find the shaded area to the nearest tenth, use 3.14 for pi. help pls due tmrw

Find The Shaded Area To The Nearest Tenth, Use 3.14 For Pi. Help Pls Due Tmrw

Answers

Answer 1

The area of the shaded region inside the circle is 49.04cm².

What is a circle?

All points in a plane that are at a specific distance from a specific point, the center, form a circle.

In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.

So, the shaded area is:

We can easily tell that the diameter of the circle here is 12cm.

So, the radius will be 6cm.

Now, calculate the area of a circle as follows:

A = πr²

A = 3.14(6)²

A = 3.14(36)

A = 113.04cm²

Now, the area of the smaller square:

A = s²

A = 2²

A = 64²

Area of the shaded region:

113.04 - 64

49.04 cm²

Therefore, the area of the shaded region inside the circle is 49.04cm².

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Related Questions

Solve the system of equations:3x+y=6 2x+3y=11

Answers

Answer:

(1,3)

Explanation:

Given the system of equations:

[tex]f(x)=\begin{cases}3x+y=6 \\ 2x+3y=11\end{cases}[/tex]

To solve the system using the elimination method, multiply the first equation by 3.

[tex]\begin{gathered} f(x)=\begin{cases}9x+3y=18 \\ 2x+3y=11\end{cases} \\ \text{Subtract} \\ 7x=7 \\ \text{Divide both sides by 7} \\ \frac{7x}{7}=\frac{7}{7} \\ x=1 \end{gathered}[/tex]

Next, substitute x=1 into any of the equations to solve for y.

[tex]\begin{gathered} 3x+y=6 \\ 3(1)+y=6 \\ y=6-3 \\ y=3 \end{gathered}[/tex]

The solution to the system of equations is (x,y)=(1, 3).

can u help solve problem

Answers

To multiply the matixes, we'll look at their elements

[tex]A=\begin{bmatrix}{A_1} & {A_2} & {A_3} \\ {} & {} & {} \\ {} & {} & \end{bmatrix},\text{ B=}\begin{bmatrix}{B_1} & {} & {} \\ {B_2} & {} & \\ {B_3} & {} & {}\end{bmatrix}[/tex]

In order to get AB, we simply use the following formula

[tex]AB=A_1\cdot B_1+A_2\cdot B_2+A_3\cdot B_3[/tex]

In this case

[tex]AB=3\cdot1+4\cdot2+5\cdot3+6\cdot4=3+8+15+24=50[/tex]

Since both matrixes have 4 elements. Thus

[tex]AB=50[/tex]

use the point slope formula in the given points to choose the correct linear equation in slope intercept formfor ( 4,-3) and (-2,5)

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The point-slope formula is

[tex]y-y_1=m(x-x_1)[/tex]

where m is the slope of a line passing through the point (x₁, y₁).

Also, the slope m of a line passing through points (x₁, y₁) and (x₂, y₂) is

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

In this problem, the line passes through points (4, -3) and (-2, 5). Thus, we have:

x₁ = 4

y₁ = -3

x₂ = -2

y₂ = 5

Then, the slope is

[tex]m=\frac{5-(-3)}{-2-4}=\frac{5+3}{-6}=\frac{8}{-6}=-\frac{4}{3}[/tex]

And the equation in point-slope form is

[tex]y-(-3)=-\frac{4}{3}(x-4)[/tex]

Now, we need to rewrite this equation in slope-intercept form. The slope-intercept equation of a line with slope m and y-intercept b is

[tex]y=mx+b[/tex]

Thus, we need to isolate y on the left side of the equation to obtain the slope-intercept form, as follows:

[tex]\begin{gathered} y+3=-\frac{4}{3}x-\frac{4}{3}(-4)\text{ using the distributive property of multiplication over addition} \\ \\ y+3=-\frac{4}{3}x+\frac{16}{3} \\ \\ y+3-3=-\frac{4}{3}x+\frac{16}{3}-3 \\ \\ y=-\frac{4}{3}x+\frac{16}{3}-\frac{9}{3} \\ \\ y=-\frac{4}{3}x+\frac{7}{3} \end{gathered}[/tex]

Therefore, the slope-intercept form of that linear equation is

[tex]y=-\frac{4}{3}x+\frac{7}{3}[/tex]

find an equation of the tangent line to the graph of the function at the given point,use a graphing utility to graph the function and its tangent line at the point, anduse the tangent feature of a graphing utility to confirm your results.

Answers

The equation of the tangent line may be identified using the first derivative of the function which gives us its slope.

[tex]\begin{gathered} y=\cos3x \\ \\ y^{\prime}=-3\sin3x \\ \\ m=-3\sin3x \\ \\ m=-3\sin3(\frac{\pi}{4}) \\ \\ m=-3(\frac{\sqrt{2}}{2}) \\ \\ m=-\frac{3\sqrt{2}}{2} \end{gathered}[/tex]

The tangent line passes through (/4, -√2/2) so we can solve for the y-intercept, b.

[tex]\begin{gathered} y=mx+b \\ \\ -\frac{\sqrt{2}}{2}=-\frac{3\sqrt{2}}{2}(\frac{\pi}{4})+b \\ \\ -\frac{\sqrt{2}}{2}=-\frac{3\pi\sqrt{2}}{8}+b \\ \\ b=-\frac{\sqrt{2}}{2}+\frac{3\pi\sqrt{2}}{8} \\ \\ b=\frac{-4\sqrt{2}}{8}+\frac{3\pi\sqrt{2}}{8} \\ \\ b=\frac{(3\pi-4)\sqrt{2}}{8} \end{gathered}[/tex]

So the equation of the tangent line is:

[tex]y=-\frac{3\sqrt{2}}{2}x+\frac{(3\pi-4)\sqrt{2}}{8}[/tex]

which of the following is the solution of the system of equations below? 6x+6y=-6 5x+y=-13

Answers

First, we divide the first equation by -6

[tex]\begin{gathered} 6x+6y=-6 \\ -x-y=1 \end{gathered}[/tex]

Then, we combine this equation with the second one

[tex]\begin{gathered} 5x-x+y-y=1-13 \\ 4x=-12 \\ x=-\frac{12}{4} \\ x=-3 \end{gathered}[/tex]

Now, we use the x-value to find y

[tex]\begin{gathered} 5x+y=-13 \\ 5(-3)+y=-13 \\ -15+y=-13 \\ y=-13+15 \\ y=2 \end{gathered}[/tex]Hence, the solution to the system is (-3, 2).

Jerry bought a $78 table on sale for 20% off. The best estimate for the discount can be found using which expression? 0.2(80) 0.2170)

Answers

1) Gathering the data

$78 20% off

2) To find the final price Jerry has paid just multiply

78----20%

3) So, the expression used was 78 x (0.8) and Jerry has paid $62.4 for the table

Find the slope of each.1. (0, 4) and (2, -3)

Answers

Answer:

slope = -3.5

Explanation:

The points we have are:

[tex]\begin{gathered} (0,4) \\ (2,-3) \end{gathered}[/tex]

We have to label the coordinates as follows:

[tex]\begin{gathered} x_1=0 \\ y_1=4 \\ x_2=2 \\ y_2=-3 \end{gathered}[/tex]

And now we use the formula to calculate the slope between the points:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

We substitute the known values:

[tex]m=\frac{-3-4}{2-0}[/tex]

And solve the operations to find the slope "m" between the points:

[tex]\begin{gathered} m=\frac{-7}{2} \\ m=-3.5 \end{gathered}[/tex]

Answer: slope = -3.5

The temperature of a solution in a science experiment is -6.2°C. Jesse wants to raise the temperature so that it is positive. (a) Give an example of a number of degrees Celsius by which Jesse could raise the temperature. (b) Write a equation to represent the solution.

Answers

Hello!

First, the temperature is -6.2ºC, and Jesse wants to raise it until be positive.

(a) Give an example of a number of degrees Celsius by which Jesse could raise the temperature.

If we add 6.2ºC, we will obtain a temperature equal to 0ºC, right? So, to the temperature be positive you can choose any temperature greater than 6.2º.

For example, I'll choose 15ºC.

(b) Write an equation to represent the solution. ​

We will write the current temperature plus the temperature that we will add, then we obtain the new temperature, look:

-6.2ºC + 15ºC = 8.8ºC

Answer two questions about Equations A and B:Skill SumA. 5 = -2(x - 1)sidesB. 5 = -20 +21) How can we get Equation B from Equation A?Choose 1 answer:a) Rewrite one side (or both) by combining like terms0215b) Rewrite one side for both) using the distributive propertyc) Multiply/divide both sides by the same non-zero constantd) Multiply/divide both sides by the same variable expression Based on the previous answer, are the equations equivalent? In other words,do they have the same solution?

Answers

Rewrite one side(or both) by combining like terms

Explanation:

Equation A: 5 = -2(x - 1)

Equation B: 5 = -20 +2

To get Equation B from Equation A, we equate the right sides of both equations since equating the left side give the same answer.

Left side: 5 = 5

Right side: -2(x - 1) = -20 +2

Then we solve:

-2x + 2 = -18

-2x = -18-2

-2x = -20

x = -20/-2

x = 10

To get Equation B from Equation A, we make x = 10

Rewrite one side(or both) by combining like terms

which expression can be used to find the length of the side of the triangle represented by the vertices (5,5) and (7,-3) on the graph?

Answers

In order to determine the correct expression for the length of the side, consider that the distance in between two points (x1,y1) and (x2,y2) is given by the following formula:

d = √((x2 - x1)² + (y2 - y1)²)

if (x1,y1) = (5,5) and (x2,y2) = (7,-3) you have for d:

d = √((7 - 5)²+(5 - (-3))²)

ESFind the distance d(P. P2) between the points P, and P2-omennsP. = (-4.3)P2 = (3.2)ERE!(P, P2) =O(Simplify your answer. Type an exact answer using radicals as needed.)1 Guit2 Gunents

Answers

We have two points and we need to calculate the distance between them.

The points are P1(-4,3) and P2(3,2).

We can apply the following formula for the distance between points:

[tex]D=\sqrt{(x_2-x_1)^2}+(y_2-y_1)^2[/tex][tex]\begin{gathered} D=\sqrt{(3-(-4))^2}+(3-2)^2 \\ D=\sqrt{7^2+1^2}=\sqrt{49+1}=\sqrt{50}=\sqrt{(25\cdot2})=5\sqrt{2} \end{gathered}[/tex]

The answe is 5 times the square root of 2:

[tex]D=5\sqrt{2}[/tex]

using the graph below wich graphs shows the mapping of ABCD to A'B'C'D for a dilation with center (0,0) and a scale factor of 3

Answers

The rule for a dilation with center at (0,0) and scale factor k is:

[tex](x,y)\rightarrow(kx,ky)[/tex]

Find the transformed vertices A'. B', C' and D' using this rule:

[tex]A(-2,3)\rightarrow A^{\prime}(3\times-2,3\times3)=A^{\prime}(-6,9)[/tex]

Similarly, the coordinates of B', C' and D' wil be:

[tex]\begin{gathered} B^{\prime}(6,12) \\ C^{\prime}(6,-3) \\ D^{\prime}(-9,3) \end{gathered}[/tex]

Plot A', B', C' and D' along with A, B, C and D:

A punter kicks a football. Its height (h) in meters, t seconds after the kick is givenby the equation: h(t) = -4.912t^2 +18.24t +0.8. The height of an approaching blocker'shands is modeled by the equation: g(t) = -1.43t+4.26, using the same time. Can theblocker knock down the punt? If so, at what time does this happen?

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[tex]t=\frac{-b\pm\sqrt[]{b^2-4ac}\text{ }}{2a}[/tex][tex]t=\frac{19.67\text{ \pm}\sqrt[]{(19.67)^2-4\cdot4.9\cdot3.46}}{2\cdot4.9}[/tex][tex]t=\frac{19.67\pm17.86}{9.8}[/tex][tex]-[/tex][tex]t_1=3.82[/tex][tex]t_2=\text{ 0.1}8[/tex]

What is the distance between the points (-9, 4) and (3,-12)? A 12 units B. 16 units c. 20 units D. 28 units​

Answers

Answer:

C

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (- 9, 4 ) and (x₂, y₂ ) = (3, - 12 )

d = [tex]\sqrt{(3-(-9))^2+(-12-4)^2}[/tex]

   = [tex]\sqrt{(3+9)^2+(-16)^2}[/tex]

   = [tex]\sqrt{12^2+256}[/tex]

   = [tex]\sqrt{144+256}[/tex]

   = [tex]\sqrt{400}[/tex]

   = 20 units

 

Find the area of 11.4 and 7.4

Answers

let,

lenght (l)=11.4 , and width (b)=7.4

so,

[tex]\begin{gathered} \text{area}=l\times b \\ =11.4\times7.4 \\ =84.36 \end{gathered}[/tex]

area=84.36

I need help with this math question I already solved the first question but I don't understand the second.

Answers

We can solve this question using cross multiplication,

If the number of students who sleep 6 hours a day increases by, this means we'll have a total of 6 students who sleep 6 hours a day.

We want the ratio to be same: 15%

Then we can write:

[tex]\frac{6}{N}=\frac{15\%}{100\%}[/tex]

6 students are the 15%, then N students are the 100%

Now solve for N:

[tex]\begin{gathered} 6·100=15·N \\ \end{gathered}[/tex][tex]N=\frac{600}{15}[/tex][tex]N=40[/tex]

The answer is 40 students are expected.

This is a reasonable answer, given that if the number of students who sleep 6 hours doubles, for the rate to remain the same, the total of students must double.

How many ways can we award a 1st, 2nd, and 3rd place prize among eight contestants?

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We have:

- There are 8 choices for awarding first prize.

- Then there are 7 choices for awarding second prize.

- And there are 6 choices for awarding third prize.

Therefore, there are:

[tex]8\cdot7\cdot6=336\text{ ways}[/tex]

Answer: 336 ways

Which equation does the following grid represent? X X XX X XX X X XX X X XX X X A 0.92 - 0.19 = 0.73 OB. 0.73 +0.19 = 0.92 O C. 1.00 - 0.19 = 0.81 O D. 1.00 +0.73 = 1.73

Answers

In the Diagram,

We have a box

Total squares: 100

In Red we have= 92 squares

The blank squares= 8

"X" squares = 19

2) Then, Dividing each by 100:

0.92 red -0.19x =0.73 the amount of red squares not marked with an x

hello I'm having some difficulty on this question thank you for viewing it and helping me

Answers

The simple interest charged by the lender on Alonzo is $ 126 and the amount paid after 6 years is $ 826.

Principal amount of loan = $ 700

Time period = 6 years

Interest rate = 3 %

The simple interest is charged by the lender:

The interest will be:

SI = p × r × t / 100

Substitute the values, we get that:

SI = 700 × 3 × 6 / 100

SI = 7 × 3 × 6

SI = $ 126

The amount paid by Alonzo after 6 years will be:

Amount = $ 700 + $ 126

A = $ 826

Therefore, the simple interest charged by the lender on Alonzo is $ 126 and the amount paid after 6 years is $ 826.

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A sales person is given a choice of two salary plans. Plan 1 is weekly salary of $600 plus 2 percent commission of sales. Plan 2 is a straight commission of 10% of sales. How much in sales must he make in a week for both plans to result in the same salary?

Answers

Answer:

He must make $7,500 in sale

Step-by-step explanation:

Let's say:

s = amount make in sales per week

P1 = weekly salary of Plan 1

P2 = weekly salary of Plan 2

P1 and P2 can be expressed using the fixed amount plus the commission.

P1 = 600 + 0.02s

P2 = 0 + 0.1s

P2 = 0.1s

If both plans result in the same salary:

P1 = P2

600 + 0.02s = 0.1s

0.1s - 0.02s = 600

0.08s = 600

s = 600/0.08

s = $7,500

Alex’s paycheck was for $624.65. If Alex worked 32.5 hours, what is his rate of pay?

Answers

In order to know the rate of pay, we need to divide the value of the paycheck ($624.65) by the total hours Alex worked (32.5 hours):

$624.65/(32.5 hours) = $624.65/(32.50 hours) = $62465/(3250 hours)

Now, to solve this division, we can do as follows:

Therefore, the rate of pay is

$19.22/hour

1) 42,58, 67,55, 40, 69, 66, 51, 46, 48, 68 Minimum : Q: Q2: Q, Maximum :

Answers

EXPLANATION

Minimum

The first Quartile is the value separating the lower quarter and higher three - quarters of the data set.

The first quartile is computed by taking the median of the lower half of a sorted set.

Arranging terms in ascending order

40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69

Here, we can see that:

Minimum = 40

Maximum = 69

Q2=55 (median)

Taking the lower half of the ascending set:

Counting the number of terms in the data set:

{40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69}

{1, 2 , 3, 4, 5, 6, 7, 8, 9, 10, 11}

The number of terms in the data set is:

11

Since the number of terms is odd, take the elements below the middle one, that is, the lower 5 elements.

40, 42 , 46, 48, 51

Median of 40, 42 , 46, 48, 51:

The number of terms in the data set is 5.

Since the number of terms is odd, the median is the middle element of the sorted set.

Q1: 46

------------------------------------

Q3:

Since the number of terms is odd, take the elements above the middle one, that is, the upper 5 elements.

58, 66, 67, 68, 69

The number of terms in the data set is

5

Since the number of terms is odd, the median is the middle element of the sorted set.

Q3=67

------------------------------------------------------------------------------------

Interquartile Range:

The interquartile range is the difference of the first and third quartiles

We have that:

Q1=46

Q3=67

Computing the difference between 67 and 46:

67-46= 21

Interquartile Range=21

-------------------------------

Answers:

Minimum = 40

Q1=46

Q2=55 (median)

Q3=67

Maximum = 69

Interquartile Range=21

how to answer this system of equations using cramer's rule

Answers

Given:

Given the system of equations:

[tex]\begin{gathered} c+w+p=456 \\ c-p=80 \\ p=2w-2 \end{gathered}[/tex]

Required: Solution of the system using Cramer's rule

Explanation:

The system of equations can be rewritten as

[tex]\begin{gathered} c+p+w=456 \\ c-p+0w=80 \\ 0c+p-2w=-2 \end{gathered}[/tex]

Write down the augmented matrix.

[tex]\begin{bmatrix}{1} & {1} & {1} & {456} \\ {1} & {-1} & {0} & {80} \\ {0} & {1} & {-2} & {-2} \\ {} & {} & {} & {}\end{bmatrix}[/tex]

Calculate the main determinant.

[tex]\begin{gathered} D=\det\begin{bmatrix}{1} & {1} & {1} \\ {1} & {-1} & {0} \\ {0} & {1} & {-2}\end{bmatrix} \\ =1\left(2-0\right)-1\left(-2-1\right) \\ =2+3 \\ =5 \end{gathered}[/tex]

Substitute the c-column with RHS and find the determinant.

[tex]\begin{gathered} D_c=\det\begin{bmatrix}{456} & {1} & {1} \\ {80} & {-1} & {0} \\ {-2} & {1} & {-2}\end{bmatrix} \\ =456\left(2-0\right)-80\left(-2-1\right)-2\left(0+1\right) \\ =912+240-2=1150 \end{gathered}[/tex]

Substitute the p-column with RHS and find the determinant.

[tex]\begin{gathered} D_p=\det\begin{bmatrix}{1} & {456} & {1} \\ {1} & {80} & {0} \\ {0} & {-2} & {-2}\end{bmatrix} \\ =1(-160-0)-1(-912+2) \\ =-160+910 \\ =750 \end{gathered}[/tex]

Substitute the w-column with RHS and find the determinant.

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A clothing store is donating socks to various charities. The store gave 6 regular packs and 5 value packs to a homeless shelter, which contained a total of 163 pairs of socks. For foster children, the store donated 6 regular packs and 4 value packs, which equaled 146 pairs. How many pairs of socks are in each pack?

Answers

Let r and v be the number of socks ina regular pack and value pack, respectively. Since the store gave 6 regular packs and 5 value packs which contained 163 pair of socks, we can write

[tex]6r+5v=163[/tex]

Similarly, since the store donated 6 regular packs and 4 value pack which add 146 pair of socks, we can write

[tex]6r+4v=146[/tex]

Then, we have the following system of equations:

[tex]\begin{gathered} 6r+5v=163\ldots(a) \\ 6r+4v=146\ldots(b) \end{gathered}[/tex]

Solving by elimilation method.

By multiplying equation (b) by -1, we have an equivalent system of equations:

[tex]\begin{gathered} 6r+5v=163 \\ -6r-4v=-146 \end{gathered}[/tex]

Then, by adding both equations, we have

[tex]v=17[/tex]

Now, in order to obtain the number of socks in a regular pack, we must substitute the last result into equation (a). It yields,

[tex]6r+5(17)=163[/tex]

which gives

[tex]6r+85=163[/tex]

By subtracting 85 to both sides, we have

[tex]6r=78[/tex]

Then, r is given by

[tex]\begin{gathered} r=\frac{78}{6} \\ r=13 \end{gathered}[/tex]

Therefore, the answer is: There are 13 pairs of socks in each regular pack and 17 pairs in each value pack.

InequalitiesEvaluate. Show your work or explain how you arrived at your answer.-|-34|

Answers

The value of -|-34| is -34

-|-34|

Apply absolute rule: |-a|=a,  a>0 =-34

The absolute value (or modulus)| x |  of a real number x is its non-negative value regardless of its sign. For example, 5 has an absolute value of 5, and 5 has an absolute value of 5. A number's absolute value can be conceived of as its distance from zero along the real number line.

Absolute values for real numbers occur in a wide range of mathematical contexts. Absolute values, for example, are defined for complex numbers, quaternions, ordered rings, fields, and vector spaces. In numerous mathematical and physical contexts, the absolute value is intimately related to the concepts of magnitude, distance, and norm.

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Math help with problems Is this line linear or nonlinear

Answers

Answer:

[tex]It\text{ is linear}[/tex]

Explanation:

Here, we want to check if the given line is linear or not

From the image shown, the line connects two points on the axes

This connection is in the form of a line segment

Thus, we can confirm that the line is linear

Write the equation of the line in standard form that passes through point P(-5,7) andPerpendicular to the equation of the line y=-x+2.

Answers

The given equation is

[tex]y=-x+2[/tex]

We have to find a new line perpendicular to the given line and must pass through P(-5,7).

First, we use the definition of perpendicularity for two lines.

[tex]m_1\cdot m_2=-1[/tex]

Where one of the slopes is equal to -1 because the coefficient of x in the given equation is -1. Let's find the other slope.

[tex]\begin{gathered} m\cdot(-1)=-1 \\ m=1 \end{gathered}[/tex]

This means the new perpendicular line has a slope of 1.

Now, we use the slope we found, the point P, and the point-slope formula, to find the equation.

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-7=1(x-(-5)) \\ y-7=x+5 \\ y=x+5+7 \\ y=x+12 \end{gathered}[/tex]Therefore, the equation of the new perpendicular line is y = x + 12.

There are 130 people at a meeting. Theyeach give a Valentine's Day card toeveryone else. How many cards weregiven?

Answers

Permutations

Suppose there are only two people in the meeting. Person A gives a card to person B and vice-versa. Two cards were given.

Now we have 3 people. Person A gives two cards. Person B gives two cards. Person C gives two cards. Total = 6 cards given.

Each people gives a card to everyone else (except themselves, of course) and it's done by everyone in the meeting, thus for 130 people:

130 x 129 = 16,770 cards were given

Determine the equation of the straight line that passes through the point (-2, -4)and is perpendicular to the line y +2x=1

Answers

If the line is perpendicular to:

[tex]y=-2x+1[/tex]

the we know that the slope will be the negative reciproc of the slope so the new slope is:

[tex]m=\frac{1}{2}[/tex]

So the equation is:

[tex]y=\frac{1}{2}x+b[/tex]

So we can replace the coordinate (-2,-4) and solve for b so:

[tex]\begin{gathered} -4=\frac{1}{2}(-2)+b \\ -4+1=b \\ -3=b \end{gathered}[/tex]

So the final equation is:

[tex]y=\frac{1}{2}x-3[/tex]

Which tree is growing faster?Tree 2Tree 1 is growing 2 week 2 4 6 8 10inches every week. inches5 10 15 20 25tallHint: First calculate the unit rate for Tree 2.Enter the number that belongs in the numerator.Unit Rate[?]=inches/week

Answers

Calculating the unit rate for Tree 2 we have the following

[tex]\text{Unit Rate }=\frac{5\text{ inches}}{2\text{ week}}\text{ }=\frac{10\text{ inches}}{4\text{ week}}\text{ }=\frac{15\text{ inches}}{6\text{ week}}[/tex]

When simplified the unit rate is

[tex]\frac{5}{2}\text{ inches/week}[/tex]

This is 2.5 inches per week. Compared to Tree 1,

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