The component of horizontal velocity of bullet is 8m/s for 4 radians per second.
Given - Rotation rate = 4 rad per sec.
This means 4 radians for one seconds . i.e. one seconds is equivalent to 60min.
To resolve the velocity following equation can be employed-
[tex]\beta =vt+\frac{\alpha t^2}{2}\\ \\\beta = rotation\\\\v= velocity\\\\t= time\\\\\alpha =acceleration[/tex]
Now substituting all values in this equation
4= 0+α/2
α=4 x 2 ⇒8m/s²
since the rotation is for one seconds so velocity = acceleration.
[tex]acceleration=\frac{dv}{dt}[/tex]
dt =1
so α=v=8m/s
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What constant torque is required to bring it up to an angular speed of 400 rev/min in 8. 00 s , starting from rest?.
The required Torque would be 13.0895 Nm.
The force that can cause an object to rotate around an axis is measured in torque.
Similar to how force accelerates an object in linear kinematics, torque accelerates an object in an angular direction.
In rotational kinematics, torque takes the place of force in linear kinematics. There is a direct equivalent to Newton’s 2ⁿᵈ law of motion (F=maF=maF, equals, m, a),
[tex]\tau = I \alphaτ=Iαtau[/tex]= αI
Given,
Time (t) =8.00 sec
Ang Velocity (W) = 400 rev/min
Moment of Inertia (I) = 2.50 kg m²
As we know,
W=Wo+αt T
= αI
400 rev/min to rad/sec-
400 × 2π/60sec = 41.8876 rad/sec
41.8876 rad/sec = 0 + α(8 sec) α = 5.2358 rad/sec²
Torque, T=αI.
T=(5.2358)(2.50)
T=13.0895 Nm
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How can you determine the velocity of a runner from a position time graph?
Answer:
below
Explanation:
The slope of the position-time graph is the velocity at any point in time
The half-life of iodine-131 is 8.07 days. If 0.25 g are left after 40.35 days, how many gramswere in the original sample?
Given data
*The half-life of iodine-131 is t = 8.07 days
*The amount of quantity left is N = 0.25 g
*The number of days is T = 40.35 days
The expression for the radioactivity decay is given as
[tex]N=N_0(\frac{1}{2})^{\frac{T}{t}}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} \text{0}.25=N_0(\frac{1}{2})^{\frac{40.35}{8.07}} \\ N_0=8\text{ g} \end{gathered}[/tex]Answer:
See below
Explanation:
40.35 days / (8.07 day per half life) = 5 half lives
.25 = x ( 1/2)^5
.25 / ( 1/2)^5 = x = 8 gm originally
if you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, how far from the sensor is the lens?
If you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, the sensor is 1.087 m from the lens.
1 / f = 1 / v + 1 / u
f = Focal length
v = Image distance
u = Object distance
u = 3.9 m
f = 85 mm
f = 0.85 m
1 / v = 1 / f - 1 / u
1 / v = 1 / 0.85 - 1 / 3.9
1 / v = 3.05 / 3.315
v = 1.087 m
The sign convention for this formula is:
When the object is on the same side of the refracting surface as the incoming light, the value of u is taken as positive else taken as negative.When the image is on the same side of the refracting surface as the incoming light, the value of v is taken as positive else taken as negative.Therefore, the sensor is 1.087 m from the lens.
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12Question 17 (1 point)It's been said that "Dilution is the solution to pollution." Which of the following is anexample of this saying?✓15Gasoline leaks into a sewage system and is filtered out at the sewage treatmentplant.A doctor's office throws all their trash into the Atlantic Ocean. Waves andcurrents wash it all ashore.18An camper washes her dishes then dumps the water into a large river.Mercury is absorbed into fish and humans eat the fish.1
detectableThe solution to pollution is not dilution. That is, due to the low levels
of contaminants in the effluent and the high volume cmd rate of flow in the St.
Clair River, most substances would be dispersed to the point of undetectability
within ten metres or so, If the contaminants were still decte after ten
kilometres. for example, that would be considered using dilution as a solution.
Since ICI trecrts the waste water before it is released. and with the mixhg zones
ço small, Lusby is confident thd the discharge is hdess because the
concentration is extremely low
What is the si unit of mass and length
Answer:
Mass: Kg (kilogram)
Length: M (meter)
A 1,470.39 N rocket travels at constant speed for 1,522.64m in 2.11 seconds. What is the kinetic energy of the rocket?
Given data:
* The weight of the rocket is 1470.39 N.
* The distance traveled by the rocket is 1522.64 m.
* The time taken by the rocket is 2.11 seconds.
Solution:
The velocity of the rocket in terms of the distance and time is,
[tex]\begin{gathered} v=\frac{\text{distance}}{\text{time}} \\ v=\frac{1522.64}{2.11} \\ v=721.63\text{ m/s} \end{gathered}[/tex]The mass of the rocket from the weight is,
[tex]\begin{gathered} mg=1470.39 \\ m=\frac{1470.39}{g} \end{gathered}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} m=\frac{1470.39}{9.8} \\ m=150.04\text{ kg} \end{gathered}[/tex]The kinetic energy of the rocket in terms of mass and velocity of the rocket is,
[tex]\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times150.04\times721.63^2 \\ K=39066654.26\text{ J} \\ K=39.07\times10^6\text{ J} \\ K=39.07\text{ MJ} \end{gathered}[/tex]Thus, the kinetic energy of the rocket is 39.07 MJ.
The average kinetic energy
of the particles in matter?
The average kinetic energy of the substance's particles is its temperature.
What is average kinetic energy?The average kinetic energy of a substance's particles is inversely correlated with that substance's temperature, according to the kinetic-molecular hypothesis.
When a substance is heated, some of the energy received is retained by the particles, while other energy quickens the motion of the particles. The material's temperature increases as a result of this.
The average kinetic energy of a substance's particles is directly proportional to the substance's temperature. These particles must move more quickly as the temperature rises because their mass is constant.
Lowering the system's temperature causes a decrease in a particle's kinetic energy.
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The mass of a bike and cyclist is 75.0 kg. The rider starts at rest at a height of Om. She speeds up to 6.00 m/s. What is the mechanical energy of thebike?The answers would be one of the four choices in the pictures.
Given that the mass of the bike and cyclist is m = 75 kg and the velocity is v = 6 m/s. The height is h= 0 m
Mechanical energy is the sum of kinetic energy and potential energy.
The kinetic energy is given by the formula
[tex]\begin{gathered} K.E\text{. =}\frac{1}{2}mv^2 \\ =\frac{1}{2}\times75\times(6)^2 \\ =1350\text{ J} \end{gathered}[/tex]The potential energy is given by the formula,
[tex]\begin{gathered} P\mathrm{}E\mathrm{}=\text{mgh} \\ =75\times9.8\times0 \\ =0\text{ J} \end{gathered}[/tex]Here, g = 9.8 m/s^2 and is the acceleration due to gravity.
The mechanical energy will be
[tex]\begin{gathered} E=\text{ 1350 J+0 J} \\ =1350\text{ J} \end{gathered}[/tex]Objects with smaller masses have more gravitational energy than objects with larger masses. True or false?
Answer:
False
Explanation:
The greater the size of the mass, the greater the size of the gravitational force/energy.
4. A car has a mass of 1,350 kg. A driver travels on a level road with an acceleration of 4.7 m/s.What force, neglecting friction, must be exerted to achieve this accelerations?
We have to use Newton's Second Law
[tex]F=ma[/tex]Where m = 1,350 kg and a = 4.7 m/s2.
[tex]\begin{gathered} F=1,350\operatorname{kg}\cdot\frac{4.7m}{s^2} \\ F=6,345N \end{gathered}[/tex]Hence, the force exerted is 6,345 Newtons.A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s
Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
Question 9 of 10: you purchased $100 each of three different stocks in january. stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value. what was the overall net percentage of gain in the three stocks? (round to the nearest percent.)
The overall net percentage of gain in the three stocks purchased each with $ 100 in which stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value is 8.3 %
Value of Stock a = 100 + 30%
Value of Stock a = $ 130
Value of stock b = 100 + 15%
Value of stock b = $ 115
Value of stock c = 100 - 20%
Value of stock c = $ 80
Net percentage gain = ( Net profit / Total investment - 1 ) * 100
Net profit = 130 + 115 + 80
Net profit = $ 325
Total investment = 100 + 100 + 100
Total investment = $ 300
Net percentage gain = ( 325 / 300 - 1 ) * 100
Net percentage gain = ( 0.083 ) * 100
Net percentage gain = 8.3 %
Therefore, the the overall net percentage of gain in the three stocks is 8.3 %
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In order to have kinetic energy an object must be
1.moving
2. At rest
3.rigid
4.elevated
Geremy rolled a can of soup off the kitchen table. The can landed 0.75m from the table. The height of the table is 1.35m. At what velocity did Geremy roll the can horizontally?
Please show all work, thank you
The velocity used by Geremy to roll the can horizontally is 1.44 m/s
How do I determine the horizontal velocity used by Geremy?First we shall obtain the time taken for the can to reach the ground. This is shown below:
Height (h) = 1.35 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
1.35 = ½ × 9.8 × t²
1.35 = 4.9 × t²
Divide both side by 4.9
t² = 1.35 / 4.9
Take the square root of both side
t = √(1.35 / 4.9)
t = 0.52 second
Finally, we shall determine the velocity used by Geremy to roll the can horizontally. Detail below:
Horizontal distance (s) = 0.75 mTime (t) = 0.52 secondHorizontal velocity (u) = ?s = ut
0.75 = u × 0.52
Divide both sides by 0.52
u = 0.75 / 0.52
u = 1.44 m/s
Thus, we can conclude that the horizontal velocity used is 1.44 m/s
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what is the mass of a hiker 350m above the ground if her GPE is 120,200 J?
Given:
The height from the ground is h = 350 m
The gravitational potential energy is GPE = 120,200 J
To find the mass of the hiker.
Explanation:
The mass of the hiker can be calculated by the formula
[tex]\begin{gathered} GPE\text{ =mgh} \\ m\text{ =}\frac{GPE}{gh} \end{gathered}[/tex]Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the mass of the hiker will be
[tex]\begin{gathered} m\text{ =}\frac{120200}{9.8\times350} \\ =35.044\text{ kg } \end{gathered}[/tex]Thus, the mass of the hiker is 35.044 kg
what is the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth its weight?
the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth of its weight is 7.35m/s²
We know from newton's second law
sum of forces = ma
here, the forces are weight (down) and resistance (up)
choosing down as the positive direction, we have
weight - resistance = ma
mg - [tex]\frac{1}{4}[/tex](mg)=ma
[tex]\frac{3}{4}[/tex] mg = ma or a = [tex]\frac{3}{4}[/tex] g =7.35m/s²
The net pressure is defined as the sum of all the forces appearing on an item. internet force can boost up a mass. some different pressure acts on a body either at relaxation or movement. Internet forces is a term utilized in a system while there may be an extensive range of forces.
the net pressure is the vector sum of forces performed on a particle or object. The internet pressure is an unmarried force that replaces the impact of the unique forces on the particle's motion. It gives the particle equal acceleration as all those actual forces collectively as defined via Newton's 2nd law of motion.
it's miles possible to decide the torque related to the factor of application of an internet pressure so that it maintains the movement of jets of the object below the original machine of forces. Its related torque, the net pressure, turns into the consequent force and has an identical impact on the rotational motion of the object as all actual forces have taken together.
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the beam is balanced use the principle of moments to calculate the weight, W, of the monkey in newtons.
the objects weight on the left is 350N and the distance from the pivot is 20m. the second object on the right weight is x and distance from the pivot is 1.5m
Answer:
below
Explanation:
350 * 20 has to equal x * 1.5
350 * 20 = 1.5 x
x = 4666.7 N
I need help with this question someone
The properties of group 18 elements, also referred to as noble gases or group 8 elements.
Eight valence electrons make them up.
They have enough electrons in their octet, therefore they don't need any more (stable).
are steady
Noble gases are those that are not reactive.
Why do elements desire to create ions?In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.
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how do astronomers currently think the amount of detectable (observable) matter in the universe compares to the amount of dark matter and dark energy?
Astronomers think the amount of detectable matter as one of some hundred thousand million out of which some are compared and contrasted with the help of modern telescopes.
In 1920 when astronomers began to study the spectra of stars in other galaxies , they found something most peculiar. There were same characteristic sets of missing colours as for stars in galaxy. But they were shifted by some relative amount towards red end of spectrum.The present rate of expanding universe has some resolutions in thermodynamics as the third law states "entropy of universe keeps increasing" , where entropy states the randomness of the universe.Some non luminous material that is believed to exist in space and have the ability to take any several forms including the weakly interacting particles , further having classification of hot dark matter and cold dark matter. Gravity has its field in every particle due to which the stability is maintained with centrifugal force. Something pairing to oppose this fundamental force or field is the dark energy that is negative in nature. And this is responsible for slowing the rate of expansion of universe.[tex]Dark. energy= \frac{\alpha }{\beta } \\\\\alpha =pressure \\\\\beta =energy-Density[/tex]
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Greenhouse A. Open system B. Closed system C. Isolated system
In an open system, both energy and matter are exchanged with the surroundings.
In a closed system, only energy is exchanged with the surroundings.
In an isolated system, neither matter nor energy is exchanged with the surroundings.
In the greenhouse, only energy is exchanged with the surroundings.
Thus, the greenhouse is a closed system.
Look at the following transformer. The source of electricity is on the left. Therefore, the primary coil is on the left, and the secondary is on the right.
A. How much the primary current ?
B. For the above transformer what is the output power if it is only 85% efficient?
C. How much the secondary voltage?
The primary current of transformer is 9A, the secondary voltage is 63.75 V and the output power at 85% efficiency is 650.25 VA.
(a) Turns of primary coil (N₁) = 400
Turns of secondary coil (N₂) = 300
Current on secondary coil (I₂) = 12 A
Current on primary coil (I₁) =
= using transformer equation,
= N₁ × I₁ = N₂ × I₂
= I₁ = (300 ×12) / 400
= I₁ = 9 A
(b) Voltage of primary coil (V₁) = 85 V
Current on secondary coil (I₂) = 12 A
Power on primary coil (P₁) =
= P₁ = V₁ × I₁
= P₁ = 85 × 9
= P₁ = 765 VA
However, if the efficiency of the transformer is 85% then,
= 85 = (P₂ / P₁ ) × 100
= 0.85 × 765 = P₂
= P₂ = 650.25 VA
(c) Voltage of primary coil (V₁) = 85 V
Current on secondary coil (I₂) = 12 A
Current on primary coil (I₁) = 9 A
Voltage on secondary coil (V₂) =
= using transformer equation,
= I₁ × V₁ = N₂ × I₂
= V₂ = (85 × 9) / 12
= V₂ = 63.75 V
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The length of an iron rod is measures by a brass scale. When both of them are at 10°C, the measured length is 50cm. What is the length of the rod at 40°C when measured by the brass scale at 40°C.? (a for brass=24x10-6°C, a for iron = 16x10 °C -¹)
Answer: The answer is 222.8
A dog walks 12 meters to the east and then 16 meters back to the west. For this motion, what is the distance moved?.
The total distance moved by the dog is 28meters while the magnitude of the displacement is 4 meters. Moreover, The direction of the displacement is zero degrees.
In Physics, Distance refers to the motion of an object in any direction while displacement is defined as the total distance traveled in a particular direction.
If a dog walks 12 meters to the east and then 16 meters back to the west, then the total distance covered will be calculated as:
Distance moved = 12m (East) + 16m (West)
Total Distance moved = 28 meters [East + West]
Now let's calculate the displacement.
Distance covered towards east (fro origin) = + 12 meters
Distance covered towards west (fro origin) = - 16metres
Displacement = -16 + 12
Displacement = - 4meters (-ve sign represents direction)
|D| = 4 meters
Thus, the magnitude of the displacement is 4 meters
Since the direction of movement is along the x-axis, therefore the direction is zero degrees.
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The complete question is:
A dog walks 12 meters to the east and then 16 meters back to the west.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
Mix a liter of 20°C water with 2 liters of 30°C water and you’ll have 3 liters of water at?
We can solve this question by using the principle of calorimetry.
The density of water is 1000 kg/m^3
According to the principle of calorimetry,
Heat lost by hot body = Heat gained by the cold body.
This principle is based on conservation of energy.
Let assume that the final temperature is t(f).
So,
[tex]\begin{gathered} Q=mc\Delta t \\ Where,\text{ } \\ Q=Heat \\ m=mass \\ c=Specific\text{ }heat\text{ }capacity \\ \Delta t=Change\text{ }in\text{ }temperature \end{gathered}[/tex]For two liter of water the final temperature is t(f) and initial temperature is 30°celcius,
So here the water will lose heat because it is at higher temperature,
[tex]\begin{gathered} Heat\text{ loose by the water is,} \\ Q=mc\Delta t=1000\times2\times c\times[t(f)-30] \end{gathered}[/tex]And for 1 liter of water the gain in heat is,
[tex]Q=mc\Delta t=1000\times1\times c\times[t(f)-20][/tex]Now,
[tex]\begin{gathered} Q\text{ }lose=Q\text{ }gain \\ -1000\times2\times c\times[t(f)-30]=1000\times1\times c\times[t(f)-20] \\ -2\times[t(f)-30]=[t(f)-20] \\ -2t(f)+60=t(f)-20 \\ -3t(f)=-20-60 \\ t(f)=\frac{80}{3}=26.667\mathring{\text{ }}celcius \end{gathered}[/tex]So the final temperature of the 3 liter water = 26.667 degree cus.
How much pressure does a box whose sides are 1.44 m long each exert on the ground due to gravity?Assume that the box has a mass of 17.3 kg. HINT: Look at the definition of pressure - what force is doing the "pushing?" What's the area?
Pressure = Force / area
m= mass = 17.3 kg
g= gravity = 9.8 m/s^2
Force = m * g = 17.3 kg * 9.8 m/s^2 = 169.54 N
P = F / A
A = area = 1.44^2 = 2.0736 m^2
P = 169.54 N/ 2.0736 m^2 = 81.76 Pa
what would happen to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled? group of answer choices
If the spacing between the slits is doubled, then the distances between bright spots (intensity maxima) on the screen will become half
From the young double slit experiment, we come up with a formula which is : β = λD/d, where β is the fringe width, λ is the wavelength of the light rays, D is the distance between the screen and the source of the rays, and the d is the distance between the two slits. here the distance between the two bright spots is also called the bandwidth. If d is doubled then the value of β will be halved.
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A roller coaster car is cresting a hill at 10 m/s . if the hill has a 30 m radius, what force will the 70 kg rider feel from the seat of the coaster? (the seat force is the normal force)
Answer:
A 53.5-kg rider on a roller coaster car is moving 10.3 m/s at the top of a loop which has a radius of curvature of 7.29 m.
Explanation:
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. What is the equal and opposite force for the force of the boy pulling on the bone as described by newton's third law?.
The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. There is no net force. Each dog exerts an equal amount of force in opposing directions, which causes the combined force to cancel out.
Newton's third law :
When one body applies pressure to another, the first body feels pressure that is equal to the applied pressure but applied in the opposite direction.Fa = - Fb force exerted on a body is equal and opposite to the force exerted on another body.The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
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answer for 27. i understand the concept just want to confirm the answer
In a vacuum x-rays and microwaves have the same velocity but different wavelengths.
Correct option: D. the same