Answer:
12.50/26.256.25×5 31.25
Step-by-step explanation:
A floor has 15 1/2 tiles in an area of 2 2/5 sqft how many tiles are in a square foot
Since in 2 2/5 sqft are 15 1/2 tiles, then in 1 square foot, there are:
[tex]\frac{15\frac{1}{2}}{2\frac{2}{5}}[/tex]tiles.
To compute the above division we transform the mixed fractions into improper fractions:
[tex]\begin{gathered} 15\text{ }\frac{1}{2}=\frac{31}{2}, \\ 2\frac{2}{5}=\frac{12}{5}. \end{gathered}[/tex]Therefore:
[tex]\frac{15\frac{1}{2}}{2\frac{2}{5}}=\frac{\frac{31}{2}}{\frac{12}{5}}=\frac{31\times5}{12\times2}=\frac{155}{24}\text{.}[/tex]Answer: 6 11/24 tiles.
There is a 40% chance that it is rainy in California. If there are 365 days in a year, how many of them would you expect to be rainy?
It is expected that 146 days will be rainy
Based on the given percentage, we want to calculate the number of rainy days
What we have to do here is to multiply the percentage by the number of days
That would be 40% of 365 days
We have this as;
[tex]\frac{40}{100}\times365\text{ = 146}[/tex]which of the following is the largest? half of 78a third of 114one-fifth of 190
Let's get the following value for the given statements and check which are the largest.
a) Half of 78.
We compute for the half of 78, which we divide 78 by 2. We have
[tex]\frac{78}{2}=39[/tex]b) A third of 114
A third of a number means we divide the number by 3. Dividing 114 by 3, we get
[tex]\frac{114}{3}=38[/tex]c) One-fifth of 190
One-fifth of a number means we divide the number by 3. Dividing 190 by 5, we get
[tex]\frac{190}{5}=38[/tex]As we can see on the results above, the largest is half of 78.
Which relation is a function?
I’m confused on this. can anyone help me out?
Answer:
The one the u have marked is a function.
Step-by-step explanation:
If you draw a vertical line through each one, each line only goes through one point
I am going to send the pictures Please solve question b(b) Canada like many countries use the metric system if the Canada news says it’s-2 degrees Celsius what is that in Fahrenheit ( Celsius is typically rounded to the tenth place
Given equation:
[tex]\text{ Wind Chill = }35.74\text{ }+\text{ }0.6215T\text{ }-\text{ 35}.75(V^{0.16})\text{ }+\text{ }0.4275T(V^{0.16})[/tex]Where T = temperature in Fahrenheit and
V = wind speed in miles per hour
Conversion formulas:
[tex]\begin{gathered} A_s\text{ = }M_s\text{ }\times\text{ }0.62 \\ F\text{ = 1.8C + 32} \end{gathered}[/tex]Question (b)
We are required to convert -2 degree Celsius to Fahrenheit
Using the conversion formula:
[tex]\begin{gathered} F\text{ = }1.8\text{ }\times-2\text{ + 32} \\ =\text{ 28.4} \end{gathered}[/tex]Answer: 28.4 F
Study the figures, figure 1 is similar to figure 2Part A : Describe a series of transformations and dilations that map figure 1 to figure 2Part 2: Describe a second series of transformations and dilations that map figure 1 to figure 2
In order to go from figure 1 to figure 2, there are a number of different transformations that can be selected.
First, notice that figure 2 is exactly three times as large as figure 1, therefore, there has been a dilation by a factor of three (3) that took place .
So Let's say that we do the dilation first.
Step 1: Dilation by a factor of "3" using the point (-1, -2) which is one of the vertices of the triangle, for reference. Then, the new triangle would have new coordinaes for the vertices at the points:
(-1, -2) (-1, 1) and (-6, -2)
I am making a drawing to show the change (give me a little time)
So, we see that the dilated triangle is represented by the green one in the image above.
Step 2: we are now going the "reflect the green triangle around the horizontal line y = 2 represented by the blue line . When we reflect the green triangle around that line, we obtain the orange triangle.
Step 3: we are going to do another reflection, this time a reflection around the vertical line x = 1 (noted in purple in the image above). After this, we obtain the triangle in figure 2.
So we
yo i need some help this determines weather i pass or fail
To make 4 dozen cookies she would need
→ 3/2 cup peanut butter
→ 3 cup of vegetable shortening
→ 1 1/2 cups of firmly packed light brown sugar
→ 6 tablespoons of milk
→ 2 3/2 tablespoons of vanilla extract
→ 2 cups of flour
→ 3/2 teaspoon of baking soda
→ 1/2 teaspoon salt
To make 4 dozen cookies
she will need double the items which are mentioned in the list
thus the required list will look like this
3/4 × 2 = 3/2 cup peanut butter
3/2 cup of vegetable shortening = 3/2 × 2 = 3 cup of vegetable shortening
1 1/4 cups of firmly packed light brown sugar = 1 1/4 × 2 = 1 1/2 cups of firmly packed light brown sugar
3 tablespoons of milk = 3 × 2 = 6 tablespoons of milk
2 3/4 tablespoons of vanilla extract = 2 3/2 tablespoons of vanilla extract
1 large egg = 1× 2 = 2 large eggs
1 1/2 cups flour = 1 1/2×2 = 1 + 1 = 2 cups of flour
3/4 teaspoon baking soda = 3/2 teaspoon of baking soda
1/4 teaspoon salt = 1/4 × 2 = 1/2 teaspoon salt
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I need help with this practice problem It’s asks to Drag the angle measure to each box to match the quadrant location of the terminal ray of the angle op
Note that the range in quadrants are :
[tex]\begin{gathered} Q1\colon\text{From}\quad 0\pi-0.5\pi \\ Q2\colon\text{From}\quad 0.5\pi-1.0\pi \\ Q3\colon\text{From}\quad 1.0\pi-1.5\pi \\ Q4\colon\text{From}\quad 1.5\pi-2\pi \end{gathered}[/tex]From the problem,
[tex]\begin{gathered} \frac{3\pi}{4}=0.75\pi\Rightarrow Q2 \\ \frac{57\pi}{8}=7.125\pi \\ \text{Note that 1 whole circle is}\quad 2\pi \\ \text{Subtracting three}\quad 2\pi \\ 7.125\pi-3(2\pi)=1.125\pi \\ \text{and}\quad 1.125\pi\quad \text{ is at Q3} \\ \\ \frac{13\pi}{6}=2.167\pi \\ Subtract\quad 2\pi \\ 2.167\pi-2\pi=0.167\pi\Rightarrow Q1 \end{gathered}[/tex]The first three answers are :
Q2, Q3 and Q1
For the second set, we have negative angles.
The range of negative angles will be the reversal of the positive angles.
This will be :
[tex]\begin{gathered} Q1\colon\text{From}\quad -1.5\pi\quad to\quad -2\pi \\ Q2\colon\text{From}\quad -1.0\pi\quad to\quad -1.5\pi \\ Q3\colon\text{From}\quad -0.5\pi\quad to\quad -1.0\pi \\ Q4\colon\text{From}\quad -0\pi\quad to\quad -0.5\pi \end{gathered}[/tex]The following angles are :
[tex]\begin{gathered} -\frac{35\pi}{4}=-8.75\pi \\ \text{Add four}\quad 2\pi \\ -8.75+4(2\pi)=-0.75\pi \\ -0.75\pi\Rightarrow Q3 \\ \\ -\frac{5\pi}{6}=-0.83\pi\Rightarrow Q3 \\ \\ -\frac{5\pi}{11}=-0.45\pi\Rightarrow Q4 \end{gathered}[/tex]The last three answers are :
Q3, Q3 and Q4
To summarized :
[tex]\begin{gathered} Q1\colon\frac{13\pi}{6} \\ Q2\colon\frac{3\pi}{4} \\ Q3\colon\frac{57\pi}{8},\quad -\frac{35\pi}{4},\quad -\frac{5\pi}{6} \\ Q4\colon-\frac{5\pi}{11} \end{gathered}[/tex]2/9x20 as a fraction
Answer:
40/9 OR 4 4/9
Step-by-step explanation:
2/9 x 20 = 2*20/9 = 40/9
3.13 geom Which triangle congruence postulate or theorem proves that these triangles are congruent?
The AAS triangle congruence postulate proves that these triangles are congruent .
In the question,
two triangles are given that are triangle KLM and triangle XYZ .
Consider the triangle KLM and triangle XYZ .
we can see that
(i) angle L = angle Y = angle 1 .....given in the figure
(ii) angle m = angle Z = angle 2 .... given in the figure
(iii) side KM = side XZ ....given in the figure
From the above three statements we conclude that
ΔKLM ≅ ΔXYZ
both the triangles KLM and XYZ are congruent by AAS Congruence Postulate .
Therefore , The AAS triangle congruence postulate proves that these triangles are congruent .
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pls help me answer these questions
Answer:
Length: 10 m
Width: 6 m
Step-by-step explanation:
The layout of the floor is l x w, which is 100 cm by 60 cm. Now, the confusing part: 1 meter (m) = 10 centimeters (cm)
To set this problem up, you'd first have to go through the logic. For every 10 centimeters of the floor layout, it is equal to 1 meter of the actualy floor plan. So you would have to scale 100 cm and 60 cm by [tex]\frac{1}{10}[/tex] (or divide by 10).
We will ignore the units, for now
Length: 100 * [tex]\frac{1}{10}[/tex] = 10 or (100/10 = 10)
Width: 60 * [tex]\frac{1}{10}[/tex] = 6 or (60/10 = 6)
Now that we've finalized the numerical value, lets move on to the units. Since the question wants us to respond in meters, the length of 10 and the width 6 6 would be in meters.
So the answer would be:
Length: 10 m
Width: 6 m
Hope this helped!
Inscribed angles, I’m being asked for a, and b but I don’t understand this question
Given the figure of a circle.
There are 3 arcs with the following measures: a, 100, and 136
the sum of the measures of the arcs = 360
So, we can write the following equation:
[tex]a+100+136=360[/tex]Solve the equation to find (a):
[tex]\begin{gathered} a+236=360 \\ a=360-236=124 \end{gathered}[/tex]The angle (b) is the Inscribed angle opposite the arc (a)
[tex]b=\frac{1}{2}a=\frac{1}{2}*124=62[/tex]So, the answer will be:
[tex]\begin{gathered} a=124 \\ b=62 \end{gathered}[/tex]There is a rope running from the top of a flagpole to a hook in the ground. The flagpole is 21 feet high, and the hook is 20 feet from its base. How long is the rope?
Sam bought a jacket for $34, which is one-third of the original price. How much did thejacket cost originally?
Let the original cost of the jacket be x.
Now, saying that one-third of the original cost of the jacket is $34, is mathematically equivalent to:
[tex]\frac{1}{3}\times x=34[/tex]Now we have to solve the resulting equation in order to obtain the value of x
This is done as follows:
[tex]\frac{1}{3}\times x=34[/tex][tex]\Rightarrow\frac{x}{3}=34[/tex][tex]\Rightarrow x=3\times34[/tex][tex]x=102[/tex]Therefore, the original cost of the jacket is $102
In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.
The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = [tex]\frac{o^{2}+p^{2}-q^{2} }{2op}[/tex]
Putting the values in equation,
cos 37 = [tex]\frac{(9.2)^{2}+(2.4)^{2}-q^{2} }{2*9.2*2.4}[/tex]
0.799 = [tex]\frac{84.64 + 5.76-q^{2} }{44.16}[/tex]
0.799*44.16 = 90.4 - [tex]q^{2}[/tex]
32.28 = 90.4 - [tex]q^{2}[/tex]
[tex]q^{2}[/tex] = 90.4 - 32.28
[tex]q^{2}[/tex] = 58.12
[tex]q = \sqrt{58.12}[/tex]
[tex]q = 7.63[/tex]
q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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Solve the quadratic equation x² + 2√2x-6=0 for x
Step-by-step explanation:
D = b²-4ac
D = (2√2)²-4×1×(-6)
D = 8+24 = 32 = 4√2
X1 =
[tex] \\ \frac{ - 2 \sqrt{2} + 4 \sqrt{2} }{ 2 } = \frac{2 \sqrt{2} }{2} = \sqrt{2} [/tex]
X2 =
[tex] \frac{ - 2 \sqrt{2 } - 4 \sqrt{2} }{2} = - 3 \sqrt{2} [/tex]
Given the lengths of the sides of a triangle, determine if it is an acute, anobtuse, or a right triangle.
Use the Pythagorean theorem to determine if the triangle is acute, obtuse or right triangle.
[tex]\begin{gathered} a^2+b^2=c^2 \\ \text{where} \\ c\text{ is the longest side of the triangle} \\ a\text{ and }b\text{ are the other 2 sides} \end{gathered}[/tex][tex]\begin{gathered} a^2+b^2=c^2 \\ (18)^2+(29)^2\questeq(46)^2 \\ 324+841\questeq2116 \\ 1165\questeq2116 \\ 1165<2116 \end{gathered}[/tex][tex]\begin{gathered} \text{IF} \\ a^2+b^2c^2 \\ \text{THEN, the triangle is an acute triangle} \\ \\ \text{IF} \\ a^2+b^2=c^2 \\ \text{THEN, the triangle is a right triangle} \end{gathered}[/tex]Since the sum of the square of the side of the two angles is less than the square of the longest side, then given the length of a triangle 18-29-46, the triangle is an obtuse triangle.
estimate 15.870 + 6.77 by first rounding each number to the nearest tenth
Given:
15.870 + 6.77
We are required to round each number to the nearest tenth before performing the addition.
The tenth digit is the number first number after the decimal point.
First step:
Round to the nearest tenth
15.870 ==> 15.9
6.77 ==> 6.8
Second step:
Add both numbers after rounding to the nearest tenth
15.9 + 6.8 = 22.7
ANSWER:
22.7
slove the equation 4c + 7 = 23
We need to solve the expression:
[tex]4c+7=23[/tex]The first step is to subtract "7" on both sides.
[tex]\begin{gathered} 4c+7-7=23-7 \\ 4c=16 \end{gathered}[/tex]Then we need to divide both sides by 4.
[tex]\begin{gathered} \frac{4c}{4}=\frac{16}{4} \\ c=4 \end{gathered}[/tex]The result of the equation is "c=4".
please help NEED FAST
a) The quadratic equation behind the parabola is y = (4 / 5) · x² - (8 / 5) · x - 1.
b) There are two x-intercepts: x₁ = - 0.5, x₂ = 2.5.
How to derive a quadratic equation and find its x-intercepts
Mathematically speaking, parabolas are represented by quadratic equations, whose standard form is introduced below:
y = a · x² + b · x + c
Where a, b, c are real coefficients.
The values of the three coefficients are found from the knowledge of three distinct points on Cartesian plane. First, choose the three points:
(x₁, y₁) = (- 0.5, 0), (x₂, y₂) = (2.5, 0), (x₃, y₃) = (0, - 1)
Second, construct the system of linear equations with all the given points and the standard form of the quadratic equation:
0.25 · a - 0.5 · b + c = 0
6.25 · a + 2.5 · b + c = 0
c = - 1
Third, solve the system by numerical methods:
(a, b, c) = (4 / 5, - 8 / 5, - 1)
Fourth, write the quadratic equation:
y = (4 / 5) · x² - (8 / 5) · x - 1
The x-intercepts of the quadratic equation are the points of the curve that pass through the x-axis. Then, the x-intercepts are x₁ = - 0.5 and x₂ = 2.5.
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There are two integers that
multiply to -45 and combine to -4. Find
the two integers, then the LARGER
integer is your answer for this question.
Answer:
5
Step-by-step explanation:
-9 × 5 = -45
-9 + 5 = -4
5 is greater than -9, therefore 5 is the answer
can you help me find BD. under the letter A the number is 25°
arc BD is 25°
Explanation:We would apply the secant-secant theorem:
[tex]\begin{gathered} \angle A\text{ =}\frac{large\text{ arc - small arc}}{2} \\ \angle A\text{ =}\frac{arc\text{ CE - arc BD}}{2} \end{gathered}[/tex]angle A = ∠A =25°
arc BD =?
arc CE = 100°
[tex]\begin{gathered} 25\text{ = }\frac{100-arc\text{ BD}}{2} \\ \text{cross multiply:} \\ 2(25)\text{ = 100 - arc BD} \end{gathered}[/tex][tex]\begin{gathered} 50\text{ = 100 - arc BD} \\ \text{subtract 100 from both sides:} \\ 50\text{ - 100 = 100 - 100 - arc BD} \\ -50\text{ = - arc BD} \end{gathered}[/tex][tex]\begin{gathered} \text{DIvide both sides by -1:} \\ \frac{-50}{-1\text{ }}=\frac{-arc\text{ BD}}{-1} \\ \text{arc BD = 50}\degree \end{gathered}[/tex]please help help me write a story to describe the graph
I'll start first by finding the slope of the line at t = 2 mins up to t = 6 mins, t = 6 mins up to t = 8 mins, and t = 14 mins up to t = 20 mins.
For the first interval (2 mins to 6 mins), we have the coordinates (2, 7) and (6, 5). The slope of the line is
[tex]m=\frac{5-7}{6-2}=-\frac{2}{4}=-\frac{1}{2}[/tex]For the second interval (6 mins up to 8 mins), we have the coordinates (6, 5) and (8,0). The slope of the line is
[tex]m=\frac{0-5}{8-6}=-\frac{5}{2}[/tex]For the last interval (14 mins up to 20 mins), we have the coordinates (14,0) and (20,9). The slope of the line is
[tex]m=\frac{9-0}{20-14}=\frac{9}{6}[/tex]The x-axis of the given graph pertains to time while its y-axis pertains to distance from home. Let's try to make a story about a person from work going home and will prepare something before going outside again.
For the first 2 mins, the person walks out of his office and will go to his car. Since he is still in the office, the distance from home does not change for the first two minutes.
For the next 4 mins (2 mins to 6 mins interval), he starts driving going home at a rate of 1/2 miles per minute. Because of traffic, he is driving slower than his usual driving speed. Upon passing away from the traffic, the person now travels at a rate of 5/2 miles per minute for 2 mins (6 to 8 mins interval). At the 8th minute mark, he is already home. He prepared something at home during the 8 min to 14 min interval time. After the preparation, he went again outside for some business trip, traveling at the speed of 9/6 miles per minute.
if i did
what would i get?
?
be more specific :)
Express 72 1/2% asa fraction in its lowest term
The percentage of the number is 29/40 when The number is 72 1/2.
Given that,
The number is 72 1/2
We have to find the percentage of the number.
The Latin word "per centum," which means "by the hundred," is where the word "percentage" originally came from. Percentages are fractions when the denominator is 100. To put it another way, it's the relationship between a part and a whole in which the value of the whole is always assumed to be 100.
We have number,
72 1/2
145/2
145/2× 1/100
145/200
29/40
Therefore, The percentage of the number is 29/40 when The number is 72 1/2.
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You have 16 yellow beads, 20 red beads, and 24 orange beads to make identical bracelets. What is the greatest number of bracelets that you can make using all of the beads?
As per the concept of GCF, the greatest number of bracelets that you can make using all of the beads is 4.
GCF:
GCF means the largest positive integer not a decimal that divides evenly into all of the numbers in the set. also know as Highest common factor.
Given,
You have 16 yellow beads, 20 red beads, and 24 orange beads to make identical bracelets.
Here we need to find the greatest number of bracelets that you can make using all of the beads.
In order to find it, we have to find the prime factorization of each beads,
So, the prime factorizations of 16, 20 and 24 is,
Factors for 16 is 1, 2, 4, 8, and 16
Factors for 20 is 1, 2, 4, 5, 10, and 20
Factors for 24 is 1, 2, 3, 4, 6, 8, 12, and 24
While we looking into the factors, we have identified that the greatest common factor is 4.
Therefore, there are 4 bracelets that you can make using all of the beads.
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If u = 1 + 3i and v = -2 − i, what is u + v?
Answer:
2i - 1
Step-by-step explanation:
The expression is,
→ u + v
Simplifying the expression,
→ u + v
→ (1 + 3i) + (-2 - i)
→ (3i - i) + (1 - 2)
→ 2i - 1
Hence, the answer is 2i - 1.
Step-by-step explanation:
you need to replace definition of both u and v into the equation
u + v = (1+3i) + (-2-i)
= 1 + 3i -2 - i
= 3i - i + 1 - 2
= 2i - 1
Answer to the nearest tenth:
12 is 90% of what number?
Answer:
13.33 is the answer im pretty sure
Step-by-step explanation:
Answer:
13.3
Step-by-step explanation:
1. If it's possible - try cutting the number down to 10%-:
We can do that by dividing 12 by 9, which would give us 10% of that
number.
2. We get 1.33, which is 10% of the number. To get 100 percent, we just need to multiply by 10
3: 1.33*10 is 13.3, so the answer has to be 13.3
Which inequality in factored form represents the region less than the quadratic function with zeros-40 and -50 and
includes the point (-55, -75) on the boundary line?
O y<-(x-40)(x-50)
O ys-(x+40)(x+50)
Oys-(x-40)(x - 50)
O y<-(x +40)(x+50)
Please help
The inequality that reflects the given region, according to the Factor Theorem, is:
y< -(x+40)(x+50)
What is the Factor Theorem?When completely factoring polynomials, the factor theorem is employed in mathematics. It is a theorem that relates the factors and zeros of a polynomial. If f(x) is a polynomial of degree n 1 and 'a' is any real number, then (x-a) is a factor of f(x) if f(a)=0.
According to the Factor Theorem, a polynomial function with roots x₁, x₂, ....xₙ is given by
f(x)=a(x-x₁)(x-x₂)...(x-xₙ)
In which a is the leading coefficient.
The roots are given as follows:
x₁=-40, x₂=-50
Hence:
y = a(x + 40)(x +50)
It includes the point (-55,-75), hence:
-75 = a(-55 + 40)(-55 +50)
a = 75/(15 x 5)
a = 1
The equation that is less than the region is:
y< -(x+40)(x+50)
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Answer:
d
Step-by-step explanation:
If you travel a 150 miles in 3 hours what was your average rate of speed
Distance (D): 150 miles
Time (t): 3 hours
[tex]Speed=\frac{D}{t}=\frac{150}{3}=50[/tex]Answer: 50 miles / hour