When the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
From the question, we have
Voltage in the circuit, V = 1.5 volts,
The circuit's resistance, R = 50,
In the third diagram, the bulb is connected in parallel, which means that the voltage in the circuit will remain constant. Additionally, because the current depends on the resistor, the resistance in this circuit will be larger.
Additionally, according to Ohm's law, a high resistance will result in a low current flow.
Since there is only one bulb in the first circuit, resistance will be minimal and current flow will be high.
As a result, the third circuit's resistance would be the highest and its current the lowest when the switch is closed.
Current :
The phrase "electric current" is frequently used to describe how much electricity flows through a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). As more electricity passes through the circuit, the ampere value increases.
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When the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
What is current?
When describing how much electricity flows through a circuit and how it flows in an electronic circuit, the term "electric current" is often employed. It is measured in amperes (A). The ampere number rises as more electricity flows through the circuit.
Given:
The Voltage in the circuit, V = 1.5 volts,
The resistance in the circuit, R = 50 Ω,
As you can see in the third diagram, there is a parallel connection of the bulb, so the voltage in the circuit will remain the same and the current depends on the resistor, so there will be higher resistance in this circuit.
And if the resistance is high the current flow will be low, (By Ohm's law)
In the first circuit, there is only one bulb, so resistance will be low, and the current flow will be high.
Therefore, when the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
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mechanical energy is select one because the roller coaster select one energy due to friction and air resistance as it travels down the track.
True, Mechanical energy is chosen because the roller coaster chooses one energy owing to friction and air resistance as it travels down the track.
Mechanical energy is the sum of kinetic energy and potential energy in an object that is used to do some work.
In other words, it describes the energy of an object due to its motion or position or both.Mechanical energy is the energy of a moving object or the energy that is stored in objects by their position. Mechanical energy is also a driver of renewable energy. Many forms of renewable energy rely on mechanical energy for adequate power generation or energy conversionMechanical energy is chosen because the roller coaster chooses one energy owing to friction and air resistance as it travels down the track. Therefore the given statement is true.
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A 8. 0-m long wire with a mass of 10 g is under tension. A transverse wave for which the frequency is 570 hz, the wavelength is 0. 10 m, and the amplitude is 3. 7 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to.
The maximum transverse acceleration of a point on a wire is 47410.0839m/sec² having mass of 10g.
Transverse Wave travels from highest point of positive amplitude to negative highest point amplitude. Amplitude is the point where potential energy of wave is highest. Transverse wave travels in definite direction. We have mass=10g=0.001kg,length of wire is 8m,frequency of transverse wave is 570Hz,wavelength =0.10m
Now, we need to transverse wave acceleration, for this we need angular frequency because there is co-relation between transverse wave acceleration and angular frequency.
We know that angular frequency=2πf where f is the angular frequency.
ω=2×π×570
=>ω=2×3.14×570
=>ω=6.28×570
=>ω=3579.6/sec
Now, for acceleration we know that =ω²A where A is the amplitude of the wave.
=>a = (3579.6)²×3.7mm
=>a=((3579.6)²×3.7×1/1000)m/sec²
=>a=[(12813,536.2)×3.7×1]/1000m/sec²
=>a=47410083.8/1000m/sec²
=>a=47410.0839m/sec²
Hence, maximum transverse acceleration is 47410.0839m/sec²
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A moving car has 40,000 j of kinetic energy while moving at a speed of 7.0 m/s. a spring-loaded automobile bumper compresses 0.30 m when the car hits a wall and stops. What can you lean about the bumpers spring using the information?
This means that the bumper's spring has a spring constant of 8.89×1058.89×105 N k=8.889×105N/m
What exactly are quantitative hypotheses?It believes that reality is a subject that can be investigated impartially.The researcher must maintain their independence and distance from the subject under study.Research was value-free; it should not be in any way influenced by the researcher's values.
What are some quantitative research presumptions?In general, quantitative research makes the following assumptions:Truth is a phenomenon that can be investigated objectively because it is "out there," objective, and independent of a researcher;
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A wave has a speed of 15 m/s and a frequency of 10 Hz. what is the wavelenght of the wave?
Answer:
1.5 m
Explanation:
speed=frequency*wavelength
15=10*wavelength
A bicycle has a kinetic energy of 124 J. What kinetic energy would the bicycle have if it had
a) twice the mass and was moving at the same speed?
b) the same mass and was moving with twice the speed?
c) one-half the mass and was moving with twice the speed?
d) the same mass and was moving with one-half the speed?
e) three times the mass and was moving with one-half the speed?
Answer:
Below
Explanation:
KE = 1/2 mv^2
soooo ...
a) doubling m doubles KE
b) doubling 'v' makes KE 4 times greater (because v is v^2)
c) 1/2 *2^2 = double KE
d ) 1/2^2 = 1/4 KE
e) 3 * 1/2^2 = 3/4 KE
two slits of widtheach in an opaquematerial, are separated by a center-to-centerdistance ofa monochromatic light ofwavelength 450 nm is incident on the double-slit. one finds a combined interference anddiffraction pattern on the screen.(a) how many peaks of the interference will beobserved in the central maximum of thediffraction pattern?(b) how many peaks of the interference will beobserved if the slit width is doubled whilekeeping the distance between the slits same?(c) how many peaks of interference will beobserved if the slits are separated by twice thedistance, that is,while keeping thewidths of the slits same?(d) what will happen in (a) if instead of 450-nmlight another light of wavelength 680 nm isused?(e) what is the value of the ratio of the intensityof the central peak to the intensity of the nextbright peak in (a)?(f) does this ratio depend on the wavelength ofthe light?(g) does this ratio depend on the width orseparation of the slits?
The distance between the slits and the fringe width are inversely proportional. When the distance between the slits is doubled, the fringe's width is reduced by half.
What diffraction and interference pattern is mixed on the screen?
Diffraction. Interference is described as occurring when waves from two different independent sources have differing wavefronts. Diffraction, on the other hand, is described as secondary waves that split off from the primary wave.
Therefore, each wavelength's waves will produce a different type of interference pattern if white light is employed in Young's experiment instead of monochromatic light. The overall result of all these designs may be seen on the screen. Consequently, the middle white fringe.
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Need some help with this physics problem!
The gravitational attraction between Tom and Sally is 2.32×10⁻¹⁰ N.
What is gravitational attraction?This the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.
To calculate the gravitational attraction between Tom and Sally, we use the formula below.
Formula:
F = GMm/r²............ Equation 1Where:
F = Gravitational attraction between Tom and SallyG = Universal constantM = Mass of Tomm = Mass of Sallyr = Distance between Tom and Sally.From the question,
Given:
M = 70.8 kgm = 48.1 kgG = 6.672589×10⁻¹¹ N.m²/kg²r = 31.3 mSubstitute these values into equation 1
F = (70.8×48.1×6.672589×10⁻¹¹)/(31.3²)F = 2.32×10⁻¹⁰ NHence, the gravitational attraction is 2.32×10⁻¹⁰ N.
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a 3.1-kg object falls vertically downward in a viscous medium at a constant speed of 2.5 m/s. how much work is done by the force the viscous medium exerts on the object as it falls 85 cm?
The work is done by the force the viscous medium exerts on the object as it falls 85 cm is -26.35 joules.
The mass of the object is m = 3.1kg
The speed of fall is v = 2.5 m/s
The depth of fall is d = 85cm
Now here given that the velocity is constant, then the work energy is zero.
So, work done by the potential energy of the object and that of the viscous liquid we have
W = Wv + Wp
Where Wv is work done by viscous liquid and
Wv is the work done by the object
Wp = mgd
So
0 = Wv + mgd
Wv = -mgd
substituting values
Wv = -3.1x10x85
Wv = 26.35 joules
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What is the wave velocity of a sound with 500 Hz and wavelength of 0.5 m?
assume that three irregularly shaped planet-like objects, each smaller than our moon, have just been discovered orbiting the sun at a distance of 35 au. one of your friends argues that the objects should be classified as planets because they are large and orbit the sun. another friend argues that the objects should be classified as dwarf planets, like pluto. state whether you agree or disagree with either or both of your friends. explain your reasoning.
It does not meet all three criteria to be considered a planet.
What are three criteria to be considered as planet?
They determined that a planet must meet the following three requirements:
It must be a body that orbits the Sun independently; as moons orbit planets, they cannot be regarded as planets.It must possess sufficient mass to be drawn into a roughly spheroidal shape by its own gravity.To "dominate" its orbit, it must be massive enough (i.e. its mass must be much larger than anything else which crosses its orbit)According to the question:
I concur with the buddy who says that it should be categorized as a dwarf planet, similar to Pluto, as Pluto is not large enough. Because it is also smaller than the Earth, it does not meet all three criteria to be considered a planet.
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It does not meet all three criteria to be considered a planet.
What are three criteria to be considered as planet?
They determined that a planet must meet the following three requirements:
It must be a body that orbits the Sun independently; as moons orbit planets, they cannot be regarded as planets.
It must possess sufficient mass to be drawn into a roughly spheroidal shape by its own gravity.
To "dominate" its orbit, it must be massive enough (i.e. its mass must be much larger than anything else which crosses its orbit)
I agree with my friend who believes it should be classified as a dwarf planet, comparable to Pluto, because Pluto is insufficiently huge. It does not match all three requirements for being called a planet because it is also smaller than the Earth.
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Consider this situation: a bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, identify which act upon the bucket.
The forces which acts on a bucket of water when it pulled upward out of a well are: b) Gravity force e) Tension force and f) Air resistance force. So, correct listed options are b, e, f.
The forces imparted through a rope, string, or wire while two contradicting forces draw on it is known as Tension force. The pressure force pulls energy similarly on the bodies at the closures and is applied along the whole length of the wire. Gravity force is acted due to gravitational force acted by the gravity on the object.
Each actual article in touch with another applies a force to that item. In view of the sort of articles, names are given to these contact forces. You can allude to strain as one of the powers following up on an item, like a rope, link, or chain.
Hence, correct options are b, e, f.
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(Complete question) is:
Consider this situation: A bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, identify which act upon the bucket.
a. Normal Force
b. Gravity Force
c. Applied Force
d. Friction Force
e. Tension Force
f. Air Resistance Force
A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up 1% -ム33% Part (b) At the instant that the mass asses through the position where the spring is unstretched, what can be said about its instantaneous ーム33% Part (c) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?
a) The instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration being zero,
c) The instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity of Speed is Zero
a) the equation that governs the simple harmonic motion is
x = A cos (wt +φφ)
Where A is the amplitude of the movement, w is the angular velocity, and φ the initial phase determined by the initial condition
Body acceleration is
a = d²x / dt²
Let's look for the derivatives
dx / dt = - A w sin (wt + φ)
a = d²x / dt² = - A w² cos (wt + φ)
In the instant when it is not stretched x = 0
As the spring is released at maximum elongation, φ = 0
0 = A cos wt
Cos wt = 0 wt = π / 2
Acceleration is valid for this angle
a = -A w² cos π/2 = 0
Acceleration is zero
b)
c) When the spring is compressed x = A
Speed is
v = dx / dt
v = - A w sin wt
We look for time
A = A cos wt
cos wt = 1 wt = 0, π
For this time the speedy vouchers
v = -A w sin 0 = 0
Speed is cero
Harmonic movement refers to the movement of an oscillating mass studies when the restoring pressure is proportional to the displacement, however in contrary directions. Harmonic motion is periodic and may be represented with the aid of a sine wave with regular frequency and amplitude. An example of that is a weight bouncing on a spring. The motion is called harmonic due to the fact musical contraptions make such vibrations that during flip cause corresponding sound waves in the air.
it is a sort of periodic motion with extreme points. simple harmonic motion is an oscillatory motion wherein the particle's acceleration and force are without delay proportional to its displacement from the mean region at every factor. it's miles a special case of oscillatory movement.
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Underline the statements you think are true:
Gravity depends on the material of the objects.
.Gravity is not a force because it can’t move objects.
Gravity is a force because a force is a push or a pull.
The moon has less gravity than the Earth because it has less mass than the Earth.
The moon has less gravity than the Earth because it has no atmosphere.
The statements that I think are true are:
Gravity depends on the material of the objects.Gravity is a force because a force is a push or a pull.What is gravity?Gravity can be described as the force by which a planet or other body draws objects toward its center however the force of gravity keeps all of the planets in orbit around the sun.
It should be noted that Gravity do depends on the material of the objects however the Gravity can not be regrded as force because it can't move objects but can be consdidered as the force because a force is a push or a pull, as it can be seen in hoiw the moon has less gravity than the Earth because it has less mass than the Earth.
In conclusion, Gravity depends on the material of the objects and it should be noted that Gravity is a force because a force is a push or a pull.
Therefore, option A and C are correct.
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The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.
The percentage of the iceberg that is visible above the water's surface will be 11.5% if specific gravity of ice is 0.917.
We know very well that density is defined as the division of mass with per unit volume. It is an important factor in order to find the fluid and its properties. Its SI.unit is kg/m³.
We know very well that the mass and density relation is given by the formula
mass = density × volume
We are given density of ice = 917 kg/m³,density of the seawater=1025 kg/m³
Therefore, the ratio by which the iceberg submerge is found as
=>[tex]V_s[/tex]/V=ρ/ρ[tex]_o[/tex]
where V and ρ is defined as the volume of the iceberg and ρ is defined as the density of the substance.
=>[tex]V_s[/tex]/V=0.917/1.025
=>[tex]V_s[/tex]/V =917/1025
=>[tex]V_s[/tex]/V=0.895
or we can 89.5% of ice is submerged inside the water.
But we need to find the percentage which is visible to us, it means we need to subtract the submerged percentage from total percentage possible.
⇒The percentage which is visible to us=100-.89.5 %
⇒The percentage which is visible to us=11.55 %
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the flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.47 rad/s2. it accelerates for 24.7 s, then maintains a constant angular velocity. calculate the total angle through which the wheel has turned 59.5 s after it begins rotating.
The flywheel of a steam engine starts revolving at rest with a constant angular acceleration of 1.47 rad/s2, therefore the wheel has rotated across a total angle of 1709.67 rad after 59.5 seconds.
To answer the question, we write down the flywheel's motion equation as 2 = 1 + t.
Where:
Initial angular velocity for the body is 0 rad/s in equation (1) Initial and final angular velocities
Time is equal to 24.7 seconds and angle acceleration is 1.47 rad/s2.
After entering the values, we discover that 2 2 = 0 + 1.35 rad/s2* 24.7 s = 38.205 rad/s.
Thus, 540.60075 rad + 1169.073 rad = 1709.67375 rad 1709.67 rad is the equation for the total angle the flywheel covered in 59.5 seconds.
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does the doppler effect occur when the source and observer are both moving towards each other? if so, how would this affect the perceived frequency?
When the source and observer are both moving towards each other, receive frequency will be same.
What is Doppler effect?The change in frequency of a wave in proportion to an observer who is moving relative to the wave source is known as the Doppler effect, Doppler shift, or simply Doppler, depending on the context. It bears the name of the Austrian scientist Christian Doppler, who first characterized it in 1842.
The Doppler effect, also known as the Doppler shift, is a term used to explain changes in frequency caused by moving sources of sound or light with regard to an observer. As the source gets closer to the observer, the waves it is emitting become compressed and have a greater frequency.
Observer and source moving in same direction, then the frequency becomes:
f = (v ± v₀) × f/ [v ± v(s)]
Now, assume observer is behind the source ,source is moving towards observer and observer is moving away from source:
f₁ = (v - v₀) × f/[v - v(s)]
Here, received frequency will be same, thus Doppler effect occur due to relative motion.
Yes , the perceived frequency will be same as the source frequency.
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a contact lens is made of plastic with an index of refraction of 1.30. the lens has an outer radius of curvature of 2.04 cm and an inner radius of curvature of 2.54 cm. what is the focal length of the lens?
The focal length of a camera lens, which is frequently stated in millimeters, is its fundamental description (mm), to the point where light rays converge to form a sharp image of an object.
An optical medium's refractive index, commonly referred to as the refraction index, is a dimensionless statistic that describes how well the medium bends light. Focal length, the amount of light that enters a substance is refracted or bent depends on the substance's refractive index. When a beam travels across the boundary between two media with refractive indices of n1 and n2, its angles of incidence and refraction are, respectively, n1 sin 1 and n2 sin 2, which describe this. The refractive indices determine the critical angle for total internal reflection, the intensity of the reflected light (Fresnel's equations), Brewster's angle, and the volume of light reflected when it reaches the interface. Since the speed of light in a medium is equal to v = c/n and the wavelength in that medium is equal to 0/n, where 0 is the wavelength of that light in vacuum, the refractive index can be thought of as the parameter that lowers those values relative to their vacuum values. This assumes that vacuum has a refractive index of 1, and that the frequency of the wave (f = v/) is unaffected by the refractive index.
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The demon drop rode at cedar point amusement park falls freely for 4.33 an after starting from rest. What is it’s velocity at the end of this time?
The velocity of the rode at the end of the time 4.33 seconds is 42.434 m/s.
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity of the, we use the formula below.
Formula:
v = u+gt................. Equation 1Where:
v = Velocity at the end of the timeu = Initial velocityg = Acceleration due to gravityt = TimeFrom the question,
Given:
u = 0 m/s (From rest)g = 9.8 m/s²t = 4.33 secondsSubstitute these values into equation 1
v = 0+9.8×4.33v = 42.434 m/sHence, the velocity at the end of the time is 42.434 m/s.
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the period t (in seconds) of a pendulum is given by , where l stands for the length (in feet) of the pendulum. if , and the period is 12.56 seconds, what is the length? the length of the pendulum is
The length of the pendulum is 128.57 feet.
What is time period?The duration of time it takes for any string element to complete an oscillation is known as the time period of an wave oscillation.
The period T (in seconds) of a pendulum is given by: T = 2π√(l/g).
The period is 12.56 seconds.
Acceleration due gravity: g = 32.1741 feet/second².
Hence, the length of the pendulum be = (T/2π)²g
= (12.56/2π)²×32.1741 feet
= 128.57 feet.
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which of the elements of a legal contract does an insurance premium payment represent?
Consideration is the element of a legal contract that the insurance premium payments represent.
A legally binding agreement is referred to as a "contract". It consists of five fundamental components:
OfferAcceptanceConsiderationCompetent partiesLegal purposeWhat is "consideration" as one of the fundamental components of a contract?A party provides another party with consideration when they provide something of value. Each party has committed to respecting the terms of the agreement by exchanging compensation in this manner. Every legal contract must have this component. The initial premium payment is the applicant's consideration for insurance contracts. If a fee is included in the application, coverage could start the day it is filed. The first premium would not become due to the insurer/insurer agent until after the application has been submitted in such case.
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if the rectangular barge is 3.5 m by 24.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
By using Archimedes Principle the Barge will sit at a depth of 0.7203 m
What is Archimedes Principle?
The buoyancy of any floating object partially or totally submerged in a fluid can be computed thanks to Archimedes' principle. The weight of the thing alone exerts a downward force on it. The upward or buoyant force acting on the object is what is meant by the aforementioned Archimedes' principle. The difference between the buoyant force and the object's weight is therefore the net force acting on it. In the event that this net force is positive, the item will rise; in the event that it is negative, the object will sink; and in the event that it is zero, the object will be neutrally buoyant, remaining stationary.
Calculation:
The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:
density (salt water) = 1029 kg / [tex]m^3[/tex]
density (fresh water) = 1000 kg / [tex]m^3[/tex]
The amount of water (in mass) displaced by the barge should be equal in two waters.
mass displaced (salt water) = mass displaced (fresh water)
Since mass is also the product of density and volume,
therefore:
[density * volume] of salt water = [density * volume] of fresh water
First we calculate the amount of volume displaced in the harbour (salt water):
V = [tex]3.5 m\ X\ 24.0 m\ X\ 0.70 m[/tex]
V = [tex]58.8 m^3[/tex] of salt water
Plugging in the values into equation 1:
1029 kg / [tex]m^3[/tex] × 58.8 m^3 = 1000 kg/[tex]m^3[/tex]× Volume fresh water
Volume fresh water displaced = 60.5052 [tex]m^3[/tex]
Therefore the depth of the barge in the river is:
60.5052 [tex]m^3[/tex] = 3.5 m × 24.0 m × h
h = 0.7203 m
By using Archimedes Principle the Barge will sit at a depth of 0.7203 m
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Calculate the wavelength (in m) of a 9. 81-g bullet traveling at 1769 miles per hour.
A bullet that has a mass of 9.81 g traveling at 1769 miles per hour has a wavelength of 0.85 x 10⁻³⁴ m
De Broglie waveA physicist "Louis de Broglie" put forward a hypothesis that particles can also be treated as particles as well as waves. Using theoretical concepts from black body radiation, de Broglie showed a relationship expressing momentum with wavelength. This equation is derived from the energy equation for a photon in black body radiation. The energy of a photon is a function of the wavelength of the photon.
The equation is:
λ = h/p
We have,
Mass of the bullet = 9.81 g = 0.00981 kg
v = 1769 mph ⇒ 790.81 ms⁻¹
h = Planck's constant ⇒ 6.63 x 10⁻³⁴ m²kg⁻¹
Determine the momentum (p) of the bullet first,
P = mv
= (0.00981) (790.81 )
= 7.75 kgms⁻¹
So, the wavelength of the bullet:
λ = 6.63 x 10⁻³⁴ / 7.75
= 0.85 x 10⁻³⁴ m
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determine δhvap for a compound that has a measured vapor pressure of 24.3 torr at 273 k and 135 torr at 325 k.
The enthalpy of vaporization as determined from the different temperatures is 23.6 kJ/mol.
What is the enthalpy of vaporization?The enthalpy of vaporization has to do with the heat that is given out when a substances is converted from liquid to vapor under standard conditions.
We can use te formula;
ln(P2/P1) = -ΔHvap/R(1/T2 - 1/T1)
P2 = final pressure
P1 = initial pressure
ΔHvap = enthalpy of vaporization
T2 = final temperature
T1 = initial temperature
Then;
ln(135/24.3) = -ΔHvap/8.314 (1/325 - 1/273)
1.7 = -ΔHvap/8.314 (0.0031 - 0.0037)
1.7 = -ΔHvap/8.314 (-0.0006)
1.7 = 0.0006ΔHvap/8.314
To obtain the enthalpy of vaporization here;
ΔHvap = 1.7 * 8.314/0.0006
= 23.6 kJ/mol
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in a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. the matter forms an accretion disk that orbits the white dwarf. then a specific sequence of events must take place for a nova event to occur.
The chronological steps that lead to the observed nova event are as follows:
Material accumulates onto the white dwarf star's surface, making its temperature and density increase.Accumulated surface hydrogen begins nuclear fusion at 10 million Kelvin.The reactions from nuclear fusion cause a temporary yet significant increase in luminosity.As nuclear fuel is either burned up or blown into space, nuclear fusion ceases and the star dims down.A nova event is an astronomical event that causes the occurrence of a bright star that slowly fades over time (usually in weeks or months). It's mainly caused by white dwarf stars that are involved in a close binary system.
Attached below is an image of the Nova Eridani in 2009 taken by Kevin Heider.
Your question seems incomplete, but the completed version is most likely as follows:
In a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. The matter forms an accretion disk that orbits the white dwarf. Then a specific sequence of events must take place for a nova event to occur.
Rank the steps leading up to the observed nova event in chronological order from first to last.
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in a movie, a superhero stops an 8 gram bullet moving at 400 m s-1 with his hand. his hand provides an impulse to stop the bullet. the average force provided to the bullet during the time of contact is 1200 newton. a. calculate the time of contact with the hand before the bullet comes to rest. b. calculate the work done by the hand in bringing the bullet to rest. c. calculate how far back the hand has been displaced. d. calculate the change in the kinetic energy of the bullet..
The bullet's kinetic energy is 4000N.
What exactly is kinetic energy?
To accelerate an item, we must apply force to it. We must make an attempt to utilise force. When work is done on an item, energy is transferred, and the object then travels at a new, constant speed. The energy conveyed is known as kinetic energy, and it is affected by the mass and speed obtained.
Kinetic energy is defined in physics as follows:
The amount of work an item can do while moving is measured by its kinetic energy.
According to the information provided:
mass=10g=10/1000=0.01kg
Initial velocity=u=200m/s
0 m/s final velocity
S=5cm=5/100=0.05m
Using the third equation of motion: V²-u²=2as
0²-(200) ²=2a*0.05
-40000=a/10
a=-400000m/s²
Newton's Second Law states:
F=ma
=0.01*(-400000)
=-4000N
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Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.
What exactly is kinetic energy?
To accelerate an item, we must apply force to it. We must make an attempt to utilise force. When work is done on an item, energy is transferred, and the object then travels at a new, constant speed. The energy conveyed is known as kinetic energy, and it is affected by the mass and speed obtained.
Kinetic energy is defined in physics as follows:
The amount of work an item can do while moving is measured by its kinetic energy.
According to the information provided:
mass=10g=10/1000=0.01kg
Initial velocity=u=200m/s
0 m/s final velocity
S=5cm=5/100=0.05m
Using the third equation of motion: V²-u²=2as
0²-(200) ²=2a*0.05
-40000=a/10
a=-400000m/s²
Newton's Second Law states:
F=ma
=0.01*(-400000)
=-4000N
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An ice skater is spinning with her arms out and is not being acted upon by an external torque. When she pulls her arms in close to her body what happens to her angular velocity?
When she pulls her arms in close to her body, the thing that happens to her angular velocity is that When she pulls her arms in, her rate of spin increases significantly, which reduces her moment of inertia. She exerts effort to pull in her arms, which causes rotational kinetic energy to rise.
What is the angular momentum conservation law?If there is no net external torque surrounding a location in a fixed inertial reference frame, the angular momentum of the system of particles around that point is conserved:
The overall angular momentum is conserved, as you can see. As long as the aggregate is constant, any one of the constituent angular momenta can change. When there is no external force acting on a system, this equation is equivalent to the conservation of linear momentum.
Therefore, since an ice skater performing a spin as an illustration of the conservation of angular momentum. Because there is hardly any friction between her skates and the ice, the net torque on her is almost nil. Additionally, the friction is applied quite near the pivot.
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calculate the mass (in kg) of 4.87 x 1025 atoms of zn. calculate the mass (in kg) of 4.87 x 1025 atoms of zn. 5.29 kg 1.24 kg 1.89 kg 8.09 kg 1.09 kg.
5.29 kg is the mass of 4.87 x 10²⁵ atoms of Zn.
What is mass?As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.The symbol for mass is m or M. The force exerted on a mass as a result of the acceleration brought on by gravity is measured as weight. W typically stands for weight.
As, we know
Mass of 1 mole of Zn = 65.38 gm/mole
= (65.38/1000) kg/mole
= 0.06538 kg/mole
We know,1 mole = 6.023 × 10²³ atoms.
Thus, moles of Zn = 4.87 × 10²⁵ / 6.023 × 10²³
= 80.87 moles
Therefore, mass of Zn = 80.87 moles × 0.06538 kg/mole
= 5.287 kg ≈ 5.29 kg
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a girl throws a rock horizontally, with a velocity of 8.0 m/s, from a bridge. it falls 20 m to the water below. how far does the rock travel horizontally before striking the water, assuming negligible air resistance?
The rock thrown horizontally at 8.0 m/s from a bridge before it hits the water = 16.15 m.
Free fall motionFree fall motion is a motion that falls from a height without having an initial velocity. As long as the object is falling, air resistance is negligible, its acceleration is constant and the magnitude is equal to the acceleration due to gravity. In addition, the time it takes for an object to fall does not depend on its mass, but depends on its height.
We have,
The velocity of the rock = 8.0 m/s ⇒ v
Fall height of the rock = 20 m ⇒ h
And, to determine how far does the rock travel horizontally before striking the water, we use the equation:
d = v x t
We have the velocity (v), but don't have the time (t).
So, determine the time first
Use the equation to determine the height:
h = ½ gt²
20 = ½ (9.8)t²
t² = 4.08
t = [tex]\sqrt{4.08}[/tex]
= 2.01 s
So, the distance the stone traveled before striking to the water:
d = (8.0) (2.01)
= 16.15 m
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Anna and jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the center should jon sit so the seesaw is balanced?.
In order to balance the seesaw, John should sit at a distance of 1.7m from the center.
This question can be solved using the concept of moment. in order to balance on the seesaw the moment on the center of seesaw should be zero or in other words
∑M = 0
Now, the moment is expressed by the formula
∑M = F × d
where, ∑M is the Algebraic sum of moments in the center of the balance, M is the moment in the center point ( N*m), F is the Force (N) and d is the distance of the force to the the center point(N*m).
Now, we have
Mass of Anna (M) = 60kg
Mass of John (m) = 70kg
Distance from Anna to the center of the seesaw (dA) = 2m
Distance from John to the center of the seesaw (dJ) = ?
Acceleration due to gravity (g) = 9.8 m/s²
Also, W = mass × g. So, W = Anna's weight and w = John's weight
Now, to find the distance we write the Moment equation as
∑M = 0
(W)(dA) - (W)(dJ) = 0
(M*g)(dA) - (m*g)(dJ) = 0
We divide the equation by g
(M)(dA) - (m)(dJ)= 0
(M)(dA) = (m)(dJ)
dJ = M(dA)/m
dJ = 60×2/70
dJ = 120/70
dJ = 1.7m which is distance of John from center.
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the moon has a mass of 1×1022 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is the gravitational force exerted on the moon while it is in orbit around the planet?
The gravitational force exerted on the moon while it is in orbit around the planet is 1×10¹⁹ N
How do I determine the gravitaional force?From the question given above, the following data were obtained:
Mass of moon (M) = 1×10²² KgGravitational field strength (E) = 0.001 N/KgGravitational force (F) =?From the above data, we can obtain the gravitational force as illustrated below:
Gravitational field strength (E) = force (F) / mass (M)
E = F / M
0.001 = F / 1×10²²
Cross multiply
F = 0.001 × 1×10²²
F = 1×10¹⁹ N
Thus, from the above calculation, we can conclude that the gravitational force is 1×10¹⁹ N
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