Answers
ANSWER:
90°
STEP-BY-STEP EXPLANATION:
Chord TD separates the circle into two equal 180° angles, so angles Since the angle 90°
Related Questions
from the base of the tower, you meassure its shadow to be 17.25m.at same the time your shadoe is 0.21m.you are 1.68 tall.how tall ia the tower?(round to two decimal plaves if necessary)
Answers
The Solution:
Representing the given in a diagram, we have
By similarity theorem, we have that:
[tex]\frac{BA}{BT}=\frac{BC}{BD}[/tex]So,
[tex]\begin{gathered} BA=1.68m \\ BT=h=(1.68+x)m \\ BC=0.21m \\ BD=17.25m \end{gathered}[/tex]Substituting these values in the formula above, we get
[tex]\frac{1.68}{1.68+x}=\frac{0.21}{17.25}[/tex]Solving for x:
We shall cross multiply,
[tex]0.21(1.68+x)=1.68\times17.25[/tex][tex]0.3528+0.21x=28.98[/tex][tex]0.21x=28.98-0.3528=28.6272[/tex]Dividing both sides by o.21, we get
[tex]x=\frac{28.6272}{0.21}=136.32\text{ m}[/tex]The height of the tower is
[tex]h=1.68+x=1.68+136.32=138m[/tex]Therefore, the correct answer is 138 meters.
Below, the two-way table is given for aclass of students.FreshmenSophomoreJuniorsSeniorsTotal46246Male2Female 33TotalIf a student is selected at random, find theprobability the student is a junior given that it'smale. Round to the nearest whole percent.[?]%
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Male students. 14
Female students: 16
Total students: 30
Since there are 2 male juniors, the probability of being junior and male is: 6.67%
[tex]\frac{2}{30}\cdot100=6.67[/tex]If we round to the nearest whole porcent: 7%
E-0-16Name a pair of similar triangles.Explain why each pair of triangles is similar.Use the given information to find each missing measure.
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The horizontal arrows denote that segments RS and VT are parallel. This means that angleR and angleV are congruent. Similarly, angleS and angleT are congruent. They are denoted in blue and red color, respectively:
Therefore,
[tex]\Delta\text{TUV}\approx\Delta SUR[/tex]by the AA-theorem (angle-angle theorem). That is because:
[tex]\begin{gathered} \angle R=\angle V \\ \angle S=\angle T \\ \angle U=\angle U \end{gathered}[/tex]Now, lets find the missing measure x. Since the above triangles are similar, we have
[tex]\frac{x}{3}=\frac{x+1}{3+9}[/tex]which gives
[tex]\frac{x}{3}=\frac{x+1}{12}[/tex]By multiplying both side by 3, we get
[tex]x=\frac{x+1}{4}[/tex]and by multiplying both side by 4, we have
[tex]4x=x+1[/tex]then, x is given as
[tex]\begin{gathered} 4x-x=1 \\ 3x=1 \end{gathered}[/tex]therefore, we obtain
[tex]x=\frac{1}{3}[/tex]then, the missing side x measures 1/3.
Now, lets find y. In this case, we have
[tex]\frac{y}{3}=\frac{2}{9+3}[/tex]then, it yields
[tex]\frac{y}{3}=\frac{2}{12}[/tex]by multipluying both sides by 3, we have
[tex]\begin{gathered} y=3\cdot\frac{2}{12} \\ y=\frac{2}{4} \\ y=\frac{1}{2} \end{gathered}[/tex]Therefore, the missing side y measures 1/2.
Which identity/formula was used to simplify from step 2 to step 3?
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Solution:
The reciprocal identities of trigonometry include the identities below
[tex]\begin{gathered} \csc \theta=\frac{1}{\sin \theta} \\ \sec \theta=\frac{1}{\cos \theta} \\ \cot \theta=\frac{1}{\tan \theta} \\ \tan \theta=\frac{1}{\cot \theta} \\ \cos \theta=\frac{1}{\sec \theta} \\ \sin \theta=\frac{1}{\csc \theta} \end{gathered}[/tex]The quotient identity include the identities below
[tex]\begin{gathered} \tan \theta=\frac{\sin \theta}{\cos \theta} \\ \cot \theta=\frac{\cos \theta}{\sin \theta} \end{gathered}[/tex]The sum formula of trigonometric identity include
[tex]\begin{gathered} \sin (\alpha+\beta)=\sin \alpha\cos \beta+\cos \alpha\sin \beta \\ \sin (\alpha-\beta)=\sin \alpha\cos \beta-\cos \alpha\sin \beta \\ \cos (\alpha+\beta)=\cos \alpha\cos \beta-\sin \alpha\sin \beta \\ \cos (\alpha-\beta)=\cos \alpha\cos \beta+\sin \alpha\sin \beta \end{gathered}[/tex]The double-angle formula is given below as
Hence,
The final answer is QUOTIENT IDENTITY
de a and perform the symmetry lest on each of the following is. eld plerd Find the in 16 r2 + 25y2 = 400 A00 (c) r2 + 4y2 = 4 (e) 4x2 + y2 = 64 (B) 9x² + 4y2 = 36 (b) 25x+6y (d) 4x + y = A () Ay? (h) 7x + y - 112 Graph the vertices, foci, endpoints of the minor axis, and endpoints of the latera recta, then draw AB is a chord of the partial ellipse with equation f(x) = ba? - x'. (a) 576x2 + 625y2 = 360,000, A (15,f(15)), B(20, f(20)) (b) 49x 2 + 625y2 = 30,625, A (15, f(15)), B(20,f(20)) – x. Find the length of AB using
Answers
The given ellipse is
[tex]576x^2+625y^2=360,000[/tex]Where A(15, f(15)), B(20, f(20)).
First, we find f(15) and f(20) by evaluating the given expression
[tex]\begin{gathered} f(15)=576(15)^2+625y^2=360,000 \\ 576\cdot225+625y^2=360,000 \\ 129,600+625y^2=360,000 \\ 625y^2=360,000-129,600 \\ 625y^2=230,400 \\ y^2=\frac{230,400}{625} \\ y^2=368.64 \\ y=\sqrt[]{368.64} \\ y=19.2 \end{gathered}[/tex]We use the same process to find f(20).
[tex]\begin{gathered} f(20)=576(20)^2+625y^2=360,000 \\ 576\cdot400+625y^2=360,000 \\ 625y^2=360,000-230,400 \\ x^2=\frac{129,600}{576} \\ x=\sqrt[]{225}=15 \\ \end{gathered}[/tex]So, the points are A(15, 19.2) and B(20, 15). To find the distance between these points, we have to use the distance formula
[tex]\begin{gathered} d_{AB}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d_{AB}=\sqrt[]{(20-15)^2+(15-19.2)^2} \\ d_{AB}=\sqrt[]{5^2+(-4.2)^2}=\sqrt[]{25+17.64}=\sqrt[]{42.64} \\ d_{AB}\approx6.5 \end{gathered}[/tex]Hence, the length of AB is around 6.5 units.Convert the following unit areas as indicated. Choose the right answe Area Conversion Number Table English Area Conversion Number Metric Area Square Miles Square Miles Acres Acres Square Yards Square Feet Square Inches 2.59 259 4.05 x 10-3 4.05 x 10-1 8.36 x 10-1 9.29 x 10-2 6.45 Square Kilometers Hectares Square Kilometers Hectares Square Meters Square Meters Square Centimeters 50 in.2 to cm2
Answers
Answer:
322.5 square centimeters
Explanation:
To convert from square inches to square centimeters, we need to multiply the number by the conversion factor 6.45, so 50 in² are equivalent to:
50 in² x 6.45 = 322.5 cm²
Therefore, the answer is 322.5 square centimeters.
PLSSSSSS HELPPPP ASAPP i only need everything in measuring segments , congruent segments and segment addition
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the answer are:
1. A(X +Y),,B (X+Y) OR d(A,B)
2. If two segments having the same length are congruent segments.This is written as for example: AB is congruent with CD.
AB=CD
3. AC=B, because B is inside points A and C it means that it was the additional point to add and arrive at C.
Recall: Averaging Two NumbersMaddie earned an 88% on her first test and an 80% onyour second test. What is her average test score? (Note:Click on the little calculator icon above to pull up acalculator.)
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We know that
• She earned an 88% on her first test.
,• She earned an 80% on her second test.
To know her average score, we just have to sum these percentages and divide them by 2, since they are just 2.
[tex]\bar{x}=\frac{88+80}{2}=\frac{168}{2}=84[/tex]Therefore, the average test score is 84%.The line that passes through the points (3,0) and (-5,8) isA.)DecreasingB.)IncreasingC.)HorizontalD.)Vertical
Answers
The slope of a line
It is a parameter that can help us to know the behavior of a line, specifically if it's increasing, decreasing
Bobs car rental is offering a special of 40$ a day for a seden as long as you purchase the car damage protection insurance for 20$
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In this case, we have a proportional relationship, since the cost varies directly with the days, this means that as x increases, y increases, and as x decreases, y decreases. A proportional relationship has the form:
y=kx
Where k is the constant of proportionality.
The ratio between them (x and y) is always the same, in this case, the ratio or constant of proportionality is 40, since each day the rent cost increases $40, then:
Constant of proportionality = 40 , replacing 40 for k into the above equation, we get:
equation: y = 40x
We can use this equation to find some pair of values (x,y) to fill the table, like this:
For x equals 2:
y= 40*2 = 80
For x equals 3:
y= 40*3 = 120
For x equals 4:
y=40*4 = 160
For x equals 5:
y=40*5=200
Then, we can fill the table as follows:
We can also use these data to graph the relationship, by taking the point (5,200) and joining it to the origin, we get:
Find an equation of an ellipse satisfying the given conditions Vertices: (0 - 6) and (0.6) Length of minor axis: 8
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As the given vertices are at a distance of 12 units:
As the major axis is vertical you have the next generall equation:
[tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex]To find the center (h,k) of the ellipse use the coordinates of that vertices as follow:
[tex](\frac{0+0}{2},\frac{6-6}{2})=(0,0)[/tex]Now use the distance between those vertices to find a:
[tex]a=\frac{12}{2}=6[/tex]b is the distance of minor axis divided into 2:
[tex]b=\frac{4}{2}=2[/tex]Then, you get the next equation for the given ellipse:
[tex]\begin{gathered} \frac{(x-0)^2}{2^2}+\frac{(y-0)^2}{6^2}=1 \\ \\ \frac{x^2}{4}+\frac{y^2}{36}=1 \end{gathered}[/tex]Alfred needs to buy small pumpkins that cost $2.75 each. The function he uses is ()=2.75. Use the function to determine the cost of 25 pumpkins.
Answers
From the question, we have a linear function for the cost of each pumpkin, and this function is:
[tex]f(x)=2.75x[/tex]As we can see, the cost for one pumpkin is:
[tex]f(1)=2.75(1)=\text{ \$2.75}[/tex]Now, to find the cost for 25 pumpkins, we need to substitute the value of x = 25 into the function, since this is a function that gives us the cost as a function of the number of pumpkins:
[tex]\begin{gathered} f(x)=2.75x \\ \\ f(25)=2.75(25)=68.75 \\ \\ f(25)=68.75 \\ \\ \end{gathered}[/tex]As we can see, we multiply 2.75 times 25, and we got 68.75.
Therefore, in summary, it will cost $68.75 for 25 pumpkins.
how do you solve y=x-2 and graph it
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The equation
y = x - 2
is the equation of a line in the slope-intercept form with a slope of 1 and a y-intercept at (0, -2).
You can graph it by locating two points on the line. One point is (0, -2). The other one can be found with the slope. The slope of 1 means that the next point is 1 unit to the left and 1 unit up, respect the previous point. In this case, the next point is (1, -1). After you locate these two points, draw the line that connects them, as follows
how do you find the length of a side of a triangle when given the length of only one other side?
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WE can find the sides if the triangle by apply the Sine rule :
[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]where, a,b & c are the sides of triangle
For eg :
Consider an triangle with one side AB = 5
and angles A = 60, angle B = 45 and angle C= 75
So, substitute the value in the expression of Sine
[tex]\begin{gathered} \frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C} \\ \frac{BC}{\sin 60}=\frac{AC}{\sin 45}=\frac{5}{\sin 75} \\ \text{ Substitute the values :} \\ \frac{BC}{\sin60}=\frac{AC}{\sin45}=\frac{5}{\sin75} \\ \frac{BC}{0.866}=\frac{AC}{0.707}=\frac{5}{0.965} \\ \text{ Simplify : }\frac{AC}{0.707}=\frac{5}{0.965} \\ \frac{AC}{0.707}=\frac{5}{0.965} \\ AC=\frac{5}{0.965}\times0.707 \\ AC=3.66 \\ \text{Now, Simplify: }\frac{BC}{0.866}=\frac{5}{0.965} \\ BC=\frac{5}{0.965}\times0.866 \\ BC=4.4 \end{gathered}[/tex]The sides : AB = 5, AC = 3.66 & BC = 4.4
[tex]7x(x + 4) = [/tex]simplify
Answers
Given expression:
[tex]=\text{ 7x(x + 4)}[/tex]Expanding:
[tex]\begin{gathered} =\text{ 7x }\times\text{ x + 7x }\times\text{ 4} \\ =\text{ 7 }\times\text{ x }\times\text{ x + 7 }\times\text{ x }\times\text{ 4} \\ =\text{ 7 }\times x^2\text{ + 7 }\times\text{ 4 }\times\text{ x} \end{gathered}[/tex]Simplifying the expression:
[tex]\begin{gathered} =7\times x^2\text{ + }28\times x \\ =7x^2\text{ + 28x} \end{gathered}[/tex]Answer:
[tex]7x^2\text{ + 28x}[/tex]At 1:00 AM the temperature was 87º. A cold front came through and at 7:00 PM the temperature was 45°. What is the rate of change in the temperature in degrees per hour?
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the rate of change in the temperature per hour is the quotient of the change of temperature divided by the change in hours. Since we have
1:00 AM =1 hr - 87 degrees
7:00 PM=19 hrs - 45 degrees,
then the rate is
[tex]\frac{45-87\text{ }}{19-1}=\frac{-42}{18}=-\frac{7}{3}=-2.33[/tex]Then, the temperature changed -2.33 degrees per hour.
A bike wheel as a radius of 13 inches. a. About how far does the bike wheel tra in 1 rotation? 5 rotations? 30 rotations? b. Write an equation relating the distance the bike travels in inches, b, to the number of wheel rotations, x. c. About how many rotations does the bike wheel make when the bike travels 1 mile?
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The radius of the bike wheel is given as 13 inches. One rotation would be equal to the entire circumference of the bike wheel. Hence;
[tex]undefined[/tex][tex]1144 \times \frac{25}{3699} + 114 \sqrt[1441]{36} - y + x \div 15663 = 2 - \sqrt[44410]{3651} + {2554}^{2} [/tex]first equation. then text
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how does equation look in session history???
Based on the information given in the following graph of a power function, can you determinethe equation of the power function? Why or why not? If you can, find the equation of the powerfunction. If not, describe the equation of the power function as much as you can.
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SOLUTIONS
To determine the equation of the power function? Why or why not? If you can, find the equation of the power
[tex]\begin{gathered} (4,2) \\ x=4,y=2 \end{gathered}[/tex]It is easy to get the graph of the exponential function since x - value = 4 and y - value = 2.
An exponential function is defined by the formula f(x) = x^a, where the input variable x occurs as an exponent. The exponential curve depends on the exponential function and it depends on the value of the x.
The general equation of an exponential function is
[tex]y=x^a[/tex][tex]\begin{gathered} y=2,x=4 \\ 2=4^a \\ 4^{\frac{1}{2}}=4^a \\ a=\frac{1}{2} \end{gathered}[/tex][tex]y=x^{\frac{1}{2}}[/tex]The figure below is an isosceles trapezoid:KLIK = 12x - 34IL = 4x - 10X =Blank 1:
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From the definition, it must have symmetry in the present figure. It seems to be a vertical line going through the middle of the drawing. From this, we can say that:
[tex]\begin{gathered} IK=JL \\ 12x-34=4x-10 \end{gathered}[/tex]Now, we can solve it.
[tex]\begin{gathered} 12x-34=4x-10 \\ 12x-4x=34-10 \\ 8x=24 \\ x=\frac{24}{8} \\ x=3 \end{gathered}[/tex]volume= {1}{3} * \pi * r ^{2}* hHELPsolve for H
Answers
Explanation
[tex]Volume=\frac{1}{3}\pi r^2h[/tex]Step 1
multiply each side by 3
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V\cdot3=\frac{1}{3}\pi r^2h\cdot3 \\ 3V=\pi r^2h \end{gathered}[/tex]Step 2
divide both sides by
[tex]\pi r^2[/tex][tex]\begin{gathered} 3V=\pi r^2h \\ \frac{3V}{\pi r^2}=\frac{\pi r^2\text{ h}}{\pi r^2} \\ h=\frac{3V}{\pi r^2} \end{gathered}[/tex]Using only the values given in the table for thefunction, f(x), what is the interval of x-values over whichthe function is increasing?Х-6-5-4-3-2.-101f(x)343-10-11-6-1-2-15O (-6,-3)O (-3,-1)O (-3,0)O (-6, -5)
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Given the table:
Х f(x)
-6 34
-5 3
-4 -10
-3 -11
-2. -6
-1 -1
0 -2
1 -15
Let's find the increasing intervals.
A function is increasing over the interval when the values of f(x) increases as the values of x increases.
At the interval:
From x = -3 to x = -1, the values of f(x) increases from -11 to -1.
Therefore, the interval of x-values over which the function is increasing is:
(-3, -1)
ANSWER:
(-3, -1)
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
The figure must be an isosceles trapezoid because it has 2 congruent base angles.
The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
The figure could be a rhombus because the 2 lines of symmetry bisect the angles.
The figure could be a square because the diagonals of a square bisect the right angles.
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The third option is correct. That is, the figure could be a rhombus because the 2 lines of symmetry bisect the angles.
What is rhombus?
A rhombus is a quadrilateral that is an equilateral parallelogram and has all of its opposite pairs of sides parallel. Sometimes the word "rhombus" is substituted with "rhomb," and a rhombus is also referred to as a "diamond."
Given: A quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors.
Since the two lines of symmetry in a quadrilateral are angle bisectors, the figure may be a rhombus if the quadrilateral has exactly two lines of symmetry. Figures with four sides and angles are called quadrilaterals. Rectangle is a type of quadrilateral.
Therefore, If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then the figure could be a rhombus because the 2 lines of symmetry bisect the angles.
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Answer:
third option
Step-by-step explanation:
A jewelry salesperson earns 5 1/5 % commission on all sales. Today he sold $7,310 in jewelry. What is his total commission earned?
The total commission the salesperson earned is
Answers
The total commission salesperson earned is $394.5.
What is commission?
Commissions are a type of variable-pay compensation for provided services or sold goods. Commissions are a typical method of encouraging and rewarding salespeople. It is also possible to create commissions to promote particular sales behaviours. For instance, while offering significant reductions, commissions might be decreased.
Given: A jewelry salesperson earns 5 1/5 % commission on all sales. Today he sold $7,310 in jewelry.
We have to find the commission earned on $7310.
Here, [tex]5\frac{1}{5} = \frac{(5)(5)+2}{5} =\frac{27}{5}[/tex]
5 1/5% = 27/5%
Today he sold $7310 in Jwellary.
So, the commission is,
[tex]\frac{(7310)(27)}{(5)(100)} = 394.5[/tex]
Hence, the total commission of $7310 is $394.5.
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1. An equation is shown below. 60 10 100 = Determine the value of the missing numerator. Your answer
Answers
m = 6
Explanations:The given equation is:
[tex]\frac{m}{10}=\text{ }\frac{60}{100}[/tex]Cross multiply:
100m = 60 x 10
100m = 600
Divide both sides by 100
[tex]\begin{gathered} \frac{100m}{100}=\text{ }\frac{600}{100} \\ m\text{ = 6} \end{gathered}[/tex]The missing numerator is 6
I NEED HELP WITH THIS TWO7) the shirt costs $25. the discount is 18% how many dollars is the discount? 8) 40% of 120 students passed the test. How many students passed?
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If the shirt costs 25 and the discount is 18%, then the amount discounted is shown as follows;
[tex]\begin{gathered} \text{Cost}=25 \\ \text{Discount}=0.18 \\ \text{Discounted amount=25}\times0.18 \\ \text{Discounted amount=4.5} \end{gathered}[/tex]The discount is $4.5.
If 40% of students passed out of 120, then the number that passed is shown below;
[tex]\begin{gathered} Total\text{ number=120} \\ \text{Percentage that passed=0.40} \\ \text{Number that passed=120}\times0.40 \\ \text{Number that passed=48} \end{gathered}[/tex]The number of students that passed is 48
Answer: 7. $20.50 & 8. 48 students
Step-by-step explanation:
The organizer of a conference is selecting workshops to include. She will select from 3 workshops about anthropology and 10 workshops about psychology. In how many ways can she select 7 workshops if 2 or fewer must be about anthropology?
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give the following from the question:
the organizer will select from 3 workshop about anthropology and 10 workshops about psychology.
we were asked in how many ways she can select 7 workshops if 2 or fewer must be anthropology
so,
If 2 or fewer must be anthropology,
Then tha means it is either she selects 2 from anthropology and 5 from psychology or 1 from anthropology and 6 from psycology.
that is:
= 3C2 x 10C5 or 3C1 x 10C6
= 3!/(3-2)!2! x 10!/(10-5)!5! + 3!/(3-1)!1! x 10!/(10-6)!6!
= 3x2!/2! x 10x9x8x7x6x5!/5!5! + 3x2!/2! x 10x9x8x7x6!/4!6!
= 3 x 252 + 3 x 210
= 756 + 630
= 1,386 ways
The ways she can select 7 workshops if 2 or fewer must be about anthroplogy is 1,386 ways
The coordinates below represents points that were translated.Match the coordinates with the correct algebraic representations
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R(1, 8) >> R'(10, -10) ........(x+9, y-18)
V(-2, -10) >> V'(5, -3).......(x+7, x+7)
U(3, -9) >> U'(10, -16).......(x+7, y-7)
T(-4, 7) >> T'(-11, 14)..........(x -7, y+7)
Explanations:When a pont A(x, y) is translated by a in the x-axis, and b in the y-axis, the new point becomes A'(x+a, y+b)
For the expression R(1, 8) >> R'(10, -10)
The coordinates of R' ae formed using the expression (x+9, y-18)
For the expression V(-2, -10) >> V'(5, -3)
The coordinates of V' are formed by using the expression (x+7, x+7)
For the expression U(3, -9) >> U'(10, -16)
The coordinates U' are formed by using the expression (x+7, y-7)
For the expression T(-4, 7) >> T'(-11, 14)
The coordinates T' are formed by using the expression (x -7, y+7)
Points A(-2,-3),B(-2,4),and C(3,6) are three vertices of parallelogram ABCD. Opposite sides of a parallelogram have the same length. Draw the parallelogram in the coordinate plane and label the coordinates of the fourth point.
Answers
Given:
Points A(-2,-3),B(-2,4),and C(3,6) are three vertices of parallelogram ABCD.
As we know, the opposite sides of the parallelogram are parallel and congruent
To draw the parallelogram, we will draw the points and connect the sides
AB, AC, and BC
then, draw two lines parallel to AB from C and BC from A, the intersection will give the point D
The graph of the parallelogram will be as shown in the following picture
As shown the coordinates of the fourth point D = (3, -1)
Locker codes at Lincoln High School consist of 4 digits. No digit can be used more than once. How many locker codes are available at Lincoln High School? A 210 B 3,024 C 5,040 D 10,000
Answers
To obtain the number of locker codes available, the following steps are necessary:
Step 1: Create a diagram to represent the slot for each of the digits, as below;
Step 2: State the number ways that each digit can be used to fill any of the spots, as below:
Given that there are the numbers 0,1,2,3,4,5,6,7,8,9 - a total of 10 numbers,
- The first slot can be filled with any of the digits above, and thus can be filled in 10 ways
- The second slot can be filled with any of the remaining 9 numbers after one of them has already been used to fill the first slot. Thus, there are 9 ways the second slot can be filled.
- The same line of reasoning tells us that the third slot will be filled in 8 ways
- Lastly, the fourth slot will be filled in 7 ways
The diagram below gives a better illustration:
Step 3: Multiply the numbers of ways to find the total number of locker codes that are available, as follows:
[tex]10\times9\times8\times7\text{ = 5040}[/tex]Therefore, there are a total of 5040 available locker codes at Lincoln High School
Correct answer = Option C