a thin, straight, uniform rod of length 1.10 m and mass 250 kg hangs from a pivot at one end. what is its period for small-amplitude oscillations?

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Answer 1

The period for a small amplitude oscillation on a thin, straight, uniform rod 1.10 m long and 250 kg mass hangs from a pivot at one end = 2.09 s.

Harmonic vibration

Harmonic vibration is the alternating motion of an object through an equilibrium point that has a fixed frequency and period. An example of harmonic vibration is a pendulum.

Period (T) is the time needed to do one vibration. Meanwhile, the frequency (f) is the number of vibrations that occur in one second. The period and frequency of the pendulum depend on the length of the string and the acceleration due to gravity, and are independent of the mass of the pendulum. The period and frequency of the pendulum can be expressed using the following equation:

T  = 2[tex]\pi[/tex][tex]\sqrt{\frac{L}{g} }[/tex]

f = [tex]\frac{1}{2\pi }[/tex]  [tex]\sqrt{\frac{L}{g} }[/tex]

Where,

T = period (s)

f = frequency (Hz)

L = length (m)

g = acceleration of gravity (9.8 m/s²)

We have,

L = 1.10 m

So,

T = 2[tex]\pi[/tex][tex]\sqrt{\frac{L}{g} }[/tex]

= 2[tex]\pi[/tex][tex]\sqrt{\frac{1.10}{9.8} }[/tex]

= 2.09 s

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Related Questions

if the net force of a system is a non-zero constant and the mass decreases, what must be true about the acceleration?(1 point)

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When the net force of a system is a non-zero constant and the mass decreases then the acceleration will be increased.

What is acceleration?

The acceleration of a moving object can be described as the rate of change of velocity of an object over time. The acceleration of an object can be specified as a vector quantity exhibiting both magnitude and direction. Acceleration can also be expressed as the second derivative of position w.r.t. time.

From Newton's 2nd law of motion, the exerted force is equal to the product of the object's mass and acceleration of an object.

F = ma

a = F/m

Therefore, the acceleration in an object is inversely proportional to the mass of the object.

So, if the net force of a system is a non-zero constant and the mass of the system is decreased its acceleration will be increased.

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a plank having mass 6.6 kg rides on top of two identical solid cylindrical rollers each having radius 4.6 cm and mass 1.9 kg. the plank is pulled by a constant horizontal force 6 n applied to its end and perpendicular to the axes of the cylinders (which are parallel). the cylinders roll without slipping on a flat surface. there is also no slipping between cylinders and plank. m r m r f m find the acceleration of the plank. answer in units of m/s 2 .

Answers

The acceleration of  plank which is weighing 6.6 Kg will be 0.90 m/s²  to ride it with a force of 6 N.

What is acceleration?

Acceleration is the rate of change in velocity. It is a vector quantity and thus having both magnitude and direction. According to Newton's second law of motion, the force acting on a moving body is the product of its mass and acceleration.

Thus, a force is needed to accelerate the body having a mass m and the relation is written as:

f = m a

Given that, mass of the plank is 6.6 kg

horizontal force acting on the plank = 6N

hence, acceleration = force/mass = 6 N/6.6 Kg = 0.9 m/s².

Therefore, the acceleration of the plank is 0.9 m/s².

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refer to question 12 on page 6/7: a type ii cepheid has an apparent magnitude of 12 and a pulsation period of 3 days. what is the approximate distance to this cepheid variable star?

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Is the approximate distance to this cepheid variable star 4,000 parsecs

The distance modulus equation will be used for distance to the sapid variable. The formula will be m. M is equivalent to 5 log d - 5 minus m. Now that we need to determine d, we can rearrange the equation. by writing, then We will discover that d is equal to 10 when we multiply m by m minus m plus 5 and divide by 5. Substitute now.

The values are: d equals 10 equals 12 less 1 less plus 5 divided by 5. When you solve for d, you will find that it is equivalent to 3090.1 per since d is equal to 10 to 18, divided by five, which is equal to 10, is to 3.6. As a result, the cepheid variable star is 3090.1 per second.

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in a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. the matter forms an accretion disk that orbits the white dwarf. then a specific sequence of events must take place for a nova event to occur.a. Material accumulates onto white dwarf's surface increasing in temperature and density b. Nuclear fusion reactions cause the an enormous but temporary increase in luminosity c. At a temperature of 10 million K, the accumulated surface hydrogen begins nuclear fusion d. As nuclear fuel is burned up or blown into space, fusion ceases and the star dims 1. first step2. last step

Answers

The correct order is:

Material accumulates onto the white dwarf's surface, increasing in temperature and density.

At a temperature of 10 million K, the accumulated surface hydrogen begins nuclear fusion.

Nuclear fusion reactions cause an enormous but temporary increase in luminosity

As nuclear fuel is burned up or blown into space, fusion ceases and the star dims.

What occurs when a white dwarf is in a binary star system?

A tight binary star system allows the companion star of a white dwarf or neutron star to give mass to the other star. A white dwarf's surface material has the potential to suddenly burst into fusion, creating a nova.

What type of binary system is needed for a nova to occur?

An eruption from the surface of a white dwarf star in a binary star system is known as a nova. When a white dwarf, which is the dense core of a former normal star, "steals" gas from a neighboring companion star, a nova is a result. When the white dwarf's surface accumulates enough gas, an explosion results.

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anderson video - ampere's law 2 of 5 review | constants first, launch the video ampere's law. after watching the video, answer the follow-up question below. select to launch video part a a solenoid has 15 turns per centimeter of its length. the solenoid is twisted into a circle so that it becomes shaped like a toroid. what is the magnetic field at the center of each turn of the toroid? the current is 57 ma.

Answers

A magnetic field's influence is perceived in the area of space known as the magnetic field. The following formula is used to determine the magnetic field at the center of each rotation of the toroid:

B = μnI

where as;

μ is permeability of empty space = 12.56x 10⁻⁷ Tm/A

There are 18 rotations each centimeter, which equates to 1,800 turns per meter.

I = 57 m is the solenoid's current.

A = 0.057A

B = (12.56 x 10⁻⁷) x (1,500) x (0.057)

B = 1.08 x 10⁻⁴ T

Is the magnetic field at the center zero?

At the core of a bar magnet, the resultant magnetic field is zero.

What does a toroid's magnetic field at its core look like?

Since there is no net current flowing through this region, the magnetic field is also zero. The toroid therefore has no magnetic moment.

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Since the beginning of time some people have believe that the earth is flat beginning around 300 BC however some began to wonder if the earth is actually spherical in shape

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Since the beginning of time, some people have believed that the earth is flat, then the example demonstrates that argumentation is a necessary part of scientific inquiry. Hence, option B is correct.

What is Earth?

In terms of size and mass, Earth is the third planet from the Sun and the fifth-largest planetary in the solar system. The only site in the cosmos known to support life is in its close-surface conditions, which is its most notable characteristic. The emblem serves as a designation. The word "Earth" is derived from the Old English and Germanic meanings for "ground" and "earth," and it is the only title for a planet in our solar system that does not originate from Greco-Roman mythology. English is the world's most widely used astronomical language.

This reasoning is a crucial part of every scientific research since it offers a variety of hypotheses about the scientific concerns that must be supported. Among these hypotheses, only one provides a thorough explanation of the phenomenon.

As a result, it can be seen in the given question that ideas about the form of the earth over time have demonstrated that argumentation is a component of the scientific process.

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Your question is not complete, the complete might be like this:

Since the beginning of time, some people have believed that the Earth is flat. Beginning around 300 B.C., however, some began to wonder if the Earth is actually spherical in shape. Those that favored the flat Earth theory made the following observations: The Earth is stable because it is a flat landmass sandwiched between a flat layer of air and a flat layer of water. If the Earth is spherical, then oceans should be curved on top, but they aren't. Some rivers flow for hundreds of miles but only fall a few feet. The rivers should fall farther if the Earth is spherical. If the Earth is spherical, people and animals that inhabit the Earth would notice as they walked along its surface. Since mariners are able to use flat compasses to navigate their ships without crashing, the Earth must not be a sphere. Those that disputed the flat Earth theory countered the claim by observing that Christopher Columbus was able to sail around the Earth without falling off the edge and later, by presenting satellite imagery taken from space of a spherical Earth. This example demonstrates that

A. scientific knowledge is unattainable.

B. argumentation is a necessary part of scientific inquiry.

C. it is easy to resolve a scientific argument.

D. it is not possible to settle a dispute.

an airplane traveling at half the speed of sound emits a sound of frequency 4.90 khz. (a) at what frequency does a stationary listener hear the sound as the plane approaches? khz

Answers

The frequency does a desk bound listener pay attention the sound because the aircraft approaches is 10.0kHz

Calculation :

velocity of the of sound (air plane) v= 172m/s

frequency emmited n=four.9 kHz

       = four.9*[tex]10^{three}[/tex]

n' =[tex](frac{V-Vo}{V-V,} )*n\[/tex]

[tex]V,[/tex]= [tex]frac{V}{2}[/tex]

Then the obvious frequency heard wiil be

n' =[tex](four.nine*10^{three} Hz)(frac{V}{V-frac{V}{2} } )[/tex]

   = (4.nine[tex]10^{3}Hz[/tex]*)(2)

   =10.0kHz

Frequency is the quantity of occurrences of a repeating event according to unit time. [1] For readability, additionally called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to 1 event in keeping with 2d. length is the reciprocal of frequency due to the fact period is the time c language between events. [2]

For example, if the coronary heart beats 120 instances according to minute (2 hertz), the length T (the c language between repeated beats) is zero.5 seconds (60 seconds divided by way of one hundred twenty beats). cost). Frequency is an crucial parameter used in technological know-how and engineering to explain the speed of vibrations and vibrational phenomena inclusive of mechanical vibrations, audio indicators (sound), radio waves, and light.

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a ferry boat is 4.00 m wide and 6.00 m long. when a large loaded truck pulls onto it, it sinks 4.00 cm in the water. what is the weight of the truck?

Answers

The weight of the truck is 9408 N.

What is density?

Mass per unit volume is the definition of density for a material substance. The equation for density is d = M/V, where D is density, M is mass, and V is volume. Density is frequently measured in grams per cubic centimeter. In comparison, the density of the Earth is 5.51 g/cc, while the density of water is 1 g/cc. It is also possible to calculate density as kilograms per cubic meter.

Given,

Length  = 6.0m

Width = 4.0m

Depth = 4.00cm

We are aware of this,

The truck's weight equals the volume of water it has moved.

weight of the truck = [tex]m_{water}[/tex]×g

We are aware of this,

density = mass/volume

mass = density X volume

weight of the truck = [tex]p_{w}[/tex]×[tex]V_{w}[/tex]×g

Now,

The volume = length × width ×4 depth

V = 6×4×0.04

V = 0.96m³.

Weight of the truck = 1000×0.96×9.8

Weight of the truck = 9408kg m/s²

Weight of the truck = 9408 N.

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What is the change in internal energy if 20j of heat is released?

Answers

The change in Internal energy will be 20J.

In chemistry and physics, the internal energy (U) is defined as the total energy of a closed system.

Internal energy is the sum of the system's potential energy and the system's kinetic energy.

The change in internal energy of a reaction (ΔU) is equal to the heat gained or lost (enthalpy change) in a reaction if the reaction were carried out at constant pressure.

The internal energy of an ideal gas is a good approximation of real-world systems.

In such a system, particles in an ideal gas appear as point objects that collide with each other in a perfectly elastic way.

For an ideal gas, the internal energy is proportional to the number of moles of gas and its temperature: U = cnT

u=dq+W

u=20J [w=0]

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light striking a metal surface causes electrons to be emitted from the metal via the photoelectric effect. part a in a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?

Answers

The number of electrons emitted from the metal per second increases.

when the intensity of the incident light is extended, even as its frequency is held regular, extra photons will hit the metal consistent with unit time and a larger number of electrons can be emitted in step with unit time. Experimentally, this corresponds to better maximum currents discovered between the anode and cathode.

The photoelectric effect is the emission of electrons while electromagnetic radiation, including light, hits a fabric. Electrons emitted in this way are referred to as photoelectrons. The phenomenon is studied in condensed rely on physics, solid nation, and quantum chemistry to attract inferences approximately the houses of atoms, molecules, and solids. The effect has been discovered in use in digital devices specialized for light detection and precisely timed electron emission.

The experimental results disagree with classical electromagnetism, which predicts that continuous mild waves switch power to electrons, which could then be emitted after they collect sufficient strength. An alteration inside the depth of mild would theoretically trade the kinetic strength of the emitted electrons, with sufficiently dim light ensuing in a behind-schedule emission.

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What is the wavelength of a Colour of frequency 4 x 10 14 Hz in a medium of refractive index 1.5 *?

Answers

Answer:

Approximately [tex]5.00 \times 10^{-7}\; {\rm m}[/tex] ([tex]500\; {\rm nm}[/tex].)

Explanation:

Look up the speed of light in vacuum: [tex]c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}[/tex].

If the speed of light in a medium is [tex]v[/tex], the refractive index  of that medium will be [tex]n = (c / v)[/tex]. For the medium in this question, it is given that [tex]n = 1.5[/tex]. Rearrange the equation [tex]n = (c / v)\![/tex] to find [tex]v[/tex]:

[tex]\begin{aligned}v &= \frac{c}{n} \\ &\approx \frac{3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}}{1.5} \\ &\approx 2.00 \times 10^{8}\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Let [tex]f[/tex] denote the frequency of this wave. When the speed of this wave is [tex]v[/tex], the wavelength [tex]\lambda[/tex] of this wave will be [tex]\lambda = (v / f)[/tex]. Therefore:

[tex]\begin{aligned}\lambda &= \frac{v}{f} \\ &\approx \frac{2.00\times 10^{8}\; {\rm m\cdot s^{-1}}}{4 \times 10^{14}\; {\rm s^{-1}}} \\ &\approx 5.00 \times 10^{-7}\; {\rm m} \\ &= 500\; {\rm nm}\end{aligned}[/tex].

(Note that [tex]1\; {\rm Hz} = 1\; {\rm s^{-1}}[/tex].)

finally, remind yourself the properties of light from the first lecture and qs1. if instead of pulses, the astronaut had sent a continuous beam of green light. how would that light appear to those on the spaceship?

Answers

Although the green light flashes first, you are moving away from it, so it illuminates you at the same moment as the red light.

A green laser is frequently used by amateur astronomers because its visible beam may be used to point out stars and galaxies because it penetrates the atmosphere so far. Red lasers are less adaptable than green lasers. Each wave or component of light in a laser has been precisely aligned to form a single, strong beam.

Green DPSS lasers are the most popular and first emerged on the market about 2000. (also called diode-pumped solid-state frequency-doubled, DPSSFD). Due to the rarity of laser diodes in this wavelength region, they are more complicated than regular red laser pointers.

Green lasers have been used in head-mounted displays and laser guides for defense and security purposes. Amateur astronomers can also direct and track stars using green laser guides.

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When a spring is stretched by 2cm It stores 100 J of energy?

Answers

The spring constant is 50000 N/m.

The spring constant is a measure of the stiffness of a spring.

Springs with higher stiffness are more difficult to stretch. Under the action of external forces, the spring is deformed and returns to its original position when the force is removed. Spring constant is denoted by 'k' and has a SI unit as N/m.It has different values for different springs and different material.

Electric potential energy of a spring can be calculated as P.E. = (1/2)*k*x²

where, k is the spring constant,

x is the displacement caused by the spring

The spring stores energy = 100 J

Displacement suffered by the spring = 2 cm = 0.02 m

P.E. = (1/2)*k*x²

k = (2*P.E.) / x²

k =  (2 * 100) / (0.02)²

k = 200 / 0.0004

k = 50000 N/m

The spring constant for a spring which stores 100 J energy is 50000 N/m.

The question is incomplete the complete question is "When a spring is stretched by 2cm It stores 100 J of energy? What is the spring constant".

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i need to know 2 types of matter and descriptions of them

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Solids and liquids or gases

A wheel 31 cm in diameter accelerates uniformly from 240 rpm to 360 rpm in 6. 8 s. How far will a point on the edge of the wheel have traveled in this time?.

Answers

Within 6.8 s, a point on the edge of the wheel have traveled a distance of  6,619.12 cm.

The problem can be solved using the equation of rotational motion.

α = (ω_t - ω_o) / t

Where:

α  = angular acceleration

ω_t  = final rotational speed

ω_o = initial rotational speed

t = time period

The angle travelled is given by:

∅ = ω_o x t + 1/2 x αt²

∅ = ω_o x t  + 1/2 x [ (ω_t - ω_o) / t] t²

∅ = 1/2 (ω_o + ω_t ) x t

Parameters given:

ω_o = 240 rpm = 25.13 rad/s

ω_t = 360 rpm = 37.7 rad/s

t = 6.8 s

Hence,

∅ = 1/2 (25.13 + 37.7 ) x 6.8 = 213.2 rad

The wheel radius:

r = 31 cm

The wheel perimeter:

C = 2 x π x 31 = 194.68 cm

Since the whole angle of a circle is 2π rad, then the travelled angle is equal to:

213.2 / 2π = 34 wheel perimeter.

Hence,

the distance travelled = 34 x 194.68 cm = 6,619.12 cm

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when making batter to use for frying foods, which liquid will require the most amount of starch in order to thicken the batter to a good consistency?

Answers

Flour and salt solution is the classic thickener ingredient for the batter to use for frying foods.

Flour is a powder made by grinding raw grains, roots, beans, nuts or seeds. They are used to make many different foods.

Steps to  to thicken the batter to a good consistency:

Mix flour and salt in a bowl.Gradually add the ice water, whisking constantly, until the mixture is smooth.Add more water if needed. batter should be thick enough to coat the back of a spoon.

Flour contains a high proportion of starch, which are a subgroup of complex carbohydrates also known as polysaccharides, and when mixed with a salt and water solution the overall liquid contains a large amount of starch which can be used to thicken the batter to a good consistency.

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using a cable with a tension of 1470 n, a tow truck pulls a car 5.00 km along a horizontal roadway. part a how much work does the cable do on the car if it pulls horizontally? express your answer with the appropriate units.

Answers

The work done by the string on the auto is 7350J.

In each case the forces are constant and the relegation(displacement) is along a straight line, so

Work = F.s cos θ

Where,

F = force

S = relegation (displacement)

Since, it's vertical to the road

so,

θ = 0 °

All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.

Given,

force = 1470 N

s = 5 km

Now,

Work = 1470.5. cos 0

Work = 7350 J

Thus, the work done by the string on the auto is 7350J.

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a 10:0 kgmass starts at the top of an incline that is 8:0 mlong and makes an angle of 400above the horizontal. as it slides down, there is a constant frictional force of 23:8 n. what is its speed at the bottom?

Answers

Speed at the bottom V = 8.45 m/s

Frictional force = μmg

                    23.8     = μ × 10 × 9.8

                      μ   = 0.24

acceleration  = g (sin 40 ° - μ cos 40°)

acceleration = 9.8 (0.64 - 0.24 × 0.766)

a = 4.47 m/[tex]s^{2}[/tex]

[tex]v^{2}[/tex] = [tex]u^{2}[/tex]  + 2as

V = [tex]\sqrt{2*4.47*8}[/tex]

V = 8.45 m/s

When a sound wave is propagating through an elastic material, the speed of sound is the distance covered per unit of time. The speed of sound in air is approximately 343 meters per second (1,235 km/h; 767 mph; 667 kn) at 20 °C (68 °F), which translates to a distance of one kilometer or one mile in 2.91 or 4.69 seconds. The medium through which a sound wave travels and temperature both have a significant role in this. Nearly 331 m/s (1,086 ft/s; 1,192 km/h; 740 mph; 643 kn) is the speed of sound in air at 0 °C (32 °F). [1]

Only temperature and composition affect the ideal gas's speed of sound. Frequency and pressure have a negligible impact on speed.

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A 2. 0 kg body is initially traveling at a velocity of 40 m/s east. If a constant force of 10 n due east is applied to the body for 5. 0 s, the final speed of the body is.

Answers

The Final speed of the body is = 65 m/s

The values that are given in the question are,

Mass of body = 2.0 kg

Velocity of the body = 40 m/s

Force = 10 N

Time = 5.0 s

Firstly we need to calculate the momentum change of the body,

The formula for change in momentum,

⇒ Change in momentum = Force x Time

⇒ Change in momentum = 10 x 5.0

⇒ Change in momentum = 50 kg-m/s

Now we have to calculate the change in velocity,

⇒ Change in velocity = Change in momentum / Mass

⇒ Change in velocity = 50 / 2.0

⇒ Change in velocity = 25 m/s towards east

Now to calculate the final velocity

⇒ Final velocity = initial velocity + change in velocity

⇒ Final Velocity = 40 + 25 = 65 m/s

Therefore, the final speed of the body is = 65 m/s

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light of wavelength 587.5 nm illuminates a slit of width 0.75 mm. (a) at what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.85 mm from the central maximum? (b) calculate the width of the central maximum

Answers

A 0.75 mm-wide slit is illuminated by light with a wavelength of 587.5 nm. If the initial minimum in the diffraction pattern is to be 0.85 mm from the central maximum, a screen should be placed 83 mm away from the slit. The width of the central maximum should be 45 m.

The spatial period, often known as the wavelength, of a wave is the length over which its shape repeats. Along with traveling and standing waves, it is a feature of various spatial wave patterns. It is the distance between two successive wave positions that have the same phase, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the wavelength's reciprocal. Greek letter lambda is typically used to represent wavelength. The term wavelength is occasionally used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids. A sinusoidal wave flowing at a constant speed has an inverse relationship between its wavelength and frequency. The wavelength of a wave depends on the medium it passes through, such as a vacuum, air, or body of water. Music, light, water, and periodic electrical signals in a conductor are all examples of waves. Sound waves are fluctuations in air pressure, whereas light and other electromagnetic radiation employ variations in electric and magnetic field strength. Water waves are variations in the height of a body of water. A crystal lattice shakes, causing changes in atomic positions.

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If the initial minimum in the diffraction pattern is to be 0.85mm from the central maximum, a screen should be positioned 1.1m from the slit.

b) the width of the central maximum is 47×[tex]10^{-5} m[/tex]

Wavelength of light = 587.5nm

Single slit width 'a' = 0.75mm

y1  = 0.85mm

[tex]L=Y_{1} \frac{a}{\lambda}[/tex]

a) The distance from the center  of the central maximum is:

[tex]Y_{1}= \frac{\lambda}{a}[/tex]

Required distance to the screen is:

[tex]L=Y_{1} \frac{a}{\lambda}[/tex]

=[tex]0.85 *10^{-3}m*(\frac{0.75*10^{-3}m }{587.5*10^{-9} m } )[/tex]

=1.1m

b)  The width of the central maximum is

There are dark bands (minima) where,

[tex]sin\Theta=m\frac{\lambda}{a}[/tex]

For the first minimum, the value of m=1

[tex]sin\Theta=m\frac{\lambda}{a}[/tex]

=[tex]\frac{587.5*10^{-9}m }{0.75*10^{-3} m}[/tex]

=[tex]47*10^{-5} m[/tex]

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at what displacement of a sho is the energy half kinetic and half potential? express your answer in terms of aaa .

Answers

The displacement of SHO at which the energy half kinetic and half potential is

A/√2

How to calculate displacement if KE and PE are half?

In case of, no frictional forces on a simple harmonic oscillator the kinetic and potential energies of the simple harmonic oscillator are transformed alternatively, but total mechanical energy is conserved.

At equilibrium position the total energy of the simple harmonic oscillator is equal to kinetic energy

The potential energy U of a simple harmonic oscillator at a given displacement x from the equilibrium position is given as follows:

U=1/2kx²

Here, k is the spring constant.

The kinetic energy K of a simple harmonic oscillator at a given displacement is given as follows:

K=1/2mv²

Here, m is the mass attached to the spring, and v is the speed of the mass at a given displacement.

The total mechanical energy E of a system is equal to the sum of potential energy U and kinetic energy K.

E=U+K

Substitute,

E=1/2kx²+1/2mv²

At extreme position, the displacement x is equal to amplitude A, and speed of oscillator is equal to zero.

Substitute

E=1/2kA²+12m(0)²

E=1/2kA²

Now,  if the total mechanical energy is proportional to square of the amplitude of the simple harmonic oscillator, then, the potential energy U of a simple harmonic oscillator at a given displacement x is,

U=1/2kx²

Equate half of total mechanical energy and potential to find the displacement.

E/2=U

Substitute

1/2(1/2kA²) =1/2kx²

A²/2=x²

x=A/√2

The displacement of SHO at which the energy half kinetic and half potential is

A/√2

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an object of mass m is rotating about a fixed axis with angular momentum l. its moment of inertia about this axis is i. what is its kinetic energy?

Answers

The Kinetic energy would be 1/2IL².

What is Rotational Kinetic energy ?

Rotational energy also known as angular kinetic energy is defined as: The kinetic energy due to the rotation of an object and is part of its total kinetic energy. Rotational kinetic energy is directly proportional to the rotational inertia and the square of the magnitude of the angular velocity.

As we know linear Kinetic energy = 1/2mv²

 where m= mass and v= velocity.

Similarly rotational kinetic energy is given by = 1/2IL²

 where I- moment of inertia and L=angular momentum.

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what is the highest spectral order that can be seen if a grating with 1850 slits per cm is illuminated with 594 nm laser light? assume normal incidence.

Answers

The spectral order of 9 is seen on the screen.

What is diffraction grating?

The clarity of the pattern is enhanced and the maxima narrow as the number of slits in an obstacle increases. Diffraction gratings are objects with a lot of slits—say, more than 20 to the millimeter. In the late eighteenth century, Fraunhofer created the first of these, which were made of fine silver wire strung on two parallel screws and provided 30 impediments per millimeter.

The equation we have in interference and diffraction pattern is

Y = mLR/d

d sinθ = mL

Where,

L = wavelength

m = order = 1,2,3,4 (for bright bands)

m = 1.5, 2.5, 3.5, 4.5 (for dark bands)

R = resistance from slit to screen

Y = distance from central spot to [tex]n^{th}[/tex] order fringe.

Applying values in d sinθ = mL

d = 1/1850 = 5.405μm

θ = 90

So, m = 5.405 μm/594 nm

m = 9.099 = 9.

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When light shines on a sample, each element emits specific wavelengths producing a unique fingerprint called its ______ spectra.

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When light shines on a sample, each element emit specific wavelength producing a fingerprint called its line spectra.

When light falls on a shining surface it makes a specific pattern.

These patterns are either in the form of bright lights are in the form of dark lights which are uniform in nature providing a particular pattern for each and every light.

This line spectra is the result of the light of different frequencies emitted by the excitation and releasing of electrons from there respective orbitals in an atom.

Basically these line spectra provides a fingerprint of the specific wavelength emitted by each element.

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What is the wave speed if the wavelength is 5 meters and the frequency is 4 Hz?

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The speed of wave is 20m/sec  if the wavelength of wave is 5 meters and the frequency of the wave is 4Hz.

At the point when a wave goes through reflection, it simply stays in the medium and just switches its heading of movement. The smooth wave has voyaged twofold its distance. This reflection peculiarity of waves is regularly seen in sound waves.

At the point when you let out a noisy cry inside a ravine, you frequently hear the reverberation of the holler. The sound waves travel through the medium; for this situation, the air and bounce off the gulch wall and return to the beginning of the sound (you). The outcome is that you hear the reverberation of your holler.

We know that when a electromagnetic wave is travelling through speed v passing in a medium, it contains certain speed and wavelength which is given by the formula

c=ν × λ

where c is the speed of light in vacuum,

ν is the frequency of the wave and

λ is the wavelength of the wave.

Now, we have frequency(ν) = 4Hz, and wavelength(λ)=5meters.

So, using the above formula, we get

c=4 × 5

=>c=20m-Hz

or c=20m/sec as 1Hz=1 /sec

Hence, wave speed is 20m/sec.

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when the displacement of a mass on a spring is 1212 aa , what percentage of the energy is kinetic energy?

Answers

The percentage of kinetic energy is not determined by the displacement of the mass; it is determined by the velocity of the mass. To calculate the percentage of kinetic energy, you would need to know the velocity of the mass.

The percentage of energy that is kinetic energy depends on the velocity of the mass. If the mass is at rest, then there is no kinetic energy and all of the energy is potential energy. If the mass is moving, then the percentage of kinetic energy depends on the speed of the mass.

At any given displacement, the potential energy of the mass on a spring is equal to 1/2 kx^2, where k is the spring constant and x is the displacement. The kinetic energy of the mass is equal to 1/2 mv^2, where m is the mass and v is the velocity.

In the given example, if the displacement is 1212 aa, then the potential energy of the mass is (1/2)k(1212)^2. The kinetic energy of the mass is (1/2)mv^2. Since the velocity is not given, we cannot calculate the percentage of kinetic energy.

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Deep surveys of the universe indicate that the largest structures in space are no larger than about 50 mpc in size.t/f

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Deep surveys of the universe indicate that the largest structures in space are about 50 Mpc in size is false.

Deep surveys of the universe indicate that the largest structures in space are no larger than about 50 Mpc in size. If the universe had an edge, that fact would violate the assumption of isotropy in the cosmological principle. Hubble's law implies that the universe will expand forever.

The cosmological principle is based on two observations and an assumption, that the universe is the same everywhere, it is the same in every direction, and that the laws of physics are the same everywhere. The statement that the universe is homogeneous regards the universe on very large scales.

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a loop antenna with loop radius of 0.4 m is made of copper wire of radius 4 mm. if the loop radiates at 6 mhz and carries a current of 50 a, find (a) the radiation resistance of the loop (b) the power radiated

Answers

The radiation resistance of the loop is 99.9 % and the power radiated 4.97 KW.

The real resistance = 8 π² (L/λ)²

L = 2πr

λ = C/f

power radiated = [tex]I^{2}[/tex]/r = 80 × 3.14 × 3.14 × 4× 3.14 × 3.14 × 0.4 × 0.4/2500

Power radiated =  4.97 KW

Radiation efficiency = Radiation resistance / radiation resistance + ohm resistance

ρL/A = 8 × [tex]10^{-8}[/tex]  = 1.99 /  8 × [tex]10^{-8}[/tex] + 1.99

99.9 %

The definition of radiation is energy that emanates from a source and moves at the speed of light through space. This energy has wave-like characteristics and is surrounded by an electric and magnetic field. Electromagnetic waves are another name for radiation. In nature, there are many different types of electromagnetic radiation. One example is visible light. The highest energy radiation comprises x-rays, gamma rays, and ultraviolet light. Both X-rays and gamma rays are extremely energetic. They can take electrons out of atoms when they engage with them, ionizing the atom in the process. Our cells' DNA can be harmed by radiation. High radiation exposures can result in cutaneous radiation injuries (CRI) or acute radiation syndrome (ARS) (CRI).

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what gauge pressure in the water mains is necessary if a firehose is to spray water to a height of 45 mm ?

Answers

The necessary gauge pressure in the water mains is approximately 70 kPa (10 psi).

The pressure necessary in the water mains to spray water to a height of 45 mm depends on factors such as the diameter of the hose, the length of the hose, the type of nozzle used, and the specific gravity of water.

Assuming the hose is of a standard size (e.g. 1.5 inch diameter) and the nozzle is designed for a nozzle pressure of 70 psi, then the pressure necessary in the water mains would be 70 psi + the pressure required to push the water 45 mm (1.8 inches) up the hose.

To calculate the pressure required, we use Bernoulli's equation:

P1 + (1/2)*ρ*V1^2 = P2 + (1/2)*ρ*V2^2

Where P is the pressure, ρ is the density of water, and V is the velocity of the water.

Assuming the velocity of the water at the nozzle is 10 m/s, and the density of water is 1000 kg/m^3, then the pressure necessary in the water mains to spray water to a height of 45 mm is 90 psi.

P1 + (1/2)*1000*10^2

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which of these stars will take the shortest time to go from the earliest protostar stage to the main sequence?

Answers

The stars which will take the shortest time to go from the earliest protostar stage to the main sequence is: the star ten times the mass of our sun.

The correct answer choice is option b.

What is meant by the stars?

A star can simply be defined as a luminous body which is usually, frequently and most of the time found in the night sky. However, a star is a also an incandescent body just the like the sun and it is in a fixed point. Below are some few characteristics of the star:

A star is massiveA star is a celestial bodyA star shines by radiation A star is held together by gravityA star also produce Its own lightIt also produce its own heat energy.

In conclusion, it can be deduced from the explanation given above that stars are luminous and highly massive bodies.

Complete question:

Which of these stars will take the shortest time to go from the earliest protostar stage to the main sequence?

a. the star which has the same mass as our sun

b. the star ten times the mass of our sun

c. the star six times the mass of our sun

d. none of the above

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