Answer:
(a)A,B.C
(b)A
(c)A, B, C
Explanation:
Part A
The outstanding balance on each account can be summarized using the mean, median, and mode since it is quantitative data.
Options A, B, and C are correct here.
Part B
The name of credit cards can only be summarized by frequency. That is, how many belong to each company (i.e. MasterCard, Visa, American Express, etc.)
The only correct option here is Mode. (Option A).
Part C
The dollar amount due on the next payment is a numerical data, we can find the mean, median, and mode for any numerical data.
Options A, B, and C are correct here.
Are these triangles congruent? If they are, justify it which congruence statement. If not, say cannot be determined. *
According to the figure given
We are given triangle GFH and EFH
[tex]\begin{gathered} <\text{ H }\cong\text{ < F} \\ FE\text{ }\cong\text{ GH} \end{gathered}[/tex]Line FE is parallel to line GH
Therefore, the triangles are congruent by side and angle
Help please look at the image and also use these terms recursive: f(1) = 2, f(n) = 2*f(n-1). explicit: we need to take 1st term/pattern.
The explicit formula for a geometric sequence is given by:
[tex]f(n)=f(1)r^{n-1}[/tex]where r is the common ratio of the sequence.
For this sequence the common ratio is 2 and the first term is 2, therefore its explicit formula is:
[tex]f(n)=2(2)^{n-1}[/tex]The recursive formula for a geometric sequence is given by:
[tex]\begin{gathered} f(1) \\ f(n)=rf(n-1) \end{gathered}[/tex]Therefore in this case we have:
[tex]\begin{gathered} f(1)=2 \\ f(n)=2f(n-1) \end{gathered}[/tex]which methods correctly solve for variable x in the equation 3/4 (x - 8)=6?
SOLUTION
The equation given is
[tex]\frac{3}{4}(x-8)=6[/tex]Step1
Multiply both sides by
[tex]\frac{4}{3}[/tex]We have
[tex]\begin{gathered} \frac{4}{3}\times\frac{3}{4}(x-8)=\frac{4}{3}\times6 \\ \\ x-8=8 \end{gathered}[/tex]Step2
Add 8 to both sides of the equation
[tex]\begin{gathered} x-8+8=8+8_{} \\ x=16 \end{gathered}[/tex]Therefore, the correct method that solves the equation is
5. Multiply both sides by 4/3 and then add 8 to both sides of the equation
similarly,
Distribute 3/4 to (x-8)
[tex]\begin{gathered} \frac{3}{4}(x-8)=6 \\ \frac{3}{4}x-6=6 \end{gathered}[/tex]Then add 6 to both sides
[tex]\begin{gathered} \frac{3}{4}x-6=6 \\ \\ \frac{3}{4}x-6+6=6+6 \\ \frac{3}{4}x=12 \end{gathered}[/tex]Then multiply both sides by 4/3
[tex]\begin{gathered} \frac{3}{4}x\times\frac{4}{3}=12\times\frac{4}{3} \\ \\ x=16 \end{gathered}[/tex]Hence
2. Distribute 3/4 to (x-8), then add 6 to both sides and finally multiply both sides by 4/3
Therefore
Distribute 3/4 to (x-8), then add 6 to both sides and finally multiply both sides by 4/3
and
Mike needs to calculate the angle a rafter makes a with a ceiling joist of a house. The roof has a rise of 5.5 for a run of 12’. What is the angle of the rafter ?
Let's illustrate the given information.
To determine the angle of this rafter, we can use the tangent function. The formula is:
[tex]\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]Our angle in the illustration is the one colored in red. The opposite side of the angle measures 5.5 inches while the adjacent side measures 12 inches. Let's plug in this data to the formula above.
[tex]\tan \theta=\frac{5.5}{12}[/tex]To be able to get the measure of angle, let's get the arc tan of the angle.
[tex]\theta=\tan ^{-1}\frac{5.5}{12}\approx24.62[/tex]Hence, the rafter must be angled 24.62 degrees away from the ceiling joist of the house.
Find the equation of the line, in slope-intercept form, through (-4, 6)and parallel to y=-3x + 4. (Show work) (3 pts)
The given equation is
[tex]y=-3x+4[/tex]Notice that this equation represents a line in slope-intercept form, where its slope is -3.
Now, we have to find a new line parallel to the one above, which means the slope of the new line is also 3 because parallel lines have equal slopes.
Then, we use the given points (-4,6) and the slope -3 to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=-3(x-(-4)) \\ y-6=-3x-12 \\ y=-3x-12+6 \\ y=-3x-6 \end{gathered}[/tex]Therefore, the equation of the parallel line is y = -3x - 6.If y varies inversely as x and y = 41 when x = 28, find y if x = 27. (Round off your answer to the nearest hundredth.)Answer How to enter your answer (Opens in new window) 6 Pointsy = 0y
When y varies inversely as x:
[tex]y=\frac{k}{x}[/tex]y= 41 when x=28; uses the given data to find k:
[tex]\begin{gathered} 41=\frac{k}{28} \\ \\ k=41*28 \\ \\ k=1148 \end{gathered}[/tex]Use the next formula to the given variation:
[tex]y=\frac{1148}{x}[/tex]Find y if x=27:
[tex]\begin{gathered} y=\frac{1148}{27} \\ \\ y=42.52 \end{gathered}[/tex]Answer: y=42.52You earn a salary of $40000 per year and decide to save 20% of your gross pay. You then set a goal of creating $16000 and emergency fund. How long will it take you to achieve your goal?
Gross pay amount = $40,000
Percentage of the gross pay saved = 20%
Amount of gross pay saved per year = 20% of 40,000
Amount of gross pay saved per year = 20/100 * 40,000
Amount of gross pay saved per year = 20*400 = $8000
This means that $8000 is saved per year.
Next is to calculate the number of years it will take to save $16,000
Let us use the equality postulate;
1 year = $8,000
x year = $16,000
cross multiply
8000x = 16000
x = 16000/8000
x = 2
This means that it will take 2 years for me to achive my goal.
question number 1 and 2 and find measure of. angle 1
Explanation
Step 1
vertical angles:
Vertical angles are pair angles formed when two lines intersect
[tex]m\measuredangle x=m\measuredangle y[/tex]so, we need to find a vertical angle in
a)
Figure 1:
blue angles are vertical, so
[tex]m\measuredangle HML\text{ and m}\measuredangle JMK[/tex]Figure 2:
hence, a pair of vertical angle is
[tex]\begin{gathered} \\ m\measuredangle LQM\text{ and m}\measuredangle\text{PQN} \end{gathered}[/tex]Step 2
pair of adjacent angles:
Adjacent angles are two angles that have a common vertex and a common side but do not overlap
[tex]m\measuredangle x\text{ is adjacent to m}\measuredangle y[/tex]then
a)
for Figure 1
pair of adjacent angles
[tex]m\measuredangle HMJ\text{ and m}\measuredangle JMK[/tex]b) for Figure 2
pair of adjacent angles
[tex]m\measuredangle LQM\text{ and m}\measuredangle LQR[/tex]I hope this helps you
Please help me if you could if you can't I understand. what fractions are equivalent to 2/3 and 7/12 using the least common denominator?
2/3 ---->8/12
7/12 ----> 7/12
1) Equivalent fractions have the same value proportionally, so let's find out equivalent fractions:
[tex]\frac{2}{3}+\frac{7}{12}[/tex]2) To find equivalent fractions and sum those fractions, let's factorize 3 and 12 dividing them only by Prime Numbers, when one of those numbers can't be divided then we repeat it below:
As we can see on the first line, 12 can be divided by 2 and 3 cannot.
So we repeat 3 on the line below.
We then picked 6 and divided by 2, and then repeated below 3.
Then divided3 by 3
3) Now we can rewrite 2/3 + 7/12 as:
So using the Least Common Denominator we have 2/3 (8/12) and 7/12 (7/12) as their equivalent fractions. Note that 7/12 in this case is equivalent to itself.
20. A sequence is defined recursivelybelow:+4a, = 8,-1a, = -3Which function can be used to find the nthsequence?
A)
1) Let's insert the Recursive formula for a:
[tex]\begin{gathered} a_n=a_{n-1}+4 \\ a_1=-3 \\ f(n)=-3\text{ +(n-1)4} \\ f(n)=-3\text{ +4n-4} \\ f(n)=4n-7 \end{gathered}[/tex]When we apply the General formula f(n) we'll need the first term. for that sequence, and then rearrange it we find the function for the nth term of that Arithmetic Sequence.
All we need now is to plug into the formula the nth term we want to find out.
Write the nth rule for each geometric sequence.5) 7, 14, 28, 56...
We have the next numbers
[tex]7,14,28,56[/tex]as we can see we have double of the previous number, so the rule is
[tex]a_n=a_{n-1}\cdot2[/tex]we need to prove the rule
[tex]a1=7[/tex][tex]a2=7\cdot2=14[/tex][tex]a3=14\cdot2=28[/tex][tex]a4=28\cdot2=56[/tex]as we can see the rule is appropriate for the geometric sequence
At what value of w does the graph have a vertical asymptote? Explain how you know and what this asymptote means in the situation.
Vertical asymptote are vertical lines which corresponds to the zeros of the denominator of our rational function. Then, the zeros of T(w) ocurr when
[tex]530-w=0[/tex]which gives
[tex]w=530[/tex]Therefore, the vertical asymptote is w = 530.
The asymptote is a line that the graph function approaches but never touches. In our case, this means that the speed of the wind is very close to 530 mph but never touches this value.
PLEASE just give me the answers and not a whole defintion of every single word. I just want quick answers so I can check my work. *don't worry, this is just a math practice
7. m and n are parallel because both alternate interior angles are equal.
8.m and n are parallel because Alternate exterior angles are equal.
9.m and n are parallel Because corresponding angles are equal.
10. m and n are parallel because corresponding and consecutive angles are equal.
11. m and n are parallel because alternate exterior angles are equal.
12.m and n are parallel because vertical (opposite) angles are equal.
Draw a graph of a parabola that has the followinsignificant features:a > 0one X - intercepty - intercept at 4Write the equation to your parabola:
Saira is using the formula for the area of a circle to determine the value of .
For this problem, we just have to use the values we're given to calculate the approximate value of pi.
The formula presented is
[tex]\pi=Ar^{-2}[/tex]When you have a negative exponent, we can use the following property
[tex]a^{-b}=\frac{1}{a^b}[/tex]Using this property, our problem turns out to be
[tex]\pi=\frac{A}{r^2}[/tex]Now, we just need to plug the given values on this equation
[tex]\pi=\frac{50.265}{4^2}=3.1415625\approx3.142[/tex]The approximated value for pi is 3.142.
I’m having trouble with this calculus practice problem Below are the answer options A. -2B. 1C. 3D. The limit does NOT exist
Given
[tex]\lim _{x\to-3^+}h(x)[/tex]Solution
The limit is tending to -3 from the right, that is why it is written as
[tex]-3^+[/tex]From the graph, we will trace the graph from the right to -3
The final answer is -2
Hi,I need help with this I tried and I can’t get the answer
Given
[tex]12000\div300[/tex]We can decompose the above expression below
Explanation
300 can be decomposed into
[tex]300=100\times3[/tex]Therefore,
Answer:
[tex]12000\div100\div3[/tex]What is the length of the side opposite the 30° angle? Explain your reasoning.
Given the triangle ABC as shown below:
The length of the side opposite the 30° angle is evaluated as follows:
Step 1:
Given that the 30° angle is the focus angle, label the sides of the triangle.
Thus,
[tex]\begin{gathered} \text{where }\theta=30^{\circ} \\ AC\Rightarrow hypotenuse\text{ (the longest side of the triangle)} \\ AB\Rightarrow opposite\text{ (the side opposite the focus angle)} \\ BC\Rightarrow adjacent \\ \text{thus, } \\ AC\text{ = 44} \\ AB\text{ = x (unknown length)} \end{gathered}[/tex]Step 2:
Evaluate the unknown side using trignometric ratios.
By trigonometric ratios,
[tex]\begin{gathered} \sin \theta\text{ = }\frac{opposite}{hypotenuse}=\frac{AB}{AC} \\ \cos \text{ }\theta\text{ = }\frac{adjacent}{hyptenuse}=\frac{BC}{AC} \\ \tan \text{ }\theta\text{ = }\frac{opposite}{adjacent}=\frac{AB}{BC} \end{gathered}[/tex]From the above trigonometric ratios, sine θ is used to evaluate the value of the unknown side.
This because the sine θ gives the ralationship between the hypotenuse and the unknown side of the triangle.
Thus,
[tex]\begin{gathered} \sin \theta\text{ = }\frac{opposite}{hypotenuse}=\frac{AB}{AC} \\ AB\text{ = x} \\ AC\text{ = 44} \\ \theta\text{ = 30} \\ \Rightarrow\Rightarrow\sin 30\text{ = }\frac{x}{44} \\ 0.5\text{ = }\frac{x}{44} \\ \Rightarrow x\text{ = 0.5}\times44 \\ x\text{ = 22} \end{gathered}[/tex]Hence, the value of the unknown side is 22.
If a card is drawn from an ordinary deck of 52 cards, find the probability of getting a heart or a face card?
Given:
Total number of cards = 52
Number of face cards = 12
Number of heart cards = 13
Required: Probability of getting a heart or a face card
Explanation:
Number of cards that is both face cards and heart cards = 3
Number of cards that are either heart or face card
= 12 + 13 - 3
=22
Probability of getting a heart or face card = Number of favorable cases/ Total number of cases
[tex]=\frac{22}{52}=\frac{11}{26}[/tex]Final Answer: The probability of getting a heart or face card is 11/26.
For the school play, tickets cost $13.50 for adults and $5 for kids under 12. How
many total tickets would someone get if they purchased 6 adult tickets and 22 kids
tickets? How many total tickets would someone get if they purchased a adult tickets
and k kids tickets?
Total tickets, 6 adult tickets and 22 kids tickets:
Total tickets, a adult tickets and k kids tickets:
Answer
The adult-135 And the Kid-27:
Step-by-step explanation:
13.50 * 10=135
4.50 * 6 =27
El producto de 2 por la diferencia de x y y
La diferencia de 'x' y 'y' se puede escribir asi:
[tex]undefined[/tex]For what values of k will the sum of the solutions of x^2 - (k^2 - 3k)x + 24=0 be 10?
The Solution:
Given the equation below:
[tex]x^2-(k^2-3k)x+24=0[/tex]We are required to find the value of k that will make the sum of the solutions to be 10.
Step 1:
Let:
[tex]\begin{gathered} k^2-3k\text{ be represented with b} \\ \text{ So that we have} \\ k^2-3k=b\ldots eqn(1) \end{gathered}[/tex]So, the given equation becomes:
[tex]x^2-bx+24=0[/tex]We shall the Quadratic Formula Method to solve for x in terms of b.
In this case,
[tex]\begin{gathered} a=1 \\ b=-b \\ c=24 \end{gathered}[/tex]Substituting, we get
[tex]x=\frac{-b\pm\text{ }\sqrt[]{(-b)^2-(4\times1\times24)}}{2(1)}[/tex][tex]x=\frac{-b\pm\text{ }\sqrt[]{b^2-96}}{2}[/tex]So, the solutions to the given equation are:
[tex]\begin{gathered} x=\frac{-b+\text{ }\sqrt[]{b^2-96}}{2} \\ \text{ or} \\ x=\frac{-b-\text{ }\sqrt[]{b^2-96}}{2} \end{gathered}[/tex]Equating their sum to 10.
[tex]\begin{gathered} \frac{-b+\text{ }\sqrt[]{b^2-96}}{2}+\frac{-b-\text{ }\sqrt[]{b^2-96}}{2}=10 \\ \\ \\ \frac{-b+\text{ }\sqrt[]{b^2-96}+-b-\text{ }\sqrt[]{b^2-96}}{2}=10 \end{gathered}[/tex]Simplifying, we get
[tex]\begin{gathered} \frac{-2b}{2}=10 \\ \\ -b=10 \end{gathered}[/tex]Substituting for b, we get
[tex]\begin{gathered} -(k^2-3k)=10 \\ k^2-3k=-10 \\ k^2-3k+10=0 \end{gathered}[/tex]Solving for k by the Quadratic Formula method of solving quadratic equation, we get
[tex]k=\frac{-b\pm\text{ }\sqrt[]{b^2-4ac}}{2a}[/tex]Where
[tex]a=1,b=-3\text{ and c=10}[/tex]Substituting, we get
[tex]k=\frac{-(-3)\pm\text{ }\sqrt[]{(-3)^2-(4\times1\times10)}}{2(1)}[/tex][tex]k=\frac{3\pm\text{ }\sqrt[]{9^{}-40}}{2}=\frac{3\pm\text{ }\sqrt[]{-31}}{2}[/tex][tex]\begin{gathered} k=\frac{3+\text{ }\sqrt[]{-31}}{2}\text{ or }k=\frac{3-\text{ }\sqrt[]{-31}}{2} \\ \end{gathered}[/tex]Therefore, the correct answer is
[tex]k=\frac{3+\text{ }\sqrt[]{-31}}{2}\text{ or }k=\frac{3-\text{ }\sqrt[]{-31}}{2}[/tex]Alternatively,
We can use the sum of roots formula below:
[tex]\begin{gathered} \text{ Sum of roots = }\frac{-b}{a} \\ \text{if given a quadratic equation of the form ax}^2+bx+c=0 \end{gathered}[/tex]So, we get
[tex]\begin{gathered} a=1 \\ b=-(k^2-3k) \\ c=24 \end{gathered}[/tex]So,
[tex]\begin{gathered} \text{ Sum=}\frac{--(k^2-3k)}{1}=10 \\ \\ k^2-3k=10 \\ \\ k^2-3k-10=0 \end{gathered}[/tex]Then you can now solve from here as have done in the previous method.
Solve the quadratic equation above for k.
In circle O, mPN= 131°. Solve for x if m
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: state the required theorem
The arc measure is equal to the angle at the center. Arc measure is a degree measurement, equal to the central angle that forms the intercepted arc.
STEP 2: Get the equation
[tex]131^{\circ}=6x+26[/tex]STEP 3: Solve for x
[tex]\begin{gathered} 131=6x+26 \\ 131-26=6x \\ 105=6x \\ \frac{6x}{6}=\frac{105}{6} \\ x=17.5 \end{gathered}[/tex]Hence, the value of x is
Hello. I think that I'm overthinking this. I'm pretty sure it's a monomial?
The expression 5x⁶ - x⁴ is a binomial because we have two terms.
Even if they have the same variable x, their exponents are not the same.
An 8-pack of batteries cost $9.44.what is the price, in dollars , of one battery?A)- $0.85B)- $1.18C)- 1.44D)- 2.36
In order to determine the cost of only one battery, calculate the quotient in between the cost of 8 batteries over 8:
$9.44/8 = $1.18
Hence, one battery costs $1.18
I need help with this 6-9 should be matched with either A-H
Explanation
To answer the question, we will make use of some of the properties of a parallelogram
These are
The opposite sides are parallel.
Opposite sides are congruent.
Opposite angles are congruent.
Same-Side interior angles (consecutive angles) are supplementary.
Each diagonal of a parallelogram separates it into two congruent triangles.
The diagonals of a parallelogram bisect each other.
Therefore
For question 6
[tex]\begin{gathered} mTherefore, the answer to question 6 is AQuestion 7
[tex]mThe answer to question 7 is EQuestion 8
[tex]\begin{gathered} DF=FB \\ Diagonals\text{ bisect each other} \\ DF=17 \end{gathered}[/tex]The answer to question 8 is C
Question 9
[tex]\begin{gathered} mThe answer to question 9 is Fdonuts at Krispy Kreme are always perfectly round. The diameter of the circular donut is 6 inches. Which of the following is closest to the circumference of the donut?
The circumference of a donut is computed as follows:
[tex]C=\pi\cdot D[/tex]where D is the diameter of the donut. Substituting with D = 6,
[tex]\begin{gathered} C=\pi\cdot6 \\ C=18.85\text{ in} \end{gathered}[/tex]Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.0.50 : 0.25
Answer:
2/1
Explanation:
Given the ratio:
[tex]0.50\colon0.25[/tex]Divide both sides by 0.25
[tex]\begin{gathered} \frac{0.50}{0.25}\colon\frac{0.25}{0.25} \\ =2\colon1 \\ =\frac{2}{1} \end{gathered}[/tex]Thus, the ratio as a fraction in simplest form is 2/1.
PLEASE HELP!! ALGEBRA 1 HW I WILL GIVE BRAINLYEST
Answer:
answer Is -5/2 becouse if the line Is horizontal his equation Is y=k and in this case k= -5/2
I need help with solving propotional segments in right triangles. I need help with number 4.
We have
AD=9 in
DB=4 in
find DC,AC and BC
we can do the next equivalences
[tex]\frac{AD}{DC}=\frac{DC}{DB}[/tex][tex]\frac{9}{DC}=\frac{DC}{4}[/tex]then we clear DC
[tex]\begin{gathered} DC=\sqrt[]{36} \\ DC=6 \end{gathered}[/tex]For AC we use the Pythagorean theorem
[tex]AC=\sqrt[]{9^2+6^2}=10.81[/tex]For BC we use the Pythagorean theorem
[tex]BC=\sqrt[]{6^2+4^2}=7.21[/tex]