Don’t get part ii of this question ? I needed help with this, please help me as I am confused.
Answers
We are given the following function:
[tex]y=\frac{1-10x}{(2x-1)^5}[/tex]We are asked to differentiate with respect to "x". To do that we need to have into account that the function is rational and therefore, we need to use the quotient rule for derivatives, which is the following:
[tex]\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{f^{\prime}(x)g(x)-f(x)g^{\prime}(x)}{g^2(x)}[/tex]Therefore, we need to determine the derivatives of f(x) and g(x). In this case, we have:
[tex]\begin{gathered} f(x)=1-10x \\ g(x)=(2x-1)^5 \end{gathered}[/tex]Now, we determine the derivative of f(x):
[tex]\frac{d}{dx}(f(x))=\frac{d}{dx}(1-10x)[/tex]First, we distribute the derivative:
[tex]\frac{d}{dx}(f(x))=\frac{d}{dx}(1)-\frac{d}{dx}(10x)[/tex]The first, derivative is the derivative of a constant and therefore is zero:
[tex]\frac{d}{dx}(f(x))=-\frac{d}{dx}(10x)[/tex]For the second derivative we use the following rule:
[tex]\frac{d}{dx}(ax)=a[/tex]Applying the rule we get:
[tex]\frac{d}{dx}(f(x))=-10[/tex]Therefore:
[tex]f^{\prime}(x)=-10[/tex]Now, we determine the derivative of g(x):
[tex]\frac{d}{dx}(g(x))=\frac{d}{dx}(2x-1)^5[/tex]Now, we determine the derivative using the following rule:
[tex]\frac{d}{dx}(g(x))^n=n(g(x))^{n-1}(g^{\prime}(x))[/tex]Applying the rule we get:
[tex]\frac{d}{dx}(g(x))=5(2x-1)^4(2)[/tex]Simplifying:
[tex]\frac{d}{dx}(g(x))=10(2x-1)^4[/tex]Therefore, we have:
[tex]g^{\prime}(x)=10(2x-1)^4[/tex]Now, we substitute the function in the quotient rule:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{(-10)(2x-1)^5-(1-10x)(10)(2x-1)^4}{((2x-1)^5)^2}[/tex]Now we simplify the denominator:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{(-10)(2x-1)^5-(1-10x)(10)(2x-1)^4}{(2x-1)^{10}}[/tex]Now, we take (2x - 1)^4 as a common factor on the numerator:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{(2x-1)^4((-10)(2x-1)^{}-(1-10x)(10))}{(2x-1)^{10}}[/tex]Now, we simplify the function:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{((-10)(2x-1)^{}-(1-10x)(10))}{(2x-1)^6}[/tex]Now, we apply the distributive property on the numerator:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{-20x+10^{}-10+100x}{(2x-1)^6}[/tex]Now, we cancel out the 10 and add like terms:
[tex]\frac{d}{dx}(\frac{1-10x}{(2x-1)^5})=\frac{80x}{(2x-1)^6}[/tex]Since we can't simplify any further this is the final answer.
Related Questions
Write the equation of a sine or cosine function to describe the graph. Please help I’ve tried but I keep missing something like finding the c/b. Thanks in advance!!!
Answers
Since the function starts at it maximum value, let's use a cosine function to represent it:
[tex]f(x)=A+B\cos(C(x+D))[/tex]Since the midline of the periodic function is y = 2, we have A = 2.
The period of the function is 4pi/3, so we have:
[tex]\begin{gathered} T=\frac{2\pi}{C}\\ \\ \frac{4\pi}{3}=\frac{2\pi}{C}\\ \\ \frac{2}{3}=\frac{1}{C}\\ \\ C=\frac{3}{2} \end{gathered}[/tex]Since the function already starts at its maximum value, there is no horizontal phase shift, so D = 0.
The amplitude is 1 (it goes up and down 1 unit from the midline), so we have B = 1.
Therefore the function is:
[tex]f(x)=2+\cos(\frac{3}{2}x)[/tex]using this input output machine,f(x)=?input. 2,3,5,7output. 9,15,33,59x^2+x+3x^2-x+3x^2+x-3x*2-5
Answers
We have values of x and f(x) and choices for the expression of f(x).
We can easily found the correct option just evaluating the expressions in the x values and see which have the correct value of f(x):
For x=2 the outpur=f(x)=9:
[tex]\begin{gathered} x^2+x+3\Rightarrow2^2+2+3=4+5=9,\text{ Correct!!!} \\ x^2-x+3\Rightarrow2^2-2+3=4+1=5 \\ x^2+x-3\Rightarrow2^2+2-3=4-1=3 \\ x\cdot2-5\Rightarrow2\cdot2-5=4-5=-1 \end{gathered}[/tex]You can evaluate in the other values of x and proof that the corretc option is the first.
What would be the correct way to solve this?[tex] {x}^{2} - 5x - 84[/tex]
Answers
Answer:
(x + 7 ) ( x - 12 )
Explanation:
We know that if we multiply any two expressions x + a and x + b then we have
[tex](x+a)(x+b)=x^2+(a+b)x+ab[/tex]Now similarly,
[tex]x^2+(a+b)x+ab=x^2-5x-84[/tex]meaning
[tex]\begin{gathered} a+b=-5 \\ ab=-84 \end{gathered}[/tex]In other words, what are the two numbers that if I add them together I get -5 and If I multiply them I get -84. The answer comes from educated guesses. We guess that if we add 7 and -12 we get 5 and if we multiply then we get -84; therefore,
[tex]\begin{gathered} a=7 \\ b=-12 \end{gathered}[/tex]Hence, the expression can be factored as
[tex]=x^2-5x-84=(x-12)(x+7)[/tex]which is our answer!
Out of 210 racers who started the marathon, 187 completed the race, 16 gave up, and 7 were disqualified. What percentage did not complete the marathon?
Answers
The total number of racers who did not completed the marathon is given by the sum of those who gave up and those who were disqualified.
Then, 16 + 7 = 23 racers did not completed the marathon.
Therefore, is represent a total of 23/210 = 0.11 = 11% (rounded) of the total number of racers.
there are 550 students how many teachers were there be in ratio form
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The ratio of teacher to student is equivalent so teacher to the student ratio is same for all the school A, B, C and D.
Equate the teacher to school ratio for school A and school C to obtain the number of teachers in school C.
[tex]\begin{gathered} \frac{15}{330}=\frac{x}{550} \\ x=\frac{15\cdot550}{330} \\ =25 \end{gathered}[/tex]The number of teacher is school C is 25.
Equate the teachers to students ratio for the school A and school D to obtain the number of students in school D.
[tex]\begin{gathered} \frac{15}{330}=\frac{36}{y} \\ y=\frac{36\cdot330}{15} \\ =792 \end{gathered}[/tex]
The number of students in school D is 792.
A. graph quadrilateral KLMN with vertices K(-3,2),L(2,2),M(0,-3)and N(-4,0) on the coordinate grid.B. on the same coordinate grid,graph the image of quadrilateral KLMN after a translation of three units to the right and four units up.C. witch side of the image is congruent to side LM?Name three other pairs of congruent sides.
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The given points are K(-3,2), L(2,2), M(0,-3), and N(-4,0).
If we graph part A, it would be as the image below shows
Notice that these four points for a quadrilateral.
Now, part B is about shifting the quadrilateral three units right and four units up, so its new coordinates would be K'(0,6), L'(5,6), M'(3,1), and N'(-1,4). So, the new parallelogram is shown in the image below, where you would notice the pre-image and the image.
According to the image above, side LM is congruent to L'M', they are corresponding sides of the transformation. The other three congruent sides are NK to N'K', MN to M'N', and KL to K'L'.
By which Theorem or postulate is Change ABC congruent Change BAD?
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Solution
we are given that
[tex]\begin{gathered} |AB|=|BC| \\ We draw the diagram as followsNotice the lettering on each triangle, they both represent the triangle we are given in the question
The postulate here is Sides, Angle, Sides (SAS)
Option C
in the figure above
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Since AB is tangent to the circle, the angle BAO equals π/2.
The same happens to BC, so the angle BCO also equals π/2.
Now, for any quadrilateral, the sum of the internal angles is 2π. Therefore:
ABC + AOC + BAO + BCO = 2π
ABC + 3π/7 + π/2 + π/2 = 2π
ABC = 2π - 3π/7 - π/2 - π/2 = π - 3π/7 = (7π - 3π)/7
ABC = 4π/7
which of the following reflective symmetries apply to the hexagon?
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The line y = -7x/3 is a line of symmetry to the given hexagon while the line y=x is not a line of symmetry to it
This makes the answer to the first statement Yes and the second statement No. That is
Reflective symmetry over the line y=-7x/3 -------------------Yes
Reflective symmetry over the x-axis ------------------------------------No
Pablo draws Rectangle P. He says that the area is greater than 50 square units. What could the missing side length be? Explain. P. ? units 6 units
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Answer:
Explanation:
Here, we want to get the missing side length
From the question, it was said that the area is greater than 50 square units
What this mean is that the product of the width and length of the rectangle is greater than 50 square units
Therefore, the number in whch we will multiply by 6 must give us a result greater than 50 square units
The highest multiple of 6 closest to 50 is 48 while the closest multiple after 50 is 54
9 multiplied by 6 will give 54 square units
In essence, we can say that the missing side length is 9 square units
Can you pls help me with number 6 my treacher said that it was d but I got b is me correct or my treacher
Answers
Given the algebraic expression below
[tex]6a+4y+a+2a[/tex]Collect like terms
[tex]6a+2a+a+4y[/tex]Add possible like terms using the distributive property of algebra
[tex]\begin{gathered} (6+2+1)a+4y \\ 9a+4y \end{gathered}[/tex]Hence, the final answer is 9a + 4y
Option D is correct
6. Solve by any method:3x - 2y = 6x + y = 2
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we can take any equation and solve for any variable, for example y will solve x from the second equation
[tex]\begin{gathered} x+y=2 \\ x=2-y \end{gathered}[/tex]now replace the value of x on the first equation
[tex]\begin{gathered} 3x-2y=6 \\ 3(2-y)-2y=6 \\ \end{gathered}[/tex]simplify
[tex]\begin{gathered} 6-3y-2y=6 \\ 6-5y=6 \end{gathered}[/tex]and solve for y
[tex]\begin{gathered} -5y=6-6 \\ -5y=0 \\ y=\frac{0}{-5} \\ \\ y=0 \end{gathered}[/tex]Value of y is 0 now we can replace y=0 on any equation and solve for x
for example I will replace y=0 on the second equation to find x
[tex]\begin{gathered} x+y=2 \\ x+(0)=2 \\ x=2 \end{gathered}[/tex]Value of x is 2
If we want to represent the solution as a point, the solution is
[tex](2,0)[/tex]if 5 guys are putting yogurt in a girl's mouth and each liter is 5 liters how much is the girl carrying in her mouth ️️
Answers
5 guys are putting yogurt in a girl's mouth
Each of the yogurt is 5 liters
The total yogurt the girl is carrying = 5 x 5
= 25
The answer is 25 liters of yogurt
use the display of data to find the mean, median, mode, and midrange 10,3, 11,3, 12,4, 13,5, 14,2, 15,3
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The mean, median, mode and midrange of the given data is 7.92, 7.5, 3 and 8.2 respectively.
What is median and midrange?The mid-way between the least value and the greatest value of the data set is called the midrange, and the median is the middle number in a sorted list of numbers.
Given a data 10,3, 11,3, 12,4, 13,5, 14,2, 15,3
Mean = (2+3+3+3+4+5+10+11+12+13+14+15)/12 = 7.92
Median = 15/2 = 7.5
Mode = 3
Midrange = (2+15)/2 = 8.2
Hence, The mean, median, mode and midrange of the given data is 7.92, 7.5, 3 and 8.2 respectively.
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Determine the concavity of the graph of f(x) = 4 - x^2 between x= -1 and x = 5 by calculating average rates of change over intervals of length 2. 1. The average rate of change over the interval 3 ≤ 2 < 5 =
Answers
Given the function:
[tex]f(x)=4-x^2[/tex]For the given function, we will determine the concavity between x = -1 and x = 5
By the average rate of change over the interval 3 ≤ x < 5
We will use the following formula:
[tex]\frac{f(5)-f(3)}{(5)-(3)}[/tex]First, we will find the value of f(5) and f(3)
[tex]\begin{gathered} x=5\rightarrow f(5)=4-5^2=-21 \\ x=3\rightarrow f(3)=4-3^2=-5 \end{gathered}[/tex]Substitute into the formula:
So, the average rate of change will be as follows:
[tex]\frac{f(5)-f(3)}{(5)-(3)}=\frac{(-21)-(-5)}{5-3}=\frac{-16}{2}=-8[/tex]As the average rate of change is negative, the concavity of the graph will be concave down
Two angles are complementary to each other. One angle measures 32°, and the other angle measures (12x − 20)°. Determine the value of x. 64 6.5 32.5 6
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Answer:
B) 6.5
Step-by-step explanation:
Complementary angles are angles that are put together to equal 90 degrees.
Angle one is 32 degrees.
90-32= 58
So we need to get the number 58 for it to be complementary. The reason for this is because 32+58=90. Which would make it complementary.
When we plug in 6.5 we get 58, which is what we want.
12(6.5)- 20= 90
78-20=58
Hope this helps!!!
The value of x is 6.5.
Complimentary angles are known as angles which makes the sum of 90°.
The angles sum up to form a right angle. When two angles complement each other they sum up to be 90°.
According to question one angle - 32° and other angle [12x - 20].
⇒ 32 + [12x - 20] = 90
⇒ 12x - 20 = 58
⇒ 12x = 78
⇒ x = 6.5
Hence, the value of x is 6.5.
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Does the data set display exponential behavior? * {(0, 1), (1, 3), (2, 9), (3, 27)}
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ANSWER
Yes, it does.
EXPLANATION
We want to check if the data set displays an exponential behavior.
An exponential function is one in which the values of the range (y values) increase by a certain factor.
The general form of an exponential function is:
[tex]y=a\cdot b^x[/tex]where a is the starting value
b = factor.
Now, we have to compare the data set with this kind of function.
To do that, we have to find a mock function of the data set using the first two data points to test each x value (domain) for each y value.
Basically, we will replace x in the function with a value and see if we get the correct y.
Therefore, when x = 0:
[tex]\begin{gathered} y=a\cdot b^0 \\ y=a\cdot1 \end{gathered}[/tex]From the data set, we see that, when x = 0, y = 1:
[tex]\begin{gathered} \Rightarrow1=a\cdot1 \\ a=1 \end{gathered}[/tex]That is the value of a.
Now, let us try when x = 1:
[tex]\begin{gathered} \Rightarrow y=1\cdot b^1 \\ y=b \end{gathered}[/tex]From the data set, we see that, when x = 1, y = 3:
[tex]\begin{gathered} \Rightarrow3=b \\ b=3 \end{gathered}[/tex]Now, we can say that we have an exponential function to test with:
[tex]y=3^x[/tex]So, let us test for the remaining values of x and y and see if they match the function.
[tex]\begin{gathered} \text{when x = 2:} \\ y=3^2 \\ y=9 \\ \text{when x = 3:} \\ y=3^3 \\ y=27 \end{gathered}[/tex]As we can see, each x value that goes into the function yields the exact y value as the data set. This means that the exponential function works for it.
Hence, the data set displays an exponential behavior.
1.2.12 m18 inC3.4.35 km5.6.15.6 cm7 mm
Answers
The required solution is the circumference of the circle for the given radius or diameter
The formula for the circumference of a circle with radius r is :
[tex]C\text{ = 2 }\pi\text{ r}[/tex]The formula for the circumference of a circle with diameter d is:
[tex]C\text{ = }\pi\text{ d}[/tex]For the first circle with a radius of 12m:
[tex]\text{Circumference = 2}\times\text{ }\pi\text{ }\times\text{ 12 = 24}\pi[/tex]For the second circle with a diameter of 18in :
[tex]C\text{ = }\pi\text{ }\times\text{ 18 = 18}\pi[/tex]For the third circle with a radius of 2.8ft:
[tex]\begin{gathered} C\text{ = 2 }\times\text{ }\pi\times\text{ 2.8 } \\ =\text{ 5.6}\pi \end{gathered}[/tex]For the fourth circle with a diameter of 35km:
[tex]\begin{gathered} C\text{ = }\pi\text{ d} \\ =\text{ }\pi\text{ }\times\text{ 35 = 35}\pi \end{gathered}[/tex]For the fifth circle with a radius of 7mm:
[tex]\begin{gathered} C\text{ = 2 }\times\pi\times\text{ r} \\ =\text{ 2 }\times\text{ }\pi\text{ }\times\text{ 7} \\ =\text{ 14}\pi \end{gathered}[/tex]For the sixth circle with a radius of 15.6 cm:
[tex]\begin{gathered} C\text{ = 2}\pi r \\ =\text{ 2 }\times\text{ }\pi\text{ }\times\text{ 15.6 } \\ =\text{ 31.2 }\pi \end{gathered}[/tex]Note: Circumference has a unit. It's unit depends on the unit of the radius/ diameter
10. Quadrilateral PQRS with P(-5,1). Q(-2,6), R(3,7), and S(6,4); dilate by a factor of 1/2 12 a. Is this an enlargement or reduction? How do you know? 14 b. What are the vertices of the image after the transformation?
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a.
The dilation is a reduction, this comes from the fact that the dilation factor is less than 1.
b.
A point after a dilation is given as:
[tex](x,y)\rightarrow(kx,ky)[/tex]where k is the dilation factor.
In this case we need to divide all the coordinates by two, then we have that:
[tex]\begin{gathered} P^{\prime}(-\frac{5}{2},\frac{1}{2}) \\ Q^{\prime}(-1,3) \\ R^{\prime}(\frac{3}{2},\frac{7}{2}) \\ S^{\prime}(3,2) \end{gathered}[/tex]Name the relationship between the pair of angles and find the value of x.
Answers
Consecutive interior angles (Same side)
x = -8
Explanations:The two angles are 136 + x and x + 56
The two angles are consecutive-interior angles because they are on the same side of the transversal.
Note that consecutive -interior angles are supplementary and they add up to 180 degrees.
Applying this rule to the diagram shown:
(136 + x) + (x + 56) = 180
136 + 56 + x + x = 180
192 + 2x = 180
2x = 180 - 196
2x = -16
x = -16 / 2
x = -8
Determine the area of the figure: 1.5 cm 5 cm 5.5 cm Your answer
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We can add the are of the 3 rectangle, so we get that the area is:
[tex]A=1.5\cdot5+1.5\cdot5+1.5\cdot0.5=15.75\operatorname{cm}[/tex]Describe in words where cube root of 30 would be plotted on a number line.
Between 3 and 4, but closer to 3
Between 3 and 4, but closer to 4
Between 2 and 3, but closer to 2
Between 2 and 3, but closer to 3
Answers
Cube root of 30 is 3.107.
How to find cube root of a number?
Cube root is the number that needs to be multiplied three times to get the original number.
The cube root of a number can be determined by using the prime factorization method. In order to find the cube root of a number:
Step 1: Start with the prime factorization of the given number.
Step 2: Then, divide the factors obtained into groups containing three same factors.
Step 3: After that, remove the cube root symbol and multiply the factors to get the answer. If there is any factor left that cannot be divided equally into groups of three, that means the given number is not a perfect cube and we cannot find the cube root of that number.
We have to find the cube root of 30.
Prime factorization of 30 = 2*3*5.
Therefore the cube root of 30 = ∛(2*3*5)= ∛30 .
As ∛30 cannot be reduced further, then the result for the cube root of 30 is an irrational number as well.
So here we will use approximation method to find the cube root of 30 using Halley's approach:
Halley’s Cube Root Formula: ∛a = x[(x³ + 2a)/(2x³ + a)]
The letter “a” stands in for the required cube root computation.
Take the cube root of the nearest perfect cube, “x” to obtain the estimated value.
Here we have a = 30
and we will substitute x = 3 because 3³ = 27< 30 is the nearest perfect cube.
Substituting a and x in Halley's formula,
∛30 = 3[(3³ + 2*30)/(2*3³ + 30)]
= 3[(27+60)/(54+30)]
= 3(87/84)
= 3*1.0357
∛30 = 3.107.
Therefore the cube root of 30 is 3.107.
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Which number line represents the solution set for the inequality 3(8 - 4x) < 6(x - 5)?-5-4-3-2 -1 01+4123on++at-5-2+ o+1-1234501-5-4-3+o-2-1+1N+W+A+5++-5-4-3-2+o-1NT1345
Answers
To find the solution, lets first simplify the inequality:
[tex]undefined[/tex]describe the transformations that occur from the parent function f(x) = x2 to the function g(x) =2(x+1)^2-7
Answers
we have
f(x)=x^2
this is a vertical parabola with vertex at (0,0)
and
we have
g(x)=2(x+1)^2-7
this is a vertical parabola with vertex at (-1,-7)
so
the transformation of f(x) to g(x) is equal to
(0,0) ------> (-1,-7)
the rule of the translation is equal to
(x,y) --------> (x-1, y-7)
that means ------> the translation is 1 unit at left and 7 units down
and we have a second transformation
(x,y) -------> (ax, y)
the factor a is 2
therefore
First transformation
x^2 --------> 2x^2
second transformation
2x^2---------> 2(x+1)^2-7
in the diagram of JEA below, JEA = 90° and EAJ = 48°. Line segment MS connects points M and S on the triangle, such that EMS = 59°. Find the measure of JSM.
Answers
The value of m∠JSM is 17 degrees.
Given data;
The measure of the ∠JAE = 48 degrees.
The measure of the ∠AEJ = 90 degrees.
The measure of the ∠EMS = 59 degrees.
In triangle JEA;
By angle sum property, we know that;
∠JAE + ∠AEJ + ∠EJA = 180 degree
Substitute the given values in the above expression.
48 degree + 90 degree + ∠EJA = 180 degree
∠EJA = 42 degrees
The angle JMS is,
∠JMS = 180 - ∠EMS (Linear pair)
∠JMS = 180 degrees - 59 degrees = 121 degrees.
In triangle JMS,
By angle sum property, we know that;
∠JMS + ∠JSM + ∠EJA = 180 degree
121 degree + ∠JSM + 42 degree = 180 degree
∠JSM = 17 degree
Thus, the measure of ∠JSM is 17 degrees.
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How can i calculate the number of students that graduated from the university faculty of natural sciences in 2002? how can i determine the sector angle that will represent the number of graduates in each subject? how can i hence construct a pie chart of radius 4cm to represent the information given in the table?
Answers
A table showing the number of graduates by subject from a university's faculty of natural science in 2002.
1) To calculate the number of students that graduated, find the sum of the number of graduates from each subject.
[tex]9+15+19+12+5=60[/tex]The number of students that graduated is 60.
2) To determine the sector angle that will represent the number of graduates in each subject, divide the number of graduates in each subject by the total number of students and then multiply by 360º.
3) To construct a pie chart with radius, 4cm to represent the information, draw a circle of radius 4cm and partition it into sectors with central angles as calculated in (2) above.
Hello! I need some assistance with this homework question, pleaseQ13
Answers
we have the new function
[tex]f(x)=\frac{2}{3}\mleft|x\mright|+3[/tex]The vertex of this function is the ordered pair (0,3)
The coordinates of the second point
(2,2) ------------> (2,f(2))
Find the value of f(2)
[tex]\begin{gathered} f(2)=\frac{2}{3}|2|+3 \\ f(2)=\frac{2}{3}\cdot(2)+3 \\ f(2)=\frac{4}{3}+3=\frac{13}{3} \end{gathered}[/tex]the new coordinates of point (2,2) are (2,13/3)
see the attached figure
a ladder is leaning against the side of a brick wall the base of the ladder is 6 feet away from the brick wall the top of the ladder touches the brick wall at 8 feet from the ground how long is the ladder 4ft 10 feet or 14 feet or 7 feet
Answers
The base of ladder is at distance of b = 6 feet from the wall.
The height of top of ladder from ground is h = 8 feet.
Let the length of ladder be l.
Determine the length of ladder by using the pythagoras theorem.
[tex]\begin{gathered} l^2=(6)^2+(8)^2 \\ =36+64 \\ =100 \\ l=\sqrt[]{100} \\ =10 \end{gathered}[/tex]So length of the ladder is 10 feet.
Find the product: (2×^2+3)^2
Answers
(2x + 3)²
We will simply expand
(2x + 3)(2x + 3)
2x(2x+3) + 3(2x+ 3)
open the parentheses
4x² + 6x + 6x + 9
4x² + 12x + 9
8. Determine the most precise name for quadrilateral PQRS.-8 -6P(-1, 1)-4 -28642-2-4-6-8Q(0, 2)R(1, 1)2S(0, -2)468
Answers
Answer:
[tex]Kite[/tex]Explanation:
Here, we want to determine the most precise name for the quadrilateral
At first sight, the image plot looks like a kite. We will have to confirm this using the properties of a kite
One of the important properties is to check that the diagonals intersect at right angles
Looking at the plot, QS and PR must be perpendicular
This is correct as they meet at right angles at the line through the origin
Also, for us to have a kite, PQ and QR must be equal
This is also correct as PQ and QR are equal in length
Furthermore, PS and RS must be equal in length
This is alo correct as the two are equal in length
We thus conclude that the quadrilateral is a kitecohis is als
plot looks like a kite. We will have to confirm this using the properties of a kite
plot looks like a kite. We will have to confirm this using the properties of a kite