Solve the following inequality for p. Write your answer in simplest form.
8p + 10 > -5p - 1
group terms
8p+5p > -1-10
13p > -11
p > -11/13
you previously learned that a unit rate is a rate in which the second quantity in the comparison is one unit, such as 4 ounces per 1 serving. Describe the relationship between ounces of salsa and small jars of salsa using a unite rate.
Suppose there are 81 ounces of salsa in 9 small jars of salsa. To find the unit rate, you have to divide the number of ounces by the number of jars, as follows:
[tex]\frac{81\text{ ounces of salsa}}{9\text{ small jars}}=\frac{81}{9}\frac{\text{ounces of salsa}}{\text{small jars}}=9\text{ }\frac{\text{ounces of salsa}}{\text{small jar}}[/tex]That is, there are 9 ounces of salsa per small jar.
Find the measure of indicated angle. Round to the 10th.
29.6 °
Explanation
we have a right triangle( a triangle with an angle of 90°), so we can use a trigonometric function
so
Step 1
a) Let
[tex]\begin{gathered} \text{angle}=\text{ ?} \\ \text{ hypotenuse( the longest side)= 23} \\ adjacent\text{ side= }20 \end{gathered}[/tex]so, we need to use a function that relates those values, it is
[tex]\begin{gathered} \cos \emptyset=\frac{adjacen\text{t side}}{\text{hypotenuse }} \\ \text{where }\emptyset\text{ is the angle} \end{gathered}[/tex]b) replace the values in the function and solve for the angle
[tex]\begin{gathered} \cos \emptyset=\frac{adjacen\text{t side}}{\text{hypotenuse }} \\ \cos \text{ ? =}\frac{20}{23} \\ \text{ inverse cosine in both sides } \\ \cos ^{-1}(^{}\cos \text{ ?) =}\cos ^{-1}(\frac{20}{23}) \\ \text{ ? = }29.59\text{ \degree} \\ \text{rounded to 10th} \\ \text{ ? = }29.6\text{ \degree} \end{gathered}[/tex]therefore, the answer is
29.6
I hope this helps you
The charge to rent a trailer is $15 for up to 2 hours plus $8 per additional hour or portion of an hour. Find the cost to rent a trailer for 2.9 hours, 3 hours, and 8.7 hours. Then graph all orderedpairs, (hours, cost), for the function,fa. What is the cost to rent a trailer for 2 9 hours?$b. What is the cost to rent a trailer for 3 hours?$c. What is the cost to rent a trailer for 8.7 hours?$d. What is the cost to rent a trailer for 9 hours?
Answer:
Explanation:
Given that the cost to rent a trailer for 2 hours is $15
[tex]\begin{gathered} C(h)=15 \\ \text{for} \\ 0$8 for an hour or a portion of an hour, we have:[tex]\begin{gathered} C(h)=8(h-2)+15 \\ =8h-1 \end{gathered}[/tex]These gives us the piecewise function:
[tex]undefined[/tex]Based on the information marked in the diagram, AABC and _DEF must becongruent.A. TrueB. False
Given:
Two right triangles ABC and DEF are given.
In which AB = DE
Required:
Find the triangles ABC and DEF must be congruent, true, or false.
Explanation:
In triangle ABC and DEF
[tex]\begin{gathered} AB=DE\text{ \lparen Given\rparen} \\ \angle A=\angle D\text{ \lparen90}\degree) \\ \angle C=\angle F \end{gathered}[/tex]Thus the triangles must be congruent.
Final Answer:
Option A is true.
Divide and simplify. Assume all variables result in non-zero denominators.
The simplified form of the given expression is [tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}=\frac{4q(4q-5)}{(q-3)(q-4)}[/tex]
In the given question we have to divide and simplify the given expression.
The given exression is [tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}[/tex].
As we know that when we change division sign into multiplication the fraction after the division change their position.
So the expression should be
[tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}=\frac{4q^2+7q-15}{4q^2-13q-12}\times\frac{16q^2+12q}{q^2-9}[/tex]...............(1)
Before simplifying the expression we firstly find the factor of each term seprately.
Firstly find the factor of [tex]4q^2+7q-15[/tex].
The multiplication of first and third variable is 60 so the possible factors are 12 and 5. So
[tex]4q^2+7q-15=4q^2+(12-5)q-15[/tex]
[tex]4q^2+7q-15=4q^2+12q-5q-15[/tex]
[tex]4q^2+7q-15[/tex] = 4q(q+3)-5(q+3)
[tex]4q^2+7q-15[/tex] = (4q-5)(q+3)
Now finding the value of [tex]4q^2-13q-12[/tex].
The multiplication of first and third term is 48, so the possible factors are 16 and 3.
[tex]4q^2-13q-12=4q^2-(16-3)q-12[/tex]
[tex]4q^2-13q-12=4q^2-16q+3q-12[/tex]
[tex]4q^2-13q-12[/tex] = 4q(q-4)+3(q-4)
[tex]4q^2-13q-12[/tex] = (4q+3)(q-4)
Now finding the factor of [tex]q^2-9[/tex].
Using the formula [tex]a^2-b^2=(a+b)(a-b)[/tex]
[tex]q^2-9=(q)^2-(3)^2[/tex]
[tex]q^2-9[/tex] = (q-3)(q+3)
Now finding the factor of [tex]16q^2+12q[/tex].
[tex]16q^2+12q[/tex] = 4q(4q+3)
Putting the value of factors in equation 1
[tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}=\frac{(4q-5)(q+3)}{ (4q+3)(q-4)}\times\frac{4q(4q+3)}{(q-3)(q+3)}[/tex]
Simplifying
[tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}=\frac{(4q-5)}{ (q-4)}\times\frac{4q}{(q-3)}[/tex]
Hence, the simplified form of the given expression is
[tex]\frac{4q^2+7q-15}{4q^2-13q-12}\div\frac{q^2-9}{16q^2+12q}=\frac{4q(4q-5)}{(q-3)(q-4)}[/tex]
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cost of a parent is $159.95 markup is 20% tax is 3%
that Solving for the retail price of a parrot with 20% markup and 3% taxes
We want to know the retail price of a parrot if it costs us $159.95 , knowing that we want to obtain 20% of profit and we're getting taxed 3%
Firts, we have to calculate the 20% of the original value ($159.95), and add that up. Then, we calculate the 3% of that value ($159.95 + 20% markup) and add it up, asl following:
[tex]\begin{gathered} 159.95\times\frac{20}{100}=31.99\rightarrow159.95+31.99=191.94 \\ 191.94\times\frac{3}{100}=5.76\rightarrow191.94+5.76=197.70 \end{gathered}[/tex]Thus, the retail price of the parrot, with 20% markup and 3% taxes, should be $197.70
Divide:7/4 ÷ 8/732/4949/3217/3281/32
7/4 ÷ 8/7
To divide fraction multiply the first fraction by the reciprocal of the second fraction:
7/4 x 7/8 = (7x7) / (4x8) = 49/32
Find the area A of the polygon with the given vertices. A(-5,-2) , B(4,-2), C(4,-7), D(-5,-7)A=
The area of the polygon is 45 square units.
From the question, we have
The given points make a rectangle with length AB and width AD.
Distance of AB = 4 - (-5) = 9
Distance of AD = -2 - (-7) = 5.
Area = length x width
Area = 9 x 5 =45 square units.
Area of Rectangle:
The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth. In contrast, the circumference of a rectangle is equal to the product of its four sides. Consequently, we can say that the area of a rectangle equals the space enclosed by its perimeter. The area of a square will, however, be equal to the square of side-length in the case of a square because all of its sides are equal.
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ANSWER IMMEDIATELY PLEASE Identify the number of roots each polynomial has.Number one. 3x^4-2x^2+17x-4Number two. 12x^5+x^7-8+4x^2Number 3. 15+6x
Step 1
The degree of the leading term determines how many roots a polynomial has. Examine the highest-degree term of the polynomial – that is, the term with the highest exponent. That exponent is how many roots the polynomial will have. So if the highest exponent in your polynomial is 2, it'll have two roots; if the highest exponent is 3, it'll have three roots; and so on. A polynomial with a leading degree of 5 has 5 roots.
Step 2
[tex]\begin{gathered} Leading\text{ term 3x}^4 \\ Number\text{ of roots 4} \end{gathered}[/tex][tex]\begin{gathered} Leading\text{ term x}^7 \\ Number\text{ of roots 7} \end{gathered}[/tex]
[tex]Number\text{ of roots 1}[/tex]
a transformation where a figure is flipped over a line1. dilation2.translation3.refelction4rotation
The answer is reflection
m/4.5 = 2/5 Solve using scale factorI'm not sure how to use scale factor can you help me please?
[tex]\frac{m}{4.5}=\frac{2}{5}[/tex]
so, m will be calculated as following
find the relation between 4.5 and 5
so,
[tex]\frac{5}{4.5}=\frac{5\cdot10}{4.5\cdot10}=\frac{50}{45}=\frac{5\cdot10}{5\cdot9}=\frac{10}{9}[/tex]so, 5 divided by (10/9) will be equal 4.5
so,
m will be equal to 2 divided by (10/9) =
[tex]\frac{2}{\frac{10}{9}}=2\cdot\frac{9}{10}=\frac{18}{10}=\frac{9}{5}=1.8[/tex]This method is called scale factor
Which mean , we have used the scale factor (10/9) to get m/4.5 from 2/5
So, the answer is m = 1.8
I need help on 3 questions-42 - 6n = -30
hello
the question given is an equation -42 - 6n = -30
step 1
collect like terms
[tex]\begin{gathered} -42-6n=-30 \\ -42+30=6n \\ 6n=-12 \end{gathered}[/tex]step 2
divide both sides by the coefficient of n
[tex]\begin{gathered} 6n=-12 \\ \frac{6n}{6}=-\frac{12}{6} \\ n=-2 \end{gathered}[/tex]from the calculations above, the value of n is equal to -2
I need help on my math
To simplify the expression 19+(11+37), solve first the expression inside the parenthesis:
[tex]11+37=48[/tex]Then:
[tex]19+(11+37)=19+48[/tex]Finally, add 19 and 48:
[tex]19+48=67[/tex]Therefore:
[tex]19+(11+37)=67[/tex]Concrete costs $105 per cubic yard. Plato is making a rectangular concrete garage
floor measuring 33 feet long by 15 feet wide by 6 inches thick. How much will the
concrete cost?
A. $311850
B. $9.17
C. $962.50
D. $247.50
The cost of concrete is $311850.
According to the question,
We have the following information:
Concrete costs $105 per cubic yard. Plato is making a rectangular concrete garage floor measuring 33 feet long by 15 feet wide by 6 inches thick.
We know that the following formula is used to find the volume of cuboid:
Volume of cuboid = 33*15*6
Volume of cuboid = 2920 cubic yard
Now, to find the total cost for concrete, we will multiply the volume of concrete with the cost of concrete per cubic yard.
Cost of concrete = 2920*105
Cost of concrete = $311850
Hence, the correct option is A.
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A 8 kg eagle is flying up in the sky. You pull out your GPE gun and are able to tell that the bird has a GPE of 2,352 J. How high must the birdbe? (remember the bird is on Earth)
Energy = work per unit time
Energy = workdone / time
energy = mgh
m = 8kg
E = 2352J
since the bird is on the earth, definitely the gravitational force will be acting on it
g = 10m/s^2
2352 = 8 x 10 x h
2352 = 80 x h
2352 = 80h
divide both sides by 80
2352/80 = 80h/80
29.4 metres = h
h = 29.4 metres
The answer is 29.4 metres
Given the following diagram, find the required measures.Given: /|| mm24 = 105° and m26 = 50°
The question gives us the following parameters:
[tex]\begin{gathered} m\angle4=105\degree \\ m\angle6=50\degree \end{gathered}[/tex]Recall that the sum of angles on a straight line is 180 degrees. This means that:
[tex]\begin{gathered} m\angle3+m\angle4=180\degree \\ \therefore \\ m\angle3=180-m\angle4=180-105 \\ m\angle3=75\degree \end{gathered}[/tex]Recall that the sum of angles in a triangle is 180 degrees. Thus, we have:
[tex]\begin{gathered} m\angle2+m\angle3+m\angle6=180\degree \\ \therefore \\ m\angle2=180-m\angle3-m\angle6=180-75-50 \\ m\angle2=55\degree \end{gathered}[/tex]The SECOND OPTION is correct.
For each ordered pair, determine whether it is a solution to 7x + 4y = -23(x,y) (2,6) it is a solution yes or no(-5,3) it is a solution yes or no(6-7) it is a solution yes or no(-1,-4) it is a solution yes or no
To do this, first plug the values of x and y into the given equation. If you get a true statement, the ordered pair will be a solution to the equation, otherwise, it won't.
So, for the ordered pair (2,6) you have
[tex]\begin{gathered} 7x+4y=-23 \\ 7(2)+4(6)=-23 \\ 14+24=-23 \\ 38=-23 \end{gathered}[/tex]Since the proposition is false, then the ordered pair (2,6) is not a solution to the equation.
For the ordered pair (-5,3) you have
[tex]\begin{gathered} 7x+4y=-23 \\ 7(-5)+4(3)=-23 \\ -35+12=-23 \\ -23=-23 \end{gathered}[/tex]Since the proposition is true, then the ordered pair (-5,3) is a solution to the equation.
For the ordered pair (6,-7) you have
[tex]\begin{gathered} 7x+4y=-23 \\ 7(6)+4(-7)=-23 \\ 42-28=-23 \\ 14=-23 \end{gathered}[/tex]Since the proposition is false, then the ordered pair (6,-7) is not a solution to the equation.
Finally, for the ordered pair (-1,-4) you have
[tex]\begin{gathered} 7x+4y=-23 \\ 7(-1)+4(-4)=-23 \\ -7-16=-23 \\ -23=-23 \end{gathered}[/tex]Since the proposition is true, then the ordered pair (-1,-4) is a solution to the equation.
If 15 people greet each other at a meeting by shaking hands with one another, how many handshakes take place?
There are 105 handshakes that take place at the meeting.
To find the number of handshakes, we can use a formula that counts the number of combinations of two items from a set of n items.
The formula is:
[tex]n * (n - 1) / 2[/tex]
In this case, n is the number of people, which is 15.
So, we plug in 15 into the formula and get:
[tex]15 * (15 - 1) / 2[/tex]
Simplifying, we get:
[tex]15 * 14 / 2[/tex]
Multiplying, we get:
[tex]210 / 2[/tex]
Dividing, we get:
[tex]105[/tex]
A: 502° CB: 6, 681° CC: 6, 135°CD: 47° C
The idea behind the problem is solving an equation involving square roots. The equation I'm talking about is
[tex]358=20\cdot\sqrt[]{273+t}[/tex](I merely replaced v by 358; what we are supposed to do is to find t). Let's solve it:
1. 20 is multiplying at the right-hand side, let's send it to divide at the left:
[tex]\frac{358}{20}=\sqrt[]{273+t}[/tex]2. (this is the most important step) Take the power of 2 on both sides:
[tex](\frac{358}{20})^2=273+t[/tex]...........................................................................................................................................................
Comment: Remember that
[tex](\sqrt[]{273+t})^2=273+t[/tex]because square root and powering by two are inverse of each other.
...........................................................................................................................................................
3. Put the left-hand side in a calculator to get:
[tex]\frac{128164}{400}=273+t[/tex]4. Let's subtract 273 to the left-hand side:
[tex]320.41-273=t[/tex][tex]47.41\degree C=t[/tex]
Question 4 of attached screenshot, I have all relevant information if required
The derivative of the function is given as:
[tex]g^{\prime}(x)=\frac{x^2-16}{x-2}[/tex]It is also given that g(3)=4.
Note that the Slope of a Tangent Line to a function at a point is the value of the derivative at that point.
Substitute x=3 into the derivative:
[tex]g^{\prime}(3)=\frac{3^2-16}{3-2}=\frac{9-16}{1}=\frac{-7}{1}=-7[/tex]It follows that the slope of the tangent line at x=3 is -7.
Since it is given that g(3)=4, it implies that (3,4) is a point on the line.
Recall that the equation of a line with slope m, which passes through a point (x₁,y₁) is given by the point-slope formula as:
[tex]y-y_!=m(x-x_1)[/tex]Substitute the point (x₁,y₁)=(3,4) and the slope m=-7 into the point-slope formula:
[tex]\begin{gathered} y-4=-7(x-3) \\ \Rightarrow y-4=-7x+21 \\ \Rightarrow y=-7x+21+4 \\ \Rightarrow y=-7x+25 \end{gathered}[/tex]Hence, the equation of the tangent line to the graph of g at x=3 is y=-7x+25.
The required equation is y=-7x+25.
I need to determine the measure in degrees of arc BC??
ANSWER:
120°
STEP-BY-STEP EXPLANATION:
We must calculate the area of the circle, using the following formula:
[tex]\begin{gathered} A=\pi\cdot r^2 \\ \text{ replacing} \\ A=\pi\cdot9^2 \\ A=81\pi \end{gathered}[/tex]We know that this area represents 360 °, we know the area of ABC, therefore we can calculate the amount in degrees that it represents in the following way:
[tex]\begin{gathered} \frac{360}{81\pi}=\frac{x}{27\pi} \\ x=\frac{360\cdot27\pi}{81\pi} \\ x=120 \end{gathered}[/tex]Therefore, the value of arc BC is equal to the angle of area ABC, that is, the arc of BC is equal to 120°
May I please get help with figuring out each triangle
Equilateral Triangle : All sides of triangle are equal
Issoceles Triangle : Only two sides of triangle are equal
Scalene Triangles : No sides of triangle are equal
In triangle A;
Sides of triangle are 8, 8, 4
Since two sides are equal i.e. both are of 8 unit
Thus, two sides are equal
Therefore triangle A is issoceled triangle.
Triangle 2
In the triangle,
All angles are equal which provides that all sides are equa
Therefore, Triangle B is an equilateral triangle
Triangle C;
In the given triangle one is of 90 degree
Since, all the angles areq different so, no two sides are equal
Therefore, triangle C is Scalene
Triangle D
In the given triangle as;
All four sides are equal, thus the triangle is an equilateral triangle
Equilateral triangle
Answer :
.
Remembers since the number is negative to think about what number multiplied by 12 three times
Given:
The number is negative to think about what number multiplied by 3 times give a -125.
Required:
To find the number.
Explanation:
Let the number be x.
[tex]\begin{gathered} x\times x\times x=-125 \\ \\ x^3=-125 \\ \\ x=\sqrt[3]{-125} \\ \\ x=(-5) \end{gathered}[/tex]Final Answer:
The number is -5.
Question 4 Find the Area of the Shaded Region Below 5"
Given data:
The given figure is shown below.
The area of the shaded region is,
[tex]\begin{gathered} A=(20)(10)-2\pi(5)^2 \\ =200-50\pi \\ =42.92\text{ sq-inches} \end{gathered}[/tex]Thus, the area of the shaded region is 42.92 sq-inches.
For the side length of 15ft 6ft and x which is it? the leg or hypotenuse they all have this option presented 2 you
Since the side length of 15ft is opposite the right angle, then this side length of 15ft is the hypotenuse of the triangle.
The other sides are considered the legs of the triangle. Therefore, the side length of 6ft is one of the legs of the triangle.
can you help me please? what is the area of this arrow?
Given
Graph
Procedure
Let's calculate the area of the figure as the sum of the area of the rectangle plus the area of the triangle.
Let's first calculate the area of the rectangle.
[tex]\begin{gathered} A_r=lw \\ A_r=10\cdot4 \\ A_r=40 \end{gathered}[/tex]Now let's calculate the area of the triangle.
[tex]\begin{gathered} A_t=\frac{1}{2}\cdot b\cdot h \\ A_t=\frac{1}{2}\cdot7\cdot6 \\ A_t=21 \end{gathered}[/tex]The total area would be
[tex]\begin{gathered} A_T=A_t+A_r \\ A_T=40+21 \\ A_T=61 \end{gathered}[/tex]The area of the arrow would be 61 sq in
4x – 2y = 20-8x + 4y = -40
We have the system of equations:
[tex]\begin{gathered} 4x-2y=20 \\ -8x+4y=-40 \end{gathered}[/tex]We can tell that the equations are linear combination of each other: if we multiply the first equation by -2 we get the second equation.
[tex]\begin{gathered} -2(4x-2y)=-2(20) \\ -8x+4y=-40 \end{gathered}[/tex]So in fact we have only one equation and two unknowns, so there are infinite solutions to this system.
We can write the solution as:
[tex]\begin{gathered} 4x-2y=20 \\ 2y=20-4x \\ y=10-2x \\ y=-2x+10 \end{gathered}[/tex]Answer: the system has infinte solutions, expressed in the line y=-2x+10.
2 groups of students group a and group B have the age distributions shown below which statement about the distributions is true
The ages of the students of groups A and B are displayed in the histograms.
For group A
We can determine the number of students per age by looking at the bars of the histogram
2 are 15 years old
5 are 16 years old
6 are 17 years old
5 are 18 years old
2 are 19 years old
The total students for group A is
[tex]\begin{gathered} n_A=2+5+6+5+2 \\ n_A=20 \end{gathered}[/tex]To calculate the average age on group a you have to use the following formula
[tex]X^{\text{bar}}=\frac{\Sigma x_if_i}{n}[/tex]Σxifi indicates the sum of each value of age multiplied by its observed frequency
n is the total number of students of the group
For group A the average value is
[tex]\begin{gathered} X^{\text{bar}}_A=\frac{(15\cdot2)+(16\cdot5)+(17\cdot6)+(18\cdot5)+(19\cdot2)}{20} \\ X^{\text{bar}}_A=\frac{340}{20} \\ X^{\text{bar}}_A=17 \end{gathered}[/tex]The average year of group A is 17 years old.
To determine the Median of the group, you have to calculate its position first.
[tex]\begin{gathered} \text{PosMe}=\frac{n}{2} \\ \text{PosMe}=\frac{20}{2} \\ \text{PosMe}=10 \end{gathered}[/tex]The Median is in the tenth position. To determine the age it corresponds you have to look at the accumulated observed frequencies:
F(15)=2
F(16)=2+5=7
F(17)=7+6=13→ The 10nth observation corresponds to a 17 year old student
F(18)=13+5=18
F(19)=18+2=20
The median of group A is 17 years old.
For group B
As before we can determine the number of students per age by looking at the bars of the histogram
2 are 15 years old
3 are 16 years old
4 are 17 years old
5 are 18 years old
6 are 19 years old
The total number of students for group B is
[tex]\begin{gathered} n_B=2+3+4+5+6 \\ n_B=20 \end{gathered}[/tex]The average age of group B can be calculated as
[tex]\begin{gathered} X^{\text{bar}}_B=\frac{\Sigma x_if_i}{n} \\ X^{\text{bar}}_B=\frac{(2\cdot15)+(3\cdot16)+(4\cdot17)+(5\cdot18)+(6\cdot19)}{20} \\ X^{\text{bar}}_B=\frac{350}{20} \\ X^{\text{bar}}_B=17.5 \end{gathered}[/tex]The average age for group B is 17.5 years old
Same as before, to determine the median you have to calculate its position in the sample and then locate it:
[tex]\begin{gathered} \text{PosMe}=\frac{n}{2} \\ \text{PosMe}=\frac{20}{2} \\ \text{PosMe}=10 \end{gathered}[/tex]The median is in the 10nth position, to determine where the 10nth student is located you have to take a look at the accumulated frequencies:
F(15)=2
F(16)=2+3=5
F(17)=5+4=9
F(18)=9+5=14 →The 10nth observation corresponds to a 18 year old student
F(19)=14+6=20
The median of group B is 18 years old
So
[tex]\begin{gathered} X^{\text{bar}}_A=17 \\ X^{\text{bar}}_B=17.5_{} \\ Me_A=17 \\ Me_B=18_{} \end{gathered}[/tex]The mean and median of group B are greater than the mean and median from group B. The correct choice is the first one.
Which of the following is equivalent to a whole number?v25v10v40
The v means a root, so the only whole number is
[tex]\sqrt{25}=5[/tex]What is 2.078 rounded to the hundredths place?
2.078 rounded to the hundredths place is 2.08.
After the decimal, the 0 is the tenth place, the 7 is the hundredth place, and the 8 is the thousandth place. To round to the hundredths place, we look at the number after the 7. Since it his higher than 5, we increase the 7 by 1, to give us a final answer of 2.08.