Can some one help me with 7 , 8 and 9 please?

Can Some One Help Me With 7 , 8 And 9 Please?

Answers

Answer 1

7) The angle asked is ajacent to the leg given and we also have the hypotenuse. So we can use cossine:

[tex]\begin{gathered} \cos x=\frac{8}{18}=\frac{4}{9} \\ x=\arccos (\frac{4}{9})=64\degree \end{gathered}[/tex]

8) Here we want the hypotenus given an angle an its opposite leg. So we can use sine:

[tex]\begin{gathered} \sin (65\degree)=\frac{10}{x} \\ x=\frac{10}{\sin (65\degree)}=11.0 \end{gathered}[/tex]

9) We want the leg which is opposite of a given angle and we have the hypotenuse. So we can use sine again:

[tex]\begin{gathered} \sin (28\degree)=\frac{x}{15} \\ x=15\cdot\sin (28\degree)=7.0 \end{gathered}[/tex]


Related Questions

Find the probability of X successes, using Table B in Appendix A of the textbook or some other method.n = 10, p = 0.3, X = 7

Answers

SOLUTION

The probability is a binomial probability

The probability is given as

[tex]\text{nCxp}^xq^{n-x}[/tex]

Where p= proability of succes=0.3

q=probability of failure=1-p=1-0.3=0.7

n=10, x=7

Then, substitute the parameters into the formula

[tex]10C_7(0.3)^7(0.7)^3[/tex][tex]\begin{gathered} 10C_7=120 \\ 120\times2.187\times10^{-4}\times0.343 \end{gathered}[/tex]

Then we have

[tex]\begin{gathered} 9.0017\times10^{-3} \\ 0.0090017 \end{gathered}[/tex]

The probability of x-success is 0.009

1v=9. Which equation represents the equation of theparabola with focus (-3,3) and directrix y = 7?A),= (x+3)2 – 5B) y = 5(? – 3)2 +5C) y=-( + 3)2 +5D) y=-2 (2-3)2 +5

Answers

SOLUTION

From the focus (-3, 3) and the directrix y = 7 given, note that the vertex is usually between the focus and the directrix.

So, the vertex will have the same x-coordinate as the focus, which is -3, and the y-coordinate of the vertex becomes

[tex]\begin{gathered} \frac{3+7}{2} \\ that\text{ is 3 from the y-coordinate of the focus and 7 from the directrix} \\ y=7 \\ \frac{3+7}{2}=\frac{10}{2}=5 \end{gathered}[/tex]

Hence coordinate of the vertex is (-3, 5)

Now, equation of a parabola is given as

[tex]\begin{gathered} (x-h)^2=4p(y-k) \\ where\text{ \lparen h, k\rparen is the coordinate of the vertex and p is the focal length} \\ y=k-p,\text{ so we have } \\ 7=5-p \\ p=5-7=-2 \end{gathered}[/tex]

So putting in the values of h, k and p into the equation, we have

[tex]\begin{gathered} (x-h)^{2}=4p(y-k) \\ (x-(-3)^2=4(-2)(y-5) \\ (x+3)^2=-8(y-5) \\ -\frac{1}{8}(x+3)^2=y-5\text{ that is dividing through by -8} \\ making\text{ y the subject, we have } \\ y=-\frac{1}{8}(x+3)^2+5 \end{gathered}[/tex]

Hence the answer is

[tex]y=-\frac{1}{8}(x+3)^{2}+5[/tex]

Please just put the answer for this question On D

Answers

Answer

The liters of air takes in during 150 seconds is 25 liters

Step-by-step explanation:

A man takes in 5 liters of air in 30 seconds

Firstly, we need to find the rate

Given:

Volume = 5 liters

time = 30 seconds

Rate =?

Volume = rate x time

5 = rate * 30

rate = 5/30 liters / second

Find the volume of air takes in during 150 seconds at the same rate

Volume = rate * time

Volume = 5/30 * 150

Volume = 5 * 150 / 30

Volume = 25 liters

Hence, the liters of air takes in during 150 seconds is 25 liters

b) Use the graph to estimate the
value of x when y = 1

Answers

Answer:

Hey bro you're welcome.

Step-by-step explanation:

Find the perimeter of quadrilateral ABCD with vertices A(0,4), B(4,1), C(1, -3), and D(-3,0).25 units100 units5 units20 units

Answers

The perimeter is the sum of the length of each side of the quadrilateral. We would find the length of each side by applying the formula for finding the distance between two points which is expressed as

[tex]\text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]

Thus, we have

[tex]\begin{gathered} ForAB,x1=0,y1=4,x2=4,\text{ y2 = 1} \\ \text{Distance = }\sqrt[]{(4-0)^2+(1-4)^2\text{ }}\text{ = }\sqrt[]{16\text{ + 9}} \\ AB\text{ = 5} \\ \text{For BC, x1 = 4, y1 = 1, x2 = 1, y2 = - 3} \\ \text{Distance = }\sqrt[]{(1-4)^2+(-3-1)^2}\text{ = }\sqrt[]{9\text{ + 16}} \\ BC\text{ = 5} \\ \text{For CD, x1 = 1, y1 = - 3, x2 = - 3, y2 = 0} \\ \text{Distance = }\sqrt[]{(-3-1)^2+(0--3)^2}\text{ = }\sqrt[]{16\text{ + 9}} \\ CD\text{ = 5} \\ \text{For AD, x1 = 0, y1 = 4, x2 = - 3, y2 = 0} \\ \text{Distance = }\sqrt[]{(-3-0)^2+(0-4)^2\text{ }}\text{ = }\sqrt[]{9\text{ + 16}} \\ AD\text{ = 5} \end{gathered}[/tex]

Perimeter = AB + BC + CD + AD = 5 + 5 + 5 + 5

Perimeter = 20 units

this graphic organizer is being used to classify triangles based on their angle measures or sideways which list shows all of the ways that strangle could be classified

Answers

D

1) Examining the sides of that triangle, we can state that this is an equilateral triangle (at least 2 sides have the same measure). But Since isosceles is a triangle that has 2 sides with the same measure.

Then we can state that about their sides this is an equilateral and isosceles triangle.

2) Examining their angles. An equilateral triangle has 3 angles with 60º measure. A 60º angle is lesser than 90º, then we can classify this triangle as an acute triangle

3) Hence, the answer is D

What is the residual of a performance with a revenue of $700 and 70 seats occupied?

Answers

[tex]\begin{gathered} \text{Calculate the total revenue using the least regression equation} \\ \hat{y}=-325+14x \\ \text{At }70\text{ seats that is} \\ \hat{y}=-325+14x(70) \\ \hat{y}=-325+980 \\ \hat{y}=655 \\ \text{Now that we have the predicted revenue, get the residual by} \\ \text{Residual}=y-\hat{y} \\ \text{Residual}=700-655 \\ \text{Residual}=45 \\ \text{Therefore, the residual of the performance is \$45.} \end{gathered}[/tex]

State weather the triangles are similar. If so write a similarity statement and that postulate or theorem you used. The diagram is not drawn to scale.

Answers

Given:

To prove the similarity.

Two triangles similarity condition:

If two triangles are similar then the corresponding sides are proportional.

[tex]\Delta\text{OKJ Similar to }\Delta ONM[/tex][tex]\begin{gathered} \frac{OK}{ON}=\frac{OJ}{OM}=\frac{KJ}{NM} \\ \frac{3}{3+1}=\frac{30}{30+10} \\ \frac{3}{4}=\frac{30}{40} \\ \frac{3}{4}=\frac{3}{4} \end{gathered}[/tex]

From the given values the corresponding sides are proves as propotional.

[tex]\Delta\text{OKJ Similar to }\Delta ONM[/tex]

A survey of 85 persons was conducted at TCC, and it was found that 54 persons carried a cell phone, 19 persons carried a tablet computer, and 16 carried both a cell phone and a tablet.How many people carried a cell phone or a tablet?How many people carried neither a cell phone nor a tablet?How many people carried a cell phone only?How many people carried a tablet but not a cell phone?

Answers

Answer:

The universal set is given below as

[tex]\xi=85[/tex]

The number of people with cell phone is

[tex]n(C)=54[/tex]

The number of persons with tablet is

[tex]n(T)=19[/tex]

The number of people who carry both cellphone and tablet

[tex]n(C\cap T)=16[/tex]

Step 1:

To figure our the number of students that carry cellphone or tablets will be

[tex]\begin{gathered} =38+16+3 \\ =57\text{ }people \end{gathered}[/tex]

Hence,

The number of people that carried cell phone or tablet

[tex]\Rightarrow57people[/tex]

Step 2:

How many people carried neither a cell phone nor a tablet?

[tex]\begin{gathered} =85-(38+16+3) \\ =85-57 \\ =28 \end{gathered}[/tex]

Hence,

The number of people that carried neither cell phone nor a tablet is

[tex]\Rightarrow28people[/tex]

Step 3:

How many people carried a cell phone only?

Hence,

The number of people who carried cell-phone only is

[tex]\Rightarrow38people[/tex]

Step 4:

How many people carried a tablet but not a cell phone?

Hence,

The number of people that carried a tablet but not a cell phone is

[tex]\Rightarrow3people[/tex]

Find the equation of this line.(2,2) and (0,-4)

Answers

To find the equation;

x₁ = 2 y₁ = 2 x₂ = 0 y₂=-4

we will use the formula;

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x_{}-x_1)[/tex]

substituting the values into the above;

[tex]y-2=\frac{-4-2}{0-2}(x-2)[/tex]

Then, we will go ahead and evaluate;

[tex]y-2\text{ = }\frac{-6}{-2}(x-2)[/tex]

[tex]y-2\text{ =3(x-2)}[/tex]

y - 2 = 3x - 6

add 2 to both-side of the equation

y = 3x -6+ 2

y = 3x -4

i’m taking an algebra pretest & i’m very confused. i haven’t learned this material. please help!!

Answers

ANSWER

7 (Option D)

EXPLANATION

Given:

Number of times the traffic light Green = 6

Number of times the traffic light Yellow = 2

Number of times the traffic light Red = ?

Desired Outcome:

Number of times the traffic light Red

Total number of times for the traffic lights

[tex]\begin{gathered} \text{ Total times = Times for traffic light Red + Times for traffic light Green + Times for traffic light Yellow} \\ 15=Red+6+2 \\ 15=Red+8 \\ substract\text{ 8 from both sides} \\ 15-8=Red+8-8 \\ \text{ Times for traffic light Red = 7} \end{gathered}[/tex]

Hence, the number of times the traffic light Red was 7.

Enter your answer, rounded to the nearest tenth, in the box.

Answers

ANSWER:

-11.4

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]f\mleft(x\mright)=\frac{100}{-10+e^{-0.1x}}[/tex]

We calculate the result when x = -2, just like this:

[tex]\begin{gathered} f(-2)=\frac{100}{-10+e^{-0.1\cdot-2}} \\ f(-2)=\frac{100}{-10+e^{0.2}} \\ f(-2)=\frac{100}{-10+1.22} \\ f(-2)=\frac{100}{-8.78} \\ f(-2)=-11.4 \end{gathered}[/tex]

When x = -2, the value of the function is equal to -11.4

Which is the best estimate for 2 2/3 × 3 1/4

Answers

The best estimate of the real number expression; 2 ⅔ × 3 ¼ as given in the task content is; 8 ⅔.

What is the best estimate of the real number expression given?

It follows from the task content that the best estimate of the real number expression given is to be determined.

On this note, the mixed numbers must be converted to fractions for ease of computation as follows;

Therefore; 2 ⅔ = 8 / 3.

And, 3 ¼ = 13 / 4.

Therefore, the required evaluation of the expression is;

2 ⅔ × 3 ¼ = 8 / 3 × 13 / 4

= 104/12

= 26 / 3

Hence, the best estimate for the given expression is; 26 / 3 Or 8 ⅔.

Read more on fractions multiplication;

https://brainly.com/question/7335118

#SPJ1

b.InOut133171066co38Rule:

Answers

Suppose that the rule is of the form

[tex]y=mx+b[/tex]

Where m is the slope and b is the intercept

The slope can be found using the formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

You can take any two consecutive x and y values from the given table.

[tex]\frac{17-3}{3-1}=\frac{14}{2}=7[/tex]

Similarly,

[tex]\frac{66-17}{10-3}=\frac{49}{7}=7[/tex]

As you can see, you will end up with the same slope.

Now let us find the intercept b.

Take any x, y coordinates from the table

[tex](x,y)=(1,3)[/tex]

Now substitute them in the slope-intercept equation.

[tex]\begin{gathered} y=7x+b \\ 3=7(1)+b \\ 3=7+b \\ b=-7+3 \\ b=-4 \end{gathered}[/tex]

So the rule is

[tex]y=7x-4[/tex]

Verification:

Let us verify whether we got the correct rule or not

Substitute the input x coordinates into the rule and check the outputs y coordinates.

[tex]\begin{gathered} y=7(1)-4=7-4=3 \\ y=7(3)-4=21-4=17 \\ y=7(10)-4=70-4=66 \\ y=7(6)-4=42-4=38 \end{gathered}[/tex]

As you can see, we have got the same results therefore, the rule is correct.

Chris tries to copy

Answers

The Chris's error is that he does not consider he can not draw the upper oblique line crosses trough the end the of the arc.

To coorect that, Chris must to draw the upper line crosses trough the center of the arc. In this way he is going to obtain a exact copy of angle ∠T.

By taking into account the previous specifications you obtain the following draw of the angle:

As you can notice, it is necessary that the upper line crosses trough the center of the arc.

the triangles are similar. find the similarity ratio of the first to the second

Answers

To get the similarity ratio between both triangles, write down a ratio between two similiar sides. Let's take the base, for example

[tex]4\colon6[/tex]

Simplifying,

[tex]2\colon3[/tex]

Thereby, the similarity ratio between both triangles is:

[tex]2\colon3[/tex]

Ans: Option B

Question 7b: Let g(x) be a polynomial function. Name all horizontal andvertical intercepts of the graphsg(x) = (x - 1)2 (x + 2)Horizontal intercepts: 1, -2; vertical intercepts: 2Horizontal intercepts: 2, vertical intercepts: 1,-2Horizontal intercepts: -1, 2, vertical intercepts: 4Horizontal intercepts: 4, vertical intercepts: -1,2

Answers

The given function is expressed as

g(x) = (x - 1)^2(x + 1)

It can be written as

y = (x - 1)^2(x + 1)

The horizontal intercept is also known as the x intercept. The x intercept is the value of x when y = 0

If we substitute y = 0 into the function, it becomes

0 = (x - 1)^2(x + 2)

This means that

(x - 1)^2 = 0 and x + 2 = 0

For (x - 1)^2 = 0, if we take the square root of both sides, it becomes

x - 1 = 0

x = 1

For x + 2 = 0,

x = - 2

Thus, the horizontal intercepts are 1 and - 2

The vertical intercept is also known as the y intercept. The y intercept is the value of y when x = 0

If we substitute x = 0 into the function, it becomes

y = (0 - 1)^2(0 + 2)

y = (- 1)^2(2)

y = 1 * 2 = 2

Thus, the vertical intercept is 2

Thus, the correct option is

Horizontal intercepts: 1, -2; vertical intercepts: 2

Part 2: Write limits given outputs.Use the graph of the function to write limit equations given limit values.Use the graph to write a limit equation for f(x) that satisfies each given condition. (2 points for each)a. b. c. d. e. Are there other values than what you chose for x where the limit of the function approaches 4? Is the graph continuous at these points? Explain your reasoning. (4 points)

Answers

a) From the graph, we see that the function takes the value y = 4 when x = 4, so we have:

[tex]\lim _{x\rightarrow4}f(x)=4.[/tex]

b) We see that the curve tends to -∞ when x approaches zero from the left, so we have:

[tex]\lim _{x\rightarrow0^-}f(x)=-\infty.[/tex]

c) We see that curve increases without limit when x tends to infinity, so we have:

[tex]\lim _{x\rightarrow\infty}f(x)=\infty.[/tex]

d) From the graph, we see that the function tends to y = 0 when x approaches zero from the right, so we have:

[tex]\lim _{x\rightarrow0^+}f(x)=0.[/tex]

e) Yes, there are two possible values of x for the limit of the function approaching 4:

• x = 2,

,

• x = 4.

By definition, a function is continuous when its graph is a single unbroken curve.

We see that at the points x = 2 and x = 4 the curve is a single unbroken curve, so we conclude that the function is continuous at those points.

Answers

a, b, c, d

[tex]\begin{gathered} \lim _{x\rightarrow4}f(x)=4 \\ \lim _{x\rightarrow0^-}f(x)=-\infty \\ \lim _{x\rightarrow\infty}f(x)=\infty \\ \lim _{x\rightarrow0^+}f(x)=0 \end{gathered}[/tex]

e. Yes, there are two possible values of x for the limit of the function approaching 4:

• x = 2,

,

• x = 4.

By definition, a function is continuous when its graph is a single unbroken curve.

We see that at the points x = 2 and x = 4 the curve is a single unbroken curve, so we conclude that the function is continuous at those points.

write an equation of a line passing through the point (-6,-3) and perpendicular to JK with J (-2, -7) and K (6,5)

Answers

EXPLANATION

Given the point: (-6,-3) and the vector JK with J=(-2,-7) K=(6,5)

First we need to the slope of the vector applying the slope formula:

[tex]\text{Slope}=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

Replacing the ordered pairs J=(-2,-7) and K=(6,5) give us the slope:

[tex]\text{Slope}=\frac{(5-(-7))}{(6-(-2))}=\frac{12}{8}=\frac{3}{2}[/tex]

Now, we have the slope and we can use this to find the line that contains the point (-6, -3) applying the generic form:

y= -2x/3 + b where -2/3 is the negative and reciprocal slope perpendicular to the vector JK.

Finally, replacing the point (-6,-3) give us the y-intercept, b,

-3 = -2(-6)/3 + b

Multiplying terms:

-3 = 12/3 + b ---> -3 = 4 + b

Subtracting 4 to both sides:

-3 - 4 = b

Switching sides:

b= -7

The linear equation is y = (-2/3)x - 7 OPTION B

What transformations were applied to the toolkit function to create the new function?

Answers

The parent functions is f(x) = 1/x

We have 1/(x+2) -1

The 1/(x+2) is f(x+2) which is a horizontal translation left 2 units

Then we have -1 which is f(x+2) -1 which is a vertical translation down 1 unit

The total transformation is a horizontal translation left 2 units and a vertical translation down 1 unit

Answer: left 2 units down 1 unit

translate and simplify subtract 18 from -11 .enter only the simplified results

Answers

Problem

translate and simplify subtract 18 from -11 .enter only the simplified results ​

Solution

For this case we can do the following:

-11- 18= -29

Final answer: -29

How much money will he raise based on the two donations?

Answers

The neighbor will donate $0.25 for every 40ft run.

The aunt will donate $18 for every mile run.

To determine how much he will raise if he runs 5miles, you have to calculate the amount per donor and then add them:

Neighbor

1 mile is equal to 5280 feet

To determine how many feet correspond to 5 miles, multiply the distance by 5280

[tex]5\cdot5280=26400ft[/tex]

Next, calculate how much we will make:

40ft → $0.25

26400ft → $x

[tex]\begin{gathered} \frac{0.25}{40}=\frac{x}{26400} \\ 26400\cdot\frac{0.25}{40}=26400\cdot\frac{x}{26400} \\ 165=x \end{gathered}[/tex]

For running 5miles, Dustin will raise $165 from the neighbor.

Aunt

The aunt will donate $18 per mile run, to determine how much she will donate, multiply $18 by 5

[tex]18\cdot5=90[/tex]

For running 5 miles, Dustin will raise $90 from the neighbor.

Next, add both amounts:

[tex]165+90=255[/tex]

Dustin will raise $255 for running 5 miles.

use the diagram at the right name the following three points ray

Answers

From the geometric diagram below

(1) Three diagram

[tex]\text{ Points JQE is a 3 points}[/tex]

(2) A ray

[tex]RP\text{ is a ray}[/tex]

(3) Two intersecting lines but not perpendicular

[tex]\text{ line RF and line NI are the two intersecting lines but not perpendicular}[/tex]

what is the difference in a probability that the student will spin a factor of 83 times in a row in the probability that a student will spin a number greater than 63 times in a row

Answers

The number 8 has factors 1, 2, 4 and 8.

The only numbers in the spin greater than 6 are 7 and 8,

The probability that the student will spin a factor of 8 three times in a row is given by: (4/8)*(4/8)*(4/8) = (1/2)*(1/2)*(1/2) = 1/8

The probability that the student will spin a number greater than 6 three times in a row is given by (2/8)*(2/8)*(2/8) = (1/4)*(1/4)*(1/4) = 1/64

Then, the difference between these two probabilities is given by 1/8 - 1/64 = 7/64

The scores at the end of a game are shown.List the scores in order from greatest to least.Scores:Vince:-0.5, Allison: 3/8, Mariah:-7/20

Answers

To arrange the numbers from greatest to least, let us begin by changing all the numbers to decimals.

Vince's Score: -0.5

Allison's Score: 0.375

By long division, we can convert the fraction to a decimal:

Mariah's Score: -0.35

By long division, we have:

Given that we have calculated the scores in decimal, we can clearly see the bigger and smaller numbers.

The order from biggest to smallest is:

Allison: 3/8, Mariah: -7/20, Vince: -0.5

which function will have the greatest value of x equals 80

Answers

In order to solve this, we can replace 80 for x into each one of the three given functions, then we identify what value of y is the greatest, like this:

For the first function:

y = 4x

y = 4×80

y = 320

For the second function:

y = x² - 15x + 88

y = 80² - 15×80 + 88

y= 6400 - 1200 + 88

y = 5288

For the third function:

[tex]\begin{gathered} y=1.1135^{80} \\ y=5435.23 \end{gathered}[/tex]

As you can see, at x = 80 the function that has the greatest value is the third one.

Find the area of each rectangle using the given information.(A=W x H)Question 9:6 and a height of 36 inches.

Answers

The rule of the area of a rectangle is

[tex]A=W\times H[/tex]

W is the width

H is the height

Since the ratio between width and height is 9: 6 and the height is 36 inches, then we will use the ratio method

[tex]\begin{gathered} W\rightarrow H \\ 9\rightarrow6 \\ W\rightarrow36 \end{gathered}[/tex]

By using the cross multiplication

[tex]\begin{gathered} W\times6=9\times36 \\ 6W=324 \end{gathered}[/tex]

Divide both sides by 6

[tex]\begin{gathered} \frac{6W}{6}=\frac{324}{6} \\ W=54 \end{gathered}[/tex]

Then the width of the rectangle is 54 inches

Substitute W by 54 and H by 36 in the rule of the area to find it

[tex]\begin{gathered} A=54\times36 \\ A=1944inches^2 \end{gathered}[/tex]

The area of the rectangle is 1944 square inches

Need help with number five. The question is solve each system

Answers

5)

The given equations are

- 4x - 2y + 3z = 7

- 3x + 5y - 3z = 13

- 5x + y - z = 11

From equation 3, we have

y = 11 + 5x + z

We would substitute y = 11 + 5x + z into equations 1 and 2. For equation 1, we have

- 4x - 2(11 + 5x + z) + 3z = 7

- 4x - 22 - 10x - 2z + 3z = 7

- 4x - 10x - 2z + 3z = 7 + 22

- 14x + z = 29

For equation 2, we have

- 3x + 5(11 + 5x + z) - 3z = 13

- 3x + 55 + 25x + 5z - 3z = 13

- 3x + 25x + 5z - 3z = 13 - 55

22x + 2z = - 42

Dividing both sides of the equation by 2, we have

11x + z = - 21

z = - 21 - 11x

Substituting z = - 21 - 11x into - 14x + z = 29, we have

- 14x - 21 - 11x = 29

- 14x - 11x = 29 + 21

- 25x = 50

x = 50/- 25

x = - 2

z = - 21 - 11(- 2) = - 21 + 22

z = 1

Substituting x = - 2 and z = 1 into y = 11 + 5x + z, we have

y = 11 + 5(-2) + 1

y = 11 - 10 + 1

y = 2

The solutions are

x = - 2, y = 2, z = 1

hi help I've been trying to solve this for an hour and this is due in 10 minutes I just really need the correct answer please help

Answers

We have the following:

We can confirm the intercepts with the y-axis, since it is when x = 0, in the case of the first equation it is 2 and in the second equation it is 1

Therefore, we limit ourselves to the answers C and D, now we can calculate the slope as follows:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The point are (0, 2) and (-6, -1)

[tex]m=\frac{-1-2}{-6-0}=\frac{-3}{-6}=\frac{1}{2}[/tex]

The slope is 1/2, therefore, the equations are

[tex]\begin{gathered} y=\frac{1}{2}x+2 \\ y=\frac{1}{2}x+1 \end{gathered}[/tex]

The answer is the option C

how would I solve the system of equations using elimination?8x - 5y = 114x - 3y =5

Answers

Using elimination. In elimination process the two system of equations are multiplied by a apropiate factor , in order to eliminate one of the variables

then

multiplicate first equation by 4

and multiplicate second equation by 8

once obtained both results, then substract them

So then

4• (8x-5y) = 4•11= 44

8• (4x-3y) = 8•5= 40

32x -20y= 44

32x - 24y= 40

4y= 4 then y=1

now replace y=1 in any of both equations

8x -5= 11. Then x= (11+5)/8= 2

x=2

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