EXPLANATION
Since we have the function:
[tex]f(x)=\frac{x^2-8x+15}{x^2}[/tex]Vertical asymptotes:
[tex]For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.[/tex]Taking the denominator and comparing to zero:
[tex]x+5=0[/tex]The following points are undefined:
[tex]x=-5[/tex]Therefore, the vertical asymptote is at x=-5
Horizontal asymptotes:
[tex]\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.[/tex][tex]If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.[/tex][tex]If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}[/tex][tex]\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}[/tex][tex]\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1[/tex][tex]\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}[/tex][tex]\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1[/tex][tex]y=\frac{1}{1}[/tex][tex]\mathrm{The\:horizontal\:asymptote\:is:}[/tex][tex]y=1[/tex]In conclusion:
[tex]\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1[/tex]How would I find the length of the highlighted arc in the circle? Also I need to know how I would right the answer using pi as the symbol
The rule of the length of the arc of a circle is
[tex]L=\frac{x^{\circ}}{360^{\circ}}\times2\pi r[/tex]Where
x is the central angle subtended by the arc
r is the radius of the circle
From the given figure
The radius is 3 units, then
r = 3
The central angle of the highlight arc is a right angle, then
x = 90 degrees
Substitute them in the rule above
[tex]\begin{gathered} L=\frac{90}{360}\times2\times\pi\times3 \\ \\ L=\frac{1}{4}\times6\pi \\ \\ L=\frac{6}{4}\pi \\ \\ L=\frac{3}{2}\pi \\ \\ L=1.5\pi\text{ unit} \end{gathered}[/tex]The length of the highlight arc is 1.5pi units
A smaller number and a larger number add up to 8 and have a difference of 6. (Let X be the larger number and Y be the smaller number)
If the larger number is x, and the smaller one is y, then what we have is;
[tex]\begin{gathered} x+y=8---(1)\text{ both add up to 8} \\ x-y=6---(2)\text{ both have a difference of 6} \\ \text{From equation (1), make x the subject,} \\ x=8-y \\ \text{Substitute for the value of x into equation (2)} \\ x-y=6 \\ (8-y)-y=6 \\ 8-y-y=6 \\ 8-2y=6 \\ 8-6=2y \\ 2=2y \\ \text{Divide both sides by 2} \\ y=1 \\ \text{If x+y=8, then when y=1} \\ x+1=8 \\ x=8-1 \\ x=7 \end{gathered}[/tex]Therefore, the numbers are 7 and 1
X^3+3x^2+kx-10 and x-1 is a factor what is k
Answer:
6
Step-by-step explanation:
Using the factor theorem, the expression evaluated at [tex]x=1[/tex] will equal [tex]0[/tex].
[tex]1^3+3(1^2)+k(1)-10=0 \\ \\ 1+3+k-10=0 \\ \\ k=6[/tex]
÷5=9i need help please
Answer
The missing number = 45
Explanation
Let the unknown number be x
x ÷ 5 = 9
Multiply both sides by 5
x ÷ 5 × 5 = 9 × 5
x = 45
Hope this Helps!!!
What is the average rate of change of f over the interval [-3, 9]? Give an exact number.
Answer: the answer is -5/6
Step-by-step explanation:
What are the coordinates of J A G when reflected over the line y=2?
We can start by plotting the triangle JAG and the line y = 2 to see how we can solve it:
We can see the line y = 2 (red line) over which we have to reflect the point J, A and G.
To do that we have to look at the distance of each point to the line.
This distance will be the distance at which the image point will be located, opposite to the the original point.
As y = 2 is an horizontal line, the distance is vertical and the x-coordinate of the original points and the images will remain equal. Only the y-coordinate will change.
We can sketch the procedure as:
Then, for example, poing G is 1 unit below y = 2, so its image G' will be one unit over the line y = 2, locating at (2,3).
Point J is 2 units above y = 2, so J' will be 2 units below y = 2.
Point A is 3 units above y = 2, so A' will be 3 untis below y = 2
We can plot the remaining points as:
The red triangle is the original triangle and the blue triangle is the image.
Answer:
The coordinates are J'=(1,0), A'=(3,-1) and G'=(2,3).
Upload your work at the end email to your teacher for full credit. Do not enter any words/spaces. Your answer should be a whole number. Answer:
x = 4
The area of the figure can be found below.
The size of the farm is a rectangle therefore, we use the area of a rectangle to find the area of the farm.
[tex]\begin{gathered} \text{area of the farm=lw} \\ \text{where} \\ l=\text{length} \\ w=\text{width} \\ l=3x+1+2x+4+5x-2=10x+3=10\times4+3=43 \\ w=2x+1+3x=5x+1=5\times4+1=21 \\ \text{area}=43\times21=903unit^2 \end{gathered}[/tex]Combine like terms. -3 + 7x^2- 4x – 5 + 3x^2 – 2x
The expression is given as,
[tex]-3+7x^2-4x-5+3x^2-2x[/tex]Rearranging the like terms,
[tex]7x^2+3x^2-4x-2x-5-3[/tex]Like terms : Terms that have same power of variable.
Simplifying further,
[tex]10x^2-6x-8[/tex]Thus the result of the given expression is,
[tex]10x^2-6x-8[/tex]Answer:
-8 + 10x^2 - 6x
Step-by-step explanation:
(doesn’t have to be in this order)
1. Combine numbers with the x^2
-3 + 10x^2 - 4x - 5 - 2x
2. Combine regular numbers
-8 + 10x^2 - 4x - 2x
3. Combine numbers with the plain x
-8 + 10x^2 - 6x
How many miles did a plane travel if it flew 455 miles per hour in 3 hours?
The distance travelled by the plane is 1365 miles.
Given,
Speed of the pane =455 miles per hour
Time taken =3 hours
To find distance covered by the plane use formula,
[tex]speed =\frac{Distance}{Time taken}\\ \\Distance=Speed * time taken\\\\Distance=455*3\\\\Distance=1365 miles[/tex]
Thus, the distance travelled by the plane is 1365 miles.
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Noam had a length of
13
1
3
cm
13
3
1
cm13, start fraction, 1, divided by, 3, end fraction, start text, c, m, end text of ribbon and cut
3
1
3
3
3
1
3, start fraction, 1, divided by, 3, end fraction equal-sized strips the full width of the ribbon.
How long is each whole strip?
The length of each strip is 4 cm
In this question, we have been given Noam had a length of 13 1/3 cm of ribbon and cut 3 1/3 equal sized strips the full width of the ribbon.
We need to find the length of each whole strip.
first we convert the improper fraction into a proper fraction.
13 1/3 = 40/3
3 1/3 = 10/3
To find the length of each whole strip, we need to divide 13 1/3 by 3 1/3
i.e., 40/3 ÷ 10/3
= (40/3) / (10/3)
= 40/3 × 3/10
= 40/10
= 4
Therefore, the length of each strip is 4 cm
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Answer:
4
Step-by-step explanation:
Just did it on khan academy.
Two friends drive off in different directions from the same place. One heads North at 40 miles per hour, while the other heads East at 25 miles per hour.
Complete an equation for the distance between the friends after t hours.
The equation for the distance between the friends after t hours is 47.17t.
What is the distance between two points?Let one point be (x, y) and another point be (h, k). Then the distance between the points will be
D² = (x - h)² + (y - k)²
Two companions drive off this way and from a similar spot. One travels North at 40 miles each hour, while different travels East at 25 miles each hour.
The equation for the distance between the friends after t hours is given as,
Let the x-axis as east and the y-axis as north. Then the coordinate after t hours will be (25t, 0) and (0, 40t). Then the distance between them is given as,
D² = (25t - 0)² + (0 - 40t)²
D² = 625t² + 1600t²
D² = 2,225t²
D = 47.17 t
The equation for the distance between the friends after t hours is 47.17t.
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b) Solve x + 5x - 14 = 0
Help me please (question in photo)
To graph the ellipse, connect (-2, -3), (6, 2), (14, -3), and (6, -8) with a smooth curve
How to graph an ellipse?The standard form of the equation of an ellipse with center (h, k) and major axis parallel to the x-axis is:
(x-h)²/a² + (y-k)²/b² = 1
When a>b
Major axis length = 2a
Coordinates of the vertices are (h±a, k)
Minor axis length is 2b
Coordinates of covertices are (h, k±b)
Coordinates of foci are (h±c, k). Also c²= a²-b²
Given: the equation (x-6)²/64 + (y+3)²/25 = 1
Comparing the given equation with (x-h)²/a² + (y-k)²/b² = 1:
h = 6, k = -3 => (h, k ) = (6, -3)
Thus, the center of the ellipse is (6, -3)
Coordinates of the vertices are (h±a, k)
Since a² = 64, a = √64 = 8
Thus, the endpoints of the major axis are 8 units from the center
(h±a, k) implies (h-a, k) or (h+a, k). Thus:
(h±a, k) = (6-8, -3) = (-2, -3) or (6+8, -3) = (14, -3)
Coordinates of covertices are (h, k±b)
Since b² = 25, a = √25 = 5
Thus, the endpoints of the minor axis are 5 units from the center
(h, k±b) implies (h, k-b) or (h, k+b). Thus:
(h, k±b) = (6, -3-5) = (6, -8) or (6, -3+5) = (6, 2)
Therefore:
The center of the ellipse is (6, -3). The endpoints of the major axis are 8 units from the center. The endpoints of the minor axis 5 are units from the center.
To graph the ellipse, connect (-2, -3), (6, 2), (14, -3), and (6, -8) with a smooth curve.
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A, B, and C are collinear, and point B lies in between point A and point C. Point D is a point not on the line. Given thatmZABD = (x - 2)° and mZCBD = (5x), find mZCBD.
Answer:
70degrees
Explanation:
The diagrammatical representation of the statement is as shown;
Since the sum of angles on a straight line is 180degrees, then;
m8x+2 + 5x = 180
13x + 2 = 180
13x = 180 + 2
13x = 182
x = 182/13
x = 14
Get mmmmHence the measure of m
7. Write an equation of the line parallel to y = 8x - 1 that contains (-6, 2). Please write the equation
in slope-intercept form.
Answer:
you have to use the formula of a line passing through a point, so: y-y0=m(x-x0)
We also know that m=8, because it is parallel to the line y=(8=m)x -1
so: y-2=8(x+6)
and you solve it, so:
y-2=8x+48
y=8x+48+2
y=8x+50
(G.5d, 1 pt) Determine the range for the measure of AC. А 10 m B 13 m O A. 10
The length of a side must be less than the sum of the other two sides. Here, that means x < 10+13, or x < 23.
In addition, remember that the length of a side must be greater than the difference of the other two sides. That means x > 13 - 10, or x > 3.
Therefore we have two limits for the value of x: 3 and 23.
3 < x < 23
PLEASE HELP ME WITH THE QUESTION IN THE PIC BELOW
Let's calculate the distance between F and G:
F=(-4,-2)
G=(2,-2)
[tex]d=\sqrt[]{(2-(-4))^2+(-2-(-2))^2}=\sqrt[]{36}=6[/tex]The distance between M and P is half the distance between F and G, so:
[tex]\frac{d}{2}=3[/tex]The coordinates of P are:
P=(2,-8)
and
M=(x,-8)
So:
[tex]\begin{gathered} 3=\sqrt[]{(x-2)^2+\mleft(-8-\mleft(-8\mright)\mright)^2} \\ 3=x-2 \\ \text{solving for x:} \\ 3+2=x \\ 5=x \\ x=\pm5 \\ \end{gathered}[/tex]Since M is in the 3rd quadrant:
M= (-5,-8)
----------------------------------------------
Let:
(x1,y1)=(-2,1)
(x2,y2)=(-5,4)
[tex]\begin{gathered} d=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ d=\sqrt[]{(-5-(-2))^2+(4-1)^2} \\ d=\sqrt[]{9+9}=\sqrt[]{18} \end{gathered}[/tex]It is stretched horizontally by a factor of 2 and translated up 3 units.
It is compressed horizontally by a factor of 2 and translated up 3 units.
It is stretched vertically by a factor of 2 and translated up 3 units.
It is compressed vertically by a factor of 2 and translated up 3 units.
The correct option B. It is compressed horizontally by a factor of 2 and translated up 3 units.
What is meant by the term translation?The translated shapes appear to be the same size as that of the original shape, and thus the shapes are congruent. They were simply shifted in one or even more directions. There isn't any change in the form because it is simply moved from one location to another.For the given question;
The image function is defined as ; y = ㏒(2x) + 3
The parent function is; y = ㏒(x).
The first graph, X, is multiplied by 2 (2x), compressing it horizontally by a factor of 2.The number 3 is then added, which moves the graph up three units.Thus, the image function y = ㏒(2x) + 3 is obtained by the process as,compressed horizontally by a factor of 2 and translated up 3 units.
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The complete question is-
How is the graph of y = ㏒(2x) + 3 related to the graph of y = ㏒(x).
Options are-
A. It is stretched horizontally by a factor of 2 and translated up 3 units.
B. It is compressed horizontally by a factor of 2 and translated up 3 units.
C. It is stretched vertically by a factor of 2 and translated up 3 units.
D. It is compressed vertically by a factor of 2 and translated up 3 units.
[tex]3/7*14/15*10/18\\[/tex]
The value of the fraction 3/7 × 14/15 × 10/18 is 2/9.
What is a fraction?A fraction is simply a piece of a whole. The number is represented mathematically as a quotient where the numerator and denominator are split. In a simple fraction, the numerator as well as the denominator are both integers. On the other hand, a fraction appears in the numerator or the denominator of a complex fraction.
The value of the fraction will be:
= 3/7 × 14/15 × 10/18
= 3/7 × 14/15 × 5/9
= 3/1 × 2/3 × 1/9
= 1 × 2 × 1/9
= 2/9
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please help asap please please i’ll give brainliest
Answer:
[tex] C = \dfrac{5}{9}(F - 32) [/tex]
Step-by-step explanation:
[tex] F = \dfrac{9}{5}C + 32 [/tex]
Switch sides to have C on the left side.
[tex] \dfrac{9}{5}C + 32 = F [/tex]
Subtract 32 from both sides.
[tex] \dfrac{9}{5}C = F - 32 [/tex]
Multiply both sides by 5/9.
[tex] \dfrac{5}{9} \times \dfrac{9}{5}C = \dfrac{5}{9} \times (F - 32) [/tex]
[tex] C = \dfrac{5}{9}(F - 32) [/tex]
Which equation represents the same line as the points in the table?
Input (x) Output (y)
−5 5
0 0
7 −7
x=−yx is equal to negative y
y=−x+5y is equal to negative x plus 5
y=−x−7y is equal to negative x minus 7
y=−x
Answer: (c) y = −1/3x −2
Step-by-step explanation:
I know it because I looked on brainly .
The weight M of an object on the moon varies directly as its weight E on earth. A person whoweighs 156.71 lb on earth weighs 26.64 lb on the moon. How much would a 213.53-lb personweigh on the moon?A 213.53-1b person would weigh___ lb on the moon. (Round to the nearest tenth.)
Since the weight varies directly, we have that
[tex]156.71=k\times26.64[/tex]where k is the constant of proportinality.
In order to find k, we can divide both sides by 26.64 and get
[tex]\begin{gathered} \frac{156.71}{26.64}=k \\ or\text{ equivalently, } \\ k=\frac{156.71}{26.64} \end{gathered}[/tex]which gives
[tex]k=5.8825[/tex]Once we know the constant of proportionallity, we can write
[tex]213.53=k\times x[/tex]where x denotes the unknown weight on the Moon. Since k is 5.8825, we get
[tex]213.53=5.8825\times x[/tex]Then, by dividing both sides by 5.8825, we obtain
[tex]\begin{gathered} \frac{213.53}{5.8825}=x \\ or\text{ equivalently,} \\ x=\frac{213.53}{5.8825} \end{gathered}[/tex]Therefore, we have
[tex]x=36.299\text{ lb}[/tex]Finally, by rounding to the nearest tenth, the answer is: 36.3 lb
In the given figure, mBJ = 106 and FHJH. Which statement is true?
F
H
G
Figure not drawn to scale
K
106°
OA.
The measure of ZG is 21", and triangle FGH is isosceles.
OB.
The measure of ZG is 56", and triangle FGH is isosceles.
O.C.
The measure of ZG is 21", and triangle FGH is not isosceles.
The measure of ZG is 56", and triangle FGH is not isosceles.
D.
The 106° measure of arc [tex]m\widehat{HJ}[/tex] and the length of the chords [tex]\widehat{FH}[/tex] and [tex]\widehat{JH}[/tex], which are the same, indicates that m∠G = 21° and ΔFGH is not isosceles. The correct option is option C;
C. The measure of ∠G is 21°, and triangle FGH is not isosceles
What is an isosceles triangle?An isosceles triangle is a triangle that have two sides of the same length and two angles of the same measure.
According to the outside angle to a circle theorem, the measure of the outside angle ∠G formed by the secant GJ and the tangent GF is equal to the difference of the measures of the arcs [tex]m\widehat{F'KJ}[/tex], and arc [tex]m\widehat{FH}[/tex] divided by 2.
[tex]m\widehat{F'KJ}[/tex] = 360° - [tex]m\widehat{FH}[/tex] - [tex]m\widehat{HJ}[/tex]
[tex]\widehat{FH}[/tex] = [tex]\widehat{JH}[/tex]
[tex]\widehat{FH}[/tex] ≅ [tex]\widehat{JH}[/tex]
The lengths of the chord intercepted by congruent arcs are congruent.
Therefore; [tex]\widehat{JH}[/tex] ≅ [tex]\widehat{FH}[/tex]
Which indicates;
[tex]m\widehat{JH}[/tex] = 106° = [tex]m\widehat{FH}[/tex]
[tex]m\widehat{F'KJ}[/tex] = 360° - 106° - 106° = 148°
m∠G = ([tex]m\widehat{F'KJ}[/tex] - [tex]m\widehat{FH}[/tex]) ÷ 2
m∠G = (148° - 106°) ÷ 2 = 21°
m∠G = 21°[tex]m\widehat{F'KJ}[/tex] = 148°
m∠FHJ = 148° ÷ 2 = 74° (Angle at the center is twice angle formed at the circumference)
∠FHJ = ∠HFG + ∠G (exterior angle to triangle ΔFGH)
∠HFG = ∠FHJ - ∠G
Therefore; m∠HFG = 74° - 21° = 53°
m∠HFG = 53°
m∠FHG = 180° - 74° = 106° (linear pair angles property)
m∠G ≠ m∠FHG ≠ m∠HFG, therefore, ΔFGH is not isoscelesThe correct option is option C.
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i need to know how to solve this question please
ANSWER
w = 6.71 or -6.71
EXPLANATION
State the postulate or theorem, if any, that could be used to prove two triangles
The angle sum property of a triangle the and in isosceles triangle base angles are equal theorem are used.
In the given triangle, the measure of two angles are 67° and 35°.
What is angle sum property of a triangle?Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
7a) Using angle sum property of triangle, we get
Now, 67°+35°+x=180°
⇒ 102°+x=180°
⇒ x=180°-102°
⇒ x=78°
7b)
67°+78°+y=180°
⇒ 145°+y=180°
⇒ y=180°-145°
⇒ y=35°
8a) In isosceles triangle base angles are equal.
Here, p=q
50°+p+q=180°
⇒ 50°+p+p=180°
⇒ 2p=130°
⇒ p=65°
So, p=q=65°
8a) Here, c+115°=180°
⇒ c=180°-115°
⇒ c=65°
So, b=c=65°
Now, a+b+c=180°
⇒ a+65°+65°=180°
⇒ a+130°=180°
⇒ a=50°
Hence, the angle sum property of a triangle the and in isosceles triangle base angles are equal theorem are used.
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Help me in these equation9^2 + b^2 = 15.81^2
ANSWER
b = 13
EXPLANATION
We want to solve the equation:
[tex]9^2+b^2=15.81^2[/tex]To do this, simplify the equation:
[tex]81+b^2=249.96[/tex]Isolate b:
[tex]\begin{gathered} b^2=249.96-81 \\ b^2=168.96 \\ Find\text{ the square root of boths side:} \\ b=\sqrt[]{168.96} \\ b=13 \end{gathered}[/tex]That is the answer.
Select the correct answer.
Which equation combines with the given equation to form a system of equations with the solution x = 3 and y = 9?
x + 2y = 21
A.
OB.
O C.
O D.
OE.
4x+6y=64
2x+y = 36
4x + y = 21
-3x + 4y = 33
3x + 2y = 28
The correct option C; 4x + y = 21 is the equation combines with the x + 2y = 21 equation to form a system of equations with the solution x = 3 and y = 9.
What is meany by the term system of equations?simultaneous equations, system of equations Two or more equations must be solved together in algebra, and the solution should first satisfy all of the equations with in system. The number of parameters must equal the amount of unknowns for a system to produce a unique solution.x + 2y = 21 eq .....(i)
The solutions are x = 3 and y = 9.
Put the values of x and y in equation (i),
3 + 2 × 9 = 21
3 + 18 = 21
21 = 21
Now, evaluate every option by substituting the values.
A. 4x + 6y = 64
Put the values of x and y in equation,
4 × 3 + 6 × 9 ≠ 64
48 ≠ 64
In correct option.
B. 2x + y = 36
Put the values of x and y in equation,
2 × 3 + 9 ≠ 36
15 ≠ 36
Incorrect option
C. 4x + y = 21
Put the values of x and y in equation,
4 × 3 + 9 = 21
12 + 9 = 21
21 = 21
Correct option.
Thus, equation combines with the x + 2y = 21 equation to form a system of equations with the solution x = 3 and y = 9 is 4x + y = 21.
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List from greatest to least:5.1 , 5 1/5, 5.5 and 5 1/4
Answer:
5.5, 5¼, 5 1/5 and 5.1.
Explanation:
To list the height from greatest to least, we convert each of them to a decimal.
[tex]\text{Suki}=5\frac{1}{5}=5+\frac{1}{5}=5+0.2=5.2[/tex][tex]\text{Also, Amir=5}\frac{1}{4}=5+\frac{1}{4}=5+0.25=5.25[/tex]Therefore, the weights are: 5.1, 5.2, 5.5 and 5.25
Arranging them from greatest to least gives:
5.5, 5.25, 5.2 and 5.1 which is equivalent to: 5.5, 5¼, 5 1/5 and 5.1.
In the diagram,ABCD is a rectangular wall that casts a shadow CDEF, on the ground. The wall has a height of 4 feet. The shadow is a parallelogram that has a height, FG, that is twice the height of the wall. If the area of the wall is 29.2 square feet, find the area of the shadow.
We know that the height of the rectangular shape is BC=AD= 4 feet and the the area is A=29.2 ft^2. Since the area of our rectangle is given by
[tex]A=(DC)\times(BC)[/tex]we get
[tex]29.2=DC\times4[/tex]By moving the number 4 to the left hand side, we have
[tex]\begin{gathered} \frac{29.2}{4}=DC \\ \text{then} \\ DC=7.3 \end{gathered}[/tex]which also is the lenght of one side of our parallelogram.
Now, the area of our parallelogram is given by
[tex]A_P=\text{base}\times height[/tex]where the base is given by segment DC=7.3 ft and the height FG=2 BC. Then, we get
[tex]\begin{gathered} A_P=DC\times FG \\ A_P=DC\times2BC \end{gathered}[/tex]by substituting our previous result and BC=4 ft, we obtain
[tex]\begin{gathered} A_P=7.3\times2(4) \\ A_P=7.3\times8 \\ A_P=58.4ft^2 \end{gathered}[/tex]Then, the answer is 58.4 ft^2
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What is four-twelfths times seven?
Your answer should be in whole or mixed number form.
A. two and four-twelfths
B. 3
C. six and six-sevenths
D. 21
Answer:
A
Step-by-step explanation:
(7 / 12) × 4 = 28 / 12 = 2 and 4 twelfths