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Rb+
Fe2+
H-
Al3+
Cl-
O2-
Using the ions above, write the formulas and give the names for 5 possible ionic compounds involving these ions.

In order to find the number of moles in a given mass of any compound, we need to use the molar mass of this compound, which is the total mass present in 1 mol of the compound. The molar mass of CaSO4 is 136.14g/mol

136.14 grams = 1 mol of CaSO4

37.16 grams = x moles of CaSO4

136.14x = 37.16

x = 37.16/136.14

x = 0.27 moles of CaSO4

In 37.16 grams, we will have 0.27 moles of CaSO4

The molarity of a solution that contains 0.75 mol of KCI in 0.250L of the solution is 3 M

The number of moles per liter of solution is termed molarity.

M=n/V(in L)

M is the molarity

n is the number of moles

V is the volume

Substituting the values, we get

M=0.75/0.25=3

The molarity is 3 M

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Answer:

Explanation:

Here, we want to get another name for the theoretical value

The theoretical value is simply the value that has been accepted as true

Thus, we can call the theoretical value the true value

The question provides the concentration of a solution (12% CaCl2) and requests us to calculate how many grams of this solution could be prepared starting from 35g of CaCl2.

Since the concentration of solution is 12%, considering it refers to % in mass, we can write that 12g of CaCl are necessary to prepare 100 g of solution:

12 g of CaCl2 --------------- 100 g of solution

Thus, we can calculate how much solution could be prepared from 35 g of CaCl2:

12 g of CaCl2 --------------- 100 g of solution

35 g of CaCl2 -------------- x

Solving for x, we have that 291.67 g of solution could be prepared from 35g of CaCl2.

Answer

47.60 g

Explanation

Given that:

Molar mass of MgCl₂ = 95.20 g/mol

Mass of Mg produced = 12.15 grams

Equation: MgCl₂ → Mg + Cl₂

What to find:

To calculate the grams of MgCl₂ needed to produce 12.15 grams of Mg.

Step-by-step solution:

Step 1: Convert the mass of Mg produced to moles.

Using the molar mass of Mg (24.305 g/mol) and the mole formula, the moles of Mg produced is

Step 2: Determine the moles of MgCl₂ needed to produce 12.15 g of Mg.

According to the given equation; 1 mol of MgCl₂ produced 1 mol of Mg

So, x mol of MgCl₂ will produce 0.49989714 mol of Mg

That is:

Step 3: Convert the moles of MgCl₂ needed to produce 12.15 g of Mg to grams.

Using the molar mass of MgCl₂ = 95.20 g/mol, therefore the mass in grams of MgCl₂ needed to produce 12.15 g of Mg will be:

Hence, the grams of MgCl₂ needed to produce 12.15 grams of Mg is 47.60 g.

Answer:

I am sure it's Transuranium.

Explanation:

Hope it's right

Answer:

Explanation:

Here, we want to get the number of moles in 2.24 L of a sample of gas

Mathematically,

At STP, 1 mole of a gas occupies a volume of 22.4 L

Thus x moles will occupy 2.24 L at STP

To get the value of x, we have it that:

Answer: Joules (J)

Explanation:

Answer:

Joules or Newton metre

Explanation:

Work = Force × distance

Force = kgm/s² (Newton)

×

Distance = m

= kgm²/s² (Newton metre or Joules) (Nm or J)

Taking into account the Charles' Law, a sample of gas in a closed expandable container with an initial volume of 5.00 L was allowed to warm from 25°C to 35°C to a volume of 5.168 L.

Charles' Law consists of the relationship that exists between the volume and the temperature of a certain amount of ideal gas, which is maintained at a constant pressure.

This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of motion of the gas molecules.

In summary, Charles's law is a law that says that when the amount of gas and the pressure remain constant, the ratio between the volume and the temperature will always have the same value:

V÷T=k

Considering an initial state 1 and a final state 2, it is fulfilled:

V₁÷ T₁= V₂÷ T₂

In this case, you know:

Replacing in Charles' law:

5 L÷ 298 K= V₂÷ 308 K

Solving:

(5 L÷ 298 K)× 308 K= V₂

5.168 L= V₂

Finally, the new volume is 5.168 L.

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Answer

• Carbon has the atomic symbol C,

• Carbon is a nonmetallic chemical element with 4 electrons in its valence shell, which allows it to form 4 bonds forming compounds like CH₄.

• Reactivity: Carbon does not dissolve in or react with water or acids.

• The atomic mass of carbon is 12.011 g. It contains 6 protons in its nucleus.

• When Sodium Sulfate is mixed with Barium chloride, the following reaction occurs :

• a precipitate is the solid that forms, the white solide will be BaSO4

• So option 4 is correct. BaSo4.

Answer: Solubility

Explanation:

The property by which substances dissolve in water is called solubility. Soluble substances (such as salt) dissolve in water.

Answer: Electical charge

Explanation:At the molecular level, salt dissolves in water due to electrical charges and due to the fact that both water and salt compounds are polar, with positive and negative charges on opposite sides in the molecule.

Answer

4.94x10^22 molecules

explanation

to calculate the number of molecules in 8.21x10^-2 moles ca be determined by using Avogadros number

we know that

1 mol has 6.022x10^23 molecules

therefore,

8.21x10^-2 moles have:

(8.21x10^-2) x (6.022x10^23)

= 4.94x10^22 molecules

MgSO4.7H2O

First of all, we need to calculate the molar mass of this molecule, using the periodic table.

Let's take each atomic mass of the elements that form this molecule from the periodic table.

Mg = 24.30 u

S = 32.06

O = 15.99 u

H = 1.007 u

Now, we have to do this:

Molar mass (g/mol) = 1 x 24.30 + 1 x 32.06 + 4 x 15.99 + 14 x 1.007 + 7 x 15.99

Molar mass = 246.3 g/mol

We have to be careful with this result because 246.3 g is the mass of 1 mole of MgSO4.7H2O and we want the mass of 1 formula unit or molecule.

Pay attention to this:

1 mole of MgSO4.7H2O = 246.3 g = 6.022 x 10^23 formula units or molecules of MgSO4.7H2O

(We want the mass of 1 molecule and we have just calculated the mass of 6.022x10^23 molecules)

----------------------------------------------------------------------------------------------------------------

For 1 formula unit or molecule:

246.3 g of MgSO4.7H2O ------------- 6.022 x 10^23 formula units or molec.

x ------------- 1 formula unit or molec.

Answer: The mass of 1 formula unit or molecule of MgSO4.7H2O = 4.09x10^-22 g

Answer:

Explanation:

Here, we want to get the temperature of the gas

We can use the ideal gas equation here

Mathematically, we have this as:

P is the pressure which is given as 34.56 kPa

V is the volume which is given as 440.99 mL

R is the molar gas constant which is 0.08205 L atm/mol k

n is the number of moles which is given as 1.43 mol

We need to convert the pressure to the correct unit (considering the molar gas consnat value in atm)

1 kPa = 0.00986923 atm

34.56 kPa will be = 34.56 * 0.00986923 = 0.341 atm

We need to convert the volume to Liters by dividing by 1000

We have that as 440.99/1000 = 0.44099 L

Finally,we rewrite the equation in terms of temperature and substitute the values as follows:

The final volume of the balloon if 0.20 moles of gas are added will be 1.62 L.

The volume of the balloon given that 0.20 moles of a gas is added to it is determined using the ideal gas equation as follows:

P₁V = nRT

Where;

Initial volume, V₁ = 1.50 L

Initial mole of gas, n₁ = 2.50 mol

Initial temperature, T₁= 25°C or 298 K

Initial pressure, P₁ = RT₁n₁/V₁

P₁ = 0.082 * 298 * 2.50 /1.50

P₁ = 40.7 atm

With pressure and temperature held constant:

Final temperature, T₂ is equal to T₁ = 298 K

Final pressure, P₂ is equal to P₁ = 40.7 atm

Final moles of gas, n₂ = 0.20 + 2.5

n₂ = 2.70 mol

Final volume, V₂ = RT₂n₂/P₂

V₂ =  0.082 * 298 * 2.70 /40.7

V₂ = 1.62 L

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In order to solve this question, we can use the concept of molar ratio, which means the amount of reactant is needed in order to produce a certain amount of product. In our question we have:

2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O

The molar ratio between O2 and H2O is 5:2 (we use only the numbers in front of the compound), so that means that for every 5 moles of O2 used, we will have 2 moles of H2O being produce, now we can use this information to calculate how many moles of H2O will be produced from 3.80 moles of O2

5 O2 = 2 H2O

3.80 O2 = x H2O

x = 1.52 moles of H2O are produced from 3.80 moles of O2

Answer

The mole ratio of H2O to H2SO4 is 2:1

Explanation

Given chemical equation:

From the balanced chemical equation above, 2 moles of NaOH react with sulfuric acid, 1 mole of H2SO4, to produce 2 moles of water and 1 mole sodium sulfate.

So, from the chemical equation, you have a 2:1 mole ratio between H2O and H2SO4

Given the reaction:

We're going to write a net ionic equation for this reaction as follows:

1. First, write the total ionic equation:

2. Now, we could cancel the same type of ions that are in both sides of the reaction. Therefore, the net ionic equation is:

The problem is asking for how many moles of water there are in 1 mol of solution with NaCl. This is telling us that NaCl is dissolved in water.

There are 0.132 moles of NaCl and summing the moles of water, we're going to obtain 1 mol of solution. You can see it, like this:

We just have to clear for 'X moles water', and we obtain:

The answer is that we have 0.868 moles of water in the solution.

Step 1 - Understanding how mole relates to temperature, pressure and volume

These variables are related according to the ideal gas equation:

We can use this equation to predict the behavior as well as the quantity of a gas, given that the remaining variables are given.

Step 2 - Using the equation to solve the equation

According to the exercise:

Setting the values in the equation:

We need to make two observations now: the temperature must be in Kelvin in this equation for it to work. R stands for the universal gas constant, as has the value of 0.082 atm.L/mol.K.

Therefore:

Answer: the amount of moles used is 0.17 moles.

5 F2 (g) + 2 NH3 (g) → N2F4 (g) + 6 HF (g)

From the above balanced reaction, we can see that :

5 moles of F2 reacts to form : 6 moles of HF ,

so, 7.78moles F2 will give :x moles of HF

Therefore,x mole HF =( 6 moles HF * 7.78 mole F2)/ 5 mole F2

= 6 * 7.78/5

=9.336

≈9.34moles HF

• This means that , if you reacted 7.78 moles of F2 , ,9.34 moles of HF would be produced,.

So,

The molecular mass of the empirical formula of the compound SO2, can be found multiplying the molar mass of each element by the number of atoms and then sum. Let me explain this here below:

We're given that the molecular mass of the molecular formula is 256g/mol. So, we could find the ratio between the mass of both formulas:

This means that the mass of the molecular formula is 4 times greater than the mass of the empirical formula.

Thus, the molecular formula will be:

Sulphur atom has 16 as its atomic number, which is also the same number of protons and the same number of electrons:

Z = 16

P = 16

e- = 16

But when we have a Sulphur ion, it is usually -2, and since we have 18 electrons in this case, the charge will be -2

Answer

B. sulfur dioxide released from a coal-fired power plant.

Explanation

Power plants release the majority of sulfur dioxide and much of the nitrogen oxides when they burn fossil fuels, such as coal, to produce electricity. In addition, the exhaust from cars, trucks, and buses releases nitrogen oxides and sulfur dioxide into the air. These pollutants cause acid rain.

Therefore, what is directly responsible for acid rain is:

B. sulfur dioxide released from a coal-fired power plant.

Answer:

The charge of the metal is +5.

Explanation:

As the chlorine atom has a valence of -1, and the metals have a positive valence, we have to look for the charge that makes the molecule neutral.

In this case, there are 5 Cl, so the total negative charge of Cl is -5.

To make the molecule neutral, the metal must have a positive charge of +5.

CH3CH3

CH3SCH3

CH3CH2OH 

What are organic compounds?

Organic compounds are compounds that class of compounds that contains the carbon-hydrogen bond. This means that for a compound to be classified as an organic compound, they must contain the C-H bond in their compound

From the listed compouds, the compound that contains theC-H bonds are:

• CH3CH3

• CH3SCH3

• CH3CH2OH

These are therefore considered the required list of organic compounds from the given options

The balanced half-reaction is Fe²⁺ + 2e⁻ --------> FeO₄²⁻

The given reaction is a redox reaction. Balancing a redox reaction is a bit different than solving a normal chemical reaction. The first step is to find the oxidation state of each element in the reactant as well as the product side. By doing so we get,

The oxidation state of Fe - +2

On the product side, we get,

The oxidation state of Fe - +6

The oxidation state of O - -2

The next step is to calculate the difference between the oxidation states.

The difference in oxidation state of Fe - +6 - (+2) = +4

The difference in oxidation state of O - 0 -2 = -2

To balance this reaction, 2 electrons should be added to the reactant side so that the oxidation states of O and Fe get balanced equally. By doing so we get,

Fe²⁺ + 2e⁻ --------> FeO₄²⁻

This is a balanced half-reaction in acid

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-292.8J/mmol

Given the reaction of NaCl and NaOH expressed by the chemical equation:

Amount of heat released when one mole of strong acid reacts with one mole of the strong base is -48.8 kJ/mmol.

If 6 moles of the sample acid reacts with 6 moles of NaOH, the required enthalpy cheange is expressed as:

Hence the enthalpy change if you neutralized six moles of HCl with an equal number of moles NaOH is -292.8J/mmol