We have the expression:
[tex]x^2+3=19\Rightarrow x^2=16[/tex][tex]\Rightarrow x=\pm4[/tex]Translate the sentence into an inequality. A number w increased by 8 is greater than −16.
Input data
A number w increased by 8 is greater than −16.
Procedure
A number w increased by 8...
[tex]w+8[/tex]is greater than −16.
[tex]w+8>-16[/tex]graph the equation y= -x² + 10x - 16. you must plot 5 points including the roots and the vertex
Given the function:
[tex]y=-x^2+10x-16[/tex]The graph of the function is plotted and attached below:
From the graph:
• The roots are (2,0) and (8,0).
,• The vertex is a maximum that occurs at (5,9)
,• The graph intersects the y-axis at (0,-16).
The other points are added as a guide when plotting your own graph.
A table of values of a linear function is shown below. Find the output when the input is n. input: 1 2 3 4 n output: 3 1 -1 -3
We have the points of a linear function and need to find the equation that represent.
Because it is a linear function, we can find its equation with two points.
We get the points (1,3) and (2,1):
[tex]\begin{gathered} We\text{ call input as x and output as y:} \\ P_1=(x_1,y_1)=(1,3),P_2=(x_2,y_2)=(2,1) \\ y-y_1=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1) \\ y-3=\frac{(1-3)}{(2-1)}(x-1) \\ y-3=-\frac{2}{1}(x-1)=-2(x-1) \\ y=-2x-2\cdot(-1)+3 \\ y=-2x+2+3 \\ y=-2x+5 \end{gathered}[/tex]We can check that the points (3,-1) and (4,-3) also satisfy the equation that we found above:
[tex]\begin{gathered} \text{For point (3,-1):} \\ y=-2\cdot3+5=-6+5=-1 \\ \text{For point (4,-3):} \\ y=-2\cdot4+5=-8+5=-3 \end{gathered}[/tex]The above shows that the points satisfy the equation.
So, for input=n the output is:
[tex]\text{output}=-2\cdot n+5[/tex]Gemma had $2, 054 in her checking account. She wrote acheck for $584 to pay the rent on her apartment. After thelandlord cashed the check, how much money did Gemmahave left in her checking account?
Solution
Given that Gemma had $2, 054 in her checking account.
She wrote a check for $584 to pay the rent on her apartment.
That means she would have $2, 054 - $584 = $1, 470 left in her checking account
Option C
Write the following fractions in thesimplest form:1. 20/52. 12/963. 100/2
So the first fraction is:
1)
[tex]\frac{20}{5}[/tex]So we have to find a number that is multiple of 20 and 5, in this case is the number 5. the we have to divide the two numbers in 5:
[tex]\frac{5}{5}=1\to\text{ }\frac{20}{5}=4[/tex]So at the end the fraction is going to be equal to:
[tex]\frac{20}{5}=4[/tex]2)
[tex]\frac{12}{96}[/tex]and 12 and 96 are multiples of two, so we can divide by 2
[tex]\frac{12}{2}=6\to\frac{96}{2}=48[/tex]now we need to find other number that is multiple of 6 and 48, and agins is the number 2:
[tex]\frac{6}{2}=3\to\frac{48}{2}=24[/tex]Now 3 and 24 are multiples of 3, so we make the same procedure:
[tex]\frac{3}{3}=1\to\frac{24}{3}=8[/tex]So at the end is going to be:
[tex]\frac{12}{96}=\frac{1}{8}[/tex]3)
[tex]\frac{100}{2}[/tex]100 and 2 are multiples of 2, so we divide them by 2:
[tex]\frac{100}{2}=50\to\frac{2}{2}=1[/tex]So the final Resold will be:
[tex]\frac{100}{2}=\frac{50}{1}=50[/tex]Select the equation that represents the graph of the line. 3+ 2 1- -5 -4 -3 -2 -1 1 2 3 4 5 -3+ -4- -57 o y = 1 / 2 x + 2 O'y=x-1 o y = 1 / 2 x - 1 O y=x+2
First, we have to find the slope with the formula below.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Let's replace the points (0, -1) and (2, 0).
[tex]m=\frac{0-(-1)}{2-0}=\frac{1}{2}[/tex]Once we have the slope, we use the slope-intercept formula to find the equation.
[tex]y=mx+b[/tex]Where m = 1/2, and b = -1.
[tex]y=\frac{1}{2}x-1[/tex]Hence, the answer is the third choice.Convert the following angle from degrees to radians. Express your answer in simplestform.150°
Recall that:
[tex]2\pi radians=360^{\circ}.[/tex]Therefore:
[tex]150^{\circ}=\frac{150*2\pi}{360^}\text{ radians.}[/tex]Simplifying the above result, we get:
[tex]150^{\circ}=\frac{5}{6}\pi.[/tex]Answer: [tex]\begin{equation*} \frac{5}{6}\pi. \end{equation*}[/tex]y=-2/3x +7y = 2x - 3For each equation, write the slope and y-intercept.Graph both equations on the same graph (do this on paper)
The given equations of the lines are in their slope-intercept form, that is:
[tex]\begin{gathered} y=mx+b \\ \text{ Where m is the slope and} \\ b\text{ is the y-intercept of the line} \end{gathered}[/tex]Then, we have:
• First equation
[tex]\begin{gathered} y=-\frac{2}{3}x+7 \\ \boldsymbol{m=-\frac{2}{3}} \\ \boldsymbol{b=7} \end{gathered}[/tex]• Second equation
[tex]\begin{gathered} y=2x-3 \\ \boldsymbol{m=2} \\ \boldsymbol{b=-3} \end{gathered}[/tex]Now, to graph the first equation, we can find two points through which the line passes:
• First point
If x = 3, then we have:
[tex]\begin{gathered} y=-\frac{2}{3}x+7 \\ y=-\frac{2}{3}\cdot3+7 \\ y=-2+7 \\ y=5 \end{gathered}[/tex]That means that the line passes through the point (3,5).
• Second point
If x = 6, then we have:
[tex]\begin{gathered} y=-\frac{2}{3}x+7 \\ y=-\frac{2}{3}\cdot6+7 \\ y=-2\cdot2+7 \\ y=-4+7 \\ y=3 \end{gathered}[/tex]That means that the line passes through the point (6,3).
To graph the second equation, we can find two points through which the line passes:
• First point
If x = 3, then we have:
[tex]\begin{gathered} y=2x-3 \\ y=2\cdot3-3 \\ y=6-3 \\ y=3 \end{gathered}[/tex]That means that the line passes through the point (3,3).
• Second point
If x = 4, then we have:
[tex]\begin{gathered} y=2x-3 \\ y=2\cdot4-3 \\ y=8-3 \\ y=5 \end{gathered}[/tex]That means that the line passes through the point (4,5).
Now that we know two points through which each line passes, we can graph them and then join them to obtain the graph of both equations:
2h-3(3-h)+_=5h-8 Solve
ANSWER
1
EXPLANATION
We have the equation:
2h - 3(3 - h) + _ = 5h - 8
We need to find the missing number.
Let us expand the bracket and simplify the equation. We have:
2h - 9 + 3h + __ = 5h - 8
Collect like terms:
__ = 5h - 2h - 3h - 8 + 9
=> __ = 1
Therefore, the missing number is 1.
Donna got a prepaid debit card with $25 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 21 cents per yard. If after that purchase there was $21.22 left on the card, how many yards of ribbon did Donna buy?
Given data:
Initial amount of money: $25.00
Final amount of money: $21.22
Price of ribbon: $0.21 per yard
1. Find the money Donna spend in the craft store: Subtract the final amount of money from the initial amount of money:
[tex]25.00-21.22=3.78[/tex]2. Divide the result of step 1 by the price per yard of the ribbon:
[tex]\frac{3.78}{0.21}*\frac{100}{100}=\frac{378}{21}[/tex]Then, Donna bought 18 yards of ribbonPlease help me with this problem I am trying to help my son to understand I have attached what I have helped him with so far just need to be sure i am correct:Solve the system of equations.13x−y=90y=x^2−x−42 Enter your answers in the boxes. ( __,__) and (__,__)
y=xTo solve the system of equations, follow the steps below.
Step 01: Substitute the value of y from equation 2 in equation 1.
In the second equation:
[tex]y=x^2-x-42[/tex]In the first equation:
[tex]13x-y=90[/tex]So, let's substitute y by x² - x - 42.
[tex]\begin{gathered} 13x-y=90 \\ 13x-(x^2-x-42)=90 \\ 13x-x^2+x+42=90 \end{gathered}[/tex]Adding the like terms:
[tex]-x^2+14x+42=90[/tex]Subtracting 90 from both sides:
[tex]\begin{gathered} -x^2+14x+42-90=90-90 \\ -x^2+14x-48=0 \end{gathered}[/tex]Step 02: Use the quadratic formula to solve the equation.
For a quadratic equation ax² + bx + c = 0, the quadratic formula is:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \end{gathered}[/tex]In this question, the equation is -1x² + 14x + -48 = 0, then, teh coeffitients are:
a = -1
b = 14
c = -48
Substituting the values and solving the equation:
[tex]\begin{gathered} x=\frac{-14\pm\sqrt{14^2-4*(-1)*(-48)}}{2*(-1)} \\ x=\frac{-14\pm\sqrt{196-192}}{-2} \\ x=\frac{-14\pm\sqrt{4}}{-2}=\frac{-14\pm2}{-2} \\ x_1=\frac{-14-2}{-2}=\frac{-16}{-2}=8 \\ x_2=\frac{-14+2}{-2}=\frac{-12}{-2}=6 \end{gathered}[/tex]Step 03: Substitute the values of x in one equation and find y.
Knowing that:
[tex]y=x^2-x-42[/tex]Let's substitute x by 6 and 8 and find the ordered pairs that are the solution of the system.
First, for x = 8:
[tex]\begin{gathered} y=8^2-8-42 \\ y=64-8-42 \\ y=14 \end{gathered}[/tex]Second, for x = 6:
[tex]\begin{gathered} y=6^2-6-42 \\ y=36-48 \\ y=-12 \end{gathered}[/tex]So, the solutions for the system of equations are (8, 14) and (6, -12).
Answer: (8, 14) and (6, -12).
suppose cos(0) = -3/7 and 0 is in quadrant 2. What is the value of sin(0)?
In the second quadrant, the sine function is positive while the cosine function is negative.
[tex]\Rightarrow\cos \theta<0,\sin \theta>0[/tex]Furthermore, we can use the following trigonometric identity.
[tex]\cos ^2\theta+\sin ^2\theta=1[/tex]Therefore,
[tex]\begin{gathered} \Rightarrow\sin ^2\theta=1-\cos ^2\theta \\ \Rightarrow\sin \theta=\pm\sqrt[]{1-\cos ^2\theta} \\ \Rightarrow\sin \theta=\sqrt[]{1-\cos^2\theta} \end{gathered}[/tex]Because sin(theta) has to be positive, as stated before; thus,
[tex]\begin{gathered} \Rightarrow\sin \theta=\sqrt[]{1-(-\frac{3}{7})^2}=\sqrt[]{1-\frac{9}{49}}=\sqrt[]{\frac{40}{49}}=\frac{\sqrt[]{40}}{7}=\frac{2\sqrt[]{10}}{7} \\ \Rightarrow\sin \theta=\frac{2\sqrt[]{10}}{7} \end{gathered}[/tex]Thus, the answer is sinθ=2sqrt(10)/7
Use the slope formula to find the slope of the line through the points (9,5) and (-7,2).
The formula for determining slope is expressed as
slope = (y2 - y1)/(x2 - x1)
Where
y2 and y1 are the final and initial values of y respectively
x2 and x1 are the final and initial values of x respectively
From the information given,
x1 = 9, y1 = 5
x2 = - 7, y2 = 2
Thus,
Slope = (2 - 5)/(- 7 - 9)
Slope = - 3/ - 16
Slope = 3/16
the graph shows that school's profit P for selling x lunches on one day.The school wants to change the price for lunch so that when it sells more than 30 lunches in one day, it begins to make a profit.How much would the school need to charge for each lunch situation?
Find the slope of the line. That will give us the present price for each lunch.
Use the points (0,-150) and (50,0):
[tex]\begin{gathered} m=\frac{0--150}{50-0} \\ \Rightarrow m=3 \end{gathered}[/tex]Then, the current profit equation is given by:
[tex]y=3x-150[/tex]We want to change the price of each lunch so that the point (30,0) belongs to the graph (that means that when selling 30 lunches, it begins to make profit).
Let M be the new price. Then:
[tex]\begin{gathered} 0=30M-150 \\ \Rightarrow30M=150 \\ \Rightarrow M=\frac{150}{30} \\ \therefore M=5 \end{gathered}[/tex]Therefore, the school should charge 5 dollars for each lunch.
it’s a system of equation graph and they need to be matched with its solution
Explanation
Step 1
[tex]\begin{gathered} f(x)=2^x-3 \\ j(x)=x+2 \end{gathered}[/tex]a) to graph f(x) , we start from the function
[tex]\begin{gathered} f(x)=2^x \\ then,\text{ we shift the graph 3 units down, so} \end{gathered}[/tex]b) j (x) is a line, so we need 2 points
[tex]\begin{gathered} j(0)=0+2=2 \\ P1(0,2) \\ and \\ j(1)=1+2=3 \\ P2(1,3) \end{gathered}[/tex]then, draw a line that passes through P1 and P2
finally, the solution is the point where the graph intersect each other, so
so, we can conclude that
the answer is
Find the point of intersection of the following pair of equations, then sketch your solutions indicating all point where the equations intersect both sets of axes: a) y = 2x – 1 and x + 2y = 5b) ^2 + ^2 = 4 and 3x + y = 2
Answer:
a) Intersection of the equations (1.4, 1.8)
b) Intersection of the equations (0, 2) and (1.2, -1.6)
Explanation:
Part a) y = 2x – 1 and x + 2y = 5
To find the intersection point, let's replace the first equation on the second one, so
x + 2y = 5
x + 2(2x - 1) = 5
Now, we can solve the equation for x
x + 2(2x) - 2(1) = 5
x + 4x - 2 = 5
5x - 2 = 5
5x - 2 + 2 = 5 + 2
5x = 7
5x/5 = 7/5
x = 1.4
Then, replace x = 7/5 on the first equation
y = 2x - 1
y = 2(1.4) - 1
y = 2.8 - 1
y = 1.8
Then, the graph of the lines is:
Where the intersection points with the axes for y = 2x - 1 are (0, -1) and (0.5, 0) and the intersection points with the axes of x + 2y = 5 are (0, 2.5) and (5, 0)
Part b) ^2 + ^2 = 4 and 3x + y = 2
First, let's solve 3x + y = 2 for y, so
3x + y - 3x = 2 - 3x
y = 2 - 3x
Then, replace y = 2 - 3x on the first equation and solve for x
x² + y² = 4
x² + (2 - 3x)² = 4
x² + 2² - 2(2)(3x) + (3x)² = 4
x² + 4 - 12x + 9x² = 4
10x² - 12x + 4 = 4
10x² - 12x + 4 - 4 = 0
10x² - 12x = 0
x(10x - 12) = 0
So, the solutions are
x = 0
or
10x - 12 = 0
10x = 12
x = 12/10
x = 1.2
Replacing the values of x, we get that y is equal to
For x = 0
y = 2 - 3x
y = 2 - 3(0)
y = 2 - 0
y = 2
For x = 1.2
y = 2 - 3(1.2)
y = 2 - 3.6
y = -1.6
Therefore, the intersection points are (0, 2) and (1.2, -1.6)
Then, the graph of the functions are:
Since ^2 + ^2 = 4 is a circle with radius 2, the intersection points with the axes are (2,0), (0, -2), (-2, 0) and (0, 2). Additionally, the intersections potins with the axis of the line 3x + y are (0, 2) and (0.667, 0)
Suppose that ABC is isosceles with base BA.Suppose also that mZ B=(5x+24)° and mC = (2x + 72).Find the degree measure of each angle in the triangle.с(2x + 72)m 2A =0D9Хm ZB =Аm LC =BT(5x + 24)口。
1) The best way to tackle questions like these is to sketch out:
2) We were told that this is an isosceles triangle therefore at least 2 of their angles are congruent to themselves. Therefore we can write down the following equation also considering the Triangle Sum Theorem:
[tex]\begin{gathered} 5x+24+5x+24+2x+72=180 \\ 12x+48+72=180 \\ 12x+120=180 \\ 12x+120-120=180-120 \\ 12x=60 \\ \frac{12x}{12}=\frac{60}{12} \\ x=5 \end{gathered}[/tex]Note that now, we can find the measure of each angle by plugging x=5:
[tex]\begin{gathered} m\angle A=m\angle B=5x+24=5(5)+24=49^{\circ} \\ m\angle A=m\angle B=49^{\circ} \\ m\angle C=2(5)+72 \\ m\angle C=82^{\circ} \end{gathered}[/tex]3) Thus the answer is:
[tex]m\angle A=49^{\circ},m\angle B=49^{\circ},m\angle C=82^{\circ}[/tex]15. Find the volume of the figure below.20 yd15 yd9 yd12 yd- 20.9
The volume of a triangular prism is the following equation:
[tex]V=Ah[/tex]where A represents the area of the base and h represents the height of the prism.
In this case, the area of the base is the following:
[tex]A=\frac{12\cdot9}{2}=\frac{108}{2}=54yd^2[/tex]then, the volume of the prism is:
[tex]V=54(20)=1080yd^3[/tex]will send image 8.2 + x + 2; x= 3.1
For x = 3.1
10) 8.2 + x
Is anyone able to assist with this complex question? Thanks
Solution
Step 1:
A finite discontinuity exists when the two-sided limit does not exist, but the two one-sided limits are both finite, yet not equal to each other. The graph of a function having this feature will show a vertical gap between the two branches of the function.
I need help.on a problem
the equation
[tex]-1.26\times n=-10.08[/tex]total days
we solve n dividing all expression by -1.26
[tex]\begin{gathered} \frac{-1.26\times n}{-1.26}=\frac{-10.08}{-1.26} \\ \\ n=8 \end{gathered}[/tex]then the total number of days is 8
you roll a number cube numbered from 1 to 6 p( a number greater than 4)
The probability of an event A can be calclated obythe number of possible favorable outcomes of A dividaed by the total possible outcomes of the random experience.
If we rolled a number cube (1 to 6), the total possible outcomes is 6 because we cn get {1, 2, 3, 4, 5, 6}.
From those outcomes, only two are greater than 4: {5, 6}.
Thu, the required probability is:
[tex]p=\frac{2}{6}=\frac{1}{3}[/tex]The approximate value is p = 0.33
Jenny makes money by mowing lawns. She can mow 8 lawns in 5 hours. At this rate, how long does it take her to mow 12 lawns?
Answer is 20 hours.
Given:
Jenny can make 8 lawns in 5 hours.
The objective is to calculate the time required for her to mow 12 lawns.
Consider the required time as t.
The rate of equation can be represented as,
[tex]\begin{gathered} r=\frac{12}{8} \\ r=4 \end{gathered}[/tex]Now, the time required can be calculated as,
[tex]\begin{gathered} r=\frac{t}{5} \\ 4=\frac{t}{5} \\ t=20\text{ hours} \end{gathered}[/tex]Hence, the time required for her to mow 12 lawns is 20 hours.
I need the answers please show work so I don’t fail
Solution
- The way to solve the question is that we should substitute the values of x and y given into the formula given to us.
- The formula given to us is:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ where, \\ (x_1,y_1)\text{ are the points given to us} \\ m\text{ is the slope} \end{gathered}[/tex]- Thus, we can solve the question as follows:
Question 1:
[tex]\begin{gathered} m=5 \\ x_1=3,y_1=6 \\ \\ \text{ Thus, the equation is:} \\ y-6=5(x-3) \end{gathered}[/tex]Question 2:
[tex]\begin{gathered} m=\frac{2}{7} \\ x_1=-5,y_1=4 \\ \\ \text{ Thus, the equation is:} \\ y-4=\frac{2}{7}(x-(-6)) \\ \\ y-4=\frac{2}{7}(x+6) \end{gathered}[/tex]Question 3:
[tex]\begin{gathered} m=-\frac{3}{2} \\ x_1=-7,y_1=-10 \\ \\ \text{ Thus, the equation is:} \\ y-(-10)=-\frac{3}{2}(x-(-7)) \\ \\ y+10=-\frac{3}{2}(x+7) \end{gathered}[/tex]Final Answer
Question 1:
[tex]y-6=5(x-3)[/tex]Question 2:
[tex]y-4=\frac{2}{7}(x+6)[/tex]Question 3:
[tex]y+10=-\frac{3}{2}(x+7)[/tex]Yellow chip = +1 Red chip = -1Find the sum of 4 + -5 using the counter chips.4=-5=4 + -5 =
Notice that 5 is greater than 4.
To find 4-5, remember that when a greater number is subtracted from another, the result is a negative number. Then, the result is the same as the result of 5 minus 4 but with a negative sign.
Since 5-4 is equal to 1, then:
[tex]4-5=-1[/tex]Therefore, the answer is: -1.
ms or mr could you please help me out with this problem?
The coordinates of the triangle after reflection over the line x= 1 will be A'(5,0), B' (2,4) and C'(2,0)
The first thing we need to do here is to label the coordinates of the vertices of the triangle
What we need here is to know the coordinates of the points A,B and C on the graph
Let us have our scale as 1 cm representing 1 unit on both axes
We have the coordinates of the vertices as follows;
A = (-3, 0)
B = (0,4)
c = (0,0) ; it is at the origin
Now, we will perform a reflection on these coordinates over the line x= 1
To perform a reflection over the line x = 1,
Matematically given that we want to reflect over a line with equation x = b,
The coordinates of the reflected point will be;
(2b-x, y)
So for A (-3,0); A' will be (2(1)-(-3), 0) = (5,0)
For B (0,4), B' will be (2(1)-0, 4) =(2,4)
C' will be (2(1)-0, 0) = (2,0)
So the coordinates of the reflected image will be;
A'(5,0) , B' (2,4) , C (2,0)
Hence, we proceed to get these points on the graph.
After locating them, we join them together to form a triangle
Explain the Pythagorean Theorem, and provide two additional examples (other than football) of how it can it apply to sports
Given:
The objective is to explain Pythagorean Theorem with two examples by applying it to sports.
Explanation:
The Pythagorean Theorem states that. in a right triangle the sum of the squares of a two perpendicular legs will be equal to the square of the largest side of the triangle.
Consider a right triangle ∆ABC right angled at B.
By applying the Pythagorean Theorem to the above right triangle,
[tex]AC^2=AB^2+BC^2\text{ . . . . . .(1)}[/tex]Example 1:
Consider a tennis player standing striking the ball to the service line of opponent field.
Let the height of the tennis player will be h = 3m.
The distance between the tennis player and the opponent service line is x = 18m.
Then, the distance at which the tennis player strikes the ground can be calculated as,
From the above diagram the distance d can be calculated using equation (1) as,
[tex]d^2=h^2+x^2\text{ . . . . . . (2)}[/tex]On plugging the values in equation (2),
[tex]\begin{gathered} d^2=3^2+18^2 \\ d^2=9+324 \\ d=\sqrt[]{333} \\ d\approx18.25m \end{gathered}[/tex]Example 2:
Consider a basket ball player ready to take a free throw standing at a horizontal distance of 20 ft from the ring and holding the ball at with distance of 10ft below the ring.
Then, the hypotenuse distance of the ring can be calculated using equation (1) as,
[tex]\begin{gathered} x^2=10^2+20^2 \\ x^2=100+400 \\ x=\sqrt[]{500} \\ x\approx22.36ft \end{gathered}[/tex]Hence, the explanation for Pythagorean Theorem with two examples are provided.
What are the critical points of f prime = 2x -2/x
The critical points of f prime are at x = ± 1
What are critical points?Critical points of a function are the points at which the function changes direction.
How to find the critical points of f prime?Since we have the function f'(x) = 2x - 2/x
Since the functionis f'(x), this implies that it is a derivative of x.
So, to find the critical points of f'(x), we equate f'(x) to zero.
So, we have that
f'(x) = 0
⇒ 2x - 2/x = 0
⇒ 2x = 2/x
cross-multiplying, we have that
⇒ 2x² = 2
Dividing through by 2, we have that
⇒ x² = 2/2
⇒ x² = 1
Taking square root of both sides, we have that
⇒ x = ±√1
⇒ x = ± 1
So, the critical points are at x = ± 1
Learn more about critical points here:
https://brainly.com/question/26978374
#SPJ1
21a. Ellen is selling fruit juice and each juice is $3. Write an equation for thesituation.
price of each juice = $3
Number of juices = x
total cost = y
Equation
y= 3x
Todd mowed 1/3 of his yard in the morning and then 3/6 of his yard in the
afternoon. How much of his yard has Todd mowed so far?
1 point
Answer: 5/6 of the yard mowed
Step-by-step explanation:
We will add 1/3 to 3/6 to find the total amount of yard mowed so far.
1/3 + 3/6 = 2/6 + 3/6 = 5/6 of the yard mowed