The force exerted by the insect and the automobile is equal and opposite, according to Newton's law.
What exactly is acceleration?
In physics, acceleration is defined as the rate of change in velocity. As a result, the unit is m/s2. According to Newton's second equation of motion, the force acting on a moving body is the product of its mass and acceleration.
As a result, F= ma an implies that the acceleration is inversely proportional to the mass. As a result, a body with more mass will have less acceleration but more force.
An action has an equal and opposite response, according to the third law of motion. Thus, the force exerted by the bug on the car and the force exerted by the car on the bug are equal and opposite, with the bug accelerating faster due to its lower mass.
The force exerted by the insect and the automobile is equal and opposite, according to Newton's law. As a result, their acceleration reduces as their mass grows. As a result, the bug's acceleration will be greater than that of the automobile.
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Neglecting air resistance, what would happen if you were a
passenger in a convertible car traveling at a constant velocity
and threw a ball straight up in the air?
If I were a passenger in a convertible car traveling at a constant velocity and threw a ball straight up into the air, neglecting air resistance, the ball would follow a parabolic path and would eventually fall back into the car.
When the ball is thrown straight up, it will initially have a vertical velocity of 0 at the top of its trajectory. This means that it will begin to fall back down at the same speed that it was thrown up, due to the force of gravity. Since the car is moving at a constant velocity, the ball will appear to fall back into the car from the perspective of someone inside the car. However, from an outside perspective, the ball will be seen to fall to the ground at a point ahead of the car.
It's important to note that this scenario is based on the assumption that there is no air resistance. In the real world, air resistance would cause the ball to slow down as it moves through the air, which would affect the trajectory of the ball and would likely cause it to fall outside of the car.
PLS HELP NEED ANSWER SOON What is the value of g, the gravitational field strength, at the surface of the planet Venus?
Round your answer to two decimal places
With the use of formula, the magnitude of the gravitational field strength is 8.83 m/s²
What is Gravitational Field Strength ?Gravitational Field Strength at any point in a gravitational field is defined as the gravitational force per unit mass on any object placed at that point.
To calculate the value of g, the gravitational field strength, at the surface of the planet Venus, we will use the formula below
g = GM/r²
Where
g = gravitational field strengthG = Universal gravitational constant = 6.67 × [tex]10^{-11}[/tex] Nm²/kgr = radius = 6.073 × [tex]10^{6}[/tex] mM = mass of the Venus = 4.88 × [tex]10^{24}[/tex] KgSubstitute all the parameters written above into the formula
g = ( 6.67 × [tex]10^{-11}[/tex] × 4.88 × [tex]10^{24}[/tex]) / (6.073 × [tex]10^{6}[/tex])²
g = 3.255 × [tex]10^{14}[/tex] / 3.688 × [tex]10^{13}[/tex]
g = 8.83 m/s²
Therefore, the value of g, the gravitational field strength, at the surface of the planet Venus is 8.83 m/s²
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In the laboratory, you connect a resistor and a capacitor with unknown values in series with a battery of emf ε = 12 V. You include a switch in the circuit. When the switch is closed at time t = 0, the circuit is completed, and you measure the current through the resistor as a function of time as plotted below. A data-fitting program finds that the current decays according to the equation Using common symbols for the battery, the resistor, the capacitor, and the switch, draw the circuit that you constructed (on paper). Show the circuit before the switch is closed and include whatever other devices you need to measure the current through the resistor to obtain the above plot. Label each component in your diagram.
The voltage across the capacitor is VC=qC since the formula for capacitance is C=q/V. Ohm's law states that the current is defined as I=dq/dt and the potential drop across the resistor is VR=IR.
What happens when a capacitor and a resistor are connected in series?
A series connection between a resistor and a capacitor creates an RC circuit, which charges the capacitor progressively through the resistor until the voltage across it equals the supply voltage. The time needed to fully charge the capacitor is about equal to 5 time constants, or 5T.
How can a capacitor with a resistor issue be fixed?
Simply use V=IR, where V is the battery voltage and R is the resistor resistance, to determine the current flowing through the circuit, and then solve for I. When the capacitor is finished charging, the current has progressively decreased and is getting close to zero.
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Jibari walks 40.0 meters east in 120.0 seconds. He then walks 30.0 meters west in 60.0 seconds. What is his average velocity for the trip?
Answer:
0.1667 meters/second.
Explanation:
To find Jibari's average velocity for the trip, we need to first calculate his average velocity for each leg of the trip. To do this, we need to divide the distance he traveled by the time it took him to travel that distance.
For the first leg of the trip, Jibari walked 40.0 meters east in 120.0 seconds. His average velocity for this leg of the trip is therefore 40.0 meters / 120.0 seconds = 0.3333 meters/second east.
For the second leg of the trip, Jibari walked 30.0 meters west in 60.0 seconds. His average velocity for this leg of the trip is therefore 30.0 meters / 60.0 seconds = 0.5000 meters/second west.
To find Jibari's average velocity for the entire trip, we need to add the velocities for each leg of the trip, taking into account their direction. Since the first leg of the trip was east and the second leg was west, we can simply add the two velocities together to find the overall average velocity.
Jibari's overall average velocity for the trip is therefore 0.3333 meters/second east + 0.5000 meters/second west = 0.1667 meters/second.
Therefore, Jibari's average velocity for the trip was 0.1667 meters/second.
Jibari's average velocity for the trip is 0.7 m/s east.
To solve for Jibari's average velocity, we will first need to find his total displacement. We can do this by adding the magnitudes of his eastward and westward displacements. The magnitude of Jibari's eastward displacement is 40.0 meters, and the magnitude of his westward displacement is 30.0 meters. So, his total displacement is
40.0 - 30.0 = 10.0 meters east.
We can then find Jibari's average velocity by dividing his total displacement by the total time it took him to complete the trip. The total time it took Jibari to complete the trip is
120.0 + 60.0 = 180.0 seconds.
So, his average velocity is
10.0 / 180.0 = 0.7 m/s east.
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which of the following would be included in a neutral posture
answer: A
The correct answer choice which is correct about the description of a neutral posture from above is: A boy sitting on an examination chair whose knees are at the same height.
The correct answer choice is option a.
What is meant by neutral posture?Neutral posture can simply be defined as that position which an individual is that he or she finds comfort in and that can be in that position for a prolonged time. However, the part of the mammalian brain which controls our body postures is known as what we call the cerebellum.
From the context of the task, the body is sitting on a chair with his two knees at the same height is a neutral posture because he will be eased and comfortable to be in this position for a long while.
So therefore, we can now deduce from all said and done above that good posture helps us to maintain balance.
Complete question:
Which of the following would be included in a neutral posture:
a. A boy sitting on an examination chair whose knees are at the same height
b. An examiner sitting on a chair whose knees are at heights far above each other apart
c. A man standing on the stairs whose elbows are lifted upward for long
d. None of the above.
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URGENT PLS HELP A moon of mass m orbits a planet of mass M in uniform circular motion with a constant tangential velocity. The distance between the center of the moon and the center of the planet is R. The gravitational field strength at the center of the moon is Gmoon. A satellite of mass m/5 is halfway between the center of the moon and the center of the planet. What is the gravitational field strength at the satellite?
The gravitational field strength at the satellite is 80 % of the gravitational field strength at the center of the moon.
What is the gravitational field of the moon?
The gravitational field strength of the moon is calculated as follows;
G. moon = F/M
where;
F is the gravitational forcem is massF = GMM/R²
G. moon = F/M
G. moon = GM/R²
Where;
G is universal gravitational constantM is the mass of the moonR is the radius of the moonFor a satellite with the following characteristics;
mass of satellite = M/5
distance of the satellite = R/2
G. S = G (M/5) / (¹/₂R)²
G. S = G (M/5) / (¹/₄R²)
G. S = 4GM / 5R²
G. S = 4/5 ( GM/R² )
G. S = 0.8 ( GM/R² )
G. S = 0.8 ( G. moon )
G. S = 80 % of G. moon
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9. Which Lewis structure represents a molecule with a bent geometry?
Answer:
The third structure is a bent geometry of a molecule as it consists of one atom of B(boron)and 3 atoms of Cl(chlorine) linked to the atom of and the bond angle is 120°
Answer:
The first one.
Explanation:
if the mass of an object were doubled, its weight would be
Weight of a body is defined as the force with which it is attached to the earth.
mass is the total quantity of matter present.
the weight of something is given as mass * acceleration
weight of an object is directly proportional to the mass of the object. so, if mass doubles, weight will also double.
hope this helps :)
- jeron
A future space vehicle massing 250,00 kilograms lifts off vertically from the lunar surface at a net acceleration of 3.27 m/s^2. What is the net force that the Moon exerts on the space vehicle, in Newtons?
The net force acting on the future space vehicle be 81750 Newton.
What is force?The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given parameters:
Mass of the future space vehicle: m = 250,00 kilograms.
Net acceleration of the future space vehicle: a = 3.27 m/s^2.
Hence, according to Newton's 2nd law of motion:
Net force acting on the future space vehicle: F = mass × acceleration
= 25000 × 3.27 Newton
= 81750 Newton.
Hence, net force acting on the future space vehicle be 81750 Newton.
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The driver of a car made an emergency stop on a
straight horizontal road. The wheels locked and
the car skidded to a stop. The marks made by the
rubber tires on the dry asphalt are 16 meters long,
and the car's mass is 1200 kilograms.
Calculate the magnitude of the frictional force the road
applied to the car in stopping it. [Show all work,
including the equation and substitution with units.]
The magnitude of the frictional force the road applied to the car in stopping it is 8,232 N.
What is the acceleration of the car?
The acceleration of the car is the rate of change of velocity of the car with time.
The acceleration of the car is determined by applying Newton's second law of motion as follows;
ma = μmg
a = μg
where;
a is the acceleration of the carμ is the coefficient of static friction between the car and the asphalt road g is acceleration due to gravitythe coefficient of static friction between the car and the asphalt road = 0.7
a = 0.7 x 9.8 m/s²
a = 6.86 m/s²
The magnitude of the frictional force the road applied to the car in stopping it is calculated as follows;
Ff = ma
where;
m is the mass of the carFf = 1200 kg x 6.86 m/s²
Ff = 8,232 N
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Alex drives 1900 meters in 200 s. Assuming he does not speed up or slow down, what is his speed?
amount of water supply required for fire extinguishment, expressed in gallons per minute (gpm), best defines which of the following?
According to the given information amount of water supply required for fire extinguishment Fire flow.
What is fire extinguishment How is it done and why?According to the idea of fire extinguishment, the fire can be put out by removing one or several of the four components of the fire tetrahedron. ELIMINATING THE HEAT Something has to be applied toward the fire that absorb the temperature or serve as a heat exchanger in order to evacuate the heat.
What are the three guiding principles for putting out a fire?Basic operating principles for fire extinguishers: -Smouldering: This includes either removing oxygen or reducing its presence. - Cooling: This procedure involves removing heat or lowering heat. -Starvation: This entails removing fuel from the fire's site.
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Determine the frequency of a sound wave with a 1-meter wavelength propagating
through air at 75° F.
The frequency of a sound wave with a 1-meter wavelength propagating through air at 75° F be 345 Hz.
What is frequency?In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.
After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration.
At 75° F velocity of sound in air be = 345 m/s.
Given that, wavelength of sound be = 1 meter.
Hence, frequency of sound be = velocity/wavelength
= 345 m/s / 1 m
= 345 s⁻¹
= 345 Hz.
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the result of a calculation with the drake equation is intended to be an estimate of the number of worlds in the galaxy on which .
The result of a calculation with the Drake equation is estimating the number of worlds in the galaxy on which: C. The number of worlds in the galaxy on which civilizations are transmitting signals now.
What is the Drake equation?The Drake equation, which is also known as the Green Bank equation, is used to estimate the number of communicative extraterrestrial civilizations in the Milky Way galaxy. This equation is based on electromagnetic emissions that are detectable from Earth. Hence, the correct answer is: C.
This question is incomplete. The complete options for the query are as follows:
“The result of a calculation with the Drake equation is intended to be an estimate of:
a. The number of worlds in the galaxy on which life has arisen.b. The number of worlds in the galaxy on which intelligence has arisen.c. The number of worlds in the galaxy on which civilizations are transmitting signals now.”Learn more about Drake's equation and extraterrestrial life here https://brainly.com/question/28963050
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vertical columns in the periodic table represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties list elements that have similar properties
The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.
What is group of elements in a periodic table?
The groups in periodic table is the same as vertical columns in the periodic table
These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.
Examples of elements found in the same group with similar chemical properties include;
group 7 elements.
FluorineChlorineBromineIodineThe valence electron of elements found in the group 7 of periodic table is negative 1 (-1).
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Which of the following statement describes the coriolis effect? Coriolis effect causes the air moving into a low pressure system to bend to the left in the northern hemisphere Coriolis effect causes the air moving out of a high pressure system to bend to the left in the northern hemisphere. Coriolis effect causes the air moving into a low pressure system to bend to the right in the southern hemisphere. Coriolis effect causes the air moving out of a high pressure system to bend to the left in the southern hemisphere. All of the above
C is the finest statement to describe the Coriolis effect. The apparent route of ocean currents curves due to the rotation of the Earth.
What is the effect of Coriolis?
This is an evident force, relative to the earth's surface, that causes moving things to the right within the Northern Hemisphere and to the left within the Southern Hemisphere as a result of the earth's rotation.
The Coriolis effect is an apparent force, relative to the earth's surface, that causes moving objects to deflect to the right within the Northern Hemisphere and to the left within the Southern Hemisphere as a result of the earth's rotation.
C is the finest statement to describe the Coriolis effect. The apparent route of ocean currents curves due to the rotation of the Earth.
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A 2.4 × 10-6 C charge experiences a 1.7 × 10-2 N force from a -4.1 × 10-6 C charge. What is the distance separating these two charges?
A.
5.7 × 10-10 m
B.
2.3 m
C.
5.2 m
D.
2.4 × 10-5 m
The distance separating these two charges is 2.3 m. Hence, option (B) is correct.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged particles.
Given that: the two charges are 2.4 × 10^-6 C and -4.1 × 10^-6 C.
Force experienced by it = 1.7 × 10^-2 N.
Let the distance between them = r, then
F = kQq/r²
1.7 × 10^-2 = {9×10^9×2.4 × 10^-6×4.1 × 10^-6 }/r^2
r =√[ {9×10^9×2.4 × 10^-6×4.1 × 10^-6 }/ 1.7 × 10^-2 ]
=2.3 m.
Hence, the distance between two charges is 2.3 m.
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What is the main difference between the gravitational potential energy is elasctic potential energy
Answer:
• Gravitational potential energy is always negative while the elastic potential energy is always positive.
• Gravitational potential energy depends on the mass of the object, but elastic potential energy does not depend on the mass.
A cannon is fired horizontally at 235 m/s off of a 61 meter tall, shear vertical cliff. How many seconds will have elapsed before the cannon ball strikes the ground? Round to the nearest hundredth.
Answer:
Hope this helps!
Explanation:
The time elapsed before the cannon ball strikes the ground can be found by using the equation for kinematic vertical motion,
t = (2*d)/g
Where d is the vertical distance and g is the acceleration due to gravity (9.8 m/s^2).
t = (2*61)/9.8
t = 12.24 seconds
The time elapsed is 12.24 seconds, rounded to the nearest hundredth is 12.24 seconds.
In a ballistic pendulum, a spring pushes a ball from rest. It flies through the air and sticks in the base of a pendlum that swings upwards.
Given that the ball and pendulum reach a maximum angle of 45º, the pendulum is 30 cm long, the mass of the ball is 76 g, and the mass of the pendulum is 250 g, calculate the speed of the ball after it has left the spring but before it hits the pendulum. Do not include the units in your response.
Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO
Take a look inside your heart
Is there any room for me?
I would have to hold my breath
'Til you get down on one knee
Because you only want to hold me
When I'm looking good enough
Did you ever fault me?
Would you ever picture us?
Every time I pull my hair out
Was only out of fear
That'd you find me ugly
And one day you'll disappear
Because what's the point of crying?
It was never even love
Did you ever want me?
Was I ever good enough?
A 1.60 kg, horizontal, uniform tray is attached to a vertical ideal spring of force constant 195 N/m and a 280 g metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down 15.0 cm below its equilibrium point (call this point A) and released from rest. a) How high above point A will the tray be when the metal ball leaves the tray? (Hint: This does not occur when the ball and tray reach their maximum speeds.) b) How much time elapses between releasing the system at point A and the ball leaving the tray? c) How fast is the ball moving just as it leaves the tray?
(a) The height above point A will be the tray when the metal ball leaves the tray is 29.24 cm.
(b) The total time elapses between releasing the system at point A and the ball leaving the tray is 0.09 seconds.
(c) The speed of the ball moving just as it leaves the tray is 1.16 m/s.
A) F= gx
ma=gx
(2.295)(9.8)=190x
X= 11.84 cm
B) h= 11.84+17.4 = 29.24 cm
Y=Acos√kt/m-0
T= 0.09s
C) ½ mv² + ½ ky² = ½ kA²
v² = 1.16m/s
What is speed?
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compute the warping stress at the edge and at the interior of the slab assuming the temperature differential between top and bottom of slab is 3of per inch of thickness
During a summer midday, warping strains are produced in reinforced cement concrete pavements that are tensile in the bottom fibre and compressive in the top fibre.
There is a temperature difference between the top and bottom layers
the pavement when it is nighttime because the top surface is colder than the bottom surface. which results in the pavement warping.
Internal tensile tensions form at the top as the top slab attempts to contract but is unable to do so.
bottom-up compression stress
There is a temperature difference between the top and bottom layers of the pavement when it is nighttime because the top surface is colder than the bottom surface. This results in pavement warping
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Amid a summer late morning, warping strains are delivered in strengthened cement concrete asphalts that are ductile within the bottom fibre and compressive within the best fibre.
There may be a temperature contrast between the best and foot layers the asphalt when it is nighttime since the beat surface is colder than the foot surface. which comes about within the asphalt warping. Internal pliable pressures form at the best as the best piece endeavors to contract but is incapable to do so.
bottom-up compression stress There could be a temperature distinction between the beat and foot layers of the asphalt when it is night time since the best surface is colder than the foot surface. This comes about in asphalt distorting
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Which of the following quantities is conserved for plant orbiting a star in a circular orbit? Only the planet itself is to be taken as the system the star is not included a. Momentum and energy b. Energy and angular momentum c. Momentum, angular momentum and energy d. None of the above.
Energy and angluar momentum quantity is conserved for plant orbiting a star in a circular orbit.
What is energy?Energy is ability to do the work.scientist defines energy as the ability to do work.
Energy and angular momentum, arter all other factors- change.
In the Earth-Satellite system, a gravitational force acts to the join the two bodies. Thus, there is no torque due by to gravitational force. Hence, the angular velocity is conserved.
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What does the elasticity (stretchiness) of the resistance band determine?
The resistance band's elasticity (stretchiness) dictates how easily it can be stretched or can be flexible.
What does the resistance band's elasticity determine?It is the proportion of tensile stress to strain, where strain is the amount of deformation and tensile stress is the tension force applied to a surface area (amount of stretch of the resistance band).
Instead than requiring you to hold additional weight per se, resistance bands function by providing an external resistance force that can be imposed. They are flat, occasionally looping bands that might be thin or thick.
Both rubber bands and springs have a unique quality. The stretch distance affects how hard a band pulls back. The spring constant, denoted by the symbol k (in units of N/m), is a proportionality constant.
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Problem 4 Consider two superconducting wires, tin (Sn, Type I) and Nb3Sn (Type II), each 1 mm in thickness. The magnetic field on the surface of a current-carrying conductor is given by BMol 2nr a) Assuming that Sn wire loses its superconductivity when the field at the surface reaches the critical field (0.2 T), calculate the maximum current and hence the critical current density that can be passed through the Sn wire near absolute zero of temperature. b) Calculate the maximum current and critical current density for Nb3Sn wire using the same assumption as in part (a) but taking the critical field to be the upper critical field Bc2, which is 24.5 T at 0 K. How does your calculation of Je compare with the critical current density of about 10" A/m² for Nb3Sn at OK?
This value is close to the experimental value of approx. 1011 A/m2
Super conductivity, or current flow with zero electric resistance, is the ability to conduct electricity without suffering energy losses.
The superconductivity is quenched when current through the wire causes the critical magnetic field at the wire surface.
Given that,
B = 0.2T
R = 0.001m (R = r/2)
a. Maximum current, critical current density
Ic = B*2πr / μo
Ic = {0.2 * 2 * (22/7) * (0.001/2)} / 4 * (22/7) * 10-7
Ic = 500A
Thus, maximum current Jc=Ic/A = 6.363 * 108 A/m2
It turns out that the critical current density for TYPE I superconductors is indeed in the range of this magnitude. The superconductivity is destroyed by a current that produces a field on the conductor surface that is equivalent to B.
b. Type II superconductor, Nb3Sn
Critical field is the upper critical field, B2
Ic = B*2πr / μo
Given that, B = 24.5T, Thickness = 0.001m
Ic = {24.5 * 2 * π * (0.001/2)} / 4 * π *10-7
Ic = 61250A
Thus, Maximum Current Jc= Ic/A = 7.795 * 1010 A/m2
This value is close to the experimental value of approx. 1011 A/m2
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The side mirrors on cars are convex mirrors. If the side mirror on the driver side of your car has a focal length with a magnitude of 5.90 m and a truck is at a distance of 2.00 m from the mirror, determine the following.(a) image distance of the truck (Include the appropriate positive or negative sign.)=_____ m(b) magnification for this object distance (Include the appropriate positive or negative sign.)
a) Image distance of truck v = -1.49m/s
b) magnification for this object distance m = +0.643
Image distance and focal length of a convex mirror is negative.
a) Calculating the image distance using the mirror formula;
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
f = the mirror's focal length, which is 5.90 meters,
u = the object's distance from the mirror, which is 2.00 meters, and
v = the image's distance from the mirror.
[tex]\frac{1}{-5.90}[/tex] = [tex]\frac{1}{2}[/tex] + [tex]\frac{1}{v}[/tex]
[tex]\frac{1}{v}[/tex] = [tex]\frac{1} {-5.9}[/tex] - [tex]\frac{1}{2}[/tex]
[tex]\frac{1}{v}[/tex] = - 0.169 -0.5
= -0.669
v = [tex]\frac{1}{-0.669}[/tex]
v = - 1.49m/s
What are convex mirrors used for?
All automobiles have convex mirrors in their rearview mirrors. They provide a wider vision than flat mirrors. To span the breadth visible via a convex mirror of a considerably smaller size, we will require enormous plane mirrors. Additionally, convex mirrors are utilized for security in storefronts, corridors of buildings, etc.
b) Magnification is equal to the image/object distance.
Magnification is 1.49/2.
magnifying glass = +0.74
Note that we do not compute the object's magnification using the image distance's negative value.
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based on what you know about the moons of saturn, select all of the correct statements from the following list.
Saturn's atmosphere is substantially less active than Jupiter's because it is twice as far away from the sun.
how many moons are there for saturn ?
Saturn's moons are many and diverse, ranging from small moonlets barely tens of metres wide to Titan, which is bigger than Mercury. Saturn has 83 verified moons with proven orbits that are not contained in its rings, with just 13 having diameters more than 50 kilometres, as well as thick rings with millions of embedded moonlets and uncountable smaller ring particles. Only one or two of Saturn's moons, Titan and maybe Rhea, are massive enough to have collapsed into a relaxed, ellipsoidal form. Titan, the second-largest moon in the Solar System (after Jupiter's Ganymede), has a nitrogen-rich Earth-like atmosphere and a terrain that includes dry river networks.
Smaller moons "shepherd" or retain particles in their rings in the ring system.
Saturn's atmosphere is substantially less active than Jupiter's because it is twice as far away from the sun.
Saturn's rings are largely comprised of ice particles.
Saturn is not the only planet with a ring system, despite being the most extensive.
Some ring particles are miniature moons separated by tidal forces.
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party hearing. as the number of people at a party in creases you must rasie your voice for a listerner to her you agaisnt the backgorund noise of the other party ogesrs. however, once you reach
The listener must be 0.67 meters away from the speaker in in order to hear that speaker's voice.
What does the word "yelling" mean?to shout or make a loud sound, typically out of anger, discomfort, or excitement: This morning, our neighbors were shouting (using expletives) at one another. The youngster screamed in agony.
Briefing :difference in sound level is-
Δβ=βf −βt =(10dB)log( If/It)
Thus, if Δβ=5.0 db, then log(I f /I t )=1/2, which implies that It = √10 It.
The intensity, however, is lower at a separation r from of the source because
I= P/4πr²
where P represents the source's power.
A fixed P implies that Itrt²=Ifrf². Thus, with
rt =1.2 m, we obtain
rt =( If/It ) ∧1/2 rt
=(1/10) ∧1/4 (1.2 m)
=0.67 m.
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The complete question is -
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the backgrounds noise of the other partygoers. However, once you reach the level of yelling, the only way you can be heard is if you move closer to your listener, into the listener's "personal space". Model the situation by replacing you with an isotropic point source of fixed power P and replacing your listener with a point that absorbs part of your sound waves. These points are initially separated by r1 =1.20 m. If the background noise increases by Δβ=5 dB, the sound level at your listener must also increase. What separation rf is then required?
If we represent the sun as a Grapefruit of diameter 10 cm, how big would Jupiter be? How big would the Earth be? (Helpful information: Diameter of Sun = 1,392,000 km; Diameter of Jupiter = 139.800 km: Diameter of Earth = 12,740 km)
Although the exact location of the liquid/gas transition is not known, Jupiter is likely totally liquid a few thousand kilometers below the planet's cloud tops. Therefore, even if we removed all of the gases from Jupiter, it would still be larger than Saturn.
From Earth, how huge would Jupiter appear?
Io and Ganymede would frequently emerge in the sky and would appear to be more than 1.5 times larger than our Moon does in the sky above Earth. In the sky above Earth, Jupiter would appear to be almost 24 times larger than our Moon.
Is Jupiter an ailing star?
The same elements as the Sun (hydrogen and helium), Jupiter is referred to as a failed star because it lacks the mass required to have the internal pressure and temperature required to cause hydrogen to fuse to helium, the energy source that powers the sun and most other stars.
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Using the concepts of impulse and momentum, describe how to win a water balloon contest by not breaking the balloon.
Requirements:
o Focus on the catch.
o You must mention how momentum, impulse, force and impact time play a part in the catch.
o You may use diagrams to support your reasoning.
o Remember the equation: ∆p = m∆v = F∆t
You must concentrate on the catch to win a water balloon contest without breaking the balloon. Momentum, impulse, force, and impact time are all important factors in the catch's success. The key to catching a water balloon without breaking it is to reduce the balloon's impact force. The momentum of the balloon, the impulse applied to the balloon, and the impact time all contribute to the impact force.
What is the momentum?The product of an object's mass and velocity is its momentum. As it is thrown towards you, the water balloon has a certain mass and velocity. The greater the balloon's momentum, the more difficult it will be to catch it without breaking it.
In order to catch a water balloon, you must apply an impulse to the balloon. The higher the impulse, the more effectively you can stop the balloon. To catch a water balloon without breaking it, apply a large impulse to the balloon in a short period of time. This reduces the impact force on the balloon and keeps it from breaking.
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