Both integers have negative values
Explanation
Let
x and y represents the number
so, the options are
[tex]\begin{gathered} +\text{ + +} \\ +\text{ + -} \\ -\text{ + +} \\ -\text{ +-} \end{gathered}[/tex]a) Both integers have negative values Both integers
[tex]-x-y=-(x+y)\rightarrow you\text{ will always get a negative number}[/tex]b) Both integers have positive values
[tex]x+y=+\text{ + += you will always get a positive number}[/tex]c)One integer has a positive value, and one integer has a negative value
[tex]\begin{gathered} -x+y\text{ or x-y} \\ the\text{ sign of the result depends on the greates absolute value, it means the answer will have the same of the bigger number( absolute value)} \end{gathered}[/tex]d)The values of the two integers are opposites
as the point C , the sign depends on the bigger number
for example
[tex]\begin{gathered} 8-5=3\text{ positive because 8 is the bigger} \\ 5-8=-3\text{ negative because (-8) is has the bigger absolute value} \end{gathered}[/tex]so, the answer is Both integers have negative values
I hope this helps you
y varies directly as x. y =84 when x=6. Find y when x=12y= ?
If y varies directly as x, we have that
[tex]y\propto x[/tex]Then
[tex]y=kx(where\text{ k is a constant\rparen}[/tex][tex]\begin{gathered} When\text{ y=84 , x= 6} \\ y=kx \\ 84=6k \\ k=\frac{84}{6}=14 \end{gathered}[/tex]The relationship between x and y is given as
[tex]\begin{gathered} y=kx \\ y=14x \end{gathered}[/tex]Therefore when x= 12, y=?
[tex]\begin{gathered} y=14x \\ y=14\times12=168 \end{gathered}[/tex]Hence, the value of y when x = 12 is 168
Final answer: y = 168
To solve for x, you divide each side by what number?(4.5)x = 264.5456
Answer
4.5
Step-by-step explanation
Given the equation:
[tex]4.5x=26[/tex]Dividing at both sides by 4.5, we get:
[tex]\begin{gathered} \frac{4.5x}{4.5}=\frac{26}{4.5} \\ x=\frac{52}{9} \end{gathered}[/tex]Answer:
Divide each side by 4.5
Step-by-step explanation:
(4.5)x = 264.5456
We want to isolate x
Divide each side by 4.5
(4.5)x / 4.5 = 264.5456/ 4.5
x =58.78791
Solve 3x2 + 18x + 15 = 0 by completing the square
Step 1
Given;
[tex]3x^2+18x+15=0[/tex]Required; To solve by completing the square method.
Step 2
Subtract 15 from both sides of the equation.
[tex]\begin{gathered} 3x^2+18x+15-15=0-15 \\ 3x^2+18x=-15 \end{gathered}[/tex][tex]\begin{gathered} Divide\text{ all terms by 3} \\ x^2+6x=-5 \end{gathered}[/tex]Find half of the coefficient of x (i.e 6) and square it
[tex](\frac{6}{2})^2=3^2[/tex]Add it to both sides
[tex]\begin{gathered} x^2+6x+3^2=-5+3^2 \\ Use\text{ perfect square} \\ (x+3)^2=-5+9 \\ (x+3)^2=4 \\ x+3=\pm\sqrt{4} \\ x=\operatorname{\pm}\sqrt{4}-3 \end{gathered}[/tex][tex]\begin{gathered} x=\pm2-3 \\ x=-1\text{ or -5} \end{gathered}[/tex]Answer;
[tex]x=-1,-5[/tex]finding the vertex, intercepts, and axis of symmetry from the graph of a parabola
Solution
Explanation:
Given:
(b) Equation of the axis of symmetry
[tex]\begin{gathered} x=-8 \\ x=4 \end{gathered}[/tex][tex]\begin{gathered} x=-8,x=4 \\ (x+8)(x-4)=0 \\ x^2-4x+8x-32=0 \\ x^2+4x-32=0 \\ y=x^2+4x-32 \end{gathered}[/tex]where
[tex]\begin{gathered} y=ax^2+bx+c \\ a=1,b=4,c=-32 \end{gathered}[/tex]The formula for the axis of symmetry and the x value of the vertex
[tex]x=-\frac{b^2}{2a}[/tex]Plug in the value
[tex]x=\frac{-(4)^}{2}=-2[/tex](d) To find the y value of the vertex, substitute 1 for x in the equation.
[tex]\begin{gathered} y=x^2+4x-32 \\ y=(-2)+4(-2)-32 \\ y=-2-8-32 \\ y=-42 \end{gathered}[/tex]The vertex is (-2 , -42) Since a > 0 the vertex is the minimum point and the parabola opens upward.
Hence the vertex = (-2 , -42)
This table shows how many sophomores and juniors attended two school events.What is the probability that a randomly chosen person from this group is a sophomore and attended the jazz band concert?Round your answer to two decimal places.
Given:
Number of sophomores attended jazz band concert = 35
Total number of students = 137
Required: Probability that a randomly chosen person from this group is a sophomore and attended the jazz band concert.
Explanation:
The formula to find probability is
[tex]p=\frac{\text{Number of favorable outcomes}}{\text{ Total number of outcomes}}[/tex]Probability that a randomly chosen person from this group is a sophomore and attended the jazz band concert
[tex]\begin{gathered} =\frac{\text{Number of sophomores attended jazz band concert}}{\text{ Total number of students in this group}} \\ =\frac{35}{137} \\ =0.26 \end{gathered}[/tex]Option D is correct.
Final Answer: Probability that a randomly chosen person from this group is a sophomore and attended the jazz band concert is 0.26.
use the circle unit to evaluate csc(-/2)
The definition of the cosecant function is
[tex]\csc \theta=\frac{1}{\sin \theta}[/tex]Therefore,
[tex]\Rightarrow\csc (-\frac{\pi}{2})=\frac{1}{\sin (-\frac{\pi}{2})}[/tex]To find sin(-pi/2), use the diagram below.
Consider that the circumference has a radius equal to 1. Then, the coordinates of the orange point are (0,-1). Furthermore, the points on the circumference are given as (cos(theta), sin(theta)); therefore,
[tex]\begin{gathered} \Rightarrow(0,-1)=(\cos (-\frac{\pi}{2}),\sin (-\frac{\pi}{2})) \\ \Rightarrow\sin (-\frac{\pi}{2})=-1 \\ \Rightarrow\csc (-\frac{\pi}{2})=\frac{1}{-1}=-1 \\ \Rightarrow\csc (-\frac{\pi}{2})=-1 \end{gathered}[/tex]Thus, the answer is csc(-pi/2)=-1
Bob had three 10' lengths of conduit. If he used a total of 13.75' of conduit to install a motor, how much total conduit does he have left?
Given that Bob had three 10' lengths of conduit and he used a total of 13.75' of conduit to install a motor.
To find how much total conduit he has left we would subtract the initial from what was used.
The initial length = three 10' lengths = 30'
Length used = 13.75'
[tex]\begin{gathered} \text{Conduit left = Initial length - length used} \\ \text{Conduit left }=\text{ 30 - 13.75} \\ =16.25 \\ \end{gathered}[/tex]
The total conduit he has left is
Answer: 16.25 feet
If you can help me with this I would be thankful
When a function is compose by its inverse, the result is its original input. Therefore,
[tex]f(f^{-1}(x))=x[/tex]TED BORROWED $1,200 FOR TWO YEARS AND HE MADE MONTHLY PAYMENTS. IF THE TOTAL FINANCE CHARGE IS $175.92 WHAT IS THE APR?
Given: Ted Borrowed $1200 for two years and made monthly payments. The total finance charge is $175.92
Required: To determine the Annual Percentage Rate.
Explanation: The formula for APR is as follows-
[tex]APR=\lbrace\frac{(Fees+Interest)}{\frac{Principal}{n}}\frac{}{}\times365\rbrace\times100[/tex]where n is the total number of days in the loan term.
Here, the total finance charge is $175.92, and the Principal amount is $1200.
Also, n=2 years or 730 days. Substituting these values into the formula as-
[tex]APR=(\frac{175.92}{\frac{1200}{730}}\times365)\times100[/tex]Further solving as-
[tex]APR=7.29\%[/tex]Final Answer: The Annual Percentage Rate is 7.29%
Leave K in fraction form or round to at least 3 decimal places. Round off your final answer to the nearest hundredth.
By definition, an equation of a Combined Variation has the following form:
[tex]z=k(\frac{x}{y})[/tex]Where "k" is the Constant of Variation.
In this case, you know that the resistance "R" of a wire varies directly as its length and inversely as the square of its diameter.
Then, let be "R" the resistance of the wire (in ohms), "l" its length of the wire (in feet), and "d" its diameter (in inches).
Therefore, you can set up that the equation has this form:
[tex]R=k(\frac{l}{d^2})[/tex]According to the information given in the exercise, when:
[tex]\begin{gathered} l=3300 \\ d=0.16 \end{gathered}[/tex]The resistance is:
[tex]R=10357[/tex]Then, you can substitute values into the equation and solve for "k":
[tex]\begin{gathered} 10357=k(\frac{3300}{(0.16)^2}) \\ \\ (10357)(\frac{(0.16)^2}{3300})=k \end{gathered}[/tex][tex]k\approx0.080[/tex]Therefore, you can set up the following equation that represents this situation (using the value of "k"):
[tex]R=0.080\cdot\frac{l}{d^2}[/tex]Hence, if:
[tex]\begin{gathered} l=2900 \\ d=0.15 \end{gathered}[/tex]You can substitute these values into the equation and then evaluate, in order to find the corresponding resistance. This is:
[tex]\begin{gathered} R=0.080\cdot\frac{(2900)}{(0.15)^2} \\ \\ R\approx10311.11 \end{gathered}[/tex]Therefore, the answer is:
[tex]10311.11\text{ }ohms[/tex]
is this left continuous at x=2?from those intervals pleases answer the part of the question asking if left or right continuous and where
Not, the left graph is discontinuous in x=2, the kind of discontinuity is removable discontinuity. It is not continuous because in x=2 there us a abrupt change in the function value.
To determine if the function is left or right continuous you identify if the function in a jump discontionuity has the defined point on the left or on the right.
The function given in number 11 has a jump discontinuity at x=3, as the defined point is on the part of the graph on the left, you say the function is left continuous at x=3.
Answer: left continuous at endpoint x=3The figure below is a right rectangular pyramid. Which of the following is not a cross-section from a right rectangular pyramid?
Answer:
(B)
Explanation:
The base of a right rectangular pyramid is a rectangle, so if we cut the pyramid with a plane that is parallel to the base, we will get a cross-section with a rectangular form or (A)
We can also cut the pyramid with a plane that is perpendicular to the base, In this case, we will get a cross-section with a triangular form (C)
Finally, we can cut the pyramid with a transversal plane and get a cross-section with the form of a trapezoid (D)
Therefore, the answer is (B) because a square is not a cross-section for the right rectangular pyramid.
Write a simplified expression for the model below. 1 1 -1 -1 х X X х х -X -X 1 1 ו-ווו-| 1 1 1 -1 ||-1
we have the following:
[tex]\begin{gathered} 4\cdot(x)+2\cdot(-x)+6\cdot(1)+6\cdot(-1) \\ 4x-2x+6-6 \\ 2x \end{gathered}[/tex]therefore, the answer is 2x
Analyze the diagram below and complete the instructions that follow.F45E28DSolve AEFD. Round the answers to the nearest hundredth.
Since this is a right triangle we can use trig functions
First we can find the length of the hypotenuse using the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
28^2 + 45^2 = c^2
784+2025 = c^2
2809 = c^2
Taking the square root of each side
sqrt(2809) = sqrt(c^2)
53 = c
The hypotenuse, DR = 53
Then we can find the measurements of the angles
sin F = opp/ hyp
sin F = 28/53
Taking the inverse sin of each side
sin D = opp/ hyp
sin D = 45/53
Taking the inverse sin of each side
hello) i need some help with b) include an explanation if not a problem, thanks in advance)
What would happen if X doesn't lie on OM? If it is true that X lies on OM, if we suppose the opposite then we should have a contradiction, so the only way the contradiction doesn't happen is that it is true
Statements1. We know that BX:XA = 1:2
2. We know that M is the middle point between B and P
We need to prove that X lies on OM
Let's suppose X doesn't lie on OM
By 2, we know that 2BM = BP
If X doesn't lie on OM then the intersection between OM and BA is not X
Let's say the line that goes from O to the line BP and intersects BA on X is OX', where X'≠M
Food Express is running a special promotion in which customers can win a free gallon of milk with their food purchase if there is a star on their receipt. So far, 219 of the first 264 customers have not received a star on their receipt. What is the experimental probability of winning a free gallon of milk?options: 3/11....15/88....73/88.....1/78
Solution:
Experimental probability is a probability that is determined on the basis of a series of experiments. A random experiment is done and is repeated many times to determine their likelihood, and each repetition is known as a trial.
[tex]\begin{gathered} P(E)=\frac{n(E)}{n(T)} \\ \\ Where; \\ n(E)=\text{ number of event} \\ \\ n(T)=\text{ total outcome} \end{gathered}[/tex]If 219 of the first 264 customers have not received a star on the receipt, then a customer that would win a free gallon of milk would be among (264 - 219) customers. Thus;
The experimental probability of winning a free gallon of milk is;
[tex]\begin{gathered} =\frac{264-219}{264} \\ \\ =\frac{45}{264} \\ \\ =\frac{15}{88} \end{gathered}[/tex]CORRECT OPTION:
[tex]\frac{15}{88}[/tex]
Which equation is represented by the table of values below
Choosing two points: A(0, 3) and B(3, -9)
• Sope (m):
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}=\frac{-9-3}{3-0}=\frac{-12}{3}=-4 \\ m=-4 \end{gathered}[/tex]• Find b: choosing point A
y = mx + b
[tex]\begin{gathered} y=mx+b \\ 3=-4\cdot(0)+b \\ b=3 \end{gathered}[/tex]• Education:
[tex]\begin{gathered} y=m\cdot x+b \\ y=-4x+3 \end{gathered}[/tex]
Answer: A. y= -4x + 3
I could use some help on math I’m really struggling
We need to find how much will be left after 6 half-lives of a radioactive isotope starting with 130g.
One way to write the amount N of radioactive isotope left after a time t, with an initial amount N₀ and a half-life τ is:
[tex]N=N_0\left(\frac{1}{2}\right)^{t\text{ /}\tau}[/tex]Notice that when t = τ, we have:
[tex]N=\frac{N_0}{2}[/tex]In this problem, we have:
[tex]\begin{gathered} N_0=130g \\ \\ t=6\tau \end{gathered}[/tex]Then, we obtain:
[tex]N=130g\left(\frac{1}{2}\right)^{6\tau\text{ /}\tau}=130g\left(\frac{1}{2}\right)^6=\frac{130g}{64}\cong2\text{ g}[/tex]Therefore, rounding to the nearest gram, the answer is 2 grams.
a bank account principal is $1,000 and accumulate yearly interest at 6%. assuming that no withdrawals are made, use the compound interest formula to compute the amount in the account after 10 yearsIf interest is compounded yearly, what is the amount of money after t = 10 years?
The rule of the compounded interest is
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]A is the new amount
P is the initial amount
r is the rate in decimal
n is the number of periods per year
t is the time in years
Since the principal is $1000, then
P = 1000
Since the yearly interest rate is 6%, then change it to decimal by dividing it by 100
r = 6/100 = 0.06
Since the interest is compounded yearly, then
n = 1
Since the time is 10 years, then
t = 10
Substitute them in the rule above
[tex]\begin{gathered} A=1000(1+\frac{0.06}{1})^{(1)(10)} \\ A=1000(1.06)^{10} \\ A=1790.847697 \end{gathered}[/tex]The amount of money in the account after 10 years is $1790.847697
What did I do wrong? Need help with this equation
Recall that :
1) A function
[tex]f\mleft(x\mright)[/tex]translated n-units to the left is
[tex]f\mleft(x-n\mright).[/tex]2) A function
[tex]h\mleft(x\mright)[/tex]translated m-units up is:
[tex]h\mleft(x\mright)+m.[/tex]3) A function g(x) reflected over the x-axis is:
[tex]-g(x)\text{.}[/tex]The parent function is:
[tex]y=\sqrt[]{x}\text{.}[/tex]The function of the graph of the above function translated horizontally 3 units to the left is:
[tex]y=\sqrt[]{x+3}.[/tex]The function of the graph of the above function translated vertically 4 units up is:
[tex]y=\sqrt[]{x+3}+4.[/tex]The function of the graph of the above function reflected over the x-axis is:
[tex]y=-(\sqrt[]{x+3}+4)=-\sqrt[]{x+3}-4.[/tex]Finally, the function of the graph of the above function stretched vertically by a scale factor of 2 is:
[tex]y=-2\sqrt[]{x+3}-4.[/tex]Answer:
The graph of the function has a horizontal translation Left 3 and vertical translation Up 4. The graph has been reflected over the x-axis and has been Vertically stretched.
Find both the x-intercept and the y-intercept of the line given by this equation 7.2x-9.6y-5.7=0
To find the x intercept of the line we have to replace y for 0 and solve for x:
[tex]\begin{gathered} 7.2x-9.6y-5.7=0 \\ 7.2x-9.6(0)-5.7=0 \\ 7.2x-5.7=0 \\ 7.2x=5.7 \\ x=\frac{5.7}{7.2} \\ x=0.79 \end{gathered}[/tex]To find the y intercept of the line we have to replace x for o and solve for y:
[tex]\begin{gathered} 7.2x-9.6y-5.7=0 \\ 7.2(0)-9.6y-5.7=0 \\ -9.6y-5.7=0 \\ -9.6y=5.7 \\ y=\frac{5.7}{-9.6} \\ y=-0.59 \end{gathered}[/tex]It means that the x intercept is 0.79 and the y intercept is -0.59.
what is the density of the oak board? show your work.
I think this is a physics problem.
I'll read it
a) A rectangular prism and a cylinder
b) Volume of the log = pi*r^2 x h
Volume of the log = 3.14*5^2* 30
Volume of the log = 2355 in^3
density = weight / volume
density = 4263 / 2355
density = 1.81 lb/in^3 This is the result
I need help with this assignment!! I already did A and B! I need help with the rest.
Given:
The roller-coster is moving in the trajectory of this curve
[tex]f(x)=3x^4-18x^3-21x^2+144x-108[/tex]Step by step solution:
To solve this complete problem we need to draw the estimated graph of this function, so that we can answer this question easily.
First of all, we need to find the roots of the given equation,to plot the curve:
let us put the random numbers that may satisfy the equation:
Let us put x = 1:
[tex]\begin{gathered} f(x)=3x^4-18x^3-21x^2+144x-108 \\ \\ f(1)=3-18-21+144-108 \\ \\ f(1)=\text{ 0} \end{gathered}[/tex]From here we can say that 1 is the root of the equation.
We will now divide this function from (x-1), so that we can get the cubic equation:
We will use long division method for division, the result we get after the division is:
[tex]f(x)=(x-1)(3x^3-15x^2-36x+108)[/tex]We will now try to factorize the cubic equations, by putting the random numbers that may satisfy the equation:
let us put x = 2:
[tex]\begin{gathered} f(x)=(x-1)(3x^3-15x^2-36x+108) \\ \\ f(2)=(2-1)(3(2)^3-15(2)^2-36(2)+108) \\ \\ f(2)=(1)(24\text{ }-\text{ 60 - 72 +108}) \\ \\ f(2)=0 \end{gathered}[/tex]From here we can say that f(2) is also the root of this cubic
We will now divide the cubic equation with (x-2), so we can break the cubic into quadratic:
Upon division the cubic equation break into following factors:
[tex]\begin{gathered} =(x-2)(3x^2-9x-54) \\ \\ which\text{ further simplified into:} \\ \\ =(x-2)(x-6)(x+3) \end{gathered}[/tex]From here we have found out four roots of the initial function that are:
x = 1,2,6,-3
Now we can easily plot the curve:
This is estimated curve, there are no sharp edges.
On the basis of this curve, we can easily answer all the questions related to this curve.
The radius of a quarter circle is 3 millimeters. What is the quarter circle's perimete r=3 mm ude 3.14 for .. millimeters Submit can you explain
Given:
The radius of the quarter circle is given 3 mm.
To find:
The perimeter of the quarter circle.
Solution:
It is known that the perimeter of the quarter circle is given by:
[tex]2r+\frac{\pi r}{2}[/tex]So, the perimeter of the quarter circle:
[tex]\begin{gathered} P=2r+\frac{\pi r}{2} \\ =2(3)+\frac{3.14\times3}{2} \\ =6+4.71 \\ =10.71 \end{gathered}[/tex]Thus, the perimeter of the quarter circle is 10.71 mm.
Write the point-slope form of the equation of the line that passes through the point (-1, 5) and has a slope of -1.
a. Using variables, write out the formula for the point-slope form of the equation.
b. Identify the values for m, x1, and y1.
c. Fill these values into the point-slope form of the equation from part (a), and simplify as needed.
Use the box provided to submit all of your calculations and final answers. Simplify the answer as needed.
[tex](\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{- 1}(x-\stackrel{x_1}{(-1)}) \implies {\large \begin{array}{llll} y -5= -(x +1) \end{array}}[/tex]
Please help me this question I couldn’t understand it please.
Given:
Length of a rectangle is a+1
width of a rectangle is a
[tex]\begin{gathered} \text{Perimeter}=2(a+1+a) \\ =2(2a+1) \\ =4a+2 \end{gathered}[/tex]reshma is making a necklace using green beads and purple beads in a ratio represented on the following double number line fill in the missing values on the diagram and then answer the following question
From the double number line, we can see that the corresponding number of Green and Purple beads needed in each case are stated.
[tex]\begin{gathered} 4\text{ Gre}en\text{ }\rightarrow5\text{ Purple} \\ 8\text{ Gr}een\text{ }\rightarrow10\text{ Purple} \\ \cdot \\ \cdot \\ 20\text{ Gre}en\text{ }\rightarrow\text{ 25 Purple} \end{gathered}[/tex]Therefore, for 20 Green beads she will need to use 25 Purple Beads.
[tex]25\text{ Purple Beads}[/tex]Six times the sum of a number and 7 is 3.
and solve x
[tex]\begin{gathered} x+7=\frac{3}{6} \\ \\ x=\frac{1}{2}-7 \\ \\ x=-\frac{13}{2}=-6.5 \end{gathered}[/tex]the number is -6.5
The length of a rectangle is 5 inches more than the width. The perimeter is 42 inches. Find the length and the width of the rectangle.The width of the rectangle is ___ cubit inches, square inches or inches ? and the length of the rectangle is ____ cubit inches, square inches or inches?
Given
perimeter = 42 inches
length of a rectangle is 5 inches more than the width.
Find
width, length
Explanation
Let width of rectangle = x inches
length = 5 + x
Perimeter of rectangle = 2 (l + b) = 2(5+x+x) = 42
[tex]\begin{gathered} 2\times(5+x+x)=42 \\ 5+2x=21 \\ 2x=16 \\ x=8 \end{gathered}[/tex]width = 8 inches
Length = 5 + 8 = 13 inches
Final Answer
The width of the rectangle is 8 inches.
The length of the rectangle is 13 inches.
Using the table, what is the average daily balance of the credit card for the December 1 - December 31 billing period? Round your answer to the nearest cent. Do not include a dollar sign or comma in your answer. For example, $5,678.00 should be entered as 5678.00.
Answer
ADB= 8145.16
Problem Statement
The question tells us to calculate the Average Daily Balance (ADB) for a period of December 1 - December 31 using the balances given in the table.
Method
To find the Average Daily Balance (ADB), we apply the formula given below:
[tex]\text{ADB}=\sum ^n_{i=1}\frac{(\text{Balance after Day}_i)}{Total\text{ number of days in Billing cycle}}[/tex]The question has given us the Balance after Day 1 - Day 10 (10 days) to be 11,000. We are also given that the Balance from Day 11 to Day 20 (10 days) is 8000, from Day 21 to 30 (10 days), the Balance is 5500 while Day 31 (1 day) with a balance of 7500.
The total number of days in the billing cycle is from Day 1 to Day 31, which is 31 days altogether.
Thus we can use the above formula to find the Average Daily Balance (ADB).
Implementation
[tex]\begin{gathered} \text{ADB}=\frac{(10\times11,000)+(10\times8,000)+(10\times5,500)+(1\times7,500)}{31} \\ \\ \text{ADB}=\frac{252,500}{31} \\ \\ \therefore ADB=8,145.16 \end{gathered}[/tex]
Final Answer
The Answer is:
ADB= 8145.16