You can identify that the following is a Decimal number:
[tex]0.005[/tex]In order to convert a Decimal number to an Equivalent fraction, you can follow the steps shown below:
1. You need to write the Decimal number 0.005 as the numerator of the fraction and the denominator must be 1:
[tex]=\frac{0.005}{1}[/tex]2. Now you can multiply the numerator and the denominator by 1,000, in order to remove the decimal places of the numerator (notice that it has three decimal places):
[tex]=\frac{0.005\cdot1,000}{1\cdot1,000}=\frac{5}{1,000}[/tex]3. Finally, you have to reduce the fraction. Notice that you can divide the numerator and the denominator by 5. Then, you get:
[tex]=\frac{1}{200}[/tex]The answer is:
[tex]\frac{1}{200}[/tex]5 times 5 I need help solving that one
5 times 5 = 5 x 5
= 25
Answer : 25
I got the first one right but I can’t figure out the rest. College Calculus 1. Please help :)
SOLUTION
Consider the image given
In other to evaluate the value of
[tex]g(f(0))[/tex]We first evaluate
[tex]f(0)[/tex]From the graph,
[tex]f(0)=0[/tex]Then, we obtain the value of g(0) by tracing the value of zero on the blue curve, we have
[tex]g(0)=3[/tex]Therefore
g(f(0) = 3
Flying against the wind, an airplane travels 2010 kilometers in 3 hours. Flying with the wind, the same plane travels 10,530 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?
it is given that,
the distance travel against wind = 2010
time = 3 hrs
so, the relative speed is = distance/ time = 2010/3 = 670 km/hr
the distance travel with wind is 10,530
time 9 hrs
so,the relative speed is,= 10 530/9 = 1170 km/hr
let a = speed of plane ,
b = speed of wind
so, when plane travel with wind the the relative speed is ,
a + b = 1170
when travel against wind then the relative speed,
a - b = 670
sum the equation
a + b + a - b = 1170 + 670
2a = 1840
a = 920
put a = 920 in equation a + b = 1170
920 + b = 1170
b = 1170 - 920
b = 250
thus, the rate of plane is 920
rate of wind is 250
Emma made a mistake when she divided 6.4 by 0.02. She divided 2 into 64 and got 32 but she did not use the decimals. Describe her mistake and show the correct division.
The given division can be expressed mathematically as:
[tex]\frac{6.4}{0.02}[/tex]Emma did 64/2 and got 32 because he multiplied the numerator by 10 and the denominator by 100. This is a mistake because both the numerator and the denominator should be multiplied by equal number.
Emma can correct this mistake by multiplying the numerator (6.4) and the denominator(0.02) by 100 as shown below
[tex]\begin{gathered} \frac{6.4\times100}{0.02\times100} \\ =\text{ }\frac{640}{2} \\ =\text{ 320} \end{gathered}[/tex]Therefore, the correct result for 6.4 divided by 0.02 is 320 and not 32 that Emma got.
-2/5 divide (-3) multiply and reduce to lowest terms.
Answer:
2/15
Explanation:
Given the expression:
[tex]-\frac{2}{5}\div(-3)[/tex]First, change the division sign to times by taking the reciprocal of the number after the sign:
[tex]=-\frac{2}{5}\times-\frac{1}{3}[/tex]Next, multiply the numerators and denominators:
[tex]\begin{gathered} =\frac{(-2)\times(-1)}{5\times3} \\ =\frac{2}{15} \end{gathered}[/tex]The fraction is already in its lowest form as required.
I need help with this question please. Also, this is just apart of a homework practice
Given:
[tex]P(x)=4x^5+9x^4+6x^3-x^2+2x-7[/tex]The leading coefficient is the coeffient (number) written in front of the the variable with the highest power of x.
So, the leading coefficient is 4
The degree of the equation is the highest power of the variable.
In this question, the degree is 5.
Finally, to find the end behavior, you have to substitute the leading term by +∞ and -∞ to observe the behavior of the function.
Substituting by +∞:
[tex]4\cdot\infty^5=\infty[/tex]Substituting by -∞:
[tex]4\cdot(-\infty)^5=-\infty[/tex]Answer:
Leading coefficient: 4
Degree: 5
x → +∞; P(x) → +∞
x → -∞; P(x) → -∞
Alternative A.
Let f(x)=x^2+5x−36. Enter the x-intercepts of the quadratic function in the boxes.___and__
Given
[tex]f(x)=x^2+5x-36[/tex]Question: What is the solution to this system of linear equations? 8x + 2y = 2 and x + 3y 2 = 14 I NEED The claim, evidence and reasoning. Please I need help
In a painting of the Mona Lisa, the length of the painting is 4 - inches, Milo scales the drawing up by 2 What is the length of the scaled copy?
Wee, it he is scalaing the painting by two the new length must be twice the original length.
length = 2 x 4 = 8 in
New length = 8 in
If f(x)=x²-20 and g(x) = 4+3x, then f(g(-3)) =
The value of function f(g(-3)= 5.
What is composite function?
A composite function is generally a function that is written inside another function. Composition of a function is done by substituting one function into another function. For example, f [g (x)] is the composite function of f (x) and g (x).
Given, f(x)=x²-20 and g(x) = 4+3x
first we will find
f(g(x)) = f(4+3x)^2-20
=9x^2+16+24x-20
=9x^2+24x-4
Now to find, f(g(-3)), substitute x=-3,
= 9(9)+24(-3)-4
=81-72-4
=5
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P(A)=0.35P(B)=0.40P(A and B)=0.13Find P(A or B).Round your answer to two decimal places.
Given:
[tex]\begin{gathered} P\left(A\right)=0.35 \\ P\left(B\right)=0.40 \\ P\left(A\text{ }and\text{ }B\right)=0.13 \end{gathered}[/tex]To find:
[tex]P(A\text{ or }B)[/tex]Explanation:
Using the formula,
[tex]\begin{gathered} P(A\text{ or}B)=P(A)+P(B)-P(A\text{ and }B) \\ =0.35+0.40-0.13 \\ =0.62 \end{gathered}[/tex]Therefore, the value is,
[tex]P(A\text{ or }B)=0.62[/tex]Final answer:
The value is,
[tex]P(A\text{ or }B)=0.62[/tex]At the rodeo, the bronco riding event takes place in a large dirt ring which has a diameter of 14 yards. What is the ring's radius?
The ring's radius is 7 yards.
Diameter = 14 yd.
The diameter can be defined as:
It is the length of the line passing through the center that touches two points on the edge of the circle.
Also, diameter is double of the radius
That is:
Diameter = 2 times the radius
Diameter = 2 × radius
Let the radius be r
14 = 2 × r
2 r = 14
Divide both the sides by 2:
2 r / 2 = 14 / 2
r = 7 yards.
Therefore, we get that, the radius of the ring will be 7 yards.
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what is five plus two
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
five plus two
Step 02:
addition:
5 + 2 = 7
The answer is:
7
If [tex]f(x)=3x-2[/tex] and [tex]g(x)=\frac{1}{3}x+1[/tex], then [tex](f(g))^{-1} (x)[/tex] equals:
a. [tex]1-x[/tex]
b. [tex]x-1[/tex]
c. [tex]\frac{1}{3} (3x-1)[/tex]
d. [tex]x+1[/tex]
Answer:
B) x - 1=================
Givenf(x) = 3x - 2, g(x) = 1/3x + 1Find the composite function f(g(x))f(g(x)) = 3(1/3x +1) - 2 = x + 3 - 2 = x + 1Find the inverse of f(g(x))x = f(g)⁻¹(x) + 1f(g)⁻¹(x) = x - 1Correct choice is B
find the slope of the line
Solution
We can use the following points from the graph:
(0,-2) and (2,1)
And we can find the slope on this way:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1+2}{2-0}=\frac{3}{2}[/tex]Then we can find the intercept on this way:
1= 3/2 (2)+b
b= 1-3= -2
Then the equation would be:
y= 3/2 x -2
use the equation and type the ordered-pairs.y=3^x[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]
Given the equation :
[tex]y=3^x[/tex]we need to complete the order pairs :
[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]
So, for each value of x, we will find the corresponding value of y
[tex]\begin{gathered} x=-1\rightarrow y=3^{-1}=\frac{1}{3} \\ \\ x=0\rightarrow y=3^0=1 \\ \\ x=1\rightarrow y=3^1=3 \\ \\ x=2\rightarrow y=3^2=9 \\ \\ x=3\rightarrow y=3^3=27 \\ \\ x=4\rightarrow y=3^4=81 \end{gathered}[/tex]So, the answer is : the order pairs will be :
[tex](-1,\frac{1}{3}),(0,1),(1,3),(2,9),(3,27),(4,81)[/tex]f(2)=1/xsolve both go 2)=3x
The functions are:
[tex]\begin{gathered} f(x)=\frac{1}{x} \\ g(x)=3x \end{gathered}[/tex]We need to evaluate f(x) in x=-2 and g(x) in x=2, so:
[tex]\begin{gathered} f(-2)=\frac{1}{(-2)}=-\frac{1}{2}=-0.5 \\ g(2)=3\cdot2=6 \end{gathered}[/tex]Jordan plots point m at (-3,7) Graph point m reflected across the y-axis. in which quadrant would the new point be located?
If he reflected the point (-3, 7) over the y-axis it will end up in the first quadrant.
*The transformation rule is (x, y) -> (-x, y) so, x & y-components will be positive, thus being in the first quadrant.
two numbers have a sum of -10 and a difference of -2 what is the product of numbers
let 'x' and 'y' be two numbers that have a sum of -10 and a difference of -2, then, we have the following system of equations:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \end{gathered}[/tex]notice that if we add both equations at the same time, we get:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \\ --------- \\ 2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]now that we have that x = -6, we can find the value of y substituting x = -6 on any equation:
[tex]\begin{gathered} -6+y=-10 \\ \Rightarrow y=-10+6=-4 \\ y=-4 \end{gathered}[/tex]therefore, x = -6 and y = -4. Next, we have that the product is (-6)(-4) = 24
Which relation is a function?
Answer:
The left upper one is a function
Step-by-step explanation:
If you draw a straight vertically and the line goes through two point then its not a function. Just look what makes a function or answer again if you are confused.
The relation which is a function is f ( x ) = x³
What is a function rule?The function rule is the relationship between the input or domain and the output or range. A relation is a function if and only if there exists one value in the range for every domain value.
A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Given data ,
Let the function be represented as f ( x )
Now , the value of f ( x ) is
y = x³ be equation (1)
Now , relation is a function if and only if there exists one value in the range for every domain value.
So , when x = { 1 , 2 , 3 , 4 }
The values of y are = { 1 , 8 , 27 , 64 }
Hence , the function is y = x³ and the graph is plotted
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Blair purchases the T-shirts from Company B. She needs to add a 75markup to her total cost to make a profit when she sells the shirts at thcarnival. How should Blair determine the selling price of each T-shirt athe carnival?Drag a number into each box to make the statements true.She canThe total cost Blair paid for one T-shirt is $calculate the markup by multiplying her total cost byBlair will sell each T-shirt at the carnival for $
Isolating selling price,
[tex]\begin{gathered} \frac{\text{ markup \% }}{100}\text{= }\frac{\text{ selling price - cost}}{\text{ cost}} \\ \frac{\text{ markup \% }}{100}\cdot\cos t=\text{selling price - cost} \\ \frac{\text{ markup \% }}{100}\cdot\cos t+cost=\text{selling price} \\ \cos t(\frac{\text{ markup \% }}{100}+1)=\text{ selling price} \end{gathered}[/tex]The markup is 75 %. Supposing that the cost of a T-shirt is $6.00, then the selling price will be:
[tex]\begin{gathered} \text{selling price = 6.00}\cdot(\frac{75}{100}+1) \\ \text{selling price = 6.00}\cdot(0.75+1) \\ \text{selling price = 6.00}\cdot1.75 \\ \text{selling price = \$}10.5 \end{gathered}[/tex]Which of the following is a solution to the quadratic equation below?x²-3x-54-0A. 9B. -57C. 2D. 27
A. 9
Explanationto solve for x we can use the quadratic formula
it says
[tex]\begin{gathered} for \\ ax^2+bc+c=0 \\ the\text{ solution for x is} \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]hence
Step 1
a) let
[tex]\begin{gathered} x^2-3x-54=0\Rightarrow ax^2+bx+c=0 \\ so \\ a=1 \\ b=-3 \\ c=-54 \end{gathered}[/tex]b) now, replace in the formula and evaluate
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x=\frac{-(-3)\pm\sqrt{(-3)^2-4(1)(-54)}}{2(1)} \\ x=\frac{-(-3)\pm\sqrt{9+216}}{2}=\frac{3\pm\sqrt{225}}{2} \\ x=\frac{3\pm15}{2} \end{gathered}[/tex]so
[tex]\begin{gathered} x_1=\frac{3+15}{2}=9 \\ x_2=\frac{3-15}{2}=-6 \end{gathered}[/tex]therefore, the answer is
A. 9
I hope this helps you
what is four fiths minus 6 fiftheens
what is four fiths minus 6 fiftheens
we have
4/5-6/15
Multiply by 3/3 fraction 4/5
4/5(3/3)=12/15
substi
What is the value of y in the equation 2(2y − 16) = 0? (5 points)4689
Given the following equation,
[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex]Let's determine the value of y.
[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex][tex]\text{ }\frac{2(2y\text{ - 16\rparen}}{2}\text{ = 2}[/tex][tex]\text{ 2y - 16 = 0}[/tex][tex]\text{ 2y = 16}[/tex][tex]\text{ }\frac{2y}{2}\text{ = }\frac{16}{2}[/tex][tex]\text{ y = 8}[/tex]Therefore, y = 8
The answer is 8.
PLEASE HELP 15 POINTS I'M GIVING BRAINLIEST
Answer:
below
Step-by-step explanation:
In a RIGHT triangle such as this, cos = adjacent leg / hypotenuse
cos (beta) = 22/24 = 11/12
What type of number is 3 - 77iChoose all answers that apply:A. RealB. ImaginaryC. Complex
The sum of two numbers is30. The sum of4 times the larger and6 times the smaller is128. Find the numbers.
let
the smaller number = x
the larger number = y
x + y = 30
4y + 6x = 128
[tex]\begin{gathered} x+y=30 \\ 4y+6x=128 \\ x=30-y \\ 4y+6(30-y)=128 \\ 4y+180-6y=128 \\ -2y=128-180 \\ -2y=-52 \\ y=\frac{52}{2} \\ y=26 \\ x+y=30 \\ x+26=30 \\ x=30-26 \\ x=4 \end{gathered}[/tex]
The numbers are 4 and 26.
please help me with my question.
The volume of a cylinder is given by
[tex]V=\pi(R^2)H[/tex]Here H = 8cm, we do not know the value of the radius, but we can find that given the circumference.
[tex]\begin{gathered} C=2\pi R=20\pi \\ R=\frac{20\pi}{2\pi}=10\operatorname{cm} \end{gathered}[/tex]Thus the volume should be;
[tex]\begin{gathered} V=\pi(10^2)8 \\ V=2513.27\operatorname{cm}^3 \end{gathered}[/tex]That is option A
help my brother the other one I tried was a scam
1. Given the integers a and b, a common multiple is a positive integer that is divisible by both a and b.
2. The Least Common Multiple (LCM ) is the smallest positive integer that is divisible by both a and b.
3. Multiples of 6: 6 (= 6x1), 12 (= 6x2), 18 (= 6x3), 24 (= 6x4), ...
Multiples of 4: 4 (= 4x1), 8 (= 4x2), 12 (= 4x3), 16 (= 4x4), ...
The smallest number of these two lists is 12, then the LCM between 6 and 4 is 12.
The solutions to a quadratic equation are -2 and 6. What is the equation of its axisof symmetry?
General form of a quadratic equation is
[tex]ax^2+bx+c=0[/tex]another form is
[tex](x+h)(x+k_{})=0[/tex]where h and k are the number opposite by the sign of the solutions, then on this case the values of h and k are 2 and -6
[tex](x+2)(x-6)=0[/tex]Our equatio is a parabola then if we find the vertex we are finding the axis of simmetry
to find the vertex we trasnforme ou equation to the general form of a quadratic equation multipliying parenthesis
[tex]\begin{gathered} (x\times x)+(x\times-6)+(2\times x)+(2\times-6)=0 \\ x^2-6x+2x-12=0 \\ x^2-4x-12=0 \end{gathered}[/tex]now take the equation and derivate
[tex]\begin{gathered} 2x-4-0=0 \\ 2x-4=0 \end{gathered}[/tex]if we solve x we find the coordinate x of the vertex and the axis of simmetry
then
[tex]\begin{gathered} 2x-4=0 \\ 2x=4 \\ x=\frac{4}{2} \\ \\ x=2 \end{gathered}[/tex]axis of Symmetry is x=2