Answers
the floor exerts a force of 600 N on her
Explanation
Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction,in this case the wowan exerts a force on the floor, it is her weigth, in the other hand, the floor exerts a force on the woman,this is called Normal force, the normal force is the force that surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force.
Step 1
a) diagram:
as the woman is at equilibrium , the sum of the forces acting on it equals, zero, hence
[tex]\begin{gathered} Normal\text{ force-weigth= 0} \\ Normal\text{ force = weigth} \\ Normal\text{ force=600 N} \end{gathered}[/tex]therefore, the floor exerts a force of 600 N on her
so, the answer is
d) 600 N
I hope this helps you
Related Questions
A miniature quadcopter is located at xi = 1.50 m and yi = 4.70 m at t = 0 and moves with an average velocity having components vav, x = 2.70 m/s and vav, y = −2.50 m/s. What are the x-coordinate and y-coordinate (in m) of the quadcopter's position at t = 3.10 s?
Answers
Answer:
xf = 9.87 m and yf = -3.05 m
Explanation:
The x and y coordinated can be calculated using the following equation
xf = xi + Vav,x(t)
yf = yi + Vav,y(t)
Where xi, yi are the initial positions, Vav,x and Vav,y are the averages velocities and t is the time.
Replacing the given values, we get that the equations are
xf = 1.50 + 2.70t
yf = 4.70 - 2.50t
Now, we can calculate the position at t = 3.10s, replacing t by 3.10, so
xf = 1.50 + 2.70(3.10)
xf = 1.50 + 8.37
xf = 9.87 m
yf = 4.70 - 2.50(3.10)
yf = 4.70 - 7.75
yf = -3.05 m
Therefore, the x-coordinate and y-coordinate are xf = 9.87 m and yf = -3.05 m
Finding the coefficient of friction,I need how I would find the friction coefficient
Answers
the coefficient is 0.267
ExplanationFree-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object
Step 1
so, to graph the forces we use the Cartessian plane
let the x-axis paralle to the inclided plane
therefore,the weigth is a force acting directly to the center of the earth , ( bottomof page), so we have to find the x and y components of the weitgh
hence
the Free body diagram would be
Step 2
how to find the friction coefficient
the force of friction (ff) is given by
[tex]\begin{gathered} ff=\mu *N \\ where\text{ }\mu\text{ is the coefficient } \\ Nis\text{ the normal force} \end{gathered}[/tex]so, to find the coefficient we need the Normal force
if we do the sum of forces in y -axis equal zero
[tex]\begin{gathered} N-wcos(15)=0 \\ N=wcos(15) \end{gathered}[/tex]now, x -axis
[tex]\begin{gathered} ff-wsin(15)=0 \\ ff=wsin(15) \end{gathered}[/tex]finally, replace and solve for the coefficient
[tex]\begin{gathered} ff=\mu N \\ w*sin(15)=\mu *wcos(15) \\ divide\text{ both sides by w cos\lparen15\rparen} \\ \frac{wsin(15)}{wcos(15)}=\frac{\mu *w*cos(15)}{wcos(15)} \\ \frac{sin(15)}{cos(15)}=\mu \\ tan(15)=\mu \\ 0.267=\mu \end{gathered}[/tex]therefore, the coefficient is 0.267
I hope this helps you
What is the term for an object that does not allow any light to pas through it? opaque, transparent, or translucent
Answers
Answer:
Opaque
Explanation:
Opaque objects are objects that doesn't allow the light to pass through them
Transparent objects are objects that allow almost all light to pass through them
Translucent object are objects that allow some light to pass through them
Then, the answer is opaque.
Answer:
I think opaque im not sure
Explanation:
While Dexter is on a camping trip with his boy scout troop, the scout leaderhands each boy a compass and map. The directions on Dexter's map read asfollows: "Walk 500.0 m north, 200.0 m east, 300.0 m south, and 400.0 m west."If he follows the map, what is Dexter's displacement? Solve graphically.
Answers
To solve this problem graphically we need perform the following steps:
Draw the axis and labeled them correctly.
We choose an appropriate scale to represent one meter, for example we can choose 1 cm to represent 50 meters; in that way 500 m will be represented by an arrow with length 10 cm.
We draw an arrow pointing north of 10 cm.
We draw an arrow pointing east of 4 cm from the head of the previous arrow.
We draw an arrow pointing south of 6 cm from the head of the previous arrow.
We draw an arrow pointing west of 8 cm from the head of the previous arrow.
We draw an arrow from the origin to the head of the last arrow.
We measure the horizontal projection of the last arrow and the vertical projection, this will give us the displacement in the x and y direction, respectively.
This is shown in the diagram below:
Therefore, the displacement of Dexter from the origin is -200 m on x and 200 m on y, this can be also said as Dexter is 200 m west and 200 m north from where he began.
(i) Discuss your understanding about symmetric and non-symmetric projectile motion, give
some examples. (ii) Discuss your understanding about uniform and non-uniform circular
motions; give some examples.
Answers
In a symmetric projectile motion, the trajectory is symmetrical. In a non-symmetric projectile motion, the projectile path will not be symmetrical.
An example of symmetrical projectile motion is a ball launched with an initial velocity which lands at the same height from which it was launched. An example of non-symmetrical projectile motion is a ball launched with an initial velocity which lands at a different height from which it was launched.
In an uniform circular motion, an object moves with constant speed. So its angular and tangential acceleration becomes zero. But due to its change in direction, its centripetal acceleration has a non zero value. In a non-uniform circular motion, the object does not move with constant speed.
Therefore, in a symmetric projectile motion, the trajectory is symmetrical. In a non-symmetric projectile motion, the projectile path will not be symmetrical.
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I take my calculator from the top of a building and toss it straight upward at 9 m/s from a 23 m tall building.A. what is the speed of the Calculator right before it hits the ground? B. What is the acceleration of the calculator at peak height? C. How much time does it take for the calculator to reach peak height?
Answers
Given,
The initial velocity with which the calculator was thrown, u=9 m/s
The height of the building, h=23 m
A.
When the calculator reaches the peak height, its velocity will become zero. That is v=0 m/s
And while it is going up the acceleration due to gravity will be acting downward. Thus the acceleration due to gravity will be a negative value.
From the equation of motion,
[tex]v^2-u^2=2gs_{}[/tex]Where s is the peak height reached by the calculator and g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} 0-9^2=2\times-9.8\times s \\ \Rightarrow s=\frac{-9^2}{2\times-9.8} \\ =4.13\text{ m} \end{gathered}[/tex]Thus the total height reached by the calculator from the ground is
[tex]\begin{gathered} H=h+s \\ =23+4.13 \\ =27.13 \end{gathered}[/tex]After reaching the peak height, the calculator starts descending. This descent starts with the initial velocity of v=0 m/s. And the acceleration due to gravity will be in the direction of motion of the calculator. Thus it will be a positive value.
From the equation of motion,
[tex]v^2_0-v^2=2gH[/tex]where v₀ is the velocity of the calculator right before it hits the ground.
On substituting the known values,
[tex]\begin{gathered} v^2_0-0=2\times9.8\times27.13 \\ \Rightarrow v_0=\sqrt[]{2\times9.8\times27.13}^{} \\ =23.06\text{ m/s} \end{gathered}[/tex]Thus the speed of the calculator right before it hits the ground is 23.06 m/s
B.
The acceleration of the calculator is a constant value. It is always equal to the acceleration due to gravity.
Thus the acceleration of the calculator at peak height is 9.8 m/s²
C.
From the equation of motion,
[tex]v=u+gt[/tex]Where t is the time it takes for the calculator to reach the peak height.
On substituting the known values,
[tex]\begin{gathered} 0=9+(-9.8)t \\ \Rightarrow t=\frac{-9}{-9.8} \\ =0.92\text{ s} \end{gathered}[/tex]Thus it takes 0.92 s for the calculator to reach the peak height.
I want to know how to answer this and I'm having difficulties telling what type of force is acting on an object.
Answers
A worker pushes a crate with a horizontal force of 225 N a distance of 8.0 M. How much work did the worker do on the crate?11,200 J1,800 J3,920 J0 J
Answers
We area asked to determine the work done by pushing a crate a distance of 8 meters using a force of 225N. To do that we will use the following formula:
[tex]W=Fd[/tex]Where:
[tex]\begin{gathered} W=\text{ work} \\ F=\text{ horizontal force} \\ d=\text{ distance} \end{gathered}[/tex]Now, we plug in the values:
[tex]W=(225N)(8m)[/tex]Now, we solve the operations:
[tex]W=1800J[/tex]Therefore, the amount of work done is 1800 Joules.
Study the following statements regarding energy and the Law of Energy Conservation: 1. The Law of Energy Conservation means it is saved for another time often for environmental reasons. 2. The Law of Energy Conservation means that there is the same amount of energy before the transfer took place as after 3. When energy is dissipated it means that it disappears. 4. When energy is dissipated it means some of the energy is converted into less useful forms. Which two of the above statements are true?
Answers
Answer:
2. The Law of Energy Conservation means that there is the same amount of energy before the transfer took place as after
4. When energy is dissipated it means some of the energy is converted into less useful forms.
Explanation:
Conservation means that energy is conserved through the transfer. It is equal at the start and at the end.
Energy cannot be created or destroyed, so it doesn't disappear, it changes (converted)
Concave lenses havefocal lengths and always formimages.A. negative; virtualOB. positive; virtualC. positive; realD. negative; realSUBMIT
Answers
We will have that concave lenses have negative focal lengths and always form a virtual image.
[Option A]
A white crowned sparrow flying horizontally with a speed of 1.80m/s folds its wings and begins to drop in free fall. (a) How far does the sparrow fall after traveling a horizontal distance of 0.500m? (b) If the sparrows initial speed is increased, does the distance of fall increase, decrease or stay the same?
Answers
First, find the time that it takes for the sparrow to travel 0.500m at a speed of 1.80 m/s. Since speed is the ratio between distance and the time taken to travel that distance, then:
[tex]v=\frac{d}{t}[/tex]Isolate t from the equation:
[tex]\Rightarrow t=\frac{d}{v}[/tex]Replace d=0.500m and v=1.80 m/s to find the time:
[tex]t=\frac{0.500m}{1.80\frac{m}{s}}=0.2777\ldots s[/tex]During that time, the sparrow falls vertically according to the equation:
[tex]h=\frac{1}{2}gt^2[/tex]Where g is the gravitational acceleration on Earth:
[tex]g=9.81\frac{m}{s^2}[/tex]Replace the value of g and t=0.2777...s to find how far does the sparrow fall:
[tex]h=\frac{1}{2}(9.81\frac{m}{s^2})(0.2777\ldots s)^2=0.378472\ldots m[/tex]If the initial speed is increased, it will take less time to travel 0.500m, and then, the falling time will be decreased, and so the distance of fall would decrease. However, the horizontal speed does not affect the distance of fall if the fall time is the same (but the horizontal displacement would increase).
Therefore, the answers are:
a) The sparrow falls a distance of 0.378m
b) The distance of fall would decrease since it would take less time to travel 0.500m.
A grinding wheel 0.37 m in diameter rotates at 2400 rpm.(A) Calculate its angular velocity in rad/s.(B) What is the linear speed of a point on the edge of the grinding wheel? (C) What is the acceleration of a point on the edge of the grinding wheel?
Answers
A) Angular velocity = 251.36 rad/s
B) Linear speed = 46.50 m/s
C) Acceleration = 11687.8 m/s^2
Explanations:A) Angular velocity, w = 2400 rpm
Note that:
1 rpm = (2π)/60
Therefore:
2400 rpm = (2π/60) x 2400 rad/s
2400 rpm = 80π rad/s
2400 rpm = 80 x 3.142
2400 rpm = 251.36 rad/s
The angular velocity, w = 251.36 rad/s
B) The relationship between linear speed(v) and angular velocity(w) is:
v = wr
The diameter, d = 0.37m
Radius, r = d/2
r = 0.37/2
r = 0.185m
Substituting r = 0.185m and w = 251.36 rad/s into v = wr:
v = 251.36 x 0.185
v = 46.50 m/s
C) The acceleration a point on the edge of the grinding wheel is the centripetal acceleration, and is given by the formula:
[tex]\begin{gathered} a\text{ = }\frac{v^2}{r} \\ a\text{ = }\frac{46.50^2}{0.185} \\ a\text{ = }\frac{2162.25}{0.185} \\ a\text{ = }11687.8m/s^2 \end{gathered}[/tex]Two long, parallel wires separated by 0.496 m carry equal currents of 11.062 A in the same direction. Find the magnitude of the net magnetic field 0.703 m away from each wire on the side opposite the other wire . Express your answer in microTesla.
Answers
In order to solve this exercise, let us first recap about point and cross notation. They are used to indicate vectors which are entering and leaving the screen. They are as follows:
You can think of it as an arrow. When the arrow is going away from us, we see the end of it, which is a cross. However, when it is coming in our direction, we see its tip, which is a point.
Now, starting into the problem, we can draw it as the following:
This happens as each wire with a flowing current generates a magnetic field that spins around it, as you can see in this drawing:
Now, we want to calculate the resulting magnetic field in the following point:
So, we can calculate our resulting magnetic field as:
[tex]B=\frac{\mu_0i}{2\pi}(\frac{1}{r_1}+\frac{1}{r_2})[/tex]Which, replacing the values, gives us:
[tex]B=\frac{\mu_0*11.062}{2\pi}*(\frac{1}{0.703}+\frac{1}{0.703+0.496})=4.99\mu T[/tex]Then, our final answer is B=4.99uT
Derive Kinetic Energy and Potential Energy.
Answers
Answer:
[tex]\begin{gathered} \Delta K=\frac{1}{2}m(v_f)^2-\frac{1}{2}m(v_i)^2 \\ P=m\cdot g\cdot h \end{gathered}[/tex]Explanation: We need to derive the formula for both Kinetic energy and potential energy, the derivation of these formulas is as follows:
(i) Kinetic energy:
[tex]\begin{gathered} \Delta K=\Delta W=F\cdot\Delta d\cdot\cos (\theta) \\ \theta=0 \\ \therefore\Rightarrow \\ \Delta K=F\cdot\Delta d\Rightarrow(1) \end{gathered}[/tex]By using the Kinematic equations of motions, equation (1) can be changed to the kinetic energy formula as follows:
[tex]\begin{gathered} (1)\Rightarrow\Delta K=F\cdot\Delta d=m\cdot a\cdot\Delta d\Rightarrow(2) \\ (v_f)^2=(v_i)^2+2a\Delta d \\ \therefore\Rightarrow \\ a\Delta d=\frac{(v_f)^2-(v_i)^2}{2} \\ \text{ Substituting above in the }(2)\text{ gives the formula:} \\ \Delta K=m\cdot\frac{(v_f)^2-(v_i)^2}{2} \\ \Delta K=\frac{1}{2}m(v_f)^2-\frac{1}{2}m(v_i)^2 \\ \text{ This is the kinetic energy formula} \end{gathered}[/tex](ii) Potential-energy:
Potential energy is basically the work needed to lift an object to a certain height, mathematically, the derivation would be as follows:
[tex]\begin{gathered} \Delta P=\Delta W=F\cdot\Delta d \\ \Delta d=\Delta h \\ \therefore\Rightarrow \\ \Delta P=m\cdot a\cdot\Delta h \\ a=g \\ \therefore\Rightarrow \\ \Delta P=m\cdot g\cdot\Delta h \\ \text{ Simple version:} \\ P=m\cdot g\cdot h \end{gathered}[/tex]A fire is an example of ________________ reaction, because heat is _____________ the system.
A. exothermic; leaving
B. exothermic; entering
C. endothermic; leaving
D. endothermic; entering
Answers
Because heat is being introduced into the system, a fire is just an example of an exothermic reaction.
The right response is B.
What is exothermic example?Any process was considered to be exothermic if it produces heat while also undergoing a net decrease in standard enthalpy change. Examples include any type of combustion, iron rusting, and water freezing. Exothermic processes are those that discharge warmth and energy into the surrounding environment.
What process are exothermic?If heat is released from the system into the environment, the reaction or change is exothermic. The temperature of the environment rises because it is absorbing heat from the system.
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AM radio signals are broadcast at frequencies between 550 kilohertz (kHz) and 1600 kilohertz. FM radio signals are broadcast at frequencies between 88.0 megahertz (MHz) and 108.0 megahertz. a. What is the wavelength of an AM station with a frequency of 790 kilohertz? Include units in your answer.b. What is the wavelength of an FM station with a frequency of 98.7 megahertz? Include units in your answer.
Answers
a)
From the information given,
Lowest frequency = 550 khz = 550 x 10^3 hz
Highest frequency = 1600 khz = 1600 x 10^3 hz
The formula for calculating wavelength is expressed as
wavelength = velocity/frequency
Recall, radio signals travel at the speed of light and speed of light = 3 x 10^8 m/s
Thus, for a frequency of 790 khz which is equal to 790 x 10^3 hz,
the wavelength of the AM station would be
3 x 10^8/790 x 10^3
wavelength of the AM station = 379.75 m
b) From the information given,
Lowest frequency = 88 mhz = 88 x 10^6 hz
Thus, for a frequency of 98.7 mhz = 98.7 x 10^6 hz,
wavelngth of FM station would be
3 x 10^8/98.7 x 10^6
wavelength of the FM station = 3.04 m
A phonograph record has an initial angular speed of 33 rev/min . The record slows to 11 rev/min in 2.0 seconds. What is the records angular acceleration in rad/s2 during this time interval ?
Answers
In order to calculate the angular acceleration, we can use the following formula:
[tex]a=\frac{v_f-v_i}{t}[/tex]Where vf is the final angular speed, vi is the initial angular speed and t is the interval of time.
Since the speed is in rev/min, we need to convert to rad/s.
Knowing that 1 rev = 2π rad and 1 min = 60 s, we have:
[tex]\begin{gathered} 33\text{ rev/min}=33\cdot\frac{2\pi\text{ rad}}{60\text{ s}}=3.456\text{ rad/s} \\ 11\text{ rev/min}=11\cdot\frac{2\pi\text{ rad}}{60\text{ s}}=1.152\text{ rad/s} \end{gathered}[/tex]Now, using vf = 1.152, vi = 3.456 and t = 2, we have:
[tex]a=\frac{1.152-3.456}{2}=\frac{-2.304}{2}=-1.152\text{ rad/s2}[/tex]So the angular acceleration is -1.152 rad/s².
Determine the image distance and image height for a 5.00 cm tall object placed 20.0 cm from a double convex lens with a focal length of 15.0 cm.
Answers
Given:
the height of the object is
[tex]h_0=5\text{ cm}[/tex]The distance of the object is
[tex]d_0=-20\text{ cm}[/tex]The focal length of the lens is
[tex]f=15\text{ cm}[/tex]Required: the distance of the image and height of the image.
Explanation:
the lens formula is given by
[tex]\frac{1}{f}=\frac{1}{d_i}-\frac{1}{d_0}[/tex]Plugging all the values in the above relation, we get:
[tex]\begin{gathered} \frac{1}{15\text{ cm}}=\frac{1}{d_i}-\frac{1}{-20\text{ cm}} \\ \frac{1}{d_i}=\frac{1}{15\text{ cm}}-\frac{1}{20\text{ cm}} \\ \frac{1}{d_i}=\frac{4-3}{60\text{ cm}} \\ d_i=60\text{ cm} \end{gathered}[/tex]Thus, the distance of the image is 60 cm.
now calculate the height of the image
we know that
[tex]\frac{h_i}{h_0}=\frac{d_i}{d_0}[/tex]substitute all the values in the above relation, we get:
[tex]\begin{gathered} h_i=5\text{ cm}\times\frac{60}{-20} \\ h_i=-15\text{ cm} \end{gathered}[/tex]Thus, the height of the image is 15 cm.
which property justifies the statement below? x(y-3)=xy-3xis it associative, transitive, distributive, or communitive
Answers
Given the equation:
x(y - 3) = xy - 3x
Let's identify the property which justifies the statement.
Here, the property which was applied is the distributive property.
The law of distributive property states that multiplying the sum of two or more addends by a given value will amount to the same result as multiplying the addends individually by the number and adding the products.
In this equation, we can see x is distributed into the values in the parentheses.
Therefore, the property that justifies this statement is the distributive property.
ANSWER:
Distributive property
Point A is on the ground, and points B and C are h = 20 meters above the ground. Point B is directly above point A, and point C is L = 40 meters away from point A as shown.(a) How much work must be done by an external agent to move a 2 kg object from rest at point A to rest at point B?(b) How much work must be done to move the same object from rest at point A to rest at point C?
Answers
Given the mass of the object, m = 2 kg
Distance between point A and B, h= 20 m
(a) To find work done in moving the object from A to B
Work done is
[tex]\begin{gathered} W1=Force\times displacement\text{ } \\ =mgh \end{gathered}[/tex]Here, g is the acceleration due to gravity whose value is 9.8 m/s^2.
Substituting the values, we get
[tex]\begin{gathered} W1=2\times9.8\times20 \\ =\text{ 392 J} \end{gathered}[/tex](b) To find work done in moving the object from A to C
Gravitational force is a conservative force and work done depends only on the initial and final position and not on the path.
So, the work done will be
[tex]\begin{gathered} W2=\text{mgh} \\ =2\times9.8\times20 \\ =\text{ 392 J} \end{gathered}[/tex]A pulse travels along a string that is fixed to a wall, as shown. The pulse reaches the wall and is reflected. Which of the following diagrams illustrates the orientation of the reflected pulse?
Answers
Using the concept of Simple Harmonic motion, we got that phase of the string wave changes by 180° and velocity gets reversed.
Simple Harmonic Motion or SHM is defined as motion in which the restoring force is directly proportional to the displacement of the body from its mean position. The direction of this restoring force is always towards a mean position. The acceleration of particle executing simple harmonic motion is given by a(t) = -ω2 x(t). Here, ω is the angular velocity of particle.
A pulse of string wave when travels along a stretched string and reaches the fixed end of the string, then it will be reflected back to the same medium and the reflected ray suffers a phase change of π with the incident wave but the wave's velocity after reflection reverses its direction.
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4. Thunderstorms are caused by warm and cold air colliding and making a large cloud which is positively charged near the top of the cloud, but negatively charged near the bottom of the cloud. (a) What charge is the surface of the ground? Explain how you know. (b) The thunderclouds are 15,000 meters high off the ground and if there’s a tall tree, 70 meters tall, how much voltage does a single lightning bolt containing 6.25 x 1019 electrons have as it strikes the tree?
Answers
let's go,
Generally,
Thunderstorms are caused by warm and cold air colliding and making a large cloud that is positively charged near the top of the cloud but negatively charged near the bottom of the cloud. the charge on the surface of the ground will be positive.
To calculate voltage --- By measuring the length of a lightning strike, multiplying it by the energy per length required.
[tex]\begin{gathered} V=(15000-70)\times(6.25\times10^{19}) \\ \\ V=93,312.5\times10^{19} \\ \\ V=9.33125\times10^{23} \end{gathered}[/tex]A stone is thrown straight upward and reaches a maximum height of 32.1 m above itslaunch point. What was the initial speed with which the stone was thrown upwards?Answer:m/s
Answers
The initial speed = 25.08 m/s
Explanation:The maximum height, H = 32.1 m
The initial speed, u = ?
The acceleration due to gravity, g = 9.8 m/s²
Write out the maximum height formula and solve for u
[tex]H=\frac{u^2}{2g}[/tex]Substitute H = 32.1 and g = 9.8
[tex]\begin{gathered} 32.1=\frac{u^2}{2(9.8)} \\ \\ u^2=32.1(2)(9.81) \\ \\ u^2=629.16 \\ \\ u=\sqrt{629.16} \\ \\ u=25.08\text{ m/s} \end{gathered}[/tex]The initial speed = 25.08 m/s
I
Suppose you have an electrical device that needs a steady current of
10 milliamperes. You need to greatly increase the length of the wire
between the battery pack and the appliance. What changes will you
need to make in your circuit to keep a steady current?
Answers
main answer- by keeping resistance constant,voltage should be increased
supporting answer-For keeping the current constant we must keep the resistance constant so that the current will stay constant
When the length of the conductor is going to be increased then the voltage should also be increased as there is a resistance increase due to the length increase at the conductor because it goes by the formula r is equal to raw l by a where is the resistivity of the conductor and length of the conductor by divided by area of the conductor
To keep the following current constant reverse increase the voltage supply to the circuit
final answer-by keeping resistance constant,voltage should be increased
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You will need to increase the cross-sectional area of the wire in order to keep the current steady.
What is wire?
A wire is a thin, malleable metal strand. The most common way to make wire is to draw the metal through a hole in a draw plate or die. When expressed in terms of a gauge number, wire gauges are available in a variety of common sizes. Mechanical loads are carried by wires, frequently in the form of wire rope. A "wire" can refer to an electrical cable in the context of electricity and telecommunications signals. This type of cable may have a "solid core" made up of a single wire or multiple strands woven together in stranded or braided forms. While wire is often cylindrical in shape, it can also have alternative cross-sections, such as square, hexagonal, flattened rectangular, or other shapes, for both aesthetic and technical uses, such as high-efficiency voice coils in loudspeakers.
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Why are metals the best conductors of electricity? Why are metals the best magnetisers ? What is the key characteristic of metals that allows us to answer these two apparently different questions?
Answers
Question: What is the key characteristic of metals that allows us to answer these two apparently different questions?
Answer:
Explanation:
The atoms of a metal contains at least one free electron. Conduction of electricity is due to the these free electrons.
Magnetism is also affected by the availability of free electrons.
Thus, metals are good conductors of electricity and also the best magnetisers because of the availability of free electrons in metals
You are told that the value of a car of the given model, based on its age, is less than $6000. Give a range of values that could represent the car.
Answers
The following equation represents the value (y) of a car based on its age (x).
[tex]y=-800x+12000[/tex]We are told that the value of a car of the given model, based on its age, is less than $6000.
So, we can write
[tex]6000<-800x+12000[/tex]Let us solve the above inequality for x.
[tex]\begin{gathered} 6000<-800x+12000 \\ 6000-12000<-800x \\ -6000<-800x \\ \frac{-6000}{-800}<\frac{-800x}{-800} \\ 7.5>x \\ x<7.5 \end{gathered}[/tex]This means that the age of the car is less than 7.5 years.
Therefore, the possible range of values that could represent the age of the car is 0 to 7.5 years.
[tex]06) If a system has 48 J of work done on it and absorbs 22 J of heat, what is the value of ΔE for this change?
Answers
ANSWER
ΔE = 70 J
EXPLANATION
Given:
• The work done on the system, W = 48 J
,• The heat absorbed by the system, Q = 22 J
Find:
• The change of energy of the system, ΔE
We will use the convention where:
• Heat transferred to the system: positive (otherwise negative)
,• Work done on the system: positive (otherwise negative)
By the first law of thermodynamics,
[tex]\Delta E=Q+W[/tex]Replace with the known values and solve,
[tex]\Delta E=22J+48J=70J[/tex]Hence, the change in the system's internal energy is 70 J.
Determine the volume in cubic inches (in. ^3) of a 2 liter bottle
Answers
Given
Volume of the bottle, V=2 l
To find
The volume in cubic inch
Explanation
We know,
[tex]\begin{gathered} 1\text{ l=61.024 cubic inch} \\ \Rightarrow2\text{ l=2}\times61.024\text{ cubic inch} \\ =122.048\text{ cubic inch} \end{gathered}[/tex]Conclusion
The required volume is 122.048 cubic inch
A uniform rod of mass m=1.0 kg and length L=2 meters is free to rotate about its center as shown in the figure. A constant torque is applied by a constant force of magnitude F=5.0 N to one end of the rod, as shown. To be clear, the force is always perpendicular to the rod, which rotates about the axis indicated by the red line.a) If the rod is initially at rest, how long does it take to reach an angular velocity omega=30 radians/s. b) Assuming the torque stops when the angular velocity is 30 radians/s, what is the total rotational energy of the rod? c) The rod suddenly turns into a uniform sphere of radius R=1m and mass M=1.0 kg rotating about its center. Assuming angular momentum is conserved, what is the angular velocity of the sphere omegasphere?
Answers
a)
If the length is 2 meters and the rod rotates about its center, so 2 meters is the diameter, and the radius of rotation is 1 meter.
Then, if the force is 5 N, let's calculate the torque:
[tex]\begin{gathered} \tau=F\cdot r \\ \tau=5\cdot1=5\text{ Nm} \end{gathered}[/tex]Then, calculating the rotational inertia and the angular acceleration, we have:
[tex]\begin{gathered} I=\frac{1}{2}mr^2 \\ I=\frac{1}{2}\cdot1\cdot1^2=0.5 \\ \\ \alpha=\frac{\tau}{I}=\frac{5}{0.5}=10 \end{gathered}[/tex]The angular acceleration is 10 rad/s², so to reach an angular velocity of 30 rad/s, it takes 3 seconds.
b)
The rotational energy can be calculated with the formula below:
[tex]\begin{gathered} E_k=\frac{1}{2}I\cdot\omega^2 \\ E_k=\frac{1}{2}\cdot0.5\cdot30^2 \\ E_k=225\text{ J} \end{gathered}[/tex]c)
The angular momentum is given by:
[tex]\begin{gathered} L=I\cdot\omega \\ L=0.5\cdot30 \\ L=15 \end{gathered}[/tex]Then, since the rod turns into a sphere, the new rotational inertia is:
[tex]\begin{gathered} I=\frac{2}{5}mr^2 \\ I=\frac{2}{5}\cdot1\cdot1^2 \\ I=\frac{2}{5}=0.4 \end{gathered}[/tex]So the new angular velocity is:
[tex]\begin{gathered} L=I\cdot\omega \\ 15=0.4\cdot\omega \\ \omega=\frac{15}{0.4}=37.5\text{ rad/s} \end{gathered}[/tex]What is the extension force (in lbf) of a 14 inch diameter cylinder with a 10 inch rod and pressure of 700psi?
Answers
The given problem can be exemplified in the following diagram:
To determine the extension force we will use the definition of pressure:
[tex]P=\frac{F}{A}[/tex]Where "F" is the force, and "A" is the area. To determine the area we will use the following equation:
[tex]A=\frac{\pi D^2}{4}[/tex]Where "D" is the diameter. The force acts over the area of the 10 inches diameter alone, therefore we don't need to have into account the area of the rod. Replacing the value of the diameter we get:
[tex]A=\frac{\pi(14in)^2}{4}[/tex]Solving the operation:
[tex]A=153.94in^2[/tex]Replacing in the formula for the pressure we get:
[tex]P=\frac{F}{153.94in^2}[/tex]Since we are required to determine the force, we will multiply both sides by the area:
[tex]153.94in^2P=F[/tex]Replacing the given value of the pressure we get:
[tex](153.94in^2)(700\frac{lbf_{}}{in^2})=F[/tex]Solving the operations we get:
[tex]107756.62lb_f[/tex]Therefore, the extension force is 107756.62 lbf.