Find the surface area of a sphere with a radius of 1 cm to the nearest tenth. (Do NOTtypeinany units in your answer.)

Answers

Answer 1

The area of the sphere is 12.6

Here, we want to find the area of the sphere given the radius

Mathematically, we can calculate the area of the sphere using the formula below;

[tex]\begin{gathered} A\text{ = 4}\times\pi\times r^2 \\ r\text{ = 1 cm} \\ \pi\text{ = 3.142} \\ \text{Area of sphere = 4}\times3.142\times1^2=12.6cm^2 \end{gathered}[/tex]


Related Questions

suppose s and t are mutually exclusive events. find p (s or t) if p(s)=29% and p(t)=49%

Answers

Given:

P(s) = 29%

P(t) = 49%

For us to be able to determine P(S or T), we will be using the following formula:

[tex]\text{ P\lparen S or T\rparen = P\lparen S\rparen + P\lparen T\rparen}[/tex]

We get,

[tex]\text{ P\lparen S or T\rparen = 29\% + 49\% = 78\%}[/tex]

Therefore, the answer is CHOICE A: 78%

PO Triangle ABC is similar to triangular DEF. What is the value of x?

Answers

If triangle ABC is similar to DEF then the ratio between the sides will be a constant so we can get the expression:

[tex]\frac{15}{30}=\frac{x}{36}[/tex]

and we solve for x so:

[tex]\begin{gathered} x=\frac{36\cdot15}{30} \\ x=18 \end{gathered}[/tex]

find the first five terms of the recursive sequence. aₙ = -6aₙ₋₁ where a₁ = 45

Answers

The first terms is

[tex]undefined[/tex]

Substitute 2, 3, 4, and 5 for n in the equation to find first four next terms.

Which of the following is equal to ? 1/5^-2

Answers

25

1) Let's evaluate this expression making use of one exponent property:

[tex](\frac{1}{5})^{-2}=(\frac{5}{1})^2=(5)^2=25[/tex]

2) Note that negative exponents reciprocate the base.

3) Hence, the answer is 25

fill in the table using the function rule y=3x+5

Answers

Fill in the table using the function rule y= 3x + 5​

________________________________________

Replace each value of x in the expression

____________________________________

x= -4

y = 3* (-4)+5​

= -12 +5

= -7

_______________

x= -2

y = 3* (-2)+5​

= -6 +5

= -1

_____________

x= 0

y = 3* (0)+5​

= 0 +5

= 5

_____________

x= 2

y = 3* (2)+5​

= 6 +5

= 11

______________________________

Answer

_________________________

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Dave started at the black dot and traveled the distance shown on the map on his bike. The length of the section in red is not known.

About how far did Dave travel on his bike?

Answers

Answer: 9,00

Step-by-step explanation:

I am right.

Answer:

1,402

Step-by-step explanation

the red line is further than the 1,396

Evaluate the determinant.7 3 28 2 76 8 5A) 212B) -464© -212D860

Answers

| 7 3 2|

8 2 7

6 8 5

7(10 - 56) - 3(40 - 42) + 2(64 - 12)

7(-46) - 3(-2) + 2( 52)

-322 + 6 + 104

= -212

Devin owes $26,000 in students loans for college. The interest rate is 8.75% and the loan will be paid off over 15 years. How much will Devin pay altogether?$60,125$72,123$3,412,500$8,125

Answers

Answer:

$60,125

Explanation:

We'll use the below formula to determine how much Devin will pay altogether;

[tex]A=P(1+rt)[/tex]

where A = final amount = ?

P = principal amount = $2600

r = interest rate in decimal = 8.75/100 = 0.0875

t = time in years = 15 years

Substituting the given values into our formula and solving for A, we'll have;

[tex]\begin{gathered} A=26000(1+0.0875\times15) \\ =26000(2.3125) \\ =60,125 \end{gathered}[/tex]

Therefore, Devin will pay $60,125 altogether.

There are a total of 50 questions worth 130 points on Chenille's history exam. Someof the questions are worth five points each, and the other questions are worth twopoints each. Which of the following systems of equations could be used todetermine F, the correct number of five point questions, and t, the correct numberof two point questions answered correctly?

Answers

Since F represents the number of five point questions and t represents the number of two point questions, and the total amount of questions is 50, then:

[tex]F+t=50[/tex]

F correct answers would give us 5F points, and t correct answers would give us 2t points, for a total of 130 points. Then:

[tex]undefined[/tex]

Identify the units you would expect for the given quantity.The price of a bottle of French perfume, found by multiplyingthe unit price of the perfume in euros per milliliter by thevolume of the bottle in milliliters.

Answers

Given:

The price of a bottle of French perfume, found by multiplying

the unit price of the perfume in euros per milliliter by the volume of the bottle in milliliters.

the unit of the unit price is: euros per milliliter

And the unit of the volume is: milliliters

By multiplying the two units: the unit of the result will be euros

If we chose a theater and movie to attend at random, what probability would we have of seeing anything other than a romantic or sci-fi movie ?

Answers

we have that

The probability of seeing a romantic or sci-fi movie is

P=0.203+0.12=0.323

therefore

the probability of seeing anything other than a romantic or sci-fi movie is

P=1-0.323

P=0.677

the answer is option B

What are the coordinates of point w? 5 Z 3 2 Y 3 0 2 2. 4 -1 -2 W -3 -5 Х

Answers

the point W is positioned 3 units to the right (the x-coordinate is 3) and 2 units down (the y-coordinate is -2), thus the coordinates of W are (3,-2)

The vertices of ABCDE are A(-6,0), B(-3,0), C(0, -3), D(-3,-6), and E(-6, -3). Find the vertices of the image after a translation using the rule (x,y) - (x + 9, y-6) and a dilation with a scale factor of 4s centered at the origin.

Answers

Vertices of new image: A' = (12, -24)

B' = (24, -24)

C' = (36, -36)

D' = (24, -48)

E = (12, -36)

Explanation:

A(-6,0), B(-3,0), C(0, -3), D(-3,-6), and E(-6, -3)

A translation of (x + 9, y-6)

A becomes A'

A' = (-6 + 9, 0 - 6) = (3, -6)

B(-3,0)

B becomes B'

B' = (-3+9, 0 - 6) = B' (6, -6)

C(0, -3)

C becomes C'

C' = (0+9, -3-6) = C' (9, -9)

D(-3,-6)

D becomes D'

D' = (-3+9, -6-6) = (6, -12)

E(-6, -3)

E becomes E'

E' = (-6+9, -3-6) = (3, -9)

A dilation with scale factor of 4, we multiply the cooordinates of the alphabeths with prime with 4.

Vertices of new image:

A' = 4(3, -6) = (12, -24)

B' = 4(6, -6) = (24, -24)

C' = 4(9, -9) = (36, -36)

D' = 4(6, -12) = (24, -48)

E = 4(3, -9) = (12, -36)

Express the following as an algebraic function of x.sin(sin-'(x) – cos-'(x))

Answers

Hello there. To solve this question, we'll have to remember some properties about inverse trigonometric functions.

Given the expression:

[tex]\sin (\sin ^{-1}(x)-\cos ^{-1}(x))[/tex]

We want to express it as an algebraic function of x.

For this, imagine the following triangle:

Now, we find the missing leg of the triangle applying Pythagoras theorem:

[tex]\begin{gathered} 1^2=x^2+?^2 \\ 1-x^2=?^2 \\ ?^{}=\sqrt[]{1-x^2} \end{gathered}[/tex]

Now, finding the sine and cosine of the angles alpha and beta, we get:

First, remember the sine of an angle is equal to the ratio between the opposite side to the angle and the hypotenuse of the triangle. The cosine of the same angle is equal to the ratio between the adjacent side to the angle and the hypotenuse of the triangle.

Therefore, we have:

[tex]\begin{gathered} \sin (\alpha)=\frac{x}{1}=x \\ \cos (\beta)=\frac{x}{1}=x \\ \sin (\beta)=\frac{\sqrt[]{1-x^2}}{1}=\sqrt[]{1-x^2} \\ \cos (\alpha)=\frac{\sqrt[]{1-x^2}}{1}=\sqrt[]{1-x^2} \end{gathered}[/tex]

This means that:

[tex]\begin{gathered} \alpha=\sin ^{-1}(x) \\ \beta=\cos ^{-1}(x) \end{gathered}[/tex]

Now, the expression we had earlier turns into:

[tex]\sin (\alpha-\beta)[/tex]

For this, we'll use the angle sum formula:

[tex]\sin (u-v)=\sin (u)\cos (v)-\sin (v)\cos (u)[/tex]

Which gives us:

[tex]\sin (\alpha)\cos (\beta)-\sin (\beta)\cos (\alpha)_{}[/tex]

Plugging the results we got earlier, this is simply:

[tex]x\cdot x-\sqrt[]{1-x^2}\cdot\sqrt[]{1-x^2}[/tex]

As x > 0, because we're using it as a triangle side (but it could be negative considering inverse sine and cosine as functions), we get:

[tex]\begin{gathered} x^2-(1-x^2) \\ x^2-1+x^2 \\ 2x^2-1 \end{gathered}[/tex]

You bought a magazine for $7 and some notepads for $5 each. You spend a total of $27 how many notepads did you buy.

Answers

From the information available, some magazines (m) and some notepads (n) were bought.

If you bought a magazine for $7, then mathematically that would be;

[tex]\begin{gathered} 1\times m=7 \\ m=7 \end{gathered}[/tex]

Also, if you bought some notepads for $5 each, that would be expressed as;

[tex]5\times n=5n[/tex]

This represents 5 dollars times every given number of notepads, hence we would have;

[tex]\begin{gathered} m+5n=27 \\ \end{gathered}[/tex]

Note that one magazine was bought which is why we have m = 7. We shall now substitute for thw value of m;

[tex]\begin{gathered} m+5n=27 \\ 7+5n=27 \\ \text{Subtract 7 from both sides;} \\ 7-7+5n=27-7 \\ 5n=20 \\ \text{Divide both sides by 5;} \\ \frac{5n}{5}=\frac{20}{5} \\ n=4 \end{gathered}[/tex]

The value of n = 4

ANSWER:

This means you bought 4 notepads

Type the correct answer in the box. Use numbers instead of words.
The number 392,000 is divided by 10.
What is the value of the digit 2 in the quotient?

Answers

The value of 2 in the quotient is 200.

What is division?

One of the four fundamental operations of arithmetic, or how to mix numbers to create new ones, is division. Addition, subtraction, and multiplication are the other operations.

The opposite of multiplication is division. When you multiply three groups of four to produce twelve, you get four in each group when you split twelve into three equal groups.

Let, the number 392,000 is divided by 10.

That means, [tex]\frac{392000}{10}[/tex]

Here, 392000 is the numerator and 10 is the base.

Simplifying the fraction, we get 39200.

39200 is the quotient.

Here 2 is on the hundredth place.

Therefore, the value of 2 in the quotient is 200.

To know more about the division, click on the link

https://brainly.com/question/25289437

#SPJ1

6 At a 33-foot depth underwater, the pressure is 29.55 pounds per square inch (psi). At a depth of 66 feet, the pressure reaches 44.4 psi. At what rate is the pressure increasing? ur answer on ouatlon for the

Answers

To solve the exercise you can apply the following formula:

[tex]rate=\frac{\text{difference in pressure}}{\text{difference in depth}}[/tex]

In this case, based on the information given in the exercise, you can identify that:

[tex]\begin{gathered} \text{difference in pressure= (44.4.}-29.55)psi=14.85\text{ psi} \\ \text{difference in dept}=(66-33)ft=33\text{ ft} \end{gathered}[/tex]

Substituting values, you get:

[tex]rate=\frac{14.85\text{ ps i}}{33\text{ ft}}=0.45\text{ }\frac{ps\text{ i}}{ft}[/tex]

Therefore, The pressure is increasing at 0.45 psi per foot.

MAH ~ WCF what is the value of x?picture will be sent in messages

Answers

Since both triangles are congruent, the proportion between their sides is the same, so we can write:

[tex]\frac{MA}{MH}=\frac{WC}{WF}\Longrightarrow\frac{62}{92}=\frac{15.5}{x}\Longrightarrow62x\text{ = 92 }\cdot\text{ 15.5 = }1426\Longrightarrow\text{ x = 1426/62 =}23[/tex]

x = 23

Answer:

x = 23

What is the Y intercept of 8X plus 4Y equals -48

Answers

the given equation is,

[tex]8x+4y=-48[/tex]

Now, we will solve it further,

[tex]\begin{gathered} 8x+4y=-48 \\ 4y=-8x-48 \end{gathered}[/tex][tex]\begin{gathered} y=\frac{-8x-48}{4} \\ y=-2x-12 \end{gathered}[/tex]

Now, we will put x=0 to get the intercept of the line on the Y axis,

[tex]\begin{gathered} y=-2x-12 \\ y=-2\times0-12 \\ y=-12 \end{gathered}[/tex]

So, the Y-intercept of the given line equation is -12.

4p-9=2p+21solve the equation

Answers

The given equation is,

[tex]4p-9=2p+21[/tex]

The equation can be solved as,

[tex]\begin{gathered} 4p-9=2p+21 \\ 4p-2p=21+9 \\ 2p=30 \\ p=\frac{30}{2} \\ p=15 \end{gathered}[/tex]

Thus, the requried value of p is 15.N

Which of the following is the graph of f(x)= x² +3x-4?

Answers

Given the function

[tex]f(x)=x^2+3x-4[/tex]

To determine which graph corresponds to this function you have to determine the coordinates of the vertex and the roots of the function.

Vertex

To determine the coordinates of the vertex you have to calculate the x-coordinate using the formula:

[tex]x=-\frac{b}{2a}[/tex]

a is the coefficient of the quadratic term

b is the coefficient of the x-term

The term of the quadratic term, in this case, is a=1 and the term of the x-term is b=3

[tex]\begin{gathered} x=-\frac{3}{2\cdot1} \\ x=-\frac{3}{2}=-1.5 \end{gathered}[/tex]

Replace the x-coordinate in the function to calculate the corresponding value of f(x):

[tex]\begin{gathered} f(x)=x^2+6x-4 \\ f(-3)=(-\frac{3}{2})^2+3\cdot(-\frac{3}{2})-4 \\ f(-3)=\frac{9}{4}-\frac{9}{2}-4 \\ f(-3)=-\frac{25}{4}=-6.25 \end{gathered}[/tex]

The coordinates of the vertex are (-1.5,-6.25)

Roots of the function

To determine the roots of the function you have to use the quadratic formula:

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

a is the coefficient of the quadratic term

b is the coefficient of the x-term

c is the constant of the function

For a=1, b=3, and c=-4

[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-4)}}{2\cdot1} \\ x=\frac{-3\pm\sqrt[]{9+16}}{2} \\ x=\frac{-3\pm\sqrt[]{25}}{2} \\ x=\frac{-3\pm5}{2} \end{gathered}[/tex]

Solve the addition and the subtraction separately

Addition

[tex]\begin{gathered} x=\frac{-3+5}{2} \\ x=\frac{2}{2} \\ x=1 \end{gathered}[/tex]

Subtraction

[tex]\begin{gathered} x=\frac{-3-5}{2} \\ x=\frac{-8}{2} \\ x=-4 \end{gathered}[/tex]

The roots of the function are (1,0) and (-4,0)

The graph that corresponds to this function is

URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!

Answers

Answer: A 143 degrees because angle 5 is a congruent to angle one

Step-by-step explanation:

Determine the area of the base of a cone with a volume of 36 cubic inches and a height of 9 inches?

Answers

the are of a base cone, while we have the volume and the height

V= pi*r^2*(h/3)

36=pi*r^2*3

we can find out now the r, radius

r=sqrt(3*36/pi*9)=1.95

Area, A= pi*r^2=

we can look at the Volume formula

36=pi*r^2*3

and if we divide both sides by 3 we get

12=pi*r^2, which is area

A= 12

Question 4 please . Using a graphing utility (geogebra) to graph the function

Answers

Problem N 4

we have the function

[tex]f\mleft(x\mright)=x^4-3x^2+2x-1[/tex]

Interval (-2,2)

using a graphing tool

Local minimum value at (1,-1)

Local maximum value at (0.37,-0.65)

Increasing function

Intervals (-1.37,0.37) U (1, infinite)

Decreasing function

Intervals (-infinite, -1.37) U (0.37,1)

Evaluate: sin(30 degrees)cos(60 degrees)=(See attached image to assist with these 2 problems)

Answers

According to the figure we need to evaluate the sin(30°) and the cos(60°). Remember the trigonometric relations defined over the rectangle triangles as follows, suppose we have an angle called "alpha"

[tex]\begin{gathered} \sin(\alpha)=\frac{oc}{h}, \\ \\ cos(\alpha)=\frac{ac}{h}, \\ \\ tan(\alpha)=\frac{co}{ca} \\ \\ where\text{ }h:Hypotenuse,\text{ }ac:Adjacent\text{ }cathetus\text{ and }oc:Opposite\text{ }cathetus \end{gathered}[/tex]

Now, according to the figure, we have that for the angle of 60 degrees:

[tex]\begin{gathered} h=2x,ac=x,oc=\sqrt{3}x \\ \\ \sin(60°)=\frac{oc}{h}=\frac{\sqrt{3}x}{2x}=\frac{\sqrt{3}}{2} \\ \\ \cos(60^{\circ})=\frac{ac}{h}=\frac{x}{2x}=\frac{1}{2} \end{gathered}[/tex]

And for the angle of 30 degrees we get the following

[tex]\begin{gathered} h=2x,oc=x,ac=\sqrt{3}x \\ \\ \sin(30°)=\frac{oc}{h}=\frac{x}{2x}=\frac{1}{2}=\cos(60°) \\ \\ \cos(30^{\circ})=\frac{ac}{h}=\frac{\sqrt{3}x}{2x}=\frac{\sqrt{3}}{2}=\cos(60^{\circ}) \end{gathered}[/tex]

So, your answer is: sin(30°)=1/2=cos(60°).

In AFGHFH.GF +40, HF 3x - 20, and GH find the value of 21 20

Answers

You have the next triangle:

As the triangle has two angles that are congruent, then it is a isisceles triangle. The opposite sides of the equal angles have the same measure.

Sides FG and GH have the same measure:

[tex]FG\cong GH[/tex][tex]x+40=2x+20[/tex]

Use this equation to find the value of x:

- Substract in both sides of the equation 2x:

[tex]\begin{gathered} x-2x+40=2x-2x+20 \\ -x+40=20 \end{gathered}[/tex]

- Substract in both sides of the equation 40:

[tex]\begin{gathered} -x+40-40=20-40 \\ -x=-20 \end{gathered}[/tex]

- Multiply both sides of the equation by -1:

[tex]\begin{gathered} (-1)(-x)=(-1)(-20) \\ \\ x=20 \end{gathered}[/tex]Answer x=20

write an inequality for the graph using x for the variable.

Answers

Given:

There are given that the inequality graph.

Explanation:

In the given question, there are given number line graphs, in which the arrow has been shown in a negative direction.

Also,

There are given that the number 2 has not been included in the given graph.

So,

The inequality will be:

[tex]x<2[/tex]

Final answer:

Hence, the inequality is shown below:

[tex]x\lt2[/tex]

Write the equation of the parabola in vertex form given the vertex (–2, 3) and point (0, 1).

Answers

[tex]y=a(x-h)^2+k[/tex][tex]y=a(x-(-2))^2+3[/tex][tex]y=a(x+2)^2+3[/tex][tex]1=a(0+2)^2+3[/tex][tex]1=4a+3[/tex][tex]\frac{1-3}{4}=a[/tex][tex]-\frac{1}{2}=a[/tex]

the equation is

[tex]y=-\frac{1}{2}(x+2)^2+3[/tex]

25. Ally is making a replica of a building that is at ascale of 4 m. to 3 in.The model is 84 in tall. How tallis the building?

Answers

We know that in our model 3 inches represent 4 m, to determine how tall the building is with the knowledge that the model is 84 in we can use a rule of three:

[tex]\begin{gathered} 4\text{ m}\rightarrow3\text{ in} \\ x\rightarrow84\text{ in} \end{gathered}[/tex]

then:

[tex]x=\frac{84\cdot4}{3}=112[/tex]

Therefore, the building is 112 meters tall.

Convert 15 gal to quarts

Answers

The conversion rate for a gallon to quart is given as

[tex]1\text{ ga }\to4\text{ quart}[/tex]

This means that to get the number of quarts in a given measure in gallons, we multiply the number by 4.

The question asks us to convert 15 gallons to quarts.

This can be calculated as

[tex]\begin{gathered} 15\times4 \\ =60\text{ quarts} \end{gathered}[/tex]

Therefore,

[tex]15\text{ gal }\to60\text{ quarts}[/tex]

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The box plots represent the length of 100 randomly sampled commercial breaks for two different television stations Length of Commercial Breaks Channel 1 Channel 2 20 40 60 140 160 80 100 120 Time (seconds) Which statement about the difference in the medians of the two data sets is true? What is the correct answer to this question The options are A. 24B. 44C. 40D. 52 16. 2y+5=-1IIs 3 the solution? Suppose f(x) = x. Find the graph of f(x + 2).graph 1, 2, 3, or 4 Evaluate the expression when y= -4.y-7y+2 A Complication or TwoThe rejection letter from my Ivy League school of choice was the first major obstacle I encountered in my grand 10-year plan. It was not the last. I was 17, and at the time quite certain that nothing would derail me from my grandiose future. I planned to achieve everything my parents expected, and more. The first step was supposed to have been attending my parents alma mater, graduating with honors, and then moving on to law school without pausing to let my peersor competitorscatch me. To say thats not how it went is a gross understatement.Needing a distraction in my moment of crisis, I decided to pick up another couple of hours of volunteer service. I rode the subway to Tri-Valley Hospital with that rejection letter wrinkled in my right fist. I probably should have left it at home, but I couldnt bring myself to put it down. Id spent so many hours volunteering at Tri-Valley to build my community service rsum that the trek there felt like it was accomplished on autopilot rather than through any active involvement on my part.Alma was a new volunteer that morning, and I felt grateful for her presence, though I suppose I really didnt pay much attention to her. Mostly, I was relieved to have something to focus on, other than the big fat rejection letter swelling in my pocket. I showed Alma the volunteer wing, which was really just a room with a few lockers, a microwave, and a lot of large posters with rules and cautionary messages. She shadowed me on that shift, and together we delivered food trays, chatted with bed-ridden patients who didnt have visitors that morning, and carried out a number of fairly tedious tasks. I forgot Almas name three times and had to apologize. It was a unique enough name that I shouldnt have forgotten once, but the rejection letter was burning a hole in my pocket and apparently in my mind.At lunch, Alma sat across from me, even though by then several other regular volunteers had arrived and offered to take her out for real food rather than subjecting her to the cafeteria fare. I cant imagine how far gone I must have seemed to her, but Ill never forget what she said as I prodded the chocolate mass parading as cake on my tray. You must really love what you do here, she said. I can tell you care about this place and the patients we visited.Her words dug into me, primarily because I had never once stopped to consider whether I enjoyed my time at the hospital. Hundreds of food trays served, hundreds of patients visited, and still somehow the whole experience amounted to nothing more than a checkmark on the extensive list of what I needed to accomplish to achieve my goals. I did think about it then, as I finished my dessert. She wasnt incorrect. A lot of people hate hospitalsthe lights, the sterile smell, the undercurrent of urgency, illness, and tragedy. But I didnt hate it at all. The fact that I was there that day proved more than anything else that I saw it as a comfortable place.Alma and I ended up attending the same university. It wasnt Ivy League, and I wasnt pre-law. Freshman year, I decided to complete my undergraduate degree on an accelerated three-year plan. 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