If the two objects are on the same scale, then as the toy size increases the real size should increase on the same proportion. This means that these two variables, toy size and real car size, are directly proportional and we have to solve the rule of three on the following manner:
[tex]\begin{gathered} \frac{3}{x}=\frac{120}{5} \\ 120\cdot x=3\cdot5 \\ 120\cdot x=15 \\ x=\frac{15}{120}=\frac{1}{8} \end{gathered}[/tex]The door handle toy size is 1/8 of an inch, which is equal to 0.125 inches.
What is the Effective Annual Yield in percent when the annual nominal interest rate is 7.042% compounded quarterly?EAY = ___%
Answer:
Given that,
Annual nominal interest rate is 7.042% compounded quarterly
To find the effective annual yield.
Explanation:
The formula for calculating effective annual yield (E) is,
[tex]E=(1+\frac{r}{n})^n-1[/tex]where r is the interest rate, n is the number of compounds per year.
Here, r=7.042 % and n=4
Substitute the values we get,
[tex]E=(1+\frac{7.042}{100\times4})^4-1[/tex][tex]E=(1+0.017605)^4-1[/tex][tex]E=1.07230154-1[/tex][tex]E=0.07230154[/tex][tex]E=0.07230154\approx7.23\%[/tex]Effective annual yield is 7.23%
ABC High School is debating whether or not to write a policywhere all students musthave uniforms and wear them during school hours. In a survey,45% of the studentswanted uniforms, and 55% did not.Calculate the probability that a person selected at random fromABC High School will want the school to have uniforms or willnot want the school to have uniforms.
If 45% don't want uniforms, it means that 45 out of 100 students don't want them, so the probability is 45/100 = 9/20
And 55% want unifrms, so the probability = 55/100 = 11/20
Hi, can you help me to solve this exercise, please!!
Given the Right Triangle BCD, you know that:
[tex]\begin{gathered} BD=8 \\ m\angle BCD=63\degree \end{gathered}[/tex]Then, you can use the following Trigonometric Function in order to find the length of the side CD:
[tex]\sin \beta=\frac{opposite}{hypotenuse}[/tex]In this case:
[tex]\begin{gathered} \beta=63\degree \\ opposite=BD=8 \\ hypotenuse=CD \end{gathered}[/tex]Therefore, substituting values and solving for CD, you get:
[tex]\begin{gathered} \sin (63\degree)=\frac{8}{CD} \\ \\ CD\cdot\sin (63\degree)=8 \end{gathered}[/tex][tex]\begin{gathered} CD=\frac{8}{\sin(63\degree)} \\ \\ CD\approx9.0 \end{gathered}[/tex]Hence, the answer is:
[tex]CD=9.0[/tex]PLEASE HELP!!!!! (31 POINTS!) Fill in the arithmetic table
The table for this arithmetic sequence should be completed as follows:
Position 1 6 8 11 19 25
Term 0 -10 -14 -20 -36 -48
How to calculate an arithmetic sequence?Mathematically, the nth term of an arithmetic sequence can be calculated by using this expression:
aₙ = a₁ + (n - 1)d
Where:
d represents the common difference.a₁ represents the first term of an arithmetic sequence.n represents the total number of terms.Next, we would determine the common difference by using the 25th term of this arithmetic sequence:
-48 = 0 + (25 - 1)d
-48 = 24d
d = -48/2
d = -2.
For the nth term of this arithmetic sequence with -10, we have:
aₙ = a₁ + (n - 1)d
-10 = 0 + (n - 1)-2
-10 = -2n + 2
2n = 12
n = 6.
For the 8th term of this arithmetic sequence, we have:
a₈ = a₁ + (n - 1)d
a₈ = 0 + (8 - 1)-2
a₈ = -14.
For the nth term of this arithmetic sequence with -20, we have:
aₙ = a₁ + (n - 1)d
-20 = 0 + (n - 1)-2
-20 = -2n + 2
2n = 22
n = 11.
For the 19th term of this arithmetic sequence, we have:
a₁₉ = a₁ + (n - 1)d
a₁₉ = 0 + (19 - 1)-2
a₁₉ = -36.
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Harold and Harry both rented cars from Hurry Up Motors. Harold rented his car for 6 days andwas charged $194. Harry rented his car for 3 days and was charged $122. Choose theequation that represents y, the rental cost, in terms of x, the days of the rental.
Step 1:
Write the coordinates in terms of cost and number of days.
( cost , days )
Step 2
( 3 , 122 ) and ( 6, 194)
Step 3:
Find the slope
[tex]\begin{gathered} \text{Slope m = }\frac{y_2-y_1}{x_2-x_1} \\ x_1\text{ = 3} \\ y_1\text{ = 122} \\ x_2\text{ = 6} \\ y_2\text{ = 194} \\ m\text{ = }\frac{194\text{ - 122}}{6\text{ - 3}} \\ m\text{ = }\frac{72}{3} \\ m\text{ = 24} \end{gathered}[/tex]Step 4
Find the equation using the slope m and point 1
[tex]\begin{gathered} m\text{ = }\frac{y-y_1}{x-x_1} \\ 24\text{ = }\frac{y\text{ - 122}}{x\text{ - 3}} \\ \text{y - 122 = 24(x - 3)} \\ \text{y - 122 = 24x - 72} \\ y\text{ = 24x - 72 + 122} \\ y\text{ = 24x + 50} \end{gathered}[/tex]Final answer
The equation is y = 24x + 50
What are the known solution to you can see the solution in the picture
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The known solutions to:
[tex]f(x)\text{ = g(x) are:}[/tex][tex]\begin{gathered} \text{when x= 1,} \\ f(1)\text{ = 14,} \\ g(1)\text{ = 14} \\ \text{and } \\ \text{when x = 9 ,} \\ f(1)\text{ = 6} \\ g(1)\text{ = 6} \end{gathered}[/tex]CONCLUSION:
The correct answers are:
[tex]\begin{gathered} \text{ x = 1 -- OPTION A} \\ \text{and } \\ \text{x = 9 }--\text{OPTION D} \end{gathered}[/tex]For Monday morning's staff meeting, Jim bought 3 bags of bagels and 3 packages of cream cheese and paid $16.50 (excluding sales tax).For Friday's meeting, he bought 5 bags of bagels and 2 packages of cream cheese and paid $22.25 (again, excluding sales tax). How much dobags of bagels and packages of cream cheese cost?
Answer:
Explanation:
Let the price of one bag of bagel = b
Let the price of one package of cream cheese = c
3 bags of bagels and 3 packages of cream cheese costs $16.50.
[tex]3b+3c=16.50\cdots(1)[/tex]5 bags of bagels and 2 packages of cream cheese costs $22.25.
[tex]5b+2c=22.25\cdots(2)[/tex]Thus, we derive a system of two linear equations which we then solve for b and c.
[tex]\begin{gathered} 3b+3c=16.50\operatorname{\cdots}(1) \\ 5b+2c=22.25\operatorname{\cdots}(2) \end{gathered}[/tex]Multiply equation 1 by 5 and equation 2 by 3.
[tex]\begin{gathered} 15b+15c=82.5 \\ 15b+6c=66.75 \end{gathered}[/tex]Subtract to eliminate b.
[tex]9c=15.75[/tex]Divide both sides by 9:
[tex]\begin{gathered} \frac{9c}{9}=\frac{15.75}{9} \\ c=1.75 \end{gathered}[/tex]Next, substitute c=1.75 into equation 1.
[tex]\begin{gathered} 3b+3c=16.50 \\ 3b+3(1.75)=16.50 \\ 3b=16.50-3(1.75)=11.25 \\ b=\frac{11.25}{3}=3.75 \end{gathered}[/tex]The price per bag of bagel is $3.75 and the price per package of cream cheese is $1.75.
Find the image of (1,2) after a reflection about x=3 followed by a reflection about x=7.
EXPLANATION
Given the point (1,2), if we reflect the point the new image must be at the same distance from the reflective line just at the original image.
Therefore when (1,2) is reflected over x= 3 the image becomes
[tex](5,2)[/tex]As the distance between line x=3 is 2 units on both sides.
When we then reflect (5,2) over x =7, using the same idea above the image becomes
Answer:
[tex](9,2)[/tex]Thomas is buying football jerseys for his high school football team. Thecost of each jersey is $80. The company also charges a processing fee of$100.Write an equation that represents Thomas' total cost for purchasing xnumber of jerseys.What is Thomas' total cost, if he buys 55 jerseys?
Thomas is buying football jerseys for his high school football team.
The cost of each jersey is $80.
The company also charges a processing fee of $100.
We could write an equation that models Thomas's total cost for purchasing x
number of jerseys.
Since for every x jerseys Thomas buys, he pays
[tex]80x\text{ dollars}[/tex]But he also has to pay the company's processing fee, this is independent of the quantity bought.
So, the total cost for buying x number of jerseys is;
[tex]y=80x+100\text{ dollars}[/tex]ii. What is Thomas's total cost, if he buys 55 jerseys?
We can use our formula,
[tex]\begin{gathered} y=80x+100\text{ , when x =55, we have;} \\ y=80(55)+100 \\ y=4400+100 \\ y=4500\text{ dollars} \end{gathered}[/tex]Therefore, Thomas's total cost for 55 jerseys is $4500
I have to find the length of x but I need guidance
Since we are dealing with a right triangle, we can use trigonometric identity below
[tex]\begin{gathered} sin\theta=\frac{O}{H} \\ \theta\rightarrow\text{ interior angle} \\ O\rightarrow\text{ opposite side to}\theta \\ H\rightarrow\text{ hypotenuse} \end{gathered}[/tex]Therefore, in our case,
[tex]\begin{gathered} sin(45\degree)=\frac{5}{x} \\ \Rightarrow x=\frac{5}{sin(45\degree)}=\frac{5}{\frac{1}{\sqrt{2}}}=5\sqrt{2} \end{gathered}[/tex]Thus, the answer is x=5sqrt(2), the second option)Mr. Nacarrato and his family are going on a road trip that is
2457 miles long. They have already driven 128 53/100 miles
How much further do they have to drive?
They need to go further 2328.47 miles distance.
What is improper fraction and mixed fraction?
A mixed fraction is one that has both a correct fraction and a whole number portion, and whose value is consistently greater than 1. When the numerator is always higher than or equal to the denominator, the fraction is said to be inappropriate. 4/3, 7/3, 11/5, and other incorrect fractions are a few instances.
Here the road trip is 2457 miles long .
They already drive 128 [tex]\frac{53}{100}[/tex] miles.
That is in mixed fraction , we need to convert them in improper fraction , then,
=> 128 [tex]\frac{53}{100}[/tex] = [tex]\frac{128*100+53}{100}= \frac{12853}{100}[/tex]
Now we need to subtract them from total distance then ,
=> 2457 - [tex]\frac{12853}{100}[/tex]
=> [tex]\frac{2457*100-12853}{100}[/tex]
=> [tex]\frac{245700-12853}{100}[/tex]
=> 2328.47 miles.
They need to go further 2328.47 miles.
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What should you multiply the first equation (top equation) by in order to eliminate the variable y when the two equations are added together? {x+2y=5{3x-4y=8
2
Explanationgiven
[tex]\begin{gathered} x+2y\rightarrow equation(1) \\ 3x-4y=8\rightarrow equation(2) \end{gathered}[/tex]Step 1
a) to eliminate the y variable we have
[tex]\begin{gathered} 2y \\ -4y \end{gathered}[/tex]in order to be eliminated both terms must have the same value and different sign,in other words the addition must equla zero, so weed a number (a) that makes the term from teh first equation equals (4y)
so
[tex]\begin{gathered} (2y*a)-4y=0 \\ 2ay=4y \\ so \\ 2a=4 \\ divide\text{ both sides by 2} \\ \frac{2a}{2}=\frac{4}{2} \\ a=2 \end{gathered}[/tex]therefore, the first equation should be multiplied by 2
I hope this helps you
Calculate the population variance and population standard deviation for the following data said if necessary round to one more decimal place than the largest decimal
Given the dataset
2, 3, 4, 5, 6, 7, 8, 9, 10, 11
range is given by
[tex]range=maxValue-MinValue[/tex][tex]range=11-2[/tex][tex]range=9[/tex]Range=9
population variance is given by
[tex]s^2=\frac{SumSquares}{n}[/tex][tex]s^2=\frac{82.5}{10}[/tex][tex]s^2=8.25[/tex]rounded
population variance = 8.3
population standar deviation is given by
[tex]std=\sqrt{\frac{SumSquares}{n}}[/tex][tex]std=\sqrt{8.25}[/tex][tex]std=2.872[/tex]rounded
population standar deviation= 2.9
please help! i’ll give points.
Answer:
87
Step-by-step explanation:
112+74=186
360-186=174
174/2=87
you rent a moving van you have to pay a flat fee of $99 plus $0.50 per mile you drive 120 miles how much does it cost to drive the van also I NEED work
It cost $159 to drive the van for 120 miles
Explanation:
The flat fee of the van = $99
The charge per mile = $0.50
Let m represent the number of miles
T = total cost
The total cost becomes:
T = 0.5m + 99
When you drive 120 miles, m = 120 miles
T = 0.5(120) + 99
T = 60 + 99
T = $159
Hence, it cost $159 to drive the van for 120 miles
Which of the equations will be a true statement if p = 10 3 ? Select the two choices that apply. A.
3
.
4
÷
p
=
0
.
034
B.
437
÷
p
=
0
.
437
C.
53
.
45
÷
p
=
53
.
45
D.
6
,
340
÷
p
=
6
.
34
E.
2
,
458
.
2
÷
p
=
24
.
582
The linear equation in one variable is used to know on e unknown quantity. The correct answer is option a.
What is a Linear equation?A linear equation is a equation that has degree as one.
To find the solution of n unknown quantities n number of equations with n number of variables are required.
Given that,
The value of p = 10.3
Substitute p = 10.3 in all the given option as,
(a)
3.4 ÷ p = 0.34
Substitute p = 10.3 in the above equation to get,
LHS = 0.33
Since LHS = RHS
The given option is true.
(b)
437 ÷ p = 0.437
Substitute p = 10.3 in the above equation to get,
LHS = 42.427
Since LHS ≠ RHS
The given option is not true.
(c)
53.45 ÷ p = 53.45
Substitute p = 10.3 in the above equation to get,
LHS = 5.18
Since LHS ≠ RHS
The given option is not true.
(d)
340 ÷ p = 6.34
Substitute p = 10.3 in the above equation to get,
LHS =33
Since LHS ≠ RHS
The given option is not true.
(e)
2458 ÷ p = 24.582
Substitute p = 10.3 in the above equation to get,
LHS =238.64
Since LHS ≠ RHS
The given option is not true
Hence, the value of p satisfies only for option a.
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Given K is the midpoint of line segment CR, line segment MA bisects angle CMR. conclusion?
From the given image, on which you have that MA bisect angle CMR, you can conclude:
- Inside the parallelogram ACMR you have four congruent triangles.
- Angles MKR and CKA are congruent, that is, these angles have the same measure.
- Angles CKM and AKR are congruent.
Exercises 11.3- omplete the following: Find the slope of a line parallel to the line through the points. (a) (2, 5) and (4, -6)
If the lines are parallel then the slopes will be equal
The slope is the ratio of the rate of change in y coodinate with respect to rate of change in x coordinate
[tex]\text{ Slope=}\frac{y_2-y_1}{x_2-x_1}_{}[/tex]The given pair of coordinates : (2,5) and (4,-6)
[tex]\begin{gathered} \text{ Slope = }\frac{-6-5}{4-2} \\ \text{ Slope=}\frac{-11}{2} \end{gathered}[/tex]The slope of the line is -11/2
The slope of the line parallel to line whose coordinates are (2,5) and (4,-6) is -11/2
Every 3 months, homeowners in boice pay $46.00 for service provided by the city. how much do homeworkers pay in one year? (1 year = 12 months)
We were told that in every 3 months, homeowners in boice pay $46.00 for service provided by the city.
Given that there are 12 months in a year, the number of 3 months in a year would be
12/3 = 4
This means that $46 would be paid 4 times in a year.
Thus, the amount that the homeworkers would pay in a year is
4 * 46 = $184
Did you turn the volume of the cylinder given. Calculate using pi on calculator and grounded to the nearest tenth. Is the correct option A, B, or C?
V= 14726 ft^3
Which option shows a DISCRETE data set? >>> CORRECT ANSWER: The NUMBER OF CARS that I pass through an intersection EVERY HOUR. >> Why is this discrete? Your answer
Discrete measure:
Assumes countable values. For example, 0, 1, 2, 3,...
It does not assume decimal numbers, for example 2.5. There is not half a car, so the number of cars will always be a discrete measure.
solve for tangent x= -1 in radians without a calculator
Answer:
[tex]x\text{ = }\frac{3}{4}\pi\text{ or }\frac{7}{4}\pi[/tex]Explanation:
Here, we want to calculate the value of x without using a calculator
We have to look for the quadrants where the tan is negative
These are the second and the fourth quadrant
On the second quadrant, we have the reference angles as:
[tex]180-x[/tex]Mathematically in degrees:
[tex]\begin{gathered} \text{if tan x = 1} \\ x\text{ = 45 deg} \end{gathered}[/tex]Now, on the second quadrant, we have it that:
[tex]180-45\text{ = 135 deg}[/tex]On the fourth quadrant, we have the reference angle calculated as:
[tex]\begin{gathered} 360-\theta \\ \theta\text{ = 360-45} \\ \theta\text{ = 315 deg} \end{gathered}[/tex]Lastly, we have to convert these angles to radians
Mathematically, 1 pi is 180 degrees:
[tex]\begin{gathered} 1\text{ }\pi=\text{ 180 deg} \\ x\text{ = 135 deg} \\ x\text{ = }\frac{135\pi}{180}\text{ = }\frac{3}{4}\pi \\ \\ \text{Lastly:} \\ 1\pi\text{ = 180 deg} \\ x\text{ = 315 deg } \\ \\ x\text{ = }\frac{315}{180}\pi\text{ = }\frac{7}{4}\pi \end{gathered}[/tex]Michael is constructing a boat ramp. He knows that the angle of elevation of the ramp is 30°. If the distance from the bottom of the boat ramp to the top of the boat ramp is 40 feet, what is the height of the boat ramp?
Let's draw a rough figure:
Here, h is the distance we are solving for.
Now,
With respect to the given angle 30 degrees, we have the hypotenuse and want to find the opposite side.
The trig ratio relating opposite side and hypotenuse is SINE.
Thus, we can write:
[tex]\sin (30)=\frac{opposite}{\text{hypotenuse}}=\frac{h}{40}[/tex]Cross multiiplying, we solve for h [remember, value of sin(30) is 1/2]:
[tex]\begin{gathered} \sin (30)=\frac{h}{40} \\ h=40\times\sin (30) \\ h=40\times\frac{1}{2} \\ h=20 \end{gathered}[/tex]The height of the boat ramp is 20 feet.
Write the function below in slope intercepts form. Show all the steps
we need to find the equation in the form y=mx+b, so:
4x+y=5
y=-4x+5
the "4x" go subtracting to the other side
and we have m=-4 and b=5
so the answer is: y=-4x+5
Define the domain of the following:A. -3,-2,-1,0,1,2,3,4,5,6,7,8,B. 3,-1,2,0,-2C. -3,-1,1,3,6D. All real numbers
The domain is the values of x in the given graph
Since the graph is some points
(-3, 3), (-1, -1), (1, 2), (3, 0), (6, -2)
Then the domain is the x-coordinates of all point
D = {-3, -1, 1, 3, 6}
The answer is C
Write a general formula to describe the variation. M varies directly with the square of d and inversely with the square root of x; M=12 when d=3 and x=4
Given that 'M' varies directly with the square of 'd',
[tex]M\propto d^2[/tex]Given that 'M' varies inversely with the square root of 'x',
[tex]M\propto\frac{1}{\sqrt[]{x}}[/tex]Combining the relationships,
[tex]M\propto\frac{d^2}{\sqrt[]{x}}[/tex]Let 'k' be the constant of proportionality. Then,
[tex]M=k\cdot\frac{d^2}{\sqrt[]{x}}[/tex]Given that M=12 when d=3 and x=4,
[tex]\begin{gathered} 12=k\cdot\frac{(3)^2}{\sqrt[]{4}} \\ 12=k\cdot\frac{9}{2} \\ k=\frac{12\cdot2}{9} \\ k=\frac{8}{3} \end{gathered}[/tex]Substitute the value of this constant in the general expression,
[tex]M=\frac{8}{3}\cdot\frac{d^2}{\sqrt[]{x}}[/tex]Thus, the required general formula to describe the relation is obtained as,
[tex]M=\frac{8}{3}\cdot\frac{d^2}{\sqrt[]{x}}[/tex]simplify the expression so there is only one positive power for the base -5
When we are dividing, exponents are subtracted!
The rule is shown below:
[tex]a^b\div a^c=a^{b-c}[/tex]We can apply this rule to this problem as shown:
[tex]\begin{gathered} -5^7\div-5^2 \\ =-5^{7-2} \\ =-5^5 \end{gathered}[/tex]A man is approaching a pole 75 feet high and walking at the rate of
3 miles/hour. At what rate is he approaching the top of the pole
when he is 100 feet away from the pole?
Answer:
375!
Step-by-step explanation:
3 x 100 = 300
Now he is at the pole. Now he has to get to the top of it
which your basically doing
3 x 100 = 300 + 75 = 375
( 375 - 75 = 300 300 ÷ 100 = 3 )
Please answer correctly! Giving brainliest!
Describe in words where cube root of 30 would be plotted on a number line.
Between 3 and 4, but closer to 3
Between 3 and 4, but closer to 4
Between 2 and 3, but closer to 2
Between 2 and 3, but closer to 3
Answer:
A) Between 3 and 4, but closer to 3======================
First, find the cubes of 2, 3 and 4 and then compare them with 30.
2³ = 8,3³ = 27,4³ = 64We see that 30 is between 27 and 64 and is closer to 27:
27 < 30 < 64Therefore cube root of these numbers are:
∛27 < ∛30 < ∛643 < ∛30 < 4So the ∛30 is between 3 and 4 and closer to 3.
Correct answer choice is A.
Answer:
A) Between 3 and 4, but closer to 3.
Step-by-step explanation:
A perfect cube is the result of multiplying the same integer three times.
First few perfect cubes: 1, 8, 27, 64, 125, etc.To estimate the value of the cube root of a number, find the perfect cubes above and below the number:
The perfect cubes either side of 30 are:
27 < 30 < 64Therefore, the cube roots are:
[tex]\implies \sf \sqrt[3]{27} < \sqrt[3]{30} < \sqrt[3]{64}[/tex]
[tex]\implies \sf 3 < \sqrt[3]{30} < 4[/tex]
As 30 is closer to 27 than 64, the cube root of 30 is closer to the cube root of 27 than the cube root of 64.
Therefore, the cube root of 30 would be plotted on a number line:
between 3 and 4, but closer to 3.There are 45 students in the 4th grade at Akili Academy. If Ms. Lause found out that 68% of them attended the football game over the weekend, how many students attended the game? You may have to round to the closest whole student.
There are 45 students in the 4th grade at Akili Academy. If Ms. Lause found out that 68% of them attended the football game over the weekend, how many students attended the game? You may have to round to the closest whole student.
we have that
45 students represents -------> 100%
so
Applying proportion
Find out how much students represents 68%
45/100=x/68
solve for x
x=(45/100)*68
x=30.6
therefore
the answer is 31 students