The given parameters are:
y=x^3, y=1
From the question,
Question 7 Luna's savings increases as a linear function of the number of chores she does, as shown in the table. How much money did Luna have saved before she started doing chores? Chores Savings ($) 1 74 2 78 3 82 4 86 $0 $70 $64 $68
A 100$ printer cost 44$ less than eight times the cost of a ream of paper. How much is a ream of paper?
3. Which inequality is represented by the graph below?y < 3x + 2y =3x + 2y > 3x + 2y= 3. + 2
Answer
Option A is correct.
The inequality equation represented by the graph is
y < 3x + 2
Explanation
When plotting the graph of linear inequality equations, the first step is to first plot the graph of the straight line normally, using intercepts to generate two points on the linear graph.
Looking at the graph given, we can tell that the graph without considering the inequality yet is y = 3x + 2
If the inequality sign is (< or >), then the line drawn will be a broken line.
If the inequality sign is (≤ or ≥), then the line drawn is an unbroken one.
For this question, we can see that the lin is a broken line, so, the inequality sign will either be a < or >.
The shaded region now depends on whether the inequality sign is facing y or not.
If the inequality sign is facing y, it means numbers above the line plotted are the wanted region and the upper part of the graph is shaded.
If the inequality sign is not facing y, it means numbers below the line plotted are the wanted region and the lower part of the graph is shaded.
For this question, we can see that the lower part of the line is shaded, so, that means the inequality sign is not facing y.
So, the inequality equation represented by the graph is
y < 3x + 2
Hope this Helps!!!
rick is preparing a roast beef for his family.the roast beef weighs 2 3/4 pounds. if he wants to make each serving to be 1/2 pounds of meat how many servings can he make
To find the number of roast beef servings that Rick can make, we proceed as follows:
Step 1: Divide the total weight of the roast beef by the amount of weight of meat per serving, as follows:
[tex]\begin{gathered} \text{Total weight of roast beef =}2\frac{3}{4}\text{ pounds=}\frac{11}{4}\text{ pounds} \\ \text{amount of weight of meat per serving = }\frac{1}{2}\text{ pounds} \\ \text{Therefore:} \\ \text{Number }of\text{ servings =}\frac{T\text{otal weight of roast beef}}{A\text{mount of weight of meat per serving}} \\ \Rightarrow\text{ Number }of\text{ servings =}\frac{\frac{11}{4}}{\frac{1}{2}} \\ \Rightarrow\text{Number }of\text{ servings =}\frac{11}{4}\times\frac{2}{1}=\frac{22}{4}=\frac{11}{2}=5.5\text{ } \end{gathered}[/tex]Therefore, the number of roast beef servings that Rick can make is 5.5
Determine the equation of a line in point slope that passes through (5, -6) and (-1, 6)?
First, let's take a look at the point-slope form of a line:
[tex]y-y_0=m(x-x_0)[/tex]Where:
• m, is the ,slope, of the line
,• (Xo,Yo) ,is a point that belongs to the line
Now, let's calculate the slope of our line with the poins given:
[tex]\begin{gathered} m=\frac{6-(-6)}{-1-5}\rightarrow m=\frac{6+6}{-6}\rightarrow m=\frac{12}{-6} \\ \\ \rightarrow m=-2 \end{gathered}[/tex]Using this slope and point (5,-6), we'll get the equation of our line in the point-slope form.
[tex]y-y_0=m(x-x_0)\rightarrow y-(-6)=-2(x-5)\rightarrow y+6=-2(x-5)[/tex]The equation of the line is the following:
[tex]y+6=-2(x-5)[/tex]Which of the following graphs have hamiltonian circuits?
Answer:
D
Step-by-step explanation:
Please help with parts (a), (b),and (c).No need much explanation
Given the Histogram that summarizes the data obtained by Kemala:
(a) The Class Width is the length of the intervals.
In order to find the Class Width, you need to subtract the lowest value of each bar from the lowest value of the previous bar.
In this case, you get:
[tex]\begin{gathered} 5-2=3 \\ 8-5=3 \\ 11-8=3 \end{gathered}[/tex]Therefore:
[tex]Class\text{ }Width=3[/tex](b) You need to identify the number of beaches that had 10 or fewer pregnant turtles. Therefore, you need to add the corresponding number of beaches that correspond to these bars (A, B and C):
Then, you get:
[tex]3+8+4=15[/tex](c) You can identify that the interval of the last bar is from 11 to 13, and the number of beaches that corresponds to that bar is:
[tex]6[/tex]As you can see below
Hence, the answers are:
(a)
[tex]3[/tex](b)
[tex]15[/tex](c)
[tex]6[/tex]Select all of the value below the satisfy the inequality
Given:
[tex]\frac{1}{2}(x-5)+9>8[/tex][tex]\frac{1}{2}(x-5)>8-9[/tex][tex]\frac{1}{2}(x-5)>-1[/tex][tex]x-5>-2[/tex][tex]x>5-2[/tex][tex]x>3[/tex]Values satisfying the inequality are:
[tex]5\text{ , }\frac{22}{7}\text{ , }3.015[/tex]Max has 15-foot long piece of plastic pipe. He wants to cut it into four equivalent pieces to make corner flag poles for the soccer field. What should be the length of each flagpole that will be cut?
Answer:
3.75 feet
Explanation:
To know the length of each flagpole, we need to divide 15 (the total length of the piece of plastic pipe) by 4 because he wants 4 pieces. Then:
15 ÷ 4 = 3.75 feet
Then, each flagpole should have a length of 3.75 feet.
How much would $700 be worth after 8 years, if it were invested at 5%interest compounded continuously? (Use the formula below and round youranswer to the nearest cent.)
ANSWER :
D. $1044.28
EXPLANATION :
From the problem, the present value is P = $700, the interest rate is r = 5% or 0.05, and the time is t = 8 years
Using the given formula :
[tex]A(t)=Pe^{rt}[/tex]Then :
[tex]\begin{gathered} A(t)=700e^{0.05(8)} \\ A(t)=1044.28 \end{gathered}[/tex]rogers father vompares the text plan from two different companies dail up charges $5.00 for 100 text messages and ring ring charges $8 for 200 text messages
Rogers father compares the text plan from two different companies dial up charges $5.00 for 100 text messages and ring ring charges $8 for 200 text messages
Step 1
find the unit price
Company 1
price= $ 5
number of text messages=100
[tex]\begin{gathered} \text{unit price=}\frac{\text{price}}{\text{number of text messages}} \\ \text{unit price=}\frac{5}{100} \\ \text{unit price=0.05} \end{gathered}[/tex]Company 2
price= $ 8
number of text messages=200
[tex]\begin{gathered} \text{unit price=}\frac{8}{200} \\ \text{unit price=}0.04 \end{gathered}[/tex]Step 2
compare the text plan
[tex]\begin{gathered} \text{price 1 }then, the text message is cheaper in the company 2What is the constant of proportionality in the table below? Hours worked 3 6 9 12 Money Earned $45.75 $91.50 $137.25 $183.00 $ I per hour
If the "hours worked" and the "Money earned" are proportional, this means that both variables increase and decrease at the same rate. You could say that the more hours you work, the more money you make, and vice-versa.
The constant of proportionality indicates the rate of change of one of the variables with respect to the other.
Let "y" represent the money earned and "x" represent the hours worked, you can express the proportional relationship between both variables as follows:
[tex]y=kx[/tex]Where "k" represents the constant of proportionality and can be calculated by dividing the value of y by the value of x:
[tex]k=\frac{y}{x}[/tex]To determine the said value you have to choose any ordered pair of the table and do as follows:
Using the pair
Hours worked x=3
Money earned y=$45.75
[tex]\begin{gathered} k=\frac{y}{x} \\ k=\frac{45.75}{3} \\ k=15.25 \end{gathered}[/tex]The constant of proportionality is $15.25 per hour.
a rational function with at least one vertical asymptote, and a horizontal asymptote. You will describe the characteristics of your function, and give a numerical example of the function at one of the vertical asymptotes.
ANSWERS
Function:
[tex]h(x)=\frac{x+1}{(x-1)(x+3)}[/tex]Key features:
• Asymptotes: x = 1, x = -3, (vertical), and ,y = 0, (horizontal).
,• Intercepts: (0, -1/3), (-1, 0)
,• Symmetry: none
,• Example of end behavior: as x → 1⁺, y → infinity,, while, as x → 1⁻, y → -infinity
EXPLANATION
The vertical asymptotes of a rational function are given by the zeros of the denominator. For example, the function,
[tex]h(x)=\frac{x+1}{(x-1)(x+3)}[/tex]Has two vertical asymptotes: one at x = 1, and one at x = -3.
The horizontal asymptote is determined by the degrees of the numerator (n) and denominator (m):
• If n < m then the horizontal asymptote is the x-axis
,• If n = m then the horizontal asymptote is y = a/b, where a and b are the leading coefficients of the numerator and denominator, respectively.
,• If n > m then there is no horizontal asymptote
In the given example, the degree of the numerator is 1, while the degree of the denominator is 2. Thus, function h(x) has a horizontal asymptote that is the x-axis.
Now, we have to find the key features for this function:
• y-intercept:, occurs when x = 0
[tex]h(0)=\frac{0+1}{(0-1)(0+3)}=\frac{1}{-3}=-\frac{1}{3}[/tex]Hence, the y-intercept is (0, -1/3)
• x-intercepts:, the x-intercepts are the x-intercepts of the numerator: ,(-1, 0),.
,• The ,asymptotes, are the ones mentioned above: ,x = 1, x = -3, (vertical), and ,y = 0, (horizontal).
,• The ,symmetry, is determined as follows:
[tex]\begin{gathered} Even\text{ }functions:f(-x)=f(x) \\ Odd\text{ }functions:f(-x)=-f(x) \end{gathered}[/tex]If we replace x with -x in function h(x), we will find that the result is neither h(x) nor -h(x) and, therefore this function is neither even nor odd.
Finally, an example of the end behavior of this function around the asymptote x = 1 is that as x → 1⁺, y → infinity, while as x → 1⁻¹, y → -infinity.
If we take values of x greater than x = 1 - so we will approach 1 from the right, we will get values of the function that show an increasing behavior. Let's find h(x) for x = 4, x = 3, and x = 2,
[tex]\begin{gathered} h(4)=\frac{4+1}{(4-1)(4+3)}=\frac{5}{3\cdot7}=\frac{5}{21} \\ \\ h(3)=\frac{3+1}{(3-1)(3+3)}=\frac{4}{2\times6}=\frac{4}{12}=\frac{1}{3} \\ \\ h(2)=\frac{2+1}{(2-1)(2+3)}=\frac{3}{1\times5}=\frac{3}{5} \end{gathered}[/tex]And we will find the opposite behavior for values that are less than 1 - but greater than -1 because there the function has a zero and its behavior could change,
[tex]\begin{gathered} h(0)=\frac{0+1}{(0-1)(0+3)}=\frac{1}{-1\times3}=-\frac{1}{3} \\ \\ h(\frac{1}{2})=\frac{\frac{1}{2}+1}{(\frac{1}{2}-1)(\frac{1}{2}+3)}=\frac{\frac{3}{2}}{-\frac{1}{2}\times\frac{7}{2}}=\frac{\frac{3}{2}}{-\frac{7}{4}}=-\frac{3\cdot4}{2\cdot7}=-\frac{6}{7} \end{gathered}[/tex]The graph of the function and its key features is,
I need help with this question... the correct answer choice
The given a parallelogram with 4 coordnates in the corner.
The transformation that carries the parallegoram below itself is ,
the rotation of 180 counterclockwise about the origin.
A student usually saves $25 a month. He would like to reach a goal of saving $400 in 12 months. The student writes the equation 400 = 12(×+ 25) to represent this situation. Solve the equation for x.Show your workWrite your answer as a sentence that describes what the variable x represents
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
$25 / month = monthly savings
$400 = goal
12 months = time
400 = 12 * (x + 25 ) ====> equation
Step 02:
400 = 12 (x + 25)
400 = 12 x + 12(25)
400 = 12 x + 300
400 - 300 = 12 x
100 / 12 = x
8.33 = x
x = $8.33
The answer is:
The variable x represents the amount of additional money the student must save each month to reach the goal.
x = $8.33
Divide.
-10/25 8/10
What is the quotient?
Enter your answer as a simplified fraction in the box.
Answer:
-10/25÷8/10
-10/25×10/8
-100/25(8)
-100/200
-1/2
Hope this is right!!
Answer:
-1/2
Step-by-step explanation:
change the sign from divide to multiply: -10/25 X 8/10
flip the second fraction: -10/25 X 10/8
simplify the expression: -10 divide 5/ 25 divide 5 x 10 divide 2/ 8 divide 2
cancel out greatest factor: -2/5 x 5/4
simplify: - 2 /4
answer: - 1/2
help me on this math question! please
Answer:
X: -2, -1, 0, 1, 2
Y: -3, -1, 1, 3, 5
Step-by-step explanation:
A problem solver site says the table will look like this
two gongs strike at intervals of 90 and 60 minutes respectively.At what time will they strike together again if they start simultaneously at 12 noon
Both the gongs will strike together at 3 pm.
Given,
Two gongs strike at intervals 90 and 60 minutes respectively.
Use LCM to find at what time they will strike together
Using prime factorization:
LCM of (60,90)=[tex]2^2*3^2*5=4*9*5=180[/tex]
They will strike together after 180 minutes i.e. 3 hours
Hence, if they start simultaneously at 12 noon then they will strike together again at 3 pm
To learn more about LCM refer here
https://brainly.in/question/332006
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A water tower tank in the shape of a right circular cylinder is44 meters tall and has a diameter of26 meters. What is the volume of the tank? UseT = 3.14 and round to the nearest hundredth, if necessary.
We have that the volume of a cylinder is given by the following equation:
[tex]V=\pi\cdot r^2\cdot h[/tex]h is tall and r the radius, the radius is:
[tex]\begin{gathered} r=\frac{d}{2}=\frac{26}{2}=13 \\ \end{gathered}[/tex]replacing:
[tex]\begin{gathered} V=3.14\cdot(13)^2\cdot44 \\ V=23349.04 \end{gathered}[/tex]The volumen of the cylinder is 23349.04 cubic meters
Triangles ACD and BCD are isosceles. Angle DBC has a measure of 84 degrees and angleBDA has a measure of 24 degrees. Find the measure of angle BAC.
The Solution.
The reflex angle DBC can be calculated as below:
[tex]\angle DBC=360-84=276^o\text{ ( angle at a point)}[/tex][tex]So,\text{ }\angle DBA=\angle CBA=\frac{276}{2}=138^o[/tex]Note that: angle BDA = angle BCA = 24 degrees
Thus, considering triangle CBA (which is similar to triangle DBA), we can find angle BAC.
[tex]\angle BAC+138+24=180\text{ (sum of angles in a triangle)}[/tex][tex]\begin{gathered} \angle BAC=180-(138+24) \\ \text{ =180-162} \\ \text{ =18 }^o \end{gathered}[/tex]Therefore, the correct answer is 18 degrees.
I am trying to find the slope-intercept form of the following equation:Find the equation of a line through (7, -3) that is perpendicular to the line y = -x/3 - 8
Given:
The equation of line is,
[tex]y=-\frac{x}{3}-8[/tex]As given that the required line is perpendicular to the above line.
It means the slope of required line will be negative reciprocal of above line.
[tex]\begin{gathered} y=-\frac{x}{3}-8 \\ \text{Compare it with y=mx+b} \\ \Rightarrow m=-\frac{1}{3} \end{gathered}[/tex]The slope of the required line will be,
[tex]m_1=-\frac{1}{m}=-\frac{1}{-\frac{1}{3}}=3[/tex]Now, given that the required line passing through point (7,-3) .
[tex]\begin{gathered} y=m_1x+b \\ (x,y)=(7,-3) \\ -3=3(7)+b \\ b=-24 \end{gathered}[/tex]The slope-intercept form is,
[tex]\begin{gathered} y=m_1x+b \\ y=3x-24 \end{gathered}[/tex]Which rule describes the X – coordinates in this translation
Translation of function is :
[tex]x\rightarrow x-6[/tex]At any point for x is translat for B is x=2 then :
[tex]\begin{gathered} x^{\prime}=x-6 \\ x^{\prime}=2-6 \\ x^{\prime}=-4 \end{gathered}[/tex]For point x=4
[tex]\begin{gathered} x^{\prime}=x-6 \\ x^{\prime}=4-6 \\ x^{\prime}=-2 \end{gathered}[/tex]So x - coordinates in the translation:
[tex]=x-6[/tex]
which of the fillowing statements must be true based on the diagram below?
Answer:
HI is a perpendicular bisector
H is the vertex of a right angle
H is the midpoint of a segment in the diagram
Explanation:
Taking into account the diagram, we can say that the segments GH and HF have the same length. Additionally, HI form an angle of 90° with segment GF.
So, the true statements are:
HI is a perpendicular bisector because it forms a 90° angle and divides the segment GF into two equal segments.
H is the vertex of a right angle because angle FHI is right ( measures 90°)
H is the midpoint of a segment in the diagram because point H divides segment GF into two equal parts.
Therefore, the answers are:
HI is a perpendicular bisector
H is the vertex of a right angle
H is the midpoint of a segment in the diagram
7.) A jug of egg nog sells for $5.12One jug holds(128 punces. What is the unit priceper ounce?
Answer:
The unit price per ounce is;
[tex]\text{\$0.04 per ounce}[/tex]Explanation:
Given that A jug of egg nog sells for $5.12 and One jug holds 128 ounces.
We can derive the unit price per ounce by dividing the price by the number of ounces;
[tex]\begin{gathered} r=\frac{\text{ \$5.12}}{128\text{ ounces}} \\ r=\text{ \$0.04 per ounce} \end{gathered}[/tex]Therefore, the unit price per ounce is;
[tex]\text{\$0.04 per ounce}[/tex]A. Translate the verbal phrases into algebraic expressions.3. The square of the quotient of 54 and j
ANSWER
(54/j)²
EXPLANATION
We have to translate this verbal phrase into an algebraic expression. An algebraic expression is a combination of variables, numbers, and arithmetic operations. For example, the expression (x² + 2) is an algebraic expression.
In this phrase, we have "the square of ...", so we will have an expression in the form (...)².
Then, the square is of a quotient, between 54 and j, where 54 is the numerator and j is the denominator.
Hence, the algebraic expression is (54/j)².
A line passes through the point (3,-8) and has a slope of -4 . Write an equation in slope-intercept form for this line.
The slope-intercept form of the line which passes through the point (3,-8) and with a slope of -4 is y = -4x + 4
We know that the equation of a line passing through a given point is as follows:
(y - y1) = m (x - x1) ….. (i)
Here, (x1, y1) ⇒ coordinates of the point
m ⇒ slope of the line
In the given question,
y1 = -8
x1 = 3
m = -4
Putting these values in equation (i),
(y - (-8)) = (-4) (x-3)
(y + 8) = -4x + 12
On rearranging, we get
y = -4x + 12 - 8
y = -4x + 4
Therefore, the slope-intercept form of the line which passes through the point (3,-8) and with a slope of -4 is y = -4x + 4.
Read more about slope intercepts:
brainly.com/question/13959234
Quadrilateral QRST is dilated and translated to form similar figure Q'R'S'T'. What is the scale factor for the dilation?
We can find the factor of dilation by finding the ratio between two correspondent sides of the quadrilaterals.
Consider Q'R' and QR.
[tex]\begin{gathered} QR=6 \\ Q^{\prime}R^{\prime}=2 \\ \Rightarrow\frac{Q^{\prime}R^{\prime}}{QR}=\frac{2}{6}=\frac{1}{3} \end{gathered}[/tex]Therefore, the scale factor for the dilation is equal to 1/3
Answer: 1/3
Step-by-step explanation: just did it on edge
Find the perimeter and area of the figure, rounding to the nearest tent. Use 3.14 for π 7ft 25 ft 4 ft
Answer:
89.12 ft
Explanation:
The perimeter of the figure is the sum of all the sides. So, we need to find the length of the quarter of the circles. This length can be calculated as:
[tex]\frac{2\cdot\pi\cdot r}{4}=\frac{2\cdot3.14\cdot4ft}{4}=6.28\text{ ft}[/tex]Where r is the radius of the circle.
Then, the perimeter can be calculated as:
Perimeter = 2(7 ft) + 2(25 ft) + 4(6.28 ft)
Perimeter = 14 ft + 50 ft + 25.12 ft
Perimeter = 89.12 ft
Because there are 2 segments of 7 ft, 2 of 25 ft, and 4 corners of 6.28 ft
Therefore, the answer is 89.12 ft
find the perimeter of the following folded then be sorted and the crew correct units in your answer
Solution
Given a triangle of the followingdimensions
[tex]19in,17in,14in[/tex]To find the perimeter, P, of a triangle, the formula is
[tex]\begin{gathered} P=a+b+c \\ \text{Where a, b and c are the side lengths} \end{gathered}[/tex]Then,
[tex]\begin{gathered} a=19in \\ b=17in \\ c=14in \end{gathered}[/tex]Substitute the values to find P.
[tex]\begin{gathered} P=a+b+c \\ P=19+17+14=50in_{} \\ P=50in \end{gathered}[/tex]Hence, the perimeter, P, is 50 inches
what is 8 7/8+1/2 and what is 45.35 + 40 7/10
8 7/8+1/2
1) We need to turn that Mixed number into an improper fraction, by keeping the denominator and multiplying it by the whole number, and then adding to the numerator of that Mixed Number:
[tex]8\frac{7}{8}=\frac{8\cdot8+7}{8}=\frac{71}{8}[/tex]2) Adding then:
[tex]\frac{71}{8}+\frac{1}{2}=\frac{8\colon8\times71+8\colon2\times1}{8}=\frac{71+4}{8}=\frac{75}{8}[/tex]Turning back to Mixed Number:
Dividing 75 by 8 and placing the quotient as the whole number, the divisor as the denominator, and the remainder as the numerator we have the mixed number back.
2)45.35 + 40 7/10
Rewriting 45.35 as a fraction:
[tex]\begin{gathered} 45.35\text{ =}\frac{4535}{100} \\ 40\frac{7}{10}+\frac{4535}{100} \\ \frac{407}{10}+\frac{4535}{100} \\ \frac{4070+4535}{100} \\ \frac{8605}{100} \\ \frac{1721}{20} \end{gathered}[/tex]Note that we've rewritten as fractions, and then turned them into improper ones, added them, and then simplified.
3) Hence, the answer is
[tex]\begin{gathered} a)9\frac{3}{8}\text{ or }\frac{75}{8} \\ b)\text{ }\frac{1721}{20} \end{gathered}[/tex]