A sample of liquid ethanol is added to a sealed glass beaker.A sealed beaker contains liquid ethanol, represented as circles. Most of the circles are in the liquid, but a few are in the space above the liquid.Figure © 2019 StrongMindBeaker: BlueRingMedia/ShutterstockWhat will happen to the ethanol after a minute?

A Sample Of Liquid Ethanol Is Added To A Sealed Glass Beaker.A Sealed Beaker Contains Liquid Ethanol,

Answers

Answer 1

We don't have information about how fast the equilibrium will be reached, however, we can analyze the options to see which ones are wrong.

What in fact happens is that the system's previous conditions doesn't matter much. After it is sealed, there is no way something gets out. At first, the system will not be at an equilibrium, it needs some time for that.

The system will have ethanol gas condensating and liquid ethanol evaporating, but at different rates.

Assuming the rate of evaporation is higher at the beginning, we will get more ethanol gas with time, but this will decrease the rate of evaporation a situation where both rates are equal. After that point, the system will be at equilibrium, meaning the amount of liquid and gas won't change anymore.

Having that in mind, the first alternative have the first part wront because the system nees time to get to equilibrium, but its second part is wrong too, because as we said the system will eventually stop getting more ethanol gas.

The second is wrong because both evaporating and condensation are happening at the same time, not one after the other.

The third is wrong because it wil always have an equilibrium. If all ethanol condensates, the rate of condensation will be zero and any evaporation that happens will make some ethanol gas back.

We can't know for sure that 1 minute will be enough to reach the equilibrium, but assuming it is, the fourth alternative perfectly describes what is happening: ethanol condensates and increase the pressure up to a point where both rates equilizes and the system reach the equilibrium.

So, the correct option is the fourth alternative.


Related Questions

5. What is the amount of moles of nitrous oxide gas (N2O) used to sedate Mr. Muthbefore his wisdom teeth are pulled? The pressure is 2.5 atm, a temperature of 25.and volume of 1.67L?tbd

Answers

Step 1 - Understanding how mole relates to temperature, pressure and volume

These variables are related according to the ideal gas equation:

[tex]pV=nRT[/tex]

We can use this equation to predict the behavior as well as the quantity of a gas, given that the remaining variables are given.

Step 2 - Using the equation to solve the equation

According to the exercise:

[tex]\begin{gathered} p=2.5atm \\ T=25°C\text{ \lparen298 K\rparen} \\ V=1.67L \\ n=? \end{gathered}[/tex]

Setting the values in the equation:

[tex]2.5\times1.67=nR\times298[/tex]

We need to make two observations now: the temperature must be in Kelvin in this equation for it to work. R stands for the universal gas constant, as has the value of 0.082 atm.L/mol.K.

Therefore:

[tex]\begin{gathered} 2.5\times1.67=n\times0.082\times300 \\ \\ n=\frac{4.17}{24.6}=0.169\approx0.17 \end{gathered}[/tex]

Answer: the amount of moles used is 0.17 moles.

If something is made of 2.1 g Ni and 0.58 g O, what is the empirical formula?

Answers

To know the empirical formula we will determine how many moles of each element we have. To do this, we must look up in the periodic table the atomic weight of each element.

The atomic weight of Ni = 58.6934 g/mol

O = 15.999 g/mol

Now we divide the mass of each element by its atomic weight to determine how many moles are in the sample.

[tex]\begin{gathered} \text{Mol of Ni = }\frac{\text{Mass of Ni}}{\text{Atomic weight}} \\ Mol\text{ of Ni = }\frac{\text{2.1 g}}{58.6934\text{ g/mol}}=0.036\text{ mol of Ni} \end{gathered}[/tex]

[tex]\begin{gathered} \text{Mol of O = }\frac{Mass\text{ of O}}{\text{Atomic weight}} \\ \text{Mol of O = }\frac{0.\text{58 g}}{15.999\text{ g/mol}}=\text{ 0.036 mol of O} \end{gathered}[/tex]

In the sample, there are 0.036 moles of oxygen and 0.036 moles of Ni. The ratio is 1 to 1, so the empirical formula will be: NiO

Calculate the molarity of a solution that contains 0.75 mol of KCI in 0.250L of solution

Answers

The molarity of a solution that contains 0.75 mol of KCI in 0.250L of the solution is 3 M

The number of moles per liter of solution is termed molarity.

M=n/V(in L)

M is the molarity

n is the number of moles

V is the volume

Substituting the values, we get

M=0.75/0.25=3

The molarity is 3 M

Molarity is a concentration term and denotes the number of moles dissolved per liter.It can be defined as the amount of substance in a particular volume of solution.The unit is mol/LIt can be found by the given mass and volume of the solution.

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A testing chamber holds a 2.50 L sample of neon gas at 325.0 K.If the pressure is measured inside the chamber as 4.00 atm, how many moles of neon are present?0.4530.44200.3750.326

Answers

Answer: There are 0.375 moles of neon gas present in the testing chamber.

Explanation:

The question requires us to calculate the number of moles of neon gas, given that the gas is in a 2.50 L chamber at 325.0 K and the pressure inside the chamber is 4.00 atm.

We can solve this problem using the equation for ideal gases, as shown below:

[tex]PV=nRT[/tex]

where P is the pressure of the gas (P = 4.00 atm), V is the volume of the gas (V = 2.50 L), n is the number of moles, that we want to calculate, T is the temperature of the gas (T = 325.0 K) and R is the gas constant.

Note that the values of pressure and volume are given in atm and L, respectively. Therefore, we can apply the gas constant in units of L.atm/mol.K:

R = 0.082057 L.atm/K.mol

First, let's rearrange the equation of ideal gases in order to calculate the number of moles of gas:

[tex]PV=nRT\rightarrow n=\frac{PV}{RT}[/tex]

Now, applying the values given by the question and the constant R, we'll have:

[tex]n=\frac{(4.00atm)\times(2.50L)}{(0.082057L.atm/K.mol)\times(325.0K)}=0.375mol[/tex]

Therefore, there are 0.375 moles of neon gas in the testing chamber under the conditions given by the question.

Balance the following half-reaction in acid (some electrons, e, will be needed to balance it):Fe²+ ——-> FeO4²-

Answers

The balanced half-reaction is Fe²⁺ + 2e⁻ --------> FeO₄²⁻

The given reaction is a redox reaction. Balancing a redox reaction is a bit different than solving a normal chemical reaction. The first step is to find the oxidation state of each element in the reactant as well as the product side. By doing so we get,

The oxidation state of Fe - +2

On the product side, we get,

The oxidation state of Fe - +6

The oxidation state of O - -2

The next step is to calculate the difference between the oxidation states.

The difference in oxidation state of Fe - +6 - (+2) = +4

The difference in oxidation state of O - 0 -2 = -2

To balance this reaction, 2 electrons should be added to the reactant side so that the oxidation states of O and Fe get balanced equally. By doing so we get,

Fe²⁺ + 2e⁻ --------> FeO₄²⁻

This is a balanced half-reaction in acid

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Please please help please please help me please please help

Answers

A single bond is made up of 1.0 sigma bond and no pi bonds.

Pi bonds appears from double bonds onwards.

What mass of oxygen is needed to burn 54.0 g of butane

Answers

Answer

The mass of oxygen needed to burn 54.0g of butane is 193.24 g

Explanation

Given:

Mass of butane = 54.0 g

What to find:

The mass of oxygen needed to burn 54.0g of butane.

Step-by-step solution:

Step 1: Write the balanced chemical equation for the reaction.

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Step 2: Convert 54.0 g of butane to moles

Molar mass of C₄H₁₀ = 58.12 g/mol

[tex]Moles=\frac{Mass}{Molar\text{ }mass}=\frac{54.0\text{ }g}{58.12\text{ }g\text{/}mol}=0.9291\text{ }mol[/tex]

Step 3: Use the mole ratio in step one and the mole of C₄H₁₀ in step 2 to calculate the mole of oxygen.

[tex]\begin{gathered} 13\text{ }mol\text{ }O_2=2\text{ }mol\text{ }C_4H_{10} \\ \\ x=0.9291\text{ }mol\text{ }C_4H_{10} \\ \\ x=\frac{0.9291\text{ }mol\text{ }C_4H_{10}}{2\text{ }mol\text{ }C_4H_{10}}\times13\text{ }mol\text{ }O_2 \\ \\ x=6.03915\text{ }mol\text{ }O_2 \end{gathered}[/tex]

Step 4: Convert the moles of O₂ in step 3 to mass in grams.

Molar mass of O₂ = 31.998 g/mol

[tex]\begin{gathered} Mass=Moles\times Molar\text{ }mass \\ \\ Mass=6.03915mol\times31.998g\text{/}mol \\ \\ Mass=193.24\text{ }g\text{ }of\text{ }O_2 \end{gathered}[/tex]

Hence, the mass of oxygen needed to burn 54.0g of butane is 193.24 g

Convert 960 Torr to kPa

Answers

Step 1

Torr and kPa are units of pressure

---------

Step 2

The equivalence:

760 torr = 101325 Pa

1 kPa = 1000 Pa

Procedure:

960 Torr x (101325 Pa/760 Torr) = 127989.47 Pa

Then, 127989.47 Pa x (1 kPa/1000 Pa) = 128 kPa approx.

Answer: Pressure = 128 kPa

Write a net ionic equation for this reaction.Express your answer as a chemical equation. Identify all of the phases in your answer.ANSWER:

Answers

Given the reaction:

[tex]2HNO_3+Ca(OH)_2\to Ca(NO_3)_2+2H_2O[/tex]

We're going to write a net ionic equation for this reaction as follows:

1. First, write the total ionic equation:

[tex]^{}Ca^{2+}_{aq}+2OH^-_{aq}+2H^+_{aq_{}}+2NO^-_3\to^{}Ca^{2+}_{aq}+2NO^-_3+2H_2O[/tex]

2. Now, we could cancel the same type of ions that are in both sides of the reaction. Therefore, the net ionic equation is:

[tex]H^+_{aq}+^{}OH^-_{aq}\to H_2O_{(l)}[/tex]

A balloon is filled to a volume of 1.50 L with 2.50 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume of the balloon if 0.20 moles of gas are added?

Answers

The final volume of the balloon if 0.20 moles of gas are added will be 1.62 L.

What will be the volume of the balloon given that 0.20 moles of a gas is added to it?

The volume of the balloon given that 0.20 moles of a gas is added to it is determined using the ideal gas equation as follows:

P₁V = nRT

Where;

P is pressureV is volumen is the number of moles of gasR is molar gas constant = 0.082 atm.L/K.mol

Initial volume, V₁ = 1.50 L

Initial mole of gas, n₁ = 2.50 mol

Initial temperature, T₁= 25°C or 298 K

Initial pressure, P₁ = RT₁n₁/V₁

P₁ = 0.082 * 298 * 2.50 /1.50

P₁ = 40.7 atm

With pressure and temperature held constant:

Final temperature, T₂ is equal to T₁ = 298 K

Final pressure, P₂ is equal to P₁ = 40.7 atm

Final moles of gas, n₂ = 0.20 + 2.5

n₂ = 2.70 mol

Final volume, V₂ = RT₂n₂/P₂

V₂ =  0.082 * 298 * 2.70 /40.7

V₂ = 1.62 L

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please help!! 100pts and brainliest!
Rb+
Fe2+
H-
Al3+
Cl-
O2-
Using the ions above, write the formulas and give the names for 5 possible ionic compounds involving these ions.

Answers

The formulas and and  the names for 5 possible ionic compounds involving these ions are :

Rb₂O, Rubidium Oxide

FeCl₂, Iron(II)chloride

Al(OH)₃ , Aluminum hydroxide

LiH, Lithium Hydride

NaCl, Sodium chloride

1) The  Rb₂O is called as Rubidium oxide. rubidium oxide is an ionic compound. Ionic compound formed between a positive ion called cation and a negative ion called anion . ionic bond is formed with the complete transfer of electrons. In Rubidium oxide : the cation is Rb⁺ and the anion is O²⁻.

2) The FeCl₂ is called as iron(II)chloride. iron(II)chloride is an ionic compound. in  iron(II)chloride : the cation is Fe²⁺ and the anion is Cl⁻.

3) Al(OH)₃ is aluminum hydroxide . In aluminum hydroxide : the cation is present as Al³⁺ and anion is present as OH⁻.

4) LiH is lithium hydride . the cation is Li⁺ and the anion is H⁻.

5) NaCl is sodium chloride. cation is Na⁺ and anion is Cl⁻

Thus, The formulas and and  the names for 5 possible ionic compounds involving these ions. Rb₂O, Rubidium Oxide

FeCl₂, Iron(II)chloride

Al(OH)₃ , Aluminum hydroxide

LiH, Lithium Hydride

NaCl, Sodium chloride

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A chemical formula of an unknown metal (M) combines with chlorine in the followingformula:MC15What is the charge of the metal

Answers

Answer:

The charge of the metal is +5.

Explanation:

As the chlorine atom has a valence of -1, and the metals have a positive valence, we have to look for the charge that makes the molecule neutral.

In this case, there are 5 Cl, so the total negative charge of Cl is -5.

To make the molecule neutral, the metal must have a positive charge of +5.

When the combustion engine was invented it had many positive effects on society. In 1938
scientists concluded that burning fossil fuels would cause which disastrous effect to the
environment?
A. climate change
B. the ozone layer to dissipate
C. increased deforestation
D. increased flooding

Answers

The answer is A Climate change

answer: The burning of fossil fuels leads to climate change so the correct answer is option D

Explanation: Burning fossil fuels releases a large amount of co2 into the atmosphere. C02 is a greenhouse gas so it traps the sun's heat this, in turn, heats up our atmosphere which leads to climate change.

now option B is wrong because the ozone layer is depleted due to ozone-depleting substances which when it comes to contact with ozone damage it and option c is due to human activities

finally, option d is due to climate change and this is an indirect effect of burning fossil fuels.

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How many grams of 12% solution can be prepared from 35 g of CaCl2

Answers

The question provides the concentration of a solution (12% CaCl2) and requests us to calculate how many grams of this solution could be prepared starting from 35g of CaCl2.

Since the concentration of solution is 12%, considering it refers to % in mass, we can write that 12g of CaCl are necessary to prepare 100 g of solution:

12 g of CaCl2 --------------- 100 g of solution

Thus, we can calculate how much solution could be prepared from 35 g of CaCl2:

12 g of CaCl2 --------------- 100 g of solution

35 g of CaCl2 -------------- x

Solving for x, we have that 291.67 g of solution could be prepared from 35g of CaCl2.

How many moles in 2.24 L of a sample of gas.1 mol10 mole0.1 mole5 mol

Answers

Answer:

[tex]0.1\text{ mole}[/tex]

Explanation:

Here, we want to get the number of moles in 2.24 L of a sample of gas

Mathematically,

At STP, 1 mole of a gas occupies a volume of 22.4 L

Thus x moles will occupy 2.24 L at STP

To get the value of x, we have it that:

[tex]\begin{gathered} x\times22.4\text{ = 1}\times2.24 \\ x\text{ = }\frac{2.24}{22.4} \\ \\ x\text{ = 0.1 mole} \end{gathered}[/tex]

Calculate how many grams of MgCl2 are needed to produce 12.15 grams

Answers

Answer

47.60 g

Explanation

Given that:

Molar mass of MgCl₂ = 95.20 g/mol

Mass of Mg produced = 12.15 grams

Equation: MgCl₂ → Mg + Cl₂

What to find:

To calculate the grams of MgCl₂ needed to produce 12.15 grams of Mg.

Step-by-step solution:

Step 1: Convert the mass of Mg produced to moles.

Using the molar mass of Mg (24.305 g/mol) and the mole formula, the moles of Mg produced is

[tex]Moles=\frac{mass}{molar\text{ }mass}=\frac{12.15\text{ }g}{24.305\text{ }g\text{/}mol}=0.49989714\text{ }mol[/tex]

Step 2: Determine the moles of MgCl₂ needed to produce 12.15 g of Mg.

According to the given equation; 1 mol of MgCl₂ produced 1 mol of Mg

So, x mol of MgCl₂ will produce 0.49989714 mol of Mg

That is:

[tex]\begin{gathered} 1mol\text{ }MgCl₂=1mol\text{ }Mg \\ \\ x=0.49989714mol\text{ }Mg \\ \\ x=\frac{0.49989714mol\text{ }Mg}{1mol\text{ }Mg}\times1mol\text{ }MgCl₂ \\ \\ x=0.49989714mol\text{ }MgCl₂ \end{gathered}[/tex]

Step 3: Convert the moles of MgCl₂ needed to produce 12.15 g of Mg to grams.

Using the molar mass of MgCl₂ = 95.20 g/mol, therefore the mass in grams of MgCl₂ needed to produce 12.15 g of Mg will be:

[tex]\begin{gathered} Mass\text{ }of\text{ }MgCl_2\text{ }needed=Molar\text{ }mass\times Moles \\ \\ Mass\text{ }of\text{ }MgCl_2\text{ }needed=95.20\text{ }g\text{/}mol\times0.49989714\text{ }mol \\ \\ Mass\text{ }of\text{ }MgCl_2\text{ }needed=47.60\text{ }g \end{gathered}[/tex]

Hence, the grams of MgCl₂ needed to produce 12.15 grams of Mg is 47.60 g.

write any three chemical properties of carbon

Answers

Answer

• Carbon has the atomic symbol C,

,

• Carbon is a nonmetallic chemical element with 4 electrons in its valence shell, which allows it to form 4 bonds forming compounds like CH₄.

,

• Reactivity: Carbon does not dissolve in or react with water or acids.

,

• The atomic mass of carbon is 12.011 g. It contains 6 protons in its nucleus.

What is the charge on a sulfur atom that contains 18e−e−?

Answers

Sulphur atom has 16 as its atomic number, which is also the same number of protons and the same number of electrons:

Z = 16

P = 16

e- = 16

But when we have a Sulphur ion, it is usually -2, and since we have 18 electrons in this case, the charge will be -2

Calculate the number of molecules in 8.21 x 10^-2 moles in (NH4)2Cr2O7

Answers

Answer

4.94x10^22 molecules

explanation

to calculate the number of molecules in 8.21x10^-2 moles ca be determined by using Avogadros number

we know that

1 mol has 6.022x10^23 molecules

therefore,

8.21x10^-2 moles have:

(8.21x10^-2) x (6.022x10^23)

= 4.94x10^22 molecules

Which of the following best describes an ecosystem in the Great Lakes?

Answers

The statement " all the living organisms in an area and their physical surroundings " will describes an ecosystem in the Great Lakes.

A biological combination of cooperating organisms and surrounding physical environment can be referred to as an ecosystem.

A system made up of biotic and abiotic elements that work together as a whole is called an ecosystem. All live things are considered to be biotic components, although non-living items are considered to be abiotic components.

Therefore, "all the living organisms in an area and their physical surroundings " will define ecosystem in the Great Lakes.

The given question is incomplete. The complete question is

Which of the following best describes an ecosystem?

A. all the living organisms in an area

B. all the living organisms in an area and their physical surroundings

C. a region with a distinct climate

D. all the living organisms of the same species throughout the world

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The mole fraction of NaCl in anaqueous solution is 0.132. Howmany moles of water are present in1 mole of this solution?Molar MassNaCl: 58.44 g/molH2O: 18.016 g/mol

Answers

The problem is asking for how many moles of water there are in 1 mol of solution with NaCl. This is telling us that NaCl is dissolved in water.

There are 0.132 moles of NaCl and summing the moles of water, we're going to obtain 1 mol of solution. You can see it, like this:

[tex]\text{0}.132\text{ moles NaCl+X moles water = 1 mol solution.}[/tex]

We just have to clear for 'X moles water', and we obtain:

[tex]X\text{ moles water = 1-0.132 = 0.868 moles water.}[/tex]

The answer is that we have 0.868 moles of water in the solution.

Using the ΔH -48.8 kJ/mmol, calculate the enthalpy change if you neutralized six moles of HCl with an equal number of moles NaOH to one decimal place.

Answers

Answer:

-292.8J/mmol

Explanations:

Given the reaction of NaCl and NaOH expressed by the chemical equation:

[tex]6HCl+6NaOH\rightarrow6NaCl+6H_2O[/tex]

Amount of heat released when one mole of strong acid reacts with one mole of the strong base is -48.8 kJ/mmol.

If 6 moles of the sample acid reacts with 6 moles of NaOH, the required enthalpy cheange is expressed as:

[tex]\begin{gathered} Amount\text{ of heat released }=6\times-48.8 \\ Amount\text{ of heat released}=-292.8kJ\text{/mmol} \end{gathered}[/tex]

Hence the enthalpy change if you neutralized six moles of HCl with an equal number of moles NaOH is -292.8J/mmol

What is the phase of water at 0.25 atm and 0°C?A. GasB. Solid and liquidC. Solid and gasD. Solid

Answers

Explanation:

We have to find the phase of water at 0.25 atm and 0°C. If we look at the phase diagram of water and throw the lines we will find that the phase of water at those conditions is solid.

Answer: d. Solid

What is the concentration if I have 450 mL of iron (II) chloride (FeCl2) solution that contains9.6 grams of iron (II) chloride solute?

Answers

Answer;

0.168M

Explanations:

The formula for calculating the concentration of the solution is expressed as:

[tex]concentration=\frac{mole}{volume}[/tex]

Determine the moles of iron(II) chloride

[tex]\begin{gathered} mole\text{ of FeCl}_2=\frac{9.6g}{126.751g\text{/}mol} \\ mole\text{ of FeCl}_2=0.0757moles \end{gathered}[/tex]

Given that volume is 0.45L, hence the concentration is expressed as:

[tex]\begin{gathered} concentration=\frac{0.0757}{0.45} \\ concentration=0.168M \end{gathered}[/tex]

Hence the concentration of the solution is 0.168M

2C2H2 + 5O2 —> 4CO2 + 2H2OIf 3.80 moles of oxygen wre used up in the reaction, how many moles of water are produced?

Answers

In order to solve this question, we can use the concept of molar ratio, which means the amount of reactant is needed in order to produce a certain amount of product. In our question we have:

2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O

The molar ratio between O2 and H2O is 5:2 (we use only the numbers in front of the compound), so that means that for every 5 moles of O2 used, we will have 2 moles of H2O being produce, now we can use this information to calculate how many moles of H2O will be produced from 3.80 moles of O2

5 O2 = 2 H2O

3.80 O2 = x H2O

x = 1.52 moles of H2O are produced from 3.80 moles of O2

Force and distance are used to calculate work. Work is measured in which unit?

Answers

Answer: Joules (J)

Explanation:

Answer:

Joules or Newton metre

Explanation:

Work = Force × distance

Force = kgm/s² (Newton)

×

Distance = m

= kgm²/s² (Newton metre or Joules) (Nm or J)

4 N2H3CH3 (l) + 5 N2O4 (l) →12 H2O(g) + 9 N2(g) + 4 CO2 (g)The enthalpy of formation for liquid methylhydrazine is +53 kJ/mol and the enthalpy of formation for liquid dinitrogen tetroxide is -20 kJ/mol. Calculate ∆H° for this reaction, ignore significant digits for this question.

Answers

Answer

[tex]\Delta H_{rxn}\operatorname{\degree}=-4791.6\text{ }kJ\text{/}mol[/tex]

Explanation

The given chemical equation for the reaction is:

[tex]4N_2H_3CH_3(l)+5N_2O_4(l)\text{ }→\text{ }12H_2O\left(g\right)+9N_2\left(g\right)+4CO_2(g)[/tex]

From the given table and question, the enthalpies of formation of the reactants ad products are:

[tex]\begin{gathered} ∆H_f°(N_2H_3CH_{3(l)})=+53\text{ }kJ\text{/}mol \\ \\ ∆H_f°(N_2O_{4(l)})=-20\text{ }kJ\text{/}mol \\ \\ ∆H_f°(H_2O_{(g)})=-258.8\text{ }kJ\text{/}mol \\ \\ ∆H_f°(N_{2(g)})=0\text{ }kJ\text{/}mol \\ \\ ∆H_f°(CO_{2(g)})=-393.5\text{ }kJ\text{/}mol \end{gathered}[/tex]

The ∆H° for this reaction can be calculated using the formula below:

[tex]\Delta H_{rxn}\degree=ΔH_f^{\degree}(products)-ΔH_f^{\degree}(reactants)[/tex]

Put the each enthalpy of formation of the reactants and the products into the formula:

[tex]\begin{gathered} \Delta H_{rxn}\degree=[12(-258.8)+9(0)+4(-393.5)]-[4(+53)+5(-20)] \\ \\ \Delta H_{rxn}\degree=[-3105.6+0-1574]-[212-100] \\ \\ \Delta H_{rxn}\degree=-4679.6-112 \\ \\ \Delta H_{rxn}\degree=-4791.6\text{ }kJ\text{/}mol \end{gathered}[/tex]

Therefore, the ∆H° for this reaction is -4791.6 kJ/mol.

QUESTION 2How many moles are in 37.16 g of calcium sulfate,CaSO4

Answers

In order to find the number of moles in a given mass of any compound, we need to use the molar mass of this compound, which is the total mass present in 1 mol of the compound. The molar mass of CaSO4 is 136.14g/mol

136.14 grams = 1 mol of CaSO4

37.16 grams = x moles of CaSO4

136.14x = 37.16

x = 37.16/136.14

x = 0.27 moles of CaSO4

In 37.16 grams, we will have 0.27 moles of CaSO4

The theoretical value isa) true valueOb) experimental valueOc) observed valueO d) measured value

Answers

Answer:

[tex]A\text{ : True value}[/tex]

Explanation:

Here, we want to get another name for the theoretical value

The theoretical value is simply the value that has been accepted as true

Thus, we can call the theoretical value the true value

16. Which of the following is directly responsible for acid rain? A. steam vented from a nuclear power plant B. sulfur dioxide released from a coal-fired power plant. C. mining of coal for a coal-fired power plant D. processing of uranium for a nuclear power plant

Answers

Answer

B. sulfur dioxide released from a coal-fired power plant.

Explanation

Power plants release the majority of sulfur dioxide and much of the nitrogen oxides when they burn fossil fuels, such as coal, to produce electricity. In addition, the exhaust from cars, trucks, and buses releases nitrogen oxides and sulfur dioxide into the air. These pollutants cause acid rain.

Therefore, what is directly responsible for acid rain is:

B. sulfur dioxide released from a coal-fired power plant.

Other Questions
Given the recursive formula shown, what are the first 4 terms of the sequence? A) 5, 25, 100, 400B) 5, 14, 60, 236C) 5, 25, 125, 625D) 5, 20, 80, 320 (40s + 100t) + 6 distributive property to write the products in standard form Please give me an explanation and the answers on question 3 Amer class, Mrs. Sandoval picked up several piece of paper containing students' work from SHAVN ELLA LEVI 263.140)14) + 2(3.4)() 602.86 units 21314)(a)) 2512 unit 23.425) - 2/3 4729 RUBY KATRINA LORENZO 22 28.141815) 218.1489 663.12 units 2[3.2) 203.4)(48) + 213.)(4) 30144 units Which student found the total surface area of a cylinder with a height that was two times greater than its radius? O Ruby O Lorenzo O Ella O Levi solve the following system y=5x-33x-8y=24 Solve for x and simplify your solutions:x^2 = 63Select ALL the correct answers.answer choices include:18797-3737-187-97 Andrei gauged the level of exposure to his marketing campaign using the percentage of the target population exposed at least once to his advertisement, representing its. I'll show you the picture of the question I'm struggling with There are 4 options on the dessert menu at a restaurant. Bill and Laura like all of the choices equally, so theyeach choose a dessert at random from the menu. What is the probability that Bill will choose apple pie andLaura will choose strawberry cheesecake for dessert? Express your answer as a decimal. If necessary, roundyour answer to the nearest thousandth.O 0.083O 0.250 0.938O 0.063 given the childhood experiences that typically precede borderline personality disorder, some multicultural theorists believe that the disorder may actually be a reaction to persistent feelings of: Let f(x)=x2-2 and g(x)=9-X. Perform the composition or operation indicated.(fg)(-7) A population of values has a normal distribution with = 159.8 and = 59.5 . If a random sample of size n = 13 is selected, Find the probability that a single randomly selected value is greater than 156.5. Round your answer to four decimals. P(X > 156.5) = Find the probability that a sample of size n = 13 is randomly selected with a mean greater than 156.5. Round your answer to four decimals. P(M > 156.5) = A scientist records 61 moreshooting stars in the fall than in the spring.There are 15 shooting stars in the spring.How many shooting stars are in the fall? A diagram is shown, where kill and Move statements and reasons to the table to provem is a transversal.that 21 25.mReasonsStatements1. kl-K2.1. Given2. Corresponding anglesare congruent.3.253763.4. 215 254.A Linear Inequalities (Level 1)Sep 30, 10:57:41 PMWatch help videoSolve the following inequality for p. Write your answer in simplest form.8p + 10 > -5p - 1P 3.13 Which triangle congruence postulate or theorem proves that these triangles are congruent? I have four legs but never walk. I may be covered in flowers but have no soil. I hold food each day butnever eat a meal. What am I? The United Stated Supreme court is:*O Elected to six-year termsO The supreme law of the landO Restricted by state lawsO Restricted to decisions regarding federal law Find the algebraic form g(x) of the function g whose graph is produced by the following transformations on thegraph of f(x) = : The graph of f is reflected vertically, expanded horizontally by a factor of 2, shifted right 6 units, and shifteddown 4 units. Include graphs off and g as a part of your answer. Write 2 proportions so that the product of the means equal 27