ASGC is also considering adding tennis racquets to the product lines it produces. This would require a $500,000 modification to its factory as well as the purchase of new equipment that costs $1,600,000. The variable cost to produce a tennis racquet would be $55, but John thinks that ASGC could sell the racquet at a wholesale price of $75. John thinks that if ASGC sells the racquet at a lower price, many other retailers might decide to carry it. However, the vice president of ASGC thinks that the tennis racquet is a superior product and that ASGC should sell it for $99.99 to upscale country clubs only. The higher price would give a prestige image. Questions based on the above (10 pts)7. If ASGC produces tennis racquets, how many racquets must it sell at $75.00 and $99.99 to break even? •Breakeven units at 75.00 _______________________________. •Breakeven units at 99.99 _______________________________. •Which price do you recommend and why? __________________________

Answers

Answer 1

Solution

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Related Questions

Use the formula t= ln2 over k that gives the time for a population, with growth rate k, to double, to answer the following questions. The growth model A=6e^0.001t describes the population, A, of a country in millions, t years after 2003. A. What is the country's growth rate? B. (After answering A I will assistance for question B following question A)

Answers

Answer:

A. k = 0.001

B. 693 years

Explanation:

An exponential function has the following form:

[tex]y=a\cdot e^{kt}[/tex]

Where a is the initial value and k is the growth or decay rate.

So, if the equation is:

[tex]A=6e^{0.001t}[/tex]

Therefore, the growth rate is 0.001.

Now, to know how long will it take the country to double its population, we can use the equation:

[tex]t=\frac{\ln 2}{k}[/tex]

Where k is the growth rate. So, replacing k by 0.001, we get:

[tex]\begin{gathered} t=\frac{\ln 2}{0.001} \\ t=693.14\approx693\text{ years} \end{gathered}[/tex]

Therefore, the country will double its population 693 years after 2003

Vectors u = −10i + 3j and v = −3i − 7j. What is u − v?

Answers

In order to calculate the subtraction of the vectors, we can do the following steps:

[tex]\begin{gathered} u-v\\ \\ =(-10i+3j)-(-3i-7j)\\ \\ =-10i+3j+3i+7j\\ \\ =(-10i+3i)+(3j+7j)\\ \\ =-7i+10j \end{gathered}[/tex]

Therefore the correct option is the first one.

5x - 2 + 10 = 20 - 32

Answers

In this case the answers is very simple. .

We must apply algebraic rules to find the solution.

5x - 2 + 10 = 20 - 32

5x = 20 - 32 + 2 - 10

5x = (20 + 2) + (- 32 - 10)

5x = 22 - 42

5x = -20

x = -20 / 5

x = -4

The answers is:

x = -4

Marge makes four payments each year of $175 for her auto insurance. Howmuch must she budget weekly to cover this fixed expense?a. $13.46b. $.84c. $58.33d. $ 700

Answers

Since she makes four payments each year, the total amount she pays in a year is

[tex]\$175\times4=\$700[/tex]

Now there are 52 weeks in a year, divide the total amount of what she pays in a year by the number of weeks in a year.

[tex]\$700\div52=\$13.46[/tex]

Therefore, she must budget weekly $13.46 to cover for this fixed expense.

A boat is heading towards a lighthouse, where Dalvin is watching from a vertical distance of 138 feet above the water. Round your answer to the nearest tenth of a foot if necessary.

Answers

To find the first distance we use:

[tex]\begin{gathered} tan13=\frac{138ft}{x} \\ x=\frac{138ft}{tan13º} \\ x=\frac{138ft}{0.23} \\ x=\text{ 600ft} \end{gathered}[/tex]

For the second distance, we change 13º to 45º and 77º to 45º as well.

So:

[tex]\begin{gathered} tan45=\frac{138ft}{x} \\ 1=\frac{138ft}{x} \\ x=138ft \end{gathered}[/tex]

So the distance from point A to B is=600ft - 138ft = 462ft

A. Show all of your work to solve each equation and to check for extraneous solutions:4. [√(2x^2 - 1)]=x

Answers

ANSWER:

x = 1

STEP-BY-STEP EXPLANATION:

We have the following equation:

[tex]\sqrt{2x^2-1}=x[/tex]

We solve for x:

[tex]\begin{gathered} 2x^2-1=x^2 \\ \\ 2x^2-x^2=1 \\ \\ x^2=1 \\ \\ x=\sqrt{1}=\pm1 \\ \\ \text{ we check:} \\ x=1 \\ \\ \sqrt{2\left(1\right)^2-1}=1 \\ \\ \sqrt{2-1}=1 \\ \\ 1=1 \\ \\ x=-1\rightarrow\text{ true} \\ \\ \sqrt{2\left(-1\right)^2-1}=-1 \\ \\ \sqrt{2^-1}=-1 \\ \\ 1=-1\rightarrow\text{ false} \end{gathered}[/tex]

Therefore, the solution of the equation is x = 1

How many routes does this function have Y= -2x^2+12x-10

Answers

We have that the equation is equal to

[tex]-2(x-1)(x-5)[/tex]

So the equation have two roots, x = 1 and x = 5.

If Erica teaches 15 fewerthan twice as many as Bo, how many classes does each instructor teach per week?

Answers

STEP - BY - STEP EXPLANATION

What to find?

The number each instructor teach per week.

Given:

Total number they teach per week =39

let e = number of classes Erica teaches per week and b = the number of classes Bo teaches per week.

e =2b - 15

Step 1

Form the linear equation.

[tex]b+e=39[/tex]

Step 2

Substitute e=2b-15 into the above.

[tex]b+2b-15=39[/tex]

Step 3

Collect like term.

[tex]b+2b=39+15[/tex][tex]3b=54[/tex]

Step 4

Divide both-side of the equation by 3.

[tex]\frac{3b}{3}=\frac{54}{3}[/tex][tex]b=18[/tex]

Step 5

Determine Erica's age.

[tex]\begin{gathered} b+e=39 \\ \\ e=39-b \\ \\ e=39-18 \\ \\ e=21 \end{gathered}[/tex]

ANSWER

c. 18 Bo; 21 Erica

in the figure below, points D, E, and F are the midpoints of sides ABC. suppose AC =58, DF =26, and AB =38. find the following lengths. DE, BC, and CE

Answers

The values of the lengths DE, BC, and CE are 29, 52, and 26 respectively which can be found out by using the relations for mid-points of triangle.

In the figure, it is given to us that -

Points D, E, and F are the midpoints of sides AB, BC, and AC of the ΔABC respectively.

AC = 58

DF = 26

and, AB = 38

We have to find out the values of the lengths DE, BC, and CE.

Now, AC = 58 is parallel to the mid-segment DE

=> The mid-segment DE is half of the AC.

=> DE = AC/2

=> DE = 58/2

=> DE = 29

Similarly, the mid-segment DF = 26 is parallel to BC

=> BC = Twice the mid-segment DF

=> BC = 2*26

=> BC = 52

Now, E is the midpoint of BC of the ΔABC.

=> CE = BC/2

=> CE = 52/2

=> CE = 26

Through the formulas for mid-points of triangle, we find out that the values of the lengths DE, BC, and CE are 29, 52, and 26 respectively.

To learn more about mid-points of triangle visit https://brainly.com/question/4657453

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Point P(4,-2) undergoes a translation given by (x, y) - (x+3, x-a) , followed by another translation (x, y) - (x-b, x+7) to produce the image of P”(-5,-8). Find the values of a and b and point P’.

Answers

Assuming x - a = y - a and x + 7 = y + 7

Original Point P (4, -2)

Translated to Point P' (x + 3, y - a) = (4 + 3, -2 - a) = (7, -2 - a)

Translated to next point P'' = (x - b, y + 7) = (7 - b, -2 - a + 7) = (7 - b, 5 - a) = (-5, 8)

From the above changes, we can see that 7 - b = -5 and 5 - a = 8. Therefore:

[tex]\begin{gathered} 7-b=-5 \\ 7+5=b \\ 12=b \end{gathered}[/tex][tex]\begin{gathered} 5-a=8 \\ 5-8=a \\ -3=a \end{gathered}[/tex]

The value of a = -3 and b = 12.

The point P' (7, -2 - a) = (7, -2 - (-3)) = (7, 1). Point P' is at (7, 1).

To check if this is right, let's look at the original point again and its transformations.

P (4, -2) translated to (x + 3, y - a) = (4 + 3, -2 - (-3)) = (7, 1).

P' (7, 1) is then translated to ( x - b, y + 7) = (7 - 12, 1 + 7) = (-5, 8).

As mentioned in the question, P'' is indeed found at (-5, 8).

refer to the figure to complete thus proportion. c/a = a/?

Answers

[tex]\frac{c}{a}\text{ = }\frac{a}{r}[/tex]

Here, we want to compare triangles and such write the equivalent ratio on both

Mathematically, if two triangles are similar, the ratio of their sides are fixed

In the triangle consisting of c and a, we can see that c is the hypotenuse( the side facing the right-angle) while a represents the base

Now, in the triangle where we have a as the hypotenuse, we can see that the measure r reresents the base of the triangle

Thus, we can complete the proportion as;

[tex]\frac{c}{a}\text{ = }\frac{a}{r}[/tex]

A community service group spent Planet summer planting trees in City park the table shows the total of number of trees after a certain number of weeks how many trees were already planted in the park before the community group started to plant?

Answers

If we consider the number of weeks equals 0 as the moment where the group started to plant, we can notice that at this point there were already 16 trees, then the answer is 16 trees

The length of a rectangle is 4 in longer than its width. If the perimeter of the rectangle is 362 in, find it's area.

Answers

The length of a rectangle is 4 in longer than its width, which means

Length = 4 in + width

P = 362 in = 2L + 2W

362in = 2(4 in + W) + 2W = 8in+2W+2W = 8in + 4W

362in = 8in + 4W

Solve for W

362 in - 8in = 4W

354 = 4W

354/4 = W

88.5 = W

Replace W in the Length

Length = 4 in + W

Length = 4 in + 88.5in

Length = 92.5in

The formula for the area is A = Length * Width = L * W

Replace the values and find the area

A = L* W

A = 92.5in * 88.5in

A = 8186.25 in²

On a set of architectural drawings for a new school building the scale is 1/4 inch = 2 feet. Find the missing lengths of the rooms.

Answers

We have a scale for the drawing that is 1/4 inch = 2 feet.

This means that 1/4 inch in the drawing represent 2 feet in the real world.

1. Lobby.

The actual length is 16 feet.

If 2 feet are drawn in 1/4 inch (0.25), the drawing length is 2 inches

[tex]\frac{16*0.25}{2}=\frac{4}{2}=2[/tex]

2. Principal's office

The drawing length is 1.25 inches.

We can calculate the actual length as:

[tex]1.25\cdot\frac{2}{0.25}=\frac{2.50}{0.25}=10[/tex]

3. Library

The actual length is 20 feet.

We have discovered that we can transform this in drawing units (inches) multypling by 0.25/2=0.125.

[tex]20\cdot0.125=2.5[/tex]

The drawing length is 2.5 inches.

4. School room

The drawing length is 3 inches.

We have discovered that we can transform this in actual length units by dividing by 0.125, or multiplying by 2/0.25=8:

[tex]3\cdot8=24[/tex]

The actual length is 24 feet.

5. Science lab.

In the drawing has 1.5 inches, so we multiply by 8 and we get 1.5*8=12 feet.

The actual length is 12 feet.

6. Cafeteria

The actual length is 48 feet.

Then, the drawing length is 48*0.125=48/8=6 inches.

7. Music room

The drawing length is 4 inches.

Then, the actual length is 4*8=32 feet.

8. Gymnasium

The drawing length is 13 inches, so the actual length is 13*8=104 feet.

9. Auditorium

The actual length is 56 feet, so the drawing length is 56/8=7 inches.

10. Teachers lounge

The drawing length is 1.75 inches, so the actual length is 1.75*8=14 feet.

We can calculate the scale factor drawing to actual length as:

[tex]\frac{\text{drawing}}{\text{actual}}=\frac{\frac{1}{4}in}{2\text{ feet}}=\frac{1}{8}\cdot\frac{in}{\text{ feet}}\cdot\frac{1\text{ feet}}{12\text{ in}}=\frac{1}{96}[/tex]

The scale is 1:96.

12) If the scale is 12 inches = 1 foot, the scale factor is:

[tex]\frac{\text{drawing length}}{\text{actual length}}=\frac{12\text{ in}}{1\text{ ft}}\cdot\frac{1\text{ ft}}{12\text{ in}}=1[/tex]

The scale in this case is 1:1 (the drawing has the same size as the actual object).

14) We have a road which length is 30 cm.

The scale is 1 cm = 3.5 m.

We can calculate the actual length of the road as:

[tex]\text{Actual length}=30cm\cdot\frac{3.5\text{ m}}{1\text{ cm}}=105\text{ m}[/tex]

The actual legth of the road is 105 meters.

Find the distance between the points (-5,4) and (-2,-1)

Answers

Answer

√34

Step-by-step explanation

Distance formula

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

where

• d: distance between two points

,

• (x₁, y₁): coordinates of the first point

,

• (x₂, y₂): coordinates of the second point

Substituting into the formula with the points (-5,4) and (-2,-1), we get:

[tex]\begin{gathered} d=\sqrt{(-2-(-5))^2+(-1-4)^2} \\ d=\sqrt{3^2+(-5)^2} \\ d=\sqrt{9+25} \\ d=\sqrt{34} \end{gathered}[/tex]

find the slope of the line passing through the points (-6,4) and (2,4)

Answers

To find the slope, we will use the formula below:

[tex]\text{slope =}\frac{y_2-y_1}{x_2-x_1}[/tex]

x₁= -6 y₁=4 x₂=2 y₂=4

substitute the values into the formula

[tex]\text{slope =}\frac{4-4}{2+6}[/tex]

[tex]\text{slope}=\frac{0}{8}[/tex][tex]\text{slope = 0}[/tex]

A baseball player went up to bat 500 times in a season. He hit the ball 150 times. Find the rate of balls hit to times at bat. Express as a ratio.

Answers

To find the answer, we just divide

[tex]\frac{150}{500}=0.30[/tex]

As ratio would be

[tex]\frac{150}{500}=\frac{15}{50}=\frac{3}{10}[/tex]Hence, his rate is 3/10, three hits every 10 attempts.

While hiking manuel descended 400 meters if manuel started at 1000 meters above sea level which integer represents his elevation now

Answers

Let me explain this with the following drawing:

If Manuel started at 1000 meters above sea level and he descended 400 meters, his elevation after this, is 600m above sea level.

So the integer that represents his elevation now is 600.

A group of people were asked "What time do you prefer to see a movie? The two way tablebelow represents the results by their age.Morning 4 2 12 25 4316-20 21-25 26-30 Over 30 TotalsAfternoon 8 12 18 32 70EveningTotals28 34 28 11 101Late Night 34 18 21 4 7774 66 79 72 291What the approximate probability that a person will be over 30 given they prefer afternoonmovies?

Answers

From theinformation given,

total number of people = 291

Number of persons over 30 that prefer afternoon movies = 32

Number of persons that prefer afternoon movies = 70

This is a conditional probability.

Recall, Probability of event A given event B = P(A and B)/P(B)

Thus,

Probability that a person will be over 30 given that they prefer afternoon movies = 32/70

By multiplying by 100, it becomes

32/70 x 100

= 46%

Probability that a person will be over 30 given that they prefer afternoon movies = 46%

Last year. Kareem deposited into an account that paid 4% interest per year and $6000 into an account that paid 9% interest per year. No with withdrawals were made from either account. No rounding needed What was the total interest earned at the end of 1 year? What was the percent interest for the total deposited?

Answers

[tex]\begin{gathered} \text{Account 1} \\ \text{\$2000} \\ \text{4\%=0.04} \\ Interest=(\text{\$2000})(\text{0.04}) \\ Interest=\text{\$}80 \\ \text{Account 2} \\ \text{\$6000} \\ 9\text{\%=0.09} \\ Interest=(\text{\$6000})(\text{0.09}) \\ Interest=\text{\$}540 \\ \text{Total interest=\$80+\$540}=\text{\$620} \\ \text{Total interest is \$620} \\ \text{Question b)} \\ \text{Total interest=\$620} \\ \text{Total deposited=\$2000}+\text{\$6000}=\text{\$8000} \\ \text{percent =}\frac{\text{\$620}}{\text{\$8000}}\cdot100 \\ \text{percent =}7.75\text{ \%} \\ \text{The percent interest for the total deposited is }7.75\text{ \%} \end{gathered}[/tex]

What is the positon of the letter E on the number line and how can i write it as a fraction or mixed number

Answers

We are asked to identify the position of the letter E on the number line.

First of all, count the total number of spacings between 2 and 3.

There are a total of 7 spacings.

The letter E is at the 6th spacing.

So, we can write the position of the letter E in the mixed form as

[tex]2\frac{6}{7}[/tex]

We can also re-write the above mixed number as a fraction

[tex]2\frac{6}{7}=\frac{2\times7+6}{7}=\frac{14+6}{7}=\frac{20}{7}[/tex]

So, the position of the letter E on the number line as a fraction is 20/7

What graph is the function of the table shown ?

Answers

Answer:

Explanation:

The table contains corresponding values of x and y

We would look at the points in the graph that contains these corresponding values of x and y. Looking at the graphs,

Karina purchased 5 yard a fabric costing $7.99/yard, two spools of thread at $1.25/spool and a pattern costing $5.25 . what was the total amount of her purchase before tax?

Answers

Given:

She purchased:

5 yard of fabric at $7.99/yard

2 spools of thread at $1.25/spool

1 pattern at $5.25

We can calculate the total amount of her purchase before tax by summing the cost of each item without tax.

The total amount:

[tex]\text{Total amount = cost of yard }\times\text{ number of yards purchased + cost of thread }\times\text{ number of spools + cost of pattern }\times Number\text{ of pattern}[/tex]

Substituting we have:

[tex]\begin{gathered} \text{Total amount = 7.99}\times\text{ 5 + 1.25}\times2\text{ + 5.25 }\times\text{ 1} \\ =47.7 \end{gathered}[/tex]

Hence, the total amount of her purchase before tax is $47.7

Answer: $47.7

The graph of function fis shown.YA-10X-5g(x)ENTEENENEN-10-2-325(0,-2)-5Function g is represented by the table.-10(2,8)-1-16BUDETETIEREDIVITETITENTENTENDEUREN MEDIOEMED MERDENDENDIENTEDETETTETTEN VEDIMENMEDITED RENDUER TRENINEEEEE5ENITEDIOUS0-8101-42-2

Answers

For function f:

According to the graph in the interval [0,2] the function is increasing.

Rate: 8 - 0 = 8

For function g:

According to the table g function is increasing.

Rate: -2 - ( -8) = -2 + 8 = 6

Answer: C. both functions are increasing but f is increasing faster

A tailor cut 1/2 inch off a skirt and 1/6 inch off a pair of pants. which garment had the greater amount cut off

Answers

The garment that had the greater amount cut off is the skirt

Explanation:

Amount cut off from skirt = 1/2

Amount cut off from pants = 1/6

To determine the grament witht he greater cut, we need to find the LCM of the fractions

[tex]\text{LCM of the denominator, 2 and 6 = 12}[/tex][tex]\begin{gathered} \frac{1}{2},\frac{1}{6}=\frac{6(1),2(1)}{12}=\frac{6,\text{ 2}}{12} \\ \text{the fraction with higher number of numerator had the greater amount cut off} \end{gathered}[/tex]

The fractor with higher number in the numerator = 1/2 has it has 6 has the numerator

In other words, 1/2 > 1/6

The garment that had the greater amount cut off is the skirt

Roseanna, Kennedy and Guadalupe had a super mean Math teacher who made them come up with a probability game where the chances of winning was 1/7. Roseanna’s idea was to have 5 red blocks and 30 blue blocks all in a bag. Each player gets one chance to pull out a block and if they pull out a red one they win Kennedy’s idea was the same as Roseanna’s except to have 1 red block and 7 blue blocks.Guadalupe’s idea was to have a seven sided die with a number 1 through 7 on each side. Each player rolls the die once and wins if they get a 3Whose game has a 1/7 chance of winning? Whose game doesn’t? For each game that doesn’t, show one way to change it so that it does have a 1/7 chance.

Answers

We are asked to determine which games have a 1/7 chance of winning. -

In the case of Roseanna's game, we have that there are 5 red blocks and 30 blues blocks. If the winner is the person that pulls out a red block then to determine the probability we must determine the quotient between the number of red blocks and the total number of blocks, like this:

[tex]P(red)=\frac{5}{5+30}[/tex]

Solving the operations:

[tex]P(red)=\frac{5}{35}=\frac{1}{7}[/tex]

Therefore, Roseanna's game has a 1/7 probability.

In the case of Kennedy's game, there are 1 red block and 7 blue blocks, therefore, the probability of getting a red block is:

[tex]P(red)=\frac{1}{7+1}=\frac{1}{8}[/tex]

Therefore, Kennedy's game has not a chance of 1/7 but 1/8 of winning.

For Kennedy's game to have a probability of 1/7 he could remove one of the blue blocks, that way the probability is:

[tex]P(red)=\frac{1}{6+1}=\frac{1}{7}[/tex]

In the case of Guadalupe's game, we have that there is a dice with 7 sides numbered from 1 to 7. This means that the probability of getting a 3 is:

[tex]P(3)=\frac{1}{7}[/tex]

Therefore, Guadalupe's game has a probability of 1/7.

1. Which of the following is the value of -13 - 51 – 3? (A) -5 (B) -1 (C) 0 (D) 1 M

Answers

The value of -|3-5|-3 is,

[tex]\begin{gathered} -|3-5|-3=-|-2|-3 \\ =-2-3 \\ =-5 \end{gathered}[/tex]

Hence, Option A is right.

question is in image

Answers

r-value being 0.9874, shows that the goodness of fit of the equation is close to 1. This implies that y = 65.18x + 21.43 properly approximates the data.

substitute 32 for x in the equation.

y = 65.18(32) + 21.43

y = 2107.19

Thus, the correct answer is $2107.19 (option A)

Could you please help me out with this question ??

Answers

Answer:[tex](x+1)(x-1)(x-2)[/tex]

Explanations:

Given the polynomial function:

[tex]x^3-2x^2-x+2[/tex]

Group the functions:

[tex](x^3-2x^2)-(x-2)[/tex]

Factor out the greatest common factor from the parenthesis

[tex]\begin{gathered} x^2(x-2)-1(x-2) \\ (x^2-1)(x-2) \end{gathered}[/tex]

Simplify fully to have:

[tex]\begin{gathered} (x^2-1)(x-2) \\ \lbrack(x^2-1^2)\rbrack(x-2) \\ (x+1)(x-1)(x-2) \end{gathered}[/tex]

This gives the factored form of the given polynomial.

A dilation by a scale factor od 2 centered at (2,-1) is performed on the triangle shown draw the resulting triange

Answers

Explanation:

The vertices of the triangle are:

• (2, -1)

,

• (-3, -1)

,

• (1,2)

The triangle is dilated by a scale factor of 2 with the center of dilation at (2, -1).

The coordinates of the image triangle are (-2,1), (0,5) and (-8, -1).

Answer:

The triangle and its image are attached below:

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