We can find the equation of a line given one point and its slope.
Remember that two parallel lines have the same slope; therefore, the slope of 5x-2y-4=0 is equal to the slope of the line we are trying to find.
[tex]\begin{gathered} 5x-2y-4=0 \\ \Rightarrow2y=5x-4 \\ \Rightarrow y=\frac{5x}{2}-\frac{4}{2}=\frac{5x}{2}-2 \\ \Rightarrow y=\frac{5x}{2}-2 \\ \Rightarrow m=\frac{5}{2} \end{gathered}[/tex]Then, we have got everything we need, the slope is equal to 5/2 and a point in the line is (2,-4)
The equation is:
[tex]\begin{gathered} y-(-4)=\frac{5}{2}(x-2) \\ \Rightarrow y+4=\frac{5}{2}(x-2) \\ \Rightarrow y+4=\frac{5x}{2}-5 \\ \Rightarrow y=\frac{5x}{2}-9 \\ \Rightarrow y+9=\frac{5}{2}x \\ \Rightarrow2y+18=5x \\ \Rightarrow5x-2y-18=0 \end{gathered}[/tex]The answer is 5x-2y-18=0
hey! I need help/answers to 20 questions. Heres the first question Find the volume of a pyramid with a square base, where the side length of the base is 10.9 m and the height of the pyramid is 4.7 m. Round your answer to the nearest tenth of a cubic meter.
Answer:
The Volume of the pyramid is;
[tex]186.1\text{ }m^3[/tex]Explanation:
Given the pyramid with a square base and dimensions;
[tex]\begin{gathered} l=10.9m \\ h=\text{4}.7m \end{gathered}[/tex]Recall that the volume of a pyramid can be calculated using the formula;
[tex]V=\frac{l\times l\times h}{3}[/tex]Substituting the given values;
[tex]\begin{gathered} V=\frac{10.9\times10.9\times4.7}{3} \\ V=186.1m^3 \end{gathered}[/tex]Therefore, the Volume of the pyramid is;
[tex]186.1\text{ }m^3[/tex]Can you please figure out this equation and see if I have the right answer
The expression is given to be:
[tex]\tan \left(\frac{7\pi }{12}\right)[/tex]Rewrite the expression:
[tex]\frac{7\pi}{12}=\frac{\pi}{4}+\frac{\pi}{3}[/tex]Therefore, we have:
[tex]\tan\left(\frac{7\pi}{12}\right)=\tan\left(\frac{\pi}{4}+\frac{\pi}{3}\right)[/tex]Recall the summation identity:
[tex]\tan \left(x+y\right)=\frac{\tan \left(x\right)+\tan \left(y\right)}{1-\tan \left(x\right)\tan \left(y\right)}[/tex]Therefore, we have:
[tex]\tan\left(\frac{\pi}{4}+\frac{\pi}{3}\right)=\frac{\tan\left(\frac{\pi}{4}\right)+\tan\left(\frac{\pi}{3}\right)}{1-\tan\left(\frac{\pi}{4}\right)\tan\left(\frac{\pi}{3}\right)}[/tex]Recall that:
[tex]\begin{gathered} \tan \left(\frac{\pi }{4}\right)=1 \\ \tan \left(\frac{\pi }{3}\right)=\sqrt{3} \end{gathered}[/tex]Hence, the equation becomes:
[tex]\frac{\tan(\frac{\pi}{4})+\tan(\frac{\pi}{3})}{1-\tan(\pi\/4)\tan(\pi\/3)}=\frac{1+\sqrt{3}}{1-1\cdot\sqrt{3}}[/tex]Therefore, we can simplify the expression to be:
[tex]-2-\sqrt{3}[/tex]The THIRD OPTION is correct.
I need help on this
You consider each parittion of the axis represents 1 unit.
You can notice that in the given image, the coordinates of the points A, B, C and D are the following:
A(-6,4)
B(-2,1)
C(2,3)
D(-1,-4)
where you have taken into account that point left side of the origin have negative x valuesand points right side have positive x values. Point down side of origin have negative y values and points above origin has positive y values.
Find the slope and y-intercept of the line.y = -3,000 + 30x
The given equation is
[tex]y=-3,000+30x[/tex]It's important to know that this is a linear equation, and it's written in the form
[tex]y=mx+b[/tex]Where m is the slope, and b is the y-intercept.
That means we only need to look for these values and that's it!
According to the given equation, we have
[tex]m=30,b=-3,000[/tex]Therefore, the slope is 30, and the y-intercept is at (0, -3000).Given BD bisects ∠ABC, complete the flowchart proof below. Note that the last statement and reason have both been filled in for you.
In order to prove that the triangles are congruent, we can write the following statements and reasons:
first box in the first row:
statement: BD bisects angle ABC
reason: given
first box in the second row:
statement: angle ABD congruent to angle DBC
reason: A segment bisector divides a segment into two congruent segments.
second box in the second row:
statement: angle ADB congruent to angle BDC
reason: given
third box in the second row:
statement: side AB congruent to side BC
reason: given
Since we have two pairs of congruent angles and one pair of congruent sides that are not between the angles, we can prove the triangles congruent by case AAS.
i need help doing number 34 and 35 if you can please :(
The tangent of an angle, we will follow the steps below
Step 1: Write out the trigonometric ratio to obtain the tangent of an angle
[tex]\tan \emptyset=\frac{opposite}{adjacent}[/tex]From question 35
Step 2: Apply the tangent ratio
[tex]\begin{gathered} \tan A=\frac{\text{opposite}}{\text{adjacent}}=\frac{60}{100}=\frac{6}{10}=\frac{3}{5} \\ \tan A=\frac{3}{5}=0.6000 \end{gathered}[/tex]For tan B
[tex]\begin{gathered} \tan B=\frac{\text{opposite}}{\text{adjacent}}=\frac{100}{60}=\frac{5}{3} \\ \tan B=\frac{5}{3}=1.6667 \end{gathered}[/tex]If AABC – ADEF, which angle corresponds with angle A in the following image?Side16deee3ce67551e9dd974313e76f08f2 webm 10Blank 1:
Answer:
Angle D corresponds to angle A
Explanations:
Since △ABC ≅ △DEF;
It means both triangles have corresponding sides and angles.
To make it obvious which angle in △DEF corresponds to angle A in △ABC, let us redraw △DEF to look like △ABC
Obviously from the diagrams I drew above,
determine the ratio of surface area to volume of the triangular prism
Solution
The surface area of a Triangular prism is given as;
[tex]SA=bh+(s_1+s_2+s_3)H[/tex]The volume of a triangular prism is given as;
[tex]V=\frac{1}{2}bhl[/tex]The ratio of surface area to volume of the triangular prism
[tex]\text{ratio}=\frac{SA}{V}=\frac{bh+(s_1+s_2+s_3)H}{\frac{1}{2}bhl}[/tex]hi, I would like help with this please and ty
You can use number line or inequalities to compare the temperatures of this three different cities.
Using number line to compare the temperatures 2.5, -3.5 F and -5 F
Using inequality
[tex]\begin{gathered} 2.5>-3.5 \\ -3.5>-5 \end{gathered}[/tex]What is 3 times 5????
For natural numbers, a multiplication can be seen as a repetitive addition. In this case, 3 times 5 is the same as addign 5+5+5. Then:
[tex]3\times5=5+5+5=15[/tex]4. A number between 200 and 400 with 6 more tens than ones.
Answer
Question 3
Largest number where the sum of the digits is 16 is 862
Question 4
The number between 200 band 400 with 6 more tens than ones is 382
Explanation
We can only use numbers from the digit bank to answer this questions.
Question 3
Largest number where the sum of the digits is 16 is 862
Question 4
A number between 200 and 400 with 6 more tens than ones.
Noting that the tens digit is the second digit from the right in a number and the ones digit is the first number from the right for any number.
So, we are asked to form a number whose second number from the right is 6 more than the first number from the right.
So, we can easily see that
The ones number has to be 2
The tens number has to be 8 (Since 8 is 6 more than 2)
Then, for the third and last number, since the number has to be between 200 and 400, the last number has to be 3.
So, the number between 200 band 400 with 6 more tens than ones is 382
Hope this Helps!!!
Divide the stars into 3 equal groups. How many stars are in each group? 8 What is 13 of 9?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
total stars = 9
equal groups = 3
stars per group = ?
1/3 of 9 = ?
Step 02:
stars per group = total stars / equal groups
stars per group = 9 / 3
stars per group = 3
1/3 of 9 = 1/3 * 9 = 9/3 = 3
The answer:
There are 3 stars per group.
1/3 of 9 is 3.
Can you just help me with this it is hurt
A horizontal line is in the form
y =
This means the x component changes and the y component stays the same
( -7, 10)
The line is in the form
y = 10
x can be any value
The slope is zero since it is horizontal
The point ( 3,10) is on the line
The equation of the line is y = 10
The y intercept is 10 not -7
Enter the missing values in the area model to find 2(5n+1)
First box: 10n
2
10n + 2
Explanations:The area model = 2 (5n + 1)
Thsi can expanded into:
2 (5n) and 2(1)
In the first box:
2 (5n) = 10n
In the second box:
2(1) = 2
In the third box:
2 (5n + 1) = 10n + 2
A time traveler can take 4 books with him, and he has 86 books to choose from. How many differentways can the books be selected?
Combination:
[tex]_nC_r=\frac{n!}{r!(n-r)!}[/tex]n is the number of things to choose from, and r is the number of thing
A football team played A games last year. They lost B of those games. What was their winning percentage
Answer:
(A - B)/A x 100%
Explanation:
If they played A games last year and lost B of those games, they win the rest of the games, so they win A - B games.
Then, the percentage is calculated as the number of games that they win over the total number of games multiplied by 100, so the winning percentage is
(A - B)/A x 100%
what is 12 times 12?
Answer:
144
Step-by-step explanation:
Answer: 12x12=144.
I hope this helps!!!!!!!!!!!!!!!!!!!!!!!!!!
list 6 different types of geometric principles represented in the picture.
We need to list 6 geometric principles represented in the picture.
We can see the vertices of something that looks like leaves, arranged in a spiral.
Those vertices form angles. Also, the leaves seem to be tridimensional, so they have a surface area and a volume.
Also, notice that leaves equidistant from the center of the spiral seem to be congruent.
Therefore, we can list the following types of geometric principles:
• vertices
,• spiral
,• angles
,• surface area
,• volume
,• equidistance
,• congruent
Find the GCF of 24m^4n and 16m^2n.
Answer:
[tex]8m^2n[/tex]Step-by-step explanation:
To find the GCF (greatest common factor), we have to find the prime factors of each number. Then, we have to find similar factors.
In this exercise, we have:
24m⁴n = 2 * 2 * 2 * 3 * m * m * m * m * n
16m²n = 2 * 2 * 2 * 2 * m * m * n
The GCF will be 2 * 2 * 2 * m * m * n
So, The GCF is 8m²n.
72. Suppose that Sarah walks along a hiking trail at 2 mi/hra. What is her rate in mi/day?b. How many days will it take for her to reach a destination that is 14 1/2 miles away?c. If she started hiking at 6:00 am, what time will she reach her destination?
Supposing the rate is:
[tex]2\frac{mi}{hour}[/tex](a) Converting tho mi/day
Knowing that 1 day = 24 hours
[tex]\begin{gathered} 2\text{ }\frac{mi}{hour}*\frac{24hour}{day} \\ 2*24\text{ }\frac{mi}{day} \\ 48\frac{m\imaginaryI}{day} \end{gathered}[/tex]The rate is 48 mi/day.
(b) Finding how many days will it take to reach 14 1/2
14 1/2 is the same as 14.5
Dividing 14.5 by 48:
[tex]\frac{14.5miles}{48\frac{miles}{day}}=0.3days[/tex]It will take 0.30 days.
(c) Finding when it will reach the destination.
Knowing the rate is 2 mi/hour, let's find how many hours it will take to reach 14.5 miles.
[tex]\begin{gathered} \frac{14.5mi}{2\text{ }\frac{mi}{hour}} \\ 7.25hours \end{gathered}[/tex]7.25 hours is 7 hours + 1/4 hour (15 min)
So, let's sum 06 (starting time) + 07 hours + 15 min
01:15 pm.
He will reach her destination at 01:15 pm.
Answer:
- (a) The rate is 48 mi/day.
- (b) It will take 0.30 days.
- (c) He will reach her destination at 01:15 pm.
As shown above a classical deck of card is made up 52 cards suppose one card is selected at random and calculate the following proper ability
To determine the probability of selecting a classical deck of card
(a) Probability of selecting a 7 or club
[tex]\begin{gathered} Pr(\text{selecting a 7 or club) = pr( selecting a 7) + pr(selecting a club )} \\ \text{pr( selecting a 7) = }\frac{4}{52} \\ \text{pr( selecting a club) = }\frac{13}{52} \\ Pr(\text{selecting a 7 or club) = }\frac{4}{52}+\frac{13}{52}=\text{ }\frac{4+13}{52}=\frac{17}{52}\text{ = 0.3269} \\ Pr(\text{selecting a 7 or club) = }0.327\text{ (3dp)} \end{gathered}[/tex](b) Probability of selecting a face card or heart
[tex]\begin{gathered} Pr(\text{selecting a face card or heart) = pr(selecting a face card) + pr(selecting a heart)} \\ Pr(\text{selecting a face card) = }\frac{12}{52} \\ Pr(\text{selecting a heart) = }\frac{13}{52} \\ Pr(\text{selecting a face card or heart) = }\frac{12}{52}+\frac{13}{52}=\frac{12+13}{52}=\frac{25}{52}=0.4807 \\ Pr(\text{selecting a face card or heart) }=\text{ 0.481 (3dp)} \end{gathered}[/tex](c) Probability of selecting both a face card and a club
[tex]\begin{gathered} Pr(\text{selecting both a face card and a club) = pr(selecting a face card)+pr(selecting a club)} \\ \text{pr(selecting a face card) = }\frac{12}{52} \\ \text{pr(selecting a club) = }\frac{13}{52} \\ Pr(\text{selecting both a face card and a club) = }\frac{12}{52}\text{ }\times\frac{13}{52}=\text{ }\frac{3}{52}=0.0577 \\ Pr(\text{selecting both a face card and a club) = 0.058 (3dp)} \end{gathered}[/tex]
explain the meaning of the point (1, 1 .5) in terms of the situation
The graph above is a relationship between the amount of oil and the amount of vinegar use to prepare salad dressing. The point 1 is the x axis while the point 1.5 is the y axis .
In terms of the situation if the x axis represents the amount of oil required for the salad dressing and the y axis represents the amount of vinegar , the point (1, 1.5) says for every 1 table spoon of oil required , 1.5 table spoon of vinegar is also used to make the salad dressing.
how do I create equal groups that represent the division fact 28÷4=7?
So to make equal groups just create the number of groups (divisor, in this case: 4) and insert into that the number of the quotient( in this case: 7)
1) Let's make equal groups for that division since 7 added 4 times is equal to 28:
2) Since 7 x 4 is the same as adding 7 four times, we have above four groups with seven balls that added up yields 28, in each group we have 7 balls.
3) So to make equal groups just create the number of groups (divisor) and insert into that the number of the quotient. Note that this is valid just for exact divisions.
A wire is attached from the top of a 30-foot tall telephone pole…
The diagram illustrating the given scenario is shown below
The triangle formed is a right triangle. From the diagram,
AB = height of pole
angle ACB is the angle between the and the pole
AC is the length of the wire
taking angle 48 as the reference angle,
hypotenuse = AC
adjacent side = BC = 30
θ = 48
We would find AC by applyng the Cosine trigonometric ratio which is expressed as
Cosθ = adjacent side/hypotenuse
By substituting these values into the formua, we have
Cos 48 = 30/AC
By crossmultiplying, we have
AC Cos 48 = 30
By dividing both sides of the equation by Cos 65, we have
AC = 30/Cos48
AC = 44.8
The length of the wire is 44.8 feet
A rectangle or televisions length is 3 inches more than twice its width the perimeter of the television is 144 inches what is the width of the television
The width of the television is 23 in.
What is rectangle?A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles. The opposite sides of a rectangle are equal and parallel.
Given that, A television's length is 3 inches more than twice its width the perimeter of the television is 144 inches
Perimeter of a rectangle = 2(length+width)
According to question,
l = 3+2w
Therefore,
Perimeter = 2(w + 3+2w) = 144
3w + 3 = 72
3w = 69
w = 23
Hence, The width of the television is 23 in.
For more references on rectangle, click;
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a. a grade that is 12 points lower than a grade of x can be represented as Options: x-12both x-12 and 12-x 12-x
a. If a friend says his grade is 12 points lower than your grade, it means your grade is greater than his grade, if your grade is represented by x, then the grade of your friend can be found by subtracting 12 from your grade, this can be written as:
[tex]x-12[/tex]b. If x represents your friend's grade instead of yours, then to find your grade you need to add 12 to his grade, it can be represented as:
[tex]\begin{gathered} x+12 \\ 12+x \end{gathered}[/tex]The correct answers are B. and D.
100_0.22 help me please
Given the expression :
[tex]100-0.22[/tex]The answer will be as follows, add the decimal point and two zeros
[tex]100-0.22=100.00-0.22[/tex]See the following picture:
=In AABC, the measure of ZC=90°, CB = 35, AC = 12, and BArepresents the cosine of ZA?37. What ratio
ANSWER:
[tex]\frac{12}{37}[/tex]STEP-BY-STEP EXPLANATION:
The first thing is to draw the triangle ABC:
We have that the trigonometric cosine ratio is given as follows
[tex]\begin{gathered} \cos \theta=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \text{For A, we have} \\ \text{adjacent = 12} \\ \text{hypotenuse = }37 \\ \text{replacing:} \\ \cos A=\frac{12}{37} \end{gathered}[/tex]Adu pick one pen from a box,
containing one blue pen, 2 red
pens and 3 green pens without.
looking into the box. What is the
probability of picking
(1) Blue Pen
if Red pen
( Green pen
(iv) green or blue pen
Red or green pen
The probability of picking Blue pen, Red pen and Green pen out of the box at random will be 1/6, 1/3 and 1/2 respectively.
As per the question statement, we are supposed to find the probability of picking Blue pen, Red pen and Green pen out of the box at random.
It is given that the box contains one blue pen, 2 red pens and 3 green pens.
Total pen = 6
Probability of Blue pen = 1/6
Probability of Red pen = 2/6 = 1/3
Probability of Green pen = 3/6 = 1/2
Hence, the probability of picking Blue pen, Red pen and Green pen out of the box at random will be 1/6, 1/3 and 1/2 respectively.
Probability: The chance of happening or not happening of any event is its probability. It is the ratio of favorable outcome and the total number of event.To learn more about probability and similar concept, click on the link given below:
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Find the radius when the arc is / and / radians
The arc length formula is :
[tex]l=r\theta[/tex]where r = radius
θ = angle in radians
and l = arc length
From the problem, the arc length is 18π/7 and the angle is 6π/7.
Using the formula above :
[tex]\begin{gathered} \frac{18\pi}{7}=r(\frac{6\pi}{7}) \\ 18\pi=r(6\pi) \\ r=\frac{18\pi}{6\pi} \\ r=3 \end{gathered}[/tex]ANSWER :
The radius is 3