Alice traveled 30 miles in 3 hours. What graph shows the relationship between time traveled in hours and total miles traveled?The graph shows the relationship between the number of hours that Michelle has been driving and the distance that she has left to travel to get to her destination. Which statement is true? It took Michelle 6 hours to complete the trip. For each hour that Michelle drove, she traveled an additional 50 miles. In the first 6 hours, Michelle had traveled a total of 50 miles. In the first 3 hours, Michelle had traveled a total of 200 miles.

Alice Traveled 30 Miles In 3 Hours. What Graph Shows The Relationship Between Time Traveled In Hours

Answers

Answer 1

Given that Alice traveled 30 miles in 3 hours. Initially, the distance traveled is 0 miles.

Take distance on the x-axis and time on the y-axis.

From the given information, the two points on the graph are (0,0) and (30,3).

Mark the points on the graph.

The distance-time graph of a body is a straight line. Join the points by a straight line to get the required graph.

Alice Traveled 30 Miles In 3 Hours. What Graph Shows The Relationship Between Time Traveled In Hours
Alice Traveled 30 Miles In 3 Hours. What Graph Shows The Relationship Between Time Traveled In Hours

Related Questions

Question 41: Find the product and express it in rectangular form.

Answers

ANSWER:

[tex]-18-18\sqrt[]{3}i[/tex]

SOLUTION:

The salesperson earned a commission of $1110.20 for selling $7930 worth of paper products. Find the commission rate

Answers

Commision = $1110.20

Selling= $7930

x is the commission rate

[tex]7930\cdot\frac{x}{100}=1110.20[/tex]

Then we isolate the x

[tex]x=\frac{1110.20\cdot100}{7930}=14\text{ \%}[/tex]

ANSWER

The commission rate is 14%

The Dover Symphony categorizes its donors as gold, silver, or bronze depending on the amount donated.

Answers

Explanation

Given the donors as

[tex]\begin{gathered} Gold=4 \\ silver=7 \\ Bronze=9 \end{gathered}[/tex]

The total number of donors are

[tex]9+7+4=20[/tex]

Therefore, the percent of donors at the bronze or silver level is

[tex]\frac{sum\text{ }of\text{ }bronze\text{ }and\text{ }silver\text{ donors}}{number\text{ of donors}}=\frac{9+7}{20}\times100=16\times5=80\text{\%}[/tex]

Answer:

Enter the equation of the circle with the given center and radius. Center: (7,0); radius: 3 The equation is

Answers

Given data:

The given coordinate of centre of the circle is (7,0).

The given radius of the circle is r=(3)^(1/2).

The equation of the circle is,

[tex]\begin{gathered} (x-7)^2+(y-0)^2=(\sqrt[]{3})^2 \\ (x-7)^2+y^2=3 \end{gathered}[/tex]

Thus, the equation of the circle is (x-7)^2 +y^2 =3.

what is the simplified form of the expression x^2+4x-21 over 4(x+7)​

Answers

Answer:

x-3 over 4

Let me know if you need elaboration

Jessica and her father are comparing their ages. At the current time, Jessica's father is 24 years older than her l. Three years from now, Jessica father will be five times her age at the pointQUICK PLEASE

Answers

Current ages

Jessica's age = x

Jessica's father = x + 24

In 3 years time, there ages will be:

Jessica's age = x+ 3

Jessica's father = x + 24 + 3 = x + 27

But Jessica's father will be 5 times her age

Hence;

x + 27 = 5(x+3)

Open the parenthesis

x + 27 = 5x + 15

collect like term

5x - x = 27 - 15

4x = 12

Divide both-side of the equation by 4

x = 3

In the current time;

Jessica is 3 years old

Jessica's father is x + 24 = 3 + 24 = 27 years old

Erika is working on solving the exponential equation 50^x = 17; however, she is not quite sure where to start. Using complete sentences, describe to Erika how to solve this equation.

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

50^x = 17

Step 02:

exponential equation:

1. Apply logarithms to both sides of the equality.

[tex]log\text{ 50}^x=\text{ log 17}[/tex]

2. Apply properties of logarithms.

[tex]x\text{ log 50 = log 17}[/tex]

3. Apply the algebraic rules to find the value of x.

[tex]x\text{ = }\frac{log\text{ 17}}{log\text{ 50}}\text{ }[/tex]

The answer is:

x = (log 17) / (log 50)

1.) Your 3 year investment of $20,000 received 5.2% interested compounded semi annually. What is your total return? ASW

Answers

Let's begin by listing out the information given to us:

Principal (p) = $20,000

Interest rate (r) = 5.2% = 0.052

Number of compounding (n) = 2 (semi annually)

Time (t) = 3 years

The total return is calculated as shown below:

A = p(1 + r/n)^nt

A = 20000(1 + 0.052/2)^2*3 = 20000(1 + 0.026)^6

A = 20000(1.1665) = 23,330

A = $23,330

Julie is buying chocolate chip and oatmeal cookies from the bakery. Chocolate chip cookies cost 25¢ each and oatmeal cookies cost 20c each. She wants to buy a mixture of at least 50 cookies. Julie is planning to spend less than $10. Let: C = number of chocolate chip cookies she can buy. M = number of oatmeal cookies she can buy. Select the system of inequalities that represents this situation.

Answers

[tex]\begin{gathered} \text{ Since we have to spend less that \$10} \\ 0.25C+0.20M<10.00 \\ \\ \text{ Since she want to buy at least 50,} \\ C+M\ge50 \\ \\ \text{ The answer is } \\ 0.25C+0.20M<10.00 \\ C+M\ge50| \end{gathered}[/tex]

Kristy is paid semimonthly. The net amount of each paycheck is$750.50. What is her net annual income?a. $18,012b. $4,503c. $19,513d. $9,006

Answers

SOLUTION

Given the question in the question tab, the following are the solution steps to answer the question.

STEP 1: Define semimonthly

A semimonthly payroll is paid twice in a month.

STEP 2: Calculate the net annual income

[tex]\begin{gathered} Net\text{ annual income means the total money received in a year.} \\ \text{If net amount of each paycheck is \$750.50 and it is a semimonthly payment, then;} \\ \text{monthly payment=\$750.50}\times2=\text{\$}1501 \\ \\ There\text{ are 12 months in a year,} \\ \text{If Kristy earns in month, then the amount earned in a year is:} \\ 12\times\text{\$1501=\$18,012} \end{gathered}[/tex]

Hence, her net annual income will be $18,012

OPTION a

Find the volume of a rectangular prism with the following dimensions.length: 4.2 cmwidth: 7 cmheight: 15 cmvolume = ____ cm3

Answers

Given:

length: 4.2 cm

width: 7 cm

height: 15 cm

Required:

volume = ____ cm3

Explanation:

volume of prism=

[tex]\begin{gathered} l\times w\times h \\ 4.2\times7\times15 \\ =441cm^3 \end{gathered}[/tex]

Required answer:

[tex]441cm^3[/tex]

complete the table using y=5x+9 (x)-1,0,1,2,3(y)

Answers

To complete the table, plug each given x value into the equation. Then,

[tex]\begin{gathered} \text{ If x = -1} \\ y=5x+9 \\ y=5(-1)+9 \\ y=-5+9 \\ y=4 \\ \text{ So, you have the point} \\ (-1,4) \end{gathered}[/tex][tex]\begin{gathered} \text{ If x = 0} \\ y=5x+9 \\ y=5(0)+9 \\ y=0+9 \\ y=9 \\ \text{ So, you have the point} \\ (0,9) \end{gathered}[/tex][tex]\begin{gathered} \text{ If x = 1} \\ y=5x+9 \\ y=5(1)+9 \\ y=5+9 \\ y=14 \\ \text{ So, you have the point} \\ (1,14) \end{gathered}[/tex][tex]\begin{gathered} \text{ If x = 2} \\ y=5x+9 \\ y=5(2)+9 \\ y=10+9 \\ y=19 \\ \text{ So, you have the point} \\ (2,19) \end{gathered}[/tex][tex]\begin{gathered} \text{ If x = 3} \\ y=5x+9 \\ y=5(3)+9 \\ y=15+9 \\ y=24 \\ \text{ So, you have the point} \\ (3,24) \end{gathered}[/tex]

Therefore, you would get the table

can you help me solve this​

Answers

Refer to photo taken.

In a dog race of 9 equally talented runners, what is the probability that Dasher, Dancer, and Prancer will finish first,second, and third, respectively?21/907201/3628801/5041/3

Answers

Combinations and Variations of Elements

Let's suppose we have two dogs only, A and B. They can only finish in two possible orders: AB or BA.

If we add a third dog, let's say C, the combinations (better-called variations here) are now ABC, ACB, BAC, BCA, CAB, and CBA, a total of 6 variations.

Note that we added a 3rd element and the variations changed from 2 to 6, that is, the number was multiplied by 3.

If we add a fourth dog, the total number of possible variations is 6*4 = 24

Following this very same pattern, for 9 dogs, there will be a total of

9*8*7*6*5*4*3*2 = 362880 variations.

Out of these possibilities, we are trying to find the probability that the first three places are occupied by three specific dogs, and the other 6 positions can be filled up with a random variation that will give us

6*5*4*3*2 = 720 variations.

Thus the required probability is:

[tex]\begin{gathered} p=\frac{720}{362880} \\ \text{Simplifying the result, we get:} \\ p=\frac{1}{504} \end{gathered}[/tex]

just need help with this one real quick. What do I put for B.I know the maximum value is (3,24)

Answers

We were given:

[tex]\begin{gathered} f(x)=-3x^2+18x-3 \\ f(x)=y \\ \Rightarrow y=-3x^2+18x-3 \\ y=-3x^2+18x-3 \\ a=-3,b=18,c=-3 \end{gathered}[/tex]

We will calculate the minimum point as shown below:

[tex]\begin{gathered} min=c-\frac{b^2}{4a} \\ min=-3-\frac{18^2}{4(-3)} \\ min=-3-\frac{324}{-12} \\ min=-3-(-27) \\ min=-3+27 \\ min=24 \\ \text{This is the maximum value (not minimum)} \\ x=-\frac{b}{2a} \\ x=-\frac{18}{2(-3)} \\ x=\frac{-18}{-6} \\ x=3 \\ \\ \therefore Maximum\text{ point is (3, 24)} \end{gathered}[/tex]

This quadratic equation opens downward because the value of ''a'' is negative. Hence, the function only has a maximum point, it does not have a minimum point

The maximum value of the function is 24 and it occurs at x equals 3

You are to show how to correctly graph y = -x - 5

Answers

Answer and Explanation:

The slope-intercept form of the equation of a line is generally given as;

[tex]y=mx+b[/tex]

where m = the slope of the line

b = the y-intercept of the line

So given the equation;

[tex]y=-x-5[/tex]

Comparing the two equations, we can deduce the following;

* m = -1

This means that the line will have a negative slope

* b = -5

This means that the line will cut the y-axis at -5.

We can now choose values for x and determine the corresponding values of y and then proceed to plot the graph.

When x = 1;

[tex]\begin{gathered} y=-1-5 \\ y=-6 \end{gathered}[/tex]

When x = 0,

[tex]\begin{gathered} y=-0-5 \\ y=-5 \end{gathered}[/tex]

When x = -2,

[tex]\begin{gathered} y=-(-2)-5 \\ y=2-5 \\ y=-3 \end{gathered}[/tex]

When x = -4,

[tex]\begin{gathered} y=-(-4)-5 \\ y=4-5 \\ y=-1 \end{gathered}[/tex]

When x = -6;

[tex]\begin{gathered} y=-(-6)-5 \\ y=6-5 \\ y=1 \end{gathered}[/tex]

With the above values and information, we can then go ahead and plot our graph as shown below;

What is the smallest figure in geometry?

Answers

By definition, a point is the smallest figure in geometry.

The graph of y= 2x^2 - kx + 6 touches the x-axis. What are the possible value(s) of k?

Answers

Given:

The graph of

[tex]y=2x^2-kx+6[/tex]

Required:

What are the possible value(s) of k?

Explanation:

[tex]Set\text{ y = 0, evaluate the quadratic at }h=-\frac{b}{2a}and\text{ solve for k}[/tex]

You want to find the value the value of k such that the y coordinate of the vertex is 0.

[tex]\begin{gathered} y=2x^2-kx+6 \\ 0=2x^2-kx+6 \end{gathered}[/tex]

The x coordinate, h , of the vertex is found, using the following equation:

[tex]\begin{gathered} D=b^2-4ac \\ b^2-4ac=0 \\ k^2-4\times2\times6=0 \\ k^2-48=0 \\ k^2=48 \\ k=\pm4\sqrt{3} \end{gathered}[/tex]

Answer:

So, values of k are above.

O GEOMETRY Perimeter involving rectangles and circles A rectangular paperboard measuring 20 in long and 13 in wide has a semicircle cut out of it, as shown below. What is the perimeter of the paperboard that remains after the semicircle is removed? (Use the value 3.14 for , and do not round your answer. Be sure to include the correct unit in your answer.) Explanation +0 13 in 20 in Check 0 in X in² 5 in³ 3/5 ? Nikida E: 6 C E E 121

Answers

The perimeter of the paperboard that remains after the semicircle is removed is 185.66in.

It is given to us that the measurement of rectangular paperboard are -

Length = 20in

Width = 13in

A semicircle is cut out of it.

We have to find out the perimeter of the paperboard that remains after the semicircle is removed.

Now, according to the given figure,

Radius of the semi circle = 1/2 (Width of the paperboard) ---- (1)

Let us say the radius of the semi circle is "[tex]r[/tex]".

So, from equation (1),

[tex]r = \frac{13}{2}\\ = > r = 6.5[/tex] in ---- (2)

Now, Perimeter of the paperboard that remains after the semicircle is removed =

Bottom length + Left width + Top length + Right circumference of the semicircle

= 20 + 13 + 20 + ([tex]\pi r^{2}[/tex])  [Circumference of semicircle = [tex]\pi r^{2}[/tex]]

= 53 + [[tex]\pi (6.5)^{2}[/tex]]             [From equation (2), we have [tex]r = 6.5[/tex] in]

= 53 + 132.66

= 185.66 in

Thus, the perimeter of the paperboard that remains after the semicircle is removed is 185.66in.

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of the 800 participants in a marathon, 120 are running to raise money for a cause. How many participants out of 100 are running for a cause?a.8 b. 20c. 15d. 12OMG i hate iready please heeeelp

Answers

To find how many participants out of 100 are running for a cause we can use the next proportion:

[tex]\frac{800\text{ total participants}}{100\text{ total participants}}=\frac{120\text{ running for a cause}}{x\text{ running for a cause}}[/tex]

Solving for x:

[tex]undefined[/tex]

Diego is trying to write the expression 2 + 1 - in a way that makes it easier tocalculate. He says, “I can switch the order of 1 and and write 2+- 1 then I canget an equivalent expression that's easier to compute.Do you agree with Diego's reasoning? Why or why not?

Answers

While switching the order during adding or substraction,

If y varies directly with x, and y = 12 when x = 8, write the direct linear variationequation.O y=8xO y = 12xO y=2/3xO y= 3/2 x

Answers

A direct linear variation of y with x has the general form:

[tex]y=mx[/tex]

Where m is the ratio of y to x, which is a y divided by x.

Since we know that when x equals 8, y equals 12, we can calculate m, like this:

[tex]m=\frac{y}{x}=\frac{12}{8}=\frac{6}{4}=\frac{3}{2}[/tex]

Now that we know that m=3/2, the linear variation equation would be:

[tex]y=\frac{3}{2}x[/tex]

What is the reason these triangles are congruent? M N Р o Not Congruent

Answers

Since the line in red is common to both triangles and segments PM and ON are parallel, then the angles in purple are congruent and so are the angles in green. So they are congruent by ASA

Solve each systems of the equations by elimination. 1* x-y=-13 x+y=-52* 2x-9y=17 2x+3y=-19

Answers

Let us solve the given system of equations by using the elimination method.

Question 1:

[tex]\begin{gathered} x-y=-13\quad eq.1 \\ x+y=-5\quad eq.2 \end{gathered}[/tex]

Add these two equations so that the y variable cancels out

So, the value of x can be found now

[tex]\begin{gathered} 2x=-18 \\ x=-\frac{18}{2} \\ x=-9 \end{gathered}[/tex]

Substitute the value x into any of the two equations to find the value of y.

[tex]\begin{gathered} x-y=-13 \\ -9-y=-13 \\ y=-9+13 \\ y=4 \end{gathered}[/tex]

Therefore, the solution of this system is x = -9 and y = 4

In the relationship shown by the data linear ? If so , model the data with an equation A. The relationship is not linear B. The relationship is linear; y+2=4/5 (x+9) C . The relationship is linear; y + 9 = - 4/5 (x+2) D. The relationship is linear; y+ 2 = -5/4 (x+9)

Answers

Let's take two points so that we can get the equation of the line which goes through those points. P1 (-9, -2), P2 (3, -17):

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-17-(-2)}{3-(-9)}=\frac{-17+2}{3+9}=-\frac{15}{12}=-\frac{5}{4}[/tex][tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=-\frac{5}{4}\cdot(x-(-9)) \\ y+2=-\frac{5}{4}\cdot(x+9)_{} \\ y=-\frac{5}{4}x-\frac{45}{9}-2 \\ y=-\frac{5}{4}x-7 \\ f(x)=-\frac{5}{4}x-7 \end{gathered}[/tex]

So, y is the line which goes through the first and last points of the chart.

To proof that the rest of points go through the line as well, we will evalute each point

[tex]\begin{gathered} f(-5)=-\frac{5}{4}\cdot(-5)-7=\frac{25}{4}-7=-\frac{3}{4}\ne-7 \\ f(-1)=-\frac{5}{4}(-1)-7=\frac{5}{4}-7=-\frac{23}{4}\ne-12 \end{gathered}[/tex]

Since the evaluation of these points don't correspond to the values of the chart we can assure that the relationship is not linear

How do I find the area of different shapes? Is it the same exact as finding the area of a square?Please help! e.g. Trapezoid, Triangle, Octagon

Answers

Then area of each shape can be find ina different form. Each figure have a formula to find the area.

For example

Trapezoid:

[tex]A=\frac{1}{2}(B_1+B_2)\cdot h[/tex]

Where B1 is one of the bases and B2 the other base. h is the vertical height.

Triangle:

[tex]A=\frac{1}{2}(b\cdot h)[/tex]

b is the base and h is the vertical height.

Regular polygon:

[tex]A=\frac{P\cdot a}{2}[/tex]

P is the perimeter of the regular polygon and a is the apothem (the distance for the center of the polygon to the mind-point of a side.

15 Points and branliest for all three!​

Answers

According to SAS Congruence Theorem and the reflexive property of congruence, it can be proved  that ΔSPQ ≅ ΔTPQ.

It is given to us that -

PQ bisects ∠SPT

SP ≅ TP

We have to prove that ΔSPQ ≅ ΔTPQ

Now, as PQ bisects ∠SPT,

∠SPQ = ∠TPQ

Also, according to the Reflexive Property of Congruence, PQ is a common side of both triangles - ΔSPQ and ΔTPQ.

Thus, according to SAS Congruence Theorem,

"If two sides and the angle between these two sides are congruent to the corresponding sides and angle of another triangle, then the two triangles are congruent."

Therefore, according to SAS Congruence Theorem, we have proved that ΔSPQ ≅ ΔTPQ.

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Can you help me find the discriminant of this quadratic question aswell as the number and type of solutions?Problem: 2x^2+2=-5x

Answers

Given the quadratic equation:

[tex]2x²+2=-5x[/tex]

we can write it like this:

[tex]2x²+5x+2=0[/tex]

the discriminant is the expression b²-4ac. In this case, a = 2, b = 5 and c = 2, then, the discriminant is:

[tex]b²-4ac=(5)²-4(2)(2)=25-16=9[/tex]

notice that the discriminant is 9 > 0, therefore, the quadratic function has two real solutions

Graph g(x)= 2|x-2|-3 and the parent function f(x)=|x|. Describe the transformations that occurred from f(x) to g(x). Then, describe the domain and range.

Answers

The first thing to do is to graph both equations, as follows:

It is possible to check from the equations that there is no restriction for the value of x in both equations, and from the graph, we see that for each value of x, there is always a value of Y well defined. For this reason, we are able to conclude that the domain of both equations is all the real numbers.

Now, for the range of each, we can see that the values of Y for both are restricted to real numbers higher than the minimum value. For equation g(x), the range is the real numbers higher or equal to -3, while for f(x) the range is the real numbers higher or equal to 0.

Question 6 of 21Which of the following best describes the graph of the polynomial functiibelow?5Х-55-5-

Answers

Solution:

The zeros of a polynomial function are the points at which the graph of the function cuts the x-axis.

Given the graph of the polynomial function as shown below:

[tex]\begin{gathered} When\text{ the curve cuts the x-axis twice, this implies that the graph has 2 zeros.} \\ When\text{ the curve cuts the x-axis once, this implies that the graph has only 1 zero.} \\ \end{gathered}[/tex]

Since the curve on the graph cuts the x-axis once, it implies that the graph has one zero.

The correct option is D.

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