f the area of the rhombus below is 232 m 2, and diagonal AC = 16 m, find the length of diagonal BD.

F The Area Of The Rhombus Below Is 232 M 2, And Diagonal AC = 16 M, Find The Length Of Diagonal BD.

Answers

Answer 1

The formula for calculating the area of a rhombus is expressed as

Area = 1/2d1d2

where

d1 and d2 are the lengths of the diagonals

From the information given,

Area = 232

d1 = AC = 16

d2 = BD

Thus,

232 = 1/2 x 16 x BD

232 = 8BD

BD = 232/8

BD = 29


Related Questions

Art wants to calculate the diagonal distance across opposite corners of a rectangular parcel. The parcel is 161’ by 326’ . How long is the diagonal measurement?

Answers

Recall that the formula for the length of the diagonal of a rectangle is:

[tex]l=\sqrt[]{a^2+b^2}.[/tex]

Where a, and b are the lengths of the sides of the rectangle.

Substituting a=161´, b=326´ in the above formula we get:

[tex]\begin{gathered} l=\sqrt[]{(161^{\prime})^2+(326^{\prime})^2}, \\ l=363.5890537^{\prime}\text{.} \end{gathered}[/tex]

Answer: 363.5890537 ´.

use only commutative property of addition to rewrite the expression 619+59

Answers

Given:

Given the sum 619+59

Required: Another expression using commutative property and the simplified expression

Explanation:

The commutative property says that for any two real numbers,

[tex]a+b=b+a[/tex]

So, the expression 619+59 can also be written as 59+619, using commutative property.

Now, find the sum.

So, the sum is 678.

Final Answer: Another expression of 619+59 is 59+619 and its sum is 678.

The figure below is composed of squares and semi-circles. Find the perimeter of this shape. Show your work.

Answers

Problem

Solution

For this case we can find the perimeter of the figure with the following operation

[tex]P=(2\cdot4)+\pi(4)+(2\cdot4)+\pi(4)=2\pi(4)+8+8[/tex]

Then the final answer would be:

[tex]P=16+8\pi[/tex]

how many people are :9 or younger ?At most 60 years old ?40 to 59 ?

Answers

Given the table represents the ages of people :

We need to find the following:

1. how many people are : 9 or younger ?

As shown in the table : the ages 0 - 9 has a frequency of 8

So, the answer is : 8 people

2. How many people at most 60 years old ?

From the table : the age 60 - 69 the frequency is 10

But there is no information to specify the age 60

The answer is : NEI

3. How many people are : 40 to 59 ?

From the table :

the age 40-49 has a frequency = 9

the age 50-59 has a frequency = 6

So, the answer is 9 + 6 = 15 people

The amount of garbage, G produced by a city with population p is given by G = f ( p ) . G is measured in tons per week, and p is measured in thousands of people. The town of Tola has a population of 45,000 and produces 6 tons of garbage each week. Express this information in terms of the function f. f = 6 / 45 f ( 45 ) = 6 f ( 6 ) = 45

Answers

Solution:

Given that the amount of garbage G produced by a city with population p is expressed as

[tex]\begin{gathered} G=f(p) \\ where \\ G\text{ is measured in tons per week} \\ p\text{ is measured in thousands of people} \end{gathered}[/tex]

If a town Tola has a population of 45,000 and produces 6 tons of garbage per week, this implies that we substitute these parameters into the above equation.

This gives

[tex]6=f(45)[/tex]

Hence, in terms of function f, the information is expressed as

[tex]f(45)=6[/tex]

The second option is the correct answer.

12. What is the equation of a circle with center (6,-4) and radius 6?(x - 6)2 + (y + 4)2 = 6(x + 6)2 + (y - 4)2 = 36(x + 6)2 + (y - 4)2 = 6(x - 6)2 + (y + 4)2 = 36

Answers

The equation of a circle with center (h, k) and radius r is given by the following expression:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

In this case, the center of the circle is located at (6, -4), and its radius equals 6, then by replacing 6 for h, -4 for k and 6 for r, we get:

[tex]\begin{gathered} (x-6)^2+(y-(-4))^2=6^2 \\ (x-6)^2+(y+4)^2=36 \end{gathered}[/tex]

Then, the last option is the correct answer: (x - 6)^2 + (y + 4)^2 = 36

You'll have to make a series of transformations to make this parabola fit the bridge. Describethem

Answers

The transformations are as follows:

- There is firstly a vertical reflection

- There is a vertex shift from (0,0) to the (-2, 3) position (approximate)

- There is also a horizontal compression of the parabola.

Select all the statements below that are true for the following graph

Answers

From the graph given,

It is an absolute function

The following statements are true about the graph

i) The vertex is located at (2, -2)

ii) The graph has two zeros

ii) The range is [-2, ∞)

please help me solve this step by step with wrriten explanation. context and words help me

Answers

[tex]\begin{gathered} \text{If we try to rationalize} \\ \frac{5}{1+\sqrt[]{7}}\text{ using }\sqrt[]{7} \\ \\ \text{what happens is we still end up having a denominator with a radical} \end{gathered}[/tex][tex]\begin{gathered} \frac{5}{1+\sqrt[]{7}}\cdot\frac{\sqrt[]{7}}{\sqrt[]{7}},\text{ multiply by 1} \\ =\frac{5\sqrt[]{7}}{1(\sqrt[]{7})+\sqrt[]{7}(\sqrt[]{7})},\text{ distribute }\sqrt[]{7\text{ }}\text{ to numerators and denominator} \\ =\frac{5\sqrt[]{7}}{\sqrt[]{7}+7}\text{ final answer} \end{gathered}[/tex]

For the following exercises, determine the least possible degree of the polynomial function shown.

Answers

Solution

To determine the least possible degree of the polynomial function

The function has atmost n - intercepts in the horizontal

The graph turns 4 times in the above curve, hence n = 4

[tex]\begin{gathered} n+1 \\ n=\text{ number of turns} \\ 4+1=5 \end{gathered}[/tex]

Therefore the least possible degree of the polynomial = 5

Hence it is a 5 possible polynomial function

If a car travels at a speed of 45 mi/h fort hours, then travels 65 mi/h for m hours, what does theexpression 45t +65m represent?The expression represents the (select)

Answers

total distance travelled by the car (option D)

Explanation:

When speed = 45mi/h

time = t hours

when speed = 65mi/h

time = m hours

45t +65m means 45mi/h × t + 65mi/h × m

The formula that relates the speed and the time is distance:

speed = distance/time

distance = speed × time

The distance for the first speed and time = 45mi/h × t hours = 45t

The distance for the second speed and time = 65mi/h × m hours = 65m

The sum of the two distance = distance covered by the car = 45t + 65m

Hence, we can say the expression 45t +65m represents the total distance travelled by the car (option D)

BD is the perpendicular bisector of ac,ac=10and bc=7 find the length of ad and ab

Answers

Since, BD is the perpendicular bisector of AC. So, AD = 1/2(AC) = 5.

Since, BD is the perpendicular bisector of AC and BC is not equal to AC. So, triangle ABC is an isosceles triangle. Therefore, AB = BC = 7.

Find quotient of 5,433 % 8

Answers

Find the quotient of 5,433 by 8.

8 | 5,433

Divide 54 by 8. The quotient is 6. 6x8 = 48. 54 - 48 = 6.

6

8 | 5433

-48

-------

63

63 by 8 is 7. 7x8 = 56. 63 - 56 = 7.

67

8 | 5433

-48

-------

63

-56

--------

73

73 by 8 is 9. 9x8 = 72. 73 - 72 = 1. The final step is:

679 <== Quotiet

8 | 5433

-48

-------

63

-56

--------

73

-72

-------------

1 <== Remainder

Line Segment AC is 10 centimeters (cm) long, Point M is the midpoint of AC.What will happen to the length of AC if Point A is moved so that the length of AM is squared and the length of MC remains the same?The length of AC will triple.The length of AC will double.The length of AC will be squared.The length of AC will be five times as large.

Answers

We know that AC is 10 centimeters long, and M is the midpoint of AC.

If we move point A as the problem says, we have.

As you can observe, the length of AC is triple.

Hence, the right answer is the first option: The length of AC will triple.

Please help me with these 2 questions they are both solved problems that go together with one huge problem so please answer both thank you

Answers

1).

r = 11 in

The diameter is twice the radius, so:

d = 2*11 = 22 inches

2).

d = 18 inches

The radius is half the diameter, so:

r = 18/2 = 9 inches

grandma has $250000 to invest. she divides her money into two accounts. one account is in ultra-safe treasury bills paying 4% interest, and the other is in riskier corporate bonds paying 6%. if she needs $12,000 per year in income from her investments, how much should she invest in each account

Answers

for the ultra-safe treasury bills:

[tex]\begin{gathered} I_1=PV\cdot r\cdot t \\ I_1=x\cdot0.04\cdot1 \\ I_1=0.04x \\ \text{where:} \\ x=\text{amount 1} \end{gathered}[/tex]

For riskier corporate bonds:

[tex]\begin{gathered} I_2=PV\cdot r\cdot t \\ I_2=y\cdot0.06\cdot1 \\ I_2=0.06y \\ \text{Where:} \\ y=\text{amount 2} \end{gathered}[/tex]

she needs $12,000 per year, so:

[tex]\begin{gathered} I_1+I_2=12000 \\ 0.04x+0.06y=12000 \end{gathered}[/tex]

grandma has $250000 to invest, therefore:

[tex]x+y=250000[/tex]

Let:

[tex]\begin{gathered} x+y=250000\text{ (1)} \\ 0.04x+0.06y=12000\text{ (2)} \\ \text{From (1) solve for x:} \\ x=250000-y\text{ (3)} \\ \text{ Replace (3) into (2)} \\ 0.04(250000-y)+0.06y=12000 \\ 10000-0.04y+0.06y=12000 \\ 0.02y=12000-10000 \\ 0.02y=2000 \\ y=\frac{2000}{0.02} \\ y=100000 \end{gathered}[/tex]

Replace y into (3):

[tex]\begin{gathered} x=250000-100000 \\ x=150000 \end{gathered}[/tex]

Therefore, grandma needs to invest $150000 in ultra-safe treasury bills, and

I need help question

Answers

[tex]f(x)=x^2-4x-94[/tex]

The diffrentiated function will be

[tex]2x-4[/tex]

RULES FOR DIFFERENTIATION

[tex]\begin{gathered} y=x^n \\ \frac{dy}{dx}=nx^{n-1} \end{gathered}[/tex]

Also

[tex]\begin{gathered} y=kx \\ \frac{dy}{dx}=k \end{gathered}[/tex]

Also

[tex]\begin{gathered} y=k \\ \frac{dy}{dx}=0 \end{gathered}[/tex]

ring×heart=hathat×2=heartheart-ring=1/4

Answers

Let's begin by identifying key information given to us:

[tex]undefined[/tex]

In a study of 200 students under 25 years old one-fifth have not yet learned to drive. What percentage can drive?

Answers

[tex]\begin{gathered} \text{Total number of students is }\Rightarrow200 \\ \frac{1}{5}\text{ can't drive}\Rightarrow200\times\frac{1}{5}=40\text{ students can't drive} \\ Number\text{ of students tthose can drive}\Rightarrow200-40=160\text{ students} \\ So, \\ \text{percentage}\Rightarrow\frac{160}{200}\times100=80\text{ \% students can drive.} \end{gathered}[/tex]

Dane is using two differently sized water pumps to clean up flooded water. The larger pump can
remove the water alone in 240 min. The smaller pump can remove the water alone in 400 min.

How long would it take the pumps to remove the water working together?
minutes

Answers

The rate of work obtained from the 240 and 400 minutes it takes for the large and small pumps to remove the water alone respectively, gives the duration it takes for the two pumps to remove the water working together as 150 minutes.

What is the rate of work formula?

The rate of work in completing a project is given by the reciprocal of the time it takes to complete the project.

The given parameters are;

The time it takes the larger pump to remove the water, A = 240 minutes

The time it takes the smaller pump to remove the water, B = 400 minutes

The rate of doing work by the larger pump = [tex]\frac{1}{240}[/tex]

The work rate of the smaller pump = [tex]\frac{1}{400}[/tex]

The rate of work of the two pumps combined, [tex]\frac{1}{r}[/tex], is therefore;

[tex]\dfrac{1}{A} +\dfrac{1}{B} = \dfrac{1}{r}[/tex]

Where;

r = The time it takes for the two pumps to remove the water together

Which gives;

[tex]\dfrac{1}{240} +\dfrac{1}{400} = \dfrac{1}{150} = \dfrac{1}{r}[/tex]

∴ r = 150

The time it takes for the two pumps to remove the water together is 150 minutes

Learn more about rate of work here:

https://brainly.com/question/29242115

#SPJ1

Answer: 150 min

(I completed the question)                  

5 Ramon sched 13 -6 She said she thought about taking away and then 3 more from 13. CanRamon do this? Show a diagram and write an equation to show what this solution path would look like

Answers

we know that

14-7=7 --------> given problem

so

we have

14-8

Rewrite the expression

14-(7+1)

14-7-1

Remember that

14-7=7

substitute

7-1

6

we have

12-6=6

so

12-7

rewrite

12-(6+1)

12-6-1

substitute

6-1

5

we have

13-6

13-(3+3)

13-3-3

10-3

7

find the equation of line with points (3, 3) that passes through a slope of 2/3

Answers

hello

the standard equation of a straight line is given as y = mx + b

y = y-coordinate

x = x-coordinate

m = slope

b = intercept

the points given are (3, 3) and the slope = 2 / 3

y = mx + b

y = 3

x = 3

let's substitute in our values and solve for b

[tex]\begin{gathered} y=mx+b \\ 3=\frac{2}{3}(3)+b \\ 3=2+b \\ b=3-2 \\ b=1 \end{gathered}[/tex]

since we have the value of the slope, we can simply write the equation from y = mx + b to y = 2/3x + 1

[tex]y=\frac{2}{3}x+1[/tex]

this is the equation of the line.

but we can further simplify this by looking for the LCM of the denominators of the independent variables

[tex]\begin{gathered} y=\frac{2}{3}x+1 \\ y=\frac{2x+3}{3} \\ \text{cross multiply both sides} \\ 3y=2x+3 \end{gathered}[/tex]

the equation can be rewritten as 3y = 2x + 3

Find the volume of the rectangular prism O 8 cubic units O 4 cubic units 6 cubic units O 3 cubic units

Answers

Given data:

The given rectangular prism.

The volume of the given prism is,

[tex]\begin{gathered} V=6(\text{volume of a cube)} \\ =\text{ 6(1 cubic-units)} \\ =\text{ 6 cubic-unis} \end{gathered}[/tex]

evaluate the following expression 2 * 1 + 2 * 24/4

Answers

[tex]\begin{gathered} 2\times1+2\times\frac{24}{4} \\ =(2\times1)+(2\times6) \\ =2+12 \\ =24 \end{gathered}[/tex]

using PEDMAS/ BODMAS

division is executed first followed by multiplication then addition

I have no clue how to graph inequalities and find the solution

Answers

In the graph we can see two line y=2 and y=x.

Also, we know that there is a system of inequalities and the blue area in the graph represent the solutions for the system.

We can see that the blue area is above the line y=2, thats mean one inequality is:

[tex]y\ge2[/tex]

So, any points that y-coordinate is greater than or equal than 2 satisfy the inequality.

Also we can see that the blue area is bellow the line y=x and the line is a dotted line, this last means the inequality do not take take value in the line. So, the second inequation is:

[tex]ySo, the points that satisfy the system of inequalities are above the line y=2 and bellow the line y=x and not touch the line y=x.

a. 20% of 60 is ____ d. 50% of 90 is b. 25% of _____ Is 6 e. 10% of _ is 7c. _____% of 100 is 14 f. 30% of 70 is _

Answers

20% of 60 is 12

25% of 24 is 6

14% of 100 is 14

50% of 90 is 45

10% of 70 is 7

30% of 70 is 21

a. 20% of 60 is 12 because 60x20/100 = 60x0.2 = 12

b. 25% of 24 is 6 because 6x100/25 = 24

c. 14% of 100 is 14 because 100x(14/100) = 14

d. 50% of 90 is 45 is 14 because 90x50/100 = 45

e. 10% of 70 is 7 because 7x100/10 = 70

f. 30% of 70 is 21 because 70x30/100 = 21

n% of m is (n x m)/100

For example: 20% of 60 is (20 x 60)/100 = 1200/100 = 12

please help me 60 points please show all work this is due in 15 minutes5x-(3x-6)=182(3x-4)=102x+7=5x+16x/3-8=-23x – 6 = -12x/-3=8

Answers

[tex]\begin{gathered} 5x-(3x-6)=18 \\ 5x-3x+6=18 \\ 2x+6=18 \\ 2x=18-6 \\ 2x=12 \\ x=\frac{12}{2} \\ x=6 \end{gathered}[/tex][tex]\begin{gathered} 2x+7=5x+16 \\ 2x-5x=16-7 \\ -3x=9 \\ x=\frac{9}{-3} \\ x=-3 \end{gathered}[/tex][tex]\begin{gathered} \frac{x}{3}-8=-2 \\ \frac{x}{3}=-2+8 \\ \frac{x}{3}=6 \\ x=18 \end{gathered}[/tex][tex]\begin{gathered} 3x-6=-12 \\ 3x=-12+6 \\ 3x=-6 \\ x=-\frac{6}{3} \\ x=-2 \end{gathered}[/tex][tex]\begin{gathered} \frac{x}{-3}=8 \\ x=(8)(-3) \\ x=-24 \end{gathered}[/tex]

I am thinking of a number. It has two digits. When I reverse the digits and then add the new number to the original number I get 33. What is my number?

Answers

I am thinking of a number. It has two digits. When I reverse the digits and then add the new number to the original number I get 33. What is my number?

Let

the number xy

so

Reverse the digits yx

xy+yx=33

10x+10y=30 ------> equation 1

y+x=3 ----> equation 2

solve the system by graphing

the syste

Frank's rectangular box of toys has a perimeter of 30 inches. The length is twice as long as the width. Which of the following expressions could be a major step in finding the length? A. Length times Width equals AreaB. 2 times Width plus 2 times Width plus Width plus Width equals 30C. Perimeter equals Width plus Width plus Width plus WidthD. 2 times Length equals Width

Answers

From the given problem,

length is twice as long as the width

length = 2 x width

Note that the perimeter is :

[tex]P=2W+2L[/tex]

where W and L are the width and length respectively.

Since L = 2W

Perimeter will be :

[tex]\begin{gathered} P=2W+2(2W) \\ P=2W+4W \\ P=6W \end{gathered}[/tex]

Perimeter is equal to 30 inches :

[tex]6W=30in[/tex]

From the given choices, only B satisfies this condition.

2W + 2W + W + W = 30

6W = 30

Therefore, the answer is B.

I'm not entirely sure what I'm supposed to be doing

Answers

The intercept between both lines, represents the solution to the system compounded by the equations for both lines. It means (3,4) is the solution to both lines A and B.

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