Find the volume of a cylinder whose base has a radius of 3 inches and whose height is 12.5 inches. Use π = 3.14 and round your answer to the nearest tenth37.5 in^3333.8 in^3353.3 in^3421.8 in^3
Answers
Answer:
353.3 in^3
Explanation:
Given:
The radius of the base of the cylinder (r) = 3 inches
The height of the cylinder (h) = 12.5 inches
pi = 3.14
To find:
The volume of the cylinder
We'll use the below formula to determine the volume(V) of the cylinder;
[tex]V=\pi r^2h[/tex]Let's go ahead and substitute the given values into the formula and solve for V;
[tex]V=3.14*3^2*12.5=3.14*9*12.5=353.3\text{ in}^3[/tex]So the volume of the cylinder is 353.3 in^3
Related Questions
find the mean of the data sets. round answers to the nearest integer. 4. { 24,21,23,22,26,23,24,21} 5. { 3,3,4,3,3,2}
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Let's begin by identifying key information given to us:
[tex]24,21,23,22,26,23,24,21[/tex]The mean of the data set is calculated by using the formula:
[tex]\begin{gathered} m=\frac{SumOfTerms}{NumberOfTerms} \\ m=\frac{\Sigma x}{n}=\frac{24+21+23+22+26+23+24+21}{8} \\ m=\frac{184}{8}=23 \\ m=23 \end{gathered}[/tex]Therefore, the mean of the data set is 23
-2x^3 - 10y-7 evaluate if x = 4 and y = -9
Answers
We are given the following expression:
[tex]-2x^3-10y-7[/tex]We are asked to evaluate the expression in the following points:
[tex]\begin{gathered} x=4 \\ y=-9 \end{gathered}[/tex]To determine the value of the expression we will substitute the value in the expression like this;
[tex]-2(4)^3-10(-9)-7[/tex]Now, we solve the exponents:
[tex]-2(4)^3-10(-9)-7=-2(64)-10(-9)-7[/tex]Now, we solve the products:
[tex]-2(64)-10(-9)-7=-128+90-7[/tex]Solving the operations:
[tex]-128+90-7=-45[/tex]Therefore, the numerical value is -45
Write an equation and graph the cosine function with amplitude 3 and period 4 pi.
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An equation and graph the cosine function with amplitude 3 and period 4 pi is y is 3cos([tex]\frac{1}{2} x[/tex])
How to write an equation ?
The general form for the cosine function is:
y = A cos(Bx+C)+D
The amplitude is:
|A|
The period is:
P = 2π/B
The phase shift is
ϕ = −C/B
The vertical shift is D
Explanation:
Given:
The amplitude is 3:
|A|=3
The above implies that A could be either positive or negative but we always choose the positive value because the negative value introduces a phase shift:
A=3
Given:
The period is
P = 4π
4π =2π/B
B = 1/2
Nothing is said about the phase shift and the vertical shift, therefore, we shall assume that
C and D are 0.
Substitute these values into the general form:
y = 3cos([tex]\frac{1}{2} x[/tex])
An equation and graph the cosine function with amplitude 3 and period 4 pi is y is 3cos([tex]\frac{1}{2} x[/tex])
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can someone help me with this math problem a write a number line to it
Answers
How would you change 65% to a decimal?
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In converting percentage to decimals, you need to divide it by 100.
[tex]\frac{65}{100}=0.65[/tex]The answer is 0.65
Four times a number b is six times the sum of b and five
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The number b is -15
Here, we want to write an equation and solve it
We go step by step
Four times a number b
= 4 * b = 4b
is six times the sum of b and 5
The sum of b and 5 is b+ 5
six times this is = 6(b + 5)
Now euating the two, we have;
4b = 6(b + 5)
4b = 6b + 30
collect like terms
6b - 4b = -30
2b = -30
b = -30/2
b = -15
Write the equation of a function that has the given characteristics.The graph of y = |x|, shifted 8 units upwardоа y = |x-81y = |x+81y = x| + 8y = |x| - 8
Answers
The given function is
[tex]y=|x|[/tex]The transformation is shifted 8 units upwards.
Remember, to move the function upwards we have to sum outside the absolute value bars.
Therefore, the transformed function would be
[tex]y=|x|+8[/tex]What is the image of (-6, -2) after a dilation by a scale factor of 4 centered at theorigin?
Answers
The image of (-6, -2) after dilation by a scale of 4 is (-24, -8)
Explanation:The image of (-6, -2) after dilation by a scale of 4 is
(-6*4, -2*4)
= (-24, -8)
There are 7 balls numbered I through 7 placed in a bucket What is the probability of reaching into the bucket and randomly drawing two balls numbered 6 and 3 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
Answers
We have:
- Numbers of balls from 1 to 7 = 7
- Number of balls with number 6 = 1
- Number of ball with number 3 = 1
Then, the probability of ramdomly choosing a 6 is
[tex]p(6)=\frac{1}{7}[/tex]Once we chose a ball, there are 6 balls into the bucket. Then the probability of ramdomly choosing a 3 is
[tex]P(3)=\frac{1}{6}[/tex]Then, the probability of randomly choosing a 6 and 3 in that order, is
[tex]\begin{gathered} P(6\text{and}3)=P(6)\cdot P(3)=\frac{1}{7}\cdot\frac{1}{6} \\ P(6\text{ and 3)=}\frac{1}{7\cdot6} \\ P(6\text{ and 3)=}\frac{1}{42} \end{gathered}[/tex]that is, the probability is 1/42 = 0.023809
sketch the angle then find its reference angle [tex] \frac{13\pi}{4} [/tex]
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We need to find the reference angle by sketching the angle:
First, we need to subtract it by 2π, then:
[tex]θ=\frac{13\pi}{4}-2\pi=\frac{5}{4}\pi[/tex]Hence, the reference angle is 5π / 4.
Driving down a mountain, Bob Dean finds that he descends 3300 feet in elevation by the time he is 4.5 miles (horizontally) away from the high point on the mountain road. Find the sic
descent. (1 mile 5280 feet).
The slope is
(Type an integer or decimal rounded to two decimal places as needed.)
Answers
Answer:
[tex]-0.14[/tex]
Step-by-step explanation:
Slope is defined as the change in [tex]y[/tex] divided by the change in [tex]x[/tex].
The change in [tex]y[/tex] is a decrease of 3,300 feet.
The change in [tex]x[/tex] is an increase of 4.5 miles. Converting to feet so that both measurements are in identical units:
[tex]\frac{4.5\text{ mi}}{1}\times\frac{5280\text{ ft}}{1\text{ mi}}=23760\text{ ft}[/tex]
Therefore, the slope is:
[tex]\frac{\Delta{y}}{\Delta{x}}=\frac{-3300}{23760}=-\frac{5}{36}[/tex]
As a decimal rounded to two places:
[tex]-\frac{5}{36}\approx{-0.14}[/tex]
Which two expressions are equivalent?A. A(0.52)-21B. A(1.04)-C. A(0.96)D. A(0.96 0.08
Answers
Equivalent expressions are expressions that have the values when we put the same values for the variables.
From the given expressions, let's find the equivalent expressions.
From the given expressions, let's substitute 1 for t and evaluate.
The expressions with the same result will be equivalent expressions.
[tex]\begin{gathered} A(0.52)^{-2t} \\ \\ A(0.52)^{-2(1)} \\ \\ A(0.52)^{-2} \\ \\ A(\frac{1}{0.52^2}) \\ \\ A(\frac{1}{0.274}) \\ \\ =3.698A \end{gathered}[/tex][tex]\begin{gathered} A(1.04)^{-t}_{} \\ \\ A(1.04)^{-1} \\ \\ A(\frac{1}{1.04}) \\ \\ A(0.96) \\ \\ =0.96A \end{gathered}[/tex][tex]\begin{gathered} A(0.96)^t \\ \\ A(0.96)^1 \\ \\ A(0.96) \\ \\ =0.96A \end{gathered}[/tex][tex]\begin{gathered} A(0.96)^{0.08t}^{} \\ \\ A(0.96)^{0.08(1)} \\ \\ A(0.96)^{0.08} \\ \\ A(0.998) \\ \\ =0.998A \end{gathered}[/tex]The expressions with the same result are the expressions in options B and C:
[tex]\begin{gathered} B.A(1.04)^{-t} \\ \\ C.A(1.96)^t \end{gathered}[/tex]Therefore, the two expressions that are equivalent are:
[tex]\begin{gathered} B.A(1.04)^{-t} \\ \\ C.A(1.96)^t \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} \text{ B. A(1.04})^{-t} \\ \\ \text{ C. A(1.96)}^t \end{gathered}[/tex]instructions for building a polynomial roller coaster in factored form
Answers
The polynomial that is used to represent the roller coaster in factored form is y = +a x (x- 500) (x- 1000)
The given conditions are.
The negative intercept at x = 500
the roller coaster passes through the x-axis at x=0 and at x=1000
The polynomial equation is of the form will be
y = a x (x- 500) (x- 1000)
The polynomial will have a root at x=0 , at x=500 and at x = 1000
Polynomials are used in many areas of mathematics and science. For instance, they are employed in calculus, but numerical analysis is used to approximate other functions instead.
Polynomial functions are used in a variety of situations, from basic physics and biology to economics and social science. From straightforward word problems to intricate scientific conundrums, polynomial equations are utilized to represent a wide range of topics.
Polynomials are used in higher mathematics to construct algebraic varieties and polynomial rings, two key concepts in algebra and algebraic geometry with the use of variables.
Therefore the polynomial that is used to represent the roller coaster in factored form is y = a x (x- 500) (x- 1000)
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Slove for x Cosec(x-20°)=2/√3
Answers
The trignometric ratio is x Cosec(x-20°)=2/√3 is x = 80°.
What is trigonometry as it is a ratio?Trigonometric: A ratio is the sum of the values of all trigonometric functions whose values depend on the ratio of the sides of a right-angled triangle.The trigonometric ratio of a right-angled triangle is determined by the ratio of the triangle's sides to any acute angle.Metric and trigon are the respective Greek words for measurement and triangle.Right triangles have a 90° angle, and trigonometric ratios are specific measurements of these triangles.Now, calculate the trigonometric ratio as follows:
cosec(x-20) = 2/√3cosec ( x-20) = cosec ( 60 )x - 20 = 60x = 80°Therefore, the trignometric ratio is x Cosec(x-20°)=2/√3 is x = 80°.
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I need help, I’m not sure which one is the answer
Answers
Given the triangles are similar, the pair of corresponding sides are proportional.
Then,
[tex]\frac{AB}{ED}=\frac{BC}{EF}[/tex]Knowing that:
AB = 30
ED = 5
BC = 42
EF = x
Substituting the values:
[tex]\begin{gathered} \frac{30}{5}=\frac{42}{x} \\ 6=\frac{42}{x} \end{gathered}[/tex]Multiplying both sides by x and then dividing the sides by 6.
[tex]\begin{gathered} 6*x=\frac{42}{x}*x \\ 6x=42 \\ \frac{6x}{6}=\frac{42}{6} \\ x=7 \end{gathered}[/tex]Answer: x = 7.
Let f(x)=V3x and g(x)=×6. What'sthe smallest number that is in the domain off° g?
Answers
Answer:
Explanation:
Given:
[tex]\begin{gathered} f(x)\text{ = }\sqrt{3x} \\ g(x)\text{ = x - 6} \end{gathered}[/tex]To find:
the domain of f o g
fog = (f o g)(x) = f(g(x))
First, we will substitute the expression in g(x) with x in f(x)
[tex][/tex]The measure of angle 1 is greater than 97 degrees and at most 115. Graph the possible values of x.
Answers
We are given the following:
Angle 1 is greater than 97 degrees and at most 115 degrees
The angle alternate to angle 1 is "(9x +7)"; alternate angles are congruent
Using the information above, we will develop the inequality shown below:
[tex]\begin{gathered} 97^{\circ}10 \\ x>10 \\ \\ \therefore x>10 \end{gathered}[/tex]We will proceed to the second portion of the inequality. We have:
[tex]\begin{gathered} (9x+7)\le115^{\circ} \\ 9x+7\le115 \\ \text{Subtract ''7'' from both sides, we have:} \\ 9x\le115-7 \\ 9x\le108 \\ \text{Divide both sides by ''9'', we have:} \\ \frac{9}{9}x\le\frac{108}{9} \\ x\le12 \\ \\ \therefore x\le12 \end{gathered}[/tex]We will combine both inequalities into one. We have it thus:
[tex]\begin{gathered} x>10 \\ x\le12 \\ \text{Combining the inequalities, we have:} \\ 10We will proceed to plot this inequality on the number line as shown below:Solve this system of equations byusing the elimination method.3x + 3y = 182x + y = 4( [?]. []).
Answers
Given the system of equations:
3x + 3y = 18
2x + y = 4
Let's solve the system of equations using the elimination method.
Multiply one equation by a number which makes one variable of each equation opposite.
Multiply equation 2 by -3:
3x + 3y = 18
-3(2x + y) = -3(4)
3x + 3y = 18
-6x - 3y = -12
Add both equations:
3x + 3y = 18
+ -6x - 3y = -12
_________________
-3x = 6
Divide both sides by -3:
[tex]\begin{gathered} \frac{-3x}{-3}=\frac{6}{-3} \\ \\ x=-2 \end{gathered}[/tex]Substitute -2 for x in either of the equations.
Take the second equation:
2x + y = 4
2(-2) + y = 4
-4 + y = 4
Add 4 to both sides:
-4 + 4 + y = 4 + 4
y = 8
Therefore, we have the solutions:
x = -2, y = 8
In point form, we have the solution:
(x, y) ==> (-2, 8)
ANSWER:
(-2, 8)
You have one type of chocolate that sells for $5.00/lb and another type of chocolate that sells for $7.60/lb. You would like to have 10.4 lbs of a chocolate mixture that sells for $6.50/lb. How much of each chocolate will you need to obtain the desired mixture? You will need BLANK lbs of the cheaper chocolate and BLANK lbs of the expensive chocolate.Please help!! It is urgent.
Answers
Answer
You will need 4.4 lbs of the cheaper chocolate and 6 lbs of the expensive chocolate.
Explanation
Let the amount to be made of the type of chocolate (cheaper chocolate) that sells for $5.00/lb be x pounds.
Let the amount to be made of the type of chocolate (expensive chocolate) that sells for $7.60/lb be y pounds.
We would like to make a chocolate mixture that weighs 10.4 lbs. That is,
x + y = 10.4 .......... equation 1
This chocolate mixture is supposed to cost $6.50/lb and weigh 10.4 lbs. Hence, the cost of 10.4 lbs of this chocolate mixture will be
= 6.50 × 10.4 = $67.6
The cost of x pounds of the $5.00/lb = x × 5 = 5x dollars
The cost of y pounds of the $7.60/lb = y × 7.60 = 7.6y dollars
The cost of the two types of chocolate have to amount to $67.6
5x + 7.6y = 67.6 .......... equation 2
Writing the two equations together
x + y = 10.4
5x + 7.6y = 67.6
This simultaneous equation is then solved and the solution obtained is
x = 4.4 pounds and y = 6 pounds.
Hope this Helps!!!
POSSIBLE Match the function rule to the table of values. f(x)=2 х f (x) = (3) f(x) = 32 2 f () = ( 1 ) 28
Answers
First, we must evaluate each function at the given values of x.
When x=-2, we have
[tex]\begin{gathered} f(x)=2^x\Rightarrow f(-2)=2^{-2}=\frac{1}{2^2}=\frac{1}{4}=0.25 \\ \end{gathered}[/tex][tex]f(x)=(\frac{1}{3})^x\Rightarrow f(-2)=(\frac{1}{3})^{-2}=\frac{1}{3^{-2}}=3^2=9[/tex][tex]f(x)=3^x\Rightarrow f(-2)=3^{-2}=\frac{1}{3^2}=\frac{1}{9}=0.11[/tex][tex]f(x)=(\frac{1}{2})^x\Rightarrow f(-2)=(\frac{1}{2})^{-2}=\frac{1}{2^{-2}}=2^2=4[/tex]Now, we must compare these result with the tables. Then the solutions are:
Roxanne likes to fish. She estimates that 30% of the fish she catches are trout, 20% are bass, and 10% are perch. She designs a simulation.Let 0, 1, and 2 represent trout.Let 3 and 4 represent bass,Let 5 represent perch.Let 6, 7, 8, and 9 represent other fish.The table shows the simulation results. what is the estimated probability that at least one of the next four roxanne catches will be bass?
Answers
We have 20 equally probable events in the table. So, each box has probability equal to 1/20.
With this in mind, we must find the numbers 3 and 4 in each box. Then, we can see that there are 12 boxes containing these numbers. Therefore, the probability to catch a bass is
[tex]\begin{gathered} P(\text{bass)}=12\cdot(\frac{1}{20}) \\ P(\text{bass)}=\frac{12}{20} \\ P(\text{bass)}=\frac{3}{5} \end{gathered}[/tex]By converting these result in percentage, we have
[tex]\frac{3}{5}\cdot100=60[/tex]that is, 60% could be bass fish.
Question 18(1 point)Passes through the points, (0,6), (-8,6)What is the slope?
Answers
Given the coordinates of two points that passes through a line:
[tex]\text{ (0,6) and (-8,6)}[/tex]Let's name the points:
x1, y1 = -8,6
x2, y2 = 0,6
To be able to get the slope of the line (m), we will be using this formula:
[tex]\text{ m = }\frac{y_2-y_1}{x_2-x_1}[/tex]Let's plug in the coordinates to the formula to get the slope (m).
[tex]\text{ m = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]undefined[/tex]What is the volume of the cone? 1 Use the formula 1 = 6 cm 1 1 18 cm 1 1 1 1 A 16-em> or < 50.3 cm B) 32cm or 100.5 CMS 8 cm or
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Determine the amplitude, period, and phase shift for y=1/3tan (0 +30) and use them to plot the graph of the function.
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Given: The function below
[tex]y=\frac{1}{3}tan(\theta+30^0)[/tex]To Determine: The amplitude, the period, and the phase shift
Solution
The graph of the function is as shown below
The general equation of a tangent function is
[tex]f(x)=Atan(Bx+C)+D[/tex]Where
[tex]\begin{gathered} A=Amplitude \\ Period=\frac{\pi}{B} \\ Phase-shift=-\frac{C}{B} \\ Vertical-shift=D \end{gathered}[/tex]Let us compare the general form to the given
[tex]\begin{gathered} y=\frac{1}{3}tan(\theta+30^0) \\ f(x)=Atan(B\theta+C)+D \\ A=\frac{1}{3} \\ B=1 \\ C=30^0 \\ D=0 \end{gathered}[/tex]Therefore
[tex]\begin{gathered} Amplitude=\frac{1}{3} \\ Period=\frac{\pi}{B}=\frac{180^0}{1}=180^0 \\ Phase-shift=-\frac{C}{B}=-\frac{30^0}{1}=-30^0 \end{gathered}[/tex]Hence, the correct option is as shown below
I will show you the pic
Answers
Part b
we have
2y=-x-8
Remember that
the equation in slope intercept form is
y=mx+b
so
Isolate the variable y
divide by 2 both sides
2y/2=-(x/2)-8/2
y=-(1/2)x-4Part c
we have
y-4=-3(x-3)
apply distributive property right side
y-4=-3x+9
Adds 4 both sides
y=-3x+9+4
y=-3x+1315/2 as a mixed number
Answers
We must express the number 15/2 as a mixed number, which is a number consisting of an integer and a proper fraction. To do that, we compute the quotient in the following way:
[tex]\frac{15}{2}=\frac{14+1}{2}=\frac{14}{2}+\frac{1}{2}=7+\frac{1}{2}=7\frac{1}{2}\text{.}[/tex]Answer
The number 15/2 expressed as a mixed number is:
[tex]7\frac{1}{2}\text{.}[/tex]A) Graph the ellipse. Use graph paper or sketch neatly on regular paper. The ellipse must be hand drawn - no computer tools or graphing calculator. Give the center of the ellipse. Give the vertices of the ellipse. Give the endpoints of the minor axis. Give the foci.
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The general equation of an ellipse is:
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1.[/tex]Where:
• (h, k) are the coordinates of the centre,
,• a and b are the lengths of the legs.
The parts of the ellipse are:
In this case, we have the equation:
[tex]\frac{(x+1)^2}{5^2}+\frac{(y-4)^2}{4^2}=1.[/tex]So we have:
• (h, k) = (-1, 4),
,• a = 5,
,• b = 4.
A) The graph of the ellipse is:
B) The center of the ellipse is (h, k) = (-1, 4).
C) The vertices of the ellipse are:
• (h + a, k) = (-1 + 5, 4) = ,(4, 4),,
,• (h - a, k) = (-1 - 5, 4) =, (-6, 4),,
D) The endpoints of the minor axis are:
• (h, k + b) = (-1, 4 + 4 ) = ,(-1, 8),,
,• (h, k - b) = (-1, 4 - 4) = ,(-1, 0),.
E) To find the focuses, we compute c:
[tex]c=\sqrt[]{a^2-b^2}=\sqrt[]{5^2-4^2}=\sqrt[]{25-16}=\sqrt[]{9}=3.[/tex]The focuses of the ellipse are:
• (h + c, k) = (-1 + 3, 4) = ,(2, 4),,
,• (h - c, k) = (-1 - 3, 4) = ,(-4, 4),.
Answer
A)
B) (-1, 4)
C) (4, 4), (-6, 4)
D) (-1, 8), (-1, 0)
E) (2, 4), (-4, 4)
Michael monthly salary after tax is 2,675 if Michele pays for rent,food,and other Bill's totaling 2,140 then how much money is left
Answers
We are told that Michael has a total of $2675. If he spends $2140, then the total amount left is the difference between the total and the spent amount, that is:
[tex]2645-2140=505[/tex]Therefore, he has $505 left.
And the surface area of each hemisphere below.7.8C
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The surface area of the hemisphere is computed using the equation
[tex]SA=3\pi r^2[/tex]For the hemisphere with a radius of 14 yds, the surface area of the hemisphere is
[tex]SA=3\pi(14)^2=588\pi[/tex]For the hemisphere with a diameter of 12.2 yds, we need to find its radius first. The radius is just half of the diameter, hence, the radius of this hemisphere is 6.1 yds. Computing for its surface area, we have
[tex]SA=3\pi(6.1)^2=111.63\pi[/tex]f(x) = 3x2 + 4x – 6g(x) = 6x3 – 522 – 2Find (f - g)(x).O A. (f - g)(x) = -6x3 + 8x2 + 4x – 4O B. (f - g)(x) = 623 – 2x² + 4x - 8O C. (f - g)(x) = 6x3 – 8x2 - 4x + 4O D. (f - g)(x) = -6x3 – 2x2 + 4x – 8SUBMIT
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We are being asked to subtract one function from another function.
[tex](f-g)(x)=f(x)-g(x)[/tex][tex]\begin{gathered} (f-g)(x)=(3x^2+4x-6)-(6x^3-5x^2-2)=3x^2+4x-6-6x^3+5x^2+2 \\ (f-g)(x)=-6x^3+8x^2+4x-4 \end{gathered}[/tex]Answer: .