Answer:
2910
Explanation:
970 × 3. 970 in one hour × 3 hrs. 2910 kilometers
a 138 kg refrigerator, 2.00 m tall and 87.0 cm wide, has its center of mass at its geometrical center. you are attempting to slide it along the floor by pushing horizontally on the side of the refrigerator. the coefficient of static friction between the floor and the refrigerator is 0.550. depending on where you push, the refrigerator may start to tip over before it starts to slide along the floor. what is the highest distance above the floor that you can push the refrigerator so that it won't tip before it begins to slide?
The highest distance above the floor that you can push the refrigerator so that it won't tip before it begins to slide is 0.79 m
What is torque?Torque is known to be the rotational equivalent of a linear force. In some fields of study, it is also called moment, moment of force, rotational force, or rotational effect. It describes the ability of a force to effect a change in the rotational motion of an object.
For the given case:
F = μmg
F = frictional resistance
μ = coefficient of static friction (0.55)
m = 138 kg
g = 9.8 m/s²
F = 0.55 × 138 × 9.8
F = 743.82 N
Take the refrigerator's mid-size weight halfway to the floor,
i.e. 0.87/2 = 0.435 m
d = 0.435 m
The torque around the bottom of the refrigerator should be zero to reach the maximum range. So,
F × x = mg × d
x = ( mg × d)/ μmg
x = d/μ
x = 0.435/0.55
x = 0.79 m
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A 4.3-kg bat is traveling 21 m/s just before it strikes a 2.5-kg baseball that’s moving 37 m/s. After the collision, the bat travels in the same direction at 19 m/s. What is the baseball’s speed just after impact?
The speed of the baseball is 30.38m/s .
We are given that,
The mass of bat = m₁ = 4.3 kg
The mass of baseball = m₂ = 2.5 kg
The initial velocity of bat = v₁ = 37 m/s
The final velocity of bat = v₁' = 19 m/s
So that the speed in baseball can be calculated from the law of conservation of momentum which can be given as,
mₙvₙ = m₁v₁ +m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
Where, vₙ is the speed of the baseball after impact, mₙ is the total mass of the system ,
(4.3kg + 2.5kg)vₙ = (4.3kg × 37m/s) + (2.5kg × 19m/s)
(6.8kg) vₙ = 159.1kg-m/s + 47.5kg-m/s
vₙ = (206.6kg-m/s)/6.8kg
vₙ = 30.38 m/s
Therefore, the speed of the baseball would be 30.38m/s after impact.
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An object is launched at a velocity of 20 m/s in a direction making an angle of 22° upward with the horizontal.What is the maximum height achieved by the projectile?
Given data:
Initial velocity,
[tex]u=20\text{ m/s}[/tex]Angle of projection,
[tex]\theta=22\degree[/tex]The maximum height achieved by the projectile is given as,
[tex]H=\frac{u^2\sin ^2\theta}{2g}[/tex]Here, g is the acceleration due to gravity.
Substituting all known values,
[tex]\begin{gathered} H=\frac{(20\text{ m/s})^2\times\sin ^2(22\degree)}{2\times(9.8\text{ m/s}^2)} \\ \approx2.86\text{ m} \end{gathered}[/tex]Therefore, the maximum height achieved by the projectile is 2.86 m.
Light of frequency 3.62 x 10^15 Hz strikes a surface of copper (W0=4.70 eV). How much kinetic energy does the liberated electron have in eV?
From the equation of photoelectric effect, the kinetic energy is 10.2 eV.
What is the kinetic energy?According to the Einstein photoelectric equation, we know that the kinetic energy is the difference between the energy of the incident photon and the work function of the metal.
KE = E - Wo
KE = kinetic energy
E = energy of the photon
Wo = work function
Thus;
E = hf
h = Plank's constant
f = frequency
E = 6.6 * 10^-34 * 3.62 x 10^15
= 2.39 * 10^-18 J or 14.9 eV
Thus we have;
KE = 14.9 eV - 4.70 eV
KE = 10.2 eV
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Answer:
10.2 eV
Explanation:
there's no need for an explanation
An object rolls off a 8 m tall table with a velocity of 3 and lands 6 away from the base of the table. What is the vertical acceleration of the object? (Answer must be negative!!!)
Answer:
-9.81 m/s/s or -4 m/s/s
Explanation:
Technically, the only vertical component of force and therefore acceleration on the object after it leaves the table will be acceleration due to gravity. So we can say the value of acceleration is g, -9.81m/s/s.
Though after checking your parameters, maybe you are on another planet with a different gravitation constant.
in this case, assuming your other values are in the standard m/s and m, we can determine how long the ball should be in the air to land 6 meters away and thus use that to find downward acceleration.
6m = 3m/s • t
2s = t
8 = 1/2 g • (2)^2
2m/s/s = 1/2 g
4 m/s/s = g
this would approximate to doing this experiment on mercury
A 50 kg child is on a carnival ride with a radius of 5 meters. If the ride spins at a velocity of 5
m/s, what is the centripetal force on the child?
Explanation:
Find a force is F=mv^2/r, so F=50*5^2/5 = 250N
a child pulls a friend in a little red wagon with constant speed. if the child pulls with a force of 16 n for 10.0 m, and the handle of
The work done by the child to pull the wagon is found to be 67.61N.
The child pulls the wagon with a force 16N and the handle of the wagon is inclined at the angle of 25°. The wagon is puled till a distance of 10m.
So, the force will have to component, one vertical and one is horizontal,
The horizontal component will move the wagon,
So, the work done by the child is given by,
W = F.S.sin(25°)
F is the force and S is the distance, Putting values,
W = 16 x 10 x 0.42
W = 67.61 N.
The work done by the child in pulling the wagon is 67.61 N.
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Complete Question - A child pulls a friend in a little red wagon with constant speed. If the child pulls with a force of 16 N for 10.0 m, and the handle of the wagon is inclined at an angle of 25° above the horizontal, how much work does the child do on the wagon?
PLS HURRY
The photo shows a roller coaster. Assume the system is closed. Which roller-coaster car has the least potential energy due to gravity?
A. Car A
B. Car B
C. Car C
D. Car D
Answer: it's rather A or B
Explanation: those are the moments it stops but most likely it is answer A.
what is the magnetic field amplitude b0b0 of an electromagnetic wave that has an electric field amplitude e0e0e 0 of 0.465 v/mv/m ?
An electromagnetic wave with an electric field amplitude E0 of 0.165V/m has a magnetic field amplitude b0 of 5.5 × [tex]10^{-10}[/tex]T.
What is electromagnetic?In terms of physics, electromagnetic radiation is made up of electromagnetic field waves that move over space while carrying radiant energy. It is made up of radio waves, microwaves, infrared, light, and X and gamma rays. The electromagnetic spectrum includes all of these wavelengths.Radio waves, microwaves, infrared, visible light, ultraviolet, x-rays, and gamma rays are all examples of electromagnetic waves. The smallest energy, frequency, and wavelength are found in radio waves. The highest energy, frequency, and shortest wavelength are found in gamma rays.How to calculate the magnetic field amplitude Bo?Speed of light / Electric field amplitude (Eo) = magnetic field amplitude (Bo)
where C = 3 × [tex]10^{8}[/tex] m/s
Bo = 0.165 / 3 × [tex]10^{8}[/tex]
Bo = 5.5 × [tex]10^{-10}[/tex]T (magnetic field amplitude)
The complete question is:
what is the magnetic field amplitude b0b0 of an electromagnetic wave that has an electric field amplitude e0e0e 0 of 0.165 v/mv/m ? express your answer with the appropriate units.
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A lemming take off from the roof of a building 56m tall and lands 45m from the base. What was the lemming’s initial speed ?
Given data
*The given height of the building h = 56 m
*The distance from the base is d = 45 m
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the time taken by the lemming is given as
[tex]t=\sqrt[]{\frac{2h}{g}}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} t=\sqrt[]{\frac{2\times56}{9.8}} \\ =3.38\text{ s} \end{gathered}[/tex]The formula for the lemming's initial speed is given as
[tex]v=\frac{d}{t}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v=\frac{45}{3.38} \\ =13.3\text{ m/s} \end{gathered}[/tex]Hence, the lemming's initial speed is v = 13.3 m/s
a child is sledding down a hill. the child has 200 j of potential energy and 500 j of kinetic energy at one point on the hill. how much more kinetic energy does the child gain for the remainder of the motion to the bottom of the hill?
The additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule. The result is obtained by using the principle of Conservation of Mechanical Energy.
What is Conservation of Mechanical Energy?The principle of conservation of energy states that "The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and transferred from one object to another, but the total amount remains constant."
In the same way, the Conservation of Mechanical Energy states that the total mechanical energy of a system is conserved. It can be expressed as
[tex]E_{1} = E_{2}[/tex]
[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]
[tex]\frac{1}{2} mv_{1} ^{2} + mgh_{1} = \frac{1}{2} mv_{2} ^{2} + mgh_{2}[/tex]
Where
E₁ = mechanical energy at point 1E₂ = mechanical energy at point 2K₁ = kinetic energy at point 1K₂ = kinetic energy at point 2U₁ = potential energy at point 1U₂ = potential energy at point 2m = mass of an objectv₁ = velocity of object at point 1v₂ = velocity of object at point 2h₁ = height of object at point 1h₂ = height of object at point 2At one point, a child has:
U₁ = 200 JK₁ = 500 JHow much more kinetic energy does the child gain at the bottom of the hill?
At the bottom of the hill, the height of the child is zero, h₂ = 0. So, the potential energy is
[tex]U_{2} = mgh_{2}[/tex]
[tex]U_{2} = mg(0)[/tex]
[tex]U_{2} = 0[/tex]
The kinetic energy at the bottom of the hill is
[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]
[tex]500 + 200 = K_{2} + 0[/tex]
[tex]K_{2} = 700 J[/tex]
The kinetic energy added for the remainder of the motion is
[tex]K = K_{2} - K_{1}[/tex]
[tex]K = 700 - 500[/tex]
[tex]K = 200 J[/tex]
Hence, the additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule.
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If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will.
The correct answer is option E.
If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will accelerate but will not spin.
In the absence of air resistance the object will accelerate but will not spin, it is because if there is no air resistance then same amount of force is applied on every part of the object. When all forces are same in all directions then it means net force is zero.
Moreover, the force is being applied in downward direction having same magnitude which leads to the fact that net force is zero.
Thus, the object will not spin as all forces cancel their effect. However, the object will accelerate due to force of gravity.
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The complete question is:
If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will:
A) accelerate and turn about its center of gravity with uniform angular acceleration.
B) accelerate and spin until its center of gravity reaches its highest point.
C) accelerate and turn until its center of gravity reaches its lowest point.
D) accelerate and turn about its center of gravity with uniform angular speed.
E) accelerate but will not spin.
In FIGURE 2, a block of mass m=2.5 kg slides heads on into a spring of spring constant k=320 N/m. When the block stops, it has compressed the spring by 7.5 cm. The coefficient of kinetic friction between block and floor is 0.25. While the block is in contact with the spring and being brought to rest, calculatea. the work done by the spring force.b. the increase in thermal energy of the block-floor system.c. What is the block's speed just as it reaches the spring?
(a)
The work done by the spring force can be calculated with the formula below:
[tex]W=\frac{1}{2}kx^2[/tex]Using k = 320 N/m and x = 0.075 m, we have:
[tex]\begin{gathered} W=\frac{1}{2}\cdot320\cdot0.075^2\\ \\ W=0.9\text{ J} \end{gathered}[/tex](b)
The increase in thermal energy is given by the work done by the friction force.
To calculate this work, first let's find the friction force:
[tex]\begin{gathered} F_{friction}=F_{normal}\cdot\mu\\ \\ F_{friction}=m\cdot g\cdot\mu\\ \\ F_{friction}=2.5\cdot9.8\cdot0.25\\ \\ F_{friction}=6.125\text{ N} \end{gathered}[/tex]Now, calculating the work, we have:
[tex]\begin{gathered} W=F\cdot d\\ \\ W=6.125\cdot0.075\\ \\ W=0.46\text{ J} \end{gathered}[/tex](c)
The block speed can be found by converting the potential energy from the spring (same value of the calculated work in item a) into kinetic energy for the block:
[tex]\begin{gathered} PE=KE\\ \\ 0.9=\frac{mv^2}{2}\\ \\ mv^2=1.8\\ \\ 2.5v^2=1.8\\ \\ v^2=\frac{1.8}{2.5}\\ \\ v^2=0.72\\ \\ v=0.8485\text{ m/s} \end{gathered}[/tex]Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a mass of 120 kg and was moving with a velocity of 4 m/s before the collision and with a velocity of −2 m/s after the collision. The second bumper car has a mass of 90 kg and was moving at a velocity of −5 m/s before the collision. To prove conservation of momentum, what must the velocity of the second bumper car be after the collision?
A. 1.0 m/s
B. 2.7 m/s
C. 3.0 m/s
D. 2.3 m/s
The velocity of the second bumper car will be 3 m/s after the collision.
Given parameters:
Mass of the first bumper car; m = 120 kg.
Mass of the second bumper car; M = 90 kg.
Before collision velocity of first bumper car; u = 4 m/s.
Before collision velocity of second bumper car; U = -5 m/s.
After collision velocity of first bumper car; v = -2 m/s.
After collision velocity of second bumper ; V= ?
From principle of conservation of momentum,
Total momentum before collision = Total momentum after collision
⇒ 120 × 4 + 90 × (-5) = 120 × (-2) + 90 × V
⇒ 90 × v = 270
⇒ v = 3 m/s.
The velocity of the second bumper car must be 3 m/s after the collision.
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A runner covers the last straight stretch of a race in 8s.During that time he speeds up from 7 m/s to 9m/s. What is the acceleration
Given
Time taken is t=8 s.
The initial speed is u=7 m/s
The final speed is v=9 m/s.
To find
The acceleration
Explanation
We know the acceleration is the ratio of the difference in the speed to the time taken.
Thus,
[tex]\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow a=\frac{9-7}{8} \\ \Rightarrow a=\frac{2}{8}=\frac{1}{4}=0.25\text{ m/s}^2 \end{gathered}[/tex]Conclusion
The acceleration is
[tex]0.25\text{ m/s}^2[/tex]The more gallons of milk I have, the more cups milk I can pour what’s the independent and dependent variable?
Answer: I think the independent variable is the gallons of milk. and the dependent variable is the amount of milk you can pour.
(The more gallons of milk you have is the thing that changes the whole outcome, which is the amount of milk that can be poured out)
a motorcycle traveling 100m/s drives off a horizontal ramp and lands a horizontal distance of 40m away from the edge of the ramp, what is the height of the ramp?
We will have the following:
First, we determine the time it takes for the motorcycle to traverse the 40 m:
[tex]40m=(100m/s)t\Rightarrow t=0.4s[/tex]Now, we will use the time to determine the height of the ramp:
[tex]\begin{gathered} d=(0m/s)(0.4s)+\frac{(9.8m/s^2)(0.4s)^2}{2}\Rightarrow d=\frac{98}{125}m \\ \\ \Rightarrow d=0.784m \end{gathered}[/tex]So, the ramp was located 0.784 meters in height.
A golf club exerts an average force of 33 kN on a ball of mass 0,06 kg. if the golf club is in contact with the golf ball for 5x10-4
'seconds,
calculate:
a) the change in the momentum of the golf ball.
b) the speed of the golf ball as it leaves the ciub.
(a) The change in momentum of the golf ball 0f mass 0.06 kg is
16.5 Ns.
(b) The Speed of the golf ball as it leaves the club is 275 m/s.
What is change in momentum?Change in momentum is the product of mass and change in velocity of a body.
(a) To calculate the change momentum of the golf ball, we use the formula below.
Formula:
ΔM = Ft............ Equation 1Where:
ΔM = Change in momentumF = Forcet = TimeFrom the question,
Given:
F = 33 kN = 33000 Nt = 5×10⁻⁴ sSubstitute these values into equation 1
ΔM = 33000×5×10⁻⁴ ΔM = 16.5 Ns(b) Also, to calculate the speed of the golf as it leaves the club we use the formula below.
Formula:
v = ΔM/m (When the club was at rest)............... Equation 2Where:
v = Speed of the golf as it leaves the clubm = Mass of the golfFrom the question,
Also given:
m = 0.06 kgSubstitute into equation 2
v = 16.5/0.06v = 275 m/s.Hence, The change in momentum and speed of the golf are 16.5 Ns and 275 m/s respectively.
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as the temperature of a gas increases . (select all the options that complete this sentence correctly.) multiple select question. the average kinetic energy of the gas particles increases the speed of individual gas particles increases but the average speed remains the same the distribution of the speeds of the gas particles narrows the average speed of a gas particle increases
As the temperature of a gas increases.
The average kinetic energy of the gas particles increase. The average speed of a gas particle increases.
Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness. Temperature is measured with a thermometer.
Thermometers are calibrated in various temperature scales that traditionally have trusted diverse reference points and thermometric substances for definition. The most common scales are the Celsius scale with the unit image °C (formerly known as centigrade), the Fahrenheit scale (°F), and the Kelvin scale (k), the latter getting used predominantly for scientific purposes. The kelvin is one of the seven base units within the worldwide device of gadgets (SI).
Absolute 0, i.e. zero kelvin or −273.15 °C, is the bottom factor in the thermodynamic temperature scale. Experimentally, it could be approached simplest very intently, however not truly reached, as identified in the 1/3 law of thermodynamics. it might be impossible to extract strength as warmth from a frame at that temperature.
Temperature is vital in all fields of natural technology, along with physics, chemistry, Earth technology, astronomy, medicinal drug, biology, ecology, cloth technological know-how, metallurgy, mechanical engineering and geography as well as most aspects of daily life.
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A ball is dropped from the top of a cliff. By the time it reaches the ground, all the energy in its gravitational potential energy store has been transferred into its kinetic energy store. If the ball is travelling at 20 m/s when it hits the ground, what height was it dropped from? (Assume that the gravitational field strength is 10 N/kg
Answer:
h = 20 meters
Explanation:
Comment
Comment
The total energy (potential energy) it has at the top of the cliff has a formula of PE = mgh. The KE at the top is zero.
The Kinetic Energy at the bottom is 1/2 m v^2 The PE at the bottom is 0.
Givens
g = 10 N/kg
vf = 20 m/s
h = ?
Formula
mgh = 1/2 m v^2 Its the same energy at the top as at the bottom. It just has exchanged Potential Energy to Kinetic Energy. Cancel the ms
mgh/m = 1/2 m v^2 / m
gh = 1/2 v^2 Multiply by 2
2gh = v^2 Put in the given values
2*10 * h = 20^2 Simplify
20h = 400
h = 400/20
h = 20 meters.
4.82 the variable resistor in the circuit in fig. p4.82 is adjusted for maximum power transfer to ro. a) find the value of ro. b) find the maximum power that can be deleivered to ro.
Answer:
u don't know this one but try a not for sure
When can the normal force of an object have the same value as the force of weight? Explain.
Answer:
at rest
Explanation:
at rest
If the object is at rest, net force on the object is equal to zero; therefore, the downward force (weight) must be equal to the upward force (normal force).
what is the direction of the magnetic force on a positive charge moving into the page in a b field that is facing to the right?
According to the right hand rule, the thumb of the right hand should point in the direction of the magnetic force acting on a positive moving charge.
Which magnetic field direction is positive?It is demonstrated that the magnetic line's direction is from north to south and the electric line's direction is from positive to negative.
What direction does the coil's left-hand side force come from?A downward force is produced when current flows through the left hand of the coil, and an upward force is produced when current flows through the right hand of the coil.
What direction does this magnetic force go in?The direction of the magnetic field's force is opposite the direction that it acts.
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when you drive through deep water, you should dry out your brakes by driving slowly in low gear and apply your brakes lightly. a. true b. false check answers
It is true when you drive through deep water, you should dry out your brakes by driving slowly in low gear
When water surges over a road it can cover up dips, debris, and streets that have been washed away totally. It’s not the street you know no matter how numerous times you’ve driven it. Six inches of water is sufficient to hit the foot of most passenger cars, flooding the exhaust and clearing out you're immobile. Drive in low gear to protect the car. On the off chance that you’re driving an automatic vehicle, keep the speed low enough to remain in, to begin with, or second gear. Keep your foot on the gas and utilize the brake to direct speed. to dry Your Brakes Once you get through the water you don’t need to turn out. You'll dry your brakes after moving through water by braking gently while driving exceptionally slowly.
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a projectile lands at the same height from which it was launched. which initial velocity will result in the greatest horizintal displacment of the projectile
The initial velocity that will result in the greatest horizontal displacement of the projectile is V cosθ
The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ. Since we are provided with a projectile that lands at the same height from which it was launched, so the component of the velocity in the vertical direction is usin θ, and the component along the horizontal direction is ucosθ.Neglecting the air resistance, the velocity will be constant for the object throughout the flight, so the initial velocity will be equal to the final velocity.Therefore the initial velocity will be, V₀ = V cosθ
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I need to find out number 51.Can you help me ?
v= constant
mass of the cart = 1.5 kg
m2 (added)= 7.5 kg
When using their brakes,
cars disengage the engine so that it no longer
provides any forward force.
A(n) 2006.1 kg car is coasting along a level
road at 31.5 m/s. A constant braking force
is applied, such that the car is stopped in a
distance of 62.1 m.
What is the magnitude of the braking force?
Answer in units of N.
The magnitude of the braking force is 0
What is acceleration?
velocity changes with time at an accelerating rate in both speed and direction. In the case of simple harmonic motion, the spring's elastic force serves as the restoring force. The application of Hooke's law, F = - kx, allowed for its discovery. Here, k is the spring constant and x is the spring's deformation (change of its length from equilibrium position).
We can see that this force is variable and dependent on the mass-spring system's x displacement. The minus sign indicates that the force's direction is the opposite of the displacement, and as a result, the force causes the mass of the back to return to its equilibrium position.
As with any force, restoring force can be calculated using Newton's second law, F = ma, where m is the body's mass and an is its acceleration.
Now we can write:
The body's displacement x is zero when it reaches equilibrium. Acceleration is therefore 0.
By the way, when the amplitude of the this mass-spring system reaches its maximum, the acceleration will be at its maximum value. The mass-spring pendulum swings in the opposite direction at these points. We refer to those as inflection points.
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Which one of these objects has kinetic energy?
an Iphone laying on a table
a frisbee sitting on a roof
a ball rolling down the driveway
Answer: A ball rolling down the driveway.
Explanation:
Kinetic is when an object is in motion. Potential is when an object rests.
A bus goes 500km east from town A to town B in the morning and comes back halfway in the evening travelling west. What is the distance and displacement of the bus?
Given:
Distance the bus goes from town A to town B = 500 km east
Given that the bus comes back halfway in the evening travelling west, let's find the distance and the displacement of the bus.
• To find the distance of the bus, we have:
[tex]\begin{gathered} d=500+(\frac{500}{2}) \\ \\ d=500+250 \\ \\ d=750\operatorname{km} \end{gathered}[/tex]Therefore, the distance the bus covered is 750 km
• To find the displacement, we have:
[tex]\begin{gathered} Displacement\text{ = 500 - (}\frac{500}{2}) \\ \\ \text{Displacement = 500 - 250} \\ \\ \text{Displacement = 250 km} \end{gathered}[/tex]Therefore, the displacement of the bus is 250 km east
ANSWER:
Distance = 750 km
Displacement = 250 km east
Johnathan weighs 650N on Earth. What would his weight be if he was on Jupiter, which has a gravity of 24.8 m/s^2?