Answer:
fxn g
Explanation:
ggnhbdfhbz
The barrel of a rifle has a length of 0.983m. A bullet leaves the
muzzle of a rifle with a speed of 602m/s. What is the
acceleration of the bullet while in the barrel? A bullet in a rifle
barrel does not have constant acceleration, but constant
acceleration is to be assumed for this problem.
Answer in units of m/s^2
According to the solving, the acceleration of the bullet while in the barrel is 184335.7 m/s^2.
What is acceleration?Any action where the velocity changes are said to it as acceleration. There are only two ways to accelerate: altering your speed or altering your direction, or altering both. This happens because velocity is both a speed and a direction.
According to the given data,
The length of the barrel of the rifle is 0.983 m.
The speed of the bullet is 602m/s.
We know,
v^2 = u^2+ 2aS
Initial velocity, u=0
v=602m/s.
S= 0.983 m.
So,
v^2=u^2+2aS
(602)^2= 0+ 2*a*0.983
1.966a=362404
a=362404/1.966
a= 184335.7 m/s^2.
According to the solving, the acceleration of the bullet while in the barrel is 184335.7m/s^2.
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It is hard to see the motion of stars because of their extreme distance from us.
It is hard to see the motion of stars because of their extreme distance from us is a True statement.
The locations of the stars in the sky remain largely constant with respect to one another. Taurus is constantly close to Orion. Draco is continually around Ursa Minor. The stars are a continuous backdrop painting when we observe the sky; they don't move much in relation to one another.
While we orbit the sun throughout the year, there are some minute movements. Stars farther away move slightly more left and right than stars closer to us. Even if it has a minor effect, it makes sense. You'll notice that distant items move less in relation to you than nearer ones if you stare out into the distance while you go along the street.
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Question 24 (1 point)—A beam of white light hits a prism and is dispersed into the its spectral componentsred, orange, yellow, green, blue, indigo, and violet. If a second prism is placed so thatonly the red band of light can pass through, what will happen?No light will pass through the second prism because red light does not haveenough energyThe prism will disperse the red light into many shades of redThe prism will polarize the red lightThe prism will refract the red light but it will still be the same color of red
prism can disperse a compound light
red is a single coloured light
when it will pass through the prism it will get refracted again but the output will be the red one
so the answer is
The prism will refract the red light but it will still be the same color of red
How much work must you do to stretch the spring 0.030 m ? and how much work must you do to compress it 0.030m ?
Given:
The force constant of spring is
[tex]k\text{ =2.5}\times10^4\text{ N/m}[/tex]To find the work done when spring is stretched to 0.03 m and work done when compressed to 0.03 m.
Explanation:
The work done to stretch the spring will be
[tex]\begin{gathered} W\text{ =}\frac{1}{2}kx^2 \\ =\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =\text{ 11.25 J} \end{gathered}[/tex]The work done to compress the spring will be
[tex]\begin{gathered} W\text{ =-}\frac{1}{2}kx^2 \\ =-\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =-11.25\text{ J} \end{gathered}[/tex]Hi I just answered a question for electricity grade 12 could you please if it is correct
F = k*(q1)*(q2)/r^2
We know that:
F = 71 N
k = coulomb's constant = 9*10^9
q1 = ?
q2 = ?
We know that q1 = q2, since in the question it states that the charges are identical.
r = 0.99 m
F = k*(q1)*(q1)/r^2
F = k*(q1)^2/r^2
71 = 9*10^9 * (q1)^2 / 0.99^2
Isolating (q1)^2,
71 * 0.99^2 / (9*10^9) = (q1)^2
Taking square root of both sides to get q1 to the power of 1,
sqrt( 71 * 0.99^2 / (9*10^9) ) = q1
Now, simplifying the left side in a calculator, we get that
q1 = 8.793 * 10^-5 C = q2
Is science physics? If so I have a question on it
Inner Planets:
A planet whose orbit lies within the asteroid belt is called inner planets. Mercury, Venus, Earth and Mars are called th inner planets.
Outer Planets:
A planet whose orbit lies outside the asteroid belt is called outer planets. Jupiter, Saturn, Uranus and Neptune are called Outer Planets.
This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.
This weeks assignment. Research concussion protocol and submit the following in a written paper format.
-What is a concussion?
-Why do we need to have a concussion protocol?
-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,
-Is there a standard concussion protocol should you follow? What is it?
-At a minimum, concussion protocol steps should include the what people in the process?
-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.
This is due Sunday I want to get started on it please someone help me ?
Answer:
Concussion is the most common type of mild traumatic brain injury and can have serious consequences
Explanation:
A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calculate the specific heat of aluminum.Group of answer choices2.11 J/g °C4.29 J/g °C0.213 J/g °C
213 J/g °C is the specific heat of aluminum when a block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat.
C=Specific heat
Q=heat energy (J)0.14 K
M =Mass (Kg)
∆T= change in temperature (K)
M= 140 g = 0.14Kg
Q - 1080 Joules.
∆T=98.4 – 62.2 = 36.2
Q=MC∆T
C =Q/M∆T
C= 1080÷0.14×36.2
C=213 J/g °C
The term "specific heat" refers to the quantity that quantifies how a substance's additional heat energy affects its temperature. The unit is J/g °C. It is generally used in Thermodynamics.
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The Round Up carnival ride below has a radius of 3.90 meters and rotates 0.527 times per second. As shown, riders can be held up by only friction. What coefficient of friction is needed to keep the riders from sliding down? Include units in your answer. Answer must be in 3 significant digits.
Given data:
* The radius of the carnival ride is r = 3.9 m.
* The linear frequency of oscillation is f = 0.527 Hz.
Solution:
The angular frequency (angular speed) of the oscillation is,
[tex]\begin{gathered} \omega=2\pi f \\ \omega=2\pi\times0.527 \\ \omega=3.31\text{ rad/s} \end{gathered}[/tex]The frictional force acting on the ride is,
[tex]F=\mu mg[/tex]The force acting on the ride in terms of the angular speed is,
[tex]F=m\omega^2r[/tex]The frictional force acting on the ride is equal to the force acting on the ride for circular motion,
[tex]\begin{gathered} \mu mg=m\omega^2r \\ \mu g=\omega^2r \\ \mu=\frac{\omega^2r}{g} \end{gathered}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} \mu=\frac{(3.31)^2\times3.9}{9.81} \\ \mu=4.36 \end{gathered}[/tex]Thus, the coefficient of friction is 4.36.
66) The fundamental wavelength for standing sound waves in an empty pop bottle is 0.88 m. (a) What is the length of the bottle? (b) What is the frequency of the third harmonic of this bottle?
Explanation
Step 1
Let
[tex]\begin{gathered} \text{fundamental wavelength=0.88 ,} \\ \lambda=2L \\ \text{hence, replace} \\ 0.88m=2\text{ L} \\ \text{divide both sides by 2} \\ \frac{0.88m}{2}=\frac{2\text{ L}}{2} \\ 0.44=L \end{gathered}[/tex]hence, the length of the bottle is 0.44 meters
Step 2
What is the frequency of the third harmonic of this bottle?
For the third harmonic, the length of the string is equivalent to three-halves of a wavelength,so
[tex]\begin{gathered} third\text{ armonci= }\frac{\text{3}}{2}\cdot0.88\text{ m} \\ third\text{ armonci= }1.32\text{ m} \\ \end{gathered}[/tex]so
[tex]\begin{gathered} 1.32=2L \\ \end{gathered}[/tex]replace in the quation and solve for
Let speed of sound = 343 m/s
[tex]\begin{gathered} f=\frac{v}{\lambda} \\ \text{replacing} \\ f=\frac{343}{0.88} \\ f=389.77\text{ Hz} \end{gathered}[/tex]I hope this helps
you
You have been given 3.152 g of copper from which you are to fashion a wire whose resistance is 2,473.562 ohms. The density of copper is 8900 kg/m 3 and the resistivity of copper is 1.7 x 10 -8 ohm m. What will the diameter, in mm, of the wire be that you fashion?
Given:
Mass of copper, m = 3.152 g = 0.003152 kg
Resistance = 2,473.562 ohms
Density of copper = 8900 kg/m³
Resistivity of copper = 1.7 x 10⁻⁸ ohm.m
Let's find the diameter of the wire.
Apply the density formula to find the volume:
[tex]\begin{gathered} \rho=\frac{m}{v} \\ \\ v=\frac{m}{\rho}=\frac{0.003152}{8900} \\ \\ v=3.54*10^{-7}\text{ m}^3 \\ \\ (\pi r^2)l=3.54*10^{-7}\text{ m}^3 \end{gathered}[/tex]Now, apply the formula:
[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \\ l=\frac{RA}{\rho} \\ \\ l=\frac{2473.562*\pi r^2}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=\frac{2473.562}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=1.455*10^{11} \\ \\ l=1.455*10^{11}*\pi r^2 \end{gathered}[/tex]Now, combine both expressions for L:
[tex]1.455*10^{11}*\pi r^2*\pi r^2=3.54*10^{-7}[/tex]Solving further:
[tex]\begin{gathered} (\pi r^2)^2=\frac{3.54*10^{-7}}{1.455*10^{11}} \\ \\ (\pi r^2)=\sqrt{2.434*10^{-18}} \\ \\ \pi r^2=1.56*10^{-9} \\ \\ r^2=\frac{1.56*10^{-9}}{\pi} \\ \\ r=\sqrt{\frac{1.56*10^{-9}}{\pi}} \\ \\ r=2.228*10^{-5} \end{gathered}[/tex]r is the radius.
We know that:
Diameter = 2 x radius
Thus, we have:
[tex]\begin{gathered} d=(2.228*10^{-5})*2 \\ \\ d=4.4569*10^{-5}\text{ m} \\ \\ d=0.044569*10^{-3}m \\ \\ d=0.0446\text{ mm} \end{gathered}[/tex]Therefore, the diameter in mm will be 0.0446 mm
ANSWER:
0.0446 mm
The picture below shows a skateboarder just before he drops down a ramp. Assume the skateboarder does not experience any friction.Which correctly shows the potential energy and kinetic energy of the skateboarder as he moves down the left side of the ramp and up to the top of the right side?
We are given that a skater is on top of a ramp. At this point the skater has the maximum gravtitaional potential energy "PE" and a minimum kinetic energy "KE". The gravitational potential enery depends on the height of the skater and the kinetic energy depends on his velocity.
When the skater is at the bottom of the ramp his gravitational potential energy is minimum since his height is the lowest and his kientic energy is maximum since all the gravitational potential eerngy has turn into kinetic energy. This means that at the lowest point the velocity is also maximum.
Whe teh sketer reaches the highest point in the right side his kinetic energy has converted again into gravitational potential energy since the height has increased. Now, the kinetic energy is minimum and the gravitational potential energy is maximum.
This can be seen represented next:
The graph should be a representation of the fluctuations in kinetic and potential energy, therefore, the only graph that represetns this is B.
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
You call out in a loud voice and hear an echo of your voice. Where are you most likely located?A.In a boat on a lakeB.In an open fieldC.In a canyonD.In a forest
We will have the following:
Since sound bounces off of surfaces particularly ones that are perpendicular, then in this scenario you are most likely located in a canyon.
Jack is selling lemonade at a stand outside his house. He is charging $1.50 per cup. He needs to make at least enough money to cover the cost of his supplies, which were $15.25.What is the minimum number of cups of lemonade Jack needs to sell?
Given,
Charge of one cup of lemonade, c=$1.50
The amount Jack needs, T=-$15.25
The number of cups Jack needs to sell in order to have the given amount can be calculated as,
[tex]N=\frac{T}{c}[/tex]On substituting the known values,
[tex]\begin{gathered} N=\frac{15.25}{1.5} \\ =10.17 \end{gathered}[/tex]The number of cups of lemonade that can be sold should be a whole number. If Jack sells 10 cups, which is lesser than the answer, he will have less amount than he wanted.
Thus he has to sell 11 cups.
Therefore the minimum number of cups Jack needs to sell is 11.
Answer: I have all answers in screen shots
Hope this helps
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Answer:
First option
Explanation:
The battery contains chemicals and the electrical energy will be produced FROM those chemicals and then when it goes into the bell the bell uses that energy to turn into sound using an electromagnet
Answer: chemical energy from the battery will be transformed into electricity energy which is this Transformer by the Dell to the security energy
Explanation:
The potential difference across the ends of a wire is doubled in magnitude. If Ohm's law is obeyed, which one of the following statements concerning the resistance of the wire is true?a- The resistance is one half of its original value.b- The resistance decreases by a factor of four.c- The resistance is twice its original value.d- The resistance is not changed.e- The resistance increases by a factor of four.
Given:
The potential difference across the ends of a wire is doubled in magnitude
To find:
which one of the following statements concerning the resistance of the wire is true
Explanation:
The potential difference is doubled in magnitude. We know, according to Ohm's law,
[tex]V=IR[/tex]I is the current and R is the resistance.
If the potential difference increases, the product of I and R also increases.
Now the resistance depends as,
[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \rho\text{ is the resistivity, l is the length and A is the area of the conductor.} \end{gathered}[/tex]The resistance is independent of potential differences. When the potential difference increases, the current also increases and the resistance remains the same.
Hence, The resistance is not changed.
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven—the driving force is transferred to the object, which oscillates instead of the entire building.(a) What effective force constant (in N/m) should the springs have to make the object oscillate with a period of 2.10 s? N/m(b) What energy (in J) is stored in the springs for a 1.80 m displacement from equilibrium? J
ANSWERS
(a) 3.58 x 10⁶ N/m
(b) 5.8 x 10⁶ J
EXPLANATION
Given:
• The mass of the object hanging from the spring, m = 4.00 x 10⁵ kg
Find:
• (a), The force constant the springs should have to make the object oscillate with a period of 2.10 s
,• (b), The energy stored in the springs for a 1.80 m displacement from equilibrium.
(a) The period of an object in a spring is,
[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]Where m is the mass of the object and k is the spring constant.
We want to find k for T = 2.10 s, so we have to solve this equation for k, which gives us,
[tex]k=m\cdot\left(\frac{2\pi}{T}\right)^2[/tex]Replace the known values and solve,
[tex]k=4\cdot10^5\cdot\frac{4\pi^2}{(2.1)^2}\approx3,580,808.85N/m\approx3.58\cdot10^^6N/m[/tex]Hence, the force constant is 3.58 x 10⁶ N/m.
(b) The energy stored in a spring with force constant k when the mass is displaced x meters from equilibrium is,
[tex]U_s=\frac{1}{2}kx^2[/tex]Replace the known values and solve to find the energy stored in this spring,
[tex]U_s=\frac{1}{2}\cdot3.58\cdot10^6N/m\cdot1.8^2m^2\approx5.8\cdot10^6J[/tex]Hence, the energy stored in the spring for a 1.80 m displacement from equilibrium is 5.8 x 10⁶ J.
Which formula is equivalent to
v = m / D
v = mD / v
v = D x m
v = D / m
Answer:
i don't know.
Explanation: I = me Don't = Don't know = know
Match each expression on the left with an equivalent expression on the right. Some answer choices on the right will not be used.1/50.451/80.6259/203/40.1250.24/55/8
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
Explanations:This exercise is to convert the given fractions to decimals
Let us find the decimal equivalents of each of the fractions first, then the equivalent choices can be matched together
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
Traumatic brain Injury such as concussion results when the undergoes very large acceleration Generally an than 800 m/s ^ 2 lasting for any length of time will not , whereas an acceleration greater than 1, 000 m/s ^ 2 for at least 1 injury. Suppose a small child rolls off a bed that is 0.47 m above the floor. If the floor is hardwood the child’s head is brought to rest in approximately 2.1 mm. If the floor is carpeted,this stopping distance is increased to about 1.3 cm . Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate. Hardwood floor magnitude m/s^2Hardwood floor duration msCarpeted floor magnitude m/s^2Carpeted floor duration ms
ANSWER:
Hardwood floor magnitude: 2193.15 m/s^2
Hardwood floor duration: 1.38 ms
Carpeted floor magnitude: 354.27 m/s^2
Carpeted floor duration: 8.56 ms
STEP-BY-STEP EXPLANATION:
We have the following information:
Distance of the bed from the floor: 0.47 m
Stopping distance by hardwood: 2.1 mm
Stopping distance by carpet: 1.3 cm
We must find the speed of the child when he hits the ground using the following formula:
[tex]v^2=u^2+2gh[/tex]Where v is the final velocity, u is the initial velocity, g is the gravitational acceleration and h is the distance traveled.
Replacing and solving for v
[tex]\begin{gathered} v^2=0^2+2\cdot9.8\cdot0.47 \\ v=\sqrt[]{9.212} \\ v=3.035\text{ m/s} \end{gathered}[/tex]We can find the deceleration provided by the hardwood when stopping the child using the formula:
[tex]v^2=u^2-2aS[/tex]Since the child will stop, the final speed will be 0, the initial speed will be the speed gained by the child while falling that we found in the first step, and the distance S to stop is given in the question.
Replacing and solving for a:
[tex]\begin{gathered} 2.1\text{ mm }\cdot\frac{1\text{ m}}{1000\text{ mm}}=2.1\cdot10^{-3}m \\ 0^2=3.035^2-2\cdot a\cdot(2.1\cdot10^{-3}) \\ 2\cdot a\cdot(2.1\cdot10^{-3})=9.211 \\ a=\frac{9.211}{2\cdot(2.1\cdot10^{-3})} \\ a=2193.15\text{ }\frac{m}{s^2} \end{gathered}[/tex]From the calculated deceleration, we can find the time it takes for the child to stop after hitting the hardwood using the formula:
[tex]\begin{gathered} v=u-at \\ \text{replacing and solving for t:} \\ t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-2193.15} \\ t=0.00138\text{ s} \\ t=1.38\text{ ms} \end{gathered}[/tex]We repeat the same procedure but now with the data of the carpet, therefore:
[tex]\begin{gathered} 1.3\text{ cm }\cdot\frac{1\text{ m}}{100\text{ cm}}=1.3\cdot10^{-2}m \\ 0^2=3.035^2-2\cdot a\cdot(1.3\cdot10^{-2}) \\ 2\cdot a\cdot(1.3\cdot10^{-2})=9.211 \\ a=\frac{9.211}{2\cdot(1.3\cdot10^{-2})} \\ a=354.27\text{ }\frac{m}{s^2} \end{gathered}[/tex]Time for stopping by the carpet:
[tex]\begin{gathered} t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-354.27} \\ t=0.00856\text{ s} \\ t=8.56\text{ ms} \end{gathered}[/tex]Can you help me with this question? Find the sum of -2x^2 - 4x - 12 and - x^2 - 2x The answer I got was -3x^2 - 6x - 12 Just want to see if I did it correctly*Last tutor got disconnected
You have the following sum of expression:
(-2x^2 - 4x - 12) + (-x^2 - 2x)
In order to find the sum, simplify like terms (terms with the same variable and same exponent). Then, you have:
(-2x^2 - 4x - 12) + (-x^2 - 2x) =
-2x^2 - x^2 - 4x - 2x -12 =
-3x^2 - 6x - 12
Hence, the answer is -3x^2 - 6x - 12
Gamma rays require _____ to be stopped.1) paper2) glass3) aluminum4) lead
The gamma rays are having very large frequency. Thus, the energy acquired by the gamma ray photons is very large.
To stop the gamma ray, highly dense material is required.
The density of the lead is more than any other element in the given opitons.
Thus, the lead is used to stop the gamma rays.
Hence, 4th option is the correct answer.
A girl weighs 58kg and runs up a staircase 52m high in 23seconds. Find her minimum power output
Given,
The mass of the girl, m=58 kg
The height of the staircase, h=52 m
The time she takes to run up the staircase, t=23 s
The work the girl does to climb up the staircase is equal to the change in the potential energy of the girl.
Thus the work done is given by,
[tex]W=\text{mgh}[/tex]Where g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} W=58\times9.8\times52 \\ =29.56\times10^3\text{ J} \end{gathered}[/tex]The power output is equal to the rate at which the work is done
Thus the power output is given by,
[tex]P=\frac{W}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} P=\frac{29.56\times10^3}{23} \\ =1285.22\text{ W} \end{gathered}[/tex]Thus the maximum power output is 1285.22 W
Bluetooth and Wi-Fi use the same frequency band. Give one reason why Bluetooth signal does not interfere with Wi-Fi signal.
There is interference between both signals especially if they are operated in same time and space. The technology that bluetooth uses helps reduce interference from wifi signals. This technoogy is called the frequency hopping spread spectrum which changes channel frequency. This only reduces interference.
b)= combined resistance of the 2 Ω and 4 Ω resistors connected in series
R1=6 Ω
R2=3 Ω
R3=2 Ω
R4=4 Ω
6 Ω and 3Ω resistances are connected in parallel.
First, find the equivalent resistance:
ER1 = R1*R2/(R1+R2)= 6*3/6+3 = 18/9 = 2Ω
The resistances of 2 Ω and 4 Ω are connected in series:
TR2 = R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
ER1 and TR2 are connected in parallel.
RT = ER1*TR2/ ER1+TR2= 2*6/2+6=12/8 = 1.5 Ω
Now, we can calculate the I (current)
On parallel circuits, Voltage is always the same. (12V)
But for series is VT=V1+V2
We have to find the current flowing across R3 and R4 (TR2)
V= I*R
I= V/R = 12/TR2= 12/6 = 2 A
With that current, we can calculate the voltage (potential difference) on R3 (2 Ω)
V=I*R= 2*2 = 4V (ai)
(aii) potential difference across the 3 Ω resistor
Since it is a parallel circuit , potential difference is always the same = 12V
b.combined resistance of the 2 Ω and 4 Ω resistors connected in series
R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
a car travels 680 km in a time of 4 h calculate its speed
Hello..!
To calculate its speed we apply the following data.
Data:
D = 680kmT = 4hrsV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 680km / 4hV = 170km/hThe speed of the car is 170 kilometers per hour.
A sports car with a mass of 2000 kg travels at a velocity of 20 m/s. What would be true of its momentum if the same sports car was traveling at a velocity of 40 m/s?
The true statement about the sports car is that the momentum of the sports car would be increased.
What is momentum?The term momentum is defined as the product of the mass and the velocity. The momentum of an object is a vector quantity. What it means is that both the magnitude and the direction of the momentum is important.
Now we are told that the sports car has a mass of 2000 kg travels at a velocity of 20 m/s. The momentum at this point is 40000 Kgm/s. If the velocity of the sports car was increased to 40 m/s, the momentum would increase to 80,000 Kgm/s.
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A turkey with a mass of 9kg is running straight at you with a velocity of 5 m/s.What is the momentum of the turkey?
Given,
The mass of the turkey, m=9 kg
The velocity of the turkey, v=5 m/s
The momentum of a body is given by the product of the mass of the body and its velocity.
Thus the momentum of the turkey is given by,
[tex]p=mv[/tex]On substituting the known values,
[tex]p=9\times5=45\text{ kg}\cdot\frac{m}{s}[/tex]Thus, the momentum of the turkey is 45 kg·m/s
The volume of a cylinder with height h and radius r can be found using the formula V = πr2hFind the volume of a cylinder with radius 8 feet and height 7 feet.__ ft3
In order to calculate the volume of this cylinder, let's use the given values of radius and height in the formula.
Using π = 3.1416, we have:
[tex]\begin{gathered} V=\pi r^2h \\ V=3.1416\cdot8^2\cdot7 \\ V=1.407.44 \end{gathered}[/tex]So the volume is 1407.44 ft³.