Describe where microwaves are found on the ems compared to the other six forms of radiation.

The objective of the experiment of submerging different objects in fluid is to determine the density of the unknown material using Archimedes' principle.

Archimedes' principle- The amount of the upward force felt by the object when submerged in fluid is equal tot he weight of the mass of the fluid displaced.

So, in this experiment,

The objects of unknown densities are submerged in liquid, they displaces some amount of liquid. The amount of liquid is related to the buoyancy of the unknown object as,

Vₐpg = Vσg

where,

p is the density of the unknown object,

σ is the density of the fluid and Vₐ is the volume of the body submerged in fluid and V is the volume of the water displaced.

So, by this relation, we can find the density of the unknown material.

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Answer: C

Explanation: because it is made out of metal.

Answer:

C- iron nail.

Explanation:

iron nails are attracted to magnets and that's made of magnetic material.

The vertical component (height) of the pendulum's maximum displacement is 0.146 meters.

In physics, the maximum displacement or range traveled by a point on a vibrating body or wave calculated from its equilibrium position is known as amplitude. It is one-half of the length of the vibration path.

We have a collision when the bullet hits the pendulum, and momentum is preserved in any collision. Let the pendulum's beginning momentum and the bullet's initial momentum be, p₁ and p₂, respectively.

Following the impact, the pendulum and the bullet travel as one object with the same velocity, v. Let p₃ be the momentum of the pendulum and as well as the bullet following the impact.

Hence,

First momentum = Last Momentum

p₁ + p₂ = p₃

[3.4kg x 0m/s] +([2.90 x 10⁻²] x 200m/s) = 3.48kg x v

Simplified, we have

5.8kg · m/s = 3.49kg · v

Making v the subject of the formula, we have

v = 1.69m/s

As a result, the combined velocity of the pendulum and bullet after the contact is v = 1.69 m/s.

We are now using the conservation of energy equation. The potential energy at the maximum height will be equal to the kinetic energy of the pendulum plus the bullet.

mgh = 1/2mv²

Where

m is the mass in kilograms

g is the acceleration due to gravity

h is height in meters; and

v is velocity

If we divide both sides with m and make h the subject of the formula, we have:

h = v²/2g

= (1.69m/s)²/2 (9.81)m/s²

= 0.14557084607m

Hence,

The vertical component of the pendulum's maximum displacement (h) [tex]\approx[/tex] 0.146m

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Full Question:

A 29-g rifle bullet traveling 220 m/s embeds itself in a 3.9-kg pendulum hanging on a 3.0-m-long string, which makes the pendulum swing upward in an arc.

Determine the vertical component of the pendulum's maximum displacement. Express your answer in two significant figures and include the appropriate units.

Answer:

Explanation:

Given:

m₁

m₂

R₁

F₁ = 16 units

m₁' = 2·m₁

m₂' = 2·m₂

R₂ = 2·R₁

_________

F₂ - ?

The force of gravity:

F₁ = G·m₁·m₂ / (R₁)²

F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =

= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁

F₂ = F₁ = 16 units

ANSWER:

a) 55.82 m/s

b) 49.8 m/s

c) 5.17 kg

STEP-BY-STEP EXPLANATION:

Given:

Height (h) = 159 m

Initial speed (vi) = 0 m/s

a)

We calculate the final speed using the following formula:

b)

To determine the final velocity with the opposing force, we have to determine the net force and then calculate the acceleration that would be used to calculate the velocity, like this:

c)

We can calculate the mass in the following way, first, we must calculate the acceleration to be able to determine the mass:

The centripetal acceleration arad and tangential acceleration atan compare at points P and Q by Q having a greater arad and atan than point P.

arad = v² / r

v = 2 π r / T

arad = 4 π² r / T²

Since time period will be constant at any point in the radius line,

arad ∝ r

So larger the radius, larger will be the centripetal acceleration. The radius at point P is smaller than the radius at point Q.

arad at Q > arad at P

atan = r α

α = 2 π / T²

atan = 2 r π / T²

Since time period will be constant at any point in the radius line,

atan ∝ r

So larger the radius, larger will be the tangential acceleration. The radius at point P is smaller than the radius at point Q.

atan at Q > atan at P

Therefore, Q has a greater arad and atan than point P.

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Based on the relationship between pressure and volume, the volume of the gas will increase if the pressure of a gas goes from 1 atm to 0.5 atm.

According to ideal gas equation,

PV = nRT

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

At constant Temperature,

P ∝ 1 / V  → ( 1 )

From ( 1 ), it can be clearly seen that pressure is inversely proportional to volume. So as pressure increases the volume will decrease and if the pressure decreases, the volume will increase. In the given situation, the pressure is decreased. So the volume will increase.

Therefore, the volume of the gas will increase if the pressure of a gas goes from 1 atm to 0.5 atm.

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smaller than the object and upright.

We have a negative lens, the image is between the object and the lens.

The top of the virtual image must be below and touching the ray that connects the top of the car with the lens (green)

So, the image will be smaller than the car and it won't be inverted.

The power crane used is2× 10⁵ W.

The amount of work finished in a specific length of time is a definition of power. The SI unit of power is the watt (W), which is derived from joules per second (J/s). Horsepower (hp) is a unit of measurement sometimes used to express the power of motor vehicles and other equipment. It is roughly comparable to 745.7 watts.

Given parameters:

Work done  = 600,000J

Time taken  = 30s

Unknown:

Power of the crane = ?

Mathematically,

Power = Work done /time taken

= 600,000J/30

Power= 200000 W

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Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dark matter. Their rotational curves be different as the orbital speeds would fall off sharply with increasing distance from the galactic center.

Plotting the orbital speeds vs radius graph gives us the rotational curves. According to the theoretical calculations, the curve increases as the radial distance decrease and then decreases as the radial distance increases. The theoretical graph does not take the dark matter into account.

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Between visible light and microwave is where infrared falls. Infrared has a higher energy than radio but a lower energy than gamma rays.

The term "infrared" refers to electromagnetic waves that exist within the electromagnetic spectrum at frequencies slightly below those of red visible light and just above those of microwaves. According to the California Institute of Technology, the wavelengths of infrared radiation are longer than those of visible light (Caltech).

The majority of the radio portion of the electromagnetic spectrum (EM spectrum) is found between 1 cm and 1 km, or 30 GHz and 300 kHz in frequency. The EM spectrum's radio region is relatively vast. Astronomers usually employ wavelength in the infrared and optical spectrum.

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1. The constant speed of Ashley for first four minute of her trip is calculated here

For first four minutes Ashley travelled 800 m distance (d) , substituting this value in the formula of speed

Speed(s) = distance (d)/ time (t)

Speed(s) = 800/4

Speed(s)= 200m/s

2. Ashley's average speed for the entire trip is

The total distance (d) traveled by Ashley is 1600 m and time (t) taken for that is 10 minutes.

Speed (s)=  distance(d)/time(t)

Speed (s)= 1600/10

Speed(s) = 160m/s

3. The average velocity of Ashley is 160 m/s in east direction. As velocity is nothing but speed with direction.

4.  In graph there is linear slop when Ashley was 800 m away from her house where net displacement is zero means she stopped there to talk with friend.

5. Slope of line after Ashley stopped to talk to her friend is

Slope = [tex]X_{2}[/tex] - [tex]X_{1}[/tex]/ [tex]Y_{2}[/tex]-[tex]Y_{1}[/tex]

Slope= 8-0/800-800

Slope= 0 as it is a linear line and slope of it is zero.

6. The slope of a line is related to her speed as speed increases the slope increases.

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Answer:

Option C is correct. The ball keeps moving forward and falls downward at the same time.

Explanation:

When the ball reaches the edge of the cliff, its forward motion will indeed continue due to its inertia. Inertia is the property of an object to maintain its state of motion. However, gravity will also be acting on the ball, causing it to accelerate downward.

As a result, the ball will move forward and descend downward at the same time. The trajectory of the ball will be a curved path that combines the horizontal motion (forward movement) and the vertical motion (downward fall) simultaneously. This curved path is known as a parabolic trajectory.

The exact shape of the trajectory will depend on factors such as the initial velocity, angle of the cliff, and air resistance. If there is no air resistance and the cliff is not too steep, the ball's trajectory may resemble a smooth parabolic curve. However, if there is air resistance or the cliff is steep, the trajectory might deviate from a perfect parabola.

Eventually, due to the downward acceleration caused by gravity, the ball's vertical motion will dominate, and it will fall straight down. But immediately after reaching the edge of the cliff, the ball will experience a combination of forward motion and downward descent.

If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.

Matter :

A substance called matter is made up of different kinds of particles, occupies space, and has inertia.

The various types of particles each have a unique mass and size according to the fundamentals of modern physics.

Antimatter :

As the opposite particles of the corresponding particles in "ordinary" matter, the antimatter is defined as matter made up of them.

The two particles' combined mass is entirely converted into energy. The term "matter-antimatter annihilation" refers to this process.

If a gram of antimatter meets a kilogram of matter, the amount of mass to survive is 1 gram.

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Given data:

* The change in gravitational potential energy is 26500 J.

* The change in height of the diver is 33.0 m.

Solution:

The change in gravitational potential energy in terms of change in height of the diver is,

where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,

Substituting the known values,

The weight of the diver is,

Thus, weight of the diver is 803.03 N.

Answer:

E) The rod remains uncharted.

Explanation:

The negatively charges rod has an excess of electrons. These electrons repel each other, so when this rod touches the horizontal uncharged insulating rod, they will try to go to the uncharge rod. However, this is an insulating rod, so there will be no transfer of electrons. It means that the rod remains uncharted.

The speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s

Torricelli's theorem states that the speed of a liquid flowing through an orifice is equal to the speed it would attain if falling freely a distance equal to the height of the liquid's free surface above the orifice.

Given that

A hoop of the moment of inertia released from the top of an inclined plane 20m high and length 32m rolls drawn without slipping

W have to determine the speed and acceleration when it reaches the foot of the inclined plane

By using Torricelli's theorem

V= √2gh

Here g= 9.8 and h = 20m

V= √2x9.8x20

V= √4x9.8

V= 14√2 m/s

Therefore the speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s

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Answer:

830 cm

Explanation:

From 0 - 4

acceleration = slope =  90 /4 = 22.5

   distance = 1/2 at^2 =   1/2 (22.5)(4^2) = 180 cm

from 4-7   velocity is constant 90 cm/s    = 270 cm

from 7-11   acceleration = slope =  10 /4  = 2.5 m/s^2

    distance =vo t   + 1/2 a t^2  = 90(4) + 1/2 (2.5)(4^2) = 380 cm

Summed = 180 + 270 + 380 = 830 cm

Answer:

Explanation:

Given:

t₀ = 0 s

V₀ = 0 cm/s = 0 m/s

t = 11 s

V = 100 cm/s = 1 m/s

________________

| S |  - ?

Movement module:

| S | =  V·t = 1·11 = 11 m

(The displacement is numerically equal to the area of the triangle AOB):

Answer:

Explanation: 1: The gas particles move in a straight line before colliding with something, usually the wall of their containers.

2: The is no attraction or repulsion between the gas particles.

The magnetic field of magnet A extends further than the magnetic field of magnet B concludes that magnet A is larger in size and have stronger magnetic field than magnet B.

A magnetic field is a vector field that represents the effect of magnetic effect on moving charges, currents, and magnetic bodies. A charge moving in a magnetic field experiences a force perpendicular to its velocity and magnetic field.

Does size affect the strength of a magnet ? The answer is yes, but it's because the size of a magnet is proportional to its ability to align and produce a stronger magnetic field than smaller pieces of the same material. Because it means there are more domains.

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Given:

• Mass of ice = 295 g ==> 0.295 kg

• Initial temperature, T1 = -5°C

• Final temperature, T2 = 20°C

Let's find the amount of heat necessary to change the ice to water.

To find the amount of heat, let's apply the Specific Heat Capacity formula:

Where:

m is the mass in kg = 0.295 kg

T1 is the initial temperature

T2 is the final temperature.

c is the specific heat capacity

Let's first find the amount of heat required to change ice from -5°C to 0°C.

Now, let's find the heat required to change from 0°C(ice) to 0°C(water).

We have:

Where L is the latent fusion of water:

Now, let's find the heat required to change 0°C (water) to 20°C(water).

We have:

Therefore, the total heat required is:

Q = Q1 + Q2 + Q3

Thus, we have:

Therefore, the amount of heat neccesary is

11.1 m and -18.4 m is the  ball's position, 5.2 m/s and -24.2 m/s  is the  ball's velocity  after leaving your hand

s = ut + 1/2at²

s = 15(t) + 1/2(-9.8)(t)²

s = 15t - 4.5(t)²

t = 1 second,

s = 15(1) - 4.9(1)²

s = 15 - 4.5

s = 11.1 m  [at t = 1 second]

t = 4 seconds,

s = 15(4) - 4.9(4)²

s = 60 - 4.9(16)

s = 60 - 78.4

s = -18.4 m  [t = 4 seconds]

v = u + at

v = 15 + (-9.8)t

time = 1 second,

v = 15 - 9.8

v = 5.2 m/s [ t = 1 second]

time = 4 seconds,

v = 15 - (9.8)(4)

v = 15 - 39.2

v = -24.2 m/s   [for t = 4 seconds]

velocity's a vector quantity have magnitude and direction.

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The driver of a car going 16.0 m/s suddenly sees the lights of a barrier 84.0 m ahead. It takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. The total displacement of the car 9.19 m

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

s = u*t + 1/2 a [tex]t^{2}[/tex]

s = displacement

u = initial speed

t = time

a = acceleration

s = 16 * 0.75 + 1/2 * ( -10 ) * [tex](0.75)^{2}[/tex] = 9.19 m

The total displacement of the car will be 9.19 m

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The kinetic energy when it returns to its original height is 100 J

The ball is thrown up with a Kinetic Energy K. E. = 0.5×m×v² = 100 J

Therefore the final height is given by

u² = v² -2·g·s

Where:

u = final velocity = 0

v = initial velocity

s = final height

Therefore v² = 2·g·s = 19.62·s

P.E = Potential Energy = m·g·s

Since v² = 2·g·s

Substituting the value of v² in the kinetic energy formula, we obtain

K. E. = 0.5×m×2·g·s = m·g·s = P.E. = 100 J

When the ball returns to the original height, we have

v² = u² + 2·g·s

Since u = 0 = initial velocity in this case we have

v² = 2·g·s and the Kinetic energy = 0.5·m·v²

Since m and s are the same then 0.5·m·v² = 100 J.

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You can improve how you handle stress and difficulties (adversity) in your life by using a variety of stress management techniques. You may lead a more well-balanced existence by controlling your stress.

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ANSWER:

6 m/s

STEP-BY-STEP EXPLANATION:

Given:

Mass of balls (m) = 3.86 kg

Initial speed of ball 1 (u1) = 5 m/s

Final speed of ball 1 (v1) = - 1 m/s

Initial speed of ball 2 (u2) = 0 m/s

We make the balance for the moment and we are left with the following:

Therefore, the speed of the second ball is equal to 6 m/s

Given,

The extension of the spring due to the attached mass, x=1.24 m

The spring constant, k=330 N/m

The weight of a mass m is given by,

Where g is the acceleration due to gravity,

The magnitude of the restoring force of a spring is given by,

Therefore,

On substituting the known values,

Thus the mass of the weight is 41.76 kg

The final velocity of the car 120.93 m/sec.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question, a car travelling with an initial velocity of 15.0 m/s, accelerates at 2.40 m/s² over a distance of 180 m

Using equation of motion,

v² = u² + 2as

v² = 15² + 2*40*180

v =  120.93 m/sec

The final velocity of the car 120.93 m/sec.

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A car moving at 46 km/h skids 15 m with locked brakes. The distance travelled by the car when it skids is 94.74 m.

The acceleration of the car is calculated by applying the following kinematic equation.

v² = u² - 2as

where,

v is the final velocity of the car

u is the initial velocity of the car

a is the acceleration of the car

s is the distance travelled by the car

when the car stops, the final velocity, v = 0

0 = u² - 2as

2as = u²

a = u²/2s

where,

u = 46 km/h = 12.7 m/s

a = (12.7²) / (2 x 15)

a = 5.37 m/s²

When the speed of the car changes from 42 km/h to 126 km/h, the distance travelled by the car at the same acceleration is calculated as follows;

s =  u²/2a

where,

u = 115 km/h = 31.9 m/s

s = (31.9²) / ( 2 x 5.37)

s = 94.74 m

The distance travelled by the car when it skids is 94.74 m.

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