Answers : • center c and scale factor 2• center a and scale factor 5• center c and scale factor 1• center a and scale factor 2

Answers : Center C And Scale Factor 2 Center A And Scale Factor 5 Center C And Scale Factor 1 Center

Answers

Answer 1
Scale factorInitial explanation

In order to find the scale factor of the dilation of ΔABC, we just need to divide any pair of the corresponding sides of both triangles. We have that the division of the corresponding sides will be always the same:

[tex]\frac{A^{\prime}C^{\prime}}{AC}=\frac{B^{\prime}C^{\prime}}{BC}=\frac{A^{\prime}B^{\prime}}{AB}=\text{scale factor}[/tex]

We are going to choose the first division:

[tex]\frac{A^{\prime}C^{\prime}}{AC}=\text{scale factor}[/tex]Finding the scale factor

We have that AC = 5 and A'C' = 10:

Then:

[tex]\begin{gathered} \frac{A^{\prime}C^{\prime}}{AC}=\text{scale factor} \\ \downarrow \\ \frac{10}{5}=2 \end{gathered}[/tex]

The scale factor is 2.

And since the point C and C' are the same, the center is C.

Answer- A. center C and scale factor 2

Answers : Center C And Scale Factor 2 Center A And Scale Factor 5 Center C And Scale Factor 1 Center

Related Questions

Question #10: Given triangle A is the pre image and B is the image, state the scale factor of the dilation from A to B. * 4 B 10 18 А 7.2 15

Answers

To find the acale factor we need to solve the following equation:

[tex]\begin{gathered} 18k=7.2 \\ k=\frac{7.2}{18} \\ k=0.4 \end{gathered}[/tex]

This comes from the fact that the biggest sides of both triangles have to be realted.

Therefore the dilation factor is 0.4.

Two jets leave harrisburg at the same time, one flying east at a speed of 20 km/h greater than the other, which is flying west. After 4 h, the planes are 6000 km apart. Find their speeds. A tourist bus leaves Richmond at 1:90 PM for New York City. Exactly 24 minutes later, a truck sets out in the same direction. The tourist bus moved at a steady 60 km/h. The truck travels at 80 km/h. How long does it take the truck to overtake the tour bus?

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We know that two jets leave Harrisburg at the same, time, one flying east, and another flying west.

We will denote the speed of the second jet by x (in km/h). Thus, the speed of the first jet is x+20. Remembering that:

[tex]v=\frac{d}{t}[/tex]

where v is speed, d is distance and t is time, we know that for the first jet:

[tex]x+20=\frac{d_1}{4}\Rightarrow4x+80=d_1[/tex]

Where d₁ represents the distance of the first jet from the starting point. For the second jet:

[tex]x=\frac{d_2}{4}\Rightarrow4x=d_2[/tex]

Where d₂ represents the distance of the second jet from the starting point.

We also know that:

[tex]d_1+d_2=6000[/tex]

As:

Thus, we have that:

[tex]\begin{gathered} (4x+80)+(4x)=6000 \\ \text{And solving for x, we get:} \\ 8x+80=6000 \\ 8x=5920 \\ x=\frac{5920}{8}=740 \end{gathered}[/tex]

This means that the second jet has a speed of 740km/h, and the first jet has a speed of 760km/h (20km/h greater than the second one).

Which triangle congruence postulate or theorem proves that these triangles are congruent?

Answers

The AAS triangle congruence postulate proves that these triangles are congruent .

In the question,

two triangles are given that are triangle ABC and triangle PQR .

Consider the triangle ABC and triangle PQR .

we can see that

(i) angle C = angle R           .....given in the figure

(iii) angle B = angle Q         .... given in the figure

(ii) side BC = side QR          ....given in the figure

From the above three statements we conclude that

ΔABC ≅ ΔPQR

both the triangles KLM and PQR are congruent by AAS Congruence Postulate .

Therefore , The AAS triangle congruence postulate proves that these triangles are congruent .

Learn more about Congruence Postulate here

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trey is draining an aquarium. the graph shows the amount of water (in liters) in the aquarium versus time (in minutes)

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Given the graph represents the amount of water in the aquarium versus time.

A) As shown in the graph :

as the time increases the amount of water in the aquarium decreases

The rate of water decreasing =

[tex]\frac{480}{8}=60[/tex]

so, the rate = 60 litres per minute

What is the solution to the linear equation 2/5+p=4/5+3/5p

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Ok ,we need to find p in the following equation: 2/5+p=4/5+3/5p, lets

-2( 4 - 6h ) +9-8 - 12h + 9-12h + 1Explain the error in the work.

Answers

The error is in the distribution property application, in the way the signs are multiplied.

We will look at it in detail:

[tex]\begin{gathered} -2(4-6h)+9 \\ \lbrack(-2)(4)+(-2)(-6h)\rbrack+9 \\ (-8+12h)+9 \\ 12h+1 \end{gathered}[/tex]

When (-2) is multiplied by (-12h) it should end with a positive sign, as (-a)*(-b)=a*b

A 3 dimensional shape is created when the shape isrotated around the y-axisFind the volumen of shape

Answers

Explanation

By rotating the shape of the graph, we get the following cylinder:

So we have a cylinder with:

• radius r = 4,

,

• height h = 6.

The volume of the cylinder using π = 3.14 is given by:

[tex]V=\pi *r^2*h=3.14*4^2*6=301.44.[/tex]Answer

The solid obtained is a cylinder of volume 301.44.

The volume of gas kept at a constant pressure varies inversely with the temperature T. If the temperature is 50 degrees, the volume is 20 quick feet. What will the volume be when the temperature is 100 degrees. V= , Temperature=. . Solution

Answers

Given that the volume of gas kept at constant pressure varies inversely with the temperature T and when the temperature is 50 degrees, the volume is 20 cubic feet.

We have to find the volume of gas when the temperature is 100 degrees.

Since it is given that volume varies inversely with the temperature. It means

[tex]T_1V_1=T_2V_2[/tex]

Substitute T1 = 50, V1 = 20, T2 = 100.

[tex]\begin{gathered} 50\times20=100\times V_2 \\ 1000=100\times V_2 \\ \frac{1000}{100}=V_2 \\ 10=V_2 \end{gathered}[/tex]

Thus, the volume of gas when the temperature is 100 degrees is 10 cubic feet.

Rewrite the area formula with the info given from the problem then find the value of x , then how many feet of fencing should me Korber buy ?

Answers

Since the triangle is a right isosceles triangle and each leg measures x, its area is given by:

[tex]A=\frac{1}{2}x^2[/tex]

Now, let's use the given area and solve it for x:

[tex]\begin{gathered} 4232=\frac{1}{2}x^2\\ \\ x^2=8464\\ \\ x=92\text{ ft} \end{gathered}[/tex]

Since the "path" already has fence, the amount of fence needed is 2x:

[tex]2x=2\cdot92=184\text{ ft}[/tex]

I need help on this, I need it answered in steps

Answers

Let's solve the given logarithmic expression:

[tex]\text{ log}_4(64)\text{ = m}[/tex]

We get,

[tex]\text{ log}_4(64)\text{ = m}[/tex][tex]\mathrm{Factor\: the\: number\colon\: }\: 64=4^3[/tex][tex]=\log _4\mleft(4^3\mright)[/tex][tex]\mathrm{Apply\: log\: rule}\colon\quad \log _a\mleft(a^x\mright)=x[/tex][tex]\log _4\mleft(4^3\mright)\text{ = 3 = m}[/tex]

Therefore, m = 3.

The USDA collects and distributes a wide variety of data about agriculture in the United States. One statistic reported each year is the number of milk cows (in thousands) in each state. A random sample of 10 states is selected, with the number of milk cows reported in both 2011 and 2015.
State 2011 2015 Difference
North Dakota 19 16 -3
California 1769 1778 9
Nevada 29 29 0
Ohio 268 267 -1
New Hampshire 14 14 0
Colorado 128 146 18
Minnesota 468 460 -8
Oklahoma 53 39 -14
Utah 93 96 3
Washington 260 277 17
mean 310.1 312.2 2.1
sd 532.857 535.367 10.159
An agricultural researcher wants to conduct a paired difference test to determine if the mean number of milk cows (in thousands) in the US changed between 2011 and 2015.
Round all calculated values to 4 decimal places as appropriate.
1. Which hypotheses should be used to conduct the test?
A. H0:μdiff=0 vs. Ha:μdiff≠0
B. H0:μdiff<2.1 vs. Ha:μdiff>2.1
C. H0:μdiff=0 vs. Ha:μdiff<0
D. H0:μdiff=0 vs. Ha:μdiff>0
2. Assume the conditions for the hypothesis test are met and find the test statistic and the p-value.
test statistic =

p-value =
3. Based on the p value we have
?
evidence that the null model is not a good fit for our observed data.
4. Construct a 99% confidence interval for the mean difference in the number of milk cows (in thousands) between 2011 and 2015.

Answers

1. The hypothesis tested are given as follows: A. H0:μdiff=0 vs. Ha:μdiff≠0.

2.

The test statistic is of: t = 0.65.The p-value is of: 0.2660

3. Based on the p-value, we do not have enough evidence that the null model is not a good fit for our observed data.

4. The 99% confidence interval for the mean difference in the number of milk cows (in thousands) between 2011 and 2015 is of (-8.34, 12.54).

What are hypothesis tested?

At the null hypothesis, it is tested if there has not been change, that is, if the mean is of zero, hence:

H0:μdiff=0

At the alternative hypothesis, it is tested if there has been change, hence:

Ha: μdiff≠0

Considering a two-tailed test, as we are testing if the mean is different of a value, with 10 - 1 = 9 df, and a significance level of 1 - 0.99 = 0.01, the critical value is of:

|t| = 3.25.

What is the test statistic?

The test statistic for the t-distribution is given by the equation presented as follows:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.s is the standard deviation of the sample.n is the sample size.

The parameters in this problem are given as follows:

[tex]\overline{x} = 2.1, s = 10.159, n = 10, \mu = 0[/tex]

Hence the test statistic is of:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{2.1 - 0}{\frac{10.159}{\sqrt{10}}}[/tex]

t = 0.65.

What are the p-value and the conclusion?

Considering a two-tailed test, with t = 0.65 and 10 - 1 = 9 df, the p-value is of:

0.2660.

What is the confidence interval?

The confidence interval is given as the estimate plus/minus the multiplication of the critical value and the standard error.

Hence the lower bound of the interval is of:

2.1 - 3.25x10.159/sqrt(10) = -8.34.

The upper bound of the interval is of:

2.1 + 3.25x10.159/sqrt(10) = 12.54.

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the density of aluminum is 2700 kg/m3. what is the mass of a solid cube of aluminum with side lengths of 0.5 meters?

Answers

SOLUTION

Density is calculated as

[tex]\begin{gathered} Density=\frac{mass}{volume} \\ \end{gathered}[/tex]

The side lengths of the aluminium cube has been given as 0.5 m

The volume becomes

[tex]\begin{gathered} volume=length\times length\times length \\ V=L\times L\times L \\ V=0.5\times0.5\times0.5=0.125m^3 \end{gathered}[/tex]

so the volume is 0.125 cubic-meters.

The mass becomes

[tex]\begin{gathered} Density=\frac{mass}{volume} \\ mass=density\times volume \\ mass=2700\times0.125 \\ =337.5 \end{gathered}[/tex]

Hence the answer is 337.5 kg

Write the point-slope form of the equation of the line through the points (-1, -1) and (2, 4)

Answers

The point-slope form of (-1, -1) and (2, 4) is y = 5/3(x+1) - 1.

The point-slope form is simply writing an equation of a line so that the slope or steepness and x-intercept i.e. where the line crosses the vertical x-axis are immediately apparent.

The slope-intercept equation is y - y1 = m(x - x1), where x and y are two variables, and m is the slope.

Slope m = (y2-y1) / (x2-x1)

Let,

(x1, y1) = (-1, -1)

(x2, y2) = (2, 4)

Slope (m) = ((4) - (-1)) / ((2) - (-1))

                = 5/3

y - y1 = m(x - x1) => (y - (-1)) = 5/3(x - (-1))

                         => y+1 = 5/3(x + 1)

                         =>y = 5/3(x+1)-1

Therefore, the point-slope form of (-1, -1) and (2, 4) is y = 5/3(x+1)-1.

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If the rate of inflation is 2.5% per year, the future price P(T) in dollars of a certain item can be modeled by the following exponential function, where T is the number of years from today

Answers

Solution:

The future price p(t), in dollars, can be modelled by the exponential function;

[tex]p(t)=800(1.025)^t[/tex]

(a) The current price is;

[tex]\begin{gathered} t=0; \\ \\ p(0)=800(1.025)^0 \\ \\ p(0)=800(1) \\ \\ p(0)=800 \end{gathered}[/tex]

ANSWER: $800

(b) The price 8 years from today;

[tex]\begin{gathered} t=8 \\ \\ p(8)=800(1.025)^8 \\ \\ p(8)=800(1.2184) \\ \\ p(8)=974.72 \\ \\ p(8)\approx975 \end{gathered}[/tex]

ANSWER: $975

What rule describes the translation that was applied to triangle JKM to create triangle J’K’M’, Initial directions with the pic below.

Answers

Given a point (x, y), let's evaluate the transformations:

- Translation 6 units to the right.

Means moving the point 6 units in the horizontal direction; to the right.

The new point will be (x + 6, y).

- Translation 2 units down.

Means moving the point 2 units down; in the vertical direction.

The new point will be (x + 6, y - 2).

Answer: (x + 6, y - 2).

Mia made a pencil box in the shape of a right rectangular prism what's the surface area of the box 20cm,6cm,7cm

Answers

1) Let's visualize it to better understand:

A right rectangular prism is made from

2 faces 6 x 7

4 faces 20 x 6

Since we have rectangles, we can write calculating the area of each rectangle.

S base = 2 (6x 7) ⇒ S base = 84 cm²

S faces = 2 (20 x 6) ⇒ S faces = 240 cm²

S faces = 2 (20 x 7) ⇒ S faces = 280 cm²

2) Then the total surface area

84+240+280=604 cm²

The population of Boom town is 775,000 and is increasing at a rate of 6.75% each year. How many years will it take to reach a population of 1,395,000?

Answers

To study population growth, we use the following formula

[tex]P=P_0\cdot e^{rt}[/tex]

Where,

[tex]\begin{gathered} P=1,395,000 \\ P_0=775,000 \\ r=0.0675 \end{gathered}[/tex]

Let's replace the values above, and solve for t.

[tex]\begin{gathered} 1,395,000=775,000\cdot e^{0.0675t} \\ e^{0.0675t}=\frac{1,395,000}{775,000} \\ e^{0.0675t}=1.8 \\ \ln (e^{0.0675t})=\ln (1.8) \\ 0.0675t=\ln (1.8) \\ t=\frac{\ln (1.8)}{0.0675} \\ t\approx8.7 \end{gathered}[/tex]Hence, it would take 8.7 years to reach a population of 1,395,000.

Given: the function f defined by f(x) = 3x^2. Which statement is true?

Answers

The given function is

[tex]f(x)=3x^2[/tex]

If we evaluate the function when x = 0, we get

[tex]f(0)=3(0)^2=3\cdot0=0[/tex]Hence, the first option is correct.

In the image below, line ris perpendicular to both lines p and q. Lines p and p and r. are parallel to one another. Transversal s goes through lines p 28° s What is the value of x? A 62 OB. 72 O C 152 OD. 162 Sign out INTL 2

Answers

In this problem we have that

m by supplementary angles

so

mmtherefore

the answer is

x=52 degrees

Part 2

the transformations that produce triangle ABC are

1) A dilation from the with scale factor of 2

2) A reflection across the x-axis

3) A translation of

im on a bit of a time crunch so please hurry :)

Answers

Answer

39 child tickets were sold that day

Step-by-step explanation

Variables

• x: child tickets sold

,

• y: adult tickets sold

Given that four times as many adult tickets as child tickets were sold, then:

[tex]y=4x[/tex]

If 1 child ticket cost $5.70, then x child tickets will cost 5.7x dollars.

If 1 adult ticket cost $9.20, then y adult tickets will cost 9.2y dollars.

Given that the theater sold tickets for $1657.50, then:

[tex]5.7x+9.2y=1657.5[/tex]

Substituting the first equation into the second one and solving for x:

[tex]\begin{gathered} 5.7x+9.2(4x)=1,657.5 \\ 5.7x+36.8x=1,657.5 \\ 42.5x=1,657.5 \\ \frac{42.5x}{42.5}=\frac{1,657.5}{42.5} \\ x=39 \end{gathered}[/tex]

someone please help I don't get it!!​

Answers

Answer:

which one

Step-by-step explanation:

don't forget to follow rate like

Marcus is playing dodge ball with hisfriends. He catches 2 out of every 5 ballsthrown in his direction. If he catches14 balls, how many balls were thrownat him?balls

Answers

Step 1

Given;

[tex]\begin{gathered} \text{Marcus is playing dodge ball with his friends.} \\ He\text{ catches 2 out of every 5 balls thrown in his direction.} \end{gathered}[/tex]

Required; To find out how many balls are thrown at him if he catches 14 balls.

Step 2

There are two approaches to determine the number of balls thrown at Marcus

Approach 1

[tex]\begin{gathered} \text{Marcus catches 2 balls for every 5 balls thrown in his direction.} \\ we\text{ can draw up a table and add up 2 balls caught and 5 balls } \\ \text{thrown respectively until we arrive at 14 balls caught.} \end{gathered}[/tex]

Draw the table;

we will now sum the total number of balls caught by Marcus and the total number of balls thrown at him to find out he had 35 balls thrown at him when 14 balls were caught by him.

Answer=35 balls

Approach 2

[tex]\begin{gathered} We\text{ will use the ratio} \\ \frac{2\text{ balls caught}}{14\text{ balls caught}}=\frac{5\text{ balls thrown }}{x\text{ balls thrown}} \\ \text{cross multiply} \\ 2x=5(14) \\ \text{simplify} \\ 2x=70 \\ \text{divide both sides by 2} \\ \frac{2x}{2}=\frac{70}{2} \\ x=35\text{ balls thrown} \end{gathered}[/tex]

Hence, 35 balls were thrown at Marcus

A standard pair of six sided dice is rolled what is the probability of rolling a sum greater than or equal to 11

Answers

The diagram below shows all the possible outcomes from rolling a pair of six sided dice.

The first row and first columns represents the numbers on each die. The numbers in the other rows and columns are outcomes for each roll. Thus, the total number of outcomes is the total number of pairs in the other rows and columns.

Total number of outcomes = 36

Number of outcomes with sum greater than or equal to 11 are the circled pairs. They are 3

Thus, the probability of rolling a sum greater than or equal to 11 is

3/36 = 1/12

f(×) = 3× + 7 f(1) =

Answers

Answer:

f(1) = 10

Explanation:

Given f(x) = 3x + 7

To find f(1), replace x by 1 in the equation above

f(1) = 3(1) + 7

= 3 + 7

= 10

Write the slope-intercept (y = mx + b) form of an equation for a line with y-intercept-5 and slope 2.

Answers

The slope-intercept form of the line is

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept

so we only need to substitute the values into the equation

m=2

b= -5

the equation is

[tex]y=2x-5[/tex]

what is the value of x to the nearest tenth on problem 5

Answers

Answer:

Explanation:

In problem 5, we can see that there is a right triangle with legs x and 16 and a hypotenuse equal to (x + 8).

So, by Pythagorean theorem, we can write the following equation

[tex](x+8)^2=x^2+16^2[/tex]

Now, we can expand the left side

[tex]\begin{gathered} x^2+2(8)(x)+8^2=x^2+16^2 \\ x^2+16x+64=x^2+256 \end{gathered}[/tex]

Then, subtract x² from both sides

[tex]\begin{gathered} x^2+16x+64-x^2=x^2+256-x^2 \\ 16x+64=256 \end{gathered}[/tex]

Subtract 64 from both sides

[tex]\begin{gathered} 16x+64-64=256-64 \\ 16x=192 \end{gathered}[/tex]

Finally, divide by 16

[tex]\begin{gathered} \frac{16x}{16}=\frac{192}{16} \\ \\ x=12 \end{gathered}[/tex]

Therefore, the value of x is 12

aThecity of Huntsville, TX has approximately 25,000 registered voters. There are two candidates forcity council in an upcoming election: Brown and Solano. The day before the election, a telephone pollof 550 randomly selected registered voters was conducted. 243 said they'd vote for Brown, 253 saidthey'd vote for Solano, and 54 were undecided.give the simple statistic for the proportion of voters surveyed

Answers

The surveyors are really interested in all registered boters in Huntsville, therefore the first answer is F.

Since they are only doing a sample of people with phones the real population is all registered voters with telephones, therefore the second answer is C.

The sample for this survey is the 550 voter surveyed.

To find the proportion of people who said they vote for brown we divide the number of this people by the total of people surveyed:

[tex]\frac{243}{550}=0.4418[/tex]

Therefore the proportion was 0.4418

i need to know which one is the answer , i’m having a hard time figuring it out

Answers

Answer:

Explanation:

Here, we want to know the table that represents a function

For a relationship to represent a function, no two y values can have a single x value but two x values can have a single y value.

What this means is that two independent variable values can take a single dependent variable value but no two dependent variable values can take a single independent variable value

Now, looking at the table given:

4x + 8 = 28Describe a real-world situation the equation could represent.

Answers

In a club, the entrance ticket is $8. And every time you order a soda you have to pay $4 per can. Since you only have $28 in your pocket, how many sodas can you afford?

The equation 4x +8=28 could be used to describe a scenario like this below:

In a club, the entrance ticket is $8. And every time you order a soda you have to pay $4 per can. Since you only have $28 in your pocket, how many sodas can you afford?

Notice the fixed amount (8) and the variable (4x) and the total of money you have (28). So the sum above describes the amount of money for that club.

With that equation you can find that:

4x +8=28

4x+8 -8 =28-8

4x=20

x=5

5 cans of soda.

Find the equation for the line that passes through the point (3.-5), and that is perpendicular to the line with the equation x = -2

Answers

• Line x = -2 is a vertical line that passes through point x = -2

Given the point ( 3;-5)

• We know that perpendicular lines have opposite reciprocal slopes , so the slope of the line will be

,

• m = 1/2

• so , the standard formula for a line : y = mx +c

at point ( 3-5) , we will have :

-5 = 1/2(3) + c

Therefore c = -5 -3/2

= -13/2

• Our y- intercept will be -13/2

• Finally , our equation of the line will be :

y = 1/2x -13/2

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