a) The percentage of total production will the company expect to replace is of 6.62%.
b) The guarantee period should be of 23 months.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation for the duration of the watches are given as follows:
[tex]\mu = 30, \sigma = 4[/tex]
The proportion of watches that will be replaced are those that last less than 2 years = 24 months, hence it is given by the p-value of Z when X = 24, as follows:
Z = (24 - 30)/4
Z = -1.5.
Z = -1.5 has a p-value of 0.0662.
Hence the percentage is of 6.62%.
For item b, the guarantee period should be the 6th percentile, which is X when Z = -1.555, hence:
-1.555 = (X - 30)/4
X - 30 = -1.555 x 4
X = 23 months.
More can be learned about the normal distribution at https://brainly.com/question/25800303
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Choose and evaluate an exponential expression that models the situation.A 1-inch vine begins tripling its length every week. After the first week, the length of the vine is3 inches. After the second week, the length is 9 inches. If this growth pattern continues, howlong will the vine be in 6 weeks?See image below for answer options.
The pattern is:
3
3x3
3x3x3
and so on
So it's 3^6 = 729
Answer: the second option
What is the density, in grams/cubic inch, of a substance with a mass of 6 grams filling a rectangular box with dimensions 2 in x 6 in x 3 in?6 8 0.11 0.17
Consider tha the density is calculated by using the following formula:
[tex]D=\frac{M}{V}[/tex]D is the density, M is the mass and V the volume. In this case, you have;
M = 6 g
V = 2 in x 6 in x 3 in = 36 in^3
Replace the previous values of the parameters into the formula for D:
[tex]D=\frac{6g}{36in^3}\approx0.17\frac{g}{in^3}[/tex]Hence, the density of the given substance is approximately 0.17 g/in^3
In Seattle, the tax on a property assessed at $500,000 is $9,000. If tax rates are proportional in this city, how much would the tax be on a property assessed at $1,000,000?
Answer:
$18,000
Explanation:
Let us represent the tax by y and the property value by x. If the tax is proportional to the property value, then the relationship between y and x is the following.
[tex]y=kx[/tex]where k is the constant of propotionality.
Now, to paraphrase, we are told that when y = $9,000, then x = $500,000. This means
[tex]9000=k(500,000)[/tex]and we need to solve for k.
Dividing both sides by 9000 gives
[tex]k=\frac{9,000}{500,000}[/tex]which simplifies to give
[tex]\boxed{k=\frac{9}{500}.}[/tex]With the value of k in hand, our formula now becomes
[tex]y=\frac{9}{500}x[/tex]We can now find the tax when x = 1,000,000.
Putting in x = 1,000,000 into the above formula gives
[tex]y=\frac{9}{500}(1,000,000)[/tex]which simplifies to give
[tex]\boxed{y=18,000.}[/tex]This means, the tax on a property assessed at $1,000,000 is $18,000.
I have to write the equation in slope intercept form. i need help, please. thank you
step 1
find the slope
we have the points
(-6,10) and (-3,-2)
m=(-2-10)/(-3+6)
m=-12/3
m=-4
step 2
find the equation in point slope form
y-y1=m(x-x1)
we have
m=-4
(x1,y1)=(-6,10)
substitute
y-10=-4(x+6)
step 3
convert to slope intercept form
isolate the variable y
y-10=-4x-24
y=-4x-24+10
y=-4x-14
what will be the cost of material if the volume is 180in^3 and the surface area is 258in^2 and the cardboard cost $0.05 per square inch.cost of material is?
A material in the shape of a rectangular prism (cuboid) is given.
The volume and the surface area are given to be 180in³ and 258in², respectively. The cost of the material per square inch is given to be $0.05.
It is required to find the cost of the material.
To do this, since the cost per square inch is given, multiply the surface area by the cost per square inch:
[tex]258\times0.05=\$12.9[/tex]The cost of the material is $12.9.
what is the distance between A and B B(4,5) A(-3,-4)
11.40 units
Explanation
Step 1
you can easily find the distance between 2 points using:
[tex]\begin{gathered} d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ \text{where} \\ P1(x_1,y_1)\text{ and } \\ P2(x_2,y_2) \end{gathered}[/tex]Step 2
Let
A=P1(-3,-4)
B=P2(4,5)
Step 3
replace
[tex]\begin{gathered} d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ d=\sqrt[]{(5-(-4))^2+(4-(-3))^2} \\ d=\sqrt[]{(9)^2+(7)^2} \\ d=\sqrt[]{81+49} \\ d=\sqrt[]{130} \\ d=\text{11}.40 \end{gathered}[/tex]I hope this helps you
In the form (x+4)(x-2)=1, the zero-factor property can or cannot be used to solve equation?
The zero-factor property is
[tex](x+a)(x+b)=0[/tex]Then we equate each factor by 0 and find the values of x
The given equation is
[tex](x+4)(x-2)=1[/tex]Since the right side is not equal to 0, then
We can not use the zero-factor property to solve the equation
The answer is
zero-factor property cannot be used
Can you help me with number 14? Thank you I am having trouble with it.
To solve number 14, we will make use of the Law of Cosines, which states that:
[tex]=\sqrt[]{^2+^2^{}-2\cos}[/tex]As in our problem b = 15, c = 13 and A = 95°,we can replace these values in the formula and solve for a:
[tex]=\sqrt[]{15^2+13^2-2\cdot(15\cdot13)\cos 95}[/tex][tex]=\sqrt[]{15^2+13^2-390\cos 95}[/tex][tex]a\approx20.69[/tex]In our case, a is the segment BC.
Answer: 20.7
TIME SENSITIVE The first step in solving this equation is to (BLANK) the second step is to (BLANK) solving this equation for X initially yields (BLANK) checking solution shows that (BLANK= 0 and 2 are valid solutions)
Give
[tex](4x)^{\frac{1}{3}}-x=0[/tex]
Procedure
The first step in solving this equation is to add x to both sides
[tex](4x)^{\frac{1}{3}}=x[/tex]The second step is to cube both sides
[tex]4x=x^3[/tex]solving this equation for X initially yields in three solutions
[tex]\begin{gathered} x(4-x^2)=0 \\ x(2-x)(2+x)=0 \end{gathered}[/tex]checking solution shows that x = 0, x = -2 and x = 2
If the equation 6X equals 84, what is the next step in the equation solving sequence?
Answer: We have to find the next solution step for the following equation:
[tex]6x=84[/tex]The solution steps are:
[tex]\begin{gathered} 6x=84 \\ \\ \text{ Divide both sides by 6} \\ \\ \frac{6x}{6}=\frac{84}{6}\Rightarrow x=\frac{84}{6}=14 \\ \\ x=14 \end{gathered}[/tex]Hello, I need help on the following question (it’s one problem but with multiple parts):
Part i. We are told that the cost for 3 throws is 1 dollar. This means that if "x" is the number of throws then the total cost must be:
[tex]C(x)=\frac{1\text{ dollar}}{3\text{ throws}}x[/tex]We can rewrite it in a simpler form as:
[tex]C(x)=\frac{1}{3}x[/tex]If we purchased the armband then this cost is equivalent to (1/6) of a dollar per throw plus the cost of the armband, we get:
[tex]C_2(x)=\frac{1}{6}x+10[/tex]Part ii. The graph of the two equations are two lines in the plane, like this:
In the graph, the red line represents the cost without the armband and the blue line represents the cost with the armband.
Part iii. We can see from the graph that if the number of throws is smaller than 60, then the cost is smaller without the armband, but if the cost is greater than 60 then the cost is smaller with the armband. Therefore, it makes sense to buy the armband if the number of throws is going to be greater than 60.
Problem ID: PRABDN8J Use what you know about exponential notation to complete the expressions below. (-5) X -X(-5) = 17 times Use the ^ symbol to represent an exponent. For example: (-5)2 should be typed as (-5)^2 engage Type your answer below (numeric expression Submit Answer
Since (-5)2 using the exponential symbol can be written as (-5)^2
This means -5 in 2 places
(-5)X, using the exponential symbol, can be written as (-5)^X
X(-5), using the exponential symbol can be written as X^(-5)
Therefore:
(-5)X - X(-5) = 17, in exponential form, can be written as:
(-5)^X - X^(-5) = 17
[tex](-5)^X-X^{-5}=\text{ 17}[/tex]make a triangular garden in the backyard. you know that one side of your yard (ac) is 100 yards long and another side (ab) is 250 yards. in order for the garden to fit and not cross into the neighbor's yard, what must be the measure of angle b if angel c measures 95 degrees?
Law of sines for the given triangle:
[tex]\frac{AC}{\sin B}=\frac{AB}{\sin C}[/tex]Use the equation above and the given data to solve angle B:
[tex]undefined[/tex]20. You want to take your family on a two week vacation this summer, which is 5 months away The total cost for the vacation is $2,245. You work extra hours at your job at $11.25 per hour. Fifteen percent of your earnings go to taxes, and the rest goes toward the expenses for this vacation. Over next five months, what is the fewest number of extra hours per month you could work and still me enough money to take this vacation? A 35 ( C. 47 E.235 8.40 D. 200 AIS rregues stepl. In this ques we are given that guastotares family to go for at Vacation this summes need atat sum 15 Then, you need to hours at your sub this vacation
Assuming that all 5 months have 30 working days.
Let us assume that you need to do 'x' hours per month to get the extra money for vacation.
Given that overtime wage is $11.25 per hour, the wage (in $) for monthly overtime is obtained as,
[tex]\begin{gathered} \text{Monthly Overtime Wage}=\text{ Monthly overtime hours}\times\text{ Wage per hour} \\ \text{Monthly Overtime Wage}=x\times11.25 \\ \text{Monthly Overtime Wage}=11.25x \end{gathered}[/tex]Then the total amount (TA) earned in 5 months of overtime work is calculated as,
[tex]\begin{gathered} \text{ Total Amount}=\text{ Amount per month}\times\text{ No. of months} \\ \text{Total Amount}=11.25x\times5 \\ \text{Total Amount}=56.25x \end{gathered}[/tex]Given that the 15% of this amount earned goes for the tax, so the net amount earned is given by,
[tex]\begin{gathered} \text{Net Amount Earned}=(1-\frac{15}{100})\times56.25x \\ \text{Net Amount Earned}=(\frac{85}{100})\times56.25x \\ \text{Net Amount Earned}=47.8125x \end{gathered}[/tex]This net amount must be sufficient to cover the total cost of vacation $2245,
[tex]\begin{gathered} \text{ Net Amount Earned}=\text{ Expense on vacation} \\ 47.8125x=2245 \\ x=\frac{2245}{47.8125} \\ x=46.95 \\ x\approx47 \end{gathered}[/tex]Thus, you have to work 47 hours of overtime monthly to cover the cost of the vacation in 5 months.
Answer:
this guy is right
Step-by-step explanation:
pls help i give brainliest
Answer: They bought 2 adult tickets and 3 children's tickets.
Step-by-step explanation: If you multiply the adult tickets, (5.10,) by 2, and then multiply the children's tickets (3.6), you will then add the products together. Your answer should come up as 21.00 dollars.
help me to complete this please help me help help help help help help help help
Hello
To solve this question, we just have to find 40% of 90
[tex]\begin{gathered} \frac{40}{100}=\frac{x}{90} \\ 0.4=\frac{x}{90} \\ x=90\times0.4 \\ x=36 \end{gathered}[/tex]From the calculations above, the castle has 36 girls present
In 9-16, estimate each product. 9. 0.12 x 105 10. 45.3 x 4 11. 99.2 x 82 12. 37 x 0.93 13. 1.67 X4 14. 3.2 x 184 15. 12 x 0.37 16. 0.904 x 75
9.
[tex]\begin{gathered} 0.12\cdot105=12.6 \\ 10.\text{ 45.3}\cdot4=181.2 \\ 11.\text{ 99.2}\cdot82=8134.4 \\ 12.\text{ 37}\cdot0.93=34.41 \\ 13.\text{ 1.67}\cdot4=6.68 \\ 14.\text{ 3.2}\cdot184=588.8 \\ 15.\text{ 12}\cdot0.37=4.44 \\ 16.\text{ 0.904}\cdot75=67.8 \end{gathered}[/tex]Solve the system of equations.−2x+5y =−217x+2y =15
To solve this question we will use the elimination method.
Adding 7 times the first equation to 2 times the second equation we get:
[tex]14x+4y+(-14x)+35y=30+(-147)\text{.}[/tex]Simplifying the above equation we get:
[tex]4y+35y=-117.[/tex]Solving for y we get:
[tex]\begin{gathered} 39y=-117, \\ y=-\frac{117}{39}, \\ y=-3. \end{gathered}[/tex]Substituting y=-3 in the first equation, and solving for x we get:
[tex]\begin{gathered} -2x+5(-3)=-21, \\ -2x-15=-21, \\ -2x=-6, \\ x=3. \end{gathered}[/tex]Answer:
[tex]\begin{gathered} x=3, \\ y=-3. \end{gathered}[/tex]An isosceles triangle has an angle that measures 128°. Which other angles could be in that Isosceles triangle? Choose all that apply.
Given:
Given angle is 128 degree.
In Isosceles triangle two angles are equal.
Let the angle be x.
Sum of the angles in a triangle is 180 degree.
[tex]\begin{gathered} 128+x+x=180 \\ 2x=180-128 \\ 2x=52 \\ x=26^{\circ} \end{gathered}[/tex]Other angles in an Isosceles triangle is 26 degree.
find the average rate of change from x= -2 to x =1
We have the graph of a function of third grade and need to find the average rate of change between x=-2 and x=1.
We can see that:
[tex]\begin{gathered} \text{The rate of change is:} \\ \frac{dy}{dx} \\ \end{gathered}[/tex]So, the average between x=-2 and x=1 is:
[tex]undefined[/tex]2,-2,-6,-10,-14, ...how do I go about finding the explicit formula?
According to the given sequence, the difference is -4, because it's decreasing with that difference: 2-2 = -2; -2-4 = -6; and so on.
To find the explicit formula, we use the arithmetic sequence formula.
[tex]a_n=a_1+(n-1)d[/tex]Replacing all the given information, we have.
[tex]\begin{gathered} a_n=2+(n-1)\cdot(-4) \\ a_n=2-4n+4 \\ a_n=6-4n \end{gathered}[/tex]This explicit formula we can also express as
[tex]f(n)=6-4n[/tex]Given P = 2L + 2W. Solve for W if P = 52 and L 18 W
First begin by making w the subject of formula
p = 2l + 2w
p-2l = 2w ( moving 2l to the left hand side )
[tex]\begin{gathered} \\ \frac{p\text{ - 2l}}{2}\text{ = w ( now we've made w the subject )} \end{gathered}[/tex]next substitute in your values p = 52 and l = 18
[tex]w\text{ = }\frac{p\text{ - 2l}}{2}\text{ = }\frac{52\text{ - 2(18)}}{2}\text{ = }\frac{52\text{ - 36}}{2}\text{ = }\frac{16}{2}\text{ = 8}[/tex]
Therefore the value for w in the expression is 8
Evaluate the equation: -9w = -54
Solution:
Given the equation:
[tex]-9w=-54[/tex]To solve for the unknown (w), we divide both sides of the equation by the coefficient of w.
The coefficient of w is -9.
Thus,
[tex]\begin{gathered} -\frac{9w}{-9}=-\frac{54}{-9} \\ \Rightarrow w=6 \end{gathered}[/tex]Hence, the value of w is
[tex]6[/tex]A game center has a $5 admission fee and charges $0.50 for each game played. Graph the equation on the coordinate plane. Be sure to label the axes appropriately and provide a scale for the axes.
A game center has a $5 admission fee (this is the y-intercept of the equation)
It charges $0.50 for each game played (this is the slope of the equation)
The equation can be written as
[tex]y=0.50x+5[/tex]Where y is the cost and x is the number of games played.
To plot the graph, you can either find some (x, y) coordinates using the above equation.
Or you can plot it using the concept of slope and y-intercept.
Start at the point of y-intercept (0, 5)
The slope is 0.50 = 1/2
Then go 1 unit up and two units to the right that is your next point.
Repeat the same, 1 unit up and two units to the right that is your next point and so on...
Let us plot the graph
Scale: one small box = 1 unit
x-axis = number of games
y-axis = Cost ($)
Find the center that eliminates the linear terms in the translation of 4x^2 - y^2 + 24x + 4y + 28 = 0.(-3, 2)(-3,- 2)(4, 0)
Step 1
Given;
[tex]4x^2-y^2+24x+4y+28=0[/tex]Required; To find the center that eliminates the linear terms
Step 2
[tex]\begin{gathered} 4x^2-y^2+24x+4y=-28 \\ 4x^2+24x-y^2+4y=-28 \\ Complete\text{ the square }; \\ 4x^2+24x \\ \text{use the form ax}^2+bx\text{ +c} \\ \text{where} \\ a=4 \\ b=24 \\ c=0 \end{gathered}[/tex][tex]\begin{gathered} consider\text{ the vertex }form\text{ of a }parabola \\ a(x+d)^2+e \\ d=\frac{b}{2a} \\ d=\frac{24}{2\times4} \\ d=\frac{24}{8} \\ d=3 \end{gathered}[/tex][tex]\begin{gathered} Find\text{ the value of e using }e=c-\frac{b^2}{4a} \\ e=0-\frac{24^2}{4\times4} \\ e=0-\frac{576}{16}=-36 \end{gathered}[/tex]Step 3
Substitute a,d,e into the vertex form
[tex]\begin{gathered} a(x+d)^2+e \\ 4(x+_{}3)^2-36 \end{gathered}[/tex][tex]\begin{gathered} 4(x+3)^2-36-y^2+4y=-28 \\ 4(x+3)^2-y^2+4y=\text{ -28+36} \\ \\ \end{gathered}[/tex]Step 4
Completing the square for -y²+4y
[tex]\begin{gathered} \text{use the form ax}^2+bx\text{ +c} \\ \text{where} \\ a=-1 \\ b=4 \\ c=0 \end{gathered}[/tex][tex]\begin{gathered} consider\text{ the vertex }form\text{ of a }parabola \\ a(x+d)^2+e \\ d=\frac{b}{2a} \\ d=\text{ }\frac{4}{2\times-1} \\ d=\frac{4}{-2} \\ d=-2 \end{gathered}[/tex][tex]\begin{gathered} Find\text{ the value of e using }e=c-\frac{b^2}{4a} \\ e=0-\frac{4^2}{4\times(-1)} \\ \\ e=0-\frac{16}{-4} \\ e=4 \end{gathered}[/tex]Step 5
Substitute a,d,e into the vertex form
[tex]\begin{gathered} a(y+d)^2+e \\ =-1(y+(-2))^2+4 \\ =-(y-2)^2+4 \end{gathered}[/tex]Step 6
[tex]\begin{gathered} 4(x+3)^2-y^2+4y=\text{ -28+36} \\ 4(x+3)^2-(y-2)^2+4=-28+36 \\ 4(x+3)^2-(y-2)^2=-28+36-4 \\ 4(x+3)^2-(y-2)^2=4 \\ \frac{4(x+3)^2}{4}-\frac{(y-2)^2}{4}=\frac{4}{4} \\ (x+3)^2-\frac{(y-2)^2}{2^2}=1 \end{gathered}[/tex]Step 7
[tex]\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 \\ \text{This is the }form\text{ of a hyperbola.} \\ \text{From here } \\ a=1 \\ b=2 \\ k=2 \\ h=-3 \end{gathered}[/tex]Hence the answer is (-3,2)
Sara made an error in solve the one-step equation below.5x + 9 = 29-9 -9- 4x = 29/4. /4x = -7.25What is the error that Sara made?What should Sara had done to solve the one-step equation above insteadof what she did?What is the answer that Sara should have found for the above one-step equation?*
To solve this one-step equation you:
1. Substract 9 in both sides of the equation:
In this step is the mistake as Sara gets as result -4x=29 and the corret result of substract 9 in both sides of the equation is 5x=20.2. Divide both sides of the equation into 5:
Then, the answer that Sara should found for the equation is x=4A veterinarian is enclosing a rectangular outdoor running area against his building for the dogs he cares for (see image). He wants to maximize the area using 108 feet of fencing.
ANSWER
The width that will give the maximum area is 27 feet. The maximum area is 1458 square feet.
EXPLANATION
The equation that gives the area is a quadratic function,
[tex]A(x)=x(108-2x)[/tex]To find the width that maximizes the area, we have to find the x-coordinate of the vertex of this parabola. We can observe in the equation that the leading coefficient is -2, so the vertex is the maximum.
First, apply the distributive property to write the equation in standard form,
[tex]A(x)=-2x^2+108x[/tex]The x-coordinate of the vertex of a parabola if the equation is in standard form is,
[tex]\begin{gathered} y=ax^2+bx+c \\ \\ x_{vertex}=\frac{-b}{2a} \end{gathered}[/tex]In this case, b = 108 and a = -2,
[tex]x_{vertex}=\frac{-108}{-2\cdot2}=\frac{108}{4}=27[/tex]Hence, the width that will give the maximum area is 27 feet.
To find the maximum area, we have to find A(27),
[tex]A(27)=27(108-2\cdot27)=27(108-54)=27\cdot54=1458[/tex]Hence, the maximum area is 1458 square feet.
Find the difference. Express the answer in scientific notation.(4.56 times 10 Superscript negative 13 Baseline) minus (1.17 times 10 Superscript negative 13)3.39 times 10 Superscript negative 265.73 times 10 Superscript negative 263.39 times 10 Superscript negative 135.73 times 10 Superscript negative 13
Given:
given expression is
[tex](4.56\times10^{-13})-(1.17\times10^{-13})[/tex]Find:
we have to elavuate the difference and write the answer in scientific notation.
Explanation:
we will evaluate the expression as follows
[tex](4.56\times10^{-13})-(1.17\times10^{-13})=(4.56-1.17)\times10^{-13}=3.39\times10^{-13}[/tex]Therefore, correct option is
[tex]3.39\times10^{-13}[/tex]identify the same-side interior angles. Choose all the Apply<3 & <4<3 & <5<3 & <6<3 & <8
The same-side interior angles are also called consecutive interior angles. They are non-adjacent interior angles that lie on the same side of the transversal (in this case, t). Then, we have that these angles are:
[tex]\measuredangle3,\text{ }\measuredangle5[/tex]And
[tex]\measuredangle4,\measuredangle6[/tex]A graph to represent them:
From the options, we have that option B is one answer: <3 and <5. The other possible answer is <4 and <6 (not shown in the possible options).
A rectangular shaped garden is 2 feet longer than the width fios aree is 13sq feet find the dimensions
We are given that the length a rectangular-shaped figure is 2 feet longer than its width. This can be written mathematically as:
[tex]l=w+2[/tex]Where "l" is the length and "w" is the width. WE are also told that the area is 13 square feet. Since the area is the product of the length and the width this means the following:
[tex]lw=13[/tex]From the previous equation we solve for the length by dividing both sides by its width:
[tex]l=\frac{13}{w}[/tex]Now we replace this in the first equation:
[tex]\frac{13}{w}=w+2[/tex]Now we multiply both sides by the width:
[tex]13=w^2+2w[/tex]Subtracting 13 to both sides:
[tex]w^2+2w-13=0[/tex]We get a quadratic equation. To solve this equation we will factor the equation by completing the square:
[tex](w^2+2w+1)-14=0[/tex]Factoring the parenthesis:
[tex](w+1)^2-14=0[/tex]Now we add 14 to both sides:
[tex](w+1)^2=14[/tex]Taking square root to both sides:
[tex]w+1=\pm\sqrt[]{14}[/tex]Subtracting 1 to both sides:
[tex]w=-1\pm\sqrt[]{14}[/tex]We take the positive value for the width, that is:
[tex]\begin{gathered} w=-1+\sqrt[]{14} \\ w=2.74ft \end{gathered}[/tex]Now we replace this value of the width in the first equation:
[tex]\begin{gathered} l=2.74ft+2ft \\ l=4.74ft \end{gathered}[/tex]Therefore, the dimensions are:
[tex]\begin{gathered} w=2.74ft \\ l=4.74ft \end{gathered}[/tex]