Find the area of the circle with a circumference of 62.8 inches. Use 3.14 for pi

Answers

Answer 1

The area of a circumference can be calculated with this formula:

[tex]C=2\pi r[/tex]

Where "r" is the radius of the circle.

The area of a circle can be found with this formula:

[tex]A=\pi r^2[/tex]

Where "r" is the radius of the circle.

If you solve for "r" from the formula of a circumference, you get:

[tex]r=\frac{C}{2\pi}[/tex]

Knowing that:

[tex]\begin{gathered} C=62.8in \\ \pi\approx3.14 \end{gathered}[/tex]

You get:

[tex]\begin{gathered} r=\frac{62.8in}{(2)(3.14)} \\ \\ r=10in \end{gathered}[/tex]

Knowing the radius, you can find the area of the circle:

[tex]\begin{gathered} A=(3.14)(10in)^2 \\ A=314in^2 \end{gathered}[/tex]

The answer is:

[tex]A=314in^2[/tex]


Related Questions

Consider the triangle shown below where m∠C=50∘, b=11 cm, and a=23 cm.Use the Law of Cosines to determine the value of x (the length of AB in cm).x=

Answers

The Law of Cosines is:

[tex]c^2=a^2+b^2-2ab\cdot\cos C[/tex]

Where "a", "b" and "c" are sides of the triangle and "C" is the angle opposite side "c".

In this case you know that:

[tex]\begin{gathered} m\angle C=50\degree \\ b=11\operatorname{cm} \\ a=23\operatorname{cm} \\ c=x \end{gathered}[/tex]

Then, you can substitute values as following:

[tex]\begin{gathered} c^2=a^2+b^2-2ab\cdot\cos C \\ x^2=(23\operatorname{cm})^2+(11\operatorname{cm})^2-2(23\operatorname{cm})(11\operatorname{cm})\cdot\cos (50\degree) \end{gathered}[/tex]

Finally, evaluating, you get that the answer is:

[tex]\begin{gathered} \\ x\approx18.02\operatorname{cm} \end{gathered}[/tex]

Use the number line to answer the question. Each tick represents 1.Which point is located at 2?PQSnone of the above

Answers

Given that each tick represents 1. The numbers on the right of 0 are positiv and on the left of 0 are negative. SInce 2 is positive, 2 lies on the right side of 0.

Since each tick represents 1, the first tick represents 0+1 = 1.

Now, the second tick represents 0 + 2 = 2. The second tick on the right of 0 denoted as S.

The correct option is S.

A parallelogram has a height of 7 meters and an area of 35 square meters. what would the sum of the bases be for a trapezoid with the same height and area as the parallelogram?

Answers

The height of trapezoid is h = 7 m.

The area of trapezoid is A = 35 m^2.

The formula for the area of trapezoid is,

[tex]A=\frac{a+b}{2}\cdot h[/tex]

Here, a and b are length of bases of trapezoid.

Substitute the values in the formula to obtain the sum of bases of trapezoid.

[tex]\begin{gathered} 35=\frac{a+b}{2}\cdot7 \\ \frac{a+b}{2}=\frac{35}{7} \\ a+b=5\cdot2 \\ =10 \end{gathered}[/tex]

So sum of bases of trapezoid is equal to 10 meters.

————————————————————————————————————————

Write the phrase as an algebraic expression: a number divided by 2

Answers

Answer:

x/2

Explanation:

Let the number = x

If the number is divided by 2, then an algebraic expression to represent the phrase is:

[tex]\frac{x}{2}[/tex]

It can also be written in the form:

[tex]x\div2[/tex]

Solve the system of equations by any method. 6x+11y =16x+2y =4

Answers

Hello! I'll draw the solution of this system of equations:

Now, let's go back to the second equation and replace where's y by 8:

So, the solution will be: (-12, 8) or x= -12 and y= 8.

16x^2 + 56x + 49 Is this a special product? If yes, what type

Answers

Let's check if the given equation is a special product.

[tex]16x^2+56x+49[/tex]

Let,

a = 1st term coefficien

b = 2nd term coefficient

c = constant

We get,

a = 16

b = 56

c = 49

Let's check, you can use this method to check if it is a perfect square binomial:

[tex]\begin{gathered} \text{ 2(}\sqrt[]{a}\text{ x }\sqrt[]{c})\text{ = b ;} \\ (a+c)^2\text{ if b is positive} \\ (a-c)^2\text{ if b is negative} \end{gathered}[/tex][tex]\begin{gathered} 2(\sqrt[]{16}\text{ x }\sqrt[]{49})\text{ = 56} \\ 2(4\text{ x 7) = 56 ; since b is positive, a and c are positive} \\ 2(28)\text{ = 56} \\ 56\text{ = 56} \end{gathered}[/tex]

Therefore, the equation is a special product. It is a square of a binomial.

The answer is YES, it is a special product. It is a Square of a Binomial (x + y)².

compare the elevation of death valley and westmorland using< or >

Answers

Answer:

If D represent the elevation of Death valley , California and W represent the elevation of Westmorland, California.

So, we would have;

[tex]DWhich means that;

the elevation of Death valley < the elevation of Westmorland

Explanation:

Given that the elevation of Death valley , California is -282 feet

[tex]D=-282[/tex]

And the elevation of Westmorland, California is -157 feet;

[tex]W=-157[/tex]

And we know that -282 ft is less than -157 ft.

[tex]-282<-157[/tex]

Therefore, the elevation of Death valley , California is less than the elevation of Westmorland, California.

So, if D represent the elevation of Death valley , California and W represent the elevation of Westmorland, California.

So, we would have;

[tex]DWhich means that;

the elevation of Death valley < the elevation of Westmorland

3. A doctor sees between 7 and 12 patients each day. On Mondays and Tuesdays.the appointment times are 15 minutes. On Wednesdays and Thursdays, they are30 minutes. On Fridays, they are one hour long. The doctor works for no morethan 8 hours a day. Here are some inequalities that represent this situation,0.25 Sy 51YS0S 12Y S83a. What does each variable represent?Your anowar3b. What does the expression xy in the last inequality mean in thissituation?

Answers

Solution

We have the following inequalities:

0.25 <= y<= 1, 7 <= x<= 12, xy <= 8

And we can conclude this:

Part a

the variable y represents the appointment time in hours and x the number of patients by the doctor

Part b

the expression xy is the time in hours that spends with a patient

What percent of 40 is 17?

Answers

In general, we can calculate what percent of y is x using the equation:

[tex]P=\frac{x}{y}\cdot100\text{\%}[/tex]

In our problem, we identify:

[tex]\begin{gathered} x=17 \\ y=40 \end{gathered}[/tex]

The percentage is:

[tex]\begin{gathered} P=\frac{17}{40}\cdot100\text{\%}=\frac{17\cdot5}{2}\text{ \%} \\ \Rightarrow P=42.5\text{\%} \end{gathered}[/tex]

What is the volume of this cone? Use 3.14 and round your answer to the nearest hundredth. 38 mm cubic millimeters

Answers

ANSWER

[tex]V=7179.09\operatorname{mm}[/tex]

EXPLANATION

We are given the height of the cone as 19 mm and the diameter of its base as 38 mm.

The volume of a cone is given as:

[tex]V=\frac{1}{3}\pi\cdot r^2h[/tex]

where r =radius; h = height

The diameter of a circle (the base of a cone) is twice the radius. Therefore:

[tex]\begin{gathered} D=2r \\ r=\frac{D}{2} \\ r=\frac{38}{2} \\ r=19\operatorname{mm} \end{gathered}[/tex]

Therefore, the volume of the cone is:

[tex]\begin{gathered} V=\frac{1}{3}\cdot3.14\cdot19^2\cdot19 \\ V=7179.09\operatorname{mm}^3 \end{gathered}[/tex]

Select all statements that must be true.
(Select all that apply)
Students selecting B are likely mistaking the range for
the IQR. Students selecting C are likely mistaking the
median for the IQR. Students selecting D are likely
mistaking the mean for the median. It may be possible
that the mean is 3.6 goals per game, but cannot be
determined from the box plot alone. Students selecting
F are likely mistaking Q1 for the minimum.
A. The interquartile range (IQR) is 1.2 goals per game.
B. The interquartile range (IQR) is 3.2 goals per game.
C. The interquartile range (IQR) is 3.6 goals per game.
The average goals scored per game are calculated for
20 soccer tournaments. The 20 averages are used to
create this box plot.
O O OOO
D. The mean is 3.6 goals per game.
E. The median is 3.6 goals per game.
E The minimum is 2.8 goals per game.
H
G. The maximum is 5.6 goals per game.
2
2.4 2.8 3.2 3.6
4
4.4
4.8
5.2 5.6
6
Average Number of Goals per
Game

Answers

The maximum = 5.6 goals per game

median = 3.6 goals per game

Interquartile range (IQR ) = 1.2 goals per games

Explanation:

To solve this question, we need an illustration that identifies the part of the box and whiskers plot:

The minimum on the box and whiskers = 2.4 goals per game

The maximum = 5.6 goals per game

The median = the line in between the box

median = M on the image

median = 3.6 goals per game

upper quartile = Q3 = 4

lower quartile = Q1 = 2.8

The interquartile range = IQR

[tex]\begin{gathered} \text{IQR = Q}_3-Q_1 \\ \text{IQR = }4\text{ - 2.8} \\ \text{IQR = 1.2} \end{gathered}[/tex]

Interquartile range (IQR ) = 1.2 goals per games

[tex]\begin{gathered} \text{Mean = average of the data set} \\ \text{Mean = }\frac{su\text{m of the numbers}}{nu\text{mber of the data set}} \\ \text{Mean = }\frac{2.4\text{ + }2.8+3.6+4+5.6}{5} \\ \text{Mean = 18.4/5} \\ \text{Mean = 3.68} \end{gathered}[/tex]

The mean is 3.68 goals per game

2.2.18Find the vertex of the graph of the quadratic function. Determine whether thegraph opens upward or downward, find the y-intercept, and sketch the graph.f(x) = - x2 - 2x+3The vertex is(Simplify your answer. Type an ordered pair.)

Answers

The quadratic function is given by the following expression:

[tex]f(x)=-x^2-2x+3[/tex]

The direction at which the graph opens is determined by the signal of the number multiplying x². If the number is positive then the graph opens upwards, if it is negative it opens downward. In this case it is negative so it opens donward.

The vertex of a quadratic expression can be found by the following expression:

[tex]x=\frac{-b}{2a}[/tex]

Where a is the number multiplying "x²", while b is the number multiplying "x". Applying the data from the problem we have:

[tex]x=\frac{-(-2)}{2\cdot(-1)}=\frac{2}{-2}=-1[/tex]

To find the value of "y" for the vertex we need to apply the coordinate for x on the expression. We have:

[tex]\begin{gathered} f(-1)=-(-1)^2-2\cdot(-1)+3 \\ f(-1)=-1+2+3=4 \end{gathered}[/tex]

The coordinates of the vertex are (-1,4).

To sketch a graph we need to find the x-intercept and y-intercept of the function. These are given when f(x) = 0 and x=0 respectively. Let's find these points.

[tex]\begin{gathered} 0=-x^2-2x+3 \\ -x^2-2x+3=0 \\ x_{1,2}=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(-1)(3)}}{2\cdot1} \\ x_1=-3 \\ x_2=1 \end{gathered}[/tex][tex]f(x)=-0^2-2\cdot0+3=3[/tex]

The x intercept happens in two points -3 and 1, while the y intercept happens in the point 3. With this and the vertex we can sketch the function.

There’s a few more questions like this I been stuck on

Answers

Problem N 9

we have that

m by addition angles postulate

substitute given values

164=(13x+4)+(10x-1)

solve for x

164=23x+3

23x=164-3

23x=161

x=7

Find out the measure of angle SQR

msubstitute the value of x

mm

According to psychologist IQs are normally distributed with a mean of 100 and a standard deviation of 19. What’s the percentage of the population has IQs above 154?

Answers

In order to solve this problem, we will calculate the z-score of the given data.

To do this, we use the formula,

[tex]z=\frac{x-\mu}{\sigma}[/tex]

We plug in the given data:

[tex]z=\frac{154-100}{19}\approx2.8421[/tex]

With this z-score, we can consult a z-score probability table or use an online resource. However, this will give us

[tex]P(z<2.8421)[/tex]

but we are interested in itbeing greater than it, so we must calculate

[tex]1-P(z<2.8421)=1-0.99776=0.00224[/tex]

So, the percentage of the population that has an IQ above 154 is 0.224%.

I need help with my math

Answers

Answer: Graph the value of b first on the Y - axis

The slope - intercept form of equation is

y = mx + b

where m = slope , and b = intercept

You graph the value of b on the Y - axis

Which represents the inverse of the function f(x) = 4x?h(x) = x + 4Oh(x) = X-4Oh(x) = 2xh(x) =17 1x

Answers

f(x) = 4x

To find the inverse of a function, you have to replace every x with an y, as follows:

f(x) = 4y

then, replace f(x) with an x,

x = 4y

and now, isolate y,

x/4 = y

Finally, replace y whit h(x),

h(x) = 1/4x

The cube root of our varies inversely with the square of S which to equations model this relationship?

Answers

The question states as follows;

"The cube root of r varies inversely with the square of s."

The general form of an inverse relationship is shown below;

[tex]y=\frac{k}{x}[/tex]

Substituting the variables, we would now have;

[tex]\sqrt[3]{r}=\frac{k}{s^2}[/tex]

Therefore, the third option is correct.

Also;

[tex]\begin{gathered} \sqrt[3]{r}=\frac{k}{s^2} \\ \text{Observe that}_{} \\ \sqrt[3]{r}=r^{\frac{1}{3}} \end{gathered}[/tex]

Therefore, we can alo have the expression;

[tex]\begin{gathered} r^{\frac{1}{3}}=\frac{k}{s^2} \\ \text{Cross multiply, and we'll have;} \\ s^2r^{\frac{1}{3}}=k \end{gathered}[/tex]

The fifth option is also correct.

ANSWER:

The third and fifth options are both correct models of the inverse relationship given.

What is the surface area of the following figure?

Answers

Answer:

surface area of cube = 37.5 units

Step-by-step explanation:

Find the area of one side of the cube with the formula sidexside:

2.5 x 2.5 = 6.25 units

now multiple the area of one side by the number of sides of the cube which is 6 sides:

6.25 x 6 = 37.5 units

Could someone help me out please I don’t know how to

Answers

As per given by the question,

There are given that ,

[tex]4y^2+y-9,\text{ when y=-3}[/tex]

Now,

There are given y=-3.

So,

Substitute the value -3 instead of y in given equation,

Then,

From the equation,

[tex]4y^2+y-9[/tex]

Put the value of y in given equation,

[tex]4y^2+y-9=4(-3)^2+(-3)-9[/tex]

Now, solve the above equation,

[tex]\begin{gathered} 4y^2+y-9=4(-3)^2+(-3)-9 \\ =4(9)-3-9 \\ =36-3-9 \\ =36-12 \\ =24 \end{gathered}[/tex]

Hence, the value of given equation is 24.

Question 4 If the vertices of ABC are A(-3,5), B(2,4). and C(-1,2), then ABC is classified as

Answers

To be able to classify the triangle you have to plot it

You can calculate the length of the sides as follows:

[tex]\begin{gathered} AC=\sqrt[]{(-1+3)^2+(5-2)^2} \\ AC=\sqrt[]{13} \end{gathered}[/tex][tex]\begin{gathered} AB=\sqrt[]{(5-4)^2+(2+3)^2} \\ AB=\sqrt[]{26} \end{gathered}[/tex][tex]\begin{gathered} BC=\sqrt[]{(2+1)^2+(4-2)^2} \\ BC=\sqrt[]{13} \end{gathered}[/tex]

Sides AC and BC are equal.

You can classify this triangle as an isosceles triangle

what will the deposit have to be if you want to have 12000 in an account that will earn 8.55% compounded weekly at the end of 5 years

Answers

Given:

The expected deposit =?

This is also referred to the principal

r = rate = 8.55%

t = time = 5years

n = we

Hi, could you please help me understand why I got some of the answers wrong?

Answers

For the figure in the right up

The two triangles have 2 equal angles and one equal side

Then it should be AAS

Triangle AOC is congruent to triangle BOC

You must write the name of the triangles with equal angles

Since < AOC = < BOC ------- Given

Since Since OC = OC ------- common side

By using the AAS theorem of congruency

Then triangle AOC is congruent to triangle BOC

For the figure in the right down

Since OX // YC, then

Since

Since OC = CB ------- Given

Then by using the AAS theorem of congruency

Triangle XCO is congruent to triangle YBC

Solve the following system of linear equations using elimination. -3x + 3y=-3 2x-y=0

Answers

The system of equations is

[tex]\begin{gathered} -3x+3y=-3\Rightarrow(1) \\ 2x-y=0\Rightarrow(2) \end{gathered}[/tex]

Since all terms in equation 1 can divide by 3, then

Divide each term in equation 1 by 3

[tex]\begin{gathered} \frac{-3x}{3}+\frac{3y}{3}=\frac{-3}{3} \\ -x+y=-1\Rightarrow(3) \end{gathered}[/tex]

Add equations (2) and (3) to eliminate y

[tex]\begin{gathered} (2x-x)+(-y+y)=(0-1) \\ x+0=-1 \\ x=-1 \end{gathered}[/tex]

Substitute x by -1 in equation (2) to find y

[tex]\begin{gathered} 2(-1)-y=0 \\ -2-y=0 \end{gathered}[/tex]

Add y to both sides

[tex]\begin{gathered} -2-y+y=0+y \\ -2+0=y \\ -2=y \\ y=-2 \end{gathered}[/tex]

The solution of the given system of equations is (-1, -2)

A new song has gone viral on the Internet. The website hosting the song uses the function f(t)=500t^2 to represent the number of daily hits over time, where t is time in days. Use the function to predict the day on which the number of daily hits reaches 1,000,000. Show your work.

Answers

We will have the following:

[tex]\begin{gathered} 1000000=500t^2\Rightarrow t^2=2000 \\ \\ \Rightarrow t=\sqrt{2000}\Rightarrow t=20\sqrt{5} \\ \\ \Rightarrow t=44.72135955... \end{gathered}[/tex]

So, on day 44 it will reach 1 000 000.

Suzan collected 560 milliliters of rainwater on Saturday. She collected 3.5 liters of rainwater on Sunday.How many total milliliters of rainwater did Suzan collect on Saturday and Sunday?A.910B.4,060C.4,600D.9,100

Answers

It's easy to see that to obtain the total of milliliters of rainwater that Suzan collected on Saturday and Sunday is the sum of the milliliters that Suzan collected each day.

The problem that we need to be careful about is the units. So we need to pass all the numbers to milliliters, we already have one in this unit then we just need to transform one:

[tex]3.5L\ast\frac{1000mL}{1L}=3500mL[/tex]

Now we can use the sum as:

[tex]mL\text{ total=}3500mL+560mL=4060mL[/tex]

Then the correct answer is B, 4060 mL.

Can you tell me what would make something a function vs. what is not a function?

Answers

Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function

Answer:

  fails the vertical line test: not a function

Step-by-step explanation:

You want to know how to tell if a relation is a function or not.

Relation

A relation is a map between values of the independent variable (input, x) and values of the dependent variable (output, y). Such a map can be represented many ways, including a table, graph, set of ordered pairs, dual number lines, or even a diagram showing inputs and outputs. The attachment shows such a diagram.

A relation does not need to be between numbers. Tokens of any kind can be used for input and output identifiers.

Function

A function is a relation in which each input corresponds (maps) to exactly one output.

The relation shown on the left of the attachment is not a function because the first (top) input item (A) maps to more than one output item (B).

When a relation is expressed as ordered pairs (x, y) or a table, it will be a function if and only if no x-value is repeated.

When a relation is expressed as a graph, it will be a function if and only if no vertical line intersects more than one point on the graph. (This is the "vertical line test.")

what digit is in the

Answers

EXPLANATION

Rounding 9177 to the nearest hundred give us the following number:

9,200

What is the probability of choosing a recheck at first and then choosing a red card with a replacement

Answers

Since there are 25 cards in the deck

Since there are 4 jacks on it 2 red and 2 black

Since the probability of an event = outcomes of events/total outcomes

Then for the first card

There are 2 red jacks for a total of 52 cards

[tex]P(r.j)=\frac{2}{52}=\frac{1}{26}[/tex]

For the second card with NO replacement

Since there are 26 red cards in the deck

Since we took out one of them for the first card, then

There are 25 red cards

Since the total is less by 1 because of the first card, then

There are 51 cards

[tex]P(r)=\frac{25}{51}[/tex]

Since and in probability means multiply, then

[tex]P(r.j&r)=\frac{1}{26}\times\frac{25}{51}=\frac{25}{1326}[/tex]

The answer is the 3rd choice 25/1326

Can you help me with this? The approximate area of the circle is (Blank) square feet. (Use 22/7 as an approximation for pi) The approximate circumference of the circle is (Blank) feet. Use 22/7 as an approximation for pi

Answers

Let's begin by listing out the given information:

10x-76=754 how do I solve this

Answers

Answer:

x=83

Step-by-step explanation:

10x-76=754

Move 76 to the other side and it becomes positive

10x=754+76

Add 754 and 76

10x=830

divide both sides by 10

10x/10=830/10

x=83

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