A plan for a park has a rectangular plot of wild flowers that needs to be enclosed by 54 feet of fencing. Only three sides need to be enclosed because one side is bordered by the parking lot. use Desmos to get your answers. 1. What is the largest area possible for the garden? DO NOT ROUND YOUR ANSWER. ____ squared feet2. What width will produce the maximum area? ____ feet3. What is the length of the garden that will produce the maximum area?

A Plan For A Park Has A Rectangular Plot Of Wild Flowers That Needs To Be Enclosed By 54 Feet Of Fencing.

Answers

Answer 1

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

a) What is the largest area possible for the garden?

Now, let the length of the rectangular plot be 54 -2x,

and the width of the rectangular plot be x,

so that:

[tex]\begin{gathered} \text{Area = (54 -2x) x = 54 x -2x}^2 \\ \frac{dA}{dx}=\text{ 54 - 4x = 0} \\ We\text{ have that:} \\ 54\text{ = 4x } \\ \text{Divide both sides by 4, we have that:} \\ \text{x = }\frac{54}{4} \\ \text{x = 13. 5} \end{gathered}[/tex]

Then, the largest area possible for the garden will be:

[tex]\text{Area = 54x -2x}^2=54(13.5)-2(13.5)^2=729-364.5=364.5ft^2[/tex]

b) What width will produce the maximum area?

[tex]Width,\text{ x = 13. 5 fe}et[/tex]

c) The length of the garden that will produce the maximum area:

[tex]\text{Length = 54 - 2x = 54 - 2( 13. 5) = 54 -27 = 27 fe}et[/tex]

A Plan For A Park Has A Rectangular Plot Of Wild Flowers That Needs To Be Enclosed By 54 Feet Of Fencing.

Related Questions

ВС: Round your answer to the nearest hundredth. B 2 7

Answers

opposite to angle 65 = BC

adjacent to angle 65 = 7

[tex]\tan \text{ }\theta\text{ = }\frac{\text{opposite }}{\text{adjacent}}[/tex][tex]\tan \text{ 65 =}\frac{BC}{7}[/tex][tex]\begin{gathered} BC\text{ = 7 x tan 65} \\ =\text{ 7 x 2.1445} \\ BC\text{ = 15.0115} \\ BC\text{ }\approx\text{ 15.01 (nearest hundreth)} \end{gathered}[/tex]

Graph the solution to the following system of inequalities.ys-2x-3y> 4x + 710-8-4-Х?10

Answers

Explanation

[tex]\begin{gathered} y\leq-2x-3 \\ y>4x+7 \end{gathered}[/tex]

Step 1

First, graph the inequality 1

[tex]y\leq-2x-3[/tex]

the related equation is

[tex]y=-2x-3[/tex]

now, get 2 coordinates of the line

a) when x=1

[tex]\begin{gathered} y=-2x-3 \\ y=-2(1)-3 \\ y=-2-3 \\ y=-5 \\ so,\text{ the coordinate is (1,-5)} \end{gathered}[/tex]

b)when x=0

[tex]\begin{gathered} y=-2x-3 \\ y=-2\cdot0-3 \\ y=0-3 \\ y=-3 \\ \text{coordinate P2}\Rightarrow(0,-3) \end{gathered}[/tex]

now, draw a line that pases trought the coordinates we found.

Since the inequality is ≤ , not a strict one, the border line is solid

Step 2

Now, do the same for inequality 2

so

[tex]y>4x+7[/tex]

the related equation is

[tex]y=4x+7[/tex]

find 2 coordinates of the line

a)when x=0

[tex]\begin{gathered} y=4x+7 \\ y=4\cdot0+7 \\ y=0+7 \\ y=7 \\ so,\text{ the coordinate 3 is (0,7)} \end{gathered}[/tex]

b) when x=-2

[tex]\begin{gathered} y=4x+7 \\ y=4\cdot-2+7 \\ y=-8+7 \\ y=-1 \\ so,\text{ the coordinate 4 is (-2},-1) \end{gathered}[/tex]

now, draw the line 2, this lines passes trougth the coordiantes 3 and 4

Since the inequality is >, a strict one, the border line is dotted

Step 3

Graph:

in inequality (1) we need the values smaller r than -2x-3, it measn all values under the line,

and in Inequality 2 we need the values greater than 4x+7, it means all values over the line

so, the solution is the dark purple zone

I hope this helps you

Which of the following represents the factorization of the trinomial below?x2 – X-20A. (x-4)(x-5)B. (X + 4)(x-5)oC. (x-2)(x-10)0D. (x+2)(x-10)

Answers

Answer:

(x+4)(x-5)

Step-by-step explanation:

Second order polynomial in the following format:

ax² + bx + c = 0

Has roots x¹ and x².

Can be factored as:

(x - x¹)(x - x²)

So, we have to find the roots.

Finding the roots:

Bhaskara formula, which is:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In the polynomial given in this question:

a = 1, b = -1, c = -20

So

[tex]x=\frac{-(-1)\pm\sqrt{(-1)^2-4\ast1\ast(-20)}}{2}=\frac{1\pm\sqrt{81}}{2}[/tex]

The roots are:

[tex]x^1=\frac{1+9}{2}=5,x^2=\frac{1-9}{2}=-4[/tex]

The factored form is:

(x - x¹)(x - x²) = (x - (-4))(x - 5) = (x+4)(x-5)

Find the distance between vertices A and C of a regular hexagon whose sides are 20 cm each angle of the hexagon is 120 degrees

Answers

Use cosine law to find b:

[tex]b^2=a^2+b^2-2ac*cosB[/tex][tex]\begin{gathered} b^2=(20cm)^2+(20cm)^2-2(20cm)(20cm)*cos120º \\ b^2=400cm^2+400cm^2-800cm^2*(-0.5) \\ b^2=400cm^2+400cm^2+400cm^2 \\ b^2=1200cm^2 \\ b=\sqrt{1200cm^2} \\ b=20\sqrt{3}cm \\ b\approx34.64cm \end{gathered}[/tex]Then, the distance between A and C is 20√3 cm or approximately 34.64 cm

I need help finding the angle measurements of 1 and 2

Answers

To find the angles 1 and 2:

In the above triangle, the angles opposite to the equal sides are equal.

Let us take,

[tex]\angle1=\angle2=x[/tex]

So, using the angle sum property of a triangle

[tex]\begin{gathered} 55+x+x=180 \\ 2x=180-55 \\ 2x=125 \\ x=62.5^{\circ} \end{gathered}[/tex]

Hence, the angles are

[tex]\begin{gathered} \angle1=62.5^{\circ} \\ \angle2=62.5^{\circ} \end{gathered}[/tex]

Write each equation in slope intercept form. Then graph .

Answers

ANSWER

EXPLANATION

Given;

[tex]y=-\frac{5}{6}x+4[/tex]

Recall, the general formula for slope - intercept form is;

[tex]\begin{gathered} y=mx+c \\ m=slope \\ c=y-intercept \end{gathered}[/tex]

comparing the given equation with the standard slope intercept form formula;

[tex]\begin{gathered} y=mx+c \\ y=-\frac{5}{6}x+4 \\ m=-\frac{5}{6} \\ c=4 \end{gathered}[/tex]

Hence, the graph of the given equation is;

What is the LCM of 10 and 4?

Answers

One way to find the least common multiple of two numbers is to first list the prime factors of each number.

[tex]\begin{gathered} 10=2\cdot5 \\ 4=2\cdot2 \end{gathered}[/tex]

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor by the greatest number of times it occurs.

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Giving a test to a group of students, the grades and gender are summarized below A B C TotalMale214 4 20Female1018 13 41Total1232 17 61If one student is chosen at random,Find the probability that the student did NOT get an "C". Round your answer to 3 decimal places_____.

Answers

Given:

⇒There are 61 students in total.

⇒12 of them got an A while 32 of them got a B.

⇒In total, 44 students did not get a C.

⇒So, 44 out of 61 students did not get a C.

Convert 44/61 into decimal form.

[tex]\frac{44}{61}=44\div61=0.721311\approx0.721[/tex]

Answer:

The probability that a randomly chosen student did not get a C is 0.721 approximately.

Find the 55th term of the arithmetic sequence -7, -5, -3,

Answers

The given numbers are -7,-5,-3.

The common differen

Find the area of the shaded sector of the circle. Leave your answers in terms of pi

Answers

Answer:

D. 8pi yd^2

Explanation:

Area of a sector is expressed as;

[tex]A\text{ = }\frac{\theta}{360}\times\pi r^2[/tex]

r is the radius of the circle

theta is the angle substended at the centre

Given the following

r = 9yd

theta = 360-200

theta = 160degrees

Substitute

A = 160/360 * pi(9)^2

A = 4/9*18pi

A = 72pi/9

A = 8pi yd2

Hence the area of the shaded sector is 8pi yd2

3 batteries cost $5r and 8 folders cost $2r. Jason bought6 batteries and 4 folders. How much does he pay?Give your answer in terms of the

Answers

We are asked to determine the total amount paid for 6 batteries and 4 folders. To do that we need to determine the unit price of each item. We do that by dividing the amount spent by the number of items that were bought. That is:

[tex]\begin{gathered} n_b=\frac{5\text{ dollars}}{3\text{ batteries}} \\ \\ n_f=\frac{2\text{ dollars}}{8\text{ folders}} \end{gathered}[/tex]

Now we multiply the desired number of items by each of the corresponding unit prices:

[tex]N=\frac{5}{3}\times6+\frac{2}{8}\times4[/tex]

Solving the operations:

[tex]\begin{gathered} N=10+1 \\ N=11 \end{gathered}[/tex]

Therefore, the total amount paid is $11.

Multiply the pair conjugates using the Product of Conjugates Pattern (simplify) (rs-2/5)(rs+2/5)

Answers

In order to calculate the product of a pair of conjugate terms, we can use the pattern below:

[tex](a+b)(a-b)=a^2-b^2[/tex]

So we have:

[tex]\begin{gathered} (rs-\frac{2}{5})(rs+\frac{2}{5}) \\ =(rs)^2-(\frac{2}{5})^2 \\ =r^2s^2-\frac{4}{25} \end{gathered}[/tex]

(7 x 10^-5) x (5 * 10^-8)= ?x 10^

Answers

1) Let's calculate that. Start by multiplying the factors 7, and 5.

[tex]\begin{gathered} 7\cdot10^{-5}\text{ x 5 }\cdot10^{-8}= \\ 35\cdot10^{-13} \end{gathered}[/tex]

After that, we use the property of the exponents when multiplying. Repeat the base and then add the exponents -8 + (-5) = -8 -5 = -13.

"The distributive Property"

Answers

Using the distributive property, the maximum number of players that can be in the NBA is; 450 players

How to use distributive property?

The distributive property is a property of algebra that states that you can distribute the contents of one parentheses into another to find an answer. For example;

a(b + c) = ab + ac

Now, we are told that there are 30 teams in the national basketball association and that each team has 12 healthy players plus three on injured reserve. Thus;

Number of players on each team = (12 + 3)

Now, for the 30 teams;

Total number of players for the teams = 30(12 + 3)

Applying distributive property, we have;

(30*12 + 30*3) = 450

Read more about distributive property at; https://brainly.com/question/2807928

#SPJ1

please help. due today! will mark as brainliest!

Answers

Answer:

which question you want to be answered

Answer:

[tex]\textsf{13.\;a)}\quad d=\dfrac{P}{0.5 \pi +1}[/tex]

[tex]\textsf{13.\;b)}\quad d=14\; \sf inches[/tex]

Step-by-step explanation:

Question 13

The perimeter, P inches, of a semicircle of diameter, d inches, is represented by the equation:

[tex]\boxed{P=0.5 \pi d+d}[/tex]

Part (a)

To express d in terms of P, rearrange the equation to isolate d.

Factor out the common term d from the right side of the equation:

[tex]\implies P=d(0.5 \pi +1)[/tex]

Divide both sides by (0.5π + 1):

[tex]\implies \dfrac{P}{0.5 \pi +1}=\dfrac{d(0.5 \pi +1)}{0.5 \pi +1}[/tex]

[tex]\implies \dfrac{P}{0.5 \pi +1}=d[/tex]

[tex]\implies d=\dfrac{P}{0.5 \pi +1}[/tex]

Part (b)

Given:

Perimeter = 36 in[tex]\pi \approx \dfrac{22}{7}[/tex]

Substitute the given values into the equation derived in part (a) and solve for d:

[tex]\implies d=\dfrac{36}{0.5 \left(\frac{22}{7}\right) +1}[/tex]

[tex]\implies d=\dfrac{36}{\frac{11}{7} +1}[/tex]

[tex]\implies d=\dfrac{36}{\frac{11}{7} +\frac{7}{7}}[/tex]

[tex]\implies d=\dfrac{36}{\frac{18}{7}}[/tex]

[tex]\implies d=36 \times \dfrac{7}{18}[/tex]

[tex]\implies d=\dfrac{252}{18}[/tex]

[tex]\implies d=14[/tex]

Therefore, the diameter is 14 inches.

I need help with part b please

Answers

we have that

interval (-infinite,0) ------> f(x)=5x+4

interval [0, infinite) ------> f(x)=x+7

Part B

f(0)

For x=0 ------> belong to the interval [0, infinite)

so

f(x)=x+7

substitute

f(0)=0+7

f(0)=7

Part C

f(3)

For x=3 ---> belong to the interval [0, infinite)

so

f(x)=x+7

substitute

f(3)=3+7

f(3)=10

how would I graph 3x + 4y = -4

Answers

Answer:

To graph a line you have to find two points on the line, one way of doing this is first setting x=0 and solving for y, as follows:

[tex]\begin{gathered} 3(0)+4y=-4, \\ 4y=-4, \\ y=-1. \end{gathered}[/tex]

With the above calculations, we got that the point (0,-1) is on the line.

Now, to find another point on the line we set y=0 and solve for x:

[tex]\begin{gathered} 3x+4(0)=-4, \\ 3x=-4, \\ x=-\frac{4}{3}\text{.} \end{gathered}[/tex]

With the above calculations, we got that the point (-4/3,0) is on the line.

Once we have those points we draw the line that passes through those points.

The graph of the given equation is:

Can you pls help with 7 I need to do 8 more packets like these by tomoghy

Answers

The daily rate can be found by dividing the total number of books over the number of calendar days.

15,260 / 28 = 545

545 books per day

The following table is a function.х15725354 9у-3 27-4 5971 0

Answers

a For any relation to be a function, an independent variable x cannot produce different dependent varible y

From the table,

when x = 5, y = 2

Also, when x = 5, y = 5

and when x = 5, y = 7

We can see that x= 5 produces 3 different values of y ( that is 2, 5, and 7). This has disobeyed the rule of a function

Hence, the table is not a function

The answer is False

I need help ASAP please can you help you help

Answers

OPTION C

A quartic function is a fourth-degree polynomial: a function that has, as its highest order term, a variable raised to the fourth power.

From our question, it was easy to

What is the probability of rolling a die (ordinary, 6-sided die with numbers 1, 2,3, 4, 5, 6) and getting a 7?

Answers

Let:

A = Getting a 7

a = Number of sides with 7

N = Number of sides

so:

[tex]\begin{gathered} P(A)=\frac{a}{N} \\ P(A)=\frac{0}{6} \\ P(A)=0 \end{gathered}[/tex]

(x² + 5x - 2)-(3x²-x+4)

Answers

Given: (x² + 5x - 2)-(3x²-x+4)

Remove the parentheses:

[tex]=x^2+5x-2-3x^2+x-4[/tex]

Add like terms:

[tex]\begin{gathered} =x^2-3x^2+5x+x-2-4 \\ =-2x^2+6x-6 \end{gathered}[/tex]

Answer:

[tex]\begin{equation*} -2x^2+6x-6 \end{equation*}[/tex]

What is an obtuse angle?A) Angle COAB) Angle BOAC) Angle DOBD) Angle DOA

Answers

An obtuse angle is an angle that measures more than 90° but not eauql or greater than 180°.

COA is the sum of COB and BOA, which is 90°, so COA is not obtuse.

BOA is 60°, so it is not obtuse.

DOA is a straight line, so it is 180°, so not obtuse.

DOB is COD plus COB. Since COA is 90°, DOC is also 90°, so DOC ples COB is 120°, which is between 90° and 180°, so DOB is obtuse and the correct alternative is C.

Where x is the horizontal distance in feet from the point at which the ball is thrown.How far from the child does the ball strike the ground?

Answers

To calculate the maximum distance that the ball takes, we can use the first and second derivatives of y to find out this. We have:

[tex]\begin{gathered} y=-\frac{1}{14}x^2+4x+3 \\ \Rightarrow y^{\prime}=-\frac{2}{14}x+4=-\frac{1}{7}x+4 \\ \Rightarrow y^{\doubleprime}=-\frac{1}{7} \end{gathered}[/tex]

Using the second derivative criterion, we have that y'' < 0, therefore, we have a maximum in the root of the first derivative. For that, we get the following:

[tex]\begin{gathered} y^{\prime}=0 \\ \Rightarrow-\frac{1}{7}x+4=0 \\ \Rightarrow\frac{1}{7}x=4 \\ \Rightarrow x=7\cdot4=28 \\ x=28 \end{gathered}[/tex]

Therefore, at x=28 is where the maximum distance is. Now we only substitute x=28 in y to find out:

[tex]\begin{gathered} y=-\frac{1}{14}(28)^2+4(28)+3 \\ \Rightarrow y=-\frac{1}{14}(784)+112+3 \\ \Rightarrow y=-56+112+3=59 \\ y=59 \end{gathered}[/tex]

Finally, we have that the ball will go 59 feet from the child

If $163,300 is invested in an account earning 3.75% annual interest compounded semi-annually, how much interest is accrued in the first 4 years? Round to the nearest cent?

Answers

Solution:

An amount compounded is given as;

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{Where;} \\ P=\text{ amount invested;} \\ r=\text{ interest rate;} \\ n=\text{ number of times interest applied per time period;} \\ t=\text{ number of time period elapsed.} \end{gathered}[/tex]

Given that;

[tex]\begin{gathered} P=163,300 \\ r=0.0375 \\ n=2 \\ t=4 \end{gathered}[/tex]

Thus, we have;

[tex]\begin{gathered} A=163300(1+\frac{0.0375}{2})^{2\times4} \\ A=163300(1.01875)^8 \\ A=189464.20 \end{gathered}[/tex]

Thus, the interest accrued in the first 4 years is;

[tex]\begin{gathered} I=A-P \\ I=189464.20-163300 \\ I=26164.20 \end{gathered}[/tex]

FINAL ANSWER: $26,164.20

Glven: Circle P with center at (-2, 3) and a radius of 23. Identify the equation that could represent circle P. (3 – 2) + (y - 3)2 = 23 (2+2) + (y + 3)' = 23 (2 – 2)2 + (y + 3) = 23 (2+2)² + (y – 3)2 =23

Answers

The correct option is:

[tex](x+2)^2+(y-3)^2=23[/tex]

Because we need to remember that the equation for a circumference centered in (h,k) and with radius r is:

Enter an algebrak expression for the word expression. twice a number, minus 19 The expression is ?

Answers

x is an unknown number

twice a number means: 2x

and twice a number minus 19 means: 2x - 19

which is the better buy and provide the unit price for your answer! $5.28 for 6 candy bars or $12.75 for 15 candy bars?

Answers

Answer:

Explanation:

Given:

$5.28 for 6 candy bars

$12.75 for 15 candy bars

To determine the better buy, we simplify each option first:

For $5.28 for 6 candy bars:

5.28/6 = $0.88 per candy bar

For $12.75 for 15 candy bars:

12.75/15 = $0.85 per candy bar

Therefore,

is rational or irrational v2

Answers

The square root of 2 is irrational

Here, we want to check if the square root of 2 is rational or not

When we talk of rational numbers, we mean numbers that can be expressed as the ratio of two integers

Roots of non-perfect squares such as two are not rational. They are referred to as irrational numbers. The special name they are called is surd

I need to write and simplify an algebraic expression for the perimeter of each shape.please help!

Answers

For the square, we have that each side's length is 2p, since the perimeter is the sum of the length of all sides of a geometric figure, this means that we have to add all the lengths of the square like this:

[tex]\begin{gathered} P=2p+2p+2p+2p_{} \\ \Rightarrow P=8p \end{gathered}[/tex]

And we can do the same with the 3 sides of the triangle:

[tex]\begin{gathered} P=2x+2x+3x+1 \\ \Rightarrow P=7x+1 \end{gathered}[/tex]

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