We know that the inital velity for this motion is 32 ft/s, this means that the height is given by:
[tex]s=-16t^2+32t[/tex]a)
To determine at what time the projectile will reach 272 we plug s=272 in the equation above and solve for t:
[tex]\begin{gathered} -16t^2+32t=272 \\ 16t^2-32t+272=0 \\ t^2-2t+17=0 \\ \text{ then} \\ t=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(1)(17)}}{2(1)} \\ t=\frac{2\pm\sqrt[]{-64}}{2} \end{gathered}[/tex]since the discrimant of the equation is negative this means that the equation does not have real solutions.
This means that the projectile does not reach that height.
b)
To find at what time the projectile return to the ground we equate the expression for the height to zero and solve for t:
[tex]\begin{gathered} -16t^2+32t=0 \\ t(-16t+32)=0 \\ \text{then} \\ t=0 \\ or \\ -16t+32=0 \\ 16t=32 \\ t=\frac{32}{16} \\ t=2 \end{gathered}[/tex]Therefore it takes 2 seconds for the projectile to return to the ground
20. There is a bell at the top of a tower that is 45 m high. The bell weighs 19 kg. The bell has
energy. Calculate it.
Explanation:
Find an energy is E =mgh, so E = 45*10*19=8550j
If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will.
The correct answer is option E.
If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will accelerate but will not spin.
In the absence of air resistance the object will accelerate but will not spin, it is because if there is no air resistance then same amount of force is applied on every part of the object. When all forces are same in all directions then it means net force is zero.
Moreover, the force is being applied in downward direction having same magnitude which leads to the fact that net force is zero.
Thus, the object will not spin as all forces cancel their effect. However, the object will accelerate due to force of gravity.
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The complete question is:
If an irregularly shaped object (such as a wrench) is dropped from rest in a classroom and feels no air resistance, it will:
A) accelerate and turn about its center of gravity with uniform angular acceleration.
B) accelerate and spin until its center of gravity reaches its highest point.
C) accelerate and turn until its center of gravity reaches its lowest point.
D) accelerate and turn about its center of gravity with uniform angular speed.
E) accelerate but will not spin.
A ball is dropped from the top of a cliff. By the time it reaches the ground, all the energy in its gravitational potential energy store has been transferred into its kinetic energy store. If the ball is travelling at 20 m/s when it hits the ground, what height was it dropped from? (Assume that the gravitational field strength is 10 N/kg
Answer:
h = 20 meters
Explanation:
Comment
Comment
The total energy (potential energy) it has at the top of the cliff has a formula of PE = mgh. The KE at the top is zero.
The Kinetic Energy at the bottom is 1/2 m v^2 The PE at the bottom is 0.
Givens
g = 10 N/kg
vf = 20 m/s
h = ?
Formula
mgh = 1/2 m v^2 Its the same energy at the top as at the bottom. It just has exchanged Potential Energy to Kinetic Energy. Cancel the ms
mgh/m = 1/2 m v^2 / m
gh = 1/2 v^2 Multiply by 2
2gh = v^2 Put in the given values
2*10 * h = 20^2 Simplify
20h = 400
h = 400/20
h = 20 meters.
when you drive through deep water, you should dry out your brakes by driving slowly in low gear and apply your brakes lightly. a. true b. false check answers
It is true when you drive through deep water, you should dry out your brakes by driving slowly in low gear
When water surges over a road it can cover up dips, debris, and streets that have been washed away totally. It’s not the street you know no matter how numerous times you’ve driven it. Six inches of water is sufficient to hit the foot of most passenger cars, flooding the exhaust and clearing out you're immobile. Drive in low gear to protect the car. On the off chance that you’re driving an automatic vehicle, keep the speed low enough to remain in, to begin with, or second gear. Keep your foot on the gas and utilize the brake to direct speed. to dry Your Brakes Once you get through the water you don’t need to turn out. You'll dry your brakes after moving through water by braking gently while driving exceptionally slowly.
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A golf club exerts an average force of 33 kN on a ball of mass 0,06 kg. if the golf club is in contact with the golf ball for 5x10-4
'seconds,
calculate:
a) the change in the momentum of the golf ball.
b) the speed of the golf ball as it leaves the ciub.
(a) The change in momentum of the golf ball 0f mass 0.06 kg is
16.5 Ns.
(b) The Speed of the golf ball as it leaves the club is 275 m/s.
What is change in momentum?Change in momentum is the product of mass and change in velocity of a body.
(a) To calculate the change momentum of the golf ball, we use the formula below.
Formula:
ΔM = Ft............ Equation 1Where:
ΔM = Change in momentumF = Forcet = TimeFrom the question,
Given:
F = 33 kN = 33000 Nt = 5×10⁻⁴ sSubstitute these values into equation 1
ΔM = 33000×5×10⁻⁴ ΔM = 16.5 Ns(b) Also, to calculate the speed of the golf as it leaves the club we use the formula below.
Formula:
v = ΔM/m (When the club was at rest)............... Equation 2Where:
v = Speed of the golf as it leaves the clubm = Mass of the golfFrom the question,
Also given:
m = 0.06 kgSubstitute into equation 2
v = 16.5/0.06v = 275 m/s.Hence, The change in momentum and speed of the golf are 16.5 Ns and 275 m/s respectively.
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Determine the fans airflow in m^3/s.Fan has an airflow of about 1.55x10^3 ft^3/minMeaning that about 1.55x10^3 cubic feet of air move over the fan blades each minute
ANSWER:
0.732 m^3/s
STEP-BY-STEP EXPLANATION:
We must convert from ft^3/min to m^3/s.
To do this, we must take into account the following conversion factors:
1 meter is equal to 3.28 feet
1 minute is equal to 60 seconds
Knowing this, we do the conversion just like this:
[tex]1.55*10^3\frac{ft^3}{min}\cdot\left(\frac{1\text{ m}}{3.28\text{ ft}}\right)^3\cdot\frac{1\text{ min}}{60\text{ s}}=0.732\text{ m}^3\text{/s}[/tex]The fans airflow in m^3/s is 0.732
ill give brainliest if you help me
The velocity of a ball about the elbow joint is 30.0rad/s and the ball is 1.30 m from the elbow joint what is he velocity of the ball
Answer:
39.0 meters per second
Explanation:
So the linear speed of the ball then is that distance from the pivot to the ball times by the angular speed. So this is 1.30 meters times 30.0 radians per second which is 39.0 meters per second.
Platform diving in the olympic games takes place at two heights: 5 meters and 10 meters. A. What is the velocity of a diver entering the water from each platform if he steps off the platform initially?.
The velocity of a diver entering the water from each platform is 14.1 m/s and 10 m/s respectively.
The speed of the compound when dropped from a height H, it will have a velocity V at the bottom which is given by the relation,
V = √(2gH)
Where,
g is the acceleration due to gravity.
The height of the diver in the Olympic game is 5m and 10m.
So, putting the values in the above relation and finding the values of the speed of diver when it enters into water is,
V₁ = √(2x10x10) and V₂ = √(2x5x10)
V₁ = 14.1 m/s
V₂ = 10 m/s.
The speed of the each diver entering water is 14.1 m/s and 10m/s respectively.
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a 138 kg refrigerator, 2.00 m tall and 87.0 cm wide, has its center of mass at its geometrical center. you are attempting to slide it along the floor by pushing horizontally on the side of the refrigerator. the coefficient of static friction between the floor and the refrigerator is 0.550. depending on where you push, the refrigerator may start to tip over before it starts to slide along the floor. what is the highest distance above the floor that you can push the refrigerator so that it won't tip before it begins to slide?
The highest distance above the floor that you can push the refrigerator so that it won't tip before it begins to slide is 0.79 m
What is torque?Torque is known to be the rotational equivalent of a linear force. In some fields of study, it is also called moment, moment of force, rotational force, or rotational effect. It describes the ability of a force to effect a change in the rotational motion of an object.
For the given case:
F = μmg
F = frictional resistance
μ = coefficient of static friction (0.55)
m = 138 kg
g = 9.8 m/s²
F = 0.55 × 138 × 9.8
F = 743.82 N
Take the refrigerator's mid-size weight halfway to the floor,
i.e. 0.87/2 = 0.435 m
d = 0.435 m
The torque around the bottom of the refrigerator should be zero to reach the maximum range. So,
F × x = mg × d
x = ( mg × d)/ μmg
x = d/μ
x = 0.435/0.55
x = 0.79 m
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Ethane, C2H6, reacts with oxygen to make carbon dioxide and water. The
equation can be written as: C2H6 + 02 → CO2 + H20. Using the equation,
what are the reactants?
CO2 + H20.
C2H6+02
C2H6
02 + H20
Answer:D is the answer
Explanation:yes
An electric space heater draws 25.0 A from a 200 V source. It is operated, on the average, for 10.0 h each day.At AED 0.30 per kWh, how much does it cost to operate the heater for 15 days?
The cost of energy consumption to operate the heater for 15 days is $2.25
Voltage (V) = 200 V
Current (I) = 25 A
Power (P) = VI = 200 * 25 = 5,000 W
Now, the calculation of the energy consumption for 15 days in KW/h
We will convert W to kW,
1000 W = 1kW
Therefore,
5,000 W = 5000 W × 1 KW / 1000 W = 5kW
The daily energy consumption will be calculated. This is attainable as follows,
P = 5kW
Time(t) = 10 h
Energy (E) = P/t = 5/10 = 0.5 kW/h per day.
Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:
1 day = 0.5 kW
Cost of one day = 0.5 * 0.30 = $ 0.15
Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25
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4.82 the variable resistor in the circuit in fig. p4.82 is adjusted for maximum power transfer to ro. a) find the value of ro. b) find the maximum power that can be deleivered to ro.
Answer:
u don't know this one but try a not for sure
Grant sprints 50 m to the right with an average velocity of 3.0m/s
How many seconds did Grant sprint?
Grant sprinted for 16.67 seconds when his average speed was 3.0 m/s.
With an average speed of 3.0 m/s, Grant sprints 50 meters to the right.
So, the distance covered (s) = 50 m
Average speed (v) = 3.0 m/s
Now,
The formula for evaluating the time(t) is given by,
[tex]t = \frac{s}{v}[/tex]
Now, Putting all the values in the formula to evaluate time, we get:
[tex]t = \frac{50}{3} = 16.67[/tex]
Hence, Grant sprinted for 16.67 seconds.
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an elevator that weighs 3.0 * 10^3 n is accelerated upward at 1.0 m/s^2. what force does the cable exert to give it this acceleration?
The answer is 3306 12M.
Solution:
By Newton Law of muts a:
T- mg = ma
T = ma + mg
T = m (a + g)
= T = 306·12 (1 + 9.8)
=) T = 3306.12 N.
Hence The force act 3306 12M.
This is the application of Newton's second law to the forces you feel in an elevator. It feels heavy when you accelerate and feels light when you accelerate. When the elevator rope breaks, you and the elevator accelerate at the same speed, so you're in weightlessness.
The elevator speeds up or slows down. In any case, the direction of acceleration is upward. The weight acts downward on a person. An upward vertical force acts on a person, and the magnitude of the vertical force is equal to the weight. The net force is due to the small vertical force the elevator exerts on the person. This force, according to Newton's third law is the same as the downward force on the elevator.
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Show that average speed of a rabbit that runs 30m in 2s is 15m/s
The rabbit's average speed is 15m/s because the formula for calculating average speed is Distance divided by time.
What is the average speed?
The average speed of an object can be defined as the total distance traveled by it in a particular interval of time. this can be determined by dividing the total distance moved by the object by the time taken to move.
It is the ratio of the distance the rabbit travels in m and the time taken by the object to travel in seconds.
Hence: Distance D=30m
Time, T=2s
Average Speed S=ΔD/ΔT
S=30m/2s
S=15m/s
Therefore rabbit's Average speed is 15m/s
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what is the ratio of the gravitational force that earth exerts on the sun in the winter and the force that it exerts in the summer?
1:1 is the ratio of the gravitational force that earth exerts on the sun in the winter and the force that it exerts in the summer because it is independent of temperature.
F=GMm/R²
Any action that aims to maintain, alter, or deform a body's motion is considered a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).
According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight path in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changes velocity) in the direction of the force.
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if the marble bounces straight upward to a height of 0.64 m , what is the magnitude of the impulse delivered to the marble by the floor? express your answer to two significant figures and include the appropriate units.
If a 15-g marble is dropped from rest onto the floor 1.4 m below and the marble bounces straight upward to a height of 0.64 m, the magnitude of the impulse delivered to the marble by the floor is 0.312 N s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
During downward motion,
s = - 1.4 m
a = 9.8 m / s²
u = 0 ( Since it is dropped and not thrown )
v² = 0 + ( 2 * 9.8 * - 1.4 )
- v² = 27.44
v = - 5.24 m / s
During upward motion,
s = 0.64 m
a = - 9.8 m / s
v = 0
- u² = 0 + ( 2 * - 9.8 * 0.64 )
u² = 12.544
u = 3.54 m / s
u = 3.54 m / s
J = m Δv
J = Impulse
m = Mass
Δv = Change in velocity
Δv = Initial velocity of upward motion - Final velocity of downward motion
Δv = 3.54 - ( - 5.24 )
Δv = 8.78 m / s
m = 15 g = 0.015 kg
J = 0.015 * 8.78
J = 0.312 N s
Therefore, the impulse delivered to the marble by the floor is 0.312 N s
The given question is incomplete. The complete question is:
A 15-g marble is dropped from rest onto the floor 1.4 m below. If the marble bounces straight upward to a height of 0.64 m, what is the magnitude of the impulse delivered to the marble by the floor?
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Particle Mass (amu)
proton 1.007593
neutron 1.008982
deuterium 2.014186
tritium 3.016448
helium 3 3.015779
helium 4 4.003873
1.0 ev = 1.6 · 10-19 j
1.0 amu = 931 Mev
1 angstrom () = 1 X 10-10m
h = 6.63 · 10-34 J-s.
Always use significant figure rules. Remember that these rules apply to all numbers that are measurements.
The mass of a deuterium nucleus 21H is less than its components masses. Calculate the binding energy.
Mev
The binding energy of deuterium is 2.224 MeV.
Given parameters:
Mass of proton = 1.007593 amu.
Mass of neutron = 1.008982 amu.
Mass of deuterium = 2.014186 amu
We know that: deuterium atom is made up with one proton and one neutron.
So, mass of the components of the deuterium = 1.007593 amu + 1.008982 amu. = 2.016575 amu.
Hence, mass loss = mass of the components of the deuterium - Mass of deuterium
= 2.016575 amu - 2.014186 amu.
= 0.002389 amu.
We know that, 1.0 amu = 931 Mev
So, binding energy = mass loss x 931 Mev
= 0.002389 x 931 Mev
= 2.224 MeV.
Hence, the binding energy of deuterium is 2.224 MeV.
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A simple harmonic oscillator has a mass m=2.0 kg and a spring constant k=800 N/m.a) What is the frequency of oscillations?b) If the oscillator has a maximum speed of v=10.0 m/s, what is the maximum oscillation amplitude?c) What length would a simple pendulum need to be in order to oscillate at the same frequency?
a)
In order to calculate the frequency of oscillations of a simple harmonic oscillator, first let's calculate the period, using the formula:
[tex]\begin{gathered} T=2\pi\sqrt[]{\frac{m}{k}} \\ T=2\pi\sqrt[]{\frac{2}{800}} \\ T=2\pi\sqrt[]{\frac{1}{400}} \\ T=2\pi\cdot\frac{1}{20} \\ T=\frac{\pi}{10}=0.31416\text{ s} \end{gathered}[/tex]Since the frequency is the inverse of the period, we have:
[tex]\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{\frac{\pi}{10}} \\ f=\frac{10}{\pi}=3.183\text{ Hz} \end{gathered}[/tex]b)
In order to calculate the maximum oscillation amplitude given the maximum speed, let's use the formula below:
[tex]\begin{gathered} v_{\max }=X\sqrt[]{\frac{k}{m}} \\ 10=X\cdot\sqrt[]{\frac{800}{2}} \\ 10=X\cdot20 \\ X=\frac{10}{20}=0.5\text{ meters} \end{gathered}[/tex]c)
The formula for the pendulum frequency is:
[tex]\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{2\pi\sqrt[]{\frac{L}{g}}} \\ f=\frac{\sqrt[]{\frac{g}{L}}}{2\pi} \end{gathered}[/tex]Then, for f = 3.183 and g = 9.81, we have:
[tex]\begin{gathered} 3.183=\frac{\frac{\sqrt[]{9.81}}{\sqrt[]{L}}}{2\pi} \\ \frac{\sqrt[]{9.81}}{\sqrt[]{L}}=3.183\cdot2\pi \\ \frac{3.132}{\sqrt[]{L}}=20 \\ \sqrt[]{L}=\frac{3.132}{20} \\ \sqrt[]{L}=0.1566 \\ L=0.3957 \end{gathered}[/tex]So the length is 0.3957 m or 39.57 cm.
How do wings help a plane to fly?
ANSWER
EXPLANATION
We want to find out how wings help a plane to fly.
The wings of an airplane are there to help lift the plane. They are shaped to make air move faster over the wings.
They are used for lifting, landing, turning and controlling the airplane. The curve on the wings make the air move faster than the air at the bottom of the wings which appropriates Bernoulli's principle to push the plane into the air.
Light of frequency 3.62 x 10^15 Hz strikes a surface of copper (W0=4.70 eV). How much kinetic energy does the liberated electron have in eV?
From the equation of photoelectric effect, the kinetic energy is 10.2 eV.
What is the kinetic energy?According to the Einstein photoelectric equation, we know that the kinetic energy is the difference between the energy of the incident photon and the work function of the metal.
KE = E - Wo
KE = kinetic energy
E = energy of the photon
Wo = work function
Thus;
E = hf
h = Plank's constant
f = frequency
E = 6.6 * 10^-34 * 3.62 x 10^15
= 2.39 * 10^-18 J or 14.9 eV
Thus we have;
KE = 14.9 eV - 4.70 eV
KE = 10.2 eV
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Answer:
10.2 eV
Explanation:
there's no need for an explanation
A platinum resistance thermometer has a resistance of 10.40 ohms at00 C and 14.35 ohms at 100 C. Assuming that the resistance changesuniformly with temperature, what is(a) The temperature when the resistance is 11.19 ohms?(b) The resistance of the thermometer when the temperature is 45 C?
(a) 0.05 ° C
(b) 12.17 ohms
Explanation
Assuming that the resistance changes uniformly with temperature we can set the equation of the line
so
Step 1
find the equation of the line:
the equation of a line has the form:
[tex]\begin{gathered} y=mx+b \\ where\text{ m is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]to do that, we need 2 points from the line, so let
x represents the temperature
y represents resistance
[tex]\begin{gathered} P1(0,10.40) \\ P2(100,14.35) \end{gathered}[/tex]now, to find the slope of a line we need to use the expression
[tex]\begin{gathered} slope=\frac{y_2-y_1}{x_2-x_1} \\ where \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]then, replace the values in the formula
[tex]slope=\frac{14.35-10.4}{100-0}=\frac{3.95}{100}=0.0395[/tex]so, the slope is 0.0395
b) now, use the slope point formula to find the equation of the line
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ where\text{ m is the slope and P1\lparen x}_1,y_1) \\ replace \\ y-10.4=0.0395(x-0) \\ y=0.0395x+10.4 \end{gathered}[/tex]so, the equation of the lines is
y=0.0395x+10.4
Step 2
Now, we can use the equation to find the asked values
(a) The temperature when the resistance is 11.19 ohms?
let
[tex]\begin{gathered} resistance\text{ = 11.19,so y=11.19} \\ replace\text{ in the equation and solve for x} \\ y=0.0395x+10.4 \\ 11.19=0.0395x+10.4 \\ 11.19-10.4=0.0395x \\ 0.79=0.0395x \\ x=\frac{0.0395}{0.79}=0.05 \end{gathered}[/tex]therefore
(a) 0.05 ° C
Step 3
(b) The resistance of the thermometer when the temperature is 45 C?
let
[tex]tempereature\text{ = x= 45 C}[/tex]now, replace in the expression to find the resistance
[tex]\begin{gathered} y=0.0395x+10.4 \\ y=0.0395(45)+10.4 \\ y=12.17 \end{gathered}[/tex]therefore,
(b) 12.17 ohms
I hope this helps you
A 0.400kg ball is dropped from a height of 3.00m onto a spring with a spring constant of 600.N/m. How much does the spring compress if the ball comes to a stop.0.313m0.098m0.0392m0.198m
Given data
*The given mass of the ball is m = 0.400 kg
*The given height is h = 3.00 m
*The given spring constant is k = 600.0 N/m
*The value for the acceleration due to the gravity is
[tex]g=9.8\text{ m/s\textasciicircum{}2}[/tex]The expression for the spring compresses at a distance is given by the conservation of energy as
[tex]\begin{gathered} U_s=U_p \\ \text{mgh}=\frac{1}{2}kx^2 \\ x=\sqrt[]{\frac{2mgh}{k}} \end{gathered}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} x=\sqrt[]{\frac{2\times0.400\times9.8\times3.00}{600.0}} \\ =0.198\text{ m} \end{gathered}[/tex]A ball is thrown vertically upward. As it rises, what happens to its kinetic energy?.
The kinetic energy and potential energy of an object continue to decrease when thrown vertically upward.The ball retains the same total energy.The ball will only have potential energy when it reaches its highest point, when its velocity is zero and it has no kinetic energy.
What happens to a ball's kinetic energy when it is thrown vertically up?Zero kinetic energy is produced. The transformation of kinetic energy into potential energy occurs in accordance with the law of conservation of energy. At this height, potential energy is at its highest.
Is there an increase in kinetic energy when a ball is thrown up?We transfer potential energy to the ball when we throw it in the upward direction, allowing it to gain kinetic energy and allow it to rise to a certain height. However, the ball's kinetic energy decreases as it continues to rise in height, eventually reaching zero.
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The more gallons of milk I have, the more cups milk I can pour what’s the independent and dependent variable?
Answer: I think the independent variable is the gallons of milk. and the dependent variable is the amount of milk you can pour.
(The more gallons of milk you have is the thing that changes the whole outcome, which is the amount of milk that can be poured out)
Rate of change of distance
Answer:
Speed
Explanation:
Speed is called as rate of change of distance, speed is a scalar quantity.
Johnathan weighs 650N on Earth. What would his weight be if he was on Jupiter, which has a gravity of 24.8 m/s^2?
3 paragraphs about who Larry page was and what advancements he provided to the world
Larry Page, real name Lawrence Edward Page, is a computer scientist and entrepreneur from the United States who co-founded Goo-gle, one of the most well-known websites on the Internet, with Sergey Brin on March 26, 1973 in East Lansing, Michigan.
Larry Page was drawn to technology at a young age and worked toward his goals. His success is truly inspirational. In the dorms of their college, he and Sergey Brin founded Goo-gle and grew it into a multinational corporation. Working hard is the secret to success.The concept of deciphering the vast amount of data amassing on the Internet interested Brin and Page, who first met while graduate students at Stanford University. They started developing Backrub, an innovative form of search technology, from Page's dorm room at Stanford. a week ago.To know more about Larry Page
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What is the length of our milky way? (astronomy)
Answer:
about 100,000 light years away
Explanation:
What is the milky way galaxy.It's where our solar system is. Scientists gave it that name because it looks like someone spilled a glass of milk.
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