hand at a point even with the roof railing with
an upward speed of 15.0 m/s; the ball is then in free fall. On its
way back down, it just misses the railing. Find the ball's posi-
tion and velocity 1.00 s and 4.00 s after leaving your hand
11.1 m and -18.4 m is the ball's position, 5.2 m/s and -24.2 m/s is the ball's velocity after leaving your hand
s = ut + 1/2at²
s = 15(t) + 1/2(-9.8)(t)²
s = 15t - 4.5(t)²
t = 1 second,
s = 15(1) - 4.9(1)²
s = 15 - 4.5
s = 11.1 m [at t = 1 second]
t = 4 seconds,
s = 15(4) - 4.9(4)²
s = 60 - 4.9(16)
s = 60 - 78.4
s = -18.4 m [t = 4 seconds]
v = u + at
v = 15 + (-9.8)t
time = 1 second,
v = 15 - 9.8
v = 5.2 m/s [ t = 1 second]
time = 4 seconds,
v = 15 - (9.8)(4)
v = 15 - 39.2
v = -24.2 m/s [for t = 4 seconds]
velocity's a vector quantity have magnitude and direction.
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What is the magnetic force on a proton that is moving at 2.5 × 107 m/s up
through a magnetic field that is 0.12 T and pointing toward you? The charge
on a proton is 1.6 x 10-19 C. Use F = qvx B sin(e).
A. 4.8 x 10-13 N left
OB. 4.0 × 10-12 N down
x
C. 4.8 x 10-13 N right
D. 4.0 × 10-12 N up
X
4.8× 10^-11 weber is the magnetic force on a proton that is moving at 2.5 × 10^7 m/s up through a magnetic field that is 0.12 T
F=qBv
q=1.6 x 10^-19 C
v=2.5 × 10^7 m/s
B=0.12T
F=qBv
F=1.6 x 10^-19 C×2.5 × 10^7 m/s×0.12T
F=4.8× 10^-11 weber
A magnetic force, attraction, or repulsion is produced by the motion of electrically charged particles. It is the underlying force that causes phenomena like the operation of electric motors and the attraction of magnets to iron. There are electric forces acting on stationary electric charges, and there are magnetic and electric forces acting on moving electric charges. The magnetic force between two moving charges is the effect of a magnetic field produced by one charge on another charge.
The intensity of the magnetic field B1 produced by the first moving charge, the sine of the angle theta, the second particle's charge q2, its velocity v2, and the magnetic force F are all inversely related in this hypothesis.
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if a gram of antimatter meets a kilogram of matter, the amount of mass to survive is group of answer choices 1 kilogram. 999 grams. 1 gram. 1.1 kilogram.
If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.
Matter :
A substance called matter is made up of different kinds of particles, occupies space, and has inertia.
The various types of particles each have a unique mass and size according to the fundamentals of modern physics.
Antimatter :
As the opposite particles of the corresponding particles in "ordinary" matter, the antimatter is defined as matter made up of them.
The two particles' combined mass is entirely converted into energy. The term "matter-antimatter annihilation" refers to this process.
If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.
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Find two specific applications/connections to Newton's first law. In your descriptions, use the terms inertia and balanced/unbalanced forces to describe whether the object in your example changes its state of motion.
Answer:
Explanation:
every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
State two assumptions of the Kinetic Theory.
Answer:
Explanation: 1: The gas particles move in a straight line before colliding with something, usually the wall of their containers.
2: The is no attraction or repulsion between the gas particles.
As part of an experiment on momentum, a billiard ball with a mass of
0.180 kg travels 1.5 m in 0.5 s. What is the momentum of the ball?
(1 point)
Answer: 0.54 kg meter per second
Explanation:
this is a cost of 0.180. Multiplying by 1.5 divided by 5 equals 0.54 Kg meter per second. This is the momentum.
I hope this helps!
A child is pulling a wagon across the grass but friction between the grass and wheel creates a force in the opposite direction . If the wagon is speeding up , what does that mean about the two forces ?
ANSWER
The applied force is larger than the frictional force
EXPLANATION
If we draw a free-body diagram,
By Newton's second law, for the horizontal forces is,
[tex]F_a-F_f=m\cdot a[/tex]If the wagon is speeding up, it means that there is a positive acceleration. Therefore, the difference Fa - Ff is positive,
[tex]\begin{gathered} F_a-F_f>0 \\ \text{therefore} \\ F_a>F_f \end{gathered}[/tex]Hence, the applied force is greater than the frictional force.
Identify a stressor in your life.
Create an action plan to manage the stressor you identified. Use the Stress Action Plan template to guide your work. Your action plan should include:
A description of the stressor you chose
At least two paragraphs explaining how you will apply the information learned in the lesson to effectively manage your stress
At least two effective strategies you will use and one ineffective strategy you will avoid
You can improve how you handle stress and difficulties (adversity) in your life by using a variety of stress management techniques. You may lead a more well-balanced existence by controlling your stress.
What are the importance of managing stress?You put your complete well-being at danger if you're under a lot of stress every day. Your mental balance and physical health both suffer from stress. Your capacity for clear thinking, successful functioning, and enjoyment of life is reduced. You could feel helpless in combating stress. There won't ever be more hours in the day, the bills won't stop rolling in, and your obligations to your job and family will always be demanding. Stress is a natural, spontaneous reaction to a stressful situation on the body, mind, and emotions. Everyone's life entails it as a normal aspect. Stress can spur growth, activity, and change when it is used constructively. Long-term, negative stress, though, might lower your level of well-being.Though it may not seem like it, you actually have a lot more control. Achieving effective stress management enables you to release the grip that stress has on your life and improves your ability to be happier, healthier, and more effective. The ultimate objective is a well-balanced existence with time for work, relationships, relaxation, and fun—as well as the resilience to hold up under stress and face obstacles head-on. However, there is no one approach to stress management that works for everyone. Discovering what works best for you through experimentation is crucial. You can do it with the aid of the stress-reduction advice that follows.To know more about Stress Management, visit:
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Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field what is the force applied to the ball ?
From Newton's second law of motion, the magnitude of the force applied is 1022.4 N
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and acceleration and it is a vector quantity.
Given that Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field.
The force F applied to the ball = mass × acceleration. That is,
F = ma
Where
m = 0.527 kgv = 19.4 m/st = 0.01 sF = ?a = ?Acceleration a = v/t
a = 19.4/0.01
a = 1940 m/s²
Force F = ma
F = 0.527 × 1940
F = 1022.4 N
Therefore, the force applied to the ball is 1022.4 N
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Consider a system of a cliff diver and the earth. The gravitational potential energy of the system decreases by 26,500 J as the diver drops to the water from a height of 33.0 m. Determine her weight in newtons.
Given data:
* The change in gravitational potential energy is 26500 J.
* The change in height of the diver is 33.0 m.
Solution:
The change in gravitational potential energy in terms of change in height of the diver is,
[tex]dU=mg\times dh[/tex]where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,
Substituting the known values,
[tex]\begin{gathered} 26500=mg\times33 \\ mg=\frac{26500}{33} \\ mg=803.03\text{ N} \end{gathered}[/tex]The weight of the diver is,
[tex]\begin{gathered} W=mg \\ W=803.03\text{ N} \end{gathered}[/tex]Thus, weight of the diver is 803.03 N.
Why are electrical safety devices important in an electric circuit?
Answer:A fuse is an electrical safety device that has the capability to protect an electric circuit from excessive electric current. It is designed to allow current through the circuit, but in the event that the current exceeds some maximum value it will open, severing the circuit.
Explanation:
Answer:
See below
Explanation:
Ground wires and fuse are used to help avoid an electrical shock and current overload (and possible fire)
the peak wavelength of the emission spectrum of a star is 320 nm. which one of the following is the only possible correct statement?
The peak wavelength of the emission spectrum of a star is 320 nm Object 1 is three times as hot as object 2.
In physics, the wavelength is the length over which a periodic wave repeats, or its spatial period. It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda () is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.
Question :
Object 1 is observed to be emitting most of its light at a wavelength of 320 nm (ultraviolet). Object 2 is observed to be emitting most of its light at a wavelength of 960 nm (infrared). How much hotter is object 1 than object 2?
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The angular speed of earth around its own axis
7.26 x 10-5 rad/sec
The angle of one rotation is 2π. The time required for this rotation is 24 hours to calculate the angular speed of the Earth as it rotates completely around its own axis. Average Angular Velocity Wav is the average rate of change of angular displacement.
On converting the hours into seconds we get,
Time = 24 hr x 60 min/hr x 60 sec/min = 86400 sec
The angular speed is given by the formula, ω = θ /t.
after substituting the value given in the equation we get,
ω = 2π / 86400 Seconds
ω = 0.0000726 radians/sec = 7.26 x 10-5 rad/sec
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360 degrees per 24 hours
Determine the power required for a 1150 kg car to climb a 100 m-long uphill road with a slope of 30 degree (from horizontal) in 12 s at a constant velocity.
The Power required for a 1150 kg car to climb is 104.46kW.
L = 100 m, 0°, 1150 kg, and 12 s are the values.
while it is moving at a fixed rateEnergy E = mxgh = mxglxsin = 1150x9.8x100xsin30=563500J
Power, P, is calculated as follows: 563500 / 12 = 46958.
3 watts equal 46.95 kW
(b) From a standstill to a final speed of 30 m/sE = mgxlsin+1/2mv2 and gxlsin+mv2
E = 1081000 J P = E / T = 1081000 / 12 = 90083.33 W = 90.1 kW E = 1150 x 9.8 x 100 x Sin 30 + 0.5 x 1150 x 30 x 30
(c) between 35 m/s and 5 m/sE = m x g x L Sin + mv - mu - half
0.5 x 1150 x 35 x 35 - 0.5 x 1150 x 5 x 5 E = 1150 x 9.8 x 100 x Sin 30 Plus = 104.46 kW = 104458.33 W = 563500 + 704375 - 14375 = 1253500 J P = E / T
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1. If a pair of running shoes would weigh 11.55 newtons on Jupiter, what is the strength of gravity there?
2. If the same pair of shoes weighs 0.3 newtons on Pluto, what is the strength of gravity on pluto?
3.What does the pair of shoes weigh on earth?
The strength of gravity of planets Jupiter and Pluto are 23.1m/s² and 0.6m/s² respectively.
We are given that,
The mass of the shoes = m=0.500 kg
The weigh of the shoes on the Jupiter = W₁=11.55 N
The weigh of the shoes on the Pluto = W₂=0.3 N
Therefore, the weight to mass ratio determines the strength of gravity, or the acceleration caused by gravity.
Then the strength of gravity on Jupiter can be calculated as,[tex]g_{j} = \frac{w_{1} }{m}[/tex]
Putting the values in above equation we can get,
[tex]g_{j} = \frac{11.55N}{0.500kg}\\ g_{j} = 23.1m/s^{2}[/tex]
Since, the gravity strength of planet Jupiter would be 23.1m/s²
The strength of gravity of planet Pluto can be calculated when shoes weigh is 0.3 N,[tex]g_{p} =\frac{w_{2} }{m} \\g_{p} = \frac{0.3N}{0.500kg} \\g_{p} = 0.6 m/s^{2}[/tex]
Thus, the gravity strength of planet Pluto may be 0.6m/s².
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1 point1. Inertia is the tendency of an object to stay at rest or in motion. *TrueFalse
The given statement is true
Inertia is the tendency of an object to stay at rest or in motion
Given a horizontal uncharged insulating rod. A negatively charged rod touches the middle of the horizontal rod. Which of these best describes what happens? A)the rod becomes positively charged on its left end and negatively charged on its right end B)the middle of the rod becomes negatively charged C)the rod becomes positively charged all over its surface D)the rod becomes negatively charged all over its surfaceE) the rod remains uncharted
Answer:
E) The rod remains uncharted.
Explanation:
The negatively charges rod has an excess of electrons. These electrons repel each other, so when this rod touches the horizontal uncharged insulating rod, they will try to go to the uncharge rod. However, this is an insulating rod, so there will be no transfer of electrons. It means that the rod remains uncharted.
This question is typical on some driver’s license exams: A car moving at 46 km/h skids
15 m with locked brakes.
How far will the car skid with locked brakes
at 115 km/h? Assume that energy loss is due
only to sliding friction.
Answer in units of m.
A car moving at 46 km/h skids 15 m with locked brakes. The distance travelled by the car when it skids is 94.74 m.
What is the acceleration of the car?The acceleration of the car is calculated by applying the following kinematic equation.
v² = u² - 2as
where,
v is the final velocity of the car
u is the initial velocity of the car
a is the acceleration of the car
s is the distance travelled by the car
when the car stops, the final velocity, v = 0
0 = u² - 2as
2as = u²
a = u²/2s
where,
u = 46 km/h = 12.7 m/s
a = (12.7²) / (2 x 15)
a = 5.37 m/s²
When the speed of the car changes from 42 km/h to 126 km/h, the distance travelled by the car at the same acceleration is calculated as follows;
s = u²/2a
where,
u = 115 km/h = 31.9 m/s
s = (31.9²) / ( 2 x 5.37)
s = 94.74 m
The distance travelled by the car when it skids is 94.74 m.
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Drag and drop the words into the correct locations. HELP A GIRL OUT I HAVE TO SUMMIT THIS IN 18 MINS AND IF I FAIL THIS TEST MY GRADE WILL GO DOWN PLEASE
Two object experiencing force between them the strength of the force increases as the mass increases , and decreases as the distance increases.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
f = Gmm/r²
Two object experiencing force between them the strength of the force increases as the mass increases , and decreases as the distance increases.
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A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s. The linear speed of a point on the wheel’s rim = 178 radWhat is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?
Given data
*The given radius of the wheel is r = 30.0 cm = 0.30 m
*The given angle of the wheel rotates in 1.00 s is
[tex]\theta=178.0\text{ rad}[/tex]*The angular velocity of the wheel is
[tex]\omega=178.0\text{ rad/s}[/tex]The formula for the linear speed of a point on the wheel's rim is given as
[tex]v=r\omega[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v=(0.30)(178.0) \\ =53.4\text{ m/s} \end{gathered}[/tex]Hence, the linear speed of a point on the wheel's rim is v = 53.4 m/s
The formula for the wheel's frequency of rotation is given as
[tex]\begin{gathered} \omega=2\pi f \\ f=\frac{\omega}{2\pi} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} f=\frac{178.0}{2\times3.14} \\ =28.34\text{ Hz} \end{gathered}[/tex]Hence, the wheel's frequency of rotation is f = 28.34 Hz
a student rolls a marble off of a 1.0 m tall table and it lands 1.5 m away Calculate the initial horizontal velocity. (closest to) Answer A 0.30 m/s B 0.54 m/s C 1.82 m/s D 3.33 m/s
The horizontal velocity of the marble is 3.33 m/s.
option D is the correct answer.
What is the initial horizontal velocity of the marble?The initial horizontal velocity of the marble is calculated by applying the following equation as shown below;
X = Vₓt
where;
Vₓ is the horizontal velocity of the marblet is the time of motion of the marbleThe time of motion of the marble from the table is calculated as follows;
t = √(2h/g)
where;
h is the height of the tableg is the acceleration due to gravityt = √(2 x 1 / 9.8)
t = 0.45 seconds
The horizontal velocity of the marble is calculated as;
Vₓ = X / t
Vₓ = 1.5 m / 0.45 s
Vₓ = 3.33 m/s
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A ball is thrown up into the air with 100 j of kinetic energy, which is transformed to gravitational potential energy at the top of its trajectory. The ball encounters some air resistance. What is its kinetic energy when it returns to its original height?.
The kinetic energy when it returns to its original height is 100 J
The ball is thrown up with a Kinetic Energy K. E. = 0.5×m×v² = 100 J
Therefore the final height is given by
u² = v² -2·g·s
Where:
u = final velocity = 0
v = initial velocity
s = final height
Therefore v² = 2·g·s = 19.62·s
P.E = Potential Energy = m·g·s
Since v² = 2·g·s
Substituting the value of v² in the kinetic energy formula, we obtain
K. E. = 0.5×m×2·g·s = m·g·s = P.E. = 100 J
When the ball returns to the original height, we have
v² = u² + 2·g·s
Since u = 0 = initial velocity in this case we have
v² = 2·g·s and the Kinetic energy = 0.5·m·v²
Since m and s are the same then 0.5·m·v² = 100 J.
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