To solve this question, we would use cosine rule which is given as
[tex]a^2=b^2+c^2-2bc\cos A[/tex]Our values have been defined for us and we will proceed to evaluate
[tex]\begin{gathered} a^2=4^2+10^2-2(4)(10)\cos 41 \\ a^2=16+100-80\cos 41 \\ a^2=116-60.376 \\ a^2=55.624 \\ \text{take the square root of both sides} \\ a=\sqrt[]{55.624} \\ a=7.458\approx7.5 \end{gathered}[/tex]From the calculations above, the value of the missing side a is 7.5 units
To find angle B,
we can use sine rule
[tex]\begin{gathered} \frac{a}{\sin A}=\frac{b}{\sin B} \\ \frac{7.5}{\sin 41}=\frac{4}{\sin B} \\ \sin B=\frac{4\times\sin 41}{7.5} \\ \sin B=0.3498 \\ B=\sin ^{-1}0.3498 \\ B=20.5^0 \end{gathered}[/tex]We can still approach C with sine rule or sum of angle in a triangle
[tex]\begin{gathered} A+B+C=180 \\ 41+20.5+C=180 \\ c=118.5^0 \end{gathered}[/tex]From the calculations above, the value of a = 7.5 , B = 22⁰ and C = 118.5⁰ respectively which is option B
-3.9-3.99-3.999-4-4.001-4.01-4.10.420.4020.4002-41.5039991.53991.89try valueclear tableDNEundefinedlim f(2)=lim f(2)=2-)-4+lim f (30)f(-4)-4
In order to determine the limit of f(x) when x tends to -4 from the right (4^+), we need to look in the table the value that f(x) is approaching when x goes from -3.9 to -3.99 to -3.999.
From the table we can see that this value is 0.4.
Then, to determine the limit of f(x) when x tends to -4 from the left (4^-), we need to look in the table the value that f(x) is approaching when x goes from -4.1 to -4.01 to -4.001.
From the table we can see that this value is 1.5.
Since the limit from the left is different from the limit from the right, the limit when x tends to -4 is undefined.
Finally, the value of f(-4) is the value of f(x) when x = -4. From the table, we can see that this value is -4.
△GHI~△WVU.51010IHG122UVWWhat is the similarity ratio of △GHI to △WVU?Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
Answer: 5
To get the similarity ratio, we must know that for the given triangles:
[tex]\frac{IG}{UW}=\frac{GH}{WV}=\frac{HI}{VU}[/tex]From the given, we know that:
UW = 2
WV = 2
VU = 1
IG = 10
GH = 10
HI = 5
Substitute these to the given equation and we will get:
[tex]\begin{gathered} \frac{IG}{UW}=\frac{GH}{WV}=\frac{HI}{VU} \\ \frac{10}{2}=\frac{10}{2}=\frac{5}{1} \\ 5=5=5 \end{gathered}[/tex]With this, we have the similarity ratio of ΔGHI to ΔWVU is 5
For each system through the best description of a solution if applicable give the solution
System A
[tex]\begin{gathered} -x+5y-5=0 \\ x-5y=5 \end{gathered}[/tex]solve the second equation for x
[tex]x=5+5y[/tex]replace in the first equation
[tex]\begin{gathered} -(5+5y)+5y-5=0 \\ -5-5y+5y-5=0 \\ -10=0;\text{FALSE} \end{gathered}[/tex]The system has no solution.
System B
[tex]\begin{gathered} -X+2Y=8 \\ X-2Y=-8 \end{gathered}[/tex]solve the second equation for x
[tex]x=-8+2y[/tex]replace in the first equation
[tex]\begin{gathered} -(-8+2y)+2y=8 \\ 8-2y+2y=8 \\ 8=8 \end{gathered}[/tex]The system has infinitely many solutions, they must satisfy the following equation:
[tex]\begin{gathered} -x+2y=8 \\ 2y=8+x \\ y=\frac{8}{2}+\frac{x}{2} \\ y=\frac{x}{2}+4 \end{gathered}[/tex]Solve the equation algebraically. x2 +6x+9=25
We must solve for x the following equation:
[tex]x^2+6x+9=25.[/tex]1) We pass the +25 on the right to left as -25:
[tex]\begin{gathered} x^2+6x+9-25=0, \\ x^2+6x-16=0. \end{gathered}[/tex]2) Now, we can rewrite the equation in the following form:
[tex]x\cdot x+8\cdot x-2\cdot x-2\cdot8=0.[/tex]3) Factoring the last expression, we have:
[tex]x\cdot(x+8)-2\cdot(x+8)=0.[/tex]Factoring the (x+8) in each term:
[tex](x-2)\cdot(x+8)=0.[/tex]4) By replacing x = 2 or x = -8 in the last expression, we see that the equation is satisfied. So the solutions of the equation are:
[tex]\begin{gathered} x=2, \\ x=-8. \end{gathered}[/tex]Answer
The solutions are:
• x = 2
,• x = -8
2. The length of Sally's garden is 4 meters greater than 3 times the width. Theperimeter of her garden is 72 meters. Find the dimensions of Sally's garden.The garden has a width of 8 and a length of 28.
L = length
W = width
L = 4 + 3*W
The perimeter of a rectangle is the sum of its sides: 2L + 2W. Since it's 72, we have:
2L + 2W = 72
Now, to solve for L and W, the dimensions of the garden, we can use the first equation (L = 4 + 3*W) into the second one (2L + 2W = 72):
2L + 2W = 72
2 * (4 + 3*W) + 2W = 72
2 * 4 + 2 * 3W + 2W = 72
8 + 6W + 2W = 72
8W = 72 - 8
8W = 64
W = 64/8 = 8
Then we can use this result to find L:
L = 4 + 3W = 4 + 3 * 8 = 4 + 24 = 28
Therefore, the garden has a width of 8 and a length of 28.
Write a word problem that the bar model in problem 2 could represent.
An example of a problem for the given diagram:
You go to a store to buy the school supplies you will need for the next term. There are boxes of 7 pencils each, and you decide to buy 5 of those boxes. How many pencils do you end up buying?
If Mason made 20 free throws, how many free throws did he attempt in all?
Answer:
what is the shooting percentage?
What value of x would make lines land m parallel?5050°t55°75xº55m105
If l and m are parallel, then ∠1 must measure 55°.
The addition of the angles of a triangle is equal to 180°, in consequence,
Find the values of the variables so that the figure is aparallelogram.
Given the following question:
[tex]\begin{gathered} \text{ The property of a }parallelogram \\ A\text{ + B = 180} \\ B\text{ + C = 180} \\ 64\text{ + }116\text{ = 180} \\ 116+64=180 \\ y=116 \\ x=64 \end{gathered}[/tex]y = 116
x = 64
2) The ratio of trucks to cars on the freeway is 5 to 8. If thereare 440 cars on the freeway, how many trucks are there?
If the ratio of trucks to trucks is 5 to 8,
then we can use proportions to solve for the number of truck (unknown "x"):
5 / 8 = x / 440
we solve for x by multiplying: by 440 both sides
x = 440 * 5 / 8
x = 275
There are 275 trucks on the freeway.
x^2-18x-57=6 solve each equation by completing the square
x=-3
x=21
Find the distance from P to l. Line l contains points (2, 4) and (5, 1). Point P has coordinates (1, 1).
First we need to find the equation of the line l passing through the points (2, 4) and (5, 1).
The equation of a line is expressed as y = mx+c
m is the slope
c is the intercept
m = y2-y1/x2-x1
m = 1-4/5-2
m = -3/3
m = -1
Get the intercept
Substitute any point (2, 4) and the slope m = -3 into the expression y = mx + c
4 = -3(2)+c
4 = -6 + c
c = 4+6
c = 10
The equation of line l is y = -3x+10
Next is to find the equation of the line w perpendicular to the line l, through P(1, 1).
Since the line w is perpendicular to lin
Given the following data: {3, 7, 8, 2, 4, 11, 7, 5, 9, 6),a. What is the median? (remember to put the data in order first)
what is the ratio of sin b
we have that
sin(B)=56/65 -----> by opposite side angle B divided by the hypotenuse
I need help on this. and there's two answers that's right but I don't know
Answer
Options B and C are correct.
(5⁸/5⁴) = 625
(5²)² = 625
Explanation
We need to first know that
625 = 5⁴
So, the options that the laws of indices allow us to reduce to 5⁴
Option A
(5⁻²/5²) = 5⁻²⁻² = 5⁻⁴ = (1/5⁴) = (1/625)
This option is not correct.
Option B
(5⁸/5⁴) = 5⁸⁻⁴ = 5⁴ = 625
This option is correct.
Option C
(5²)² = 5⁴ = 625
This option is correct.
Option D
(5⁴) (5⁻²) = 5⁴⁻² = 5² = 25
This option is not correct.
Hope this Helps!!!
Suppose that our section of MAT 012 has 23 students, and the other two sections of MAT 012 have a total of 44 students. What percent of all the students taking MAT012 are in our section of MAT 012?
Explanation
We can deduce from the information that MAT 012 has 3 sections, namely:
Our section, and two other sections
Then, we can also infer that MAT012 has a total of:
[tex]23+44=67\text{ students}[/tex]Our task will be to get the percentage of our section taking MAT 102
Since our section has 23
Then we can calculate the answer as
[tex]\frac{23}{67}\times100=34.33\text{ \%}[/tex]Thus, the answer is 34.33%
suppose each cube in this right rectangular prism is a 1/2-in unit cube
Answer:
The length of each cube is given below as
[tex]l=\frac{1}{2}in[/tex]Concept:
To figure out the dimension of the prism, we will calculate the number of cubes to make the length,width and height and multiply by 1/2
To figure out the length of the prism,
we will multiply 1/2in by 5
[tex]\begin{gathered} l=\frac{1}{2}in\times5 \\ l=2.5in \end{gathered}[/tex]To figure out the width of the prism,
we will multiply 1/2in by 4
[tex]\begin{gathered} w=\frac{1}{2}in\times4 \\ w=2in \end{gathered}[/tex]To figure out the height of the prism,
we will multiply 1/2 in by 3
[tex]\begin{gathered} h=\frac{1}{2}in\times3 \\ h=\frac{3}{2}in=1.5in \end{gathered}[/tex]Hence,
The dimensions of the prism are
Length = 2.5in
Width = 2in
Height = 1.5 in
2.5in by 2in by 1.5in
Part B:
To figure out the volume of the prism, we will use the formula below
[tex]\begin{gathered} V_{prism}=base\text{ area}\times height \\ V_{prism}=l\times w\times h \\ l=2.5in,w=2in,h=1.5in \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} V_{pr\imaginaryI sm}=l\times w\times h \\ V_{pr\mathrm{i}sm}=2.5in\times2in\times1.5in \\ V_{pr\mathrm{i}sm}=7.5in^3 \end{gathered}[/tex]Alternatively, we will calculate below by calculate the volume of each cube and then multiply by the total number of cubes
[tex]\begin{gathered} volume\text{ of each cube=} \\ =l^3=(\frac{1}{2})^3=\frac{1}{8}in^3 \\ The\text{ total number of cubes =} \\ =5\times4\times3 \\ =60cubes \\ Volume\text{ of the prism } \\ =\frac{1}{8}in^3\times60 \\ =7.5in^3 \end{gathered}[/tex]Hence,
The volume of the prism is = 7.5in³
If 6 times a certain number is added to 8, the result is 32.Which of the following equations could be used to solve the problem?O6(x+8)=326 x=8+326 x+8 = 326 x= 32
Answer: 6x + 8 = 32
Explanation:
Let x represent the number
6 times the number = 6 * x = 6x
If we add 6x to 8, it becomes
6x + 8
Given that the result is 32, the equation could be used to solve the problem is
6x + 8 = 32
please help me solve. The answer I have is in yellow. They are wrong.
Let's simplify the radicals:
[tex]\begin{gathered} \sqrt[]{30}\cdot\sqrt[]{5}=\sqrt[]{30\cdot5} \\ =\sqrt[]{150} \\ =\sqrt[]{25\cdot6} \\ =\sqrt[]{25}\sqrt[]{6} \\ =5\sqrt[]{6} \end{gathered}[/tex]Question 31 of 50 2 Points An assumption about a population parameter that is verified based on the results of sample data is a/an OA. statistical hypothesis OB. assumption OC. presumptive statement OD. prediction
From the question, it is:
An assumption about a population parameter that is verified based on the real results of sample data is a/an Statistical Hypothesis.
Hypothesis testing is a form of statistical inference that uses data from a sample to draw conclusions about a population parameter or a population probability distribution.
Therefore, the correct options is A, which is Statistical Hypothesis.
Help on question on math precalculus Question states-Which interval(s) is the function decreasing?Group of answer choicesBetween 1.5 and 4.5Between -3 and -1.5Between 7 and 9Between -1.5 and 4.5
We have a function of which we only know the graph.
We have to find in which intervals the function is decreasing.
We know that a function is decreasing in some interval when, for any xb > xa in the interval, we have f(xa) < f(xb).
This means that when x increases, f(x) decreases.
We can see this intervals in the graph as:
We assume each division represents one unit of x. Between divisions, we can only approximate the values.
Then, we identify all the segments in the graph where f(x) has a negative slope, meaning it is decreasing.
We have the segments: [-3, -1.5), (1,5, 4.5) and (7,9].
Answer:
The right options are:
Between 1.5 and 4.5
Between -3 and -1.5
Between 7 and 9
Write an equation of the line perpendicular to the line –4x + 3y = –15 and passes through the point (–8, –13)
4y = -3x - 76
Explanations:The given equation is:
-4x + 3y = -15
Make y the subject of the formula to express the equation in the form
y = mx + c
[tex]\begin{gathered} -4x\text{ + 3y = -15} \\ 3y\text{ = 4x - 15} \\ y\text{ = }\frac{4}{3}x\text{ - }\frac{15}{3} \\ y\text{ = }\frac{4}{3}x\text{ - 5} \end{gathered}[/tex]Comparing the equation with y = mx + c
the slope, m = 4/3
the y-intercept, c = -5
The equation perpendicular to the equation y = mx + c is:
[tex]y-y_1\text{ = }\frac{-1}{m}(x-x_1)[/tex]The line passes through the point (-8, -13). That is, x₁ = -8, y₁ = -13
Substitute m = 4/3, x₁ = -8, y₁ = -13 into the equation above
[tex]\begin{gathered} y\text{ - (-13) = }\frac{-1}{\frac{4}{3}}(x\text{ - (-8))} \\ y\text{ + 13 = }\frac{-3}{4}(x\text{ + 8)} \\ y\text{ + 13 = }\frac{-3}{4}x\text{ - 6} \\ y\text{ = }\frac{-3}{4}x\text{ - 6 - 13} \\ y\text{ = }\frac{-3}{4}x\text{ - 19} \\ 4y\text{ = -3x - }76 \end{gathered}[/tex]What is the solution to the equation below? 3x = x + 10 O A. x = 10 B. x = 0 C. X = 5 D. No Solutions
Hence, the correct option is C: x=5
the item to the trashcan. Click the trashcan to clear all your answers.
Factor completely, then place the factors in The proper location on the grid.3y2 +7y+4
We are asked to factor in the following expression:
[tex]3y^2+7y+4[/tex]To do that we will multiply by 3/3:
[tex]3y^2+7y+4=\frac{3(3y^2+7y+4)}{3}[/tex]Now, we use the distributive property on the numerator:
[tex]\frac{3(3y^2+7y+4)}{3}=\frac{9y^2+7(3y)+12}{3}[/tex]Now we factor in the numerator on the right side in the following form:
[tex]\frac{9y^2+7(3y)+12}{3}=\frac{(3y+\cdot)(3y+\cdot)}{3}[/tex]Now, in the spaces, we need to find 2 numbers whose product is 12 and their algebraic sum is 7. Those numbers are 4 and 3, since:
[tex]\begin{gathered} 4\times3=12 \\ 4+3=7 \end{gathered}[/tex]Substituting the numbers we get:
[tex]\frac{(3y+4)(3y+3)}{3}[/tex]Now we take 3 as a common factor on the parenthesis on the right:
[tex]\frac{(3y+4)(3y+3)}{3}=\frac{(3y+4)3(y+1)}{3}[/tex]Now we cancel out the 3:
[tex]\frac{(3y+4)3(y+1)}{3}=(3y+4)(y+1)[/tex]Therefore, the factored form of the expression is (3y + 4)(y + 1).
The relation described in the following diagram is function. A. True B. False
Answer:
False
Explanation:
A relation is a function each term of the first set is related to only one term of the second set. In this case, 1 is related to 5 and to 10, so it is not a function.
Therefore, the answer is
False
2. When we are in a situation where we have a proportional relationship between two quantities, what information do we need to find an equation?
Answer:
If two quantites have a proportional relatio
Graph each equation rewrite in slope intercept form first if necessary -8+6x=4y
slope intercept form of the required graph:
-8 + 6x = 4y
y = 3/2x - 2
Can you pls help me with this question thank you
To solve this question, follow the steps below.
Step 01: Substitute j and k by its corresponding values.
j = 6
k = 0.5
Then,
[tex]\begin{gathered} 3.6j-2k \\ 3.6\cdot6-2\cdot0.5 \\ \end{gathered}[/tex]Step 02: Solve the multiplications.
[tex]21.6-1[/tex]Step 03: Solve the subtraction.
[tex]20.6[/tex]Answer: b. 20.6.
I’m circle P with m ∠NRQ=42, find the angle measure of minor arc NQ
Here we must apply the following rule:
[tex]arc\text{ }NQ=2\cdot m\angle NRQ[/tex]Since m ∠NRQ = 42°, we have:
[tex]arc\text{ }NQ=2\cdot42=84\degree[/tex]6. An odometer shows that a car has traveled 56,000 miles by January 1, 2020. The car travels 14,000 miles each year. Write an equation that represents the number y of miles on the car's odometer x years after 2020.
Answer:
y=14000x
Step-by-step explanation:
x represents years after 2020 and y is the number of miles
The required equation for the distance travelled versus number of years after 2020 is given as y = 14000x + 56000.
How to represent a straight line on a graph?To represent a straight line on a graph consider two points namely x and y intercepts of the line. To find x-intercept put y = 0 and for y-intercept put x = 0. Then draw a line passing through these two points.
The given problem can be solved as follows,
Suppose the year 2020 represents x = 0.
The distance travelled per year can be taken as the slope of the linear equation.
This implies that slope = 14000.
And, the distance travelled by January 1, 2020 is 56000.
It implies that for x = 0, y = 56000.
The slope-point form of a linear equation is given as y = mx + c.
Substitute the corresponding values in the above equation to obtain,
y = 14000x + c
At x = 0, y = 56000
=> 56000 = 14000 × 0 + c
=> c = 56000
Now, the equation can be written as,
y = 14000x + 56000
Hence, the required equation for number of miles and years for the car is given as y = 14000x + 56000.
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