Answers
To plot these numbers on the given umber line, we need to identify where they would be on the number line
The number 2 3/8 is between 2 and 3 while the number 1 3/4 is between the 1 and 2
Now, we need to identify each of the small points between the numbers
Between two numbers on the line, we can count 7 small lines and a total of 8 spaces
Now to get what each of the small lines represent, we need to divide 1 by the number of spaces.
What this mean is that each of this small numbers between each of the big digits represent the fraction 1/8
Now, recall, we know that 2 3/8 is between 2 and 3, to identify the exact place to position it, divide the fractional part by 1/8
What this mean is that we have 3/8 divided by 1/8 = 3/8 * 8/1 = 3
So what this means is that the number 2 3/8 is on the third small line after 2 (between 2 and 3)
For 1 3/4, we know that the number is between 3 and 4
To know thw exact spot, we find the division of the fractional part by 1/8
Mathematically, that will be 3/4 divided by 1/8 = 3/4 * 8/1 = 6
So this mean it is on the sixth small line after 1 (between 1 and 2)
Related Questions
The citizens of a certain community were asked to choose their favorite pet. The pie chart below shows the distribution of the citizens answers. If there are 90,000 citizens in the community, how many chose hamsters, fish, snakes?
Answers
ANSWER :
27000
EXPLANATION :
From the problem, 7% chose hamsters, 15% chose Fish and 8% chose Snakes.
A total of 7 + 15 + 8 = 30%
Multiply this percentage by the population (90,000) to get the number of people who chose these pets.
That will be :
[tex]90000(0.30)=27000[/tex]Can you please check number 4 and check parts a, b, and c to make sure it’s right please
Answers
if the scale in the drawing is 1 centimeter= 20 meters, then:
a) Playground 3 centimeters.
[tex]\begin{gathered} \frac{1cm}{20m}=\text{ }\frac{3cm}{x}= \\ \text{ x\lparen1cm\rparen=\lparen20m\rparen\lparen3cm\rparen} \\ x=\text{ 60 meters} \end{gathered}[/tex]b) Tennis courts= 5.2cm
[tex]\begin{gathered} \frac{1cm}{20m}=\text{ }\frac{5.2cm}{x} \\ x(1cm)=\text{ \lparen5.2cm\rparen\lparen20m\rparen} \\ x=\text{ 104 meters} \end{gathered}[/tex]c) Walking trail= 21.7 cm
[tex]\begin{gathered} \frac{1cm}{20m}=\frac{21.7cm}{x} \\ \\ x(1cm)=(21.7cm)(20m) \\ x=\text{ 434 meters} \end{gathered}[/tex]What is the best approximation for the area of a semi-circle with a diameter of 11.8 ( Use 3.14 for pie
Answers
Answer:
54.7units^2
Explanation:
Area of a semi-circle = \pid^2/8
d is the diameter of the semi circle
Given d = 11.8
Area = 3.14(11.8)^2/8
Area of the semi circle = 3.14(139.24)/8
Area of the semi circle = 437.2136/8
Area of the semi circle = 54.6517units^2
Hence the best approximation is 54.7units^2
The sales tax rate is 10%. If Lindsey buys a fountain priced at $125.40, how much tax will she Inay? $
Answers
We have to calculate the sales tax over a purchase of $125.40.
The sales tax rate is 10%, so we can calculate:
[tex]\text{Sales tax}=\frac{10}{100}\cdot125.40=0.1\cdot125.40=12.54[/tex]Answer: the sales tax on this purchase is $12.54,
Manuel used pattern blocks to build the shapes below. The block marked A is a square, B is a trapezoid, C is a rhombus (aparallelogram with equal sides), and D is a triangle. Find the area of each of Manuel's shapes.
Answers
Solving for area of first figure
Recall the following formula for area of 2D figures
[tex]\begin{gathered} A_{\text{square}}=s^2 \\ A_{\text{trapezoid}}=\frac{a+b}{2}h \end{gathered}[/tex]The first figure consist of 2 figures with a square of side length of 2.5 cm, and a trapezoid with length 2.5 cm for the upper base, 5 cm for the lower base, and 2 cm for the height.
Calculate the area by getting the sum of the areas of the two figures
[tex]\begin{gathered} \text{Square: }s=2.5\text{ cm} \\ \text{Trapezoid: }a=2.5\text{ cm},b=5\text{ cm},h=2\text{ cm} \\ \\ A=s^2+\frac{a+b}{2}h \\ A=(2.5\text{ cm})^2+\frac{2.5\text{ cm}+5\text{ cm}}{2}\cdot2 \\ A=6.25\text{ cm}^2+\frac{7.5\text{ cm}}{\cancel{2}}\cdot\cancel{2}\text{ cm} \\ A=13.75\text{ cm}^2 \end{gathered}[/tex]The area of the first figure therefore is 13.75 square centimeters.
Solving for the area of the second figure
Recall the following areas for 2D figures
[tex]\begin{gathered} A_{\text{triangle}}=\frac{1}{2}bh \\ A_{\text{rhombus}}=bh \end{gathered}[/tex]Using the same procedures as above, we get the following
[tex]\begin{gathered} \text{Triangle: }b=2.5\text{ cm},h=2.2\text{ cm} \\ \text{Rhombus: }b=2.5\text{ cm},h=2\text{ cm} \\ \\ A=\frac{1}{2}(2.5\text{ cm})(2.2\text{ cm})+(2.5\text{ cm})(2\text{ cm}) \\ A=\frac{1}{2}(5.5\text{ cm}^2)+5\text{ cm}^2 \\ A=2.75\text{ cm}^2+5\text{ cm}^2 \\ A=7.75\text{ cm}^2 \end{gathered}[/tex]Therefore, the area of the second figure is 7.75 square centimeters.
if pa =1/3 and pb =2/5 and p(ab) = 3/5 what is p(ab)
Answers
Given:
[tex]P(A)=\frac{1}{3}\text{ ; P(B)=}\frac{2}{5}\text{ ; P(A}\cup B)=\frac{3}{5}[/tex][tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex][tex]\begin{gathered} \frac{3}{5}=\frac{1}{3}+\frac{2}{5}-P(A\cap B) \\ P(A\cap B)=\frac{1}{3}+\frac{2}{5}-\frac{3}{5} \\ P(A\cap B)=\frac{5+6-9}{15} \\ P(A\cap B)=\frac{2}{15} \end{gathered}[/tex]Option D is the final answer.
What postulate or theorem is used in the picture below?
Answers
If we have that in two triangles we have that the corresponding sides and the included angle are congruent, then we can say that both triangles are congruent. This is called the SAS (side-angle-side) postulate.
Then, in summary, the method that proves that both triangles are congruent is SAS (Side-Angle-Side) postulate (second option).
-x+2y=-158x-2y=-20After performing your first step in Elimination, what is the resulting equation?Then solve for x
Answers
Let:
[tex]\begin{gathered} -x+2y=-15_{\text{ }}(1) \\ 8x-2y=-20_{\text{ }}(2) \end{gathered}[/tex]Using elimination:
[tex]\begin{gathered} (1)+(2) \\ -x+8x+2y-2y=-15-20 \\ 7x=-35 \end{gathered}[/tex]Solve for x:
Divide both sides by 7:
[tex]\begin{gathered} \frac{7x}{7}=-\frac{35}{7} \\ x=-5 \end{gathered}[/tex]Replace the value of x into (1):
[tex]\begin{gathered} 5+2y=-15 \\ 2y=-20 \\ y=-\frac{20}{2} \\ y=-10 \end{gathered}[/tex]A swimmer is 1 mile from the closest point on a straight shoreline. She needs to reach her house located 4miles down shore from the closest point. If she swims at 3 mph and runs at 6 mph, how far from her house should she come ashore so as to arrive at her house in the shortest time?
Answers
Let's draw a diagram of this problem.
ABC is the shore.
D to A is 1 miles (given).
A to C is 4 miles (given).
If we let AB = x, then BC would be "4 - x".
Now, using pythgorean theorem, let's find BD:
[tex]\begin{gathered} AB^2+AD^2=BD^2 \\ x^2+1^2=BD^2 \\ BD=\sqrt[]{1+x^2} \end{gathered}[/tex]We know
[tex]D=RT[/tex]Where
D is distance
R is rate
T is time
Swimmer needs to go from D to B at 3 miles per hour. Thus, we can say:
[tex]\begin{gathered} D=RT \\ T=\frac{D}{R} \\ T=\frac{\sqrt[]{1+x^2}}{3} \end{gathered}[/tex]Next part, swimmer needs to go from B to C at 6 miles per hour. Thus, we can say:
[tex]\begin{gathered} D=RT \\ T=\frac{D}{R} \\ T=\frac{4-x}{6} \end{gathered}[/tex]So, total time would be:
[tex]T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6}[/tex]We want to find the shortest possible time. From calculus we know that to find the shortest possible time, we need to differentiate the function T, set it equal to 0 to find the critical points and then use that point in the function T to find the shortest possible time.
Let's differentiate the function T:
[tex]\begin{gathered} T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6} \\ T=\frac{1}{3}(1+x^2)^{\frac{1}{2}}+\frac{4}{6}-\frac{1}{6}x \\ T=\frac{1}{3}(1+x^2)^{\frac{1}{2}}+\frac{2}{3}-\frac{1}{6}x \\ T^{\prime}=(\frac{1}{2})\frac{1}{3}(1+x^2)^{-\frac{1}{2}}\lbrack\frac{d}{dx}(1+x^2)\rbrack-\frac{1}{6} \\ T^{\prime}=\frac{1}{6}(1+x^2)^{-\frac{1}{2}}(2x)-\frac{1}{6} \\ T^{\prime}=\frac{2x}{6(1+x^2)^{\frac{1}{2}}}-\frac{1}{6} \\ T^{\prime}=\frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6} \end{gathered}[/tex]Now, we find the critical point:
[tex]\begin{gathered} T^{\prime}=\frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6} \\ T^{\prime}=0 \\ \frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6}=0 \\ \frac{x}{3\sqrt[]{1+x^2}}=\frac{1}{6} \\ \text{Cross Multiplying:} \\ 6x=3\sqrt[]{1+x^2} \\ \text{Square both sides:} \\ (6x)^2=(3\sqrt[]{1+x^2})^2 \\ 36x^2=9(1+x^2) \\ 36x^2=9+9x^2 \\ 36x^2-9x^2=9 \\ 27x^2=9 \\ x^2=\frac{9}{27} \\ x=\frac{\sqrt[]{9}}{\sqrt[]{27}} \\ x=\frac{3}{3\sqrt[]{3}} \\ x=\frac{1}{\sqrt[]{3}} \end{gathered}[/tex]Plugging this value into the equation of T, we get:
[tex]\begin{gathered} T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6} \\ T=\frac{\sqrt[]{1+(\frac{1}{\sqrt[]{3}})^2}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\sqrt[]{1+\frac{1}{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\sqrt[]{\frac{4}{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\frac{2}{\sqrt[]{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{2}{3\sqrt[]{3}}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \end{gathered}[/tex]Now, we can use the calculator to find the approximate value of T to be:
T = 0.9553 hours
This is the optimized time.
Converting to approximate minutes, it will be:
57.32 minutes
Answer:[tex]T=0.9553\text{ hours}[/tex]What is the slope of the line given by the following equation? 13x + 4y = 52
Answers
Given the linear equation;
[tex]13x+4y=52-----1[/tex]We can find the slope by comparing the above equation with the general equation of a line. This can be seen below.
[tex]y=mx+c------2[/tex]Where m is the slope of the equation
We then make y the subject of the formula in equation one
[tex]\begin{gathered} 13x+4y=52 \\ \text{subtract 13x from both sides} \\ 13x-13x+4y=52-13x \\ 4y=52-13x \\ \text{Divide both sides by 4} \\ \frac{4y}{4}=\frac{52}{4}-\frac{13x}{4} \\ y=13-\frac{13x}{4} \end{gathered}[/tex]By comparison,
[tex]m=-\frac{13}{4}[/tex]Answer: The slope of the equation is
[tex]\text{slope}=-\frac{13}{4}[/tex]Please help me im so stressed rnIS (-2, 6) a solution of -3y + 10= 4x?
Answers
Given the expression:
[tex]-3y+10=4x[/tex]Let's check if (x,y) = (-2,6) is a solution by substituting each value on the equation:
[tex]\begin{gathered} x=-2 \\ y=6 \\ -3y+10=4x \\ \Rightarrow-3(6)+10=4(-2) \\ \Rightarrow-18+10=-8 \\ \Rightarrow-8=-8 \end{gathered}[/tex]since we got on both sides -8, we can see that (-2,6) is a solution of -3y+10=4x
It is reported that approximately 20 squaremiles of dry land and wetland were convertedto water along the Atlantic coast between 1996and 2011. A small unpopulated island in the AtlanticOcean is 2000 ft wide by 9,380 feet long. Atthis rate, how long before the island issubmerged?
Answers
2 months
1) Notice that the sinking rate is 20miles² per 5 years (2011-1996) so:
[tex]\frac{20}{5}=\frac{4m^2}{y}[/tex]So the rate is 4 square miles per year.
2) We need to convert those measures from feet to miles:
[tex]\begin{gathered} 1\text{ mile=5280ft} \\ 2000ft=\frac{2000}{5280}=0.378miles \\ 9380ft=\frac{9380}{5280}=1.7765miles \end{gathered}[/tex]So, now let's find the area multiplying the width by the height:
[tex]\begin{gathered} A=1.7765\cdot0.378 \\ A=0.671517m^2 \end{gathered}[/tex]Now, considering the sinking rate of 4miles²/year we can write the following pair of ratios:
[tex]\begin{gathered} 1year-------4miles^2 \\ x----------0.6715 \\ 4x=0.6715 \\ \frac{4x}{4}=\frac{0.6715}{4} \\ x=0.17 \\ \\ --- \\ 0.17\times12\approx2 \end{gathered}[/tex]Note that we found that approximately 0.17 year is necessary to submerge tat island, converting that to months, we can state that in approximately 2 months
what is the anss? btw this is just a practice assignment.
Answers
Anime, this is the solution:
Part A. This exponential is decay because the factor of the exponential is below one, and it decreases every year.
Part B.
5,100 * (0.95)^5 =
5,100 * 0.77378 =
3,946 (rounding to the nearest carbon atom)
Hugo is serving fruit sorbet at his party He has 1 gallon of fruit sorbet to serve to 32 friends. If each person receives the same amount, how many cups of fruit sorbet will each person get? A. 1/4 cupB.1/2 cupC. 3/4 cupD. 1 cup
Answers
Since 1 gallon is equal to 16 cups, each person will get
[tex]\begin{gathered} \frac{16}{32}\text{ cup} \\ \frac{16}{32}=\frac{1}{2} \\ \\ \text{ each person will get } \\ \frac{1}{2}\text{ cup} \end{gathered}[/tex]r(x)=−x−7 when x=−2,0, and 5
Answers
Given,
The expression of the function,
[tex]r(x)=-x-7[/tex]The value of r(x) at x = -2 is,
[tex]r(-2)=-(-2)-7=2-7=-5[/tex]The value of r(x) at x = 0 is,
[tex]r(0)=-(0)-7=0-7=-7[/tex]The value of r(x) at x = 5 is,
[tex]r(5)=-(5)-7=-5-7=-12[/tex]Hence, the value of r(x) is -2, -7 and -12.
There are two types of tickets sold at the Canadian Formula One Grand Prix race. The price of 6 grandstand tickets and 4 general admission tickets is $3200. The price of 8 grandstand tickets and 8 general admission tickets is $4880. What is the price of each type of ticket?
Answers
Let:
x = price of the grandstand ticket
y = price of the general admission ticket
The price of 6 grandstand tickets and 4 general admission tickets is $3200, so:
[tex]6x+4y=3200[/tex]The price of 8 grandstand tickets and 8 general admission tickets is $4880, so:
[tex]8x+8y=4880[/tex]Let:
[tex]\begin{gathered} 6x+4y=3200_{\text{ }}(1) \\ 8x+8y=4880_{\text{ }}(2) \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} 2(1)-(2)\colon_{} \\ 12x-8x+8y-8y=6400-4880 \\ 4x=1520 \\ x=\frac{1520}{4} \\ x=380 \end{gathered}[/tex]replace the value of x into (1):
[tex]\begin{gathered} 6(380)+4y=3200 \\ 2280+4y=3200 \\ 4y=3200-2280 \\ 4y=920 \\ y=\frac{920}{4} \\ y=230 \end{gathered}[/tex]The price of the grandstand ticket is $380 and the price of the general admission ticket is $230
Question 7Find the slope of the line that goes through the given points.(-1, 7).(-8, 7)1092
Answers
Given:
There are given that the two points;
[tex](-1,7)\text{ and (-8,7)}[/tex]Explanation:
To find the slope of the line from the given point, we need to use the slope formula:
So,
From the formula of the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]x_1=-1,y_1=7,x_2=-8,y_2=7_{}[/tex]Then,
Put all the above values into the given formula:;
So,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{7_{}-7_{}}{-8_{}-(-1)_{}} \end{gathered}[/tex]Then,
[tex]\begin{gathered} m=\frac{7_{}-7_{}}{-8_{}+1_{}} \\ m=\frac{0}{-7} \\ m=0 \end{gathered}[/tex]Final answer:
The slope of the given line is 0.
Hence, the correct option is B (0)
How many different combinations of nine different carrots can be chosen from a bag of 20? O 125,970 O 167,960
Answers
We have a bag of 20 carrots, all different, and we have to calculate the possible combinations in groups of 9 carrots.
We can calculate this with the formula for combinations (as the order does not matter):
[tex]_{20}C_9=\binom{20}{9}=\frac{20!}{9!(20-9)!}=\frac{20!}{9!11!}=167960[/tex]Answer: there are 167,960 possible combinatios
Find the value of x.
Answers
Answer
Option A is correct.
x = 5 units
Explanation
We can draw the triangle and divide it into two similar right angle triangles shown below
In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
The Pythagorean Theorem is used for right angled triangle, that is, triangles that have one of their angles equal to 90 degrees.
The side of the triangle that is directly opposite the right angle or 90 degrees is called the hypotenuse. It is normally the longest side of the right angle triangle.
The Pythagoras theorem thus states that the sum of the squares of each of the respective other sides of a right angled triangle is equal to the square of the hypotenuse. In mathematical terms, if the two other sides are a and b respectively,
a² + b² = (hyp)²
For each of the triangles,
a = 4
b = 3
hyp = x
a² + b² = (hyp)²
4² + 3² = x²
x² = 16 + 9
x² = 25
x = √25
x = 5 units
Hope this Helps!!!
. A pie company made 57 apple pies and 38 cherry pies each day for 14 days. How many apples pies does the company make in all?
Answers
To determine the total number of apples pies done, multiply the number of apple pies done each day by 14:
[tex]57\cdot14=798[/tex]Hence, the company made a total of 798 apple pies.
is 88∘ more than the smaller angle. Find the measure of the larger angle.
Answers
Let
x -----> large angle
y ----> smaller angle
so
Remember that
If two angles are supplementary, then their sum is equal to 180 degrees
so
x+y=180
y=180-x ------> equation A
and
x=y+88
y=x-88 -----> equation B
equate both equations
180-x=x-88
x+x=180+88
2x=268
x=134 degrees
the answer is 134 degreesA company purchased 10,000 pairs of men's slacks for $18.86 per pair and marked them up $22.63. What was the selling price of each pair of slacks? Use the formula S=C+M
Answers
Problem:
A company purchased 10,000 pairs of men's slacks for $18.86 per pair and marked them up $22.63. What was the selling price of each pair of slacks? Use the formula S=C+M.
Solution:
Cost = $18.86
Markup = $22.63
Markup = Sell Price - Cost
Sell Price = Cost + Markup
Sell Price = 18.86+ 22.63
Sell Price = $41.49
The selling price of each pair of slacks was $41.49.
11.y +9=-3(x-2)14.y- 6= 4( x+3)17.y-2 =-1/2(x-4)
Answers
Three linear equations , write in standard form
y +9= 3*(x+2)
y = 3x + 3 -9 = 3x -6
y-6= 4(x + 3)
y = 4x +12 -6= 4x + 6
y - 2 = -1/2(x-4)
y = (-1/2)x +2 +2= (-1/2)x +4
Select the appropriate graph for each inequality.1. {x|x<-3}a.<用HHHHH>-10 -1 -8 -7 -6 - 4 -3 -2 -1 01 23 4 5 6 7 8 9 10
Answers
Given the inequality x| x< -3
The graph of the inequality will be as following :
Find the length of an arc of a circle whose central angle is 212º and radius is 5.3 inches.Round your answer to the nearest tenth.
Answers
The formula for the arc length is,
[tex]L=2\pi r\cdot\frac{\theta}{360}[/tex]Substitute the values in the formula to determine the arc length.
[tex]\begin{gathered} L=2\pi\cdot5.3\cdot\frac{212}{360} \\ =19.61 \\ \approx19.6 \end{gathered}[/tex]So answer is 19.6 inches.
A trap for insects is in the shape of a triangular prism. The area of the base is 4.5 in2 and the height of the prism is 3 in. What is the volume of this trap? The volume of the trap is in3
Answers
Answer:
[tex]\text{Volume}=13.5in^3[/tex]Step-by-step explanation:
The area of the volume is represented by the multiplication of the area of the base by the height:
[tex]\text{Volume}=\text{Area}\cdot\text{height}[/tex]Then, the volume of the trap is:
[tex]\begin{gathered} \text{Volume}=4.5\cdot3 \\ \text{Volume}=13.5in^3 \end{gathered}[/tex]Quadrilateral A'B'C'D'is the image of quadrilateral of ABCD under a rotation of about the origin (0,0)a. -90b. -30c. 30d. 90
Answers
In this problem we have a couterclockwise about the origin
sp
Verify
option D
rotation 90 degrees counterclockwise
(x,y) -----> (-y,x)
so
A(-2,3) ------> A'(-3,-2) ------> is not ok
therefore
answer is option CSolve the following equation for and y - 3 - 7i + 6x = 19 + 2i + 13yi
Answers
Okay, here we have this:
Considering the provided equation, we are going to solve it, so we obtain the following:
[tex]\begin{gathered} -3-7i+6x=19+2i+13yi \\ (-3+6x)-7i=19+(2+13y)i \end{gathered}[/tex]So let's remember that a set of complex numbers can only be equal if their real and imaginary parts are equal. According to this we have:
-3+6x=19, -7=2+13y
6x=19+3, -7-2=13y
6x=22, -9=13y
x=22/6, y=-9/13
x=11/3, y=-9/13
Finally we obtain the following set: x=11/3, y=-9/13.
The accompanying table shows the value of a car over time that was purchased for 13700 dollars, where x is years and y is the value of the car in dollars Write an exponential regression equation for this set of data, rounding all coefficients to the nearest thousandth . Using this equation , determine the value of the car, to the nearest cent , after 12 years ,
Answers
ANSWER
[tex]y=13700(0.919)^x[/tex]Value of the car after 12 year: $4971.72
EXPLANATION
The exponential regression equation is
[tex]y=ab^x[/tex]Using the values of the table we can find both a and b. Note that a is the value of y when x = 0, so a = 13700.
For b replace a, and x and y with the next values of the table:
[tex]\begin{gathered} 12590=13700b^1 \\ b=\frac{12590}{13700} \\ b\approx0.919 \end{gathered}[/tex]The equation is
[tex]y=13700(0.919)^x[/tex]To find the value of the car after 12 years, replace x = 12:
[tex]y=13700(0.919)^{12}\approx4971.72[/tex]a single lily pad lies on the surface of a pond. Each day the number of lily pads doubles until the entire pond is covered on day 30. make a table that shows the number of lily pads at each day rfom day 1 to day 5. let x be the day number and y be the number of lily ad on that day
Answers
Given:
A single lily pad lies on the surface of a pond.
The number of lily pads doubles each day until the entire pond is covered on day 30.
To make a table that shows the number of lily pads on each day from day 1 to day 5:
Let x be the day number and y be the number of lily ads on that day.
On the first day, the number of lilies is 1.
On the second day, the number of Lillies is 2.
On the third day, the number of Lillies is 4.
And so on.
So, the table is,