Find the prime factorization of the following number write any repeated racists using exponents
Answers
Prime factorization refers to the process of decomposing a given number into a product of prime numbers that can be repeated or not.
Let's remember that prime numbers are numbers that can only be divided by 1 or itself.v Having this in mind we have that the prime factorization of 66 is:
[tex]66=(2)(3)(11)[/tex]Related Questions
helpppppppppppppppp plssssssssss
The population of Orange County is represented by the function f(x)=87,000(0.9)x, where x is the number of years since 2010.
The population of Greene County was 78,000 in 2010, and has decreased exponentially at a rate of 8% each year.
How do the populations of these counties compare in 2015?
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In 2015, the population of Orange County was approximately Response area and the population of Greene County was approximately Response area. In 2015, Response area County was more populous.
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The population of Greene County will be more than Orange County in 2015.
What is comparison?Comparing numbers, in maths, is defined as a process or method in which one can determine whether a number is smaller, greater, or equal to another number according to their values.
Given that, The population of Orange County is represented by the function f(x) = 87,000(0.9)x, where x is the number of years since 2010.
The population of Greene County was 78,000 in 2010, and has decreased exponentially at a rate of 8% each year.
Orange County population in 2015 = 87,000(0.9)^5 = 51372
Greene County population in 2015 = 78000(1+0.08)^5 = 51408
Hence, The population of Greene County will be more than Orange County in 2015.
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If the area of a trapezoid is 46 sq. cm. and its height is 4 cm. Find the shorter base if itslonger base is 15 cm.
Answers
We are given the following information about a trapezoid.
Area = 46 sq cm
Height = 4 cm
Longer base = 15 cm
We are asked to find the shorter base of the trapezoid.
Recall that the area of a trapezoid is given by
[tex]A=\frac{a+b}{2}\cdot h[/tex]Let us substitute the given values and solve for the shorter side of the trapezoid.
[tex]\begin{gathered} 46=(\frac{a+15}{2})\cdot4 \\ 2\cdot46=(a+15)\cdot4 \\ 92=(a+15)\cdot4 \\ \frac{92}{4}=a+15 \\ 23=a+15 \\ a=23-15 \\ a=8\; cm \end{gathered}[/tex]Therefore, the shorter base of the trapezoid is 8 cm
Which of the following could be the end behavior of f(x) = -x6 + 3x4 + 8x3 – 4x2 – 6? f(x) → ∞ as x → ±∞f(x) → -∞ as x → ±∞f(x) → -∞ as x → -∞ and f(x) → ∞ as x → ∞f(x) → ∞ as x → -∞ and f(x) → -∞ as x → ∞
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The given function f is given by:
[tex]f(x)=-x^6+3x^4+8x^3-4x^2-6[/tex]Therefore, as:
[tex]x\to\infty,f(x)\to-\infty[/tex]and
[tex]\begin{gathered} \text{ as } \\ x\to-\infty,f(x)\to-\infty \end{gathered}[/tex]Therefore, the correct answer is:
f(x) → -∞ as x → ±∞
all of the Patron in part shade and rewrite (x × y)^nas a product of two single powers
Answers
we have
(2*3)^5
we know that
(2*3)^5=(2^5)(3^5)
Rewrite each term as product of two single powers
so
(2^5)(3^5)=(2^3)(2^2)(3^3)(3^2)
Part c
we have
10^2/10^0
when divide, subtract the exponents
so
10^(2-0)
10^2
another way
Any number elevated to zero is equal to 1
so
10^0=1
substitute
10^2/1=10^2
Part f
we have
(2/3)^5
we know that
(2/3)^5=2^5/3^5
Which ordered pair must be a solution in the graph of the linear inequalitybelow?(-2,2)(0, -2)
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SOLUTION:
We want to determine which ordered pair must be a solution in the graph of the linear inequality. The point picked must be in the shaded region to be a solution.
Going through the options, we see that, the only ordered pair that is a solution there is;
[tex](-5,1)[/tex]
The function [tex]f(t) = 1600(0.93) ^{10t} [/tex]represents the change in a quantity over t decades. What does the constant 0.93 reveal about the rate of change of the quantity?
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Given the function;
[tex]f(t)=1600\cdot(0.93)^{10t}[/tex]The function shows exponential decay with a rate of 0.93
So, the quantity will decrease each year with the rate of 0.93
11. The table shows the distance, y, a car can travel in feet in x seconds. Speed or Car Time, x (seconds) 5 10 Distance, y (feet) 700 1,400 2,100 2,800 3,500 15 20 25 Based on the information in the table, which equation can be used to model the relationship between x and y? A. y = 140x B.y = 5x C. y = x + 140 D. y = x + 5
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In this case, we'll have to carry out several steps to find the solution.
Step 01:
y = distance
x = time
equation = ?
Step 02:
y = k x
if y = 700ft , x = 5 seconds
700 = k * 5
700 /5 = k
140 = k
y = 140 x
The answer is:
y = 140 x
Make Sense and persevere An office manageris selecting a water delivery service. AcmeH2O charges a $15 fee and $7.50 per 5-gallonjug. Best Water charges a $24 fee and$6.00 per 5-gallon jug. How many 5-gallonjugs will the office have to buy each monthfor the cost of Best Water to be less than thatof Acme H20?
Answers
You have that Acme H2O charges 15 fee and7.50 per 5-gallon. Furthermore, Best water charges 24 fee and 6.00 per 5-gallon.
In order to find the amount of five-gallons that the office have to buy, you can write, in an akgebraic form, the previous realtions, just as follow:
24 + 6x < 15 + 7.5x
That is, cost of Best water less than cost of Acme H20. x is the amount of five-gallons
You solve the previous inequality, as follow:
24 + 6x < 15 + 7.5x subtract 6x both sides and subtract 15 both sides
24 - 15 + 6x - 6x < 15 - 15 + 7.5x - 6x simplify
9 < 1.5x divide between 1.5 both sides
9/1.5 < 1.5x/1.5 simplify
6 < x
6 < x is the same as x > 6. Hence, Office would have to buy lower than 6 five-gallons.
Enter the equation in standard form.y = 4x - 9
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The general form of the standard line is:
[tex]Ax+By=C[/tex]So, we need to change the given equation to the standard form
the given equation is;
[tex]y=4x-9[/tex]Making x and y on the left side
So,
[tex]-4x+y=-9[/tex]And can be written as:
[tex]4x-y=9[/tex]Each expression represents the total number of dots in a pattern where n represents the step Select all the expressions that represent a quadratic relationship between the step number and the total number of dots. (If you get stuck, consider sketching the first few steps of each pattern as described by the expression.) A. I2 answer B. 2n C. non answer A D. nun E. n + 2 F.n=2 A &C • A, B, C B&C D. EF
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We have the following:
We have that an option is quadratic when the same value is being multiplied twice, that is,
[tex]n\cdot n=n^2[/tex]Therefore, among the answers the only quadratic options are A and C.
Solve the system by substitution. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, enter the general solution in terms of x, where x is any real number.)x − 0.2y = 2−10x + 2y = 10(x, y) =
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Start multiplying the first equation for 10
[tex]\begin{gathered} 10(x-0.2y=2) \\ 10x-2y=20 \end{gathered}[/tex]add the resulting equation with the second equation
[tex]\begin{gathered} 10x-2y+(-10x+2y)=20+10 \\ 0=30\rightarrow false\text{ }0\ne30 \\ \end{gathered}[/tex]Answer:
There is no solution for the system
James bought a movie ticket for $4.05. Hepaid the movie ticket with quarters anddimes. If James used 18 coins in all, howmany quarters (q) and dimes (d) did he use?=q + d = 180.25q + 0.1d = 4.05+=ritorddia
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q + d = 18
0.25q + 0.1d = 4.05
We will use substitution
Solving the first equation for q
q = 18 -d
Substituting this into the second equation
.25(18-d) + .1d = 4.05
Distribute
4.5 - .25d +.1d = 4.05
Combine like terms
4.5 - .15d = 4.05
Subtract 4.5 from each side
-.15d = -.45
Divide each side by -/15
-.15d/-.15 = -.45/-.15
d = 3
We have 3 dimes
Now we can find the number of quarters
q = 18-d
q = 18-3
q = 15
We have 15 quarters
I paid $17.80 for 5 gallons of gas. using the unit rate. how much would you pay to fill all the way up if my car holds 14 gallons of gas ?
Answers
Answer: 67
Step-by-step explanation:
Stan stray kids. !!
What is the half-life of the goo in minutes? Find a formula for G(t), the amount of goo remaining at time t. How many grams of goo will remain after 68 minutes?
Answers
To solve this question on the half-life, we will use this expression:
[tex]\begin{gathered} G(t)=G_oe^{-kt} \\ \text{where G(t) is the remaining sample at time t.} \\ G_{o\text{ }}\text{ is the original sample} \\ K\text{ is a constant} \\ t\text{ is time} \end{gathered}[/tex]To proceed in solving, we will need to find the value of constant k
[tex]\begin{gathered} G(t)=G_oe^{-kt} \\ G(t)=17.25 \\ G_o=276 \\ t=255 \\ \text{Now substitute the parameters above into the formula:} \\ 17.25=276e^{-k(255)} \\ \frac{17.25}{276}=e^{-k(255)} \end{gathered}[/tex][tex]\begin{gathered} 0.0625=e^{-k255} \\ \ln 0.0625=-255k \\ \frac{\ln 0.0625}{-255}=k \\ 0.0109=k \end{gathered}[/tex]Now to get the half-life in minutes will be to get the time taken for the sample to go from 276g to 138g.
[tex]\begin{gathered} G(t)=G_oe^{-kt} \\ G(t)=138g \\ 138=276e^{-0.0109t} \\ \frac{138}{276}=e^{-0.0109t} \\ 0.5=e^{-0.0109t} \\ \ln 0.5=-0.0109t \\ \frac{\ln 0.5}{-0.0109}=t \\ 63.591\text{minutes = t} \end{gathered}[/tex]The half-life is 63.59 minutes.
The formula for G(t) at time t is:
[tex]G(t)=276e^{-0.0109t}[/tex]The amount of goo that will remain after 68 minutes is calculated using the formula above:
[tex]\begin{gathered} G(t)=276e^{-0.0109t} \\ t=68\text{ minutes} \\ G(t)=276e^{-0.0109(68)} \\ G(t)=276e^{-0.7412} \\ G(t)=131.5255\text{ grams} \\ G(t)\text{ = 131.53 grams (to 2 d.p)} \end{gathered}[/tex]The amount of goo remaining after 68 minutes is 131.53 grams.
what is x? how would i find the value of x?
Answers
Given:
Find-:
The value of "x."
Explanation-:
Use a trigonometric is:
[tex]\tan\theta=\frac{Perpendicular}{\text{ Base}}[/tex]In a triangle:
[tex]\begin{gathered} \text{ Angle}=x \\ \\ \text{ Base }=3 \\ \\ \text{ Pespendicular }=4 \end{gathered}[/tex]The value of "x" is:
[tex]\begin{gathered} \tan\theta=\frac{\text{ Perpendicular}}{\text{ Base}} \\ \\ \tan x=\frac{4}{3} \\ \\ x=\tan^{-1}(\frac{4}{3}) \\ \\ x=53.13 \end{gathered}[/tex]So, the angle is 53 degree
Аis a solid consisting of two polygons which are parallel to each otherand all points between them.O A. cubeO B. prismO C. pyramidO D. triangle
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The prism is a type of polyhedron formed by two parallel faces that are identical polygons called bases. These figures are joined by the lateral faces that are parallelograms.
According to the previous definition we can conclude that the answer is:
B. Prism
10/13 ÷ 2 and 4/7.....
Answers
Given the expression;
[tex]\frac{10}{13}\div2\frac{4}{7}[/tex]First we need to convert the mixed fraction 2 4/7 into improper fraction as shown;
[tex]\frac{10}{13}\div\frac{18}{7}[/tex]Change the division sign to multiplication as shown;
[tex]\begin{gathered} =\frac{10}{13}\times\frac{7}{18} \\ =\frac{5}{13}\times\frac{7}{9} \\ =\text{ }\frac{35}{117} \end{gathered}[/tex]Hence the answer to the expression is 35/117
I need help with this problem if anyone can help me please do Find the value of the variable
Answers
Answer:
u=11
Explanation:
The statement "The quotient of 44 and 4 is u" can be represented mathematically as:
[tex]u=44\div4[/tex]We can then solve the equation for u.
[tex]\begin{gathered} u=\frac{44}{4}=\frac{4\times11}{4} \\ \implies u=11 \end{gathered}[/tex]The value of u is 11.
Stanley marked two points on the grid below to show the locations of the fiction section, point F, and the travel section, point T, in a bookstore.
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EXPLANATION
We need to calculate the distance between the points (x₁,y₁)=(-8,-3) and (x₂,y₂)=(-3,8) applying the distance equation as shown as follows:
distance=
[tex]\text{Distance}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substituting terms:
[tex]\text{Distance = }\sqrt[]{(-3-(-8))^2+(8-(-3))^2}[/tex]Adding numbers:
[tex]\text{Distance}=\sqrt[]{(5)^2+(11)^2}=\sqrt[]{(25+121)}=\sqrt[]{146}[/tex]The shortest distance is sqrt(146)
Find the number of permutations of the letters in the word. APPLICATION
Answers
SOLUTION:
We want to find the number of permutations of the letters in the word APPLICATION.
The word has 11 letters of which A,P,I are repeated two times.
Thus, the formula for the possible permutations of a word with repeated letters is;
[tex]=\frac{n!}{n_1!n_2!...n_k!}[/tex]Thus, we have;
[tex]\frac{11!}{2!2!2!}=4989600[/tex]Complete the table using the equation y = 7x +4. NO -1 0 1 2
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We will have the following:
*x = -1 => y = 7(-1) + 4 = -3
*x = 0 => y = 7(0) + 4 = 4
*x = 1 => y = 7(1) + 4 = 11
*x = 2 => y = 7(2) + 4 = 18
*x = 3 => y = 7(3) + 4 = 25
Select the conic section that represents the equation.4x2 - 25y2 = 100circleparabolaellipsehyperbola
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We know that the equation of a circle is:
[tex](x-a)^2+(y-b)^2=r^2[/tex]the equation a a parabola is:
[tex]y=ax^2+bx+c[/tex]the equation
Jasper want to venture into the food stall. She plans to create a fund by making deposits of 2,000 in a bank that gives 4% interest compounded quarterly, how much money will be in the fund after 4 years?*228,892.31*101,891.58*228,805.31*103,891.58
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We have to calculate the future value of making monthly deposits of $2000 in a bank that gives 4% interest compounded quarterly.
As the frequencies between the deposits and the compounding are different, we have to calculate a equivalent rate that compounds at the same frequency as the deposits (monthly) that keeps the same effective interest rate.
We have a nominal annual rate of 4% that compounds quarterly (m = 3). We can calculate the equivalent nominal annual rate as:
[tex]i=q\cdot\lbrack(1+\frac{r}{m})^{\frac{m}{q}}-1\rbrack[/tex]where m = 3 is the current compounding subperiod, q = 12 is the new compounding subperiod and r = 0.04 is the current annual rate.
We replace the values and calculate:
[tex]\begin{gathered} i=12\cdot\lbrack(1+\frac{0.04}{3})^{\frac{3}{12}}-1\rbrack \\ i\approx12\cdot(1.0133^{\frac{1}{4}}-1) \\ i\approx12\cdot(1.003316795-1) \\ i\approx12\cdot0.003316795 \\ i\approx0.0398 \end{gathered}[/tex]We can now use the interest rate i = 0.0398 compounded monthly as the equivalent rate.
We can calculate the future value of the annuity as:
[tex]FV=\frac{PMT}{\frac{i}{q}}\lbrack(1+\frac{i}{q})^{n\cdot q}-1\rbrack[/tex]Where PMT = 2000, i = 0.0398, q = 12 and n = 4.
We can replace with the values and calculate:
[tex]\begin{gathered} FV=\frac{2000}{\frac{0.0398}{12}}\cdot\lbrack(1+\frac{0.0398}{12})^{4\cdot12}-1\rbrack \\ FV\approx603015.075\cdot\lbrack(1+0.003317)^{48}-1\rbrack \\ FV\approx603015.075\cdot\lbrack1.1722636-1\rbrack \\ FV\approx603015.075\cdot0.1722636 \\ FV\approx103877.55 \end{gathered}[/tex]We get a future value of the annuity of $103,877.55.
We have some differences corresponding to the roundings made in the calculation, but this value correspond to the option $103,891.58.
Answer: $103,891.58
Rewrite the fraction (4/1)
Answers
Answer:
4
Explanation:
Given the fraction 4/1, this can be rewritten as 4 because any number divided by 1 can also be written as the number itself, both are equivalent.
The polynomial, 3x2 - x +1, can be classified as a 2nd degree trinomial.True or false?
Answers
The polynomial given is:
[tex]3x^2\text{ - x + 1}[/tex]A second degree polynomial is one in which the highest degree of powers is of the second degree.
Basically, a polynomial in which the highest power is 2.
By observing the given polynomial, it is a second degree polynomial.
So, the answer is True.
NEED HELP ASAPP!!!!!!
Answers
Answer:
second line
Step-by-step explanation:
no more than :
x≤ 52 (the dot is full, 52 is a value)
A hotel swimming pool is made for semi circle and square. Find The perimeter of the swimming pool. Round your answer to the nearest tenth.
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Combining the 4 semi-circles of the pool, we can make 2 circles, with a diameter of 10 yd.
The perimeter of a circle is calculated as follows:
[tex]P=\pi\cdot D[/tex]where D is the diameter.
Then, the perimeter of the swimming pool is:
[tex]\begin{gathered} P=2\cdot\pi\cdot10 \\ P=62.8yd^{} \end{gathered}[/tex]A woman invests $6300 in an account that pays 6% interest per year, compounded continuously.(a) What is the amount after 2 years? (Round your answer to the nearest cent.)$ (b) How long will it take for the amount to be $8000? (Round your answer to two decimal places.) yr
Answers
Given: A woman invests $6300 in an account that pays 6% interest per year, compounded continuously.
Required: a) To determine the amount after 2 years.
b) To determine how long it will take for the amount to be $8000.
Explanation: The amount, A after t years with an interest rate of r is given by-
[tex]A=Pe^{rt}[/tex]
Here,
[tex]\begin{gathered} P=6300 \\ r=\frac{6}{100} \\ =0.06 \\ t=2 \end{gathered}[/tex]Substituting the values, we get-
[tex]\begin{gathered} A=6300e^{0.06\times2} \\ =7103.23 \end{gathered}[/tex]Hence the amount after 2 years is $7103.23
Next, let t be the time it takes for the amount to be $8000-
[tex]\begin{gathered} 8000=6300e^{0.06t} \\ \frac{8000}{6300}=e^{0.06t} \\ \ln(1.2698)=0.06t \end{gathered}[/tex]Further solving for t as-
[tex]t=3.98\text{ years}[/tex]Hence, it takes 3.98 years for the amount to be $8000.
Final Answer: a) $7103.23
b) 3.98 years
Add.(9s² - 3s) + (-6s - 9)
Answers
We have to add the expressions, grouping by similar terms:
[tex]\begin{gathered} \mleft(9s^2-3s\mright)+(-6s-9) \\ 9s^2-3s-6s-9 \\ 9s^2-9s-9 \end{gathered}[/tex]Answer: 9s²-9x-9
Help me please I don’t understand and I don’t get this
Answers
The solution:
Representing the given problem in a diagram, we have: