Find the volume of this cone.Use 3 for TT.V = Tigh3Hint: The radius (1) is1/2 of the diameter.6 ft6 ft-3V ~ [?]ft
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ANSWER
[tex]54ft^3[/tex]EXPLANATION
The volume of a cone is given by:
[tex]V=\frac{\pi r^2h}{3}[/tex]where r = radius
h = height
The height of the given cone is 6 ft and its diameter is 6 ft. The radius of a cone is half its diameter, hence its radius is:
[tex]\begin{gathered} r=\frac{6}{2} \\ r=3ft \end{gathered}[/tex]Hence, the volume of the cone is:
[tex]\begin{gathered} V=\frac{3\cdot3^2\cdot6}{3} \\ V=54ft^3 \end{gathered}[/tex]That is the answer.
Related Questions
Anna found that there are 3^4 options for pizzas with different loppings at her local are there for pizzas? B. 12 c. 64 D.BA ker notes
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As there are 3^4 options for pizzas, we can calculate this as:
[tex]3^4=3\cdot3\cdot3\cdot3=81[/tex]Answer: 3^4 options is equivalent to 81 options (option D).
There are 364 people That have to go from the airport to the hotel. One sand can’t transfer 12 people have any vans are needed
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To find the number of van that are needed you divide the number of people into the people that a van can transport:
As the result of division is a decimal number you approximate it to the next whole number (because you can not have 0.33 of a van)
Then, there are needed 31 vansA hummingbird can travel up to 15 meters per second.What is the hummingbird's speed in miles per hour?1 mile ≈ 1609 meters Enter your answer, as a decimal to the nearest tenth, in the box. mph
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SOLUTION
The speed of the hummingbird is giving as
[tex]\text{ 15meter/seconds }[/tex]Recall that
[tex]1\text{mile}\approx1609\text{ meters }[/tex]Hence
[tex]\begin{gathered} 15\text{meters will be }\frac{15}{1609}miles\text{ } \\ \\ \end{gathered}[/tex]Recall that
[tex]3600\text{ seconds =1hour }[/tex]Hence
the speed of the hummingbird in miles per hour will be
[tex]\begin{gathered} \frac{15}{1609}\times\frac{3600}{1}=\frac{54000}{1609}=33.56\text{miles per hour } \\ \\ \end{gathered}[/tex]Therefore the speed in miles per hour to the nearest tenth is 33.6mph
Instructions: Find the missing side of the triangle. tion 24 x 7 2 =
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We are given a right-angled triangle.
Two of the side lengths are given and the third is missing.
We can us the Pythagorean theorem to find the missing side of the triangle.
[tex]c^2=a^2+b^2[/tex]Where c is the longest side, a and b are the shorter sides of the triangle.
[tex]\begin{gathered} c^2=a^2+b^2 \\ x^2=7^2+24^2 \\ x^2=49^{}+576 \\ x^2=625 \\ x^{}=\sqrt[]{625} \\ x^{}=25 \end{gathered}[/tex]Therefore, the missing side of the triangle is 25
x^2+x^2=11.3^2 solve using the pathogen theorem
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The value of x in the given expression is 8.
What is Pythagoras theorem?Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (a² + b² = c²).
Given an expression, x²+x² = 11.3²
2x² = 11.3²
[tex]\sqrt{2}[/tex]x = 11.3
x = 7.99 = 8
Hence, The value of x in the given expression is 8.
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need help- don’t mind the writing in pencil I forgot to erase it
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We will deteremine the length of segment TV as follows:
[tex]A=\frac{WU\cdot TV}{2}\Rightarrow200=\frac{16\cdot TV}{2}[/tex][tex]\Rightarrow400=16\cdot TV\Rightarrow TV=25[/tex]So, the lenght of segment TV is 25 centimeters.
Find the area bounded by the given curves. y=x², y=4 Options:32/3 31/3 34/3 37/3
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We have to find the area within the given curves.
We have to integrate the difference between the two functions.
First, we have to find the intersections between the curves to know the interval for which we will integrate.
We then write:
[tex]\begin{gathered} y_1=y_2 \\ x^2=4\Rightarrow x_i=-2,x_f=2 \end{gathered}[/tex]We will integrate in the interval [-2, 2]. In this interval, the function y=4 is greater than y=x^2, so we will integrate the difference of the functions as:
[tex]\begin{gathered} A=\int ^2_{-2}\lbrack y_2(x)-y_1(x)\rbrack dx \\ A=\int ^2_{-2}(4-x^2)dx \\ A=4x-\frac{x^3}{3}+C \\ A=(4\cdot(2)-\frac{(2)^3}{3})-(4\cdot(-2)-\frac{(-2)^3}{3}) \\ A=(8-\frac{8}{3})-(-8+\frac{8}{3}) \\ A=8-\frac{8}{3}+8-\frac{8}{3} \\ A=16-\frac{16}{3} \\ A=\frac{48-16}{3} \\ A=\frac{32}{3} \end{gathered}[/tex]The area bounded by the curves y=x^2 and y=4 is A = 32/3.
Chase rode a Ferris wheel 93 timesaround, one lap after the other. If eachlap of the Ferris wheel took 20 seconds,how long was Chase's ride?minute
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If Chase rode 93 times around, and each lap takes 20 seconds, to find out how long was Chase's ride we must multiply the time for each lap, and how many laps she did, then, the calculus will be
[tex]time=93\cdot20[/tex]The result will be in seconds!
[tex]\begin{gathered} time=93\cdot20 \\ \\ \text{time}=1860\text{ seconds} \end{gathered}[/tex]Then Chase's ride was 1860 seconds long! We can covert it in minutes by doing the division by 60
The time in minutes will be
[tex]\begin{gathered} \text{time}=\frac{1860}{60}\text{ minutes} \\ \\ \text{time}=31\text{ minutes} \\ \end{gathered}[/tex]Therefore, Chase's ride took 31 minutes
I have a practice question that I need explained and answered. Thank you - Rose
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To determine the x - coordinate of the distance between two points:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]The distance between the two points is estimated using the above formular
[tex]\begin{gathered} x_2=4 \\ x_1=?_{} \\ y_1=-1 \\ y_2=9 \\ d=6\sqrt[]{6} \end{gathered}[/tex][tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ 6\sqrt[]{6}=\sqrt[]{(x-4)^2+(9--1)^2} \\ \text{square both side } \\ (6\sqrt[]{6)^2}=(\sqrt[]{(x-4)^2+10^2})^2 \\ 216=(x-4)^2+100 \\ 216-100=(x-4)^2 \end{gathered}[/tex][tex]\begin{gathered} 116=(x-4)(x-4) \\ 116=x^2-8x+16 \\ 100=x^2-8x \\ x^2-8x-100=0 \end{gathered}[/tex]Solve using quadratic formular
[tex]\frac{-b\pm\sqrt[]{b^2}-4ac}{2a}[/tex][tex]\begin{gathered} \frac{-b\pm\sqrt[]{b^2}-4ac}{2a}\ldots..\text{ a= 1 , b = -8 , c = -100} \\ \frac{-(-8)\pm\sqrt[]{(-8)^2-4(1)(-100)}}{2(1)} \\ \frac{8\pm\sqrt[]{64+400}}{2} \\ \frac{8\pm\sqrt[]{464}}{2}=\frac{8\pm4\sqrt[]{29}}{2} \\ \frac{2(4\pm2\sqrt[]{29)}}{2}=4\pm2\sqrt[]{29} \end{gathered}[/tex]Therefore the correct answer for the x - coordinates are:
[tex]\begin{gathered} x=4+2\sqrt[]{29}\text{ and } \\ x_{}=4-2\sqrt[]{29} \end{gathered}[/tex]Brad expects that he will need $12,000 in 6 years to start an engineering consulting business. He has been offered an investment at 5%, compounded monthly. How much must he invest today to have enough money in 6 years? How much interest will he have earned?
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Answer:
Invest today: $8895.36
Interest earned: $3104.64
Explanation:
The amount after t years can be calculated as:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where P is the initial amount invested, r is the interest rate and t is the number of years and n is the number of times the interest rate is compound. Solving the equation for P, we get:
[tex]P=\frac{A}{(1+\frac{r}{n})^{nt}}[/tex]Now, we can replace A by $12,000, r by 5% = 0.05, n by 12 because it is compounded monthly and t by 6
[tex]P=\frac{12000}{(1+\frac{0.05}{12})^{12(6)}}=8895.36[/tex]Therefore, he should invest $8895.36 today to have enough money in 6 years.
Finally, the interest earned is calculated as
$12000 - $8895.36 = $3104.64
So, the answers are:
Invest today: $8895.36
Interest earned: $3104.64
Ashton, Anywhere had a population of 294876 in 2007. The population is inci upon this data, predict the population for in 9 years.
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Answer:
378,075
Explanation:
The population of Ashton in 2007 = 294876
The population increases at a constant rate of 2.8%.
Therefore, the population at any time, t after 2007 is:
[tex]\begin{gathered} P(t)=294876(1+2.8\%)^t \\ P(t)=294876(1+0.028)^t \\ P(t)=294876(1.028)^t \end{gathered}[/tex]Therefore, the population in 9 years time will be:
[tex]\begin{gathered} P(9)=294876(1.028)^9 \\ =378074.6 \\ \approx378,075 \end{gathered}[/tex]The predicted population in 9 years will be 378,075.
how much higher is 1,774 than -118(adding and subtracting integers)
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To find the difference between two numbers, we substract the smaller one from the bigger one. In this case, the smaller one is -118 and the bigger one is 1,774. Then:
[tex]1774-(-118)=1774+118=1892[/tex]Then 1774 is higher than -118 by 1892
can you help with this one its has 11 part to it
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Recall that the limit of a function exists if
[tex]\lim_{x\to n^+}f(x)=\lim_{x^\to n^-}f(x).[/tex]Now, from the graph, we get that:
[tex]\begin{gathered} \lim_{x\to0^-}f(x)=0, \\ \lim_{x\to0^+}f(x)=0, \end{gathered}[/tex]therefore:
[tex]\lim_{x\to0}f(x)=0.[/tex]Answer: [tex]True.[/tex]slove two-step liner equations 19=s/2+15
Answers
s = 8
Explanation:
19=s/2+15
collect like terms:
19 - 15 = s/2
4 = s/2
[tex]\begin{gathered} 4\text{ =}\frac{s}{2} \\ \text{cross multiply} \\ s\text{ = 4}\times2 \\ s\text{ = 8} \end{gathered}[/tex]Solve the system of equation graphed on the coordinate axed below y=-4/3x-1
Y=4/3x+7
Answers
Answer:
[tex]x=-3, y=3[/tex]
Step-by-step explanation:
The solution to a system is where the graphs intersect.
What is the slope of the points (3,64) and (9,79).
m=
m =
= 15
6
m =
Un Hồ
2-#1
m=2.5
6
15
Answers
Answer:
[tex]\boxed{\bf Slope(m)=2.5}[/tex]
Step-by-step explanation:
We can use the slope formula to find the slope of a line given the coordinates of two points on the line:- (3,64) and (9,79).
The coordinates of the first point represent x_1 and y_1. The coordinates of the second points are x_2, y_2.
[tex]\boxed{\bf \mathrm{Slope}=\cfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf \left(x_1,\:y_1\right)=\left(3,\:64\right)[/tex]
[tex]\sf \:\left(x_2,\:y_2\right)=\left(9,\:79\right)[/tex]
[tex]\sf m=\cfrac{79-64}{9-3}[/tex]
[tex]\sf m=\cfrac{5}{2}[/tex]
[tex]\sf m=2.5[/tex]
Therefore, the slope of (3,64) and (9,79) is D) 2.5!!
___________________
Hope this helps!
Have a great day!
Answer:
m = (y2 - y1)/(x2 - x1) m = 15/6 m = 2.5Step-by-step explanation:
Formula we use,
→ m = (y2 - y1)/(x2 - x1)
Then the required slope is,
→ m = (y2 - y1)/(x2 - x1)
→ m = (79 - 64)/(9 - 3)
→ m = 15/6
→ [ m = 2.5 ]
Hence, the slope is 2.5.
How do you solve literal equation:u=x-k, solve for x12am=4, solve for aa-c=d-r, solve for a
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In order to solve a literal equation, we just need to isolate the chosen variable in one side of the equation. So we have:
[tex]\begin{gathered} u=x-k \\ u+k=x \\ x=u+k \\ \\ 12am=4 \\ a=\frac{4}{12m} \\ a=\frac{1}{3m} \\ \\ a-c=d-r \\ a=d-r+c \end{gathered}[/tex]Tomas is leaving a tip of 18% of his original bill. If the amount of the tip is $2.34, which of the following equations can be used to find the amount of his original bill?0.18b = 2.34b - 0.18 = 2.342.34 x 0.18 = bb/2.34 = 0.18
Answers
Answer
0.18b = 2.34
Step-by-step explanation
Let's call b to the bill
The tip is 18% of the bill. To find the 18 percent of a number, we need to multiply this number by 18 and then divide by 100. In this case, the tip is:
[tex]\begin{gathered} tip=\frac{18}{100}b \\ tip=0.18b \end{gathered}[/tex]The amount of the tip is $2.34, then:
[tex]0.18b=2.34[/tex]Using the image above, which of the following are opposite rays?A QP and PLB PL and PQC LP and QPD LQ and PQ
Answers
ANSWER
PL and PQ
EXPLANATION
We want to find which of the rays are opposite rays.
That means which of the rays are going in opposite direction and are the same length to one another.
We see different rays in the image. Some are going upward while some are going downward.
The ones going upward are:
LQ and PQ
The ones going downward are:
QL and PL
By observation, among all the options, we see that only PL and PQ are the same length and that are in opposite directions.
That means that the answer is PL and PQ
1 Factor each polynomial over the set of realC)f(x) = x^4- 25x^2 + 144
Answers
Notice that:
[tex]\begin{gathered} x^4-25x^2+144=(x^2)^2+(-9-16)x^2+(-9)(-16) \\ =(x^2-9)(x^2-16)\text{.} \end{gathered}[/tex]Now, notice that:
[tex]\begin{gathered} x^2-9=x^2-3^2=(x+3)(x-3), \\ x^2-16=x^2-4^2=(x+4)(x-4)\text{.} \end{gathered}[/tex]Therefore:
[tex]x^4-25x^2+144=(x+3)(x-3)(x+4)(x-4)\text{.}[/tex]Answer:
[tex]x^4-25x^2+144=(x+3)(x-3)(x+4)(x-4)\text{.}[/tex]
50. What is the intersection of plane STUV and plane UYXT?SуUWZA. SVB.YZC. STD. TX
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The intersection of plane STUV and plane UYXT will be the line segment TU.
The task is to determine the intersection of the planes UYXT and STUV.
We are aware of;
When two planes overlap, their intersection is a straight line.
The points 'T' and 'U' are shown in the picture to be on both planes UYXT and STUV.
As a result, the line connecting these two points, that is, the line TU likewise lies on both planes.
As a result, the line 'TU' is formed by the intersection of both planes.
Thus, the intersection of plane STUV and plane UYXT will be the line segment TU.
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help me out please thanks
Answers
Answer:
1/10
Step-by-step explanation:
=a+4/5=3/2
=a=4/5-3/2
=a=1/10
Answer: a = 7/10
Step-by-step explanation:
Convert and mix 1 and 1/2 to get 3/2
Next move 4/5 to the right side
Then multiply 4/5 by 3/2 to get the answer 7/10
a figure has vertices (-13,13), (26,52), (39,39) what would the new coordinates of the vertices to the nearest tenth if the image were reduced by a scale factor of 0.77 with the origin as the center of dilation
Answers
Explanation
Given that the figure has vertices (-13,13), (26,52), (39,39), to reduce the image by a scale factor of 0.77 with the origin as the center of dilation, we will multiply the x and y coordinates by the scale factors.
a) which is equation of the parabola? b) name the focus and directrix ? c) name vertex and axis of symmetry?
Answers
The equation of the parabola whose axis of symmetry is parallel to x-axis is
[tex](y-k)^2=4p(x-h)[/tex]where the focus is
[tex]\text{focus}=(h+p,k)[/tex]and the directrix is
[tex]x=h-p[/tex]In our case, the focus is (6,1) and the directrix is x =2; therefore, we have
[tex](6,1)=(h+p,k)[/tex]and
[tex]h-p=2[/tex]These equations give
[tex]k=1,h=4,p=2[/tex]Hence, the equation of the parabola is
[tex](y-1)^2=8(x-4)[/tex]>>Хx = [?](Enter the number that belongs in the green box.
Answers
Answer: x = 90 degrees
Explanation:
In the given figure, the opposite sides are parallel. This means that the vertices are right angles. A right angle is 90 degrees. Thus,
x = 90 degrees
is the least common denominator of two fractions always greater than the denominators of the fractions
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The least common denominator of two fractions is not always greater than the denominators of each fraction because sometimes the least common denominator is equal to the greater denominator. For example, if we have the fractions
[tex]\frac{4}{5}-\frac{1}{5}[/tex]In this case, since you have equal denominators, the least common factor would be 5, not greater than 5.
Another example could be
[tex]4+\frac{2}{9}[/tex]In this case, the least common denominator is 9, not greater than 9.
Therefore, the least common denominator is not always greater than the denominator of the fractions.Bailey wants to buy a house, paying approximately $1000 per month. The bank estimates a 4.5% annual interest rate for 15 years. Which formula approximates the total value of a house Bailey can afford?
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Data:
Amount per month: $1000
Interest rate: 4.5% annual for 15 years
As Bailey wants to pay approx. $1000 per month, in a year he wants to pay approx.: $12000
[tex]1000\cdot12=12000[/tex]8i+ 5 - 2i equals 3i+ 23
Answers
We will have:
[tex]8i+5-2i=3i+23[/tex]We will operate like terms and solve for i, that is:
[tex]8i-2i-3i=23-5\Rightarrow3i=18\Rightarrow i=6[/tex]*Step by step:
[tex]8i+5-2i=3i+23\Rightarrow6i+5=3i+23[/tex][tex]\Rightarrow6i+5-5=3i+23-5\Rightarrow6i=3i+18[/tex][tex]\Rightarrow6i-3i=3i+18-3i\Rightarrow3i=18[/tex][tex]\Rightarrow\frac{3}{3}i=\frac{18}{3}\Rightarrow i=6[/tex]can you help me is it < > or =
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The correct answer is
[tex]\frac{1}{4}\times4\frac{1}{2}<4\frac{1}{2}[/tex]Use the drop-down menus to identify the values of theparabola.Vertex=Domain=Range=
Answers
Given:
We get the point (0,4) from the graph.
Recall that the vertex of a parabola is the point at the intersection of the parabola and its line of symmetry.
[tex]\text{Vertax =(0,4)}[/tex]Every single number on the x-axis results in a valid output for the function.
The domain of the parabola is real values.
[tex]\text{Domain}=(-\infty,\infty)[/tex]
The maximum value of y is 4 and the parabola is open down.
[tex]Range=(-\infty,4\rbrack[/tex]Final answer:
[tex]\text{Vertax =(0,4)}[/tex][tex]\text{Domain}=(-\infty,\infty)[/tex][tex]Range=(-\infty,4\rbrack[/tex]